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  • css absolute positioning hidden scrollbars ... with a twist

    - by ScottE
    I'm working on a website that targets 1024 X 768 as the minimum resolution. So, we're at about 970px wide. Design came back with an interesting layout that has a centered site with a banner that actually exceeds this width (1288px to be exact) that will look good for users with greater resolution, but look fine at 1024. So, to prevent scrollbars from showing up for those at 1024 I positioned the banner absolutely and used overflow-x: hidden on the body. This works just fine across our target browsers. Now, the client has come back and asked for scrollbars to be present for users on 800 X 600 (yes, this is not the target) so they can see a critical login button. How can this be accommodated for those 2% of their users without making radical changes? All I can think of is to detect their screen width and remove the overflow-x:hidden. You have to love when requirements change late in the build process! Edit - here's what I have that seems simple enough to me - any caveats here? if (screen.width === 800) { $("body").css("overflow-x", "visible"); }

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  • I need Selenium to open it's web browser in a larger resolution ( preferably maximized)

    - by user1854271
    I am using Selenium WebDriver and coding in Python I have looked all over the place and the best I could find were things written in different languages. I also tried to use the export tool on Selenium IDE but when I look at the data says that the function is not supported for export. EDIT: The reason I need the browser to open up with a larger resolution is because the web application that I am testing is supporting tablet resolution as so elements are different depending on the resolution of the browser window. This is the script I exported from the IDE with a couple of modifications. from selenium import webdriver from selenium.webdriver.common.by import By from selenium.webdriver.support.ui import Select from selenium.common.exceptions import NoSuchElementException import unittest, time, re from Funk_Lib import RS class CreatingEditingDeletingVault(unittest.TestCase): def setUp(self): self.driver = webdriver.Firefox() self.driver.implicitly_wait(30) self.base_url = "http://cimdev-qa40/" self.verificationErrors = [] def test_creating_editing_deleting_vault(self): driver = self.driver driver.get(self.base_url + "/Login?contoller=Home") driver.find_element_by_id("UserName").click() driver.find_element_by_id("UserName").clear() driver.find_element_by_id("UserName").send_keys("[email protected]") driver.find_element_by_name("Password").click() driver.find_element_by_name("Password").clear() driver.find_element_by_name("Password").send_keys("Codigo#123") driver.find_element_by_id("fat-btn").click() driver.get(self.base_url + "/Content/Vaults/") driver.find_element_by_link_text("Content").click() driver.find_element_by_link_text("Vaults").click() driver.find_element_by_css_selector("button.btn.dropdown-toggle").click() driver.find_element_by_link_text("New vault").click() driver.find_element_by_name("Name").clear() driver.find_element_by_name("Name").send_keys("Test Vault") driver.find_element_by_xpath("//button[@onclick=\"vault_action('createvault', null, $('#CreateVault [name=\\'Name\\']').val())\"]").click() driver.find_element_by_css_selector("button.btn.dropdown-toggle").click() driver.find_element_by_link_text("Rename vault").click() driver.find_element_by_name("Id").click() Select(driver.find_element_by_name("Id")).select_by_visible_text("Test Vault") driver.find_element_by_css_selector("option[value=\"2\"]").click() driver.find_element_by_name("Name").clear() driver.find_element_by_name("Name").send_keys("Test Change") driver.find_element_by_xpath("//button[@onclick=\"vault_action('renamevault', $('#RenameVault [name=\\'Id\\']').val(), $('#RenameVault [name=\\'Name\\']').val())\"]").click() driver.find_element_by_css_selector("button.btn.dropdown-toggle").click() driver.find_element_by_link_text("Delete vault").click() driver.find_element_by_name("Id").click() Select(driver.find_element_by_name("Id")).select_by_visible_text("Test Change") driver.find_element_by_css_selector("option[value=\"2\"]").click() driver.find_element_by_xpath("//button[@onclick=\"vault_action('deletevault', $('#DeleteVault [name=\\'Id\\']').val(), '')\"]").click() def is_element_present(self, how, what): try: self.driver.find_element(by=how, value=what) except NoSuchElementException, e: return False return True def tearDown(self): self.driver.quit() self.assertEqual([], self.verificationErrors) if __name__ == "__main__": unittest.main()

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  • How do i make multi call with SudzC

    - by laxonline
    I am developing magento eCommerce stores in iPhone. For that, i have using Sudzc service class for SOAP WS call. Now, I'm trying to create a cart session its working fine. im getting the cardid. And i need to add one product to cart with some arguments. below is the php request example i need to call same this PHP Request Example $proxy = new SoapClient('http://beta.saletab.com/api/soap/?wsdl'); $sessionId = $proxy->login('xxxx', 'zzzzzzzzzzzzzzzzzzzzzzzzz'); //print_r($sessionId); $shoppingCartId = $proxy->call( $sessionId, 'cart.create'); $result = $proxy->call($sessionId,'cart_product.add',array($shoppingCartId,array('product_id'=>"3109",'qty' => 2)),0); echo "REQUEST HEADERS:\n" . $result->__getLastRequestHeaders() . "\n"; IOS Request im trying to send some product details like productid, sku & cardid SDZMagentoService *service = [SDZMagentoService service]; NSString *sessionId = [IMAPP_DELEGATE getUserDefault:IMAPI_SESSIONID]; NSString *cartId = [IMAPP_DELEGATE getUserDefault:IMAPI_CARTSESSIONID]; NSDictionary *argu = [[NSDictionary alloc] initWithObjectsAndKeys:@"3109",@"product_id",@"2",@"qty",cartId,@"card_id", nil]; [service call:self action:@selector(cartTest:) sessionId:sessionId resourcePath:@"cart_product.add" args:argu];

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  • Issue selenium code maintenance

    - by Rajasankar
    I want to group the common methods in one file and use it. For example, login to a page using selenium may be used in multiple times. Define that in class A and call it in class B. However, it throws null pointer exception. class A has public void test_Login() throws Exception { try{ selenium.setTimeout("60000"); selenium.open("http://localhost"); selenium.windowFocus(); selenium.windowMaximize(); selenium.windowFocus(); selenium.type("userName", "admin"); selenium.type("password", "admin"); Result=selenium.isElementPresent("//input[@type='image']"); selenium.click("//input[@type='image']"); selenium.waitForPageToLoad(Timeout); } catch(Exception ex) { System.out.println(ex); ex.printStackTrace(); } } with all other java syntax in class B public void test_kk() throws Exception { try { a.test_Login(); } catch(Exception ex) { System.out.println(ex); ex.printStackTrace(); } } with all syntax. When I execute class B, I got this error, java.lang.NullPointerException at A.test_Login(A.java:32) at B.test_kk(savefile.java:58) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at junit.framework.TestCase.runTest(TestCase.java:168) at junit.framework.TestCase.runBare(TestCase.java:134) at com.thoughtworks.selenium.SeleneseTestCase.runBare(SeleneseTestCase.j ava:212) at junit.framework.TestResult$1.protect(TestResult.java:110) at junit.framework.TestResult.runProtected(TestResult.java:128) at junit.framework.TestResult.run(TestResult.java:113) at junit.framework.TestCase.run(TestCase.java:124) at junit.framework.TestSuite.runTest(TestSuite.java:232) at junit.framework.TestSuite.run(TestSuite.java:227) at junit.textui.TestRunner.doRun(TestRunner.java:116) at junit.textui.TestRunner.doRun(TestRunner.java:109) at junit.textui.TestRunner.run(TestRunner.java:77) at B.main(B.java:77) I hope someone must have tried this before. I may miss something here.

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  • Is there a way to reload the page after <fb:like> is clicked?

    - by joon
    Hi, I'm wondering about this: I have a simple facebook-connect app that will only show certain content after you login and liked a certain page. It works (huzzah!) but I want to make it more user friendly by making it refresh automatically after you pressed the like button. Here's some code: <?php if ($me) { $pageid = -----------; $uid = $me['id']; $likeID = $facebook->api( array( 'method' => 'fql.query', 'query' => 'SELECT target_id FROM connection WHERE source_id = ' . $uid . ' AND target_id = ' . $pageid ) ); if ( empty($likeID) ) { // Person is LOGGED IN, but has NOT LIKED echo '<script src="MY WEBPAGE"></script><fb:like href="MY WEBPAGE" layout="box_count" show_faces="false" width="450"></fb:like>'; } else { // Person is LOGGED IN, and has LIKED, score! echo 'Download link'; } } else { // Person is NOT LOGGED IN, so we know NOTHING echo '<script src="MY WEBPAGE"></script><fb:like href="MY WEBPAGE" layout="box_count" show_faces="false" width="450"></fb:like>'; } ?> Is there anything I can do to this code (maybe in the fb:like tag?) that makes it reload the page after a like? Thanks.

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  • can bind successfully to the ldap server, but needs to know how to find user w/i AD

    - by Brad
    I create a login form to bind to the ldap server, if successful, it creates a session (which the user's username is stored within), then I go to another page that has session_start(); and it works fine. What I want to do now, is add code to test if that user is a member of a specific group. So in theory, this is what I want to do if(username session is valid) { search ldap for user -> get list of groups user is member of foreach(group they are member of) { switch(group) { case STAFF: print 'they are member of staff group'; $access = true; break; default: print 'not a member of STAFF group'; $access = false; break; } if(group == STAFF) { break; } } if($access == TRUE) { // you have access to the content on this page } else { // you do not have access to this page } } How do I do a ldap_search w/o binding? I don't want to keep asking for their password on each page, and I can't pass their password thru a session. Any help is appreciated.

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  • Devise password reset issue (new_user?)

    - by rabid_zombie
    When a user's email is inputted into the forgot password form and submitted, I am receiving an error saying login can't be blank. I looked around devise.en.yml for this error message, but can't seem to find it anywhere. Here is my views/devise/passwords/new.html.haml: %div.registration_page %h2 Forgot your password? = form_for(resource, :as => resource_name, :url => user_password_path, :html => { :method => :post, :id => 'forgot_pw_form', :class => 'forgot_pw' }) do |f| %div = f.email_field :email, :placeholder => 'Email', :autofocus => true, :autocomplete => 'off' %div.email_error.error %input.btn.btn-success{:type => 'submit', :value => 'Send Instructions'} = render "devise/shared/links" The form is posting to users/password like it should, but I noticed that my forgot password form attaches class = 'new_user'. Here is what my form displays: <form accept-charset='UTF-8' action='/users/password' class='new_user' id='forgot_pw_form' method='post' novalidate='novalidate'></form> My routes for devise (I have custom sessions and registrations controllers): devise_for :users, :controllers => {:sessions => 'sessions', :registrations => 'registrations'} How can I setup devise's forgot password functionality? Why am I receiving this error message and why is that class being added there? I've tried: Adding my own passwords controller and adding new routes for my custom controller. Same error Adding my own class and id to the form. This successfully changes the id and class of the form, but reverts back to class and id of new_user Thanks.

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  • Domain Authentication from .NET Client over VPN

    - by Holy Christ
    I am writing a ClickOnce WPF app that will sometimes be used over VPN. The app uses resources available only to domain authenticated users. Some of the things include accessing SSRS Reports, accessing LDAP to lookup user information, hitting web services, etc. When a user logs in from a machine that is not authenticated on the domain, I need to somehow get his credentials, authenticate him on the domain, and store his credentials. What is the recommended approach for authenticating domain users over VPN? How can I securely store the credentials? I've found several articles but, not much posted recently and a lot of the solutions seem kinda hacky, or aren't very secure (ie - storing strings clear text in memory). It would be cool if I could use the ActiveDicrtoryMembershipProvider, but that seems to be geared for use in web apps. EDIT: The above is kind of a workaround. The user must enter their domain credentials to authenticate on the VPN. It would be ideal to access the credentials the user has already entered to login to the VPN instead of the WindowsIdentity.GetCurrent() (which returns the user logged into the computer). Any ideas on how that could work? We use Juniper Networks to connect to the VPN. Thanks!

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  • Executing a process in windows server 2003 and ii6 from code - permissions error

    - by kurupt_89
    I have a problem executing a process from our testing server. On my localhost using windows XP and iis5.1 I changed the machine.config file to have the line - I then changed the login for iis to log on as local system account and allow server to interact with desktop. This fixed my problem executing a process from code in xp. When using the same method on windows server 2003 (using iis6 isolation mode) the process does not get executed. Here is the code to execute the process (I have tested the inputs to iecapt through the command line and an image is generated) - public static void GenerateImageToDisk(string ieCaptPath, string url, string path, int delay) { url = FixUrl(url); ieCaptPath = FixPath(ieCaptPath); string arguments = @"--url=""{0}"" --out=""{1}"" --min-width=0 --delay={2}"; arguments = string.Format(arguments, url, path, delay); ProcessStartInfo ieCaptProcessStartInfo = new ProcessStartInfo(ieCaptPath + "IECapt.exe"); ieCaptProcessStartInfo.RedirectStandardOutput = true; ieCaptProcessStartInfo.WindowStyle = ProcessWindowStyle.Hidden; ieCaptProcessStartInfo.UseShellExecute = false; ieCaptProcessStartInfo.Arguments = arguments; ieCaptProcessStartInfo.WorkingDirectory = ieCaptPath; Process ieCaptProcess = Process.Start(ieCaptProcessStartInfo); ieCaptProcess.WaitForExit(600000); ieCaptProcess.Close(); }

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  • Pipelining String in Powershell

    - by ChvyVele
    I'm trying to make a simple PowerShell function to have a Linux-style ssh command. Such as: ssh username@url I'm using plink to do this, and this is the function I have written: function ssh { param($usernameAndServer) $myArray = $usernameAndServer.Split("@") $myArray[0] | C:\plink.exe -ssh $myArray[1] } If entered correctly by the user, $myArray[0] is the username and $myArray[1] is the URL. Thus, it connects to the URL and when you're prompted for a username, the username is streamed in using the pipeline. Everything works perfectly, except the pipeline keeps feeding the username ($myArray[0]) and it is entered as the password over and over. Example: PS C:\Users\Mike> ssh xxxxx@yyyyy login as: xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyy's password: Access denied xxxxx@yyyyy's password: FATAL ERROR: Server sent disconnect message type 2 (protocol error): "Too many authentication failures for xxxxx" Where the username has been substituted with xxxxx and the URL has been substituted with yyyyy. Basically, I need to find out how to stop the script from piping in the username ($myArray[0]) after it has been entered once. Any ideas? I've looked all over the internet for a solution and haven't found anything.

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  • FormsAuthentication authCookie is null only for some users

    - by mbalkema
    I am experiencing a strange problem with asp.net forms authentication. This problem only occurs for 3 users out of 30+ users that have successfully logged in. I am using very basic auth code that I have used many times and have never seen this problem. After the users successfully authenticates and the auth cookie is created, cookie added, and response.redirect to FormsAuthentication.GetRedirect(userid, false) is called. The Application_AuthenticateRequest method in Global.asax is hit. // Extract the forms authentication cookie string cookieName = FormsAuthentication.FormsCookieName; HttpCookie authCookie = Context.Request.Cookies[cookieName]; if (null == authCookie) { // There is no authentication cookie. return; } So immediately after a "good" cookie is saved and the redirect occurs the cookie is null. I have run the code through the debugger and the cookie is only null on these 3 users. But the cookie looks the same as the cookie for the many users that login successfully. Any ideas? This is standard code that should just work.

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  • Rss: Bookmark is not working correctly.

    - by shruti
    I'm working on project RSS generation in MVC.Net. in taht i want to make bookmark. for that i have write the code on controller. first there is one aspx page from which subscription page gets open. public ActionResult ViewBlog() { if (Session[SessionVariables.username] == null) { return RedirectToAction("Login", "Home"); } else { return View(classObj.fetchAllBlogs()); } } and coding for subscription is: public ActionResult Rss() { string bcontent = classObj.showBlog(); DateTime postdate = classObj.showPostDate(); List<SyndicationItem> items = new SyndicationItem[] { new SyndicationItem("RSS Blog",bcontent+postdate,null), }.ToList(); RssResult r = new RssResult(); SyndicationFeed feed = new SyndicationFeed("Admin: Blog Posts", "RSS Feed",Request.Url , items); return new RssResult(feed); Developer", "The latest news on ASP.NET, C# and ASP.NET MVC "); } but problem is that when usr clicks on bookmark then intested of opening ViewBlog.aspx it opens the same page. i want to open ViewBlog.aspx. I think the problem is in: SyndicationFeed feed = new SyndicationFeed("Admin: Blog Posts", "RSS Feed",Request.Url , items); Plz help ...!

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  • Is there a better way to change user password in cakephp using Auth?

    - by sipiatti
    Hi, I am learning cakephp by myself. I tried to create a user controller with a changepassword function. It works, but I am not sure if this is the best way, and I could not googled up useful tutorials on this. Here is my code: class UsersController extends AppController { var $name = 'Users'; function login() { } function logout() { $this->redirect($this->Auth->logout()); } function changepassword() { $session=$this->Session->read(); $id=$session['Auth']['User']['id']; $user=$this->User->find('first',array('conditions' => array('id' => $id))); $this->set('user',$user); if (!empty($this->data)) { if ($this->Auth->password($this->data['User']['password'])==$user['User']['password']) { if ($this->data['User']['passwordn']==$this->data['User']['password2']) { // Passwords match, continue processing $data=$this->data; $this->data=$user; $this->data['User']['password']=$this->Auth->password($data['User']['passwordn']); $this->User->id=$id; $this->User->save($this->data); $this->Session->setFlash('Password changed.'); $this->redirect(array('controller'=>'Toners','action' => 'index')); } else { $this->Session->setFlash('New passwords differ.'); } } else { $this->Session->setFlash('Typed passwords did not match.'); } } } } password is the old password, passwordn is the new one, password2 is the new one retyped. Is there any other, more coomon way to do it in cake?

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  • Re-authentication required for registered-path links (to ASP.NET site) coming to IE from PowerPoint

    - by Daniel Halsey
    We're using URL routing based on Phil Haack's example, with config modifications based on MSDN Library article #CC668202, to provide "shareable" links for a ASP.NET forms site, and have run into a strange issue: For users attempting to open links from PowerPoint presentations, and who have IE set as their default browser, using one of these links forces (forms-based) re-authentication, even in the same browser instance with a live session. Info: We know the session is still alive. (Page returns information for the currently logged-in user; confirmed via debug watches) This doesn't happen with other browsers (FF, Chrome) or with other programs (Notepad++) as the URL source. We do not have a default path set, as this caused issues with root path handling at initial login. This primarily happens with PowerPoint, but will also happen in Word and OCS. On some machines, even after changing the default browser, Office apps will continue to use IE for these links, forcing this error. (A potential registry fix for this failed, but even if it had worked, we can't control default browser choice for our users.) We can't figure out if this is an Office oddity or is being caused by our decision to use app-level URL routing (rather than IIS rewriting). Has anyone else encountered this and found a solution?

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  • On android how would I go about creating a prompt for an app that requires a user to enter a username before fully launching the app?

    - by racl101
    I'll preface this with I'm really new to working on Android. So I have to work on an existing app and create a screen that prompts the user for a username if one isn't entered then it won't launch the currently existing main activity (i.e. it won't fully launch the app. Instead it will just sit on that screen until a username is entered.) I suppose that it's tantamount to a web app login page in that it will not let a user past that page if the user is not authenticated and authorized. However, there's no authentication nor authorization in this app. Instead, on first run a user must simply register with a username and that username gets saved to the database and for any subsequent runs the app's main activity will just start because a user has registered to that phone. In fact, the app will not prompt the user for their name again unless the app gets deleted with all its data and reinstalled again. This implicitly means that I have to save the user's name in the database or some other kind of storage. So I was wondering what would be the best way of doing this in an app with an existing main activity? Should I try to accomplish this on that existing main activity or create a new activity to display this prompt screen and, in effect, block the main activity from running until the user enters their name? Any tutorials or links would be helpful and thank you in advance for any help.

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  • how to connect to MSSQL using activerecord, JDBC, JTDS and Integrated Security

    - by Rob
    As per the above, I've tried: establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';", :username => 'user', :password=>'pass' ) establish_connection(:adapter => "jdbcmssql", :url => 'jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain="mynetwork";user="mynetwork\user"' ) establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';", :username=>'user' ) establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';integratedSecurity='true'", :username=>'user' ) .. and various other combinations. Each time I get: net/sourceforge/jtds/jdbc/SQLDiagnostic.java:368:in `addDiagnostic': java.sql.SQLException: Login failed for user ''. The user is not associated with a trusted SQL Server connection. (NativeException) Any tips? Thanks, activerecord (2.3.5) activerecord-jdbc-adapter (0.9.6) activerecord-jdbcmssql-adapter (0.9.6) jdbc-jtds (1.2.5) jruby 1.4.0 (ruby 1.8.7 patchlevel 174) (2009-11-02 69fbfa3) (Java HotSpot(TM) Client VM 1.6.0_18) [x86-java]

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  • Sharepoint Active directory forms authentication

    - by Sushant
    Hi, I am devloping a sharepoint website in Forms authentication mode. I am trying to authenticate myself/ my company users against company's active directory. The ldap path I received from my technical team is LDAP://infinmumcfac.inf.com OU=Infotech,DC=inf,DC=com I got this piece of code from microsoft site. <membership defaultProvider="LdapMembershipProvider"> <providers> <add name="LdapMembership" type="Microsoft.Office.Server.Security.LDAPMembershipProvider, Microsoft.Office.Server, Version=12.0.0.0, Culture=neutral, PublicKeyToken=71E9BCE111E9429C" server="DC" port="389" useSSL="false" userDNAttribute="distinguishedName" userNameAttribute="sAMAccountName" userContainer="CN=Users,DC=userName,DC=local" userObjectClass="person" userFilter="(|(ObjectCategory=group)(ObjectClass=person))" scope="Subtree" otherRequiredUserAttributes="sn,givenname,cn" /> </providers> </membership> The site asked me to change the Server and Usercontainer attribute. I have modified the code to <membership defaultProvider="LdapMembershipProvider"> <providers> <add name="LdapMembership" type="Microsoft.Office.Server.Security.LDAPMembershipProvider, Microsoft.Office.Server, Version=12.0.0.0, Culture=neutral, PublicKeyToken=71E9BCE111E9429C" server=” infinmumcfac.inf.com” port="389" useSSL="false" userDNAttribute="distinguishedName" userNameAttribute="sAMAccountName" userContainer=" OU=Infotech,DC=inf,DC=com " userObjectClass="person" userFilter="(|(ObjectCategory=group)(ObjectClass=person))" scope="Subtree" otherRequiredUserAttributes="sn,givenname,cn" /> </providers> </membership> I placed this code in web.config file of central administration site and my sharepoint website . I am still facing login issues. Any help or insight would be highly grateful.Thanking in anticipation.

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  • Relating text fields to check boxes in Java

    - by Finzz
    This program requires the user to login and request a database to access. The program then gets a connection object, searches through the database storing the column names into a vector for later use. The problem comes with implementing text fields to allow the user to search for specific values within the database. I can get the check boxes and text fields to appear using a gridlayout and add them to a panel. How do I relate the text fields to their appropriate check box? I've tried adding them to a vector, but then they can't also be added to the panel as well. I've searched for a way to name the text fields as the loop cycles through the column names, but it seems impossible to do without having them declared ahead of time. This can't be done either, as it's impossible to determine the attributes that the user will request. I just need to be able to know the names of the text fields so I can test to see if the user entered information and perform the necessary logic. Let me know if you have to see the rest of the code to give an answer, but hopefully you get the general idea of what I'm trying to accomplish. Picture of UI: try { ResultSet r2 = con.getMetaData().getColumns("", "", rb.getText(), ""); colNames1 = new Vector<String>(); columns1 = new Vector<JCheckBox>(); while (r2.next()) { colNames1.add(r2.getString(4)); JCheckBox cb = new JCheckBox(r2.getString(4)); JTextField tf = new JTextField(10); columns1.add(cb); p3.add(cb); p3.add(tf); } }

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  • cakephp isAuthorized() not being called

    - by Jack B Nimble
    I am trying to use the isAuthorized() method to do a check for an admin flag, but the function never seems to be called. Even when I set the function to always return false, it allows any user. It just seems like it isn't being called. Do I need to do something more than setting $this-Auth-authorize = 'controller' ? from /app/app_controller.php class AppController extends Controller { var $components = array('Auth'); function beforeFilter() { $this->Auth->loginAction = array('controller' => 'users', 'action' => 'login'); $this->Auth->loginRedirect = array('controller' => 'pages', 'display' => 'home'); $this->Auth->logoutRedirect = '/'; $this->Auth->authorize = 'controller'; $this->Auth->userScope = array('User.active' => 1); } function isAuthorized() { if (strpos($this->action, "admin_") != false) { if ($this->Auth->user('isAdmin') == '0') { return false; } } return true; } }

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  • Strange befaviour of spring transaction support for JPA + Hibernate +@Transactional annotation

    - by abovesun
    I found out really strange behavior on relatively simple use case, probably I can't understand it because of not deep knowledges of spring @Transactional nature, but this is quite interesting. I have simple User dao that extends spring JpaDaoSupport class and contains standard save method: @Transactional public User save(User user) { getJpaTemplate().persist(user); return user; } If was working fine until I've add new method to same class: User getSuperUser(), this method should return user with isAdmin == true, and if there is no super user in db, method should create one. Thats how it was looking like: public User createSuperUser() { User admin = null; try { admin = (User) getJpaTemplate().execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { return em.createQuery("select u from UserImpl u where u.admin = true").getSingleResult(); } }); } catch (EmptyResultDataAccessException ex) { User admin = new User('login', 'password'); admin.setAdmin(true); save(admin); // THIS IS THE POINT WHERE STRANGE THING COMING OUT } return admin; } As you see code is strange forward and I was very confused when found out that no transaction was created and committed on invocation of save(admin) method and no new user wasn't actually created despite @Transactional annotation. In result we have situation: when save() method invokes from outside of UserDAO class - @Transactional annotation counted and user successfully created, but if save() invokes from inside of other method of the same dao class - @Transactional annotation ignored. Here how I was change save() method to force it always create transaction. public User save(User user) { getJpaTemplate().execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { em.getTransaction().begin(); em.persist(user); em.getTransaction().commit(); return null; } }); return user; } As you see I manually invoke begin and commit. Any ideas?

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  • Facebook connect with iPhone not working?

    - by Atulkumar V. Jain
    Hi Everybody, I am trying to use Facebook connect in my application, but its not working as I desire. When I am trying to use the API Key and the API SecretKey of my application which I have registered with the facebook its not working. I have downloaded the code for the facebook. In the SessionViewController.m file when I pass my key values its not working. What I am trying to achieve is, when the app launches the first page is the Facebook Login Page. The user enters his username and password and then the next view should display. But nothing is happening, even the label doesn't display the username. Heres the code which I am using - (void)request:(FBRequest*)request didLoad:(id)result { NSArray* users = result; NSDictionary* user = [users objectAtIndex:0]; NSString* name = [user objectForKey:@"name"]; _label.text = [NSString stringWithFormat:@"Logged in as %@",name]; NSLog(@"Username is :- %@",name); FrontController *main = [[FrontController alloc] init]; [self.view addSubview:main.view]; [main release]; } I am not able to figure out what is wrong with this code. When I try with some other key values such as the key for connect application its working fine. Can anyone help me with this... Thanx in advance...

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  • CSS Border spanning across another div

    - by Tux
    The problem is that the border of div#content also appears in div#navigation? <html> <head> <title>WUI</title> <style type="text/css"> div#header { } div#navigation { float: left; padding-right: 20pt; } div#content { border: 5px groove; } </style> </head> <body> <div id="header"> <h1>WUI</h1> </div> <br /> <div id="navigation"> <ul> <li>Home</li> <li>Login</li> </ul> </div> <div id="content"> <p>I like when you ride with that booty on me!</p> </div> </body> </html> EDIT: I want the left side (navigation) to appear as a sidebar to the left and the content after that (to the right). I'm applying the border to the content but that border also appears in div of navigation. I hope it is clear now.

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  • Learning OOP in PHP, trying to refactor my code. Can't connect to database anymore.

    - by Cortopasta
    Thought I understood how classes work, then I tried this code: class user { var $dbcon; var $dbinfo; var $con; var $error; function dbConnect() { $this->dbinfo['server'] = "localhost"; $this->dbinfo['database'] = "foolish_faith"; $this->dbinfo['user'] = "user"; $this->dbinfo['password'] = "password"; $this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database']; $this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']); $this->dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $this->error = $this->dbcon->errorInfo(); if ($error[0] != "") { print "Error!"; print_r($error); } } } Now it just spits out this error: Fatal error: Uncaught exception 'PDOException' with message 'invalid data source name' in E:\PortableApps\xampp\htdocs\dbcon.php:24 Stack trace: #0 E:\PortableApps\xampp\htdocs\dbcon.php(24): PDO-__construct('', NULL, NULL) #1 E:\PortableApps\xampp\htdocs\login.php(4): user-dbConnect() #2 {main} thrown in E:\PortableApps\xampp\htdocs\dbcon.php on line 24 Can anybody see what I'm doing wrong, as I'm sure it has to do with my lack of knowledge when it comes to classes?

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  • Make password case unsensitive in shared ASP.Net membership tables web ap

    - by bill
    Hi all, i have two webapps.. that share ASP.Net membership tables. Everything works fine except i cannot remove case-sensitivity in one of the apps the way i am doing it in the other. in the non-working app void Login1_LoggingIn(object sender, LoginCancelEventArgs e) { string username = Login1.UserName.Trim(); if (!string.IsNullOrEmpty(username)) { MembershipUser user = Membership.GetUser(username); if (user != null) { // Only adjust the UserName if the password is correct. This is more secure // so a hacker can't find valid usernames if we adjust the case of mis-cased // usernames with incorrect passwords. string password = Login1.Password.ToUpper(); if (Membership.ValidateUser(user.UserName, password)) { Login1.UserName = user.UserName; } } } } is not working. the password is stored as all upper case. Converted at the time the membership user is created! So if the password is PASSWORD, typing PASSWORD allows me to authenticate. but typing password does not! Even though i can see the string being sent is PASSWORD (converted with toUpper()). I am at a complete loss on this.. in the other app i can type in lower or upper or mixed and i am able to authenticate. In the other app i am not using the textboxes from the login control though.. not sure if this is making the difference??

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  • how to download data which upload to gae ,

    - by zjm1126
    this is my code : import os from google.appengine.ext import webapp from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app from google.appengine.ext import db #from login import htmlPrefix,get_current_user class MyModel(db.Model): blob = db.BlobProperty() class BaseRequestHandler(webapp.RequestHandler): def render_template(self, filename, template_args=None): if not template_args: template_args = {} path = os.path.join(os.path.dirname(__file__), 'templates', filename) self.response.out.write(template.render(path, template_args)) class upload(BaseRequestHandler): def get(self): self.render_template('index.html',) def post(self): file=self.request.get('file') obj = MyModel() obj.blob = db.Blob(file.encode('utf8')) obj.put() self.response.out.write('upload ok') class download(BaseRequestHandler): def get(self): #id=self.request.get('id') o = MyModel.all().get() #self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o))) self.response.out.write(o) application = webapp.WSGIApplication( [ ('/?', upload), ('/download',download), ], debug=True ) def main(): run_wsgi_app(application) if __name__ == "__main__": main() my index.html is : <form action="/" method="post"> <input type="file" name="file" /> <input type="submit" /> </form> and it show : <__main__.MyModel object at 0x02506830> but ,i don't want to see this , i want to download it , how to change my code to run, thanks

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