Search Results

Search found 19480 results on 780 pages for 'do your own homework'.

Page 57/780 | < Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >

  • replacing elements horizontally and vertically in a 2D array

    - by wello horld
    the code below ask for the user's input for the 2D array size and prints out something like this: (say an 18x6 grid) .................. .................. .................. .................. .................. .................. code starts here: #include <stdio.h> #define MAX 10 int main() { char grid[MAX][MAX]; int i,j,row,col; printf("Please enter your grid size: "); scanf("%d %d", &row, &col); for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { grid[i][j] = '.'; printf("%c ", grid[i][j]); } printf("\n"); } return 0; } I now ask the user for a string, then ask them where to put it for example: Please enter grid size: 18 6 Please enter word: Hello Please enter location: 0 0 Output: Hello............. .................. .................. .................. .................. .................. Please enter location: 3 4 Output: .................. .................. .................. ..Hello........... .................. .................. program just keeps going. Any thoughts on how to modify the code for this? PS: Vertical seems way hard, but I want to start on horizontal first to have something to work on.

    Read the article

  • Javascript question

    - by Craig
    I am supposed to make this simple program. It produces a multiplication problem, and when the user types the correct answer, it is supposed to produce another question. Instead it goes into an infinite loop and never stops, the answer field and the button go away. Also, I am supposed to make the comment about the users answer, one of 4 different sayings. Without using Arrays how would I do that? My professor is no help, really getting aggravated as I have no where else to turn. <html> <title>HW 9.27 and 9.28</title> <head> <script type="text/javascript"> var number1; var number2; var answer3; var answer2; function problem() { number1 = Math.floor(1 + Math.random() * 9); number2 = Math.floor(1 + Math.random() * 9); document.writeln("How much is " + number1 + " times " + number2 + " ?"); answer2 = (number1 * number2); } function answer1() { var statusDiv = document.getElementById("status"); answer3 = document.getElementById("answer").value; if (answer3 != answer2) statusDiv.innerHTML = "No. Please try again"; else if (answer3 == answer2) { statusDiv.innerHTML = "Very good!"; problem(); } } problem(); </script> </head> <body> <form> <input id="answer" type="text" /> <input type="button" value="Solve!" onclick="answer1()" /> <div id ="status">Click the Solve button to Solve the problem</div> </form> </body> </html>

    Read the article

  • C# Freq. Table with Random Values

    - by Sef
    Hello, I am trying to write a frequency program that will represent a bar diagram (in console code). The problem is i have no idea how exactly to caculate this frequency or how do i exactly then give the bars different heights according to there frequency (trough calculation). The frequency height is capped at 21. (meaning the bars go from 1 to 21, so the max bar height would be for example 21 stars(* as display sign for the bar itself). A calculation i have so far (although not sure if correct) for frequency: This array takes the random values generated: for (int j = 0; j < T.Length; j++) { T[j] = (MaxHeight* T[j]) / Ber.GreatestElement(T); Console.Write("{0,7}", T[j]); } This results in values between 0 and 21 -- Based on the values my bars should give a certain height compared to all the other frequency values. (for example 8000 could have 21 in height where 39 could have 1). To represent this diagram i used 2 for loops to display height and width (keep in mind i only wish to use Using System; to keep it to the "basics"). for (int height= 1; height<= 21; height++) { for (int width= 0; width<= 10; width++) { if(...??) { Console.Write("{0,7}", bar); // string bar= ("*"); } else { Console.Write("{0,7}", empty); } } Console.WriteLine(); } So so far i have a entire field filled with * and the random values generated along with their frequency value (although i have no idea if the freq value is properly calculated). I assume i need a if (.....) in the second for but i cannot seem to get further then this. Thanks in advance!

    Read the article

  • sloving Algorithm notation

    - by neednewname
    Use big-O notation to classify the traditional grade school algorithms for addition and multiplication. That is, if asked to add two numbers each having N digits, how many individual additions must be performed? If asked to multiply two N-digit numbers, how many individual multiplications are required Suppose f is a function that returns the result of reversing the string of symbols given as its input, and g is a function that returns the concatenation of the two strings given as its input. If x is the string hrwa, what is returned by g(f(x),x)? Explain your answer - don't just provide the result!

    Read the article

  • Return the Largest Span in a given Array -Core Java and Arrays Question

    - by Deepak
    Hi Stack People, Merry Christmas and hope you are in great Spirits,I have a Question in Java-Arrays as shown below.Im stuck up with this struggling to get it rite. Consider the leftmost and righmost appearances of some value in an array. We'll say that the "span" is the number of elements between the two inclusive. A single value has a span of 1. Write a **Java Function** that returns the largest span found in the given array. **Example: maxSpan({1, 2, 1, 1, 3}) ? 4,answer is 4 coz MaxSpan between 1 to 1 is 4 maxSpan({1, 4, 2, 1, 4, 1, 4}) ? 6,answer is 6 coz MaxSpan between 4 to 4 is 6 maxSpan({1, 4, 2, 1, 4, 4, 4}) ? 6,answer is 6 coz Maxspan between 4 to 4 is 6 which is greater than MaxSpan between 1 and 1 which is 4,Hence 64 answer is 6. I have the code which is not working,it includes all the Spans for a given element,im unable to find the MaxSpan for a given element. Please help me out. Results of the above Program are as shown below Expected This Run maxSpan({1, 2, 1, 1, 3}) ? 4 5 X maxSpan({1, 4, 2, 1, 4, 1, 4}) ? 6 8 X maxSpan({1, 4, 2, 1, 4, 4, 4}) ? 6 9 X maxSpan({3, 3, 3}) ? 3 5 X maxSpan({3, 9, 3}) ? 3 3 OK maxSpan({3, 9, 9}) ? 2 3 X maxSpan({3, 9}) ? 1 1 OK maxSpan({3, 3}) ? 2 3 X maxSpan({}) ? 0 1 X maxSpan({1}) ? 1 1 OK ::Code:: public int maxSpan(int[] nums) { int count=1;//keep an intial count of maxspan=1 int maxspan=0;//initialize maxspan=0 for(int i=0;i<nums.length;i++){ for(int j=i+1;j<nums.length;j++){ if(nums[i] == nums[j]){ //check to see if "i" index contents == "j" index contents count++; //increment count maxspan=count; //make maxspan as your final count int number = nums[i]; //number=actual number for maxspan } } } return maxspan+1; //return maxspan }

    Read the article

  • SQL query joining rows with same value

    - by user1285737
    I need to write a query that creates a view that calculates the total cost of each sale, by considering quantity and price of each bought item. The view should return the debit and total cost. In the answer each debit-number should only occur once. Thanks in advance Table ITEM: ID NAME PRICE 118 Jeans 100 120 Towel 20 127 Shirt 55 Table DEBIT: DEBIT ITEM Quantity 100581 118 5 100581 120 1 100586 127 5

    Read the article

  • dynimically using pointer

    - by gcc
    Input: 3 1 2 n 4 5 d 1 21 30 x Output: 2: 4 5 21 30 Input: 3 j 3 34 6 22 10 51 n 1 2 j 1 3 4 5 n 6 7 x Output: 1: 1 2 3 4 5 2: 6 7 3: 34 6 22 10 51 'j': (Jump to array# command) 'd': (Delete array# command) 'n': (Next array command) 'x': (Exit command) #: (Integer number) int num_arrays; /* maximum number of arrays */ int **arrays; /* array of array pointers */ int *l_arrays; /* actual lengths of arrays */ int *c_arrays; /* actual capacities of arrays */ how can we write that code

    Read the article

  • Constructors for C++ objects

    - by sasquatch
    I have class Person as following : class Person { char* name; int age; }; Now I need to add two contructors. One taking no arguments, that inserts field values to dynamically allocated resources. Second taking (char*, int) arguments initialized by initialization list. Last part is to define a destructor showing information about destroying objects and deallocating dynamically allocated resources. How to perform this task ? That's what I already have : class Person { char* name; int age; public: Person(){ this->name = new *char; this->age = new int; } Person(char* c, int i){ } };

    Read the article

  • two classes contain objects of each other

    - by Julz
    hi, i hope there's a simple answer to this. without getting too complicated i have two classes. an "Animal" and a "Cell" Cell contains an Animal as a member. Animal has methods that accept Cells in their parameters. i'm just confused as to how i #include each class the others header? i've only ever had to go up a chain of classes and just included the last class header in the next and so on, but this circular situation has me a bit lost. i hope that makes sense, any help greatly appreciated.

    Read the article

  • UNIX Programs (Shell Scripting) [closed]

    - by atif089
    Hi, I have an exam tomorrow and I need some help with these programs. Or if you can tell me where I can get these. Write a program which uses grep to search a file for a pattern and display search patterns on standard output Write an awk program to print only odd numbered lines of a file. Write a program to open the command ls and give the output to the command through which we count the number of files Thank You :)

    Read the article

  • one more time about loop that doesn't work

    - by unit
    I have asked a couple of questions about this for loop: String[] book = new String [ISBN_NUM]; bookNum.replaceAll("-",""); if (bookNum.length()!=ISBN_NUM) throw new ISBNException ("ISBN "+ bookNum + " must be 10 characters"); for (int i=0;i<bookNum.length();i++) { if (Character.isDigit(bookNum.charAt(i))) book[j]=bookNum.charAt(i); //this is the problem right here j++; if (book[9].isNotDigit()|| book[9]!="x" || book[9]!="X") throw new ISBNException ("ISBN " + bookNum + " must contain all digits" + "or 'X' in the last position"); } which will not compile. An answer I had from the other question I asked told me that the line where the error occurs is wrong in that bookNum.charAt(i) is an (immutable) string, and I can't get the values into a book array that way. What I need to do on my assignment is check an ISBN number (bookNum) to see that it is all numbers, except the last digit can be an 'x' (valid ISBN). Is this the best way to do it? If so, what the hell am I doing wrong? If not, what method would be a better one to use?

    Read the article

  • Randomised objects are assigning themselves to more than one array location

    - by Thaddeus Aid
    this.size = 9; this.populationSize = 10; Random rand = new Random(); Integer[][] easy1 = new Integer[size][size]; easy1 = this.initializeEasy1(easy1); this.sudokuArray = new Sudoku[this.populationSize]; for (int i = 0; i < this.sudokuArray.length; i++){ long seed = rand.nextLong(); System.out.println("" + seed); this.sudokuArray[i] = new Sudoku(easy1, this.size, seed); } I am building an evolutionary sudoku solver and I am having a problem where the last Sudoku object is overwriting all the other objects in the array. Where in the code did I mess up? /edit here is the constructor of the class public Sudoku(Integer[][] givensGrid, int s, long seed){ this.size = s; this.givens = givensGrid; this.grid = this.givens.clone(); Random rand = new Random(seed); System.out.println("Random " + rand.nextInt()); // step though each row of the grid for (int i = 0; i < size; i++){ ArrayList<Integer> numbers = new ArrayList<Integer>(); numbers = this.makeNumbers(numbers); // step through each column to find the givens and remove from numbers for (int j = 0; j < size; j++){ if (this.grid[i][j] != 0){ numbers.remove(this.grid[i][j]); } } // go back through the row and assign the numbers randomly for (int j = 0; j < size; j++){ if (this.grid[i][j] == 0){ int r = rand.nextInt(numbers.size()); this.grid[i][j] = numbers.get(r); numbers.remove(r); } } } System.out.println("============="); System.out.println(this.toString()); }

    Read the article

  • Sorting a list of numbers with modified cost

    - by David
    First, this was one of the four problems we had to solve in a project last year and I couldn’t find a suitable algorithm so we handle in a brute force solution. Problem: The numbers are in a list that is not sorted and supports only one type of operation. The operation is defined as follows: Given a position i and a position j the operation moves the number at position i to position j without altering the relative order of the other numbers. If i j, the positions of the numbers between positions j and i - 1 increment by 1, otherwise if i < j the positions of the numbers between positions i+1 and j decreases by 1. This operation requires i steps to find a number to move and j steps to locate the position to which you want to move it. Then the number of steps required to move a number of position i to position j is i+j. We need to design an algorithm that given a list of numbers, determine the optimal (in terms of cost) sequence of moves to rearrange the sequence. Attempts: Part of our investigation was around NP-Completeness, we make it a decision problem and try to find a suitable transformation to any of the problems listed in Garey and Johnson’s book: Computers and Intractability with no results. There is also no direct reference (from our point of view) to this kind of variation in Donald E. Knuth’s book: The art of Computer Programing Vol. 3 Sorting and Searching. We also analyzed algorithms to sort linked lists but none of them gives a good idea to find de optimal sequence of movements. Note that the idea is not to find an algorithm that orders the sequence, but one to tell me the optimal sequence of movements in terms of cost that organizes the sequence, you can make a copy and sort it to analyze the final position of the elements if you want, in fact we may assume that the list contains the numbers from 1 to n, so we know where we want to put each number, we are just concerned with minimizing the total cost of the steps. We tested several greedy approaches but all of them failed, divide and conquer sorting algorithms can’t be used because they swap with no cost portions of the list and our dynamic programing approaches had to consider many cases. The brute force recursive algorithm takes all the possible combinations of movements from i to j and then again all the possible moments of the rest of the element’s, at the end it returns the sequence with less total cost that sorted the list, as you can imagine the cost of this algorithm is brutal and makes it impracticable for more than 8 elements. Our observations: n movements is not necessarily cheaper than n+1 movements (unlike swaps in arrays that are O(1)). There are basically two ways of moving one element from position i to j: one is to move it directly and the other is to move other elements around i in a way that it reaches the position j. At most you make n-1 movements (the untouched element reaches its position alone). If it is the optimal sequence of movements then you didn’t move the same element twice.

    Read the article

  • missing subscript c++

    - by Makenshi
    right now c++ is giving me this error: error C2087 'color' missing subscript first time i get this and i dont know what to do .< hope any1 can help me struct Color{ float r; float g; float b; };Color color[][]; and im using it here for(int i=0;i<cubes;i++) { color[i][0].r = fRand();color[i][0].g=fRand(.5);color[i][0].b=fRand(); ...etc

    Read the article

  • Simple 'database' in c++

    - by DevAno1
    Hello. My task was to create pseudodatabase in c++. There are 3 tables given, that store name(char*), age(int), and sex (bool). Write a program allowing to : - add new data to the tables - show all records - sort tables with criteria : - name increasing/decreasing - age increasing/decreasing - sex Using function templates is a must. Also size of arrays must be variable, depending on the amount of records. I have some code but there are still problems there. Here's what I have: Function tabSize() for returning size of array. But currently it returns size of pointer I guess : #include <iostream> using namespace std; template<typename TYPE> int tabSize(TYPE *T) { int size = 0; size = sizeof(T) / sizeof(T[0]); return size; } How to make it return size of array, not its pointer ? Next the most important : add() for adding new elements. Inside first I get the size of array (but hence it returns value of pointer, and not size it's of no use now :/). Then I think I must check if TYPE of data is char. Or am I wrong ? // add(newElement, table) template<typename TYPE> TYPE add(TYPE L, TYPE *T) { int s = tabSize(T); //here check if TYPE = char. If yes, get the length of the new name int len = 0; while (L[len] != '\0') { len++; } //current length of table int tabLen = 0; while (T[tabLen] != '\0') { tabLen++; } //if TYPE is char //if current length of table + length of new element exceeds table size create new table if(len + tabLen > s) { int newLen = len + tabLen; TYPE newTab = new [newLen]; for(int j=0; j < newLen; j++ ){ if(j == tabLen -1){ for(int k = 0; k < len; k++){ newTab[k] = } } else { newTab[j] = T[j]; } } } //else check if tabLen + 1 is greater than s. If yes enlarge table by 1. } Am I thinking correct here ? Last functions show() is correct I guess : template<typename TYPE> TYPE show(TYPE *L) { int len = 0; while (L[len] == '\0') { len++; } for(int i=0; i<len; i++) { cout << L[i] << endl; } } and problem with sort() is as follows : Ho can I influence if sorting is decreasing or increasing ? I'm using bubble sort here. template<typename TYPE> TYPE sort(TYPE *L, int sort) { int s = tabSize(L); int len = 0; while (L[len] == '\0') { len++; } //add control increasing/decreasing sort int i,j; for(i=0;i<len;i++) { for(j=0;j<i;j++) { if(L[i]>L[j]) { int temp=L[i]; L[i]=L[j]; L[j]=temp; } } } } And main function to run it : int main() { int sort=0; //0 increasing, 1 decreasing char * name[100]; int age[10]; bool sex[10]; char c[] = "Tom"; name[0] = "John"; name[1] = "Mike"; cout << add(c, name) << endl; system("pause"); return 0; }

    Read the article

  • staying within boundaries of image?

    - by codefail
    So I am to loop through copyFrom.pixelData and copy it into pixelData. I realize that I need to check the conditions of i and j, and have them not copy past the boundaries of pixelData[x][y], I need another 2 loops for that? I tried this, but was getting segmentation fault.. Is this the right approach? void Image::insert(int xoff, int yoff, const Image& copyFrom, Color notCopy) { for (int x = xoff; x < xoff+copyFrom.width; x++) { for (int y = yoff; y < yoff+copyFrom.height; y++) { for (int i = 0; i<width; i++){ for (int j = 0; j<height; j++){ if (copyFrom.pixelData[i][j].colorDistance(notCopy)>20 ) pixelData[x][y]=copyFrom.pixelData[i][j]; } } } } }

    Read the article

  • Write a function int mystrlen(char *s) that returns the number of characters in a string wuthout str

    - by henry
    heres what i did, i just have ne error that i cant figure out. int mystrlen(char string[]) { char string1[LENGHT], string2[LENGHT]; int len1, len2; char newstring[LENGHT*2]; printf("enter first string:\n"); len1 = mystrlen(string1); printf("enter second string:\n"); len2 = mystrlen(string2); if(len1 == EOF || len2 == EOF) exit(1); strcpy(newstring, string1); strcat(newstring, string2); printf("%s\n", newstring); return 0;

    Read the article

  • Confusion with a while statement evaluating if a number is triangular

    - by Darkkurama
    I've been having troubles trying to figure out how to solve a function. I've been assigned the development of a little programme which tells if a number is "triangular" (a number is triangular when the addition of certain consecutive numbers in the [1,n] interval is n. Following the definition, the number 10 is triangular, because in the [1,10] interval, 1+2+3+4=10). I've coded this so far: class TriangularNumber{ boolean numTriangular(int n) { boolean triangular = false; int i = n; while(n>=0 && triangular){ //UE06 is a class which contains the function "f0", which makes the addition of all the numbers in a determined interval UE06 p = new UE06(); if ((p.f0(1, i))==n) triangular = true; else i=i-1; } return triangular; } boolean testTriangular = numTriangular(10) == true && numTriangular(7) == false && numTriangular(6) == true; public static void main(String[] args){ TriangularNumber p = new TriangularNumber(); System.out.println("testTriangular = " + p.testTriangular); } } According to those boolean tests I made, the function is wrong. As I see the function, it goes like this: I state that the input number in the initial state isn't triangular (triangular=false) and i=n (determining the interval [1,i] where the function is going to be evaluated While n is greater or equals 0 and the number isn't triangular, the loop starts The loop goes like this: if the addition of all the numbers in the [1,i] interval is n, the number is triangular, causing the loop to end. If that statement is false, i goes from i to (i-1), starting the loop again with that particular interval, and so on till the addition is n. I can't spot the error in my "algorithm", any advice? Thanks!

    Read the article

  • I keep getting a no match for call to error!!??

    - by Timothy Poseley
    #include <iostream> #include <string> using namespace std; // Turns a digit between 1 and 9 into its english name // Turn a number into its english name string int_name(int n) { string digit_name; { if (n == 1) return "one"; else if (n == 2) return "two"; else if (n == 3) return "three"; else if (n == 4) return "four"; else if (n == 5) return "five"; else if (n == 6) return "six"; else if (n == 7) return "seven"; else if (n == 8) return "eight"; else if (n == 9) return "nine"; return ""; } string teen_name; { if (n == 10) return "ten"; else if (n == 11) return "eleven"; else if (n == 12) return "twelve"; else if (n == 13) return "thirteen"; else if (n == 14) return "fourteen"; else if (n == 14) return "fourteen"; else if (n == 15) return "fifteen"; else if (n == 16) return "sixteen"; else if (n == 17) return "seventeen"; else if (n == 18) return "eighteen"; else if (n == 19) return "nineteen"; return ""; } string tens_name; { if (n == 2) return "twenty"; else if (n == 3) return "thirty"; else if (n == 4) return "forty"; else if (n == 5) return "fifty"; else if (n == 6) return "sixty"; else if (n == 7) return "seventy"; else if (n == 8) return "eighty"; else if (n == 9) return "ninety"; return ""; } int c = n; // the part that still needs to be converted string r; // the return value if (c >= 1000) { r = int_name(c / 1000) + " thousand"; c = c % 1000; } if (c >= 100) { r = r + " " + digit_name(c / 100) + " hundred"; c = c % 100; } if (c >= 20) { r = r + " " + tens_name(c /10); c = c % 10; } if (c >= 10) { r = r + " " + teen_name(c); c = 0; } if (c > 0) r = r + " " + digit_name(c); return r; } int main() { int n; cout << endl << endl; cout << "Please enter a positive integer: "; cin >> n; cout << endl; cout << int_name(n); cout << endl << endl; return 0; } I Keep getting this Error code: intname2.cpp: In function âstd::string int_name(int)â: intname2.cpp:74: error: no match for call to â(std::string) (int)â intname2.cpp:80: error: no match for call to â(std::string) (int)â intname2.cpp:86: error: no match for call to â(std::string) (int&)â intname2.cpp:91: error: no match for call to â(std::string) (int&)â

    Read the article

  • im writing this code so the user would enter his/her name and followed by his/her marks to get the a

    - by WM
    What if the user wanted to enter his/her grades in the following way: Will 23, 34, 45, 45 how would i get rid of the commas public class StudentAverage { public static void main(String[] args) { int markSum = 0; double average = 0; Scanner input1 = new Scanner(System.in); System.out.print("Enter student record : "); String name = input1.next(); Scanner input2 = new Scanner(input1.nextLine()); int countTotal = 0; while (input2.hasNextInt()) { countTotal++; markSum += input2.nextInt(); } average = markSum / countTotal; // to calculate the total average System.out.print( name + " " + average ); } }

    Read the article

  • Some exam questions about C++ vectors and arrays...

    - by xbonez
    Hey guys, I have a CS exam tomorrow. Just want to get a few questions cleared up. Thanks a lot, and I really appreciate the help. Que 1. What are parallel vectors? Vectors of the same length that contain data that is meant to be processed together Vectors that are all of the same data type Vectors that are of the same length Any vector of data type parallel Que 2. Arrays are faster and more efficient than vectors. True False Que 3. Arrays can be a return type of a function call. True False Que 4. Vectors can be a return type of a function call. True False

    Read the article

  • C - Call a function

    - by Pedro
    Hello. I want to get a value from a function in other function i think i have to call a function in other function, then call it on main, but how? void funcA(PEOPLE people[], int *total){ FILE *fp; char line[100]; fp=fopen("example.txt","r"); if(fp==NULL){ exit(1); } else{ fgets(line, 100, fp);//get a number from the txt total=atoi(linha);//convert to int } } void funcB(PEOPLE people[], int *total){ int i; for(i=0;i<total;i++){ printf("%s\n",people[i].name); } funcA(people,&total); } void main(){ PERSON person[100]; int *total; funcB(people,&total); } What i'm doing wrong?

    Read the article

  • Is there a way to close a Unix socket for only reading or writing?

    - by Sii
    Is there a way to only close "one end" of a TCP socket to cleanly indicate one side of a connection is done writing to the connection? (Just like you do with a pipe in every Unix pipe tutorial ever.) Or should I use some in-band solution like a sentinel value or some such? I only found shutdown() in the libc documentation and that doesn't seem like it does what I want.

    Read the article

< Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >