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• Magic behind R.java file

  - by LambergaR

  Hi! Recently I have been having quite some problems with R.java file. Now I have decided to do a backup and delete the file to see what happens. Nothing happened, so I created an empty R.java file and hopped for the best. Now Eclipse seems to figure out that the file was tempered with and even issues a warning: R.java was modified manually! Reverting to generated version! And that's all there is. I tried building it manually but got no results. So, I have two questions: 1. what should I do to force Eclipse to generate the file 2. what is happening here? How is the file created, where is the code that is generating the file? I would appreciate any help. As usual the problem occurred just a few days before the deadline :)

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• Django file uploads - Just can't work it out

  - by phoebebright

  OK I give up - after 5 solid hours trying to get a django form to upload a file, I've checked out all the links in stackoverflow and googled and googled. Why is it so hard, I just want it to work like the admin file upload? So I get that I need code like: if submitForm.is_valid(): handle_uploaded_file(request.FILES['attachment']) obj = submitForm.save() and I can see my file in request.FILES['attachment'] (yes I have enctype set) but what am I supposed to do in handle_uploaded_file? The examples all have a fixed file name but obviously I want to upload the file to the directory I defined in the model, but I can't see where I can find that. def handle_uploaded_file(f): destination = open('fyi.xml', 'wb+') for chunk in f.chunks(): destination.write(chunk) destination.close() Bet I'm going to feel really stupid when someone points out the obvious!

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• Reading an XML File with .NET

  - by Daywalker21

  I am new to xml and unable to find a way to get content in between tags. My XML file is <?xml version="1.0" encoding="utf-8"?> <block1> <file name="c:\w0.xml"> <word>Text</word> <number>67</number> </file> <file name="c:\w1.xml"> <word>Text</word> <number>67</number> </file> <file name="c:\w2.xml"> <word>Text</word> <number>67</number> </file> </block1>

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• Detecting a image 404 in javascript.

  - by xal

  After a user uploads a file we have to do some additional processing with the images such as resizing and upload to S3. This can take up to 10 extra seconds. Obviously we do this in a background. However, we want to show the user the result page immediately and simply show spinners in place until the images arrive in their permanent home on s3. I'm looking for a way to detect that a certain image failed to load correctly (404) in a cross browser way. If that happens, we want to use JS to show a spinner in it's place and reload the image every few seconds until it can be successfully loaded from s3.

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• MySQL INTO OUTFILE overide existing file?

  - by Derek Organ

  I've written a big sql script that creates a CSV file. I want to call a cronjob every night to create a fresh CSV file and have it available on the website. Say for example I'm store my file in '/home/sites/example.com/www/files/backup.csv' and my SQL is SELECT * INTO OUTFILE '/home/sites/example.com/www/files/backup.csv' FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY '\n' FROM ( .... MySQL gives me an error when the file already exists File '/home/sites/example.com/www/files/backup.csv' already exists Is there a way to make MySQL overwrite the file? I could have PHP detect if the file exists and delete it before creating it again but it would be more succinct if I can do it directly in MySQL.

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• decompress .gz file in batch

  - by kapildalwani

  I have 100 of .gz files which I need to de-compress. I have couple of questions a) I am using the code given at http://www.roseindia.net/java/beginners/JavaUncompress.shtml to decompress the .gz file. Its working fine. Quest:- is there a way to get the file name of the zipped file. I know that Zip class of Java gives of enumeration of entery file to work upon. This can give me the filename, size etc stored in .zip file. But, do we have the same for .gz files or does the file name is same as filename.gz with .gz removed. b) is there another elegant way to decompress .gz file by calling the utility function in the java code. Like calling 7-zip application from your java class. Then, I don't have to worry about input/output stream. Thanks in advance. Kapil

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• Store html form on client or server while building?

  - by Brett

  Hi, I have a fairly complex html form enhanced via jquery. It has multiple tabs, within each one things like a html form builder, uploads, descriptions. There is lots of data, and as the user flicks around the various tabs I'm thinking of posting the data to the server. For example, the form builder, has about 10 properties for each field, as the user flicks between the various fields, an ajax request saves the current values, then loads a new set from the new field clicked on. When the user hits save, the idea is then on the server all these bits and pieces come together and become the live version (i may store them as a temp version while the user is working away). So I guess my question is, for complex forms where the same fields are re-used within the one form, does anyone attempt to save all this data locally and upload it in one hit or do most of you do little ajax post's and compile it all when the final save button is hit? b

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• getting the path of a file from its grandparent folder

  - by Saswat

  i have a php file which has the followng path Shubhmangalam/admin/welcome_image_edition/delete_image.php and an image file with the follwing path Shubhmangalam/welcome_images/image_1.jpg i want to delete the image_1.jpg file which i know can be done by using unlink() method.. but the prob is that the parent folder of the .php file and .jpg file is different, and so is their level of file-system...and i cant find the proper way to get the path to delete the image_1.jpg file. now the code on the delete_image.php is accordingly <?php $image=$_REQUEST['image']; if(unlink("./../welcome_images/".$image)) echo "Successfully Deleted"; else echo "Wrong"; ?> now the above is server-scripting code, i want to delete the image by getting appropriate path.. i dnt want the actual path, but the path from the project folder that is Shubhmangalam thanks in advance

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• Maven2: Best practise for Enterprise Project (EAR file)

  - by Maik

  Hello everyone, I am just switching from Ant to Maven and am trying to figure out the best practice to set up a EAR file based Enterprise project? Lets say I want to create a pretty standard project with a jar file for the EJBs, a WAR file for the Web tier and the encapsulating EAR file, with the corresponding deployment descriptors. How would I go about it? Create the project with archetypeArtifactId=maven-archetype-webapp liek a war file and extend from there? What is the best project structure (and POM file example) for this? Where do you stick the ear file related deployment descriptors, etc? Thanks for any help.

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• Creating an SQL Compact file: Template or script?

  - by David Veeneman

  I am writing an application that writes to SQL Compact files that have a specific schema, and I am now implementing the New File use case. The simplest approach seems to be to use a Template pattern: first, create a template file that lives in the application directory. Then, when the user selects New File, the template is copied to the name and destination specified by the user in a New File dialog. The alternative is a scripted approach: Use the same New File dialog, but dispense with the template file. Instead, create an empty SQL Compact file using the name/destination specified by the user, and then execute a T-SQL script on it from managed code. At this point, I am leaning toward the Template approach, because it is simpler. Is there any reason I should not use that approach? Thanks for your help.

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• trying to find if a file exists in a given path

  - by Yeshwanth Venkatesh

  I am fairly new to java and I am trying to find if the file specified in the LINUX path exists. private void validateFilePath(String filePath) { File dir = new File(filePath); if(dir.exists()){ System.out.println("File exists in the path " + dir); setTARGET_IMG_DIR("filePath"); return; }else{ System.out.println("File does not exists in the path: " + dir); return; } } The dir.exists works fine if I give a absolute path from my root like this /Users/yv/Documents/Eclipse-workspace/InputParser/bin/test.txt but if I give a relative path like test.txt or /InputParser/bin/test.txt it says files does not exists. I am planing on creating a jar of this projects and hence this should work with both relative path(files in the same directory) and absolute path from the root. How can I handle this ? Is it possible to search for the absolute path of that file from the root and append it to the file name ?

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• Android file-creation fails.

  - by Alxandr

  I use the following code to create a folder "mymir" and a file ".nomedia" (in the mymir-folder) on the sdcard of an android unit. However, somehow it fails with the exception that the folder the ".nomedia"-file is to be placed in dosn't exist. Here's the code: private String EnsureRootDir() throws IOException { File sdcard = Environment.getExternalStorageDirectory(); File mymirFolder = new File(sdcard.getAbsolutePath() + "/mymir/"); if(!mymirFolder.exists()) { File noMedia = new File(mymirFolder.getAbsolutePath() + "/.nomedia"); noMedia.mkdirs(); noMedia.createNewFile(); } return mymirFolder.getAbsolutePath(); }

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• django handling file uploads - target different than media folder

  - by Tom Tom

  Hi, I want to enable the user to upload media which will not be saved in the media folder. When I use the following line of code data will be uploaded to media/upload/logo . logo_img = models.FileField(upload_to='upload/logo', blank=True) I'm wondering how I can change this behaviour. I would try to write a custom FileField and a view that serves the data based on the database entries. I do not want to place the data the user uploads to the media folder, since it is no public data. Is this approach correct? Are there solutions out there which do exactly what I want and I would reinvent the wheel with implementing this by myself? Would appreciate any help!

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• asp.net C# uploading big file and processing it

  - by JewelThief

  I want to be able to upload file from my .aspx page to my web server so that it can be preocessed into a different format. e.g. user will upload a doc and in few seconds it would see a pdf version of the doc on the web page. I have web service available which can convert doc to pdf. now 1- how do i automate upload + conversion process. 2- how do i handle big files here. 3- how not to make user wait for all this thing to happen.

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• Use a grepped file as an included source in bash

  - by Andrew

  I'm on a shared webhost where I don't have permission to edit the global bash configuration file at /ect/bashrc. Unfortunately there is one line in the global file, mesg y, which puts the terminal in tty mode and makes scp and similar commands unavailable. My local ~./bashrc includes the global file as a source, like so: # Source global definitions if [ -f /etc/bashrc ]; then . /etc/bashrc fi My current workaround uses grep to output the global file, sans offending line, into a local file and use that as a source. # Source global definitions if [ -f /etc/bashrc ]; then grep -v mesg /etc/bashrc > ~/.bash_global . ~/.bash_global fi Is there a way to do include a grepped file like this without the intermediate step of creating an actual file? Something like this? . grep -v mesg /etc/bashrc > ~/.bash_global

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• using Applescript to retrieve movie file duration via Finder properties

  - by Matt

  When using Get Info on movie files in the Finder, I've noticed that many movie files have an accessible "Duration" property under the More Info tab. Is there an easy way to access this data using Applescript? I've tried lines like "set theTime to (duration of aFile)", but it doesn't seem to be as simple as that. Ideally I'd like to access the movie duration via the Finder properties without having to actually open the file in QuickTime. Is this possible? Edit: I seem to have figured this out... you need to use the "System Events" application, specifically the Movie File Suite of commands (and, importantly, you need to set the movie variable as a string, rather than an alias): set theMovie to (choose file with prompt "Select a movie file:") as string tell application "System Events" set theName to name of movie file theMovie set theDuration to (duration of contents of movie file theMovie) / (time scale of contents of movie file theMovie) end tell

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• Node.js Creating and Deleting a File Recursively

  - by Matt

  I thought it would be a cool experiment to have a for loop and create a file hello.txt and then delete it with unlink. I figured that if fs.unlink is the delete file procedure in Node, then fs.link must be the create file. However, my code will only delete, and it will not create, not even once. Even if I separate the fs.link code into a separate file, it still will not create my file hello.txt. Below is my code: var fs = require('fs'), for(var i=1;i<=10;i++){ fs.unlink('./hello.txt', function (err) { if (err){ throw err; } else { console.log('successfully deleted file'); } fs.link('./hello.txt', function (err) { if (err){ throw err; } else { console.log('successfully created file'); } }); }); } http://nodejs.org/api/fs.html#fs_fs_link_srcpath_dstpath_callback Thank you!

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• sorting content of a text file in python

  - by rabidmachine9

  I have this small script that sorts the content of a text file # The built-in function `open` opens a file and returns a file object. # Read mode opens a file for reading only. try: f = open("tracks.txt", "r") try: # Read the entire contents of a file at once. # string = f.read() # OR read one line at a time. #line = f.readline() # OR read all the lines into a list. lines = f.readlines() lines.sort() f = open('tracks.txt', 'w') f.writelines(lines) # Write a sequence of strings to a file finally: f.close() except IOError: pass the only problem is that the text is displayed at the bottom of the text file everytime it's sortened... I assume it also sorts the blank lines...anybody knows why? thanks in advance

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• FileInputStream for a generic file System

  - by Akhil

  I have a file that contains java serialized objects like "Vector". I have stored this file over Hadoop Distributed File System(HDFS). Now I intend to read this file (using method readObject) in one of the map task. I suppose FileInputStream in = new FileInputStream("hdfs/path/to/file"); wont' work as the file is stored over HDFS. So I thought of using org.apache.hadoop.fs.FileSystem class. But Unfortunately it does not have any method that returns FileInputStream. All it has is a method that returns FSDataInputStream but I want a inputstream that can read serialized java objects like vector from a file rather than just primitive data types that FSDataInputStream would do. Please help!

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• overwrite a file which is already used by another process

  - by Ahmy

  I have a web site and i am showing videos to visitors, at the admin side i am filling the form of video and upload video file and sometimes i need to change(update) the video so i update the video by uploading another one, when i create the video in the first time i concatenate a datetime variable with the video name to avoid repeatition(file already exist) and when updatting the video the problem appears.... as if i upload the new video with the previous name so it will replace the previous one and in this case if the video is used by another process it will fail and the second option(which i am already using) is to upload a new video and concatenating new datetime variable with video title, so the previous and the new video will exist in the same directory and in this case i will lose too much space in my server directory as i have unused videos which takes space which in future will cause problem to me in the disk space so how can i solve this problem ? Hope that my question is clear....thanks in advance for any try

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• Reading a file used by another process

  - by Tophe

  I know this has been up for discussion but I can't find an answer to my specific problem. I am monitoring a text file that is being written to by a server program. Every time the file is changed the content will be outputted to a window in my program. The problem is of course, that I can't use the Streamreader on the file as it is being "used by another process". Also setting up a Filestream with ReadWrite won't do any good since I cannot control the process that is using the file. However... You CAN open the file in notepad, so somehow it must be possible to access it even though the server is using it. Is there a good way around this? Should I monitor the file, make a temp copy of it when it changes, read the temp copy and the delete the temp copy. I need to get hold of the text in the file whenever the server changes it.

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• How to Load external Div that has a dynamic content using ajax and jsp/servlets ?

  - by A.S al-shammari

  I need to use ajax feature to load external div element ( external jsp file) into the current page. That JSP page contains a dynamic content - e.g. content that is based on values received from the current session. I solved this problem , but I'm in doubt because I think that my solution is bad , or maybe there is better solution since I'm not expert. I have three files: Javascript function that is triggered when a element is clicked, it requests html data from a servlet: $("#inboxtable tbody tr").click(function(){ var trID = $(this).attr('id'); $.post("event?view=read",{id:trID}, function(data){ $("#eventContent").html(data); // load external file },"html"); // type }); The servlet "event" loads the data and generates HTML content using include method : String id = request.getParameter("id"); if (id != null) { v.add("Test"); v.add(id); session.setAttribute("readMessageVector", v); request.getRequestDispatcher("readMessage.jsp").include(request, response); } The readMessage jsp file looks like this: <p> Text: ${readMessageVector[0]} </p> <p> ID: ${readMessageVector[1]} </p> My questions Is this solution good enough to solve this problem - loading external jsp that has dynamic content ? Is there better solution ?

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• Please help clean this loop

  - by Alex Angelini

  I do not code much in Javascript, but I have the following snippet which IMHO looks horrendous and I have to do this nested iteration quite often in my code. Does anyone have a prettier/easier to read solution? function addBrowse(data) { var list = $('<ul></ul>') for(i = 0; i < data.list.length; i++) { var file = list.append('<li class="toLeft">' + data.list[i].name + '</li>') for(j = 0; j < data.list[i].children.length; j++) { var db = file.append('<li>' + data.list[i].children[j].name + '</li>') for(k = 0; k < data.list[i].children[j].children.length; k++) db.append('<li class="toRight">' + data.list[i].children[j].children[k].name + '</li>') } } $('#browse').append(list).show()} Here is a sample data element {"file":"","db":"","tbl":"","page":"browse","list":[ { "name":"/home/alex/GoSource/test1.txt", "children":[ { "name":"go", "children":[ { "name":"validation1", "children":[ ] } ] } ] }, { "name":"/home/alex/GoSource/test2.txt", "children":[ { "name":"go", "children":[ { "name":"validation2", "children":[ ] } ] } ] }, { "name":"/home/alex/GoSource/test3.txt", "children":[ { "name":"go", "children":[ { "name":"validation3", "children":[ ] } ] } ] }]} Thanks a lot

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• Using delayed_job to process file uploads across multiple servers

  - by Steve Klabnik

  Does anyone have any good resources on how to do this? Basically, I'm working on a project (in Rails) where people can upload files. They might be big. I'd like to process them using delayed_job before sending them to S3. I'd also like to do this processing on a separate job queue server, rather than on the webserver itself. I'd rather not have to upload the files to the webserver, then transfer them to the job queue server, and then upload them to S3 if I don't have to. Thanks.

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• Insert A Line At The Beginning Of A File

  - by thebourneid

  I'm trying to insert/add a line 'COMMENT DUMMY' at the beginnig of a file as a first row if /PATTERN/ not found. I know how to do this with OPEN CLOSE function. Probably after reading the file it should look something like this: open F, ">", $fn or die "could not open file: $!"; ; print F "COMMENT DUMMY\n", @array; close F; But I have a need to implement this with the use of the Tie::File function and don't know how. use strict; use warnings; use Tie::File; my $fn = 'test.txt'; tie my @lines, 'Tie::File', $fn or die "could not tie file: $!"; untie @lines;

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