Search Results

Search found 19350 results on 774 pages for 'mysql views'.

Page 623/774 | < Previous Page | 619 620 621 622 623 624 625 626 627 628 629 630  | Next Page >

• Useful design patterns when dealing with spring 3 controllers

  - by Mat Banik

  Recently I was overlooking my controllers and they are bit of mess. I'd like to organize they way I set returning views Do more elegant mesageSource massaging back to the users and account for i18n Security checking, what user can access an what they can't Consistent way of calling the service layer And somehow bring consistency to the debugging lines. Do better job with error handling and serving it to the user. I'm already on mission to do security logging with AOP :) I'm just looking for patterns I could implement to help me to do all of the above. Or just some general advice in case no patterns apply, or advice on something I didn't mention but is common practice.

  Read the article

• jquery cycle plugin using RSS feed images?

  - by Chris

  This could well be a terribly ignorant question, if so please forgive me: I'm using jquery cycle plugin to create an image rotator of recently posted images. Im using drupal 6.x and created an RSS feed of the recent images using the views module. I have no idea how to connect the two. Any suggestions? I have a feeling an RSS feed might not be the best way to go about this, but it's all I could come up with. Thanks for the help.

  Read the article

• PHP ZF: I can't debug my IndexController.php actions code

  - by overthetop

  Hi I'm new to php and I'm using xampp, eclipse pdt, xdebug. I've set xdebug so that I can debug my site on apache but when I click 'debug as web page' in the eclipse ide only the breakpoint in the public/index.php and in the views get hit. If I put a breakpoin here public function indexAction() { // action body $this->view->s = "deam"; } the debugger don't stop?! why is that? I can't debug the most important part of my application. :( Plese help me with this.

  Read the article

• Same Title Bar but different View below it in Android?

  - by sunil

  Hi, In one of my Android Application I need to keep the title bar same but the view that is shown in the rest of the screen changes. So, I have taken different Activity for all the views that I need to show and set the title bar in every Activities onCreate method. Now, the problem is that I have a button in the title bar and need to perform certain action on its click event. Writing the same event handling code in every Activity class is very cumbersome. Is there any other way out that whenever there is a click event on that button of the title bar then we can have the same functionality without writing the same code in all the Activity classes. Can we use ViewGroup for that? I don't have much idea about ViewGroup. Is that possible with ViewGroup? If anyone knows the solution then please let me know. Thanks & Regards Sunil

  Read the article

• Can you create a HIPAA compliant Amazon S3 Web Application?

  - by xkingpin

  I am facing some questions when trying to design an S3 application using ASP.NET MVC and trying to stay HIPAA compliant. My initial plan was to require an SSL connection to my web server, encrypt the images on my server, then send them to s3 using my private keys. Here's my obvious concerns: You cannot store unencrypted images in any temporary file cache when client views images within the browser. Even if I setup an ashx to generically handle the image in memory, couldn't this get stored in cache? Saying the images will be encrpyted because you will be connecting to my server via https still does not guarantee all browsers will not cache data. It's not possible to even consider the "Query String" with expiration option since data will be encrypted before being stored on disk at s3, and will again be decrypted at my server in memory. I think my only option would be to write/purchase some sort of ActiveX component that will not expose the image as a simple html image source or write my app as a client side WinForm application.

  Read the article

• How to build the ViewModel in MVVM not to violate the Single Responsibility Principle?

  - by Przemek

  Robert Martin says: "There should never be more than one reason for a class to change". Let's consider the ViewModel class which is bound to a View. It is possible (or even probable) that the ViewModel consists of properties that are not really related to each other. For small views the ViewModel may be quite coherent, but while the application gets more complex the ViewModel will expose data that will be subject to change for different and unrelated reasons. Should we worry about the SRP principle in the case of ViewModel class or not?

  Read the article

• Group SQL tables in Microsoft SQL Server Management Studio object explorer

  - by MainMa

  I have a table which has approximately sixty tables, and other tables are added constantly. Each table is a part of a schema. A such quantity of tables makes it difficult to use Microsoft SQL Server Management Studio 2008. For example, I must scroll up in object explorer to access database related functions, or scroll down each time I need to access Views or Security features. Is it possible to group several tables to be able to expand or collapse them in Object Explorer? Maybe a folder may be displayed for each schema, letting collapse the folders I don't need to use?

  Read the article

• data between pages: $_SESSION vs. $_GET ?

  - by Haroldo

  Ok, firstly this is not about forms this is about consistent layout as a user explores a site. let me explain: If we imagine a (non-ajax) digital camera online store, say someone was on the DSLR section and specified to view the cameras in Gallery mode and order by price. They then click onto the Compact camera's page. It would be in the users interests if the 'views' they selected we're carried over to this new page. Now, i'd say use a session - am i wrong? are there performance issues i should be aware of for a few small session vars ( ie view=1 , orderby=price) ?

  Read the article

• iPhone UITableView populating variable rows sections from flat array

  - by Biko

  I thought that would be very common and easy iPhone App. In the main app I connect to database, retrieve values from database (NSDate converted to NSString)n and put into single array. The in one of the views I populate UITableView with elements from the array. UITableView is grouped (sections). I step through array to discover number of sections (change section if new day). How do I retrieve correct element of array in cellForRowAtIndexPath? IndexPath.section and IndexPath.row seem useless as row starts count from zero for each section. If number of rows in each section was the same it would have been easy: [arryData objectAtIndex:(indexPath.row)+indexPath.section*[tblMatchesView numberOfRowsInSection:indexPath.section]]; But number of rows in each section varies... :-)

  Read the article

• asp.net mvc script and style references

  - by tom

  I'm trying to include script and style references that will not break on deployment, however I can not even get the references to work locally. I have tried using Url.Content() and MVCContrib's <%=Html.ScriptInclude("")%>. My scripts are in a Scripts folder on the root of the site; my styles are in the usual Content/css/ folder. The scripts render like this: <script type="text/javascript" src="/Scripts/MicrosoftAjax.debug.js" ></script> This will not work in a view page in the Views folder. What am I doing wrong and what is the best way to handle this? I would have thought Url.Content() would at least work for styles but used in my master page, the link rendered <link href="/Content/css/Site.css rel="stylesheet" type="text/css" /> This does not work, because the Master Page is in a Shared folder, so what is really the way forward with this?

  Read the article

• Using NSUserDefaults to load data depending on which table view cell is pressed

  - by Bad_APPZ

  I want my app to work just like the 'contacts' app on iOS. When a user selects a certain TableViewCell, i want to load certain data. No Matter which cell is pressed, Either "Joseph, Richard, or Shannon", This view comes up: Both of the views look the exact same, but they just display different information. So i guess my question is: How can I programmatically set a key @"cell1" @"cell2", etc... for each cell using NSUserDefaults? But here is the catch, I dont know how many cells will be added, so i cant hard code this, How can I create a key for each table view cell for how ever many is added? Thanks for the help!

  Read the article

• Django: How do I get logging working?

  - by swisstony

  I've added the following to my settings.py file: import logging ... logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', filename=os.path.join(rootdir, 'django.log'), filemode='a+') And in views.py, I've added: import logging log = logging.getLogger(__name__) ... log.info("testing 123!") Unfortunately, no log file is being created. Any ideas what I am doing wrong? And also is their a better method I should be using for logging? I am doing this on Webfaction.

  Read the article

• Trouble rendering a view inside a generic class

  - by Horace Loeb

  I'm trying to encapsulate the logic for generating my sitemap in a separate class so I can use Delayed::Job to generate it out of band: class ViewCacher include ActionController::UrlWriter def initialize @av = ActionView::Base.new(Rails::Configuration.new.view_path) @av.class_eval do include ApplicationHelper end end def cache_sitemap songs = Song.all sitemap = @av.render 'sitemap/sitemap', :songs => songs Rails.cache.write('sitemap', sitemap) end end But whenever I try ViewCacher.new.cache_sitemap I get this error: ActionView::TemplateError: ActionView::TemplateError (You have a nil object when you didn't expect it! The error occurred while evaluating nil.url_for) on line #5 of app/views/sitemap/_sitemap.builder: I assume this means that ActionController::UrlWriter is not included in the right place, but I really don't know

  Read the article

• KeyError this says that key(partner) is not in dict ?

  - by Ansh Jain

  I am trying to make an chat application using python and django. I almost complete it and its working fine for 8-10 minutes when two persons are chatting after that certain time it shows an error. here is the traceback : - Traceback (most recent call last): File "\Django_chat\django_chat\chat\views.py", line 55, in receive message = chatSession.getMessage(request.session['partner'],request.session['uid'],afterTime) File "C:\Python26\lib\site-packages\django\contrib\sessions\backends\base.py", line 47, in __getitem__ return self._session[key] KeyError: 'partner' here is the receive module :- def receive(request): message received by this user chatSession = chat() data = request.POST afterTime = data['lastMsgTime'] try: message = chatSession.getMessage(request.session['partner'],request.session['uid'],afterTime) except: #partnerId = virtual_users.objects.get(id=request.session['uid']).partner print('there is an error in receive request') traceback.print_exc(file=open("/myapp.log","a")) msg = serializers.serialize("json", message) return HttpResponse(msg) Please Help me :( thanks Ansh J

  Read the article

• Coldfusion 9 Inter portlet communication?

  - by Jakub

  I am having a hard time trying to find documentation at achieving IPC using Coldfusion 9 portlets under JBOSS. Does anyone have any good references I can take a look at? Or maybe some example code that I can go off of? So far I've been successful in getting my portlets working under Liferay (JBOSS), form submission, different views (edit/help) all work fine. Just need to know how to have one portlet on the page talk with another portlet. So far have been unsuccessful :( Anyone?

  Read the article

• Sinatra: How do I provide access to a login form while preventing access to the rest of my Sinatra a

  - by Brandon Toone

  I recently created a Sinatra app with a login form (no basic auth). To prevent access to the app unless the user logged in I put a before block in place before do unless request.path_info == '/login' authenticated? end end I quickly realized that this prevented me from accessing resources in the public directory like my style sheet and logo unless authenticated first as well. To get around that I changed my filter to the following: before do unless request.path_info == '/login' || request.path_info == "/stylesheets/master.css" || request.path_info == "/images/logo.png" authenticated? end end If there were lots of resources I needed to provide exceptions to this way of making them would quickly become overwhelming. What is a better way to code this so I can make exceptions for the public directory or even its specific sub-directories and files like /stylesheets, /images, /images/bg.png but not /secret or /secret/eyes-only.pdf? Or ... Is there a completely different best-practice to handle this situation of locking down everything except the stuff related to logging in (handlers, views, resources)?

  Read the article

• How Does a Login system generally work with OOP?

  - by fakingfantastic

  Sorry if this is a badly formed question, but I'm trying to make my web applications (using PHP) more OO. *EDIT* I'm developing the Framework myself */EDIT* Everything is great so far, I've made a Front Controller system that taps into a MVC system. The FC figures out what page you want, loads the specific page Controller (*EDIT* which extends an abstract Controller Object */EDIT*), which gets anything it needs from Models, and then calls the appropriate View. Very basic. But now, I need to make an admin section (quasi-CMS). How does a login system fit into the grand scheme of things? Do you set controllers as needing a login? If so, how? What If you only want certain views of a controller requiring login? Thanks in advance.

  Read the article

• Click events not working in Rails view

  - by Fdr

  I have following view (html.erb): <h3>My view</h3> <script> function test() { alert("hello"); } </script> <input type="button" onClick="test();" value="test" /> For reasons I cannot understand the onClick event never gets fired when I access the view through rails(tried static apache hosting - no problems there). Here is rendered html: http://pastebin.com/LmGysgUG I feel quite stupid, is this something to do the way Rails renders views?

  Read the article

• iPhone: TabBarController as second level of Navigation Controller

  - by Nebs

  I'm new to iphone development. I've read tutorials about implementing a tab bar controller on the window (eg as the main controller for the app). But how can I create a tab bar controller as a 'standalone' UIViewController that can be called by a navigation bar controller? Basically my navigation bar controller has an array of UIViewControllers that it displays in the table and then loads the appropriate view/controller when a user selects an item. Now I want one of these loaded views/controllers to be a tab bar controller. How can I do this? I'm not sure how to create a tab bar controller on its own without having an outlet/instance in the application delegate. Hope that made sense. Thanks.

  Read the article

• objectWithFieldNAme Best Practice for CoreData

  - by Rafael

  Hello, I'm trying to implements some methods for my CoreData models and I'm wonndering if the way I'm doing it is a good practice. I want to implement methods of the type getObjectsWithFieldName. This methods could be used by severals views. So the way I'm doing it is implementing a Class method in the model in the following way: +(NSArray *)getObjectWithFieldName:(NSString *)fieldName andContext:(NSManagedObjectContext *) context; Is this a good practice? Or there is another way to do it for iPhone Development? Thanks in advanced.

  Read the article

• Relation/Sort not working in rails controller?

  - by Elliot

  I have the following relation in my rails app: genre - has many - authors authors - belong to genre and has many books books - belongs to authors and belongs to users (users can add books to the db) in my controller I have: @books=current_user.books(:include => [:author => :genre], :order => 'created_at DESC') While I am able to use the @books variable in my views - nothing is done correctly (i.e. its not showing me only books added by that user, and its not descending by created_at)... any ideas? -- Also I'm using clearance for the user auth, so current_user without the @ in the controller seems to work fine Actually, I think the relation is working, only the sort might not be working...

  Read the article

• Passing parameters into ViewModels (Prism)

  - by vXtreme

  Hi I can't figure out how to pass parameters to my viewmodels from other views or viewmodels. For instance, I have a View called Customers. There is a grid inside, and if you double-click the grid, a new view is supposed to come up and allow you to edit that customer's data. But how will the View(Model) responsible for editing data know which customer it's supposed to open if I can't pass any parameters inside? EventAggregator is out of the question because I obviously can't create hundreds of eventargs, each for one view. And besides, it's a lousy solution. So far I was able to come up with: CustomerDataView custView = new CustomerDataView(customerId, currentContext); manager.Regions[RegionNames.Sidebar].AddAndActivate(custView); What do you think about this particular solution? Is this the way it's normally done? What I don't like about this is the fact that I lose out on automatic dependency injection by Unity.

  Read the article

• MVC Html Layout C# code formatting

  - by Andrew Florko

  I insert into asp.net mvc views C# logic that manages layout like the following: <% if (Model.People.Count > 0 ) { %> <% foreach (var person in Model.People) { %> ... <% }} else { %> <span class="error">Sorry, no people</span> <%} %> I try to minimize <% % code placing "{" symbol on the same line as it's condition (java-style). Html layout looks more clear to me after that. Do you apply C# formatting rules to <% % html injections "}" should be on a new line or manage layout in different way? Thank you in advance!

  Read the article

• How do I create a view with a picker on the bottom and a table view on the top?

  - by Andy

  Hi - first time asker, long-time lurker. I am trying to create an iPhone view that has a date/time picker on the bottom half of the screen, and a grouped, single-section, four-row table view on the top half of the screen (almost identical to the one Apple shows in Fig. 2-4 of their View Controller Programming Guide (but then never goes on to explain). Conceptually, I think I understand that what I need is a main view with a pair of subviews - one for the picker, and one for the table view. I'm pretty sure I can make the picker function once I have it on-screen, and I'm pretty sure I can make the table view function too. What I can't for the life of me figure out is how, programmatically speaking, to get the two views onto the screen simultaneously. I can lay it out perfectly in Interface Builder, but then it all goes to hell when I switch to Xcode...the view appears with the picker, but no table view. Thanks, in advance, for any help you can offer.

  Read the article

• pyramid - How to handle complex URL in a elegant way?

  - by Lingfeng Xiong

  I'm writing a admin website which control several websites with same program and database schema but different content. The URL I designed like this: http://example.com/site A list of all sites which under control http://example.com/site/{id} A brief overview of select site with ID id http://example.com/site/{id}/user User list of target site http://example.com/site/{id}/item A list of items sold on target site http://example.com/site/{id}/item/{iid} Item detailed information # ...... something similar As you can see, nearly all URL are need the site_id. And in almost all views, I have to do some common jobs like query Site model against database with the site_id. Also, I have to pass site_id whenever I invoke request.route_path. So... is there anyway for me to make my life easier? Thanks in advance.

  Read the article

< Previous Page | 619 620 621 622 623 624 625 626 627 628 629 630  | Next Page >