Search Results

Search found 20978 results on 840 pages for 'input stream'.

Page 575/840 | < Previous Page | 571 572 573 574 575 576 577 578 579 580 581 582  | Next Page >

  • How to use libavformat for a separate encoder?

    - by Brendon Tsai
    I've build a encoder based on the sample of QUALCOMM, which captures the video and compresses it into h264 file. I am using Android 4.2.2. Now I want to add a mp4 muxer into this encoder(actually, just video will be fine, I don't need audio). I want to use FFMpeg. But after I read the example, I found out that the muxer was using the encoder of FFMpeg. I don't know how to use the muxer part for another encoder. I've read this post, but I don't understand how the code provide video stream to the muxer. I think that mainly because I don't understand these code: AVCodecContext * strmCodec = oFmtCtx->streams[0]->codec; // Fill the required properties for codec context. // *from the documentation: // *The user sets codec information, the muxer writes it to the output. // *Mandatory fields as specified in AVCodecContext // *documentation must be set even if this AVCodecContext is // *not actually used for encoding. my_tune_codec(strmCodec); Can anyone give me a hint? Thank you!

    Read the article

  • php lampp permissions of fopen function

    - by marmoushismail
    hi i'm programming php using: netbeans 6.8 lampp for ubuntu (xampp) apache which came with xampp $fh = fopen("testfile2.txt", 'w') or die("Failed to create file"); $text ="hello man cool good"; fwrite($fh, $text) or die("Could not write to file"); fclose($fh); echo "File 'testfile.txt' written successfully"; //i get the next error: Warning: fopen(testfile2.txt) [function.fopen]: failed to open stream: Permission denied in /home/marmoush/allprojects/phpprojects/myindex.php on line 91 Failed to create file anyway i know what this error is; it's about folder and files permissions; i looked into the folder permission tab made access available for "others" group ( to read and write) the program worked result was a file (test.txt) so i looked at the created file permission it appears to be that (php , xampp or whoever) creates file with (nobody permission) I have 2 QUESTIONS: 1- what if i need the file created by (php code and xampp ) to have the "root or user or myname" permissions ?? where to set this setting 2-also my concern (what if i send this files to actual web server will it make nobody permissions also nobody ? when they create files

    Read the article

  • jQuery , Trigger change event on newly created elements

    - by kwhohasamullet
    Hi Guys, I have a button in a form that when clicked adds another set of form fields, In these form fields there are 2 drop downs where the contents of the 2nd dropdown rely on what is selected in the first dropdown... What i want to do is when the new form field button is clicked for the new items to be added and then the change event to be triggered on the drop down that was created so what only that drop down changes and not all the drop downs with the same name currently in that form. THe first drop down is called product Category The code for the addFormField function is: function addFormField() { var id = document.getElementById("field_id").value; $("#products").append("<table width='600' cellpadding='5' cellspacing='0' class='Add_Products' id='row" + id + "'><td width='250' class='left'><label>Select Product Category</label></td><td class='right' ><label><select name='" + id + "' id='ProductCategory'><?php foreach($categories as $key=>$category){ echo "<option value=".$key.">".$category."</option>"; } ?></select></label></td></tr><tr><td width='250' class='left'><label>Select Product Template</label></td><td class='right' ><label><select name='data[QuoteItem][" + id + "][product_id]' id='QuoteItem" + id + "product_id' class='Product' title='" + id + "'></select></label></td></tr><tr ><td class='left'>Name</td><td class='right'><label><input name='data[QuoteItem][" + id + "][name]' type='text' id='QuoteItem" + id + "name' size='50' /></label></td></tr><tr ><td class='left'>Price (ex GST)</td><td class='right'><input type='text' name='data[QuoteItem][" + id + "][price]' id='QuoteItem" + id + "price' onchange='totalProductPrice();' class='quote-item-price' value='0' /></td></tr><tr><td class='left'>Description</td><td class='right'><label><textarea name='data[QuoteItem][" + id + "][description]' cols='38' rows='5' id='QuoteItem" + id + "description'></textarea></label></td></tr><tr><td><a href='#' onClick='removeFormField(\"#row" + id + "\"); return false;'>Remove</a></td></tr></table>"); $('#row' + id).highlightFade({ speed:1000 }); id = (id - 1) + 2; document.getElementById("field_id").value = id; } The code that detects change in ProductCategory dropdown and triggers the AJAX is below: $("select#ProductCategory").live('change', function(){ var url = base + "/quotes/productList/" + $(this).val() + ""; var id = $(this).attr('name'); $.getJSON(url,{id: $(this).val(), ajax: 'true'}, function(j){ var options = ''; options += '<option value="0">None</option>'; $.each(j, function(key, value){ options += '<option value="' + key + '">' + value + '</option>'; }) $("select#QuoteItem" + id + "product_id").html(options); }) }).trigger('change'); I have been trying all afternoon to work this out and the closest one i got to work applied the returned ajax values to all items. Currently using the live function people can add new fields and are able to use the drops down independant of each other dropdown but its only when the field is first added that i have trouble getting is populated Thanks in advance for any help

    Read the article

  • PHP Outputting File Attachments with Headers

    - by OneNerd
    After reading a few posts here I formulated this function which is sort of a mishmash of a bunch of others: function outputFile( $filePath, $fileName, $mimeType = '' ) { // Setup $mimeTypes = array( 'pdf' => 'application/pdf', 'txt' => 'text/plain', 'html' => 'text/html', 'exe' => 'application/octet-stream', 'zip' => 'application/zip', 'doc' => 'application/msword', 'xls' => 'application/vnd.ms-excel', 'ppt' => 'application/vnd.ms-powerpoint', 'gif' => 'image/gif', 'png' => 'image/png', 'jpeg' => 'image/jpg', 'jpg' => 'image/jpg', 'php' => 'text/plain' ); // Send Headers //-- next line fixed as per suggestion -- header('Content-Type: ' . $mimeTypes[$mimeType]); header('Content-Disposition: attachment; filename="' . $fileName . '"'); header('Content-Transfer-Encoding: binary'); header('Accept-Ranges: bytes'); header('Cache-Control: private'); header('Pragma: private'); header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); readfile($filePath); } I have a php page (file.php) which does something like this (lots of other code stripped out): // I run this thru a safe function not shown here $safe_filename = $_GET['filename']; outputFile ( "/the/file/path/{$safe_filename}", $safe_filename, substr($safe_filename, -3) ); Seems like it should work, and it almost does, but I am having the following issues: When its a text file, I am getting a strange symbol as the first letter in the text document When its a word doc, it is corrupt (presumably that same first bit or byte throwing things off). I presume all other file types will be corrupt - have not even tried them Any ideas on what I am doing wrong? Thanks - UPDATE: changed line of code as suggested - still same issue.

    Read the article

  • How can I write an XML on my hard drive to GetRequestStream

    - by swolff1978
    I need to post raw xml to a site and read the response. With the following code I keep getting an "Unknown File Format" error and I'm not sure why. XmlDocument sampleRequest = new XmlDocument(); sampleRequest.Load(@"C:\SampleRequest.xml"); byte[] bytes = Encoding.UTF8.GetBytes(sampleRequest.ToString()); string uri = "https://www.sample-gateway.com/gw.aspx"; req = WebRequest.Create(uri); req.Method = "POST"; req.ContentLength = bytes.Length; req.ContentType = "text/xml"; using (var requestStream = req.GetRequestStream()) { requestStream.Write(bytes, 0, bytes.Length); } // Send the data to the webserver rsp = req.GetResponse(); XmlDocument responseXML = new XmlDocument(); using (var responseStream = rsp.GetResponseStream()) { responseXML.Load(responseStream); } I am fairly certain my issue is what/how I am writing to the requestStream so.. How can I modify that code so that I may write an xml located on the hard drive to the request stream?

    Read the article

  • Saving ntext data from SQL Server to file directory using asp

    - by April
    A variety of files (pdf, images, etc.) are stored in a ntext field on a MS SQL Server. I am not sure what type is in this field, other than it shows question marks and undefined characters, I am assuming they are binary type. The script is supposed to iterate through the rows and extract and save these files to a temp directory. "filename" and "contenttype" are given, and "data" is whatever is in the ntext field. I have tried several solutions: 1) data.SaveToFile "/temp/"&filename, 2 Error: Object required: '????????????????????' ??? 2) File.WriteAllBytes "/temp/"&filename, data Error: Object required: 'File' I have no idea how to import this, or the Server for MapPath. (Cue: what a noob!) 3) Const adTypeBinary = 1 Const adSaveCreateOverWrite = 2 Dim BinaryStream Set BinaryStream = CreateObject("ADODB.Stream") BinaryStream.Type = adTypeBinary BinaryStream.Open BinaryStream.Write data BinaryStream.SaveToFile "C:\temp\" & filename, adSaveCreateOverWrite Error: Arguments are of the wrong type, are out of acceptable range, or are in conflict with one another. 4) Response.ContentType = contenttype Response.AddHeader "content-disposition","attachment;" & filename Response.BinaryWrite data response.end This works, but the file should be saving to the server instead of popping up save-as dialog. I am not sure if there is a way to save the response to file. Thanks for shedding light on any of these problems!

    Read the article

  • What's causing this permission's error and how can I work around it?

    - by Scott B
    Warning: move_uploaded_file(/home/site/public_html/wp-content/themes/mytheme/upgrader.zip) [function.move-uploaded-file]: failed to open stream: Permission denied in /home/site/public_html/wp-content/themes/mytheme/uploader.php on line 79 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phptempfile' to '/home/site/public_html/wp-content/themes/mytheme/upgrader.zip' in /home/site/public_html/wp-content/themes/mytheme/uploader.php on line 79 There was a problem. Sorry! Code is below for that line... // permission settings for newly created folders $chmod = 0755; // Ensures that the correct file was chosen $accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/s-compressed'); foreach($accepted_types as $mime_type) { if($mime_type == $type) { $okay = true; break; } } $okay = strtolower($name[1]) == 'zip' ? true: false; if(!$okay) { die("This upgrader requires a zip file. Please make sure your file is a valid zip file with a .zip extension"); } //mkdir($target); $saved_file_location = $target . $filename; //Next line is 79 if(move_uploaded_file($source, $saved_file_location)) { openZip($saved_file_location); } else { die("There was a problem. Sorry!"); }

    Read the article

  • How do you place an Excel Sheet/Workbook onto a C# .NET Winform?

    - by incognick
    I am trying to create a stand alone application in Visual Studio 2008 C# .Net that will house Excel Workbooks (2007). I am using Office.Interop in order to create the Excel application and I open the workbooks via Workbooks.Open(...). The Interop does not provide any functionality to "move" the workbooks onto a form so I turned to P/Invoke Win32 library. I am able to move the entire excel application onto a WinForm with great success: // pseudo code to give you the idea excel = new Excel.ApplicationClass(); SetParent(excel.Hwnd, form.handle); This allows me to customize the form and control user input. All right click commands and formula editing work properly. Now, the issue I run into is when I want to open two workbooks in two separate forms. I do this by creating two excel application classes and placing each of those in their own form. When I try to reference one workbook to another workbook via =[Book2]Sheet1!A1, for example, it does not update. This is expected as each application is running under its own thread/process. Here are the alternatives I have tried. If you have any suggestions I would be greatly appreciative.(OLE is not an option. VSTO must be available) Create a single application class and move the workbook window into my form. Results: The window moves into my form and displays correctly, however, no right click or left click works on the form and it never gains focus. (I have tried to manually set focus and it does not work either). My guess is, by moving the window outside of the XLDESK application (viewable in Spy++ for Excel Application), the workbook application (EXCEL7) does not receive the correct window messages to gain focus and to behave properly. This leads me to: Move the XLDESK window handle into my form. Results: This allows the workbook to be click-able again but also has an undesired result of moving all child windows into the same form. Create a main excel application that creates workbooks. Create a new excel application for each new window. Move the workbook under the new excel application XLDESK window. Results: This also has the same effect of the 1st option. Unable to click in the workbook. This must mean that the thread that created the workbook is also responsible for the events. Create a windows hook that watches the WndProc procedure. Results: No events watched. The targeted thread must export the hook proc in a DLL export call. Excel does not do this and thus you cannot inject into it's DLL (unless someone can prove me wrong). I am able to watch all threads within my own process but not from an outside process. Excel is created as a separate process. Subclass NativeWindow. Results: Same as #4. After I move the window into my form, all events are captured up until the mouse is directly over the excel sheet making the sheet seem unclickable. One idea I haven't tried yet is just to continually save the excel sheet as the user edits it. This should update all references but I would feel this would cause poor system performance. There will be numerous chart references as well and I'm not sure if this solution would cause problems further down the road. I think in the end, all the workbooks need to be created by the same Excel Application and then moved to get the desired results but I can't seem to find the correct way to move the windows without disabling the user input in the process. Any suggestions?

    Read the article

  • How can i get a file from remote machine?

    - by programmerist
    How can i get a file from remote computer? i know remote computer ip and 51124 port is open. i need this algorith: 1) Connect 192.xxx.x.xxx ip via 51124 port 2) filename:123456 (i want to search it on remote machine) 3) Get File 4) Save C:\ 51124 port is open. can i access and can i search any file according to filename? My code is below: IPEndPoint ipEnd = new IPEndPoint(IPAddress.Any, 51124); Socket sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP); sock.Bind(ipEnd); sock.Listen(maxConnections); Socket serverSocket = sock.Accept(); byte[] data = new byte[bufferSize]; int received = serverSocket.Receive(data); int filenameLength = BitConverter.ToInt32(data, 0); string filename = Encoding.ASCII.GetString(data, 4, filenameLength); BinaryWriter bWrite = new BinaryWriter(File.Open(outPath + filename, FileMode.Create)); bWrite.Write(data, filenameLength + 4, received - filenameLength - 4); int received2 = serverSocket.Receive(data); while (received2 0) { bWrite.Write(data, 0, received2); received2 = serverSocket.Receive(data); } bWrite.Close(); serverSocket.Close(); sock.Close();

    Read the article

  • My C# UploadFile method successfully uploads a file, but then my UI hangs...

    - by kyrathaba
    I have a simple WinForms test application in C#. Using the following method, I'm able to upload a file when I invoke the method from my button's Click event handler. The only problem is: my Windows Form "freezes". I can't close it using the Close button. I have to end execution from within the IDE (Visual C# 2010 Express edition). Here are the two methods: public void UploadFile(string FullPathFilename) { string filename = Path.GetFileName(FullPathFilename); try { FtpWebRequest request = (FtpWebRequest)WebRequest.Create(_remoteHost + filename); request.Method = WebRequestMethods.Ftp.UploadFile; request.Credentials = new NetworkCredential(_remoteUser, _remotePass); StreamReader sourceStream = new StreamReader(FullPathFilename); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); request.ContentLength = fileContents.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); response.Close(); requestStream.Close(); sourceStream.Close(); } catch (Exception ex) { MessageBox.Show(ex.Message, "Upload error"); } finally { } } which gets called here: private void btnUploadTxtFile_Click(object sender, EventArgs e) { string username = "my_username"; string password = "my_password"; string host = "ftp://mywebsite.com"; try { clsFTPclient client = new clsFTPclient(host + "/httpdocs/non_church/", username, password); client.UploadFile(Path.GetDirectoryName(Application.ExecutablePath) + "\\myTextFile.txt"); } catch (Exception ex) { MessageBox.Show(ex.Message, "Upload problem"); } }

    Read the article

  • Python + Expat: Error on &#0; entities

    - by clacke
    I have written a small function, which uses ElementTree and xpath to extract the text contents of certain elements in an xml file: #!/usr/bin/env python2.5 import doctest from xml.etree import ElementTree from StringIO import StringIO def parse_xml_etree(sin, xpath): """ Takes as input a stream containing XML and an XPath expression. Applies the XPath expression to the XML and returns a generator yielding the text contents of each element returned. >>> parse_xml_etree( ... StringIO('<test><elem1>one</elem1><elem2>two</elem2></test>'), ... '//elem1').next() 'one' >>> parse_xml_etree( ... StringIO('<test><elem1>one</elem1><elem2>two</elem2></test>'), ... '//elem2').next() 'two' >>> parse_xml_etree( ... StringIO('<test><null>&#0;</null><elem3>three</elem3></test>'), ... '//elem2').next() 'three' """ tree = ElementTree.parse(sin) for element in tree.findall(xpath): yield element.text if __name__ == '__main__': doctest.testmod(verbose=True) The third test fails with the following exception: ExpatError: reference to invalid character number: line 1, column 13 Is the � entity illegal XML? Regardless whether it is or not, the files I want to parse contain it, and I need some way to parse them. Any suggestions for another parser than Expat, or settings for Expat, that would allow me to do that?

    Read the article

  • How do I set the LRECL in C#.NET?

    - by donde
    I have been trying to ftp a dtl file from .net to, what I beleive, is an AS400. The error being reported back to me is: "One or more lines have been truncated" and the admin is saying the file is coming over with 256 lines that have variable length columns. I found this explanation online: we have to establish defaults because no specifics about the file exist. The default RECFM is V and LRECL is 256. This means that SAS will scan the input record looking for the CR & LF to tell us that we are at the EOR. If the marker isn't found within the limit of the LRECL, SAS discards the data from the LRECL value to the end of the record and adds a message to the Log that "One or more lines have been truncated". So I need to set the LRECL. How do I do this in C# .NET? FtpWebRequest ftp = (FtpWebRequest)FtpWebRequest.Create(ftpfullpath); ftp.Credentials = new NetworkCredential(user, pwd); ftp.KeepAlive = false; ftp.UseBinary = false; ftp.Method = WebRequestMethods.Ftp.UploadFile; FileStream fs = File.OpenRead(inputfilepath + ftpfileName); byte[] buffer = new byte[fs.Length]; fs.Read(buffer, 0, buffer.Length); fs.Close(); Stream ftpstream = ftp.GetRequestStream(); int i = 0; int intBlock = 1786; int intBuffLeft = buffer.Length; while (i < buffer.Length) { if (intBuffLeft >= 1786) { ftpstream.Write(buffer, i, intBlock); } else { ftpstream.Write(buffer, i, intBuffLeft); } i += intBlock; intBuffLeft -= 1786; } ftpstream.Close();

    Read the article

  • Problem with Global Array in PHP

    - by Suezy
    Hi guys,, need some help pls.. i have a PHP code here that lets a user send a message to multiple recipients using the "phonebook" (from database) as the main list. I used an array to temporarily hold all the desired recipients for the current user. So I have a two box, with each for displaying. The user will clicks the name from the phonebook lisy and clicks "Add" button to add on the temporary list on the other select box. The problem is, whenever I use the "onChange" function in javascript; the array accepts only one recipients, and when I try to add, it replaces the first one. :( Here is my code: $recipients = array(); // How do I place the array here? function reload_page(){ i=document.maillinglist.firstletter.selectedIndex; this.location='./group_msg.php?firstletter='+document.maillinglist.firstletter.options[i].value; } function add(){ } $conn = pg_connect("host=localhost user=sa dbname=messaging"); if(isset($_GET['firstletter'])){ $letter=$_GET['firstletter']; } else { $letter='a';} print ""; print "GROUP MESSAGE"; print ""; print ""; print ""; print ""; for($chr_loop=97;$chr_loop<=122;$chr_loop++){ $alphabet = chr($chr_loop); # Displays list of users arranged by letters - this works fine if($alphabet==$letter){ print "\t\t<option value='$alphabet' selected>-------------------- $alphabet --------------------</option>\n"; } else { print "\t\t<option value='$alphabet'>-------------------- $alphabet --------------------</option>\n";} } print ""; print "<td><select style='width:210px' name=\"non_members[]\" size=10 width=200>"; $sql = "select name from test_phonebook where name like '$letter%';"; $result = pg_query($conn, $sql); # Display users from phonebook using the letter chosen while($row = pg_fetch_assoc($result)){ $my_name = $row['name']; print "<option width=200 value=\"$my_name\">$my_name</option>"; } print "</td>"; print "</select>"; print "<td><input type=submit name=add value=\"->>\" onClick=\"add()\"><br><input type=submit name=del value=\"<<-\"></td>"; print "<td><select name=\"members[]\" style='width:210px' size=10>"; # Display temporary recipients - problem: ONLY DISPLAYS ONE VALUE while (list ($key, $val) = each ($recipients)) { echo "$key -> $val <br>"; print "<option width=200 value=\"$val\">$val</option>"; } print "</select></table></form>"; My aim here, is to place all recipients that the user desires to an array, without losing the previous value added.

    Read the article

  • how do i call mpmovieplayer from applicationwillresignactive in ppdelegate

    - by ss30
    i'm using mpmovieplayer to play audio stream, one problem i'm having trouble with handling intruptions e.g when call is received. My player is declared in viewcontroller and i beleive i need to do something in applicationdidresignactive in my appdelegate right? how do i do that if my appdelegate isn't aware of my moviePlayer? i'm new to iphone dev so i'm learning as i go and enjoying it :) here is what i'm doing in viewcontroller -(IBAction)play1MButton:(id)sender{ [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(moviePlayerStatus:) name:MPMoviePlayerPlaybackStateDidChangeNotification object:nil]; NSString *url = @"http://22.22.22.22:8000/listen.pls"; [self.activityIndicator startAnimating]; moviePlayer = [[MPMoviePlayerController alloc] initWithContentURL:[NSURL URLWithString:url]]; [moviePlayer prepareToPlay]; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(moviePlayerLoadStateChanged:) name:MPMoviePlayerLoadStateDidChangeNotification object:nil]; } } -(void) moviePlayerStatus:(NSNotification*)notification { //MPMoviePlayerController *moviePlayer = notification.object; MPMoviePlaybackState playbackState = moviePlayer.playbackState; if(playbackState == MPMoviePlaybackStateStopped) { NSLog(@"MPMoviePlaybackStateStopped"); } else if(playbackState == MPMoviePlaybackStatePlaying) { NSLog(@"MPMoviePlaybackStatePlaying"); } else if(playbackState == MPMoviePlaybackStatePaused) { NSLog(@"MPMoviePlaybackStatePaused"); } else if(playbackState == MPMoviePlaybackStateInterrupted) { NSLog(@"MPMoviePlaybackStateInterrupted"); } else if(playbackState == MPMoviePlaybackStateSeekingForward) { NSLog(@"MPMoviePlaybackStateSeekingForward"); } else if(playbackState == MPMoviePlaybackStateSeekingBackward) { NSLog(@"MPMoviePlaybackStateSeekingBackward"); } } - (void) moviePlayerLoadStateChanged:(NSNotification*)notification { if ([moviePlayer loadState] != MPMovieLoadStateUnknown) { [[NSNotificationCenter defaultCenter] removeObserver:self name:MPMoviePlayerLoadStateDidChangeNotification object:moviePlayer]; [moviePlayer play]; [self.activityIndicator stopAnimating]; [moviePlayer setFullscreen:NO animated:NO]; } } and in appdelegate - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { // Override point for customization after application launch. self.window.rootViewController = self.viewController; [self.window makeKeyAndVisible]; AVAudioSession *audioSession = [AVAudioSession sharedInstance]; NSError *setCategoryError = nil; [audioSession setCategory:AVAudioSessionCategoryPlayback error:&setCategoryError]; if (setCategoryError) { } NSError *activationError = nil; [audioSession setActive:YES error:&activationError]; if (activationError) { } I can catch the errors but how do i use the player from appdelegate?!! thanks in advance

    Read the article

  • Why can't I open a JBoss vfs:/ URL?

    - by skiphoppy
    We are upgrading our application from JBoss 4 to JBoss 6. A couple of pieces of our application get delivered to the client in an unusual way: jars are looked up inside of our application and sent to the client from a servlet, where the client extracts them in order to run certain support functions. In JBoss 4 we would look these jars up with the classloader and find a jar:// URL which would be used to read the jar and send its contents to the client. In JBoss 6 when we perform the lookup we get a vfs:/ URL. I understand that this is from the org.jboss.vfs package. Unfortunately when I call openStream() on this URL and read from the stream, I immediately get an EOF (read() returns -1). What gives? Why can't I read the resource this URL refers to? I've tried trying to access the underlying VFS packages to open the file through the JBoss VFS API, but most of the API appears to be private, and I couldn't find a routine to translate from a vfs:/ URL to a VFS VirtualFile object, so I couldn't get anywhere. I can try to find the file on disk within JBoss, but that approach sounds very failure prone on upgrade. Our old approach was to use Java Web Start to distribute the jars to the client and then look them up within Java Web Start's cache to extract them. But that broke on every minor upgrade of Java because the layout of the cache changed.

    Read the article

  • TCP Socket.Connect is generating false positives

    - by Mark
    I'm experiencing really weird behavior with the Socket.Connect method in C#. I am attempting a TCP Socket.Connect to a valid IP but closed port and the method is continuing as if I have successfully connected. When I packet sniffed what was going on I saw that the app was receiving RST packets from the remote machine. Yet from the tracing that is in place it is clear that the connect method is not throwing an exception. Any ideas what might be causing this? The code that is running is basically this IPEndPoint iep = new IPEndPoint(System.Net.IPAddress.Parse(m_ipAddress), m_port); Socket tcpSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); tcpSocket.Connect(iep); To add to the mystery... when running this code in a stand alone console application, the result is as expected – the connect method throws an exception. However, when running it in the Windows Service deployment we have the connect method does not throw an exception. Edit in response to Mystere Man's answer How would the exception be swallowed? I have a Trace.WriteLine right above the .Connect method and a Trace.WriteLine right under it (not shown in the code sample for readability). I know that both traces are running. I also have a try catch around the whole thing which also does a Trace.Writeline and I don't see that in the log files anywhere. I have also enabled the internal socket tracing as you suggested. I don't see any exceptions. I see what appears to be successful connections. I am trying to identify differences between the windows service app and the diagnostic console app I made. I am running out of ideas though End edit Thanks

    Read the article

  • Listening socket

    - by hoodoos
    I got a strange problem, I never actually expirienced this before, here is the code of the server (client is firefox in this case), the way I create it: _Socket = new Socket( AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp ); _Socket.Bind( new IPEndPoint( Settings.IP, Settings.Port ) ); _Socket.Listen( 1000 ); _Socket.Blocking = false; the way i accept connection: while( _IsWorking ) { if( listener.Socket.Poll( -1, SelectMode.SelectRead ) ) { Socket clientSocket = listener.Socket.Accept(); clientSocket.Blocking = false; clientSocket.SetSocketOption( SocketOptionLevel.Tcp, SocketOptionName.NoDelay, true ); } } So I'm expecting it hang on listener.Socket.Poll till new connection comes, but after first one comes it hangs on poll forever. I tried to poll it constantly with smaller delay, let's say 10 microseconds, then it never goes in SelectMode.SelectRead. I guess it maybe somehow related on client's socket reuse? Maybe I don't shutdown client socket propertly and client(firefox) decides to use an old socket? I disconnect client socket this way: Context.Socket.Shutdown( SocketShutdown.Both ); // context is just a wrapper around socket Context.Socket.Close(); What may cause that problem?

    Read the article

  • How do I get Firefox to launch Visio when I click on a linked .vsd file?

    - by Dean
    On our intranet site, we have various MS Office documents linked. When I click on a Word, Excel or PowerPoint file, Firefox gives me the option to Open, Save or Cancel. When I click on Open, the appropriate app is launched and the file is loaded. This is perfect. But for some reason, when I click on a linked Visio file, I only get the option to Save, which is inconvenient. I know that Firefox knows the linked file is a Visio file because it tells me so in the dialog box: "You have chosen to open example.vsd which is a: Microsoft Visio Drawing". How can I make Firefox launch Visio when I click on a linked Visio file? Update: Firefox is not launching Visio when I click on a linked Visio file because the web server does not identify the content-type correctly. It identifies the Visio file as application/octet-stream instead of application/x-visio. (Thanks Grant Wagner.) This explains why it doesn't work. And in my case, I may be able to get the Apache config file changed, but this is not certain. However, I would love to know if there is a way to configure Firefox itself to launch Visio based on some other criteria, like file name extension. This way I can open Visio files even if I don't have access to the Apache configuration.

    Read the article

  • How does the receiver of a cipher text know the IV used for encryption?

    - by PatrickL
    If a random IV is used in encrypting plain text, how does the receiver of the cipher text know what the IV is in order to decrypt it? This is a follow-up question to a response to the previous stackoverflow question on IVs here. The IV allows for plaintext to be encrypted such that the encrypted text is harder to decrypt for an attacker. Each bit of IV you use will double the possibilities of encrypted text from a given plain text. The point is that the attacker doesn't know what the IV is and therefore must compute every possible IV for a given plain text to find the matching cipher text. In this way, the IV acts like a password salt. Most commonly, an IV is used with a chaining cipher (either a stream or block cipher). ... So, if you have a random IV used to encrypt the plain text, how do you decrypt it? Simple. Pass the IV (in plain text) along with your encrypted text. Wait. You just said the IV is randomly generated. Then why pass it as plain text along with the encrypted text?

    Read the article

  • java ioexception error=24 too many files open

    - by MattS
    I'm writing a genetic algorithm that needs to read/write lots of files. The fitness test for the GA is invoking a program called gradif, which takes a file as input and produces a file as output. Everything is working except when I make the population size and/or the total number of generations of the genetic algorithm too large. Then, after so many generations, I start getting this: java.io.FileNotFoundException: testfiles/GradifOut29 (Too many open files). (I get it repeatedly for many different files, the index 29 was just the one that came up first last time I ran it). It's strange because I'm not getting the error after the first or second generation, but after a significant amount of generations, which would suggest that each generation opens up more files that it doesn't close. But as far as I can tell I'm closing all of the files. The way the code is set up is the main() function is in the Population class, and the Population class contains an array of Individuals. Here's my code: Initial creation of input files (they're random access so that I could reuse the same file across multiple generations) files = new RandomAccessFile[popSize]; for(int i=0; i<popSize; i++){ files[i] = new RandomAccessFile("testfiles/GradifIn"+i, "rw"); } At the end of the entire program: for(int i=0; i<individuals.length; i++){ files[i].close(); } Inside the Individual's fitness test: FileInputStream fin = new FileInputStream("testfiles/GradifIn"+index); FileOutputStream fout = new FileOutputStream("testfiles/GradifOut"+index); Process process = Runtime.getRuntime().exec ("./gradif"); OutputStream stdin = process.getOutputStream(); InputStream stdout = process.getInputStream(); Then, later.... try{ fin.close(); fout.close(); stdin.close(); stdout.close(); process.getErrorStream().close(); }catch (IOException ioe){ ioe.printStackTrace(); } Then, afterwards, I append an 'END' to the files to make parsing them easier. FileWriter writer = new FileWriter("testfiles/GradifOut"+index, true); writer.write("END"); try{ writer.close(); }catch(IOException ioe){ ioe.printStackTrace(); } My redirection of stdin and stdout for gradif are from this answer. I tried using the try{close()}catch{} syntax to see if there was a problem with closing any of the files (there wasn't), and I got that from this answer. It should also be noted that the Individuals' fitness tests run concurrently. UPDATE: I've actually been able to narrow it down to the exec() call. In my most recent run, I first ran in to trouble at generation 733 (with a population size of 100). Why are the earlier generations fine? I don't understand why, if there's no leaking, the algorithm should be able to pass earlier generations but fail on later generations. And if there is leaking, then where is it coming from? UPDATE2: In trying to figure out what's going on here, I would like to be able to see (preferably in real-time) how many files the JVM has open at any given point. Is there an easy way to do that?

    Read the article

  • how to get selected chracter position in JTextArea?

    - by Reddy
    Hi! Here is a challenging question! Let me first tell you my scenario how am i implementing a solution to a problem. I am reading a log file and displaying it on the JTextArea. Log file is cp037 character coded. I was reading each file as a byte stream or byte array from the log file & displaying it. Anyways, i managed to display the text properly in JTextArea by cp037 character coding. Now, User may select a set of characters in the JTextArea. All i want is the position of first character of the user's selected text, from a nearest special character '+'(its character code in cp037 is 4E), which is prior to the selected text. This character may occur at several places in the JTextArea. In simple sentence, i want the first character location(of user selected text) from nearset '+' which should be occuring prior to the user's selected text. PS: cp037 is a type of character encoding scheme which is created by IBM & used for IBM Mainframes. Please fell free to ask me if the question is not clear...:-

    Read the article

  • Iphone - cannot grant permission for publishing on a Facebook page that i administer

    - by user323817
    I want to open a dialog on the IPhone so a user can grant my application permission to post on a Facebook page that the user administers. Following the docs, I can grant permissions for the user's stream and I can even post on a page that he is a fan of. However, the post on the page is listed as from the username, not on behalf of the page itself, even though he is an administrator of the page. According to the Prompting for Permissions section at: http://wiki.developers.facebook.com/index.php/Authorization_and_Authentication_for_Desktop_Applications I should be able to create a prompt on the IPhone for granting permission to publish_stream on a Facebook page that he administers. The sample url they give for a web "popup" dialog is: http://www.facebook.com/connect/prompt_permissions.php?api_key=YOURAPIKEY&v=1.0&next=http://www.facebook.com/connect/login_success.html?xxRESULTTOKENxx&display=popup&ext_perm=read_stream,publish_stream&enable_profile_selector=1&profile_selector_ids=1234%2C5454 This works as expected and a drop down of the pages is displayed. However, since my application is on the IPhone, I change the display=popup to display=touch. This does not seem to work and I've tried fiddling with the parameters several ways but the drop down never comes up. Anyone find a way around this? The popup option doesn't seem to work since I get an error trying to display it.

    Read the article

  • extra new lines with several outputStream.write

    - by Sam
    Hi All, I am writing jsp to export data in excel format to user. An excel could be recieved on the cient side. However, since there's large amount of data, and I don't want to keep it in the server memory and write them at the end. I try to divide them and write serveral times. However, each extra write(..) will cause an extra new lines at the top of the excel worksheet and then the extra data is placed after these new lines. Does anyone know the reasons? The code is something like this: response.setHeader("Content-disposition","attachment;filename=DocuShareSearch.xls"); response.setHeader("Content-Type", "application/octet-stream"); responseContent ="<table><tr><td>12131</td></tr>......."; byte[] responseByte1 = responseContent.getBytes("utf-16"); outputStream.write(responseByte1, 0, responseByte1.length ); responseContent =".....<tr><td>12131</td></tr></table>"; byte[] responseByte2 = responseContent.getBytes("utf-16"); outputStream.write(responseByte2, 0, responseByte2.length ); outputStream.close();

    Read the article

  • Login to website and use cookie to get source for another page

    - by Stu
    I am trying to login to the TV Rage website and get the source code of the My Shows page. I am successfully logging in (I have checked the response from my post request) but then when I try to perform a get request on the My Shows page, I am re-directed to the login page. This is the code I am using to login: private string LoginToTvRage() { string loginUrl = "http://www.tvrage.com/login.php"; string formParams = string.Format("login_name={0}&login_pass={1}", "xxx", "xxxx"); string cookieHeader; WebRequest req = WebRequest.Create(loginUrl); req.ContentType = "application/x-www-form-urlencoded"; req.Method = "POST"; byte[] bytes = Encoding.ASCII.GetBytes(formParams); req.ContentLength = bytes.Length; using (Stream os = req.GetRequestStream()) { os.Write(bytes, 0, bytes.Length); } WebResponse resp = req.GetResponse(); cookieHeader = resp.Headers["Set-cookie"]; String responseStream; using (StreamReader sr = new StreamReader(resp.GetResponseStream())) { responseStream = sr.ReadToEnd(); } return cookieHeader; } I then pass the cookieHeader into this method which should be getting the source of the My Shows page: private string GetSourceForMyShowsPage(string cookieHeader) { string pageSource; string getUrl = "http://www.tvrage.com/mytvrage.php?page=myshows"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookieHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); } return pageSource; } I have been using this previous question as a guide but I'm at a loss as to why my code isn't working.

    Read the article

  • Code won't work under mono, any ideas whats wrong?

    - by JL
    Mono won't fire the following code: I get internal server error 500, error writing request error. Code works perfectly under normal .net.... any ideas why its broken and how to fix it? [WebServiceBinding] public class testService : System.Web.Services.Protocols.SoapHttpClientProtocol { private string DummySoapRequest = @"<?xml version=""1.0"" encoding=""utf-8""?> <soap:Envelope xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema""> <soap:Body> <DummyOperation xmlns=""http://mynamespace.com""> </DummyOperation> </soap:Body> </soap:Envelope>"; public void SendDummyRequest() { System.Net.WebRequest req = GetWebRequest(new Uri(Url)); req.Headers.Add("SOAPAction", ""); req.ContentType = "text/xml;charset=\"utf-8\""; req.Method = "POST"; using (Stream stm = req.GetRequestStream()) { using (StreamWriter stmw = new StreamWriter(stm)) { stmw.Write(DummySoapRequest); } } System.Net.WebResponse response = req.GetResponse(); } }

    Read the article

< Previous Page | 571 572 573 574 575 576 577 578 579 580 581 582  | Next Page >