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  • Connect 4 C# (How to draw the grid)

    - by Matt Wilde
    I've worked out most of the code and have several game classes. The one bit I'm stuck on at the moment, it how to draw the actual Connect 4 grid. Can anyone tell me what's wrong with this for loop? I get no errors but the grid doesn't appear. I'm using C#. private void Drawgrid() { Brush b = Brushes.Black; Pen p = Pens.Black; for (int xCoor = XStart, col = 0; xCoor < XStart + ColMax * DiscSpace; xCoor += DiscSpace, col++) // x coordinate beginning; while the x coordinate is smaller than the max column size, times it by // the space between each disc and then add the x coord to the disc space in order to create a new circle. for (int yCoor = YStart, row = RowMax - 1; yCoor < YStart + RowMax * DiscScale; yCoor += DiscScale, row--) { switch (Grid.State[row, col]) { case GameGrid.Gridvalues.Red: b = Brushes.Red; break; case GameGrid.Gridvalues.Yellow: b = Brushes.Yellow; break; case GameGrid.Gridvalues.None: b = Brushes.Aqua; break; } MainDisplay.DrawEllipse(p, xCoor, yCoor, 50, 50); MainDisplay.FillEllipse(b, xCoor, yCoor, 50, 50); } Invalidate(); } Thanks.

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  • Need help debugging a huge chunk of JSON data...

    - by meder
    I have a huge chunk, so large that I can't manually edit the file and need to read it in and do regex operations to see what's wrong. Basically - my server is PHP 5.1.6 and I can't update it. This features an older json_decode which is less featured than the 5.2/5.3 versions. json_decode returns NULL and json_last_error is being invoked but the function doesn't exist except in PHP 5.3 so I'm manually trying to see what's wrong. $regex = '#[^0-9"$a-zA-Z{:}().]#'; $json = preg_replace( $regex, '', $json ); $tree = json_decode ( $json, true ); var_dump($tree); // NULL A snippet of the JSON.. somewhere in the middle {"109":0,"103":1,"102":59,"101":70,"100":4299,"94":0,"50":51,"46":0,"45":0,"44":0,"43":0,"42":0,"23":0,"22":0,"18":0,"17":1,"16":1,"13":160,"8":4298}},"2":{"d":{"109":0,"103":92,"102":54,"101":53,"100":4301,"94":0,"50":4278,"49":328,"46":1,"45":0,"44":1,"43":0,"42":0,"26":0,"23":0,"22":0,"18":0,"17":1,"16":1,"8":4300},"m":{"94":1,"100":1,"26":1,"50":1,"8":1,"49":1,"18":1,"43":1,"42":1,"109":1},"c":{"\/":{"d":{"109":0,"100":4301,"94":0,"50":4278,"49":328,"43":0,"42":0,"26":0,"18":0,"8":4300}},"G":{"d":{"109":1,"100":4303,"94":1,"68":17,"50":64,"49":53,"43":1,"42":1,"34":0,"18":1,"13":2216,"11":0,"8":4302}}}},"3": The }}}} is suspicious but this probably just closes 4 nested object literals. Would appreciate any insight.

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  • how do I copy value from one table and inserted to another in the same database??

    - by mathew
    I am having a tough time to do this... I have created two table say table-1 and table-2 in same database.what I want is I need to copy some values from table-1 and insert the same to table-2. I have tried many ways but it does not seems work. below is my code can any one tell me where I am missing?? $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $resultb = mysql_query("SELECT * FROM table-2")or die(mysql_error()); $row = mysql_fetch_array($resultb); $days = (strtotime(date("Y-m-d")) - strtotime($row['regtime'])) / (60 * 60 * 24); if($row > 0 && $days < 1){ $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_close($db); }else{ $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $result = mysql_query("SELECT * FROM table-1 WHERE regtime = DATE(NOW()) ORDER BY rank ASC LIMIT 1;")or die(mysql_error()); $row = mysql_fetch_array($result); $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_query("INSERT INTO table-2 (regtime,person,catog,position,location,rank) VALUES(NOW(),'$person','$catogr','$position','$location','$rank')"); mysql_close($db); }

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  • Does anyone know of any good tutorials for using the APIs from Amazon WeB Services, namely CloudWatc

    - by undefined
    Hi, I have been wrestling with Amazon's CloudWatch API with limited success. Does anyone know of any good resources (other than amazon's api docs) for using the APIs. I have tried to run them using the PHP library for CloudWatch but get nothing but error codes. I am configuring the GetMetricStatisticsSample.php file as follows: $request = array(); $endTime = date("Y-m-d G:i:s"); $yesterday = mktime (date("H"), date("i"), date("s"), date("m"), date("d")-1, date("Y")); $startTime = date("Y-m-d 00:00:00", $yesterday); $request["Statistics.member.1"] = "Average"; $request["EndTime"] = $endTime; $request["StartTime"] = $startTime; $request["MeasureName"] = "CPUUtilization"; $request["Unit"] = "Percent"; invokeGetMetricStatistics($service, $request); But this returns "Caught Exception: Internal Error Response Status Code: 400 Error Code: Error Type: Request ID: XML:" I have also tried from command line as follows - set JAVA_HOME=C:\Program Files\Java\jre1.6.0_05 set AWS_CLOUDWATCH_HOME=C:\AmazonWebServices\API_tools\CloudWatch-1.0.0.24 set PATH=%AWS_CLOUDWATCH_HOME%\bin mon-list-metrics but get C:|Program' is not recognized as an internal or external command... any suggestions? cheers

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  • htaccess change DirectoryIndex priotiry to php and not html

    - by Jayapal Chandran
    In a production server there are index.html and index.php By default index.html is getting loaded. I want index.php to be the default script to load and if index.php is not present then index.html can load. It is a shared hosting so we do not have access to the httpd.conf file So i thought of creating .htaccess file which would do the above condition. What is the directive to include in .htaccess file to do so?

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  • Random Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the old and updated version of the code: New php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Old PHP: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will this first code guarantee uniqueness?

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  • jQuery recursive function to upload many files while giving the user some feedback

    - by checcco
    Hi guys, I'm trying to write a jQuery function to let users upload many files at once. Here's the function I thought to give the user some feedback about the upload process progress. function uploadFiles(numbersOfFiles, start) { $("#info").html(start + " files uploaded"); $.post('upload.php', { start: start }, function (data) { start += 5; if (start < numbersOfFiles) { $("#info").html(start + " files uploaded"); uploadFiles(numbersOfFiles, start); } else { $("#info").html("All files have been uploaded"); } }); } The function calls a php script to upload 5 files, then if there are more files to upload it calls the script again. The whole process works. I've tried it with 100 files. The only thing that doesn't work is the #info div updating. The div get updated the first time and then again only to show "All files have been uploaded". So there's no feedback for the user about the uploading process. I can't understand why... Any help?

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  • Problem with mysql query in paging

    - by jasmine
    I have a very simple paging and mysql query. Im not sure that my query is right: $perPage =4; $page= (isset($GET['page']) && is_numeric($GET['page'])) ? $_GET['page'] : 1; $start = ($page * $perPage ) - $perPage ; if (is_numeric($_GET['cID'])){$cid = $_GET['cID'];} $totalCount = sprintf("SELECT COUNT(*) as 'Total' FROM content WHERE catID = %d", $cid ) ; $count = mysql_query($totalCount); $rowCount = mysql_fetch_array($count); $sql = sprintf("SELECT id, title, abstract, content_image FROM content WHERE catID = %d ORDER BY id DESC LIMIT %d, %d", $cid, $start, $perPage ); $query = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($query)){ echo $row['id'].' : '. $row['title'] .'<br>'; } with /categories.php?cID=1&page=2 and /categories.php?cID=1&page=1 The output is: 95 : titlev 94 : titlex 93 : titlec 92 : titleb and not changed. What is wrong in my query? Thanks in advance

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  • Make a router like zend

    - by Vahan
    I have a url http://*.com/branch/module/view/id/1/cat/2/etc/3. It becomes. array ( 'module'=>'branch', 'controller'=>'module', 'action'=>'view' ); next I need to get the params. Ihave this array. /*function getNextSegments($n,$segments) { return array_slice ( $q = $this->segments, $n + 1 ); } $params = getNextSegments(3); */ array ( 0 => 'id', 1 => '1', 2 => 'cat', 3 => '2', 4 => 'etc', 5 => '3' );//params And i wanna convert it to this one: array ( 'id'=1, 'cat'=2, 'etc'=3, ); How i can do this using php function. I know I can do using for or foreach, but I think php has such function , but i cant find it :(. Thank you. class A { protected function combine($params) { $count = count ( $params ); $returnArray = array (); for($i = 0; $i < $count; $i += 2) { $g = $i % 2; if ($g == 0 or $g > 0) { if (isset ( $params [$i] ) and isset ( $params [$i + 1] )) $returnArray [$params [$i]] = $params [$i + 1]; } } return $returnArray; } } This works normaly. If anybody has better login for this please help. Thank you again.

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  • Retrieve POST data without knowing exact number of fields

    - by James
    Hi all! I'm creating an online poll from scratch which will be held in a database. I'm working on getting a system set up so someone can create a new poll. I will be having the user fill out a simple HTML form with the Questions and Answers (there may be several answers). The user will be able to add multiple questions and multiple answers for each question. As the total number of questions and answers will be decided by the user, I need to create some clever PHP to cater for this - however many there are. When dealing with a static number of questions, it's simple. But I'm having trouble thinking of a way to get all the POST data into individual PHP variables so I can process them. I was thinking of using a foreach loop, anyone got any ideas? Sorry for the long winded description! If anyone needs anything clarified, I'd be happy to do so. My problem is that I can't get my head around how to deal with the POST values when I don't know exactly which element of the array will contain what. If things were static with a set number of questions and answers, I'd know $_POST[0] was Question1, etc Thank you! =)

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  • Query not being executed

    - by user2385241
    I'm trying to create a script that allows me to upload an image, grab the details sent through inputs (a description and chosen project number) and insert this information into a table. I currently have this function: public function NewEntry() { $connect = new dbconnect; $_SESSION['rnd'] = substr(number_format(time() * rand(),0,'',''),0,15); $allowedExts = array("gif", "jpeg", "jpg", "png"); $size = $_FILES["file"]["size"]; $path = $_FILES["file"]["name"]; $extension = pathinfo($path, PATHINFO_EXTENSION); $pr = $_POST['project']; $cl = $_POST['changelog']; $file = $_SESSION['rnd'] . "." . $extension; if (in_array($extension, $allowedExts) && $size < 200000000) { if ($_FILES["file"]["error"] == 0) { if (!file_exists("../uploads/" . $_SESSION['rnd'])) { move_uploaded_file($_FILES["file"]["tmp_name"], "../uploads/" . $_SESSION['rnd'] . "." . $extension); } } } else { echo "File validation failed."; } $row = $connect->queryExecute("INSERT INTO entries(project,file,changelog)VALUES($pr,$file,$cl)"); header('location:http://www.example.com/admin'); } When the form is posted the function runs, the image uploads but the query isn't executed. The dbconnect class isn't at fault as it's untampered and has been used in past projects. The error logs don't give any output and no MySQL errors show. Any ideas?

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  • cannot get FilesMatch and mod_rewrite working together

    - by neil
    Hello, I'm having a little difficulty with my .htaccess when combining a password protection on a file and a mod_rewrite: If I only have this as my .htaccess <FilesMatch "manage.php"> AuthName "Member Only" AuthType Basic AuthUserFile /home/myuser/.htpasswd require valid-user </FilesMatch> It password protects manage.php fine. If I have this as my .htaccess RewriteEngine on RewriteCond $1 !^(index\.php|manage\.php|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L,QSA] It works as expected: robots.txt, index.php and manage.php are left alone and are called as normal, everything else is redirected to index.php/$1 HOWEVER, If I combine them then when I visit manage.php it gets redirected as index.php/$1, i.e. the FilesMatch is causing the entry in rewritecond to be ignored. If I actually enter a password in the original test and get to the file, it works in this last test. So I guess something is up with the rewrite and the file match. i.e. entering this causes .\manage.php to be called as .\index.php\manage.php <FilesMatch "manage.php"> AuthName "Member Only" AuthType Basic AuthUserFile /home/myuser/.htpasswd require valid-user </FilesMatch> RewriteEngine on RewriteCond $1 !^(index\.php|manage\.php|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L,QSA] Thanks for any help :)

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  • Sessions not sticking linux server

    - by Jacob Windsor
    I have just moved the dev site over to my linux server for production but the sessions don't seem to be sticking for very long. I am guessing it is the server settings and not the php because it does the same thing with the plesk panel. Whenever a script is executed the sessions seems to get unset. I see nothing in the error log so not sure what it is. It all worked fine on wamp. Anyway I uploaded the php.ini file which was in the wamp server as it had all the settings i needed and all was working on localhost. Not sure what the problem is and this is the final thing that I have to sort out before going into production. And just too add the sessions are being started as they last for a little bit just don't stick around long. Here is the relevent part of my login script just in case there is something wrong with the code: // if login is ok then we add a cookie if($flag == 0) { $pass = htmlspecialchars(mysql_real_escape_string($_POST['pass'])); $username = htmlspecialchars(mysql_real_escape_string($_POST['username'])); $_SESSION['username']=$username; $_SESSION['password']=$pass;

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  • SQL code to display counts() of value retrieved from another column

    - by Doctor Trout
    I have three tables (these are the relevant columns): Table1 bookingid, person, role Table2 bookingid, projectid Table3 projectid, project, numberofrole1, numberofrole2 Table1.role can take two values: "role1" or "role2". What I want to do is to show which projects don't have the correct number of roles in Table1. The number of roles there there should be for each role is in Table3. For example, if Table1 contains these three rows: bookingid, person, role 7, Tim, role1 7, Bob, role1, 7, Charles, role2 and Table2 bookingid, projectid 7, 1 and Table3 projectid, project, numberofrole1, numberofrole2 1, Test1, 2, 2 I would like the results to show that there are not the correct number of role2s for project Test1. To be honest, something like this is a bit beyond my ability, so I'm open to suggestions on the best way to do this. I'm using sqlite and php (it's only a small project). I suppose I could do something with the php at the end once I've got my results, but I wondered if there was a better way to do it with sqlite. I started by doing something like this: SELECT project, COUNT(numberofrole1) as "Role" FROM Table1 JOIN Table2 USING (projectid) JOIN Table3 USING (bookingid) WHERE role="role1" GROUP BY project But I can't work out how to compare the value returned as "Role" with the value got from numberofrole1 Any help is gratefully received.

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  • Assistance with CC Processing script

    - by JM4
    I am currently implementing a credit card processing script, most as provided by the merchant gateway. The code calls functions within a class and returns a string based on the response. The end php code I am using (details removed of course) with example information is: <?php $gw = new gwapi; $gw->setLogin("username", "password"); $gw->setBilling("John","Smith","Acme, Inc.","888","Suite 200", "Beverly Hills", "CA","77777","US","555-555-5555","555-555-5556","[email protected]", "www.example.com"); // "CA","90210","US","[email protected]"); $gw->setOrder("1234","Big Order",1, 2, "PO1234","65.192.14.10"); $r = $gw->doSale("1.00","4111111111111111","1010"); print $gw->responses['responsetext']; ?> where setlogin allows me to login, setbilling takes the sample consumer information, set order takes the order id and description, dosale takes the amount charged, cc number and exp date. when all the variables are sent validated then sent off for processing, a string is returned in the following format: response=1&responsetext=SUCCESS&authcode=123456&transactionid=23456&avsresponse=M&orderid=&type=sale&response_code=100 where: response = transaction approved or declined response text = textual response authcode = transaction authorization code transactionid = payment gateway tran id avsresponse = avs response code orderid = original order id passed in tran request response_code = numeric mapping of processor response I am trying to solve for the following: How do I take the data which is passed back and display it appropriately on the page - If the transaction failed or AVS code doesnt match my liking or something is wrong, an error is displayed to the consumer; if the transaction processed, they are taken to a completion page and the transaction id is sent in SESSION as output to the consumer If the response_code value matches a table of values, certain actions are taken, i.e. if code =100, take to success page, if code = 300 print specific error on original page to customer, etc.

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  • A problem of a repeated parameter in the pagination links?

    - by myaccount
    The problem is that when I load page 2 for example the URL becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2 And that's fine but when I get to page 3 it becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2&currentpage=3 And so on, it adds one more currentpage parameter everytime a new page is loaded from the pagination links! I wonder how this problem can be fixed? Here's some of the pagination function's code /****** build the pagination links ******/ // Getting current page URL with its parameters $current_page_url = ($_SERVER["PHP_SELF"].(isset($_SERVER["QUERY_STRING"])?"?".htmlentities($_SERVER["QUERY_STRING"]):"")); // Determine which sign to use (? or &) before the (currentpage=xx) parameter $sign = preg_match('/\?/', $current_page_url) ? '&' : '?'; $pagination_links = ''; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=1'>First page</a> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back 1 page $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=$prevpage'>previous</a> "; } else { $pagination_links .= "? ?"; }// end if

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  • Simple iOS Get Request Not Pulling in Data

    - by user2793987
    I have a very simple get request that doesn't return data on my script. The script is fine when viewed in the web browser but the app does not pull in the data. Any other script works with this code in the app. I'm unsure of what to do because there shouldn't be a reason for this to not work. Please let me know if you need more information. Here's the script: https://shipstudent.com/complaint_desk/similarPosts.php?username=noah //retrieve saved username from user defaults (it's noah) NSUserDefaults *eUser = [NSUserDefaults standardUserDefaults]; savedUser = [eUser objectForKey:@"user"]; NSLog(@"%@",savedUser); in ViewDidLoad: NSString *categoryParam = [NSString stringWithFormat:@"https://shipstudent.com/complaint_desk/similarPosts.php?username=%@", savedUser]; NSURL *url = [NSURL URLWithString:categoryParam]; NSMutableURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLCacheStorageAllowed timeoutInterval:30.0]; NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; if (connection==nil) { NSLog(@"Invalid request"); } -(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { postData = [[NSMutableData alloc]init]; NSLog(@"Response received"); } -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [postData appendData:data]; NSLog(@"Data received"); } -(void)connectionDidFinishLoading:(NSURLConnection *)connection { [UIApplication sharedApplication].networkActivityIndicatorVisible = NO; similarPosts = [NSJSONSerialization JSONObjectWithData:postData options:kNilOptions error:nil]; [postsTbl reloadData]; for (id postObject in similarPosts) { NSLog(@"Relatable Post: %@",postObject); } }

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  • How to current snapshot of MySQL Table and store it into CSV file(after creating it) ?

    - by Rachel
    I have large database table, approximately 5GB, now I wan to getCurrentSnapshot of Database using "Select * from MyTableName", am using PDO in PHP to interact with Database. So preparing a query and then executing it // Execute the prepared query $result->execute(); $resultCollection = $result->fetchAll(PDO::FETCH_ASSOC); is not an efficient way as lots of memory is being user for storing into the associative array data which is approximately, 5GB. My final goal is to collect data returned by Select query into an CSV file and put CSV file at an FTP Location from where Client can get it. Other Option I thought was to do: SELECT * INTO OUTFILE "c:/mydata.csv" FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY "\n" FROM my_table; But I am not sure if this would work as I have cron that initiates the complete process and we do not have an csv file, so basically for this approach, PHP Scripts will have to create an CSV file. Do a Select query on the database. Store the select query result into the CSV file. What would be the best or efficient way to do this kind of task ? Any Suggestions !!!

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  • Silverstripe: outputting DataObjectManager in template include

    - by Fraser
    I have followed the tutorial here http://doc.silverstripe.org/old/modules:dataobjectmanager to create a dataobjectmanager in my CMS. It's all working perfectly there however I am having an issue getting it to output in the template. My code is as follows <?php class InfoArea extends DataObject{ static $db = array( 'Title' => 'Varchar(255)', 'Content' => 'HTMLText' ); static $has_one = array( 'ResortPage' => 'ResortPage' ); public function getCMSFields_forPopup(){ return new FieldSet( new TextField('Title'), new SimpleTinyMCEField('Content') ); } } ResortPage.php ....... static $has_many = array ( "InfoAreas" => "InfoArea" ); ....... $fields->addFieldToTab("Root.Content.AdditionalInformation", new DataObjectManager( $this, 'InfoAreas', 'InfoArea', array('Title' => 'Title','Content'=>'Content'), 'getCMSFields_forPopup' )); ........ I have a template "ResortPage.ss" which has an include "ResortInfo.ss". It is from within this include file that I need to output the DataObject. I have tried the below but it doesn't output anything <% control InfoArea %> $Title $Content <% end_control %> What am I doing wrong here? Thanks

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  • can't upload greater 50MB

    - by Syom
    i want to upload two files. here is the script <? ini_set('memory_limit', "400M"); ini_set('file_uploads', "5"); ini_set('max_execution_time', "900"); ini_set('upload_max_filesize', "400M"); ini_set('post_max_size', "400M"); ?> <form action="form.php" method="post" enctype="multipart/form-data" /> <input type="file" name="video" /> <input type="file" name="picture" > <input type="submit" class="input" value="?????" /> </form> form.php: <? ini_set('memory_limit', "400M"); ini_set('file_uploads', "5"); ini_set('max_execution_time', "900"); ini_set('upload_max_filesize', "400M"); ini_set('post_max_size', "400M"); print_r($_FILES); //returns Array ( ) ?> i've asked about this question here , and i've set ini_set(...) as you see, but when i try to upload the file greater than 50MB, it doesn't happen. could you tell me why?

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  • How to create several records in only one dynamic form?

    - by Fernando
    Hi experts, please help me with a simple PHP doubt. I have a simple form: < form action="foo" Person: < a href="javascript:addmore();"Add More < /form Every time the user clicks Add More two new input fields will be dynamically created using jQuery. This can be done several times in a same form. < form action="foo" Person: < a href="javascript:addmore();"Add More < /form Each pair (name and last_name) should create on record in my db. Two Questions: 1) What is the best option for input id? Appending a counter is the best option? 2) How can I handle it in the backend using php? Let me know if you need more info. Thanks in advance.

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  • submit in html on sql query

    - by user1644661
    i need to run this sql query , which give me a list of Id and Dates i want to click each result and take with me the Id value to the next form i wrote this query above but i see in the debager that the hidden ID get his value but not pass to the next form i think i have a problem with the submit() . where should i put him ? thanks anat function ShowAllCarts($user_email) { $connB = new ProductDAO(); $connB->Connect(); $pro_query = "SELECT * FROM Cart WHERE `Email`='$user_email';"; $db_result = $connB->ExecSQL($pro_query); $html_result = '<div data-role="content"> <ul data-role="listview" data-theme="b"> '; $html_result .= '<form action="PreviouscartProduct.php" method="POST"/>'; while($row_array = $db_result->fetch_array(MYSQLI_ASSOC)) { $Id= $row_array['Id']; $Date= $row_array['Date']; //$html_result // $html_result .="<li><a href='PreviouscartProduct.php'>Cart number: $Id from Date: $Date><input type='hidden' name='Id' value'<?=$Id?>'</input></a></li>'"; $html_result .= '<a onclick="this.form.submit();" </a>; } $html_result .= ' </ul> </div>'; $html_result .= '</form>'; $connB->Disconnect(); return $html_result; } //display all carts $func_result = ShowAllCarts($Email);

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  • Unexpected '{' with IF statement

    - by user1926208
    this is my code to move all the files in a directory to another directory which are 1 hour old or more. <?php $srcDir = 'code'; $destDir = 'code/old'; if (file_exists($destDir)) { if (is_dir($destDir)) { if (is_writable($destDir)) { if ($handle = opendir($srcDir)) { while (false !== ($file = readdir($handle))) { if (is_file($srcDir . '/' . $file)) { if(date("U",filectime($srcDir . '/' . $file) >= time() - 3600) { rename($srcDir . '/' . $file, $destDir . '/' . $file); } } } closedir($handle); } else { echo "$srcDir could not be opened.\n"; } } else { echo "$destDir is not writable!\n"; } } else { echo "$destDir is not a directory!\n"; } } else { echo "$destDir does not exist\n"; } ?> and I am getting this error: Parse error: syntax error, unexpected '{' in /home/tcity/public_html/myDir/movefiles.php on line 11

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  • Variable wont echo

    - by jonnnnnnnnnie
    I have the following code, where the var $username doesn't echo, when you type in a value. //TODO: SET AUTH TOKEN as random hash, save in session $auth_token = rand(); if (isset($_POST['action']) && $_POST['action'] == 'Login') { $errors = array(); //USED TO BUILD UP ARRAY OF ERRORS WHICH ARE THEN ECHOED $username = $_POST['username']; if ($username = '') { $errors['username'] = 'Username is required'; } echo $username; // var_dump($username) returns string 0 } require_once 'login_form.html.php'; ?> login_form is this: <form method="POST" action=""> <input type="hidden" name="auth_token" value="<?php echo $auth_token ?>"> Username: <input type="text" name="username"> Password: <input type="password" name="password1"> <input type="submit" name="action" value="Login"> </form> The auth token part isn't important, it just when I type in a value in username textbox and press the login button, the username wont echo, var_dump returns string (0) and print_r is just blank.

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  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

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