form designer - Page 574

parentNode.parentNode.rowindex to delete a row in a dynamic table

- by billy85

I am creating my rows dynamically when the user clicks on "Ajouter". <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <script> function getXhr(){ var xhr = null; if(window.XMLHttpRequest) // Firefox and others xhr = new XMLHttpRequest(); else if(window.ActiveXObject){ // Internet Explorer try { xhr = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xhr = new ActiveXObject("Microsoft.XMLHTTP"); } } else { // XMLHttpRequest not supported by your browser alert("Votre navigateur ne supporte pas les objets XMLHTTPRequest..."); xhr = false; } return xhr } /** * method called when the user clicks on the button */ function go(){ var xhr = getXhr() // We defined what we gonna do with the response xhr.onreadystatechange = function(){ // We do somthing once the server's response is OK if(xhr.readyState == 4 && xhr.status == 200){ //alert(xhr.responseText); var body = document.getElementsByTagName("body")[0]; // Retrieve <table> ID and create a <tbody> element var tbl = document.getElementById("table"); var tblBody = document.createElement("tbody"); var row = document.createElement("tr"); // Create <td> elements and a text node, make the text // node the contents of the <td>, and put the <td> at // the end of the table row var cell_1 = document.createElement("td"); var cell_2 = document.createElement("td"); var cell_3 = document.createElement("td"); var cell_4 = document.createElement("td"); // Create the first cell which is a text zone var cell1=document.createElement("input"); cell1.type="text"; cell1.name="fname"; cell1.size="20"; cell1.maxlength="50"; cell_1.appendChild(cell1); // Create the second cell which is a text area var cell2=document.createElement("textarea"); cell2.name="fdescription"; cell2.rows="2"; cell2.cols="30"; cell_2.appendChild(cell2); var cell3 = document.createElement("div"); cell3.innerHTML=xhr.responseText; cell_3.appendChild(cell3); // Create the fourth cell which is a href var cell4 = document.createElement("a"); cell4.appendChild(document.createTextNode("[Delete]")); cell4.setAttribute("href","javascrit:deleteRow();"); cell_4.appendChild(cell4); // add cells to the row row.appendChild(cell_1); row.appendChild(cell_2); row.appendChild(cell_3); row.appendChild(cell_4); // add the row to the end of the table body tblBody.appendChild(row); // put the <tbody> in the <table> tbl.appendChild(tblBody); // appends <table> into <body> body.appendChild(tbl); // sets the border attribute of tbl to 2; tbl.setAttribute("border", "1"); } } xhr.open("GET","fstatus.php",true); xhr.send(null); } </head> <body > <h1> Create an Item </h1> <form method="post"> <table align="center" border = "2" cellspacing ="0" cellpadding="3" id="table"> <tr><td><b>Functionality Name:</b></td> <td><b>Description:</b></td> <td><b>Status:</b></td> <td><input type="button" Name= "Ajouter" Value="Ajouter" onclick="go()"></td></tr> </table> </form> </body> </html> Now, I would like to use the href [Delete] to delete one particular row. I wrote this: <script type="text/javascript"> function deleteRow(r){ var i=r.parentNode.parentNode.rowIndex; document.getElementById('table').deleteRow(i); } </script> When I change the first code like this: cell4.setAttribute("href","javascrit:deleteRow(this);"); I got an error: The page cannot be displayed. I am redirected to a new pagewhich can not be displayed. How could I delete my row by using the function deleteRow(r)? table is the id of my table Thanks. Billy85

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