Search Results

Search found 3931 results on 158 pages for 'peter friend'.

Page 63/158 | < Previous Page | 59 60 61 62 63 64 65 66 67 68 69 70  | Next Page >

  • Can a user connect to my web site using an Orkut account ? Like Facebook Connect but for Orkut

    - by preguntón
    Can a user connect to my web site using an Orkut account ? Just like Google Friend Connect or Facebook, but with Orkut. The idea is, the user goes to my web site, I have a "Connect using Orkut" button there, on click takes him to the Orkut login page, once s/he logins and grants access to my app, get's redirected to my web site with the Orkut ID as a parameter. The same procedure that works for Google Friend Connect and also Facebook Connect.... I haven't seen an example of this with Orkut. Can it be done ? Is there an Orkut Connect or similar ? If there is one such example could you please give me a link to it ? A sample in c# would be excellent, but I would be happy with a sample in any language. Any help will be appreciated

    Read the article

  • Can Microsoft store three-valued fields in a single bit?

    - by fenomas
    I'm completely ignorant of SQL/databases, but I was chatting with a friend who does a lot of database work about how some databases use a "boolean" field that can take a value of NULL in addition to true and false. Regarding this, he made a comment along these lines: "To Microsoft's credit, they have never referred to that kind of field as a boolean, they just call it a bit. And it's a true bit - if you have eight or fewer bit fields in a record, it only requires one byte to store them all." Naturally that seems impossible to me - if the field can hold three values you're not going to fit eight of them into a byte. My friend agreed that it seemed odd, but begged ignorance of the low-level internals and said that so far as he knew, such fields can hold three values when viewed from the SQL side, and it does work out to require a byte of storage. I imagine one of us has a wire crossed. Can anyone explain what's really going on here?

    Read the article

  • Google App Engine and Git best practices

    - by systempuntoout
    I'm developing a small pet project on Google App Engine and i would like to keep code under source control using github; this will allow a friend of mine to checkout and modify the sources. I just have a directory with all sources (call it PetProject) and Google App Engine development server points to that directory. Is it correct to create a repo directly from PetProject directory or is it preferable to create a second directory mirroring the develop PetProject directory? In the latter case, anytime my friend will release something new, i need to pull fetch from Git copying the modified files to the develop PetProject directory. If i decide to keep the repo inside the develop directory, skipping .git on Gae yaml is enough? What are the best practices here?

    Read the article

  • servlet resopnse data for autocomplete

    - by shams haque
    Hello experts, Following code is in php. i want to do same in java. Please tell me how do i generate this type of array or collection in java. I need this to response to json autocomplete. <?php $q = strtolower($_GET["q"]); if (!$q) return; $items = array( "Peter Pan"=>"[email protected]", "Molly"=>"[email protected]", "Forneria Marconi"=>"[email protected]", "Master Sync"=>"[email protected]", "Dr. Tech de Log"=>"[email protected]", "Don Corleone"=>"[email protected]", "Mc Chick"=>"[email protected]", "Donnie Darko"=>"[email protected]", "Quake The Net"=>"[email protected]", "Dr. Write"=>"[email protected]" ); $result = array(); foreach ($items as $key=>$value) { if (strpos(strtolower($key), $q) !== false) { array_push($result, array( "name" => $key, "to" => $value )); } } echo json_encode($result); ?>

    Read the article

  • please help me in this query

    - by testkhan
    I have three tables (user, friends, posts) and two users (user1 and user2). When user1 adds user2 as friend then user1 can see the posts of user2 just like on Facebook. But only the posts after the date when user1 added user2 as friend. My query is like this: $sql = mysql_query("SELECT * FROM posts p JOIN friends f ON p.currentuserid = f.friendid AND p.time >= f.friend_since OR p.currentuserid='user1id' WHERE f.myid='user1id' ORDER BY p.postid DESC LIMIT 20"); it is working all the way fine but with a little problem.....!! it displays user2, user3 (all the users as friends of user1) posts for single time but shows user1 posts multiple.......i.e user2. hi user1. userssfsfsfsfsdf user1. userssfsfsfsfsdf user3. dddddddd user1. sdfsdsdfsdsfsf user1. sdfsdsdfsdsfsf but i in database it is single entry/post why it is happening........!! How can I fix it?

    Read the article

  • Source control on internet i.e. no private networks.

    - by Kavitesh Singh
    Me and my friend are in the process of starting a small project and want to implement a source control. Now both are located in different cities and can communicate using internet for file sharing etc. I need an online hosting solution or any way where i can maintain the source code repository for both of us to check in/out. As of now we want to maintain it as private project. Does sourceforge allow hosting projects which would not be opensource? One option i was thinking, to obtain a static IP form ISP and host the repository.But that mean my system needs to be online when my friend wants to checkin/out or do some diff with old version code. Secondly, would SVN or git be a better choice in such a situation. I have no experience in git/mercurial as of now.

    Read the article

  • How Does One Make Scala Control Abstraction in Repeat Until?

    - by peter_pilgrim
    Hi I am Peter Pilgrim. I watched Martin Odersky create a control abstraction in Scala. However I can not yet seem to repeat it inside IntelliJ IDEA 9. Is it the IDE? package demo class Control { def repeatLoop ( body: = Unit ) = new Until( body ) class Until( body: = Unit ) { def until( cond: = Boolean ) { body; val value: Boolean = cond; println("value="+value) if ( value ) repeatLoop(body).until(cond) // if (cond) until(cond) } } def doTest2(): Unit = { var y: Int = 1 println("testing ... repeatUntil() control structure") repeatLoop { println("found y="+y) y = y + 1 } { until ( y < 10 ) } } } The error message reads: Information:Compilation completed with 1 error and 0 warnings Information:1 error Information:0 warnings C:\Users\Peter\IdeaProjects\HelloWord\src\demo\Control.scala Error:Error:line (57)error: Control.this.repeatLoop({ scala.this.Predef.println("found y=".+(y)); y = y.+(1) }) of type Control.this.Until does not take parameters repeatLoop { In the curried function the body can be thought to return an expression (the value of y+1) however the declaration body parameter of repeatUntil clearly says this can be ignored or not? What does the error mean?

    Read the article

  • Error while sending message using xmpp4r_facebook

    - by santu
    I am following the instructions presented in http://dalibornasevic.com/posts/35-how-to-send-private-messages-with-facebook-api to send message to my friend and currently testing from command line. Following is the code I am using require 'xmpp4r_facebook' id = '<my facebook id>@chat.facebook.com' to = '<my friend facebook id>@chat.facebook.com' body = "hello, Im not spam!" subject = 'message from ruby' message = Jabber::Message.new to, body message.subject = subject client = Jabber::Client.new Jabber::JID.new(id) client.connect client.auth_sasl(Jabber::SASL::XFacebookPlatform.new(client, '<App ID>', '<access token got from https://developers.facebook.com/tools/explorer>', 'App Secret'), nil) I get the error RuntimeError: not-authorized from /Users/apple/.rvm/gems/ruby-1.9.3-p194/gems/xmpp4r_facebook-0.1.1/lib/xmpp4r_facebook.rb:103:in `auth' from /Users/apple/.rvm/gems/ruby-1.9.3-p194/gems/xmpp4r-0.5/lib/xmpp4r/client.rb:171:in `auth_sasl' from (irb):12 from /Users/apple/.rvm/rubies/ruby-1.9.3-p194/bin/irb:16:in `<main>'

    Read the article

  • Api/plugins for open source libraries?

    - by fayer
    whenever i use a open source library eg. Doctrine i always ending up coding a class (so called Facade) to use the Doctrine library. so next time i want to create a user i just type: $fields = array('name' => 'peter', 'email' => '[email protected]'); Doctrine_Facade::create_entity($entity, $fields); then it creates an entity with the provided information. so i guess, all coders will create their own "Facade". i wonder how usual it is with open source Facades to download and interact with the open source libraries? is this rare cause i haven't seen any of these. in some frameworks i have seen them called plugins, eg. plugins for twitter api or facebook api. so whenever you download a library, should you search for plugins/facades on the net, or is it better to just try coding your own? i just thought it would be great for everyone not to reinvent the wheel. thanks.

    Read the article

  • Binary search of unaccesible data field in ldap from python

    - by EricR
    I'm interested in reproducing a particular python script. I have a friend who was accessing an ldap database, without authentication. There was a particular field of interest, we'll call it nin (an integer) for reference, and this field wasn't accessible without proper authentication. However, my friend managed to access this field through some sort of binary search (rather than just looping through integers) on the data; he would check the first digit, check if it was greater or less than the starting value, he would augment that until it returned a true value indicating existence, adding digits and continuing checking until he found the exact value of the integer nin. Any ideas on how he went about this? I've access to a similarly set up database.

    Read the article

  • Git Specify Remote Source Durring Push

    - by ThinkBohemian
    I have a local git repository a "central" repo at github. I'm working on a part of a project, while a friend is working on a related piece that is its entirely seperate repo, is it possible for me to simply link directly to my friends repo? For example, the app is called widgets. I have all my code in widgets/app/mycode and my friend is writing code that goes into widgets/plugins/awesome/hiscode. I want to be able to always have http://github.com/mycode/widgets/plugins/hiscode to be a direct link or clone to http://github.com/hiscode/awesome ? It could be possible i'm missing something basic in my question or knowledge of git, if so please ask, and i'll be happy to try to fill in the blanks.

    Read the article

  • Best practice for Google app engine and Git.

    - by systempuntoout
    I'm developing a small pet project on Google App Engine and i would like to keep code under source control using github; this will allow a friend of mine to checkout and modify the sources. I just have a directory with all sources (call it PetProject) and Google App Engine development server points to that directory. Is it correct to create a Repo directly from PetProject directory or is it preferable to create a second directory (mirror of the develop PetProject directory); in this case, anytime my friend will release something new, i need to pull from Git and then copy the modified files to the develop PetProject directory. If i decide to keep the Repo inside the develop directory, skippin .git on yaml is enough? What's the best practice here?

    Read the article

  • Join two list comparing their elements properties

    - by 100r
    public class Person() { int ID; string Name; DateTime ChangeDate } var list1 = new List<Person> { new Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" }, new Person { ID= 2, Name = "John", ChangeDate= "2011-10-22" }, new Person { ID= 3, Name = "Mike", ChangeDate= "2011-10-23" }, new Person { ID= 4, Name = "Dave", ChangeDate= "2011-10-24" } }; var list2 = new List<Person> { new Person { ID= 1, Name = "Pete", ChangeDate= "2011-10-21" }, new Person { ID= 2, Name = "Johny", ChangeDate= "2011-10-20" }, new Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" }, new Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" } }; As output I would like to have list1 + list2 = Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" }, Person { ID= 2, Name = "John", ChangeDate= "2011-10-22" }, Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" }, Person { ID= 4, Name = "Dave", ChangeDate= "2011-10-24" } Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" } And the Algorithm is like this. Join two list. If elements of lists have same ID, compare them by ChangeDate and take the ond with bigger date. If ChangeDate are equeal take any of them but not both. Maybe its easier to concat both lists and than to filter them with lambda. I tried, but always came out with some ugly code :/ Anyone have any idea?

    Read the article

  • Interview question: Check if one string is a rotation of other string.

    - by Webdev
    A friend of mine was asked the following question today at interview for the position of software developer. Given two string s1 and s2 how will you check if s1 is a rotated version of s2 ? Example: if s1 = "stackoverflow"; then the following are some of its rotated versions: "tackoverflows" "ackoverflowst" "overflowstack" where as "stackoverflwo" is not a rotated version. The answer he gave was: Take s2 and find the logest prefix that is a substring of s1, that will give you the point of rotation. Once you find that point, break s2 at that point to get s2a and s2b, then just check if concatenate(s2a,s2b) == s1 It looks like a good solution to me and my friend. But the interviewr though otherwise. He asked for a simpler solution. Please help me by telling how would you do this in Java/C/C++ ? Thanks in advance.

    Read the article

  • How to plan my web based project before starting code ?

    - by Arsheep
    Me and my friend started working together as partners , we have decided to make Kick-as* website after website. We have the ideas written down like 100's of them (yes we are choosing best and easy among them first). My friend does the layout design and arranging things , and my part is coding and server management. The little problem i am facing is lack of experience in planing a project. What i do is, I just start the code straight away and along with code I make DB, like when i need a table i make it. I know this is very bad approach for a medium sized project. Here at stackoverflow i saw lots of experienced coders. Need to learn a lot from you guys :) . So can you plese help me on how to plan a project and what coding standard/structure/frameworks to be used (I do PHP code). Thanks in advance.

    Read the article

  • colorbox not displaying first caption from flickr gallery integration

    - by Mark
    I am pulling small thumbnails into my page from the flickr API, and using Colorbox to display larger thumbnails and captions from the title attribute. Using the API with C#. However, on the first instance of opening colorbox it does not display the caption from the anchors title attribute. If you click next or previous then it appears. The actual caption is physically there in the source code, just not getting put into the colorbox window. Demo here, if you click on a thumbnail you will see there is no caption, click next then prev and it will appear. Here's the code: <script type="text/javascript"> $(function() { $("a[rel='group']").colorbox({ opacity: 0.75 }); }); </script> <a href='http://farm6.static.flickr.com/5015/5511378425_e63d4a62f7.jpg' title='Little Hermit (Peter Dunn)' rel='group' class='tooltip'> <img src='http://farm6.static.flickr.com/5015/5511378425_e63d4a62f7_s.jpg' alt='Little Hermit (Peter Dunn)' /> </a> If i view source, the title attribute is populated with the caption, but if i ook in firebug it is not in the colorbox code. Any help on this would be great Ive ran out of ideas!

    Read the article

  • PHP Longtext to display like the user wrote it

    - by yanike
    I need to know how to display information put in a database longtext field the way it was written. Like if a user writes in this below: My life is full of love I fly like wedding doves I blow passed stop signs That intersect with hate lines - I know what I am I know who I be If you can't accept me Then don't friend me I want it to display the text from the database just like the user wrote it in the textarea instead of it displaying in one like this: My life is full of love I fly like wedding doves I blow passed stop signs That intersect with hate lines I know what I am I know who I be If you can't accept me Then don't friend me How can I could it in PHP to display the information properly using PHP?

    Read the article

  • From me friends, know who is already using the app

    - by Toni Michel Caubet
    I got working to get all friends from 'me' user, like this: FB.api('/me/friends?fields=id,name,updated_time&date_format=U&<?=$access_token?>', {limit:3, function(response){ console.log('Friend name: '+response.data[0].name); } ); But i need to get if the user is in the app already or not, how can I alter the query to get an extra row in the object 'is_in_app' true/false? FB.api('/me/friends?fields=id,name,updated_time&date_format=U&<?=$access_token?>', {limit:3, function(response){ var text = 'is not in app'; if(response.data[0].is_in_app == true) text = 'is in app!!'; console.log('Friend name: '+response.data[0].name + ' ' + text); } ); How can i achieve this?

    Read the article

  • How can I explain to a programmer that CSS positioning has many benefits over table based layouts?

    - by Pat
    I have a friend who wishes to work as a freelance web developer, but insists that tables are the way forwards for layouts. Several points he maintains in favour of tables: 1 This is what was taught at the beginning of 10 years of programming & computer science degrees. 2 Large companies use tables to achieve 'technical' things. 3 It saves time I have coded him some examples of CSS exactly matching table based layouts, and provided many links to articles explaining SEO and accessibility benefits. From the perspective of a client, I have been explaining to him that I wouldn't hire someone using outdated methods as their main strategy for layout. As he is my friend and I wish him every success, I believe it is important for him to gain the best start when pitching for work. The question again: How can I explain to a programmer that CSS positioning has many benefits over table based layouts?

    Read the article

  • how to cout a vector of structs (that's a class member, using extraction operator)

    - by Julz
    hi, i'm trying to simply cout the elements of a vector using an overloaded extraction operator. the vector contians Point, which is just a struct containing two doubles. the vector is a private member of a class called Polygon, so heres my Point.h #ifndef POINT_H #define POINT_H #include <iostream> #include <string> #include <sstream> struct Point { double x; double y; //constructor Point() { x = 0.0; y = 0.0; } friend std::istream& operator >>(std::istream& stream, Point &p) { stream >> std::ws; stream >> p.x; stream >> p.y; return stream; } friend std::ostream& operator << (std::ostream& stream, Point &p) { stream << p.x << p.y; return stream; } }; #endif my Polygon.h #ifndef POLYGON_H #define POLYGON_H #include "Segment.h" #include <vector> class Polygon { //insertion operator needs work friend std::istream & operator >> (std::istream &inStream, Polygon &vertStr); // extraction operator friend std::ostream & operator << (std::ostream &outStream, const Polygon &vertStr); public: //Constructor Polygon(const std::vector<Point> &theVerts); //Default Constructor Polygon(); //Copy Constructor Polygon(const Polygon &polyCopy); //Accessor/Modifier methods inline std::vector<Point> getVector() const {return vertices;} //Return number of Vector elements inline int sizeOfVect() const {return vertices.size();} //add Point elements to vector inline void setVertices(const Point &theVerts){vertices.push_back (theVerts);} private: std::vector<Point> vertices; }; and Polygon.cc using namespace std; #include "Polygon.h" // Constructor Polygon::Polygon(const vector<Point> &theVerts) { vertices = theVerts; } //Default Constructor Polygon::Polygon(){} istream & operator >> (istream &inStream, Polygon::Polygon &vertStr) { inStream >> ws; inStream >> vertStr; return inStream; } // extraction operator ostream & operator << (ostream &outStream, const Polygon::Polygon &vertStr) { outStream << vertStr.vertices << endl; return outStream; } i figure my Point insertion/extraction is right, i can insert and cout using it and i figure i should be able to just...... cout << myPoly[i] << endl; in my driver? (in a loop) or even... cout << myPoly[0] << endl; without a loop? i've tried all sorts of myPoly.at[i]; myPoly.vertices[i]; etc etc also tried all veriations in my extraction function outStream << vertStr.vertices[i] << endl; within loops, etc etc. when i just create a... vector<Point> myVect; in my driver i can just... cout << myVect.at(i) << endl; no problems. tried to find an answer for days, really lost and not through lack of trying!!! thanks in advance for any help. please excuse my lack of comments and formatting also there's bits and pieces missing but i really just need an answer to this problem thanks again

    Read the article

  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

    Read the article

  • SEO google keyword position tools?

    - by Peterl86
    Hi guys, I want to check our google postions for several keywords every day and make a note in a spreadseet. At the moment, we have a student doing it but it's a rubbish job and it doesn't seem fair on them! Are there any tools available to automate this process? I have tried rankchecker by seobook.com, but although that should be exactly what im looking for when i set scheduled tasks in that, it doesnt work. Any tips would be appreciated, thanks! peter EDIT: Liam has suggested a Python script to do this, which unfortunately isnt something I'm very familiar with! If anyone knows of a good tutorial or something to help us with this, that would be brilliant. Update: Found a php script at seoscript.net which looks like a step in the right direction. But I cant get it to work! I get this error. Anyone more knowledgabe than me know how to fix that? I have PEAR installed. thanks again, Peter

    Read the article

  • how to facebook shoutbox open , with clicked friendname

    - by Surendra Singh
    Hey everyone i need source code for shotbox open with clicked friend name like facebook i tried it but ... it is opening with only one friend name .... i want it will open with the name of friend whom name or image is clicked My code is something like this <tr data-name="<?php echo $online_user_name; ?>"> <td> <div <?php echo $online_user_id; ?>"> <img src="../../social_users/<?php echo $online_user_gender; ?>/<?php echo $online_user_Email; ?>/Profile/<?php echo $online_user_pic; ?>" height="30" width="30" style="border-radius: 20px; border: 2px solid #fff;" onclick="shoutbox_open();"> </div> </td> <td style="color:#ffffff;"> <div <?php echo $online_user_id; ?> style="text-transform:capitalize; text-decoration:none; color:#6A7480;" onclick="shoutbox_open();"> <?php echo $online_user_name; ?> </div> &nbsp; </td> <td> <img src="background_file/background_icons/online_symbol.png" /> </td> </tr> <div id="shout_box"> <div id="header" > <span> <?php echo $online_user_name; ?> </span> <div id="close_btn" onclick="shoutbox_close();"> &nbsp; </div> </div> <div id="toggle_chat"> <div id="message_box"> </div> <div id="user_info"> <input name="shout_username" id="shout_username" type="text" placeholder="Your Name" value="" maxlength="15" /> <input name="shout_message" id="shout_message" type="text" placeholder="Type Message Hit Enter" maxlength="100" /> </div> </div> </div>

    Read the article

  • jQuery works in FF but not in Safari

    - by Hristo
    I have some event handlers that work in FF and not in Safari. Simply put, I have a list of friends, some hard-coded, some pulled in from a database. Clicking on a buddy opens a chat window... this is much like the Facebook chat system. So in Firefox, everything works normally and as expected. In Safari, clicking on buddies that are hard-coded works fine, but clicking on buddies that are pulled in from the database doesn't pull up the chat window. <script type="text/javascript" src="js/jQuery.js"></script> <script type="text/javascript" src="js/chat.js"></script> <script type="text/javascript" src="js/ChatBar.js"></script> <script type="text/javascript" src="js/settings.js"></script> <script type="text/javascript"> var chat = new Chat(); var from = <?php echo "'" .$_SESSION['userid'] . "'"; ?>; chat.getUsers(<?php echo "'" .$_SESSION['userid'] . "'"; ?>); </script> So I load all my buddies with chat.getUsers. That function is: // get list of friends function getBuddyList(userName) { userNameID = userName; $.ajax({ type: "GET", url: "buddyList.php", data: { 'userName': userName, 'current': numOfUsers }, dataType: "json", cache: false, success: function(data) { if (numOfUsers != data.numOfUsers) { numOfUsers = data.numOfUsers; var list = "<li><span>Agents</span></li>"; for (var i = 0; i < data.friendlist.length; i++) { list += "<li><a class=\"buddy\" href=\"#\"><img alt=\"\" src=\"images/chat-thumb.gif\">"+ data.friendlist[i] +"</a></li>"; } $('#friend-list ul').append($(list)); } setTimeout('getBuddyList(userNameID)', 1000); } }); } buddyList.php just pulls in the Users from the database and returns an array with the user names. So the jQuery for clicking a buddy is: // click on buddy in #friends-panel $('#friends-panel a.buddy').click(function() { alert("Loaded"); // close #friends-panel $('.subpanel').hide(); $('#friends-panel a.chat').removeClass('active'); // if a chat window is already active, close it and deactivate $('#mainpanel li[class="active-buddy-tab"] div').not('#chat-box').removeAttr('id'); $('#mainpanel li[class="active-buddy-tab"]').removeClass('active-buddy-tab').addClass('buddy-tab'); // create active buddy chat window $('#mainpanel').append('<li class="active-buddy-tab"><a class="buddy-tab" href="#"></a><div id="chat-window"><h3><p id="to"></p></h3></div></li>'); // create name and close/minimize buttons $('.active-buddy-tab div h3 p#to').text($(this).text()); $('.active-buddy-tab div h3').append('<span class="close"> X </span><span class="minimize"> &ndash; </span>'); $('.active-buddy-tab').append('<span class="close"> X </span>'); // create chat area $('.active-buddy-tab div').append('<div id="chat-box"></div><form id="chat-message"><textarea id="message" maxlength="100"></textarea></form>'); // put curser in chat window $('.active-buddy-tab #message').focus(); // create a chat relationship return false; }); ... and the basic structure of the HTML is: <div id="footpanel"> <ul id="mainpanel"> <li id="friends-panel"> <a href="#" class="chat">Friends (<strong>18</strong>) </a> <div id="friend-list" class="subpanel"> <h3><span> &ndash; </span>Friends Online</h3> <ul> <li><span>Family Members</span></li> <!-- Hard coded buddies --> <li><a href="#" class="buddy"><img src="images/chat-thumb.gif" alt="" /> Your Friend 1</a></li> <li><a href="#" class="buddy"><img src="images/chat-thumb.gif" alt="" /> Your Friend </a></li> <!-- buddies will be added in dynamically here --> </ul> </div> </li> </ul> </div> I'm not too sure where to begin solving this issue. I thought it might be a rendering bug or something with the DOM but I've been staring at this code all day and I'm stuck. Any ideas on why it works in FF and not in Safari? btw... I'm testing on Snow Leopard. Thanks, Hristo

    Read the article

< Previous Page | 59 60 61 62 63 64 65 66 67 68 69 70  | Next Page >