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  • What''s the "earliest" place one can set an environment variable during Linux boot process?

    - by amn
    I know I can set a variable in a shell startup file, but the thing is, I am trying to set up a POSIX-compatible environment, and a POSIX shell does not parse any startup files other than the one specified by the environment variable ENV. This presents a problem - currently my login starts the shell as bash, which I will try to replace with sh so Bash runs as POSIX shell - however then it will not parse the default startup files and I need ENV set to specify these. Which means as far as I understand that I need to specify ENV before login starts the shell, correct? Now, how would I do that? I hope my question is clear, if not I will gladly redact it.

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  • Terminal Server 2003 Login Issue - Insufficient system resources exist to complete the requested ser

    - by LP
    Afternoon. We have three identical terminal servers running Windows Server 2003 SP2, on these servers there are about 250 concurrent users logged on. We're running Roaming Profiles on a central server running Active Directory which cache the profiles locally on each terminal server as well. When one, and just that one, user tries to login she gets this error message (roughly translated from Swedish): "You could not be logged in becouse your principle could not be registered. Check that you're connected to the network or ask your administrator Insufficient system resources exist to complete the requested service." Anyone have an idea about this? I'm stumped ... Best Regards LP

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  • Need a GUI app for group policy login script

    - by jayPal
    I wrote a C# 4.0 application that works on a Windows computer but when using Group Policy to set it as a login script, it does not run. The application is being called from the same location and using rsop.msc shows that the application should be run. I see that using C# 4.0 may be a little overkill for this purpose, but it just seems wrong to write a VB6 application to do the same thing. The requirements for the application states that there need to be specific GUI elements that can't be just text on the window. I need larger fonts and color elements. Is there something more appropriate (and current) that I should be using?

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  • Help with user login on Centos 5.6

    - by Owen
    I added a user for the sole purpose of using SU for root. I did not allow the creation of a home directory when creating the user. So now when I login as this user I get the following: Could not chdir to home directory /home/MYUSERNAME: No such file or directory Couldn't resolve homedir for current user at - line 0 BEGIN failed--compilation aborted. Couldn't resolve homedir for current user at - line 0 BEGIN failed--compilation aborted. Is this an error, and if so how do I fix it so it is not looking to "resolve" the homedir?

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  • Limit access on login and IP in .htaccess

    - by Rob
    There are many examples showing how to use .htaccess to restrict users by login or on their IP address (i.e they are ok from the ones given without authorisation). For some reason the following is never mentioned, yet it seems quite useful. How do I restrict using groups and ip, e.g. group1 can access the page from anywhere group2 can access the page only from certain IP addresses if you are not logged on, you cant see the page, regardless where you are I would like to have all 3 of these working at the same time.

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  • Can't get to the login screen

    - by Rod
    I upgraded my wife's Windows 7 machine, to Windows 8 Pro, about 10 days ago. She's been using it fine ever since. We typically leave our desktops running 24/7, and just turn off the monitor. This morning she turned the monitor on, and saw the screen with the Seattle Space Needle, and then she pressed the enter key to get to the login screen. Nothing happened. Next she pressed the mouse key. Nothing happened. The mouse moves around fine. But we can't get it past the Seattle Space Needle screen. She replaced the batteries in both her keyboard and mouse recently. So, what's going on? How do we fix it?

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  • Citrix on ESX 4 U1 - Slow login times

    - by thomps01
    I'm sure they'd be just as slow if not slower using ESX 3 but I'm looking for some assistance. On a physical Citrix server, logins are 1 - 4 seconds. The virtual - 16 - 23 seconds. I'm looking for performance enhancements that I can make to me VMs to try and reduce the login wait times. The hardware is fine (HP BL685 (24 cores, 64GB RAM). And there's nothing pushing it yet. Network 10Gb I'm planning to test the configuration with VMXNET3 tomorrow, but does anyone have a list a best practices I can use when testing?

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  • FaceBook Login Problem

    - by toman
    Hi All, I am for an application which extracts information from facebook search, hence i require to login facebook. i have registered my application in facebook developers site and have got api key and secret key. in my code i am getting an exception when i am trying to login. Here is my code for login to facebook: import com.facebook.api.FacebookRestClient; import org.apache.commons.httpclient.HttpClient; import org.apache.commons.httpclient.HttpState; import org.apache.commons.httpclient.NameValuePair; import org.apache.commons.httpclient.methods.GetMethod; import org.apache.commons.httpclient.methods.PostMethod; import org.apache.commons.httpclient.params.HttpClientParams; public class FaceLogin { public FaceLogin(){ getUserID("username", "password"); } private static void getUserID(String email, String password) { String session = null; try { HttpClient http = new HttpClient(); http.setParams(new HttpClientParams()); //http.getHostConfiguration().setHost("http://www.facebook.com/"); http.setState(new HttpState()); String api_key = "****some key****"; String secret = "****some key****"; FacebookRestClient client = new FacebookRestClient(api_key, secret); client.setIsDesktop(true); String token = client.auth_createToken(); final String loginId = "http://www.facebook.com/login.php"; GetMethod get = new GetMethod(loginId + "?api_key=" + api_key + "&v=1.0&auth_token=" +token); System.out.println("Get="+get); http.executeMethod(get); PostMethod post = new PostMethod(loginId); post.addParameter(new NameValuePair("api_key", api_key)); post.addParameter(new NameValuePair("v", "1.0")); post.addParameter(new NameValuePair("auth_token", token)); post.addParameter(new NameValuePair("fbconnect","true")); post.addParameter(new NameValuePair("return_session","true")); post.addParameter(new NameValuePair("session_key_only","true")); post.addParameter(new NameValuePair("req_perms","read_stream,publish_stream")); post.addParameter(new NameValuePair("lsd","8HYdi")); post.addParameter(new NameValuePair("locale","en_US")); post.addParameter(new NameValuePair("persistent","1")); post.addParameter(new NameValuePair("email", email)); post.addParameter(new NameValuePair("pass", password)); System.out.println("Token ="+token); int postStatus = http.executeMethod(post); System.out.println("Response : " + postStatus); session = client.auth_getSession(token); // Here I am getting error System.out.println("Session string: " + session); long userid = client.users_getLoggedInUser(); System.out.println("User Id is : " + userid); } catch (Exception e) { e.printStackTrace(); } } public static void main(String k[]) { FaceLogin facebookLoginObj=new FaceLogin(); } } I am getting the following exception: org.apache.commons.httpclient.HttpMethodBase processResponseHeaders WARNING: Cookie rejected: "$Version=0; $Domain=deleted; $Path=/; $Domain=.facebook.com". Cookie name may not start with $ Response : 200 Jun 8, 2010 2:07:36 PM org.apache.commons.httpclient.HttpMethodBase processResponseHeaders WARNING: Cookie rejected: "$Version=0; $Path=deleted; $Path=/; $Domain=.facebook.com". Cookie name may not start with $ Facebook returns error code 100 com.facebook.api.FacebookException: Invalid parameter - v - 1.0 at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:828) - auth_token - 004e90dc8818d5f0921d1065d24508d3 at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:606) - method - facebook.auth.getSession - call_id - 1275986256796 - api_key - f7cb1e48c383ef599da9021fc4dec322 at com.facebook.api.FacebookRestClient.auth_getSession(FacebookRestClient.java:1891) at facebookcrawler.FacebookLogin.getUserID(FacebookLogin.java:81) at facebookcrawler.FacebookLogin.( - sig - 9344ec75b74a0a87bcae645046d45da8 FacebookLogin.java:24) at facebookcrawler.FaceLogin.main(FaceLogin.java:80) Here may be the problem is for creating session, i searched for all the solutions on net but could not helped me to get login. Please help me if you can suggest me some way to resolve this problem. i thanks to all your valuable suggestion.

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  • mobile browsers' can't login to my site

    - by imin
    i've tested my site on 2 phone models using the 'generic' browser that came with the phone, but sadly, everytime I tried to login, it will return me back to my index page. here's my login code <form name='login' method='POST' action='authentication.php'> <table border=0 cellpadding=2> <tr><td>Login:</td><td></td></tr> <tr><td>E-mail: </td><td><input type=text name='email' id='email' size=20 maxlength="200"></td></tr> <tr><td>Password: </td><td><input type=password name='password' id='password' size=20 maxlength="100"></td></tr> <tr><td></td><td><input type=submit value='Login'></td></tr> </table></form> and here's the authentication.php (snippet) $currentUserEmail = $_POST["email"]; $currentUserPwd = md5($_POST["password"]); $stmt = $dbi->prepare("select status from users where email=? and pwd=?"); $stmt->bind_param('ss', $currentUserEmail,$currentUserPwd); mysqli_stmt_execute($stmt); mysqli_stmt_store_result($stmt); $isUserAvailable = mysqli_stmt_num_rows($stmt); $stmt->bind_result($getUserStatus); $stmt->execute() or die (mysqli_error()); $stmt->store_result(); $stmt->fetch(); $stmt->close(); if($isUserAvailable > 0){ if ($getUserStatus == "PENDING") { $userIsLoggedIn = "NO"; $registeredUser = "NO"; unset($userIsLoggedIn); setcookie("currentMobileUserName", "", time()-3600); setcookie("currentMobileUserEmail", "", time()-3600); setcookie("currentMobileSessionID", "", time()-3600); setcookie("currentMobileUID", "", time()-3600); header('Location: '.$config['MOBILE_URL'].'/index.php?error=2&email='.$currentUserEmail); }elseif (($getUserStatus == "ACTIVE") || ($getUserStatus == "active")){ //means successfully logged in //set the cookie setcookie("currentMobileUserName", $currentUserName, $expire); setcookie("currentMobileUserEmail", $currentUserEmail, $expire); setcookie("currentMobileSessionID", $getGeneratedMobileUSID, $expire); setcookie("currentMobileUID", $currentUID, $expire); $userIsLoggedIn = "YES"; $registeredUser = "YES"; $result = $stmt->execute() or die (mysqli_error($dbi)); if ($caller == "indexLoginForm"){ header('Location: '.$config['MOBILE_URL'].'/home.php'); }else{ header('Location: '.$config['MOBILE_URL'].'/home.php'); } } }else{ $userIsLoggedIn = "NO"; $registeredUser = "NO"; unset($userIsLoggedIn); setcookie("currentMobileUserName", "", time()-3600); setcookie("currentMobileUserEmail", "", time()-3600); setcookie("currentMobileSessionID", "", time()-3600); setcookie("currentMobileUID", "", time()-3600); header('Location: '.$config['MOBILE_URL'].'/index.php?error=1'); } The only way I can access my mobile site is by using opera mini. Just FYI, both the 'generic browsers' i tested my site with supports cookie (at least this is what the browser settings said). thanks

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  • SQL SERVER – FIX ERROR – Cannot connect to . Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452)

    - by pinaldave
    Just a day ago, I was doing small attempting to connect to my local SQL Server using IP 127.0.0.1. The IP is of my local machine and SQL Server is installed on the local box as well. However, whenever I try to connect to the server it gave me following strange error. Cannot connect to 127.0.0.1. Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452) The reason was indeed strange as I was trying to connect from local box to local box and it said my login was from an untrusted domain. As my system is not part of any domain, this was really confusing to me. Another thing was that I have been always able to connect always using 127.0.0.1 to SQL Server and this was a bit strange to me. I started to think what did I change since it  last time I connected to SQL Server. Suddenly I remembered that I had modified my computer’s host file for some other purpose. Solution: I opened my host file and immediately added entry like 127.0.0.1 localhost. Once I added it I was able to reconnect to SQL Server as usual. The location of the host file is C:\Windows\System32\drivers\etc. You will find file with the name hosts in it, make sure to open it with notepad. If you are part of a domain and your organization is using active directory, make sure that your account is added properly to active directory as well have proper security permissions to execute the task. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Overlay WPF controls

    - by sandy
    Hello I've written an 'auto-suggest' textbox user control in WPF. It behaves a little bit like the 'To' list in Hotmail, allowing the user to enter a list of items, offering suggestions when it is able. The main controls are a a text box, a wrap panel and a list box. The text box captures user input. The wrap panel contains the text box and shows previous entries. The list box is used to show suggestions. Most of the time, the list box is hidden. I'm using multiple instances of my control in a stack panel. My problem is that when the list box is shown, it is included in the measurement of the height of the control. This forces the following controls in the stack panel to be shifted down, as these pictures demonstrate: I've tried overriding the measurement of my control so not to include the list box, but this just results in the list box not being visible. What I want to do is make the list box overlay any subsequent controls in the stack panel, like a combo box's drop down would do. However, I really don't know how to do this. Any ideas? Thanks Sandy

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  • Dynamically created "CheckBoxList" in placeholder controls throwing null reference exception error d

    - by newName
    I have a web form that will dynamically create a number of checkboxlist filled with data based on the number of row in database. Then this is added to a placeholder to be displayed. theres a button when clicked, will add the selected check boxes value into database but right now when the button is clicked and after the postback, the page will show the error "System.NullReferenceException". the following code is written in Page_Load in (!Page.IsNotPostBack) and in a loop that will dynamically create a number of checkboxlist: CheckBoxLis chkContent = new CheckBoxList(); chkContent.ID = chkIDString; //chkIDString is an incremental int based on the row count chkContent.RepeatDirection = RepeatDirection.Horizontal; foreach (List<t> contentList in List<t>) //data retrieved as List<t> using LINQ { ListItem contents = new ListItem(); contents.Text = contentList.Title; contents.Value = contentList.contentID.ToString(); chkContent.Items.Add(contents); } plcSchool.Controls.Add(chkContent); //plcSchool is my placeholder plcSchool.Controls.Add(new LiteralControl("<br>")); protected void btnAdd_Click(object sender, EventArgs e) { CheckBoxList cbl = Page.FindControl("chkContent4") as CheckBoxList; Response.Write(cbl.SelectedValue.ToString()); // now im just testing to get the value from one of the checkboxlist } Anyone able to help, as it seems the controls are not recreated after the postback, therefore it can't find the control and throwing the null reference exception.

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  • Dynamic ASP.NET controls using Infragistics

    - by Emil D
    So, in my asp.net webapp I need to dynamically load a custom control, based on the selected value of a dropdown list.That seems to work at first glance, but for some reason all infragistics controls that I have in my custom control appear, but won't work.I get a "Can't init [controlname]" warning in my browser.If I declare my custom control statically, this problem doesn't apprear Here's my code: Markup: <%@ Control Language="C#" AutoEventWireup="true" CodeBehind="GenericReportGUI.ascx.cs" Inherits="GenericReportGUI" %> <%@ Register assembly="Infragistics35.WebUI.Misc.v8.3, Version=8.3.20083.1009,Culture=neutral, PublicKeyToken=7dd5c3163f2cd0cb" namespace="Infragistics.WebUI.Misc" tagprefix="igmisc" %> <asp:UpdatePanel ID="myUpdatePanel" runat="server" UpdateMode="Conditional"> <ContentTemplate> <igmisc:WebPanel ID="WebPanel1" runat="server"> <Template> <div> <asp:PlaceHolder ID="Placeholder" runat="server"> </asp:PlaceHolder> </div> </Template> </igmisc:WebPanel> </ContentTemplate> </asp:UpdatePanel> Code-behind: public partial class GenericReportGUI : System.Web.UI.UserControl { protected void Page_Load(object sender, EventArgs e) { } protected override void OnPreRender( EventArgs e ) { base.OnPreRender(e); loadCustomControl(); } protected void loadCustomControl() { Placeholder.Controls.Clear(); string controlPath = getPath(); //getPath() returns the path to the .ascx file we need to load, based on the selected value of a dropdownlist try { Control newControl = LoadControl( controlPath ); Placeholder.Controls.Add( newControl ); } catch { //if the desired control cannot be loaded, display nothing } myUpdatePanel.Update();//Update the UpdatePanel that contains the custom control } } I'm a total noob when it comes to asp.net, so any help with this issue would be greatly appreciated.

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  • 'System.Web.UI.Control.Controls' is a 'property' but is used like a 'type'

    - by senzacionale
    What i am doing wrong? I extend LinkButton and i get this error Compilation Error Description: An error occurred during the compilation of a resource required to service this request. Please review the following specific error details and modify your source code appropriately. Compiler Error Message: CS0118: 'System.Web.UI.Control.Controls' is a 'property' but is used like a 'type' Source Error: Line 1084: Line 1085: public void @_DataBinding_control30(object sender, System.EventArgs e) { Line 1086: ConfirmButton.Controls.ConfirmLinkButton dataBindingExpressionBuilderTarget; Line 1087: System.Web.UI.IDataItemContainer Container; Line 1088: dataBindingExpressionBuilderTarget = ((ConfirmButton.Controls.ConfirmLinkButton)(sender)); This is C# code: [Localizable(true)] public string Message { get { return ViewState["Message"] as string; } set { ViewState["Message"] = value; } } #region Overriden protected override void OnPreRender(EventArgs e) { if (!String.IsNullOrEmpty(Message)) { WebControlUtils.SetConfirmationMessage(Page, typeof (Page), this, Message, Page.IsAsyncPostBack(), CausesValidation); } base.OnPreRender(e); } #endregion ASPX CODE: <asp:TemplateField> <ItemTemplate> <asp:ConfirmLinkButton ID="lnkBtnDelete" runat="server" Text="Odstrani" Message="Delete?" CommandName="DeleteAgencie" Width="50" CommandArgument='<%# Eval("idAgencies") %>' OnCommand="lnkBtnDelete_Command" CausesValidation="False"></asp:ConfirmLinkButton> </ItemTemplate> </asp:TemplateField> Regards

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  • Parent Control Mouse Enter/Leave Events With Child Controls

    - by Paul Williams
    I have a C# .NET 2.0 WinForms app. My app has a control that is a container for two child controls: a label, and some kind of edit control. You can think of it like this, where the outer box is the parent control: +---------------------------------+ | [Label Control] [Edit Control] | +---------------------------------+ I am trying to do something when the mouse enters or leaves the parent control, but I don't care if the mouse moves into one of its children. I want a single flag to represent "the mouse is somewhere inside the parent or children" and "the mouse has moved outside of the parent control bounds". I've tried handling MouseEnter and MouseLeave on the parent and both child controls, but this means the action begins and ends multiple times as the mouse moves across the control. In other words, I get this: Parent.OnMouseEnter (start doing something) Parent.OnMouseLeave (stop) Child.OnMouseEnter (start doing something) Child.OnMouseLeave (stop) Parent.OnMouseEnter (start doing something) Parent.OnMouseLeave (stop) The intermediate OnMouseLeave events cause some undesired effects as whatever I'm doing gets started and then stopped. I want to avoid that. I don't want to capture the mouse as the parent gets the mouse over, because the child controls need their mouse events, and I want menu and other shortcut keys to work. Is there a way to do this inside the .NET framework? Or do I need to use a Windows mouse hook?

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  • Using Build Manager Class to Load ASPX Files and Populate its Controls

    - by Sandhurst
    I am using BuildManager Class to Load a dynamically generated ASPX File, please note that it does not have a corresponding .cs file. Using Following code I am able to load the aspx file, I am even able to loop through the control collection of the dynamically created aspx file, but when I am assigning values to controls they are not showing it up. for example if I am binding the value "Dummy" to TextBox control of the aspx page, the textbox remains empty. Here's the code that I am using protected void Page_Load(object sender, EventArgs e) { LoadPage("~/Demo.aspx"); } public static void LoadPage(string pagePath) { // get the compiled type of referenced path Type type = BuildManager.GetCompiledType(pagePath); // if type is null, could not determine page type if (type == null) throw new ApplicationException("Page " + pagePath + " not found"); // cast page object (could also cast an interface instance as well) // in this example, ASP220Page is a custom base page System.Web.UI.Page pageView = (System.Web.UI.Page)Activator.CreateInstance(type); // call page title pageView.Title = "Dynamically loaded page..."; // call custom property of ASP220Page //pageView.InternalControls.Add( // new LiteralControl("Served dynamically...")); // process the request with updated object ((IHttpHandler)pageView).ProcessRequest(HttpContext.Current); LoadDataInDynamicPage(pageView); } private static void LoadDataInDynamicPage(Page prvPage) { foreach (Control ctrl in prvPage.Controls) { //Find Form Control if (ctrl.ID != null) { if (ctrl.ID.Equals("form1")) { AllFormsClass cls = new AllFormsClass(); DataSet ds = cls.GetConditionalData("1"); foreach (Control ctr in ctrl.Controls) { if (ctr is TextBox) { if (ctr.ID.Contains("_M")) { TextBox drpControl = (TextBox)ctr; drpControl.Text = ds.Tables[0].Rows[0][ctr.ID].ToString(); } else if (ctr.ID.Contains("_O")) { TextBox drpControl = (TextBox)ctr; drpControl.Text = ds.Tables[1].Rows[0][ctr.ID].ToString(); } } } } } } }

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  • VS2010 and CSS: What is the best strategy to individually position form controls

    - by George
    OK, I have a ton of controls on my page that I need to individually place. I need to set a margin here, a padding there, etc. None of these particular styles that I want to apply will be applied to more than control. What is the bets practice for determining at which level the style is placed, etc? OK, my choices are 1) External CSS file 1A) Using ClientIdMode = Auto (the default) I could assign a unique CssClass value to the ASP.NET control and, in the external CSS file, create a class selector that would only be applied to that one control. 1B) User Client ID = Predicatable In the external CSS file, I could determine what the ID will be for the controls of interest and create an ID selector (#ControlID{Style} ). However, I fear maintenance issues due to including/removing parent containers that would cause the ID to change. 1C) User Client ID = Static. I could choose static IDs for the controls such that I minimize the likelihood of a clash with auto generated IDs (perhaps by prefixing the ID with "StaticID_" and use an external stylesheet with ID selectors. 2) I could place the style right on the control. The only disadvantage here, as I see it, is that style info is brought down each time instead of being cached , which is what I'd get using an external CSS. If a style isn't resused, I personally don't see much benefit to placing it in an external file, though please explain why if you disagree. Is there moire of a reason that "It's nice to have all the CSS in one place?"

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  • mediaelement.js play/pause on click controls don't work

    - by iKode
    I need to play and pause the video player if any part of the video is clicked, so I implemented something like: $("#promoPlayer").click(function() { $("#promoPlayer").click(function() { if(this.paused){ this.play(); } else { this.pause(); } }); ...but now the controls of the video won't pause/play. You can see it in action here(http://175.107.134.113:8080/). The video is the second slide on the main carousel at the top. I suspect I'm now getting 2 onclick events one from my code above and a second on the actual pause/play button. I don't understand how the actual video controls work, because when I inspect the element, I just see a tag. If I could differentiate the controls, then perhaps I might have figured out a solution by now. Anyone know how I should have done this, or is my solution ok. If my solutions ok, how do I intercept a click on the control, so that I only have one click event to pause / play? If you look on the media element home page, they have a big play button, complete with mouseOver, but I can't see how they have done that? Can someone else help?

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  • Silverlight performance with many loaded controls

    - by gius
    I have a SL application with many DataGrids (from Silverlight Toolkit), each on its own view. If several DataGrids are opened, changing between views (TabItems, for example) takes a long time (few seconds) and it freezes the whole application (UI thread). The more DataGrids are loaded, the longer the change takes. These DataGrids that slow the UI chanage might be on other places in the app and not even visible at that moment. But once they are opened (and loaded with data), they slow showing other DataGrids. Note that DataGrids are NOT disposed and then recreated again, they still remain in memory, only their parent control is being hidden and visible again. I have profiled the application. It shows that agcore.dll's SetValue function is the bottleneck. Unfortunately, debug symbols are not available for this Silverlight native library responsible for drawing. The problem is not in the DataGrid control - I tried to replace it with XCeed's grid and the performance when changing views is even worse. Do you have any idea how to solve this problem? Why more opened controls slow down other controls? I have created a sample that shows this issue: http://cenud.cz/PerfTest.zip UPDATE: Using VS11 profiler on the sample provided suggests that the problem could be in MeasureOverride being called many times (for each DataGridCell, I guess). But still, why is it slower as more controls are loaded elsewhere? Is there a way to improve the performance?

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  • Excel controls not visible for certain users

    - by Nossidge
    One of the users of an Excel program I've written is having a weird problem. None of the control objects (Command Button, ComboBox, etc.) are visible to him when he opens the file on his laptop. He is using Excel 2003, the same version I used to create the program, and enables macros using the pop-up when the file loads. I have Googled this, and have found these people who seem to be having the exact same problem, with various versions of Excel. Unfortunately, none of their questions were answered. I can't really explain it any better than this user: If I enter design mode and pull a control from the control toolbar onto a sheet all I see are the drag handles. When not in design mode I have to feel around with the mouse and can click the button which executes the button click code correctly and opens another sheet where again I have to feel around for the buttons to return me to the original sheet. The button I managed to click is now visible but as soon as I click anywhere on the sheet it disappears. I have verified that the visible property of the buttons is set and that the Show All Objects on the Options View tab is selected. If I pull buttons from the Forms toolbar onto a sheet they are visible. If I try to find Objects using F5 when not in design mode Excel reports no objects on the sheet. So, Super Users, can you help? UPDATE: Thanks for your replies, but much like the person in the ozgrid link, the problem has gone away. Not sure why it went, but I can confirm that the user rebooted again and also started up other Excel files that didn't contain controls in the interim. Perhaps that fixed it, or maybe it'll be back again. I'll keep udating with progress, and close if the problem doesn't reoccur for the next few days. Thanks again.

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  • MemoryStream and BitmapSource

    - by Vinjamuri
    I have a MemoryStream of 10K which was created from a bitmap of 2MB and compressed using JPEG. Since MemoryStream can’t directly be placed in System.Windows.Controls.Image for the GUI, I am using the following intermediate code to convert this back to BitmapImage and eventually System.Windows.Controls.Image. System.Windows.Controls.Image image = new System.Windows.Controls.Image(); BitmapImage imageSource = new BitmapImage(); s.SlideInformation.Thumbnail.Seek(0, SeekOrigin.Begin); imageSource.BeginInit(); imageSource.CacheOption = BitmapCacheOption.OnDemand; imageSource.CreateOptions = BitmapCreateOptions.DelayCreation; imageSource.StreamSource = s.SlideInformation.Thumbnail; imageSource.EndInit(); imageSource.Freeze(); image.Source = imageSource; ret = image.Source; My question is, when I store this in BitmapImage, the memory allocation is taking around 2MB. Is this expected? Is there any way to reduce the memory? I have around 300 thumbnails and this converstion takes around 600MB, which is very high. Appreciate your help!

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  • Bring Winforms control to front

    - by Nathan
    Are there any other methods of bringing a control to the front other than control.BringToFront()? I have series of labels on a user control and when I try to bring one of them to front it is not working. I have even looped through all the controls and sent them all the back except for the one I am interested in and it doesn't change a thing. Here is the method where a label is added to the user control private void AddUserLabel() { UserLabel field = new UserLabel(); ++fieldNumber; field.Name = "field" + fieldNumber.ToString(); field.Top = field.FieldTop + fieldNumber; field.Left = field.FieldLeft + fieldNumber; field.Height = field.FieldHeight; field.Width = field.FieldWidth; field.RotationAngle = field.FieldRotation; field.Barcode = field.BarCoded; field.HumanReadable = field.HumanReadable; field.Text = field.FieldText; field.ForeColor = Color.Black; field.MouseDown += new MouseEventHandler(label_MouseDown); field.MouseUp += new MouseEventHandler(label_MouseUp); field.MouseMove += new MouseEventHandler(label_MouseMove); userContainer.Controls.Add(field); SendLabelsToBack(); //Send All labels to back userContainer.Controls[field.FieldName].BringToFront(); } Here is the method that sends all of them to the back. private void SendLabelsToBack() { foreach (UserLabel lbl in userContainer.Controls) { lbl.SendToBack(); } }

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  • validation control unable to find its control to validate

    - by nat
    i have a repeater that is bound to a number of custom dataitems/types on the itemdatabound event for the repeater the code calls a renderedit function that depending on the custom datatype will render a custom control. it will also (if validation flag is set) render a validation control for the appropriate rendered edit control the edit control overrides the CreateChildControls() method for the custom control adding a number of literalControls thus protected override void CreateChildControls() { //other bits removed - but it is this 'hidden' control i am trying to validate this.Controls.Add(new LiteralControl(string.Format( "<input type=\"text\" name=\"{0}\" id=\"{0}\" value=\"{1}\" style=\"display:none;\" \">" , this.UniqueID , this.MediaId.ToString()) )); //some other bits removed } the validation control is rendered like this: where the passed in editcontrol is the control instance of which the above createchildcontrols is a method of.. public override Control RenderValidationControl(Control editControl) { Control ctrl = new PlaceHolder(); RequiredFieldValidator req = new RequiredFieldValidator(); req.ID = editControl.ClientID + "_validator"; req.ControlToValidate = editControl.UniqueID; req.Display = ValidatorDisplay.Dynamic; req.InitialValue = "0"; req.ErrorMessage = this.Caption + " cannot be blank"; ctrl.Controls.Add(req); return ctrl; } the problem is, altho the validation controls .ControlToValidate property is set to the uniqueid of the editcontrol. when i hit the page i get the following error: Unable to find control id 'FieldRepeater$ctl01$ctl00' referenced by the 'ControlToValidate' property of 'FieldRepeater_ctl01_ctl00_validator'. i have tried changing the literal in the createchildcontrols to a new TextBox(), and then set the id etc then, but i get a similar problem. can anyone enlighten me? is this because of the order the controls are rendered in? ie the validation control is written before the editcontrol? or... anyhow any help much appreciated thanks nat

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  • SQL Server 2008 - Login failed. The login is from an untrusted domain and cannot be used with Window

    - by Tom
    I've just installed SQL Server 2008 Developer edition and I'm trying to connect using SQLCMD.exe, but I get the following error: H:\>sqlcmd.exe -S ".\SQL2008" Msg 18452, Level 14, State 1, Server DEVBOX\SQL2008, Line 1 Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. Has anyone seen this before? Any idea what it means??

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  • problem in login in yahoo massanger

    - by khoyendra
    package session; import java.io.FileWriter; import java.text.DateFormat; import java.text.SimpleDateFormat; import javax.swing.JOptionPane; import org.openymsg.network.FireEvent; import org.openymsg.network.Session; import org.openymsg.network.SessionState; import org.openymsg.network.event.SessionListener; public class BotGUI extends javax.swing.JFrame implements SessionListener{ /** Creates new form BotGUI */ FileWriter fw; DateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss"); public BotGUI() { initComponents(); } @SuppressWarnings("unchecked") // <editor-fold defaultstate="collapsed" desc="Generated Code"> private void initComponents() { jPanel1 = new javax.swing.JPanel(); jPanel2 = new javax.swing.JPanel(); jPanel3 = new javax.swing.JPanel(); jLabel1 = new javax.swing.JLabel(); jPanel4 = new javax.swing.JPanel(); jLabel2 = new javax.swing.JLabel(); jLabel3 = new javax.swing.JLabel(); uNameTextField = new javax.swing.JTextField(); uPassPasswordField = new javax.swing.JPasswordField(); jButton1 = new javax.swing.JButton(); jMenuBar1 = new javax.swing.JMenuBar(); jMenu1 = new javax.swing.JMenu(); jMenuItem1 = new javax.swing.JMenuItem(); jMenuItem2 = new javax.swing.JMenuItem(); jMenuItem3 = new javax.swing.JMenuItem(); jMenu2 = new javax.swing.JMenu(); setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE); jPanel2.setLayout(new org.netbeans.lib.awtextra.AbsoluteLayout()); jPanel3.setBackground(new java.awt.Color(51, 51, 51)); jLabel1.setBackground(new java.awt.Color(0, 0, 255)); jLabel1.setFont(new java.awt.Font("Tahoma", 1, 12)); jLabel1.setForeground(new java.awt.Color(255, 255, 255)); jLabel1.setText("Yahoo Login Panel"); javax.swing.GroupLayout jPanel3Layout = new javax.swing.GroupLayout(jPanel3); jPanel3.setLayout(jPanel3Layout); jPanel3Layout.setHorizontalGroup( jPanel3Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(jPanel3Layout.createSequentialGroup() .addGap(38, 38, 38) .addComponent(jLabel1, javax.swing.GroupLayout.PREFERRED_SIZE, 140, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(532, Short.MAX_VALUE)) ); jPanel3Layout.setVerticalGroup( jPanel3Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jLabel1, javax.swing.GroupLayout.Alignment.TRAILING, javax.swing.GroupLayout.DEFAULT_SIZE, 30, Short.MAX_VALUE) ); jPanel2.add(jPanel3, new org.netbeans.lib.awtextra.AbsoluteConstraints(0, 0, 710, 30)); jPanel4.setLayout(new org.netbeans.lib.awtextra.AbsoluteLayout()); jLabel2.setText("Username"); jPanel4.add(jLabel2, new org.netbeans.lib.awtextra.AbsoluteConstraints(30, 20, 60, 20)); jLabel3.setText("Password"); jPanel4.add(jLabel3, new org.netbeans.lib.awtextra.AbsoluteConstraints(270, 20, 60, 20)); jPanel4.add(uNameTextField, new org.netbeans.lib.awtextra.AbsoluteConstraints(100, 20, 140, 20)); jPanel4.add(uPassPasswordField, new org.netbeans.lib.awtextra.AbsoluteConstraints(330, 20, 140, -1)); jButton1.setFont(new java.awt.Font("Tahoma", 1, 14)); // NOI18N jButton1.setText("Login"); jButton1.addActionListener(new java.awt.event.ActionListener() { public void actionPerformed(java.awt.event.ActionEvent evt) { jButton1ActionPerformed(evt); } }); jPanel4.add(jButton1, new org.netbeans.lib.awtextra.AbsoluteConstraints(490, 15, 90, -1)); jPanel2.add(jPanel4, new org.netbeans.lib.awtextra.AbsoluteConstraints(0, 30, 710, 60)); javax.swing.GroupLayout jPanel1Layout = new javax.swing.GroupLayout(jPanel1); jPanel1.setLayout(jPanel1Layout); jPanel1Layout.setHorizontalGroup( jPanel1Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jPanel2, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, Short.MAX_VALUE) ); jPanel1Layout.setVerticalGroup( jPanel1Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(jPanel1Layout.createSequentialGroup() .addComponent(jPanel2, javax.swing.GroupLayout.PREFERRED_SIZE, 135, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(293, Short.MAX_VALUE)) ); jMenu1.setText("Option"); jMenuItem1.setText("Logout"); jMenu1.add(jMenuItem1); jMenuItem2.setText("Load CSV"); jMenu1.add(jMenuItem2); jMenuItem3.setText("Exit"); jMenu1.add(jMenuItem3); jMenuBar1.add(jMenu1); jMenu2.setText("Help"); jMenuBar1.add(jMenu2); setJMenuBar(jMenuBar1); javax.swing.GroupLayout layout = new javax.swing.GroupLayout(getContentPane()); getContentPane().setLayout(layout); layout.setHorizontalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jPanel1, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, Short.MAX_VALUE) ); layout.setVerticalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jPanel1, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, Short.MAX_VALUE) ); pack(); }// </editor-fold> public void handleConnectionClosed() { connectionClosed = true; loggedIn = false; } private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { if(!uNameTextField.getText().equals("") && !uPassPasswordField.getText().equals("")){ Yahoo_login(uNameTextField.getText(),uPassPasswordField.getText()); }else{ JOptionPane.showMessageDialog(null, "Plese Enter User Id and Password"); } } Session yahooMessengerSession; MySessionListener mySessionListener; boolean loggedIn = false; boolean connectionClosed = false; public void Yahoo_login(String uName, String pass) { connectionClosed = false; if (loggedIn == false) { yahooMessengerSession = new Session(); mySessionListener = new MySessionListener(this); yahooMessengerSession.addSessionListener(mySessionListener); try { if ((uName.equals("")) || (pass.equals(""))) { System.out.println("User name/password is blank"); } else{ //initialized a file writer for log file System.out.println("Login start........"); yahooMessengerSession.login(uName, pass, true); //checks whether user was succesful in login in if (yahooMessengerSession!=null && yahooMessengerSession.getSessionStatus()== SessionState.LOGGED_ON) { //this loop is reached when the user has been successfully logined System.out.println("Login Success"); fw.write("User (" + uName + ") logged in at : " + dateFormat.format("09.05.10") + " \n"); fw.close(); } else { yahooMessengerSession.reset(); } } } catch(Exception e){ } } } public static void main(String args[]) { java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new BotGUI().setVisible(true); } }); } // Variables declaration - do not modify private javax.swing.JButton jButton1; private javax.swing.JLabel jLabel1; private javax.swing.JLabel jLabel2; private javax.swing.JLabel jLabel3; private javax.swing.JMenu jMenu1; private javax.swing.JMenu jMenu2; private javax.swing.JMenuBar jMenuBar1; private javax.swing.JMenuItem jMenuItem1; private javax.swing.JMenuItem jMenuItem2; private javax.swing.JMenuItem jMenuItem3; private javax.swing.JPanel jPanel1; private javax.swing.JPanel jPanel2; private javax.swing.JPanel jPanel3; private javax.swing.JPanel jPanel4; private javax.swing.JTextField uNameTextField; private javax.swing.JPasswordField uPassPasswordField; // End of variables declaration public void dispatch(FireEvent fe) { throw new UnsupportedOperationException("Not supported yet."); } } i have to find the error SEVERE: error during the dispatch of event: FireEvent [org.openymsg.network.event.SessionListEvent to:null from:null message:null timestamp:0 status:0 list type:Friends size:2 LIST] java.lang.UnsupportedOperationException: Not supported yet. at yahoomessangerbot.MySessionListener.dispatch(MySessionListener.java:131) at org.openymsg.network.EventDispatcher.runEventNOW(EventDispatcher.java:133) at org.openymsg.network.EventDispatcher.run(EventDispatcher.java:114)

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