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• Data Warehouse ETL slow - change primary key in dimension?

  - by Jubbles

  I have a working MySQL data warehouse that is organized as a star schema and I am using Talend Open Studio for Data Integration 5.1 to create the ETL process. I would like this process to run once per day. I have estimated that one of the dimension tables (dimUser) will have approximately 2 million records and 23 columns. I created a small test ETL process in Talend that worked, but given the amount of data that may need to be updated daily, the current performance will not cut it. It takes the ETL process four minutes to UPDATE or INSERT 100 records to dimUser. If I assumed a linear relationship between the count of records and the amount of time to UPDATE or INSERT, then there is no way the ETL can finish in 3-4 hours (my hope), let alone one day. Since I'm unfamiliar with Java, I wrote the ETL as a Python script and ran into the same problem. Although, I did discover that if I did only INSERT, the process went much faster. I am pretty sure that the bottleneck is caused by the UPDATE statements. The primary key in dimUser is an auto-increment integer. My friend suggested that I scrap this primary key and replace it with a multi-field primary key (in my case, 2-3 fields). Before I rip the test data out of my warehouse and change the schema, can anyone provide suggestions or guidelines related to the design of the data warehouse the ETL process how realistic it is to have an ETL process INSERT or UPDATE a few million records each day will my friend's suggestion significantly help If you need any further information, just let me know and I'll post it. UPDATE - additional information: mysql> describe dimUser; Field Type Null Key Default Extra user_key int(10) unsigned NO PRI NULL auto_increment id_A int(10) unsigned NO NULL id_B int(10) unsigned NO NULL field_4 tinyint(4) unsigned NO 0 field_5 varchar(50) YES NULL city varchar(50) YES NULL state varchar(2) YES NULL country varchar(50) YES NULL zip_code varchar(10) NO 99999 field_10 tinyint(1) NO 0 field_11 tinyint(1) NO 0 field_12 tinyint(1) NO 0 field_13 tinyint(1) NO 1 field_14 tinyint(1) NO 0 field_15 tinyint(1) NO 0 field_16 tinyint(1) NO 0 field_17 tinyint(1) NO 1 field_18 tinyint(1) NO 0 field_19 tinyint(1) NO 0 field_20 tinyint(1) NO 0 create_date datetime NO 2012-01-01 00:00:00 last_update datetime NO 2012-01-01 00:00:00 run_id int(10) unsigned NO 999 I used a surrogate key because I had read that it was good practice. Since, from a business perspective, I want to keep aware of potential fraudulent activity (say for 200 days a user is associated with state X and then the next day they are associated with state Y - they could have moved or their account could have been compromised), so that is why geographic data is kept. The field id_B may have a few distinct values of id_A associated with it, but I am interested in knowing distinct (id_A, id_B) tuples. In the context of this information, my friend suggested that something like (id_A, id_B, zip_code) be the primary key. For the large majority of daily ETL processes (80%), I only expect the following fields to be updated for existing records: field_10 - field_14, last_update, and run_id (this field is a foreign key to my etlLog table and is used for ETL auditing purposes).

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• devise register confirmation

  - by mattherick

  hello! i have a user and an admin role in my project. i created my authentification with devise, really nice and goot tool for handling the authentification. in my admin role i don´t have any confirmation or something like that. it is really simple and doesn´t make problems. but in my user model i have following things: model: devise :database_authenticatable, :confirmable, :recoverable, :rememberable, :trackable, :validatable, :timeoutable, :registerable # Setup accessible (or protected) attributes for your model attr_accessible :email, :username, :prename, :surname, :phone, :street, :number, :location, :password, :password_confirmation and few validations, but they aren´t relevant this time. my migration looks like following one: class DeviseCreateUsers < ActiveRecord::Migration def self.up create_table(:users) do |t| t.database_authenticatable :null = false t.confirmable t.recoverable t.rememberable t.trackable t.timeoutable t.validateable t.string :username t.string :prename t.string :surname t.string :phone t.string :street t.integer :number t.string :location t.timestamps end add_index :users, :email, :unique => true add_index :users, :confirmation_token, :unique => true add_index :users, :reset_password_token, :unique => true add_index :users, :username, :unique => true add_index :users, :prename, :unique => false add_index :users, :surname, :unique => false add_index :users, :phone, :unique => false add_index :users, :street, :unique => false add_index :users, :number, :unique => false add_index :users, :location, :unique => false end def self.down drop_table :users end end into my route.rb I added following statements: map.devise_for :admins map.devise_for :users, :path_names = { :sign_up = "register", :sign_in = "login" } map.root :controller = "main" and now my problem.. if I register a new user, I fill in all my data in the register form and submit it. After that I get redirected to the controller main with the flash-notice "You have signed up successfully." And I am logged in. But I don´t want to be logged in, because I don´t have confirmed my new user account yet. If I open the console I see the last things in the logs and there I see the confirmation-mail and the text and all stuff, but I am already logged in... I can´t explain why, ... does somebody of you have an idea? If I copy out the confirmation-token from the logs and confirm my account, I can log in, but if I don´t confirm, I also can log in..

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• drupal (CMS) or codeigniter (MVC) for creating a new web application?

  - by ajsie

  im going to create a new web application that is very customized. it will contain images, that are fully searchable - in a very, very customized way. when you click on the pictures you can add comments and so on. it requires users to be registered, but the registration/login process will be highly customized too. at the moment im using CodeIgniter for this. But i've read a lot of posts about CMS like Drupal and it sounds like i could let it handle basic stuff, maybe design and other front end work. i have no experience with CMS, in fact, i just started to use a MVC framework like CI and was impressed of how much easier it gets to start developing. so i wonder, if i'm going to create this kind of application, could i use drupal and then add the usual stuff, as i was going to do with CodeIgniter, like controllers, views, models, config files, my own libraries and so on? how does it work on a system like Drupal. how do you code PHP with it as with any MVC framework. it sounds like it has a lot of modules, i just wonder, if i can use it as a MVC framework but have the benefit of having all these basic stuff and design ready to use? cause then it sounds like the best "library" to provide for a web application from scratch. or is it difficult to create a customized app with it? i guess it has modules like images and users, but then how could i customize these so that every image has tags on it and country information, or have every user subscribing to changes to an image, that email will be sent to users and so on? cause i guess its easy to install a module. the question is, how do i customize it. maybe i don't need all that table columns. maybe i want to add/remove business logic. what are the pros and cons with using Drupal for this? is it even the right way to go? can you make a Stackoverflow with Drupal? Facebook? Twitter? Youtube? assuming that you know php of course. share your thoughts cause im totally new on creating a web application! thanks

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• Solving a cyclical dependency in Ninject (Compact Framework)

  - by Alex

  I'm trying to use Ninject for dependency injection in my MVP application. However, I have a problem because I have two types that depend on each other, thus creating a cyclic dependency. At first, I understand that it was a problem, because I had both types require each other in their constructors. Therefore, I moved one of the dependencies to a property injection instead, but I'm still getting the error message. What am I doing wrong? This is the presenter: public class LoginPresenter : Presenter<ILoginView>, ILoginPresenter { public LoginPresenter( ILoginView view ) : base( view ) { } } and this is the view: public partial class LoginForm : Form, ILoginView { [Inject] public ILoginPresenter Presenter { private get; set; } public LoginForm() { InitializeComponent(); } } And here's the code that causes the exception: static class Program { /// <summary> /// The main entry point for the application. /// </summary> [MTAThread] static void Main() { // Show the login form Views.LoginForm loginForm = Kernel.Get<Views.Interfaces.ILoginView>() as Views.LoginForm; Application.Run( loginForm ); } } The exception happens on the line with the Kernel.Get<>() call. Here it is: Error activating ILoginPresenter using binding from ILoginPresenter to LoginPresenter A cyclical dependency was detected between the constructors of two services. Activation path: 4) Injection of dependency ILoginPresenter into property Presenter of type LoginForm 3) Injection of dependency ILoginView into parameter view of constructor of type LoginPresenter 2) Injection of dependency ILoginPresenter into property Presenter of type LoginForm 1) Request for ILoginView Suggestions: 1) Ensure that you have not declared a dependency for ILoginPresenter on any implementations of the service. 2) Consider combining the services into a single one to remove the cycle. 3) Use property injection instead of constructor injection, and implement IInitializable if you need initialization logic to be run after property values have been injected. Why doesn't Ninject understand that since one is constructor injection and the other is property injection, this can work just fine? I even read somewhere looking for the solution to this problem that Ninject supposedly gets this right as long as the cyclic dependency isn't both in the constructors. Apparently not, though. Any help resolving this would be much appreciated.

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• using a Singleton to pass credentials in a multi-tenant application a code smell?

  - by Hans Gruber

  Currently working on a multi-tenant application that employs Shared DB/Shared Schema approach. IOW, we enforce tenant data segregation by defining a TenantID column on all tables. By convention, all SQL reads/writes must include a Where TenantID = '?' clause. Not an ideal solution, but hindsight is 20/20. Anyway, since virtually every page/workflow in our app must display tenant specific data, I made the (poor) decision at the project's outset to employ a Singleton to encapsulate the current user credentials (i.e. TenantID and UserID). My thinking at the time was that I didn't want to add a TenantID parameter to each and every method signature in my Data layer. Here's what the basic pseudo-code looks like: public class UserIdentity { public UserIdentity(int tenantID, int userID) { TenantID = tenantID; UserID = userID; } public int TenantID { get; private set; } public int UserID { get; private set; } } public class AuthenticationModule : IHttpModule { public void Init(HttpApplication context) { context.AuthenticateRequest += new EventHandler(context_AuthenticateRequest); } private void context_AuthenticateRequest(object sender, EventArgs e) { var userIdentity = _authenticationService.AuthenticateUser(sender); if (userIdentity == null) { //authentication failed, so redirect to login page, etc } else { //put the userIdentity into the HttpContext object so that //its only valid for the lifetime of a single request HttpContext.Current.Items["UserIdentity"] = userIdentity; } } } public static class CurrentUser { public static UserIdentity Instance { get { return HttpContext.Current.Items["UserIdentity"]; } } } public class WidgetRepository: IWidgetRepository{ public IEnumerable<Widget> ListWidgets(){ var tenantId = CurrentUser.Instance.TenantID; //call sproc with tenantId parameter } } As you can see, there are several code smells here. This is a singleton, so it's already not unit test friendly. On top of that you have a very tight-coupling between CurrentUser and the HttpContext object. By extension, this also means that I have a reference to System.Web in my Data layer (shudder). I want to pay down some technical debt this sprint by getting rid of this singleton for the reasons mentioned above. I have a few thoughts on what an better implementation might be, but if anyone has any guidance or lessons learned they could share, I would be much obliged.

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• Foreign key not stored in child entity (one-to-many)

  - by Kamil Los

  Hi, I'm quite new to hibernate and have stumbled on this problem, which I can't find solution for. When persisting parent object (with one-to-many relationship with child), the foreign-key to this parent is not stored in child's table. My classes: Parent.java @javax.persistence.Table(name = "PARENT") @Entity public class PARENT { private Integer id; @javax.persistence.Column(name = "ID") @Id @GeneratedValue(strategy=GenerationType.AUTO) public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } private Collection<Child> children; @OneToMany(mappedBy = "parent", fetch = FetchType.EAGER, cascade = {CascadeType.ALL}) @Cascade({org.hibernate.annotations.CascadeType.ALL}) public Collection<Child> getChildren() { return children; } public void setChildren(Collection<Child> children) { this.children = children; } } Child.java @javax.persistence.Table(name = "CHILD") @Entity @IdClass(Child.ChildId.class) public class Child { private String childId1; @Id public String getChildId1() { return childId1; } public void setChildId1(String childId1) { this.childId1 = childId1; } private String childId2; @Id public String getChildId2() { return childId2; } public void setChildId2(String childId2) { this.childId2 = childId2; } private Parent parent; @ManyToOne @javax.persistence.JoinColumn(name = "PARENT_ID", referencedColumnName = "ID") public Parent getParent() { return parent; } public void setParent(Operation parent) { this.parent = parent; } public static class ChildId implements Serializable { private String childId1; @javax.persistence.Column(name = "CHILD_ID1") public String getChildId1() { return childId1; } public void setChildId1(String childId1) { this.childId1 = childId1; } private String childId2; @javax.persistence.Column(name = "CHIILD_ID2") public String getChildId2() { return childId2; } public void setChildId2(String childId2) { this.childId2 = childId2; } public ChildId() { } @Override public boolean equals(Object o) { if (this == o) return true; if (o == null || getClass() != o.getClass()) return false; ChildId that = (ChildId) o; if (childId1 != null ? !childId1.equals(that.childId1) : that.childId1 != null) return false; if (childId2 != null ? !childId2.equals(that.childId2) : that.childId2 != null) return false; return true; } @Override public int hashCode() { int result = childId1 != null ? childId1.hashCode() : 0; result = 31 * result + (childId2 != null ? childId2.hashCode() : 0); return result; } } } Test.java public class Test() { private ParentDao parentDao; public void setParentDao(ParentDao parentDao) { this.parentDao = parentDao; } private ChildDao childDao; public void setChildDao(ChildDao childDao) { this.childDao = parentDao; } test1() { Parent parent = new Parent(); Child child = new Child(); child.setChildId1("a"); child.setChildId2("b"); ArrayList<Child> children = new ArrayList<Child>(); children.add(child); parent.setChildren(children); parent.setValue("value"); parentDao.save(parent); //calls hibernate's currentSession.saveOrUpdate(entity) } test2() { Parent parent = new Parent(); parent.setValue("value"); parentDao.save(parent); //calls hibernate's currentSession.saveOrUpdate(entity) Child child = new Child(); child.setChildId1("a"); child.setChildId2("b"); child.setParent(parent); childDao.save(); //calls hibernate's currentSession.saveOrUpdate(entity) } } When calling test1(), both entities get written to database, but field PARENT_ID in CHILD table stays empty. The only workaround I have so far is test2() - persisting parent first, and then the child. My goal is to persist parent and its children in one call to save() on Parent. Any ideas?

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• Why doesn't JSF 2.0 RI (Mojarra) scan my class' annotations?

  - by DWoldrich

  I have a War and Jar project in my Eclipse-based JSF project. I have decided to use annotations to declare my FacesConverter, (among a myriad other things), rather than declare it using my faces-config.xml. @FacesConverter(value="passwordFieldStringConverter") public class PasswordFieldStringConverter implements Converter { public Object getAsObject(FacesContext arg0, UIComponent arg1, String arg2) throws ConverterException { try { return arg2.getBytes("UTF-16BE"); } catch(UnsupportedEncodingException uee) { Assert.impossibleException(uee); } return(null); } public String getAsString(FacesContext arg0, UIComponent arg1, Object arg2) throws ConverterException { try { return new String((byte[]) arg2, "UTF-16BE"); } catch(UnsupportedEncodingException uee) { Assert.impossibleException(uee); } return(null); } } And then I use passwordFieldStringConverter directly in my .xhtml: <?xml version="1.0" encoding="UTF-8" ?> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:sec="http://www.springframework.org/security/facelets/tags"> <ui:composition> <f:view> <f:loadBundle basename="landingPage.bundle" var="bundle" /> <ui:decorate template="/WEB-INF/jsf_helpers/htmlShell.xhtml"> <ui:param name="PageTitleParam" value="#{bundle.pageTitle}" /> <h:form> <h:dataTable var="rowVar" value="#{userListContainer.users}"> <f:facet name="header"><h:outputText value="Users you are currently managing:" /></f:facet> <h:column> <f:facet name="header"> <h:outputText value="Screen Name" /> </f:facet> <h:outputText value="#{rowVar.screenName}" /> </h:column> <h:column> <f:facet name="header"> <h:outputText value="Password" /> </f:facet> <h:outputText value="#{rowVar.password}"> <f:converter converterId="passwordFieldStringConverter" /> </h:outputText> </h:column> </h:dataTable> </h:form> </ui:decorate> </f:view> </ui:composition> </html> JSF is supposed to scan the jars in my War at deployment-time and detect which classes have annotations on them (and auto-configure the application accordingly). My problem is that JSF is apparently not detecting the classes I have which sport annotations. The War project has all of my .xhtml files as well as the project's faces-config.xml, my Jar project has all of my faces related Java code (action beans, managed beans, custom converters, etc.)

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• Get item from spinner into url

  - by ShadowCrowe

  I searched for an answer but couldn't find it. The problem: Depending on the selected spinner-item the application should show a different image. At this moment I can't get it to work. The Url works like this: "my.site.com/images/" imc_met ".png" were imc_met is the filename. I can't get it to work. Btw the app isn't finished yet package example.myapplication; import java.io.IOException; import java.net.MalformedURLException; import java.net.URI; import java.net.URISyntaxException; import java.net.URL; import java.util.ArrayList; import java.util.List; import android.app.Activity; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.os.Bundle; import android.view.Menu; import android.view.View; import android.view.View.OnClickListener; import android.widget.AdapterView; import android.widget.ArrayAdapter; import android.widget.Button; import android.widget.ImageView; import android.widget.Spinner; public class itemsActivity extends Activity { private Spinner spinner1, spinner2; private Button btnSubmit; private Bitmap image; private ImageView imageView; private String imc_met, imc; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.items); addItemsOnSpinner2(); addListenerOnButton(); addListenerOnSpinnerItemSelection(); } // add items into spinner dynamically public void addItemsOnSpinner2() { spinner2 = (Spinner) findViewById(R.id.spinner2); List<String> list = new ArrayList<String>(); list.add("list 1"); list.add("list 2"); list.add("list 3"); ArrayAdapter<String> dataAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, list); dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); spinner2.setAdapter(dataAdapter); } public void addListenerOnSpinnerItemSelection() { spinner1 = (Spinner) findViewById(R.id.spinner1); spinner1.setOnItemSelectedListener(new CustomOnItemSelectedListener()); } // get the selected dropdown list value public void addListenerOnButton() { spinner1 = (Spinner) findViewById(R.id.spinner1); spinner2 = (Spinner) findViewById(R.id.spinner2); btnSubmit = (Button) findViewById(R.id.btnSubmit); spinner1.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() { @Override public void onItemSelected(AdapterView<?> arg0, View arg1, int arg2, long arg3) { if(spinner1.getSelectedItem()!=null){ imc_met = spinner1.getSelectedItem().toString(); } } @Override public void onNothingSelected(AdapterView<?> arg0) { // TODO Auto-generated method stub } }); imageView = (ImageView)findViewById(R.id.ImageView01); btnSubmit.setOnClickListener(new OnClickListener() { public void onClick(View v) { URL url = null; try { url = new URL("my.site.com"); //here should the right link appear. } catch (MalformedURLException e) { e.printStackTrace(); } try { if (url != null) { image = BitmapFactory.decodeStream(url.openStream()); } } catch (IOException e) { e.printStackTrace(); } imageView.setImageBitmap(image); } }); } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; } }

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• Div Background Image

  - by marskie

  i just wanted to put the 2nd grey image background on the bottom part of my body. Sorry for this kind of newbie question thank a lot for helping newbie like me.. #bgtop { background-image:url(images/bgtop.png); background-repeat: repeat-x; } #bgbottom { background:url(images/bgbottom.png) repeat-x bottom;} body { font: 100% Verdana, Arial, Helvetica, sans-serif; background: #ededed; margin: 0; / padding: 0; text-align: center; color: #000000; } #container { width: 80%; background: #FFFFFF; margin: 0 auto; border: 1px solid #000000; text-align: left; } #header { background: #DDDDDD; padding: 0 10px 0 20px; } #header h1 { margin: 0; padding: 10px 0; } #mainContent { padding: 0 20px; background: #FFFFFF; } #footer { padding: 0 10px; background:#DDDDDD; } #footer p { margin: 0; padding: 10px 0; } HTML <body> <div id="bgtop"> <div id="bgbottom"> <div id="container"> <div id="header"> <h1>Header</h1> <!-- end #header --></div> <div id="mainContent"> <h1> Main Content </h1> <p>Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Praesent aliquam, justo convallis luctus rutrum, erat nulla fermentum diam, at nonummy quam ante ac quam. Maecenas urna purus, fermentum id, molestie in, commodo porttitor, felis. Nam blandit quam ut lacus. Quisque ornare risus quis ligula. Phasellus tristique purus a augue condimentum adipiscing. Aenean sagittis. Etiam leo pede, rhoncus venenatis, tristique in, vulputate at, odio. Donec et ipsum et sapien vehicula nonummy. Suspendisse potenti. Fusce varius urna id quam. Sed neque mi, varius eget, tincidunt nec, suscipit id, libero. In eget purus. Vestibulum ut nisl. Donec eu mi sed turpis feugiat feugiat. Integer turpis arcu, pellentesque eget, cursus et, fermentum ut, sapien. Fusce metus mi, eleifend sollicitudin, molestie id, varius et, nibh. Donec nec libero.</p> <h2>H2 level heading </h2> <p>Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Praesent aliquam, justo convallis luctus rutrum, erat nulla fermentum diam, at nonummy quam ante ac quam. Maecenas urna purus, fermentum id, molestie in, commodo porttitor, felis. Nam blandit quam ut lacus. Quisque ornare risus quis ligula. Phasellus tristique purus a augue condimentum adipiscing. Aenean sagittis. Etiam leo pede, rhoncus venenatis, tristique in, vulputate at, odio.</p> <!-- end #mainContent --></div> <div id="footer"> <p>Footer</p> <!-- end #footer --></div> </div> </div> <!-- end #container --></div> </body> </html>

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• General workflow to allow multiple OpenIDs to be associated with one app account

  - by BobTodd

  I have a (typical?) scenario: that my app's users can use multiple openids mapped to one app account (like stackoverflow). For me the unique thing on the account is the email address, so this binds openids to the profile. Question is, how to allow a user to start using a second openid once one is setup. I am asking as I have read that it is a security hole to allow automatic account openid syncing simply based on the provider-supplied email address as someone could easily spoof someone's email address to create a spoof openid and falsely access the account (how I am not sure) - although this seems to be exactly how stack operates. See options a. and b. below. Problem for me with a. is what happens if the original openid no longer works for whatever reason - how would you set-up a new openid? Would b. be more acceptable if we used email verification? Does anyone have an article detailing a "standard" way (set of user stories) for this - it seems to be an increasingly popular way to authenticate. I have tried to detail this in a rough decision tree... 1. My Site > authentication landing page - user chooses an openid (facebook, google, myopenid etc), redirection > 2. Provider site returns with token (includes user registering a new openid, logging in or is already logged in to Provider site) 3. My Site > use token id to lookup user 3.1 Profile exists? Yes > authenticate. ends. No > 3.1.1 was email address supplied by provider? Yes > lookup user by email address 3.1.1.1 Profile exists? Yes > a. error message - please login with existing openid and associate this openid (from special page) Yes > b. or associate this openid with existing profile automatically. authenticate. ends. No > Register profile. With registration email address follow 3.1.1, except this time where email is unique, we will associate openid. ends

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• Selected Index Changed event not firing both Autopostback property

  - by TechGuy

  In my Dropdownlist Selected index change event not firing.Here i use auto post back true & View state also true.But Selected Index Changed Event not firing My Code <%@ Page Language="C#" AutoEventWireup="true" CodeFile="AdminEagleViewLogin.aspx.cs" Inherits="AdminEagleViewLogin" %> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <style> body{padding-top:20px;} </style> <title></title> </head> <body> <form id="form1" runat="server"> <div class="container"> <div class="row"> User : <asp:DropDownList ID="drpusr" runat="server" Visible="true" OnSelectedIndexChanged="drpusr_SelectedIndexChanged" AutoPostBack="true" EnableViewState="true" ></asp:DropDownList> Password: <asp:Label ID="lbluserpw" runat="server"></asp:Label> <div class="col-md-4 col-md-offset-4"> <div class="panel panel-default"> <div class="panel-heading"> <h3 class="panel-title">Please sign in</h3> </div> <div class="panel-body"> <form accept-charset="UTF-8" role="form"> <fieldset> <div class="form-group"> <asp:TextBox ID="txtusr" runat="server"></asp:TextBox> </div> <div class="form-group"> <asp:TextBox ID="txtpw" runat="server" TextMode="Password"></asp:TextBox> </div> <div class="checkbox"> <label> <input name="remember" type="checkbox" value="Remember Me"> Remember Me </label> </div> <asp:CheckBox ID="chkremember" runat="server" Visible="false" class="remchkbox" /> <asp:Button ID="submit" runat="server" class="btn btn-lg btn-success btn-block" Text="Submit" OnClick="submit_Click" /> </fieldset> </form> </div> </div> </div> </div> </div> </form> </body> </html> ServerSide User bind to Dropdown is working. public partial class AdminEagleViewLogin : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { BindUsers(); //lbluserpw.Text = Membership.Provider.GetPassword(drpusr.SelectedValue, String.Empty); } protected void submit_Click(object sender, EventArgs e) { if (Membership.ValidateUser(txtusr.Text, txtpw.Text)) { FormsAuthentication.SetAuthCookie(txtusr.Text, chkremember.Checked); string[] CurrentUserRole = Roles.GetRolesForUser(txtusr.Text); var admin = "Administrator"; var manager = "Manager"; var user = "User"; if (CurrentUserRole.Contains(admin)) { Response.Redirect("Administrator.aspx"); } else if (CurrentUserRole.Contains(manager)) { Response.Redirect("Manager.aspx"); } else { Response.Redirect("UserPage.aspx"); } } else { Response.Redirect("AdminEagleViewLogin.aspx"); } } protected void BindUsers() { DataAccess da = new DataAccess(); drpusr.DataSource = da.GetUsers(); drpusr.DataTextField = "UserName"; drpusr.DataValueField = "UserId"; drpusr.DataBind(); drpusr.Items.Insert(0, new ListItem("-- Select User --", "0")); drpusr.Items.RemoveAt(1); } protected void drpusr_SelectedIndexChanged(object sender, EventArgs e) { lbluserpw.Text = Membership.Provider.GetPassword(drpusr.SelectedValue, String.Empty); } }

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• Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

  - by John

  Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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• How do I get around this lambda expression outer variable issue?

  - by panamack

  I'm playing with PropertyDescriptor and ICustomTypeDescriptor (still) trying to bind a WPF DataGrid to an object, for which the data is stored in a Dictionary. Since if you pass WPF DataGrid a list of Dictionary objects it will auto generate columns based on the public properties of a dictionary (Comparer, Count, Keys and Values) my Person subclasses Dictionary and implements ICustomTypeDescriptor. ICustomTypeDescriptor defines a GetProperties method which returns a PropertyDescriptorCollection. PropertyDescriptor is abstract so you have to subclass it, I figured I'd have a constructor that took Func and an Action parameters that delegate the getting and setting of the values in the dictionary. I then create a PersonPropertyDescriptor for each Key in the dictionary like this: foreach (string s in this.Keys) { var descriptor = new PersonPropertyDescriptor( s, new Func<object>(() => { return this[s]; }), new Action<object>(o => { this[s] = o; })); propList.Add(descriptor); } The problem is that each property get's its own Func and Action but they all share the outer variable s so although the DataGrid autogenerates columns for "ID","FirstName","LastName", "Age", "Gender" they all get and set against "Gender" which is the final resting value of s in the foreach loop. How can I ensure that each delegate uses the desired dictionary Key, i.e. the value of s at the time the Func/Action is instantiated? Much obliged. Here's the rest of my idea, I'm just experimenting here these are not 'real' classes... // DataGrid binds to a People instance public class People : List<Person> { public People() { this.Add(new Person()); } } public class Person : Dictionary<string, object>, ICustomTypeDescriptor { private static PropertyDescriptorCollection descriptors; public Person() { this["ID"] = "201203"; this["FirstName"] = "Bud"; this["LastName"] = "Tree"; this["Age"] = 99; this["Gender"] = "M"; } //... other ICustomTypeDescriptor members... public PropertyDescriptorCollection GetProperties() { if (descriptors == null) { var propList = new List<PropertyDescriptor>(); foreach (string s in this.Keys) { var descriptor = new PersonPropertyDescriptor( s, new Func<object>(() => { return this[s]; }), new Action<object>(o => { this[s] = o; })); propList.Add(descriptor); } descriptors = new PropertyDescriptorCollection(propList.ToArray()); } return descriptors; } //... other other ICustomTypeDescriptor members... } public class PersonPropertyDescriptor : PropertyDescriptor { private Func<object> getFunc; private Action<object> setAction; public PersonPropertyDescriptor(string name, Func<object> getFunc, Action<object> setAction) : base(name, null) { this.getFunc = getFunc; this.setAction = setAction; } // other ... PropertyDescriptor members... public override object GetValue(object component) { return getFunc(); } public override void SetValue(object component, object value) { setAction(value); } }

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• error Caused by: java.lang.OutOfMemoryError Load Image

  - by user2493770

  This is my method to load images in background, the first and second load normally. But after these loading, a memory error appears. How can I fix this? public class MainArrayAdapterViewHolder extends ArrayAdapter<EmpresaListaPrincipal> { private final Context context; private ArrayList<EmpresaListaPrincipal> data_array; public DisplayImageOptions options; public ImageLoader imageLoader = ImageLoader.getInstance(); public MainArrayAdapterViewHolder(Context context, ArrayList<EmpresaListaPrincipal> list_of_ids) { super(context, R.layout.main_list_rowlayout, list_of_ids); this.context = context; this.data_array = list_of_ids; //------------- read more here https://github.com/nostra13/Android-Universal-Image-Loader options = new DisplayImageOptions.Builder().showImageForEmptyUri(R.drawable.ic_launcher).showImageOnFail(R.drawable.ic_launcher).resetViewBeforeLoading() .cacheOnDisc().imageScaleType(ImageScaleType.IN_SAMPLE_INT).bitmapConfig(Bitmap.Config.RGB_565).delayBeforeLoading(0).build(); File cacheDir = StorageUtils.getCacheDirectory(context); ImageLoaderConfiguration config = new ImageLoaderConfiguration.Builder(context).memoryCacheExtraOptions(720, 1280) // default = device screen // dimensions .discCacheExtraOptions(720, 1280, CompressFormat.JPEG, 100).threadPoolSize(3) // default .threadPriority(Thread.NORM_PRIORITY - 1) // default .memoryCacheSize(2 * 1024 * 1024).discCache(new UnlimitedDiscCache(cacheDir)) // default .discCacheSize(50 * 1024 * 1024).discCacheFileCount(100).discCacheFileNameGenerator(new HashCodeFileNameGenerator()) // default .imageDownloader(new BaseImageDownloader(context)) // default .tasksProcessingOrder(QueueProcessingType.FIFO) // default .defaultDisplayImageOptions(options) // default .build(); imageLoader.init(config); } @Override public View getView(int position, View convertView, ViewGroup parent) { ViewHolder viewholder; View v = convertView; //Asociamos el layout de la lista que hemos creado e incrustamos el ViewHolder if(convertView == null){ LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); //View rowView = inflater.inflate(R.layout.main_list_rowlayout, parent, false); v = inflater.inflate(R.layout.main_list_rowlayout, parent, false); viewholder = new ViewHolder(); viewholder.textView_main_row_title = (TextView) v.findViewById(R.id.textView_main_row_title); viewholder.imageView_restaurant_icon = (ImageView) v.findViewById(R.id.imageView_restaurant_icon); viewholder.textView_main_row_direccion = (TextView) v.findViewById(R.id.textView_main_row_direccion); v.setTag(viewholder); } ImageLoadingListener mImageLoadingListenr = new ImageLoadingListener() { @Override public void onLoadingStarted(String arg0, View arg1) { // Log.e("* started *", String.valueOf("complete")); } @Override public void onLoadingComplete(String arg0, View arg1, Bitmap arg2) { // Log.e("* complete *", String.valueOf("complete")); } @Override public void onLoadingCancelled(String arg0, View arg1) { } @Override public void onLoadingFailed(String arg0, View arg1, FailReason arg2) { // TODO Auto-generated method stub } }; try { viewholder = (ViewHolder) v.getTag(); viewholder.textView_main_row_title.setText(data_array.get(position).getNOMBRE()); viewholder.textView_main_row_direccion.setText(data_array.get(position).getDIRECCION()); String image = data_array.get(position).getURL(); // ------- image --------- try { if (image.length() > 4) imageLoader.displayImage(image, viewholder.imageView_restaurant_icon, options, mImageLoadingListenr); } catch (Exception ex) { } //textView_main_row_title.setText(name); //textView_main_row_address.setText(address); } catch (Exception e) { // TODO: handle exception } return v; } public class ViewHolder { public TextView textView_main_row_title; public TextView textView_main_row_direccion; //public TextView cargo; public ImageView imageView_restaurant_icon; } }

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• C++ SQLDriverConnect API

  - by harshalkreddy

  Hi, I am using visual studio 2008 and sql server 2008 for developing application(SQL server is in my system). I need to fetch some fields from the database. I am using the SQLDriverConnect API to connect to the database. If I use the "SQL_DRIVER_PROMPT" I will get pop window to select the data source. I don't want this window to appear. As per my understanding this window will appear if we provide insufficient information in the connection string. I think I have provided all the information. I am trying to connect with windows authentication. I tried different options but still no luck. Please help me in solving this problem. Below is the code that I am using: //******************************************************************************** // SQLDriverConnect_ref.cpp // compile with: odbc32.lib user32.lib #include <windows.h> #include <sqlext.h> int main() { SQLHENV henv; SQLHDBC hdbc; SQLHSTMT hstmt; SQLRETURN retcode; SQLWCHAR OutConnStr[255]; SQLSMALLINT OutConnStrLen; SQLCHAR ConnStrIn[255] = "DRIVER={SQL Server};SERVER=(local);DSN=MyDSN;DATABASE=MyDatabase;Trusted_Connection=yes;"; //SQLWCHAR *ConntStr =(SQLWCHAR *) "DRIVER={SQL Server};DSN=MyDSN;"; HWND desktopHandle = GetDesktopWindow(); // desktop's window handle // Allocate environment handle retcode = SQLAllocHandle(SQL_HANDLE_ENV, SQL_NULL_HANDLE, &henv); // Set the ODBC version environment attribute if (retcode == SQL_SUCCESS || retcode == SQL_SUCCESS_WITH_INFO) { retcode = SQLSetEnvAttr(henv, SQL_ATTR_ODBC_VERSION, (SQLPOINTER*)SQL_OV_ODBC3, 0); // Allocate connection handle if (retcode == SQL_SUCCESS || retcode == SQL_SUCCESS_WITH_INFO) { retcode = SQLAllocHandle(SQL_HANDLE_DBC, henv, &hdbc); // Set login timeout to 5 seconds if (retcode == SQL_SUCCESS || retcode == SQL_SUCCESS_WITH_INFO) { SQLSetConnectAttr(hdbc, SQL_LOGIN_TIMEOUT, (SQLPOINTER)5, 0); retcode = SQLDriverConnect( // SQL_NULL_HDBC hdbc, desktopHandle, (SQLWCHAR *)ConnStrIn, SQL_NTS, OutConnStr, 255, &OutConnStrLen, SQL_DRIVER_NOPROMPT); // Allocate statement handle if (retcode == SQL_SUCCESS || retcode == SQL_SUCCESS_WITH_INFO) { retcode = SQLAllocHandle(SQL_HANDLE_STMT, hdbc, &hstmt); // Process data if (retcode == SQL_SUCCESS || retcode == SQL_SUCCESS_WITH_INFO) { SQLFreeHandle(SQL_HANDLE_STMT, hstmt); } SQLDisconnect(hdbc); } SQLFreeHandle(SQL_HANDLE_DBC, hdbc); } } SQLFreeHandle(SQL_HANDLE_ENV, henv); } } //******************************************************************************** Thanks in advance, Harsha

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• how to obtain the relative path of a resource in a j2ee project

  - by Neeraj

  I have a Dynamic Web Project having a flat file (or say text file). I have created a servlet in which I need to use this file. My code is as following: protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // String resource = request.getParameter ("json") ; if ( resource != null && !resource.equals ( "" ) ) { //use getResourceAsStream ( ) to properly get the file. InputStream is = getServletContext ().getResourceAsStream ("rateJSON") ; if ( is != null ) { // the resource exists response.setContentType("application/json"); response.setHeader("Pragma", "No-cache"); response.setDateHeader("Expires", 0); response.setHeader("Cache-Control", "no-cache"); StringWriter sw = new StringWriter ( ) ; for ( int c = is.read ( ) ; c != -1; c = is.read ( ) ) { sw.write ( c ) ; } PrintWriter out = response.getWriter(); out.print (sw.toString ()) ; out.flush(); } } } The problem is that the InputStream is has null value. I'm not sure how to get the correct relative path. I'm using JBOSS as the app server. I have added the resource file in the WebContent directory of a Dynamic Web Project. As a different approch, I tried this: protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub ServletConfig config = getServletConfig(); String contextName = config.getInitParameter("ApplicationName"); System.out.println("context name"+ contextName); String contextPath = config.getServletContext().getRealPath(contextName); System.out.println("context Path"+contextPath); //contextPath = contextPath.substring(0, contextPath.indexOf(contextName)); contextPath += "\\rateJSON.txt"; System.out.println(contextPath); String resource = request.getParameter ("json") ; System.out.println("Hi there1"+resource); if ( resource != null && !resource.equals ( "" ) ) { System.out.println("Hi there"); //use getResourceAsStream ( ) to properly get the file. //InputStream is = getServletContext ().getResourceAsStream (resource) ; InputStream is = getServletConfig().getServletContext().getResourceAsStream(contextPath); if ( is != null ) { // the resource exists System.out.println("Hi there2"); response.setContentType("application/json"); response.setHeader("Pragma", "No-cache"); response.setDateHeader("Expires", 0); response.setHeader("Cache-Control", "no-cache"); StringWriter sw = new StringWriter ( ); for ( int c = is.read ( ) ; c != -1; c = is.read ( ) ) { sw.write ( c ) ; System.out.println(c); } PrintWriter out = response.getWriter(); out.print (sw.toString ()) ; System.out.println(sw.toString()); out.flush(); } } } The value of contextPath is now: C:\JBOSS\jboss-5.0.1.GA\server\default\tmp\4p72206b-uo5r7k-g0vn9pof-1-g0vsh0o9-b7\Nationwide.war\WEB-INF\rateJSON But at this location the rateJSON file is not there? It seems JBOSS is not putting this file in the App.war or doesn't deploy it??? Could someone please help me?

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• Facebook Connect from Localhost, doing some weird stuff

  - by Brett

  So maybe the documentation is out of date, or I am just off here. But I have done a slew of FB iframe apps (connect), but I am starting my first FB Connect site. Running it from localhost, and the Connect URL is http:// my_external_IP_address. When I click on the FB login button on my site, it pops up, says waiting for facebook, and it returns my site in that box, with the URL up top with the http:// mysite/?session={session key, user_id, etc.} The user_id is infact my FB id. And so it thinks I am logged in. If I close the popup, I'm not logged in. I'm not sure why the pop up isn't doing the normal fb connect dialog. I'm following these steps. (I added spaces to the http:// as to not be detected as 'spam') html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml" right after <body> <script src="http://static.ak.connect.facebook.com/js/api_lib/v0.4/FeatureLoader.js.php" type="text/javascript"> At the end, before the body close tag: script type="text/javascript"> FB.init("fbkey", "http://127.0.0.1/xd_receiver.htm"); I have tried using xd_receiver.htm, /xd_receiver.htm (and other combos), and that brings up a blank page. using the http://127.0.0.1 at least does something. In my config file, which is called before all of those, it checks for a PHP session key to see if they are logged in, if that doesn't exist it looks for a cookie, and if that doesn't exist it does this: require_once('includes/facebook.php'); $facebook = new Facebook($fbkey, $fbsec); $user_id = $facebook->get_loggedin_user(); if($user_id > 0){ $user = $ac->getUserFromFB($user_id); $_SESSION['user_id'] = $user['user_id']; } The user_id is always empty when I echo it out to the screen to test. The session event never occurs as well. So I don't know what it is doing in the popup, but I think Facebook thinks it is logging me in. Not sure. Pretty stumped on this one. Any help would be appreciated. Thanks!

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• Why isn't my div scrolling horizontally when adding multiple images?

  - by George

  I have an outer div, and inside of that, I have an inner div which contains a list of images. When the images are wider than the outer div, I want to have it scroll horizontally, but instead, it just puts the image on the next line instead of expanding. If I add many rows, the div does scroll vertically, but horizontally, it doesn't do it. This happens on every browser I've tried - Firefox, Chrome, IE, and Safari. Here is the css: #grid-container { left:33px; position:relative; width:300px; } #grid { width:310px; height:400px; overflow:auto; margin-bottom: 15px; } #grid-container ul { width:305px; } #grid-container li { float:left; list-style-type:none; padding:5px 15px 5px 15px; height:88px; text-align:center; } .image-row { float:left; margin-left: 10px; } .grid-image { height:50px; margin-left:-20px; } Here is the html: <div id="grid-container"> <div id="grid"> <div id="row1" class="image-row"> <ul> <li> <img id="img1" class="grid-image" src="images/img1.jpg"> </li> <li> <img id="img2" class="grid-image" src="images/img2.jpg"> </li> <li> <img id="img3" class="grid-image" src="images/img3.jpg"> </li> <li> <img id="img4" class="grid-image" src="images/img4.jpg"> </li> </ul> </div> <div id="row1" class="image-row"> <ul> <li> <img id="img5" class="grid-image" src="images/img5.jpg"> </li> <li> <img id="img6" class="grid-image" src="images/img6.jpg"> </li> </ul> </div> </div> </div> The problem is img4 is showing on the second row (with img5 and img5 on the third row), even though it should on the first row and the grid div should scroll horizontally. It does scroll vertically. Can I force the div to expand? If I remove the width from the grid div, I do get the horizontal scroll bar, but the image is still on the second row.

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• Strange behaviour on postback in ASP.NET

  - by C-King

  I'm working on a website with a login form. To log in, a postback is used to an OnClick handler in the codebehind. Somehow, the value returned from the Text-property of the username and password textboxes is ten times the value I entered, separated by commas. I checked my entire code for double ID's (which seems to be the most common problem causing this behaviour), but I found each ID defined only once. In the ASPX file I have this: <asp:Label ID="lblFeedback" ForeColor="Red" Font-Bold="true" runat="server" Visible="false" /><br /> <asp:Panel ID="pnlLogin" runat="server"> <table style="border-style: none;"> <tr> <td> <asp:Label ID="lblUsername" AssociatedControlID="txtUsername" runat="server" /> </td> <td> <asp:TextBox ID="txtUsername" runat="server" /><br /> </td> </tr> <tr> <td> <asp:Label ID="lblPassword" AssociatedControlID="txtPassword" runat="server" /> </td> <td> <asp:TextBox ID="txtPassword" runat="server" TextMode="password" /><br /> </td> </tr> <tr> <td> </td> <td> <asp:Button ID="btnLogin" OnClick="btnLogin_Click" runat="server" /> </td> </tr> </table> </asp:Panel> The OnClick handler in the Codebehind: protected void btnLogin_Click(object sender, EventArgs e) { string username = Util.Escape(txtUsername.Text); string password = Util.Escape(txtPassword.Text); WebsiteUser user = WebsiteUser.Create(username, password); if (user != null) { //Set some session variables and redirect to user profile } else { lblFeedback.Text = Localizer.Translate("INVALID_LOGIN"); lblFeedback.ForeColor = Color.Red; lblFeedback.Visible = true; pnlLogin.Visible = true; } } The website is running on ASP.NET 2.0 on ISS 5.1 (Win XP Pro)

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• Why cant I get a Thumb to be larger on a styled scrollbar in WPF.

  - by Tollo

  I have taken the MSDN templates for styling a scrollbar and have been trying to apply my different styles (Image on each track repeater and separate Image on the thumb) but I am unable to make the thumb change size. I have tried setting the Width on the Track.Thumb style and also in the ControlTemplate of the Thumb itself. For some reason the default size is only ever rendered even when the thumb actually occupies much more space. Does anyone know how to make the thumb render at the size that I want? The XAML I am using for the styles is here: <Style x:Key="ScrollBarThumb" TargetType="{x:Type Thumb}"> <Setter Property="Background" Value="Red" /> <Setter Property="OverridesDefaultStyle" Value="True"/> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="{x:Type Thumb}"> <Image Source="sampleimg.png" Stretch="Fill" /> </ControlTemplate> </Setter.Value> </Setter> </Style> <ControlTemplate x:Key="ArfleHBar" TargetType="{x:Type ScrollBar}"> <Grid > <Grid.ColumnDefinitions> <ColumnDefinition MaxWidth="18"/> <ColumnDefinition Width="0.00001*"/> <ColumnDefinition MaxWidth="18"/> </Grid.ColumnDefinitions> <RepeatButton Grid.Column="0" Style="{StaticResource ScrollBarLineButton}" Width="18" Command="ScrollBar.LineLeftCommand" Content="M 4 0 L 4 8 L 0 4 Z" /> <Track Name="PART_Track" Grid.Column="1" IsDirectionReversed="False" > <Track.DecreaseRepeatButton> <RepeatButton Style="{StaticResource ScrollBarPageButton}" Command="ScrollBar.PageLeftCommand" Width="100"/> </Track.DecreaseRepeatButton> <Track.Thumb> <Thumb Style="{StaticResource ScrollBarThumb}" Margin="0,1,0,1" Width="250" Padding="0,0,0,0"> </Thumb> </Track.Thumb> <Track.IncreaseRepeatButton> <RepeatButton Style="{StaticResource ScrollBarPageButton}" Command="ScrollBar.PageRightCommand" Width="100" /> </Track.IncreaseRepeatButton> </Track> <RepeatButton Grid.Column="3" Style="{StaticResource ScrollBarLineButton}" Width="18" Command="ScrollBar.LineRightCommand" Content="M 0 0 L 4 4 L 0 8 Z"/> </Grid> </ControlTemplate> <Style x:Key="ArfleBar" TargetType="{x:Type ScrollBar}"> <Setter Property="SnapsToDevicePixels" Value="True"/> <Setter Property="OverridesDefaultStyle" Value="true"/> <Style.Triggers> <Trigger Property="Orientation" Value="Horizontal"> <Setter Property="Width" Value="Auto"/> <Setter Property="Height" Value="18" /> <Setter Property="Template" Value="{StaticResource ArfleHBar}" /> </Trigger> </Style.Triggers> </Style>

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• php database image show problem

  - by Termedi

  here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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• The 80 column limit, still useful?

  - by Tim Post

  Related: While coding, how many columns do you format for? Is there a valid reason for enforcing a maximum width of 80 characters in a code file, this day and age? I mostly use C, however this question is language agnostic. Its also subjective, so I'll tag it as such. Many individual projects set their own various coding standards, a guide to adjust your coding style. Many enforce an 80 column limit on code, i.e. don't force a dumb 80 x 25 terminal to wrap your lines in someone else's editor of choice if they are stuck with such a display, don't force them to turn off wrapping. Both private and open source projects usually have some style guidelines. My question is, in this day and age, is that requirement more of a pest than a helper? Does anyone still login via the local console with no framebuffer and actually edit code? If so, how often and why cant you use SSH? I help to manage a few open source projects, I was considering extending this limit to 110 columns, but I wanted to get feedback first. So, any feedback is appreciated. I can see the need to make certain OUTPUT of programs (i.e. a --help /h display) 80 columns or less, but I really don't see the need to force people to break up code under 110 columns long into 2 lines, when its easier to read on one line. I can also see the case for adhering to an 80 column limit if you're writing code that will be used on micro controllers that have to be serviced in the field with a god-knows-what terminal emulator. Beyond that, what are your thoughts? Edit: This is not an exact duplicate. I am asking very specific questions, such as how many people are actually still using such a display. I am also not asking "what is a good column limit", I'm proposing one and hoping to gather feedback. Beyond that, I'm also citing cases where the 80 column limit is still a good idea. I don't want a guide to my own "c-style", I'm hoping to adjust standards for several projects. If the duplicate in question had answered all of my questions, I would not have posted this one :) That will teach me to mention it next time. Edit 2 question |= COMMUNITY_WIKI

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• How can I set an image for background of GUI interface?

  - by enriched

  hey everyone, im having some troubles displaying the background image for a GUI interface in java. Here is what i have at the moment, and with current stage of code it shows default(gray) background. import javax.swing.*; import java.awt.event.*; import java.util.Scanner; import java.awt.*; import java.io.File; import javax.imageio.ImageIO; import java.awt.image.BufferedImage; import java.io.IOException; ////////////////////////////////// // 3nriched Games Presents: // // MIPS The Mouse!! // ////////////////////////////////// public class mipsMouseGUI extends JFrame implements ActionListener { private static String ThePDub = ("mouse"); //the password JPasswordField pass; JPanel panel; JButton btnEnter; JLabel lblpdub; public mipsMouseGUI() { BufferedImage image = null; try { //attempts to read picture from the folder image = ImageIO.read(getClass().getResource("/mousepics/mousepic.png")); } catch (IOException e) { //catches exceptions e.printStackTrace(); } ImagePanel panel = new ImagePanel(new ImageIcon("/mousepics/neonglowOnwill.png").getImage()); setIconImage(image); //sets icon picture setTitle("Mips The Mouse Login"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pass = new JPasswordField(5); //sets password length to 5 pass.setEchoChar('@'); //hide characters as @ symbol pass.addActionListener(this); //adds action listener add(panel); //adds panel to frame btnEnter = new JButton("Enter"); //creates a button btnEnter.addActionListener(this);// Register the action listener. lblpdub = new JLabel(" Your Password: "); // label that says enter password panel.add(lblpdub, BorderLayout.CENTER);// adds label and inputbox panel.add(pass, BorderLayout.CENTER); // to panel and sets location panel.add(btnEnter, BorderLayout.CENTER); //adds button to panel pack(); // packs controls and setLocationRelativeTo(null); // Implicit "this" if inside JFrame constructor. setVisible(true);// makes them visible (duh) } public void actionPerformed(ActionEvent a) { Object source = a.getSource(); //char array that holds password char[] passy = pass.getPassword(); //characters array to string String p = new String(passy); //determines if user entered correct password if(p.equals(ThePDub)) { JOptionPane.showMessageDialog(null, "Welcome beta user: USERNAME."); } else JOptionPane.showMessageDialog(null, "You have enter an incorrect password. Please try again."); } public class ImagePanel extends JPanel { private BufferedImage img; public ImagePanel(String img) { this(new ImageIcon(img).getImage()); } public ImagePanel(Image img) { Dimension size = new Dimension(img.getWidth(null), img.getHeight(null)); } public void paintComponent(Graphics g) { g.drawImage(img, 0, 0, null); } } }

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• How to setup Lucene/Solr for a B2B web app?

  - by Bill Paetzke

  Given: 1 database per client (business customer) 5000 clients Clients have between 2 to 2000 users (avg is ~100 users/client) 100k to 10 million records per database Users need to search those records often (it's the best way to navigate their data) Possibly relevant info: Several new clients each week (any time during business hours) Multiple web servers and database servers (users can login via any web server) Let's stay agnostic of language or sql brand, since Lucene (and Solr) have a breadth of support For Example: Joel Spolsky said in Podcast #11 that his hosted web app product, FogBugz On-Demand, uses Lucene. He has thousands of on-demand clients. And each client gets their own database. They use an index per client and store it in the client's database. I'm not sure on the details. And I'm not sure if this is a serious mod to Lucene. The Question: How would you setup Lucene search so that each client can only search within its database? How would you setup the index(es)? Where do you store the index(es)? Would you need to add a filter to all search queries? If a client cancelled, how would you delete their (part of the) index? (this may be trivial--not sure yet) Possible Solutions: Make an index for each client (database) Pro: Search is faster (than one-index-for-all method). Indices are relative to the size of the client's data. Con: I'm not sure what this entails, nor do I know if this is beyond Lucene's scope. Have a single, gigantic index with a database_name field. Always include database_name as a filter. Pro: Not sure. Maybe good for tech support or billing dept to search all databases for info. Con: Search is slower (than index-per-client method). Flawed security if query filter removed. One last thing: I would also accept an answer that uses Solr (the extension of Lucene). Perhaps it's better suited for this problem. Not sure.

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• Bash Shell Scripting Errors: ./myDemo: 56: Syntax error: Unterminated quoted string [EDITED]

  - by ???

  Could someone take a look at this code and find out what's wrong with it? #!/bin/sh while : do echo " Select one of the following options:" echo " d or D) Display today's date and time" echo " l or L) List the contents of the present working directory" echo " w or W) See who is logged in" echo " p or P) Print the present working directory" echo " a or A) List the contents of a specified directory" echo " b or B) Create a backup copy of an ordinary file" echo " q or Q) Quit this program" echo " Enter your option and hit <Enter>: \c" read option case "$option" in d|D) date ;; l|L) ls $PWD ;; w|w) who ;; p|P) pwd ;; a|A) echo "Please specify the directory and hit <Enter>: \c" read directory if [ "$directory = "q" -o "Q" ] then exit 0 fi while [ ! -d "$directory" ] do echo "Usage: "$directory" must be a directory." echo "Re-enter the directory and hit <Enter>: \c" read directory if [ "$directory" = "q" -o "Q" ] then exit 0 fi done printf ls "$directory" ;; b|B) echo "Please specify the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 fi while [ ! -f "$file" ] do echo "Usage: \"$file\" must be an ordinary file." echo "Re-enter the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 fi done cp "$file" "$file.bkup" ;; q|Q) exit 0 ;; esac echo done exit 0 There are some syntax errors that I can't figure out. However I should note that on this unix system echo -e doesn't work (don't ask me why I don't know and I don't have any sort of permissions to change it and even if I wouldn't be allowed to) Bash Shell Scripting Error: "./myDemo ./myDemo: line 62: syntax error near unexpected token done' ./myDemo: line 62: " [Edited] EDIT: I fixed the while statement error, however now when I run the script some things still aren't working correctly. It seems that in the b|B) switch statement cp $file $file.bkup doesn't actually copy the file to file.bkup ? In the a|A) switch statement ls "$directory" doesn't print the directory listing for the user to see ? #!/bin/bash while $TRUE do echo " Select one of the following options:" echo " d or D) Display today's date and time" echo " l or L) List the contents of the present working directory" echo " w or W) See who is logged in" echo " p or P) Print the present working directory" echo " a or A) List the contents of a specified directory" echo " b or B) Create a backup copy of an ordinary file" echo " q or Q) Quit this program" echo " Enter your option and hit <Enter>: \c" read option case "$option" in d|D) date ;; l|L) ls pwd ;; w|w) who ;; p|P) pwd ;; a|A) echo "Please specify the directory and hit <Enter>: \c" read directory if [ ! -d "$directory" ] then while [ ! -d "$directory" ] do echo "Usage: "$directory" must be a directory." echo "Specify the directory and hit <Enter>: \c" read directory if [ "$directory" = "q" -o "Q" ] then exit 0 elif [ -d "$directory" ] then ls "$directory" else continue fi done fi ;; b|B) echo "Specify the ordinary file for backup and hit <Enter>: \c" read file if [ ! -f "$file" ] then while [ ! -f "$file" ] do echo "Usage: "$file" must be an ordinary file." echo "Specify the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 elif [ -f "$file" ] then cp $file $file.bkup fi done fi ;; q|Q) exit 0 ;; esac echo done exit 0 Another thing... is there an editor that I can use to auto-parse code? I.e something similar to NetBeans?

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