question about counting sort
- by davit-datuashvili
hi i have write following code which prints elements in sorted order only one big problem is that it use two additional array
here is my code
public class occurance{
public static final int n=5;
public static void main(String[]args){
// n is maximum possible value what it should be in array suppose n=5 then array may be
int a[]=new int[]{3,4,4,2,1,3,5};// as u see all elements are less or equal to n
//create array a.length*n
int b[]=new int[a.length*n];
int c[]=new int[b.length];
for (int i=0;i<b.length;i++){
b[i]=0;
c[i]=0;
}
for (int i=0;i<a.length;i++){
if (b[a[i]]==1){
c[a[i]]=1;
}
else{
b[a[i]]=1;
}
}
for (int i=0;i<b.length;i++){
if (b[i]==1) {
System.out.println(i);
}
if (c[i]==1){
System.out.println(i);
}
}
}
}
//
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1.i have two question what is complexity of this algorithm?i mean running time
2. how put this elements into other array with sorted order? thanks
