Search Results

Search found 70172 results on 2807 pages for 'archive file'.

Page 608/2807 | < Previous Page | 604 605 606 607 608 609 610 611 612 613 614 615  | Next Page >

  • Configuring Multiple Instances of MySQL in Solaris 11

    - by rajeshr
    Recently someone asked me for steps to configure multiple instances of MySQL database in an Operating Platform. Coz of my familiarity with Solaris OE, I prepared some notes on configuring multiple instances of MySQL database on Solaris 11. Maybe it's useful for some: If you want to run Solaris Operating System (or any other OS of your choice) as a virtualized instance in desktop, consider using Virtual Box. To download Solaris Operating System, click here. Once you have your Solaris Operating System (Version 11) up and running and have Internet connectivity to gain access to the Image Packaging System (IPS), please follow the steps as mentioned below to install MySQL and configure multiple instances: 1. Install MySQL Database in Solaris 11 $ sudo pkg install mysql-51 2. Verify if the mysql is installed: $ svcs -a | grep mysql Note: Service FMRI will look similar to the one here: svc:/application/database/mysql:version_51 3. Prepare data file system for MySQL Instance 1 zfs create rpool/mysql zfs create rpool/mysql/data zfs set mountpoint=/mysql/data rpool/mysql/data 4. Prepare data file system for MySQL Instance 2 zfs create rpool/mysql/data2 zfs set mountpoint=/mysql/data rpool/mysql/data2 5. Change the mysql/datadir of the MySQL Service (SMF) to point to /mysql/data $ svcprop mysql:version_51 | grep mysql/data $ svccfg -s mysql:version_51 setprop mysql/data=/mysql/data 6. Create a new instance of MySQL 5.1 (a) Copy the manifest of the default instance to temporary directory: $ sudo cp /lib/svc/manifest/application/database/mysql_51.xml /var/tmp/mysql_51_2.xml (b) Make appropriate modifications on the XML file $ sudo vi /var/tmp/mysql_51_2.xml - Change the "instance name" section to a new value "version_51_2" - Change the value of property name "data" to point to the ZFS file system "/mysql/data2" 7. Import the manifest to the SMF repository: $ sudo svccfg import /var/tmp/mysql_51_2.xml 8. Before starting the service, copy the file /etc/mysql/my.cnf to the data directories /mysql/data & /mysql/data2. $ sudo cp /etc/mysql/my.cnf /mysql/data/ $ sudo cp /etc/mysql/my.cnf /mysql/data2/ 9. Make modifications to the my.cnf in each of the data directories as required: $ sudo vi /mysql/data/my.cnf Under the [client] section port=3306 socket=/tmp/mysql.sock ---- ---- Under the [mysqld] section port=3306 socket=/tmp/mysql.sock datadir=/mysql/data ----- ----- server-id=1 $ sudo vi /mysql/data2/my.cnf Under the [client] section port=3307 socket=/tmp/mysql2.sock ----- ----- Under the [mysqld] section port=3307 socket=/tmp/mysql2.sock datadir=/mysql/data2 ----- ----- server-id=2 10. Make appropriate modification to the startup script of MySQL (managed by SMF) to point to the appropriate my.cnf for each instance: $ sudo vi /lib/svc/method/mysql_51 Note: Search for all occurences of mysqld_safe command and modify it to include the --defaults-file option. An example entry would look as follows: ${MySQLBIN}/mysqld_safe --defaults-file=${MYSQLDATA}/my.cnf --user=mysql --datadir=${MYSQLDATA} --pid=file=${PIDFILE} 11. Start the service: $ sudo svcadm enable mysql:version_51_2 $ sudo svcadm enable mysql:version_51 12. Verify that the two services are running by using: $ svcs mysql 13. Verify the processes: $ ps -ef | grep mysqld 14. Connect to each mysqld instance and verify: $ mysql --defaults-file=/mysql/data/my.cnf -u root -p $ mysql --defaults-file=/mysql/data2/my.cnf -u root -p Some references for Solaris 11 newbies Taking your first steps with Solaris 11 Introducing the basics of Image Packaging System Service Management Facility How To Guide For a detailed list of official educational modules available on Solaris 11, please visit here For MySQL courses from Oracle University access this page.

    Read the article

  • Integrating JavaFX Scene Builder in the IDEs

    - by Jerome Cambon
    I experienced recently using Scene Builder from Netbeans, Eclipse and IntelliJ IDEA. As you may know, Scene Builder is a standalone tool, that can be used independently of any IDE. But it can be very convenient to use it with your favorite IDE, for instance start it by double-clicking on an FXML file, or run samples delivered with Scene Builder.  I'm sharing here with you few tweaks that I had to do for a better integration. Scene Builder 1.1 Developer Preview should be installed before doing the tweaks. The steps below have been done on Windows 7. It should be very similar on both Mac OS and Linux. Please tell me if you find any issue on one of these 2 platforms. Netbeans 7.3 Netbeans 7.3 can be downloaded from here. Creating a New FXML project Part of the JavaFx projects, Netbeans allows to create a 'JavaFX FXML Application', that creates a JavaFx project based on FXML description. The FXML file will be editable with Scene Builder. Starting Scene Builder from Netbeans If SceneBuilder 1.1 is installed, Netbeans will discover it automatically.In case of issue, one can open the Options panel, Java section, JavaFx tab. Scene Builder home should appear here. You can then either Open the FXML file with Scene Builder, or edit it with the Netbeans FXML editor : When 'Open' is selected, Scene Builder appears on top of the Netbeans window : When 'Edit' is selected, the FXML is opened in the Netbeans FXML editor, which support syntax highlighting and completion : Using Scene Builder Samples Scene Builder provides Netbeans projects, that can be opened/run directly : Eclipse 4.2.1 + e(fx)clipse 0.1.1 JavaFX integration in Eclipse has been done with the e(fx)clipse plugin. A distribution bundle containing Eclipse and e(fx)clipse is provided here. Creating New FXML project All the JavaFX-related projects can be found in 'Other' section : First create a new JavaFX project: Enter the project name (Test here). JavaFX delivery will be found in the JRE. Then, create a 'New FXML Document': Enter the FXML file name (Sample here). You may also want to choose the FXML document root element (AnchorPane by default). Dynamic root is for advanced users which want to manage custom types. Starting Scene Builder from Eclipse Once created, you can then either Open the FXML file with Scene Builder, or Open it in the Eclipse FXML editor : Using Scene Builder Samples from Eclipse To use Scene Builder samples, first create a new JavaFX Project (from 'Other' section): Then, on the next panel, 'Link additionnal source': … and select the source directory of a Scene Builder example : HelloWorld here (the parent directory of the java package should be selected).Then, choose a 'Folder name' for your sample: You can now run the Scene Builder example by right-clicking the Main.java source file: IntelliJ IDEA 11.1.3 IntelliJ IDEA Community Edition can be downloaded from here. IntelliJ IDEA has no specific JavaFX integration. Creating New IntelliJ project from existing source Since IntelliJ has no JavaFX project knowledge, we are using the Scene Builder samples as a starting point. We are going to create a new Java project from the HelloWorld sample: Then, click twice on 'Next' (nothing to change), then 'Finish'. The 'HelloWorld' project is created. Starting Scene Builder from IntelliJ We need to tell the IDE that FXML files are opened with an external application. Then, the OS file association will be used. To do this, open the File->Settings panel. Then, select 'File Types' and 'Files opened in associated applications'. And add a new wildcard : '*.fxml' : Now, from the HelloWorld project, you can double-click on HelloWorld.fxml : Scene Builder window appears on top of the IntelliJ window : Using Scene Builder Samples from IntelliJ We need to tell IntelliJ that the fxml files must be copied in the build directory.To do that, from the HelloWorld directory, open the 'idea' section, and edit the 'compiler.xml' file. We need to add an '*.fxml' entry: Then, you can run the sample from HelloWorld project, by right-clicking the Main class:

    Read the article

  • Deploying an SSL Application to Windows Azure &ndash; The Dark Secret

    - by ToStringTheory
    When working on an application that had been in production for some time, but was about to have a shopping cart added to it, the necessity for SSL certificates came up.  When ordering the certificates through the vendor, the certificate signing request (CSR) was generated through the providers (http://register.com) web interface, and within a day, we had our certificate. At first, I thought that the certification process would be the hard part…  Little did I know that my fun was just beginning… The Problem I’ll be honest, I had never really secured a site before with SSL.  This was a learning experience for me in the first place, but little did I know that I would be learning more than the simple procedure.  I understood a bit about SSL already, the mechanisms in how it works – the secure handshake, CA’s, chains, etc…  What I didn’t realize was the importance of the CSR in the whole process.  Apparently, when the CSR is created, a public key is created at the same time, as well as a private key that is stored locally on the PC that generated the request.  When the certificate comes back and you import it back into IIS (assuming you used IIS to generate the CSR), all of the information is combined together and the SSL certificate is added into your store. Since at the time the certificate had been ordered for our site, the selection to use the online interface to generate the CSR was chosen, the certificate came back to us in 5 separate files: A root certificate – (*.crt file) An intermediate certifcate – (*.crt file) Another intermediate certificate – (*.crt file) The SSL certificate for our site – (*.crt file) The private key for our certificate – (*.key file) Well, in case you don’t know much about Windows Azure and SSL certificates, the first thing you should learn is that certificates can only be uploaded to Azure if they are in a PFX package – securable by a password.  Also, in the case of our SSL certificate, you need to include the Private Key with the file.  As you can see, we didn’t have a PFX file to upload. If you don’t get the simple PFX from your hosting provider, but rather the multiple files, you will soon find out that the process has turned from something that should be simple – to one that borders on a circle of hell… Probably between the fifth and seventh somewhere… The Solution The solution is to take the files that make up the certificates chain and key, and combine them into a file that can be imported into your local computers store, as well as uploaded to Windows Azure.  I can not take the credit for this information, as I simply researched a while before finding out how to do this. Download the OpenSSL for Windows toolkit (Win32 OpenSSL v1.0.1c) Install the OpenSSL for Windows toolkit Download and move all of your certificate files to an easily accessible location (you'll be pointing to them in the command prompt, so I put them in a subdirectory of the OpenSSL installation) Open a command prompt Navigate to the folder where you installed OpenSSL Run the following command: openssl pkcs12 -export –out {outcert.pfx} –inkey {keyfile.key}      –in {sslcert.crt} –certfile {ca1.crt} –certfile (ca2.crt) From this command, you will get a file, outcert.pfx, with the sum total of your ssl certificate (sslcert.crt), private key {keyfile.key}, and as many CA/chain files as you need {ca1.crt, ca2.crt}. Taking this file, you can then import it into your own IIS in one operation, instead of importing each certificate individually.  You can also upload the PFX to Azure, and once you add the SSL certificate links to the cloud project in Visual Studio, your good to go! Conclusion When I first looked around for a solution to this problem, there were not many places online that had the information that I was looking for.  While what I ended up having to do may seem obvious, it isn’t for everyone, and I hope that this can at least help one developer out there solve the problem without hours of work!

    Read the article

  • How to upgrade a remote server from 8.10 to newer version?

    - by DisgruntledGoat
    I have a remote server still running Ubuntu 8.10 9.04 that I can only access via SSH. If I run apt-get update I get a bunch of 404 errors on the packages. I've asked a few questions on Server Fault but got nowhere. Here's what I've done: Run apt-get update which returns errors like: Err http://gb.archive.ubuntu.com intrepid/main Packages 404 Not Found [and same for many other packages] Run do-release-upgrade which returns: Checking for a new ubuntu release Failed Upgrade tool signature Failed Upgrade tool Done downloading extracting 'jaunty.tar.gz' Failed to extract Extracting the upgrade failed. There may be a problem with the network or with the server. Edited /etc/update-manager/release-upgrades and changed from Prompt=normal to Prompt=lts (as suggested here). Running do-release-upgrade after this returns: Checking for a new ubuntu release current dist not found in meta-release file No new release found (Updated) I have followed the advice in this question and changed /etc/apt/sources.list to refer to jaunty instead of intrepid. However, that distro is not online anymore either. A comment there says I have to upgrade in chronological order... So basically, it seems like I cannot upgrade because my current distro is out of date and not supported. Is there a way to upgrade direct to 10.x or 11.x? Note, as this is a server I only have command-line access. UPDATE 24/11: I have managed to upgrade from 8.10 to 9.04. Ubuntu's EOL Upgrades page provides some alternate URLs for apt sources. I also needed to update /var/lib/update-manager/meta-release to point to the old-releases server too. However, now I cannot upgrade from 9.04 to 9.10. Running do-release-upgrade produces the same error as #2 above, except it "Failed to fetch" (the URLs in meta-release are valid). The Ubuntu Jaunty upgrade page says it's necessary to upgrade using a CD image. I followed the instructions here, but it didn't work: A fatal error occurred Please report this as a bug and include the files /var/log/dist-upgrade/main.log and /var/log/dist-upgrade/apt.log in your report. The upgrade is now aborted. Your original sources.list was saved in /etc/apt/sources.list.distUpgrade. Traceback (most recent call last): File "/tmp/tmp.JLhTwVUugb/karmic", line 7, in sys.exit(main()) File "/tmp/tmp.JLhTwVUugb/DistUpgradeMain.py", line 132, in main if app.run(): File "/tmp/tmp.JLhTwVUugb/DistUpgradeController.py", line 1590, in run return self.fullUpgrade() File "/tmp/tmp.JLhTwVUugb/DistUpgradeController.py", line 1506, in fullUpgrade if not self.doPostInitialUpdate(): File "/tmp/tmp.JLhTwVUugb/DistUpgradeController.py", line 762, in doPostInitialUpdate self.quirks.run("PostInitialUpdate") File "/tmp/tmp.JLhTwVUugb/DistUpgradeQuirks.py", line 83, in run for plugin in self.plugin_manager.get_plugins(condition): File "/tmp/tmp.JLhTwVUugb/computerjanitor/plugin.py", line 167, in get_plugins filenames = self.get_plugin_files() File "/tmp/tmp.JLhTwVUugb/computerjanitor/plugin.py", line 120, in get_plugin_files basenames = [x for x in os.listdir(dirname) OSError: [Errno 2] No such file or directory: './plugins' It does say to report the bug, but since this is an old unsupported release I don't know if it's worth doing. However, is there a way round this, to upgrade from 9.04 to 9.10 (And then finally to 10.04 LTS.)

    Read the article

  • TFS: cannot build my app, CS0042: Unexpected error creating debug information file. Access is denied.

    - by zeta
    I am trying to deploy my MVC app, but in the TFS build I get this error message; CSC : fatal error CS0042: Unexpected error creating debug information file 'c:\Builds\2\STAS\STAS\Sources\Documents and Settings\jyothisrinivasa\My Documents\Visual Studio 2010\Projects\STAS\STAS\obj\Debug\STAS.PDB' -- 'c:\Builds\2\STAS\STAS\Sources\Documents and Settings\jyothisrinivasa\My Documents\Visual Studio 2010\Projects\STAS\STAS\obj\Debug\STAS.pdb: Access is denied. I have excluded the Debug directory from my application, so why am I getting this?

    Read the article

  • System.EntryPointNotFoundException

    - by Hema Joshi
    thank, but by using this i am getting the output c2@ubuntu:~/Desktop$ mcs testingsrp.cs -lib:/home/c2/Desktop/libsrp/libsrp.so c2@ubuntu:~/Desktop$ nm -D /home/c2/Desktop/libsrp/libsrp.so | grep SRP_initialize_library c2@ubuntu:~/Desktop$ MONO_LOG_LEVEL="debug" MONO_LOG_MASK="dll" mono testingsrp.exe Mono-INFO: DllImport attempting to load: 'libsrp.so'. Mono-INFO: DllImport loading location: 'libsrp.so.so'. Mono-INFO: DllImport error loading library: 'libsrp.so.so: cannot open shared object file: No such file or directory'. Mono-INFO: DllImport loading library: './libsrp.so.so'. Mono-INFO: DllImport error loading library './libsrp.so.so: cannot open shared object file: No such file or directory'. Mono-INFO: DllImport loading: 'libsrp.so'. Mono-INFO: Searching for 'SRP_initialize_library'. Mono-INFO: Probing 'SRP_initialize_library'. Mono-INFO: Probing 'SRP_initialize_library'. Mono-INFO: Probing 'SRP_initialize_libraryA'. Mono-INFO: Probing 'SRP_initialize_libraryA'. Mono-INFO: DllImport attempting to load: 'libsrp.so'. Mono-INFO: DllImport loading location: 'libsrp.so.so'. Mono-INFO: DllImport error loading library: 'libsrp.so.so: cannot open shared object file: No such file or directory'. Mono-INFO: DllImport loading library: './libsrp.so.so'. Mono-INFO: DllImport error loading library './libsrp.so.so: cannot open shared object file: No such file or directory'. Mono-INFO: DllImport loading: 'libsrp.so'. Mono-INFO: Searching for 'SRP_finalize_library'. Mono-INFO: Probing 'SRP_finalize_library'. Mono-INFO: Probing 'SRP_finalize_library'. Mono-INFO: Probing 'SRP_finalize_libraryA'. Mono-INFO: Probing 'SRP_finalize_libraryA'. Mono-INFO: DllImport attempting to load: 'libsrp.so'. Mono-INFO: DllImport loading location: 'libsrp.so.so'. Mono-INFO: DllImport error loading library: 'libsrp.so.so: cannot open shared object file: No such file or directory'. Mono-INFO: DllImport loading library: './libsrp.so.so'. Mono-INFO: DllImport error loading library './libsrp.so.so: cannot open shared object file: No such file or directory'. Mono-INFO: DllImport loading: 'libsrp.so'. Mono-INFO: Searching for 'SRP_initialize_library'. Mono-INFO: Probing 'SRP_initialize_library'. Mono-INFO: Probing 'SRP_initialize_library'. Mono-INFO: Probing 'SRP_initialize_libraryA'. Mono-INFO: Probing 'SRP_initialize_libraryA'. Unhandled Exception: System.EntryPointNotFoundException: SRP_initialize_library at (wrapper managed-to-native) Main.Test:SRP_initialize_library () at Main.Test1.Main (System.String[] args) [0x00000] sorry , but really i am not able to get where is the problem .please help me to finding the the problem. thanks

    Read the article

  • Open excel 2007 excel files and save as 97-2003 formats in VBA

    - by ABB
    I have a weird situation where I have a set of excel files, all having the extension .xls., in a directory where I can open all of them just fine in Excel 2007. The odd thing is that I cannot open them in Excel 2003, on the same machine, without opening the file first in 2007 and going and saving the file as an "Excel 97-2003 Workbook". Before I save the file as an "Excel 97-2003 Workbook" from Excel 2007, when I open the excel files in 2003 I get the error that the file is not in a recognizable format. So my question is: if I already have the excel file opened in 2007 and I already have the file name of the open file stored in a variable, programatically how can I mimic the action of going up to the "office button" in the upper right and selecting, "save as" and then selecting "Excel 97-2003 Workbook"? I've tried something like the below but it does not save the file at all: ActiveWorkbook.SaveAs TempFilePath & TempFileName & ".xls", FileFormat:=56 Thanks for any help or guidance!

    Read the article

  • How to get fully qualified path of css file?

    - by Malcolm
    Hi, In ASP.NET MVC how do I get the fully qualified path to my css file by specifying the relative path. Eg Url.Content("~/Content/Print.css") This returns eg "/Content/Print.css" Where as I want http://www.mysite.com/Content/Printcss Understand the issue? Malcolm

    Read the article

  • How to write an XML file without header in Python?

    - by Nico
    Hi, when using Python's stock XML tools such as xml.dom.minidom for XML writing, a file would always start off like <?xml version="1.0"?> [...] While this is perfectly legal XML code, and it's even recommended to use the header, I'd like to get rid of it as one of the programs I'm working with has problems here. I can't seem to find the appropriate option in xml.dom.minidom, so I wondered if there are other packages which do allow to neglect the header. Cheers, Nico

    Read the article

  • If record exists in database, UPDATE a single column

    - by Doug
    I have a bulk uploading object in place that is being used to bulk upload roughly 25-40 image files at a time. Each image is about 100-150 kb in size. During the upload, I've created a for each loop that takes the file name of the image (minus the file extension) to write it into a column named "sku". Also, for each file being uploaded, the date is recorded to a column named DateUpdated, as well as some image path data. Here is my c# code: protected void graphicMultiFileButton_Click(object sender, EventArgs e) { //graphicMultiFile is the ID of the bulk uploading object ( provided by Dean Brettle: http://www.brettle.com/neatupload ) if (graphicMultiFile.Files.Length > 0) { foreach (UploadedFile file in graphicMultiFile.Files) { //strip ".jpg" from file name (will be assigned as SKU) string sku = file.FileName.Substring(0, file.FileName.Length - 4); //assign the directory where the images will be stored on the server string directoryPath = Server.MapPath("~/images/graphicsLib/" + file.FileName); //ensure that if image existes on server that it will get overwritten next time it's uploaded: file.MoveTo(directoryPath, MoveToOptions.Overwrite); //current sql that inserts a record to the db SqlCommand comm; SqlConnection conn; string connectionString = ConfigurationManager.ConnectionStrings["DataConnect"].ConnectionString; conn = new SqlConnection(connectionString); comm = new SqlCommand("INSERT INTO GraphicsLibrary (sku, imagePath, DateUpdated) VALUES (@sku, @imagePath, @DateUpdated)", conn); comm.Parameters.Add("@sku", System.Data.SqlDbType.VarChar, 50); comm.Parameters["@sku"].Value = sku; comm.Parameters.Add("@imagePath", System.Data.SqlDbType.VarChar, 300); comm.Parameters["@imagePath"].Value = "images/graphicsLib/" + file.FileName; comm.Parameters.Add("@DateUpdated", System.Data.SqlDbType.DateTime); comm.Parameters["@DateUpdated"].Value = DateTime.Now; conn.Open(); comm.ExecuteNonQuery(); conn.Close(); } } } After images are uploaded, managers will go back and re-upload images that have previously been uploaded. This is because these product images are always being revised and improved. For each new/improved image, the file name and extension will remain the same - so that when image 321-54321.jpg was first uploaded to the server, the new/improved version of that image will still have the image file name as 321-54321.jpg. I can't say for sure if the file sizes will remain in the 100-150KB range. I'll assume that the image file size will grow eventually. When images get uploaded (again), there of course will be an existing record in the database for that image. What is the best way to: Check the database for the existing record (stored procedure or SqlDataReader or create a DataSet ...?) Then if record exists, simply UPDATE that record so that the DateUpdated column gets today's date. If no record exists, do the INSERT of the record as normal. Things to consider: If the record exists, we'll let the actual image be uploaded. It will simply overwrite the existing image so that the new version gets displayed on the web. We're using SQL Server 2000 on hosted environment (DiscountAsp). I'm programming in C#. The uploading process will be used by about 2 managers a few times a month (each) - which to me is not a allot of usage. Although I'm a jr. developer, I'm guessing that a stored procedure would be the way to go. Just seems more efficient - to do this record check away from the for each loop... but not sure. I'd need extra help writing a sproc, since I don't have too much experience with them. Thank everyone...

    Read the article

  • Trouble using ‘this.files’ in GruntJS Tasks

    - by whomba
    Background: So I’m new to writing grunt tasks, so hopefully this isn’t a stupid question. Purpose of my grunt task: Given a file (html / jsp / php / etc) search all the link / script tags, compare the href / src to a key, and replace with the contents of the file. Proposed task configuration: myTask:{ index:{ files:{src:"test/testcode/index.html", dest:"test/testcode/index.html"}, css:[ { file: "/css/some/css/file.css", fileToReplace:"/target/css/file.css" }, { file: "/css/some/css/file2.css", fileToReplace:"/target/css/file2.css" } ], js:[ { file: "/css/some/css/file.css", fileToReplace:”/target/css/file.css" }, { file: "/css/some/css/file2.css", fileToReplace:"/target/css/file2.css" } ] } } Problem: Now, per my understanding, when dealing with files, you should reference the ‘this.files’ object because it handles a bunch of nice things for you, correct? Using intelliJ and the debugger, I see the following when i watch the ‘this.files’ object: http://i.imgur.com/Gj6iANo.png What I would expect to see is src and dest to be the same, not dest ===‘src’ and src === undefined. So, What is it that I am missing? Is there some documentation on ‘this.files’ I can read about? I’ve tried setting the files attribute in the target to a number of other formats per grunts spec, none seem to work (for this script, ideally the src / dest would be the same, so the user would just have to enter it once, but i’m not even getting in to that right now.) Thanks for the help

    Read the article

  • Linux Bash Script, Single Command But Multiple Lines?

    - by Jay LaCroix
    I have the following script I wrote by searching Google, and it backs up my Linux system to an archive: #!/bin/bash # init DATE=$(date +20%y%m%d) tar -cvpzf /share/Recovery/Snapshots/$HOSTNAME_$DATE.tar.gz --exclude=/proc --exclude=/lost+found --exclude=/sys --exclude=/mnt --exclude=/media --exclude=/dev --exclude=/share/Archive / This works, but I am wondering if I can format the script to show the command over multiple lines, something like this, so it is easy to edit later: tar -cvpzf /share/Recovery/Snapshots/$HOSTNAME_$DATE.tar.gz --exclude=/proc --exclude=/lost+found --exclude=/sys --exclude=/mnt --exclude=/media --exclude=/dev --exclude=/share/Archive / That way it is easier to read and edit later. Is it possible to format a Bash script this way?

    Read the article

  • TinyMCE Not Defined Error

    - by Tim
    I am trying to add TinyMCE to page but I am getting these errors: Error: tinyMCE is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/langs/en.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/themes/advanced/editor_template.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/pagebreak/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/style/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/advimage/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/advlink/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/iespell/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/preview/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/media/editor_plugin.js Line: 1 Error: tinymce is not defined Source File: https://my.secure.site/tinymce/jscripts/tiny_mce/plugins/paste/editor_plugin.js Line: 1 Here is the code I have in header: <script type="text/javascript" src="https://my.secure.site/jquery/jquery-1.3.2.min.js"></script> <script type="text/javascript" src="https://my.secure.site/tinymce/jscripts/tiny_mce/tiny_mce.js"></script> <script type="text/javascript"> $(document).ready(function() { tinyMCE.init({ mode: "textareas", script_url: "https://my.secure.site/tinymce/jscripts/tiny_mce/tiny_mce.js", theme: "advanced", plugins: "pagebreak,style,advimage,advlink,iespell,preview,media,paste", theme_advanced_buttons1: "help,newdocument,|,bold,italic,underline,strikethrough,|,link,unlink,anchor,image", theme_advanced_buttons2: "fontsizeselect,hr,removeformat,charmap,visualaid,sub,sup", theme_advanced_buttons3: "cut,copy,paste,|,undo,redo,|,cleanup,code,preview", theme_advanced_toolbar_location: "top", theme_advanced_toolbar_align: "left", theme_advanced_statusbar_location: "bottom", theme_advanced_resizing: false, editor_selector: "tinymce", width: "398px", force_p_newlines: false, force_br_newlines: true }); }); </script> And this is my textarea that I'm expecting TinyMCE to use: <textarea id="post1msg" class="tinymce" rows="4" cols="40"><?=$r->post->message?></textarea> Please does anyone have any idea why it's not working?

    Read the article

  • Why does Mac OS X ignore my Windows NTFS and Share permissions?

    - by Michael
    Mac OS X Snow Leopard Windows Server 2003 Windows Folder "Videos" Share Permissions on Videos - Everyone NTFS Permissions on Videos - System (Full Control) - Domain Users (Modify) - Domain Admins (Full Control) Mac user Michael is a part of the Domain Users group. He connects to Videos using cifs://server/Videos and authenticates with his username Michael. Michael copies over a file "dance dance baby.avi". User Jon opens the Videos folder but cannot see the dance dance baby.avi file. Checking the dance dance baby.avi file permissions here is what I see: Everyone - Read, Write Domain Admins - Full Control Michael - Read, Write Owner of File - Michael So here's my question, how come when Michael copies a file over from a Mac, the permissions on the file get changed even though Michael has no rights to change permissions? If the same file is copied over from a Windows machine, it just inherits the proper permissions from the parent Video folder. Am I missing something? Are my permissions wrong? Thanks. Michael

    Read the article

  • pip install -E requirements.txt failure

    - by Alexander A.Sosnovskiy
    Why does this happen? pip install -E ../../conf/requirements.txt Traceback (most recent call last): File "/home/alecs/workspace/Homepage/env/bin/pip", line 5, in <module> pkg_resources.run_script('pip==0.7.1', 'pip') File "/home/alecs/workspace/Homepage/env/lib/python2.6/site-packages/setuptools-0.6c11-py2.6.egg/pkg_resources.py", line 489, in run_script File "/home/alecs/workspace/Homepage/env/lib/python2.6/site-packages/setuptools-0.6c11-py2.6.egg/pkg_resources.py", line 1207, in run_script File "/home/alecs/workspace/Homepage/env/lib/python2.6/site-packages/pip-0.7.1-py2.6.egg/EGG-INFO/scripts/pip", line 3, in <module> sys.exit(pip.main()) File "/home/alecs/workspace/Homepage/env/lib/python2.6/site-packages/pip-0.7.1-py2.6.egg/pip/__init__.py", line 94, in main return command.main(initial_args, args[1:], options) File "/home/alecs/workspace/Homepage/env/lib/python2.6/site-packages/pip-0.7.1-py2.6.egg/pip/basecommand.py", line 103, in main complete_args) File "/home/alecs/workspace/Homepage/env/lib/python2.6/site-packages/pip-0.7.1-py2.6.egg/pip/venv.py", line 50, in restart_in_venv [python, file] + args + [base, '___VENV_RESTART___']) File "/usr/lib/python2.6/subprocess.py", line 633, in __init__ errread, errwrite) File "/usr/lib/python2.6/subprocess.py", line 1139, in _execute_child raise child_exception OSError: [Errno 13] Permission denied Thanks.

    Read the article

  • build .pyc prob

    - by Apache
    hi experts, i build .py as follow python /root/pyinstaller-1.4/Makespec.py test.py then python /root/pyinstaller-1.4/Build.py test.spec this working fine then i test to build with my .pyc as follow python /root/pyinstaller-1.4/Makespec.py test.pyc then python /root/pyinstaller-1.4/Build.pyc test.spec but its generating error as follow checking Analysis building because inputs changed running Analysis outAnalysis0.toc Analyzing: /root/pyinstaller-1.4/support/_mountzlib.py Analyzing: /root/pyinstaller-1.4/support/useUnicode.py Analyzing: test.pyc Traceback (most recent call last): File "/root/pyinstaller-1.4/Build.py", line 1160, in main(args[0], configfilename=opts.configfile) File "/root/pyinstaller-1.4/Build.py", line 1148, in main build(specfile) File "/root/pyinstaller-1.4/Build.py", line 1111, in build execfile(spec) File "test.spec", line 3, in pathex=['/root/test']) File "/root/pyinstaller-1.4/Build.py", line 245, in init self.postinit() File "/root/pyinstaller-1.4/Build.py", line 196, in postinit self.assemble() File "/root/pyinstaller-1.4/Build.py", line 314, in assemble analyzer.analyze_script(script) File "/root/pyinstaller-1.4/mf.py", line 559, in analyze_script co = compile(string.replace(stuff, "\r\n", "\n"), fnm, 'exec') TypeError: compile() expected string without null bytes why this error occur, cannot we build using .pyc, or there is other way to build it,

    Read the article

  • What is casper rw loop file and why do I need it to make saving persistant on usb flash drive?

    - by l245c4l
    Suppose I've installed linux on my flash drive. Why do I need something like casper loop file to make saving persistant? So files are being erased? Isn't flash drive the same as actual hard drive? I'm linux noob so be patient. Or it is because linux on flash drive is actually live cd on flash drive? Can it be installed just like it is installed on hard drive? Thanks in advance

    Read the article

  • OSX, G/AWK, Bash - "illegal statement, unterminated string" and no file output.

    - by S1syphus
    I have a script that somebody from SO kindly provided to solve an issue I was having, However, I'm having some issues getting it to work on OSX. gawk --version GNU Awk 3.1.6 awk --version awk version 20100208 The original source is: awk -F, -vOFS=, -vc=1 ' NR == 1 { for (i=1; i<NF; i++) { if ($i != "") { g[c]=i; f[c++]=$i } } } NR>2 { for (i=1; i < c; i++) { print $1,$2, $g[i] > "output_"f[i]".csv } }' data.csv When I run the script it gives the following error: awk: syntax error at source line 12 context is print $1,$2, $g[i] > >>> "output_"f <<< [i]".csv awk: illegal statement at source line 13 From the look of it the variable of [i] isn't been amended to the output file, but I don't know why. If I change AWK to GAWK and run the original script here is the output: gawk: cmd. line:11: print $1,$2, $g[i] > "output_"f[i]".csv gawk: cmd. line:11: ^ unterminated string So I edit the relevant line to fix the unterminated string print $1,$2, $g[i] > "output_"f[i]".csv" Then it runs through fine produces no errors, but there is no output files. Any ideas? I spent the majority of last night and this morning pouring over this. A sample input file: ,,L1,,,L2,,,L3,,,L4,,,L5,,,L6,,,L7,,,L8,,,L9,,,L10,,,L11, Title,r/t,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,neede d,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst EXAMPLEfoo,60,6,6,6,0,0,0,0,0,0,6,6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 EXAMPLEbar,30,6,6,12,6,7,14,6,6,12,6,6,12,6,8,16,6,7,14,6,7.5,15,6,6,12,6,8,16,6,0,0,6,7,14 EXAMPLE1,60,3,3,3,3,5,5,3,4,4,3,3,3,3,6,6,3,4,4,3,3,3,3,4,4,3,8,8,3,0,0,3,4,4 EXAMPLE2,120,6,6,3,0,0,0,6,8,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 EXAMPLE3,60,6,6,6,6,8,8,6,6,6,6,6,6,0,0,0,0,0,0,6,8,8,6,6,6,0,0,0,0,0,0,0,10,10 EXAMPLE4,30,6,6,12,6,7,14,6,6,12,6,6,12,3,5.5,11,6,7.5,15,6,6,12,6,0,0,6,9,18,6,0,0,6,6.5,13 And the example out put should be So for L1 an example out put would look like: EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 And for L2: EXAMPLEfoo,60,0 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,0 EXAMPLE3,60,6 EXAMPLE4,30,6

    Read the article

  • Rails. How to extend controller class from plugin without any modification in controller file?

    - by potapuff
    I'm use Rails 2.2.2. Rails manual said, the way to extend controller from plug-in is: Plugin: module Plug def self.included(base) base.extend ClassMethods base.send :include, InstanceMethods base.helper JumpLinksHelper end module InstanceMethods def new_controller_metod ... end end module ClassMethods end end app/controller/name_controller.rb class NameController < ApplicationController include Plug ... end Question: is any way to extend controller from plug-in, without any modification of controller file, if we know controller name.

    Read the article

< Previous Page | 604 605 606 607 608 609 610 611 612 613 614 615  | Next Page >