Search Results

Search found 89481 results on 3580 pages for 'new technology'.

Page 572/3580 | < Previous Page | 568 569 570 571 572 573 574 575 576 577 578 579  | Next Page >

  • Passing parameters in MVC

    - by Avinash
    Thare is two forms in a page first one for searching and another for deleting.... <table><tr><td> <% using(Html.BeginForm("ViewList","ControllerName", [values],FormMethod.Post,new{id="viewListForm"})) { %> Name: <%=Html.TextBox("Name", "[value]", new { maxlength = "250" })%> Location: <%=Html.TextBox("Location", "[Value]", new { maxlength = "250" })%> <input type="submit" id="Search" name="Search" value="Search" /> <% } %> </td></tr> <tr><td> <% using(Html.BeginForm("DeleteList","ControllerName", new { name=?,location=? },[values],FormMethod.Post, new{id="deleteListForm"})) { %> [here the code for all items displayed in a table.] <input type="submit" id="Delete" name="Delete" value="Delete" /> When delete buttom pressed i need to pass two parameters ie name and location. The values of name and location are in the above viewListForm. How i take this value from the viewListForm at run time ? <% } %> </td></tr><table>

    Read the article

  • how to change font color and size within single label component in flex

    - by Rees
    i'm trying to create a unordered list in Flex. My issue is that within each line, i want the word NEW to be a different font color and different font size from the rest of the label text. I am unsure of how to do this INLINE within the label component. Any thoughts anyone? <s:VGroup fontSize="15" color="#ffffff"> <s:Label text="\u2022 NEW Invite your friends!" /> <s:Label text="\u2022 NEW Features coming soon!" /> <s:Label text="\u2022 NEW Invite your friends!" /> </s:VGroup>

    Read the article

  • .NET Remoting Connecting to Wrong Host

    - by Dark Falcon
    I have an application I wrote which has been running well for 4 years. Yesterday they moved all their servers around and installed about 60 pending Windows updates, and now it is broken. The application makes use of remoting to update some information on another server (10.0.5.230), but when I try to create my remote object, I get the following exception: Note that it is trying to connect to 127.0.0.1, not the proper server. The server (10.0.5.230) is listening on port 9091 as it should. This same error is happening on all three terminal servers where this application is installed. Here is the code which registers the remoted object: public static void RegisterClient() { string lServer; RegistryKey lKey = Registry.CurrentUser.OpenSubKey("SOFTWARE\\Shoreline Teleworks\\ShoreWare Client"); if (lKey == null) throw new InvalidOperationException("Could not find Shoretel Call Manager"); object lVal = lKey.GetValue("Server"); if (lVal == null) throw new InvalidOperationException("Shoretel Call Manager did not specify a server name"); lServer = lVal.ToString(); IDictionary props = new Hashtable(); props["port"] = 0; string s = System.Guid.NewGuid().ToString(); props["name"] = s; ChannelServices.RegisterChannel(new TcpClientChannel(props, null), false); RemotingConfiguration.RegisterActivatedClientType(typeof(UpdateClient), "tcp://" + lServer + ":" + S_REMOTING_PORT + "/"); RemotingConfiguration.RegisterActivatedClientType(typeof(Playback), "tcp://" + lServer + ":" + S_REMOTING_PORT + "/"); } Here is the code which calls the remoted object: UpdateClient lUpdater = new UpdateClient(Settings.CurrentSettings.Extension.ToString()); lUpdater.SetAgentState(false); I have verified that the following URI is passed to RegisterActivatedClientType: "tcp://10.0.5.230:9091/" Why does this application try to connect to the wrong server?

    Read the article

  • Multiple infowindows - tearing my hair out

    - by thewinchester
    Ok, I'll admit I'm nowhere near the best programmer on the planet - and I'm used to the answer staring me right in the face but not making sense of it. Problem I need to display multiple markers on a map, each with their own infowindow. I have created the individual markers without a problem, but don't know how to create the infowindows for each. Steps so far I am generating a map using the V3 API within an ASP-based website, with markers being created from a set of DB records. The markers are created by looping through a rs and defining a marker() with the relevant variables: var myLatlng = new google.maps.LatLng(lat,long); var marker = new google.maps.Marker({ map: map, position: myLatlng, title: 'locationname', icon: 'http://google-maps-icons.googlecode.com/files/park.png' }); This is creating all the relevant markers in their correct locations. What I need to do now, and am not sure of how to achieve is give each of them their own unique infowindow which I can use to display information and links relevant to that marker. Source <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script> <script language="javascript"> $(document).ready(function() { //Google Maps var myOptions = { zoom: 5, center: new google.maps.LatLng(-26.66, 122.25), mapTypeControl: false, mapTypeId: google.maps.MapTypeId.ROADMAP, navigationControl: true, navigationControlOptions: { style: google.maps.NavigationControlStyle.SMALL } } var map = new google.maps.Map(document.getElementById("map_canvas"), myOptions); <!-- While locations_haslatlong not BOF.EOF --> <% While ((Repeat1__numRows <> 0) AND (NOT locations_haslatlong.EOF)) %> var myLatlng = new google.maps.LatLng(<%=(locations_haslatlong.Fields.Item("llat").Value)%>,<%=(locations_haslatlong.Fields.Item("llong").Value)%>); var marker = new google.maps.Marker({ map: map, position: myLatlng, title: '<%=(locations_haslatlong.Fields.Item("ldescription").Value)%>', icon: 'http://google-maps-icons.googlecode.com/files/park.png', clickable: true, }); <% Repeat1__index=Repeat1__index+1 Repeat1__numRows=Repeat1__numRows-1 locations_haslatlong.MoveNext() Wend %> <!-- End While locations_haslatlong not BOF.EOF --> google.maps.event.addListener(marker, 'click', function() { infowindow.open(map,marker); }); google.maps.event.addListener(marker, 'dblclick', function() { map.setZoom(14); }); });

    Read the article

  • AS3 variables handling by AVM/compiler/scope

    - by jchmielewski
    I have couple of questions about AS3 variables handling by AVM/compiler/scope .1. This code in Flash will throw an error: function myFunction() { var mc:MovieClip=new MovieClip(); var mc:MovieClip=new MovieClip(); } but it won`t throw an error in Flex (only warning in Editor). Why? .2. How Flash sees variables in loops? Apparently this: for (var i:int=0; i<2; i++) { var mc:MovieClip=new MovieClip(); } isn`t equal to just: var mc:MovieClip=new MovieClip(); var mc:MovieClip=new MovieClip(); because it will throw an error again as earlier in Flash, but in Flex in function not? Is Flash changing somehow my loop before compilation? .3. Where in a class in equivalent to timeline in Flash - where in class I would put code which I put normally on timeline (I assume it is not constructor because of what I have written earlier, or maybe it`s a matter of Flash/Flex compiler)?

    Read the article

  • Parallel processing via multithreading in Java

    - by Robz
    There are certain algorithms whose running time can decrease significantly when one divides up a task and gets each part done in parallel. One of these algorithms is merge sort, where a list is divided into infinitesimally smaller parts and then recombined in a sorted order. I decided to do an experiment to test whether or not I could I increase the speed of this sort by using multiple threads. I am running the following functions in Java on a Quad-Core Dell with Windows Vista. One function (the control case) is simply recursive: // x is an array of N elements in random order public int[] mergeSort(int[] x) { if (x.length == 1) return x; // Dividing the array in half int[] a = new int[x.length/2]; int[] b = new int[x.length/2+((x.length%2 == 1)?1:0)]; for(int i = 0; i < x.length/2; i++) a[i] = x[i]; for(int i = 0; i < x.length/2+((x.length%2 == 1)?1:0); i++) b[i] = x[i+x.length/2]; // Sending them off to continue being divided mergeSort(a); mergeSort(b); // Recombining the two arrays int ia = 0, ib = 0, i = 0; while(ia != a.length || ib != b.length) { if (ia == a.length) { x[i] = b[ib]; ib++; } else if (ib == b.length) { x[i] = a[ia]; ia++; } else if (a[ia] < b[ib]) { x[i] = a[ia]; ia++; } else { x[i] = b[ib]; ib++; } i++; } return x; } The other is in the 'run' function of a class that extends thread, and recursively creates two new threads each time it is called: public class Merger extends Thread { int[] x; boolean finished; public Merger(int[] x) { this.x = x; } public void run() { if (x.length == 1) { finished = true; return; } // Divide the array in half int[] a = new int[x.length/2]; int[] b = new int[x.length/2+((x.length%2 == 1)?1:0)]; for(int i = 0; i < x.length/2; i++) a[i] = x[i]; for(int i = 0; i < x.length/2+((x.length%2 == 1)?1:0); i++) b[i] = x[i+x.length/2]; // Begin two threads to continue to divide the array Merger ma = new Merger(a); ma.run(); Merger mb = new Merger(b); mb.run(); // Wait for the two other threads to finish while(!ma.finished || !mb.finished) ; // Recombine the two arrays int ia = 0, ib = 0, i = 0; while(ia != a.length || ib != b.length) { if (ia == a.length) { x[i] = b[ib]; ib++; } else if (ib == b.length) { x[i] = a[ia]; ia++; } else if (a[ia] < b[ib]) { x[i] = a[ia]; ia++; } else { x[i] = b[ib]; ib++; } i++; } finished = true; } } It turns out that function that does not use multithreading actually runs faster. Why? Does the operating system and the java virtual machine not "communicate" effectively enough to place the different threads on different cores? Or am I missing something obvious?

    Read the article

  • How to catch exception in the main thread if the exception occurs in the secondary thread?

    - by Ashish Ashu
    How to catch exception in the main thread if the exception occurs in the secondary thread? The code snippet for the scenario is given below: private void button1_Click(object sender, EventArgs e) { try { Thread th1 = new Thread(new ThreadStart(Test)); th1.Start(); } catch (Exception) { } } void Test() { for (int i = 0; i < 100; i++) { Thread.Sleep(100); if (i == 2) throw new MyException(); } } }

    Read the article

  • onListItemClick with Mulitple Value/Retrieving Value

    - by JuniorFlip
    Hello, I am trying to retrieve the value from a Arraylist/ArrayAdapter that I have populated. I believe my issue is at the Onitemclick event. What I would like to accomplished is that when I click on Yasmin, I can return the value of 8. Please let me know if I am on the right track import java.util.ArrayList; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.AdapterView; import android.widget.ArrayAdapter; import android.widget.ListView; import android.widget.TextView; import android.widget.AdapterView.OnItemClickListener; public class lister extends Activity { /** Called when the activity is first created. */ TextView txHomeTeam; protected ListView mFavlist; protected ArrayList fakeFavs = new ArrayList(); @Override public void onCreate(Bundle icicle) { super.onCreate(icicle); this.setContentView(R.layout.main); this.txHomeTeam = (TextView)this.findViewById(R.id.title); fakeFavs.add(new Favorite("John", "1")); fakeFavs.add(new Favorite("Yasmin", "8")); fakeFavs.add(new Favorite("Jack", "10")); //this.mFavlist = (ListView) this.findViewById(R.id.list_favorites); this.mFavlist = (ListView) this.findViewById(R.id.list_favorites); initListView(); mFavlist.setTextFilterEnabled(true); mFavlist.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView arg0, View view, int position, long id) { // user clicked a list item, //and read the value from <Favorite>.value //txHomeTeam.setText=???? } }); } public void refreshFavListItems() { mFavlist.setAdapter(new ArrayAdapter(this, android.R.layout.simple_list_item_1, fakeFavs)); } public void initListView() { /* Loads the items to the ListView. */ refreshFavListItems(); } protected class Favorite { protected String Detail; protected String value; protected Favorite(String Detail, String value) { this.Detail = Detail; this.value = value; } public String toString() { return Detail; } } }

    Read the article

  • JTree - Issues with adding of nodes

    - by John
    Hi. Im developing a system that stores courses that participants can apply to. I'm presenting the enrollments in a JTree in the courseadministratorGUI. My problem is that, for every enrollment it's adding a new courseNode. Been trying for many hours, and hope I can now get some advice that will point me in the correct direction. Thank you. private void updateJTree() { for (Category cat : catcontrol.getAllCategoriesList()) { category = new DefaultMutableTreeNode(cat); for (Course c : ccontrol.getAllCourses()) { if (cat.getIdCategory() == c.getIdCategory()) { for (Enrollment e : econtrol.getAllEnrollments()) { if (e.getIdCourse() == c.getIdCourse()) { if (cat.getIdCategory() == c.getIdCategory() && e.getCourse().equals(c)) { root.add(category); } if (c.getIdCourse() == e.getIdCourse()) { course = new DefaultMutableTreeNode(c); category.add(course); enrollment = new DefaultMutableTreeNode(e.getParticipant().getFirstNames()); course.add(enrollment); } } } } } } jTree1.setModel(new DefaultTreeModel(root)); jTree1.addTreeSelectionListener(this); jTree1.getSelectionModel().setSelectionMode(TreeSelectionModel.SINGLE_TREE_SELECTION); }

    Read the article

  • Database table copying

    - by vbNewbie
    I am trying to rectify a previous database creation with tables that contains data that needs to be saved. Instead of recreating a completely new database since some of the tables are still reusable, I need to split a table that exists into 2 new tables which I have done. Now I am trying to insert the data into the 2 new tables and because of duplicate data in the old table I am having a hard time doing this. Old table structure: ClientProjects clientId PK clientName clientProj hashkey MD5 (clientname and clientProj) new table structures: client clientId PK clientName projects queryId PK clientId PK projectName I hope this makes sense. The problem is that in the old table for example you have clients with multiple clientIds.

    Read the article

  • Locked DataGridView. Linq is a problem ?

    - by phenevo
    Hi, I get the collection from webservice: var allPlaceHolders = (from ph in new MyService().GetPlaceHolders() select ph).Select(l => new { Code = l.Code, Name = l.Name, Related = false }).ToList(); dgPlaceHoldersAdd.DataSource = allPlaceHolders; Designer.cs: this.dgPlaceHoldersAdd.ColumnHeadersHeightSizeMode = System.Windows.Forms.DataGridViewColumnHeadersHeightSizeMode.AutoSize; this.dgPlaceHoldersAdd.Location = new System.Drawing.Point(3, 54); this.dgPlaceHoldersAdd.Name = "dgPlaceHoldersAdd"; this.dgPlaceHoldersAdd.RowHeadersVisible = false; this.dgPlaceHoldersAdd.Size = new System.Drawing.Size(286, 151); this.dgPlaceHoldersAdd.TabIndex = 15; The problem is, that I can't changing value of checkBox column. I has enabled AutoGeneratedColumns (In datagridview at start there is not any column)

    Read the article

  • ArrayList.Sort should be a stable sort with an IComparer but is not?

    - by Kaleb Pederson
    A stable sort is a sort that maintains the relative ordering of elements with the same value. The docs on ArrayList.Sort say that when an IComparer is provided the sort is stable: If comparer is set to null, this method performs a comparison sort (also called an unstable sort); that is, if two elements are equal, their order might not be preserved. In contrast, a stable sort preserves the order of elements that are equal. To perform a stable sort, you must implement a custom IComparer interface. Unless I'm missing something, the following testcase shows that ArrayList.Sort is not using a stable sort: internal class DisplayOrdered { public int ID { get; set; } public int DisplayOrder { get; set; } public override string ToString() { return string.Format("ID: {0}, DisplayOrder: {1}", ID, DisplayOrder); } } internal class DisplayOrderedComparer : IComparer { public int Compare(object x, object y) { return ((DisplayOrdered)x).DisplayOrder - ((DisplayOrdered)y).DisplayOrder; } } [TestFixture] public class ArrayListStableSortTest { [Test] public void TestWeblinkCallArrayListIsSortedUsingStableSort() { var call1 = new DisplayOrdered {ID = 1, DisplayOrder = 0}; var call2 = new DisplayOrdered {ID = 2, DisplayOrder = 0}; var call3 = new DisplayOrdered {ID = 3, DisplayOrder = 2}; var list = new ArrayList {call1, call2, call3}; list.Sort(new DisplayOrderedComparer()); // expected order (by ID): 1, 2, 3 (because the DisplayOrder // is equal for ID's 1 and 2, their ordering should be // maintained for a stable sort.) Assert.AreEqual(call1, list[0]); // Actual: ID=2 ** FAILS Assert.AreEqual(call2, list[1]); // Actual: ID=1 Assert.AreEqual(call3, list[2]); // Actual: ID=3 } } Am I missing something? If not, would this be a documentation bug or a library bug? Apparently using an OrderBy in Linq gives a stable sort.

    Read the article

  • to connect matlab with java

    - by user304005
    Through the below given code I was able to connect to matlab. But I was not able to execute the script file containing matlab code...Please help me to modify the code so as to execute the matlab code.... Here luck2 is a .m file.... import java.io.InputStreamReader; import java.io.*; public class matlab { private static File myMATLABScript; public static String runScript(File luck2) { String output = "" ; String error = ""; try { String commandToRun ="C:\\Program Files\\MATLAB\\R2009a\\bin\\matlab -nodisplay <" + "Z:\\sem\\java\\luck2"; //String commandToRun = "matlab -nosplash -r myMATLABScript -nodisplay -nodesktop < " + opentxt; System.out.println(commandToRun); Process p = Runtime.getRuntime().exec(commandToRun); String s; BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream())); BufferedReader stdError = new BufferedReader(new InputStreamReader(p.getErrorStream())); System.out.println("\nHere is the standard output of the command:\n"); while ((s = stdInput.readLine()) != null) { System.out.println("haiiiiiiiiiiii"); output = s + "\n"; System.out.println(s); } while ((s = stdError.readLine()) != null) { error = s + "\n"; System.out.println(s); } } catch (Exception e) { System.out.println("exception happened here what I know:"); e.printStackTrace(); System.exit(-1); } return output + error; } public static void main(String[] args) throws IOException { matlab m = new matlab(); matlab.runScript(myMATLABScript); //matlab.runScript(); } }

    Read the article

  • C#: Hook up all events from object in single statement.

    - by David
    In my domain layer all domain objects emit events (of type InvalidDomainObjectEventHandler) to indicate invalid state when the IsValid property is called. On an aspx codebehind, I have to manually wire up the events for the domain object like this: _purchaseOrder.AmountIsNull += new DomainObject.InvalidDomainObjectEventHandler(HandleDomainObjectEvent); _purchaseOrder.NoReason += new DomainObject.InvalidDomainObjectEventHandler(HandleDomainObjectEvent); _purchaseOrder.NoSupplier += new DomainObject.InvalidDomainObjectEventHandler(HandleDomainObjectEvent); _purchaseOrder.BothNewAndExistingSupplier += new DomainObject.InvalidDomainObjectEventHandler(HandleDomainObjectEvent); Note that the same method is called in each case since the InvalidDomainobjectEventArgs class contains the message to display. Is there any way I can write a single statement to wire up all events of type InvalidDomainObjectEventHandler in one go? Thanks David

    Read the article

  • Need a SQL statement focus on combination of tables but entries always with uinque ID

    - by Registered User KC
    Hi All, I need SQL code to solve the tables combination problem, described on below: Table old data: name version status lastupdate ID A 0.1 on 6/8/2010 1 B 0.1 on 6/8/2010 2 C 0.1 on 6/8/2010 3 D 0.1 on 6/8/2010 4 E 0.1 on 6/8/2010 5 F 0.1 on 6/8/2010 6 G 0.1 on 6/8/2010 7 Table new data: name version status lastupdate ID A 0.1 on 6/18/2010 #B entry deleted C 0.3 on 6/18/2010 #version_updated C1 0.1 on 6/18/2010 D 0.1 on 6/18/2010 E 0.1 off 6/18/2010 #status_updated F 0.1 on 6/18/2010 G 0.1 on 6/18/2010 H 0.1 on 6/18/2010 #new_added H1 0.1 on 6/18/2010 #new_added the difference of new data and old date: B entry deleted C entry version updated E entry status updated C1/H/H1 entry new added What I want is always keeping the ID - name mapping relationship in old data table no matter how data changed later, a.k.a the name always has a unique ID number bind with it. If entry has update, then update the data, if entry is new added, insert to the table then give a new assigned unique ID. However, I can only use SQL with simple select or update statement then it may too hard for me to write such code, then I hope someone with expertise can give direction, no details needed on the different of SQL variant, a standard sql code as sample is enough. Thanks in advance! Rgs KC

    Read the article

  • Why no ArgumentEmptyException in .NET ?

    - by Andrei Rinea
    I am beginning to think I am doing something wrong. I mean they did place System.String.IsNullOrWhitespace finally but no ArgumentEmptyException class. public FilterItem(string name, IEnumerable<string> extensions) { if (string.IsNullOrWhiteSpace(name)) { throw new ArgumentNullException("name"); } if (extensions == null) { throw new ArgumentNullException("extensions"); } if (extensions.Count() == 0) { throw new ArgumentOutOfRangeException("extensions"); } this.Name = name; this.Extensions = extensions; } throwing an ArgumentOutOfRangeException feels unnatural. Also an instance of ArgumentException is too general in my opinion. It's easy to me to create a new exception class call it this way and have it over with. What bugs me is that it's not in the BCL/FCL and I am beginning to think there's a good reason not to have it. Should there be one?

    Read the article

  • deadlock when using WCF Duplex Polling with Silverlight

    - by Kobi Hari
    Hi all. I have followed Tomek Janczuk's demonstration on silverlight tv to create a chat program that uses WCF Duplex Polling web service. The client subscribes to the server, and then the server initiates notifications to all connected clients to publish events. The Idea is simple, on the client, there is a button that allows the client to connect. A text box where the client can write a message and publish it, and a bigger text box that presents all the notifications received from the server. I connected 3 clients (in different browsers - IE, Firefox and Chrome) and it all works nicely. They send messages and receive them smoothly. The problem starts when I close one of the browsers. As soon as one client is out, the other clients get stuck. They stop getting notifications. I am guessing that the loop in the server that goes through all the clients and sends them the notifications is stuck on the client that is now missing. I tried catching the exception and removing it from the clients list (see code) but it still does not help. any ideas? The server code is as follows: using System; using System.Linq; using System.Runtime.Serialization; using System.ServiceModel; using System.ServiceModel.Activation; using System.Collections.Generic; using System.Runtime.Remoting.Channels; namespace ChatDemo.Web { [ServiceContract] public interface IChatNotification { // this will be used as a callback method, therefore it must be one way [OperationContract(IsOneWay=true)] void Notify(string message); [OperationContract(IsOneWay = true)] void Subscribed(); } // define this as a callback contract - to allow push [ServiceContract(Namespace="", CallbackContract=typeof(IChatNotification))] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] [ServiceBehavior(InstanceContextMode=InstanceContextMode.Single)] public class ChatService { SynchronizedCollection<IChatNotification> clients = new SynchronizedCollection<IChatNotification>(); [OperationContract(IsOneWay=true)] public void Subscribe() { IChatNotification cli = OperationContext.Current.GetCallbackChannel<IChatNotification>(); this.clients.Add(cli); // inform the client it is now subscribed cli.Subscribed(); Publish("New Client Connected: " + cli.GetHashCode()); } [OperationContract(IsOneWay = true)] public void Publish(string message) { SynchronizedCollection<IChatNotification> toRemove = new SynchronizedCollection<IChatNotification>(); foreach (IChatNotification channel in this.clients) { try { channel.Notify(message); } catch { toRemove.Add(channel); } } // now remove all the dead channels foreach (IChatNotification chnl in toRemove) { this.clients.Remove(chnl); } } } } The client code is as follows: void client_NotifyReceived(object sender, ChatServiceProxy.NotifyReceivedEventArgs e) { this.Messages.Text += string.Format("{0}\n\n", e.Error != null ? e.Error.ToString() : e.message); } private void MyMessage_KeyDown(object sender, KeyEventArgs e) { if (e.Key == Key.Enter) { this.client.PublishAsync(this.MyMessage.Text); this.MyMessage.Text = ""; } } private void Button_Click(object sender, RoutedEventArgs e) { this.client = new ChatServiceProxy.ChatServiceClient(new PollingDuplexHttpBinding { DuplexMode = PollingDuplexMode.MultipleMessagesPerPoll }, new EndpointAddress("../ChatService.svc")); // listen for server events this.client.NotifyReceived += new EventHandler<ChatServiceProxy.NotifyReceivedEventArgs>(client_NotifyReceived); this.client.SubscribedReceived += new EventHandler<System.ComponentModel.AsyncCompletedEventArgs>(client_SubscribedReceived); // subscribe for the server events this.client.SubscribeAsync(); } void client_SubscribedReceived(object sender, System.ComponentModel.AsyncCompletedEventArgs e) { try { Messages.Text += "Connected!\n\n"; gsConnect.Color = Colors.Green; } catch { Messages.Text += "Failed to Connect!\n\n"; } } And the web config is as follows: <system.serviceModel> <extensions> <bindingExtensions> <add name="pollingDuplex" type="System.ServiceModel.Configuration.PollingDuplexHttpBindingCollectionElement, System.ServiceModel.PollingDuplex, Version=4.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35"/> </bindingExtensions> </extensions> <behaviors> <serviceBehaviors> <behavior name=""> <serviceMetadata httpGetEnabled="true"/> <serviceDebug includeExceptionDetailInFaults="false"/> </behavior> </serviceBehaviors> </behaviors> <bindings> <pollingDuplex> <binding name="myPollingDuplex" duplexMode="MultipleMessagesPerPoll"/> </pollingDuplex> </bindings> <serviceHostingEnvironment aspNetCompatibilityEnabled="true" multipleSiteBindingsEnabled="true"/> <services> <service name="ChatDemo.Web.ChatService"> <endpoint address="" binding="pollingDuplex" bindingConfiguration="myPollingDuplex" contract="ChatDemo.Web.ChatService"/> <endpoint address="mex" binding="mexHttpBinding" contract="IMetadataExchange"/> </service> </services> </system.serviceModel>

    Read the article

  • nested form & habtm

    - by brewster
    so i am trying to save to a join table in a habtm relationship, but i am having problems. from my view, i pass in a group id with: = link_to "Create New User", new_user_url(:group => 1) User model (user.rb) class User < ActiveRecord::Base has_and_belongs_to_many :user_groups accepts_nested_attributes_for :user_groups end UserGroups model (user_groups.rb) class UserGroup < ActiveRecord::Base has_and_belongs_to_many :users end users_controller.rb def new @user = User.new(:user_group_ids => params[:group]) end in the new user view, i have access to the User.user_groups object, however when i submit the form, not only does it not save into my join table (user_groups_users), but the object is no longer there. all the other objects & attributes of my User object are persistent except for the user group. i just started learning rails, so maybe i am missing something conceptually here, but i have been really struggling with this.

    Read the article

  • Test if file exists

    - by klaus-vlad
    Hi, I'm trying to open a file in android like this : try { FileInputStream fIn = context.openFileInput(FILE); DataInputStream in = new DataInputStream(fIn); BufferedReader br = new BufferedReader(new InputStreamReader(in)); if(in!=null) in.close(); } catch(Exception e) { } , but in case the file does not exists a file not found exception is thrown . I'd like to know how could I test if the file exists before attempting to open it.

    Read the article

  • Java Http request on api.stackexchange with json response

    - by taoder
    I'm trying to use the api-stackexchange with java but when I do the request and try to parse the response with a json parser I have an error. public ArrayList<Question> readJsonStream(InputStream in) throws IOException { JsonReader reader = new JsonReader(new InputStreamReader(in, "UTF-8")); reader.setLenient(true); try { System.out.println(reader.nextString()); // ? special character return readItem(reader); } finally { reader.close(); } } public ArrayList<Question> readItem(JsonReader reader) throws IOException { ArrayList<Question> questions = new ArrayList<Question>(); reader.beginObject(); while (reader.hasNext()) { System.out.println("here");//not print the error is before String name = reader.nextName(); if (name.equals("items")) { questions = readQuestionsArray(reader); } } reader.endObject(); return questions; } public final static void main(String[] args) throws Exception { URIBuilder builder = new URIBuilder(); builder.setScheme("http").setHost("api.stackexchange.com").setPath("/2.0/search") .setParameter("site", "stackoverflow") .setParameter("intitle" ,"workaround") .setParameter("tagged","javascript"); URI uri = builder.build(); String surl = fixEncoding(uri.toString()+"&filter=!)QWRa9I-CAn0PqgUwq7)DVTM"); System.out.println(surl); Test t = new Test(); try { URL url = new URL(surl); t.readJsonStream(url.openStream()); } catch (IOException e) { e.printStackTrace(); } } And the error is: com.google.gson.stream.MalformedJsonException: Expected literal value at line 1 column 19 Here is an example of the Json : { "items": [ { "question_id": 10842231, "score": 0, "title": "How to push oath token to LocalStorage or LocalSession and listen to the Storage Event? (SoundCloud Php/JS bug workaround)", "tags": [ "javascript", "javascript-events", "local-storage", "soundcloud" ], "answers": [ { "question_id": 10842231, "answer_id": 10857488, "score": 0, "is_accepted": false } ], "link": "http://stackoverflow.com/questions/10842231/how-to-push-oath-token-to-localstorage-or-localsession-and-listen-to-the-storage", "is_answered": false },... So what's the problem? Is the Json really malformed? Or did I do something not right? Thanks, Anthony

    Read the article

  • Retrieve XML from URL

    - by Pl4za
    I am having some problems retrieving a xml from url with the following code: private static String getAlbumArt(String artistName, String albumName){ try{ XMLParser xml_parser = new XMLParser(); String xml = xml_parser.getXmlFromUrl(getAlbumURL(artistName, albumName)); Document doc = xml_parser.getDomElement(xml); NodeList N = doc.getElementsByTagName("album"); Node node = N.item(0); NodeList N2 = node.getChildNodes(); System.out.println("1------"); for (int i = 0; i < N2.getLength(); i++) { Node detailNode = N2.item(i); if (detailNode.getNodeType() == Node.ELEMENT_NODE) { System.out.println("2------"); if (detailNode.getNodeName().equalsIgnoreCase("image")) { String sizeVal = ((Element) detailNode).getAttribute("size"); String url = detailNode.getTextContent(); if (sizeVal.equalsIgnoreCase("large")) { return url; } } } } } catch (Exception e){ } return null; } The xml function which i call in the above code: public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } getAlbumURL: public static String getAlbumURL(String artist, String album){ return URL_METHOD + METHOD_GETALBUM + AMPERSAND + API_KEY + AMPERSAND + PARAM_ARTIST + artist + AMPERSAND + PARAM_ALBUM + album; } XMLparser: public class XMLParser { // constructor public XMLParser() { } //Get XML from URL public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } //Get dom element public Document getDomElement(String xml){ Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } //Get nod element public final String getElementValue(Node elem ) { Node child; if( elem != null){ if (elem.hasChildNodes()){ for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ if( child.getNodeType() == Node.TEXT_NODE ){ return child.getNodeValue(); } } } } return ""; } //Get element value public String getValue(Element item, String str) { NodeList nlList = item.getElementsByTagName(str).item(0).getChildNodes(); Node nValue = (Node) nlList.item(0); return nValue.getNodeValue(); } } Any ideas ? I seriously don't know what is wrong.. I used this before and it worked.

    Read the article

  • Error while sending message using xmpp4r_facebook

    - by santu
    I am following the instructions presented in http://dalibornasevic.com/posts/35-how-to-send-private-messages-with-facebook-api to send message to my friend and currently testing from command line. Following is the code I am using require 'xmpp4r_facebook' id = '<my facebook id>@chat.facebook.com' to = '<my friend facebook id>@chat.facebook.com' body = "hello, Im not spam!" subject = 'message from ruby' message = Jabber::Message.new to, body message.subject = subject client = Jabber::Client.new Jabber::JID.new(id) client.connect client.auth_sasl(Jabber::SASL::XFacebookPlatform.new(client, '<App ID>', '<access token got from https://developers.facebook.com/tools/explorer>', 'App Secret'), nil) I get the error RuntimeError: not-authorized from /Users/apple/.rvm/gems/ruby-1.9.3-p194/gems/xmpp4r_facebook-0.1.1/lib/xmpp4r_facebook.rb:103:in `auth' from /Users/apple/.rvm/gems/ruby-1.9.3-p194/gems/xmpp4r-0.5/lib/xmpp4r/client.rb:171:in `auth_sasl' from (irb):12 from /Users/apple/.rvm/rubies/ruby-1.9.3-p194/bin/irb:16:in `<main>'

    Read the article

  • commons-exec: hanging when I call executor.execute(commandLine);

    - by Stefan Kendall
    I have no idea why this is hanging. I'm trying to capture output from a process run through commons-exec, and I continue to hang. I've provided an example program to demonstrate this behavior below. import java.io.DataInputStream; import java.io.IOException; import java.io.PipedInputStream; import java.io.PipedOutputStream; import org.apache.commons.exec.CommandLine; import org.apache.commons.exec.DefaultExecutor; import org.apache.commons.exec.ExecuteException; import org.apache.commons.exec.PumpStreamHandler; public class test { public static void main(String[] args) { String command = "java"; PipedOutputStream output = new PipedOutputStream(); PumpStreamHandler psh = new PumpStreamHandler(output); CommandLine cl = CommandLine.parse(command); DefaultExecutor exec = new DefaultExecutor(); DataInputStream is = null; try { is = new DataInputStream(new PipedInputStream(output)); exec.setStreamHandler(psh); exec.execute(cl); } catch (ExecuteException ex) { } catch (IOException ex) { } System.out.println("huh?"); } }

    Read the article

< Previous Page | 568 569 570 571 572 573 574 575 576 577 578 579  | Next Page >