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  • MySQL left outer join is slow

    - by Ryan Doherty
    Hi, hoping to get some help with this query, I've worked at it for a while now and can't get it any faster: SELECT date, count(id) as 'visits' FROM dates LEFT OUTER JOIN visits ON (dates.date = DATE(visits.start) and account_id = 40 ) WHERE date >= '2010-12-13' AND date <= '2011-1-13' GROUP BY date ORDER BY date ASC That query takes about 8 seconds to run. I've added indexes on dates.date, visits.start, visits.account_id and visits.start+visits.account_id and can't get it to run any faster. Table structure (only showing relevant columns in visit table): create table visits ( `id` int(11) NOT NULL AUTO_INCREMENT, `account_id` int(11) NOT NULL, `start` DATETIME NOT NULL, `end` DATETIME NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; CREATE TABLE `dates` ( `date` date NOT NULL, PRIMARY KEY (`date`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; dates table contains all days from 2010-1-1 to 2020-1-1 (~3k rows). visits table contains about 400k rows dating from 2010-6-1 to yesterday. I'm using the date table so the join will return 0 visits for days there were no visits. Results I want for reference: +------------+--------+ | date | visits | +------------+--------+ | 2010-12-13 | 301 | | 2010-12-14 | 356 | | 2010-12-15 | 423 | | 2010-12-16 | 332 | | 2010-12-17 | 346 | | 2010-12-18 | 226 | | 2010-12-19 | 213 | | 2010-12-20 | 311 | | 2010-12-21 | 273 | | 2010-12-22 | 286 | | 2010-12-23 | 241 | | 2010-12-24 | 149 | | 2010-12-25 | 102 | | 2010-12-26 | 174 | | 2010-12-27 | 258 | | 2010-12-28 | 348 | | 2010-12-29 | 392 | | 2010-12-30 | 395 | | 2010-12-31 | 278 | | 2011-01-01 | 241 | | 2011-01-02 | 295 | | 2011-01-03 | 369 | | 2011-01-04 | 438 | | 2011-01-05 | 393 | | 2011-01-06 | 368 | | 2011-01-07 | 435 | | 2011-01-08 | 313 | | 2011-01-09 | 250 | | 2011-01-10 | 345 | | 2011-01-11 | 387 | | 2011-01-12 | 0 | | 2011-01-13 | 0 | +------------+--------+ Thanks in advance for any help!

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  • In PHP + MySQL, How do I join many tables with conditions

    - by Moe
    Hi, I'm trying to get the users full activity throughout the website. I need to Join many tables throughout the database, with that condition that it is one user. What I currently have written is: SELECT * FROM comments AS c JOIN rphotos AS r ON c.userID = r.userID AND c.userID = '$defineUserID'; But What it is returning is everything about the user, but it repeats rows. For instance, for one user he has 6 photos and 5 comments So I expect the join to return 11 rows. Instead it returns 30 results like so: PhotoID = 1; CommentID = 1; PhotoID = 1; CommentID = 2; PhotoID = 1; CommentID = 3; and so on... What am i doing wrong?

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  • How to convert X/Y position to Canvas Left/Top properties when using ItemsControl

    - by kshahar
    I am trying to use a Canvas to display objects that have "world" location (rather than "screen" location). The canvas is defined like this: <Canvas Background="AliceBlue"> <ItemsControl Name="myItemsControl" ItemsSource="{Binding MyItems}"> <ItemsControl.ItemTemplate> <DataTemplate> <Canvas> <TextBlock Canvas.Left="{Binding WorldX}" Canvas.Top="{Binding WorldY}" Text="{Binding Text}" Width="Auto" Height="Auto" Foreground="Red" /> </Canvas> </DataTemplate> </ItemsControl.ItemTemplate> </ItemsControl> </Canvas> MyItem is defined like this: public class MyItem { public MyItem(double worldX, double worldY, string text) { WorldX = worldX; WorldY = worldY; Text = text; } public double WorldX { get; set; } public double WorldY { get; set; } public string Text { get; set; } } In addition, I have a method to convert between world and screen coordinates: Point worldToScreen(double worldX, double worldY) { // return screen coordinates using the canvas properties and an internal MapData object } With the current implementation, the items are positioned in the wrong location, because their location is not converted to screen coordinates. How can I apply the worldToScreen method on the MyItem objects before they are added to the canvas?

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  • Align text with right edge of an html form

    - by williamjones
    I have an html form where the width of a textarea is specified with cols=. I want the textarea to have a specific width in terms of number of characters. However, I also want some controls to be right-justified to the right edge of the textarea. They're not in the textarea, but directly above or below it. Is it possible to do this? I was thinking a possible approach might be enclosing the textarea with some type of container that could grow to the width of the textarea, but I'm not sure how I could right-justify text within that.

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  • PHP: Doctrine: order joined records

    - by Sebastian Bechtel
    Hi, I'm new to doctrine: I have a problem with the sorting of joined records. A sample. I've got an Article model which is associated with a Source model in 1 <- n. The source model has a property called 'position' with an integer value. Now I want to fetch an article with it's sources orderes by the position. My DQL looks like this: $q = Doctrine_Query::create() ->select('a.title, s.content') ->from('Article a') ->leftJoin('a.Source s') ->where('a.id = ?') ->orderBy('s.position'); The result doesn't change if I edit the position. Best regards, Sebastian

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  • Program always returns binary '>>' : no operator found which takes a left-hand operand of type error

    - by Tom Ward
    So I've been set a task to create a temperature converter in C++ using this equation: Celsius = (5/9)*(Fahrenheit – 32) and so far I've come up with this (I've cut out the 10 lines worth of comments from the start so the code posted begins on line 11, if that makes any sense) #include <iostream> #include <string> #include <iomanip> #include <cmath> using namespace std; int main () { float celsius; float farenheit; std::cout << "**************************" << endl; std::cout << "*4001COMP-Lab5-Question 1*" << endl; std::cout << "**************************" << endl << endl; std::cout << "Please enter a temperature in farenheit: "; std::cin >> farenheit >> endl; std::cout << "Temperature (farenheit): " << endl; std::cout << "Temperature (celsius): " << celsius << endl; std::cin.get(); return 0; } Everytime I try to run this program I get a heap of errors with this one appearing every time: 1m:\visual studio 2010\projects\week 5\week 5\main.cpp(26): error C2678: binary '' : no operator found which takes a left-hand operand of type 'std::basic_istream<_Elem,_Traits' (or there is no acceptable conversion) I've tried everything I can think of to get rid of this error but it reappears every time, any idea on how to fix this?

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  • The least amount of code possible for this MySQL query?

    - by ddan
    I have a MySQL query that: gets data from three tables linked by unique id's. counts the number of games played in each category, from each user and counts the number of games each user has played that fall under the "fps" category It seems to me that this code could be a lot smaller. How would I go about making this query smaller. http://sqlfiddle.com/#!2/6d211/1 Any help is appreciated even if you just give me links to check out.

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  • differentiating results of sql right join

    - by Sourabh
    Hi I have a below SQL query SELECT `User`.`username` , Permalink.perma_link_id, Permalink.locale, Permalink.title, DATEDIFF( CURDATE( ) , Permalink.created ) AS dtdiff, `TargetSegment`.segment_text, TargetSegment.source_segment_id ,TargetSegment.perma_link_id ,TargetSegment.created ,TargetSegment.updated, DATEDIFF( CURDATE( ) , TargetSegment.updated ) AS datediff FROM `users` AS `User` RIGHT JOIN perma_links AS `PermaLink` ON ( `PermaLink`.`username` = `User`.`username` ) RIGHT JOIN target_segments AS `TargetSegment` ON ( `TargetSegment`.`username` = `User`.`username` ) RIGHT JOIN source_segments AS `SourceSegment` ON ( `SourceSegment`.`source_detail_id` = `PermaLink`.`source_detail_id` ) LEFT JOIN source_details AS `SourceDetail` ON ( `SourceSegment`.`source_detail_id` = `SourceDetail`.`id` ) WHERE `TargetSegment`.`username` = "xxxx" AND `TargetSegment`.`segment_text` <> "" AND `Permalink`.`perma_link_id` = `TargetSegment`.`perma_link_id` AND `TargetSegment`.`source_segment_id` = `SourceSegment`.`id` AND `Permalink`.`source_detail_id` = `SourceDetail`.`id` ORDER BY `TargetSegment`.`updated` DESC LIMIT 0 , 10 This SQL is fetching correct results for me.I want to identify from which table each row if from , to be specific which result is due to PermaLink table and which is from TargetSegment table. is this achievable ?

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  • ordering by a property on a joined table linq to sql

    - by Gazeth
    I have the following linq query from o in context.Opportunities join i in context.Interactions on o.OpportunityID equals i.OpportunityID into ints from i in ints.DefaultIfEmpty() orderby i.StatusID descending, o.StatusID descending select o Now i want to then do a distinct on the opportunities table but doing so removes my orderby. I know that you can do Distinct().OrderBy but how do i get a reference to the interactions table that was joined when I'm only selecting the opportunity entity?

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  • In Ubuntu, how do I change my default Greek font?

    - by Matthew
    I'm taking a course in ancient Greek, and I store notes and flash cards on my computer. However, by default Ubuntu uses a modern Greek font. This changes some noticable things--for example, a circumflex is ? instead of a?. I can type the circumflex by switching back to english and entering the unicode combining character u0311 (which is what I just did to type the second a), but obviously this is very cumbersome. I've installed the "ttf-linex" package from the Ubuntu repositories, which claims to include an ancient Greek font. But I have no idea how to enable this font for whenever I switch to the Greek keyboard layout.

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  • Diferent keyboard layouts at same time for diferent devices

    - by Joao Carlos
    Hello, I have a MacBook Pro running Snow Leopard, and I am using it was a portable but also desktop computer. In order to acheive this, i bought a VGA adapter and I am using it with an external mouse+keyboard+monitor. The problem is, the external keyboard layout is diferent from the one on the macbook. It is set to US qwerty (its a logitech G15), and because of that, most keys behave diferently from what they are supposed to. Question is, how can I set up diferent layouts at same time for diferent devices? I want US for external keyboard and PT for the default one.

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  • Different keyboard layouts at same time for different devices

    - by Joao Carlos
    I have a MacBook Pro running Snow Leopard, and I am using it as a portable but also desktop computer. In order to acheive this, I bought a VGA adapter and I am using it with an external mouse, keyboard, and monitor. The problem is, the external keyboard layout is different from the one on the macbook. It is set to US qwerty (its a logitech G15), and because of that, most keys behave differently than they should. Question is, how can I set up different layouts at same time for different devices? I want US for external keyboard and PT for the default one.

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  • Can't add German as input language in Windows XP

    - by jdm
    I have a laptop that was brought to a computer shop for a hard disk problem. They replaced the disk and reinstalled windows XP, although the English version (the laptop has a German keyboard). I'd like to switch the input language to German. Usually I know how to do this (via "Regional and Language Options"), the problem is when I choose Languages/Details/Add... it doesn't offer me the German keyboard layout: It also uses the "Standard 101/102-Key or Microsoft Natural PS/2 Keyboard" driver - the laptop's keyboard is a 104/105 key German version. I can't seem to change this. Did I just miss the setting, or what is going on here?

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  • Pressing zero key brings up lock/switch user screen in W7

    - by qinghua
    This issue started after my cat walked all over the keyboard... Whenever I press the "zero" key, the screen goes black and I'm taken to the lock/switch user screen. The other functions of the key work fine - it can produce ) and / like usual. Numlock is off, and as far as I know, my computer doesn't have Function Lock. If I log out of my user account and sign in as a guest, the "zero" works again, but if I create a new user profile, it doesn't work. I get the same issue when I hit "zero" using the on-screen keyboard. My keyboard layout is set to US English. I've uninstalled and reinstalled the ATK package, and updated my keyboard drivers. I have an ASUS U43JC-X1 laptop running Windows 7, and I haven't installed any new programs lately.

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  • Haskell: Left-biased/short-circuiting function

    - by user2967411
    Two classes ago, our professor presented to us a Parser module. Here is the code: module Parser (Parser,parser,runParser,satisfy,char,string,many,many1,(+++)) where import Data.Char import Control.Monad import Control.Monad.State type Parser = StateT String [] runParser :: Parser a -> String -> [(a,String)] runParser = runStateT parser :: (String -> [(a,String)]) -> Parser a parser = StateT satisfy :: (Char -> Bool) -> Parser Char satisfy f = parser $ \s -> case s of [] -> [] a:as -> [(a,as) | f a] char :: Char -> Parser Char char = satisfy . (==) alpha,digit :: Parser Char alpha = satisfy isAlpha digit = satisfy isDigit string :: String -> Parser String string = mapM char infixr 5 +++ (+++) :: Parser a -> Parser a -> Parser a (+++) = mplus many, many1 :: Parser a -> Parser [a] many p = return [] +++ many1 p many1 p = liftM2 (:) p (many p) Today he gave us an assignment to introduce "a left-biased, or short-circuiting version of (+++)", called (<++). His hint was for us to consider the original implementation of (+++). When he first introduced +++ to us, this was the code he wrote, which I am going to call the original implementation: infixr 5 +++ (+++) :: Parser a -> Parser a -> Parser a p +++ q = Parser $ \s -> runParser p s ++ runParser q s I have been having tons of trouble since we were introduced to parsing and so it continues. I have tried/am considering two approaches. 1) Use the "original" implementation, as in p +++ q = Parser $ \s - runParser p s ++ runParser q s 2) Use the final implementation, as in (+++) = mplus Here are my questions: 1) The module will not compile if I use the original implementation. The error: Not in scope: data constructor 'Parser'. It compiles fine using (+++) = mplus. What is wrong with using the original implementation that is avoided by using the final implementation? 2) How do I check if the first Parser returns anything? Is something like (not (isNothing (Parser $ \s - runParser p s) on the right track? It seems like it should be easy but I have no idea. 3) Once I figure out how to check if the first Parser returns anything, if I am to base my code on the final implementation, would it be as easy as this?: -- if p returns something then p <++ q = mplus (Parser $ \s -> runParser p s) mzero -- else (<++) = mplus Best, Jeff

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  • Why / how does XNA's right-handed coordinate system effect anything if you can specify near/far Z values?

    - by vargonian
    I am told repeatedly that XNA Game Studio uses a right-handed coordinate system, and I understand the difference between a right-handed and left-handed coordinate system. But given that you can use a method like Matrix.CreateOrthographicOffCenter to create your own custom projection matrix, specifying the left, right, top, bottom, zNear and zFar values, when does XNA's coordinate system come into play? For example, I'm told that in a right-handed coordinate system, increasingly negative Z values go "into" the screen. But I can easily create my projection matrix like this: Matrix.CreateOrthographicOffCenter(left, right, bottom, top, 0.1f, 10000f); I've now specified a lower value for the near Z than the far Z, which, as I understand it, means that positive Z now goes into the screen. I can similarly tweak the values of left/right/top/bottom to achieve similar results. If specifying a lower zNear than zFar value doesn't affect the Z direction of the coordinate system, what does it do? And when is the right-handed coordinate system enforced? The reason I ask is that I'm trying to implement a 2.5D camera that supports zooming and rotation, and I've spent two full days encountering one unexpected result after another.

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  • Force float left with no line break no matter what

    - by Tesserex
    I'm guessing this isn't possible, but here goes. I have two tables, and I'm trying to get them to sit side-by-side so that they look like one table. The reason for this, instead of using one larger table, is that the data in the second table needs to be handled on a column basis, not row basis, for performance reasons like caching and AJAX-fetching data. So rather than have to reload the whole table for a single column, I decided to break the column out into a separate table, but have it visually seem like a single table. I can't find a way to forcibly put the second table next to the first. I can float them, but when the first table is too wide, the second one breaks to the next line. Here's the kicker: the width of the first table is dynamic. So I can't just set a huge width to their container. Well, I could set a huge width, like 1000%, but then I have a huge ugly horizontal scroll bar. So is there any way to tell the second table "Stay on that same line, no matter what! And line up right next to the previous element please!"

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  • ViewFliper in layout

    - by Surabhi Kale
    i am doing one application in android but i have one problem in layout file i am doing by viewFliper here is code <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" > <TextView android:id="@+id/Quesiontext" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentLeft="true" android:layout_alignParentTop="true" android:layout_marginTop="44dp" android:text="@string/Question" android:textSize="18sp" /> <RadioGroup android:id="@+id/radioGroupOptions" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentLeft="true" android:layout_below="@+id/Quesiontext" android:layout_marginTop="30dp" > <RadioButton android:id="@+id/optionOne" android:layout_width="wrap_content" android:layout_height="wrap_content" android:checked="false" android:text="@string/option1" /> <RadioButton android:id="@+id/optionTwo" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/option2" /> <RadioButton android:id="@+id/optionthree" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/option3" /> <RadioButton android:id="@+id/optionFour" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/option4" /> </RadioGroup> <TextView android:id="@+id/corrertView" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentRight="true" android:layout_below="@+id/radioGroupOptions" android:layout_marginRight="48dp" android:text="@string/correct" /> <Button android:id="@+id/btnNext" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignLeft="@+id/corrertView" android:layout_below="@+id/corrertView" android:layout_marginTop="42dp" android:text="@string/Next" android:textSize="16sp" /> <Button android:id="@+id/Btnpervious" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignBaseline="@+id/btnNext" android:layout_alignBottom="@+id/btnNext" android:layout_alignParentLeft="true" android:text="@string/Pervious" android:textSize="16sp" /> <RelativeLayout android:id="@id/layout"//error android:layout_width="match_parent" android:layout_height="match_parent"> <ViewFlipper android:id="@+id/ViewFlipper01" android:layout_width="wrap_content" android:layout_height="wrap_content" > </RelativeLayout> </RelativeLayout> i didnt get it that how i put another button into ViewFliper ..its confusion and generating error...

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  • How to fix width of DIV that contains floated elements?

    - by joe
    I have a DIV container with several inner DIVs layed out by floating them all left. The inner DIVs may change width on certain events, and the containing DIV adjusts accordingly. I use float:left in the container to keep it shrunk to the width of the inner divs. I use float:left in the inner divs so the layout is clean even when their contents change. The catch is that I want the DIV container width and height to remain constant, UNLESS a particular event causes a change to the inner widths. Conceptually I want to use float on the inners for the layout benefit, but then I want to "fix" them so they don't float around. So if the container is 700px wide, I want it to remain so even if the user narrows the browser window. I'd like the container, and it's internal DIVs to just be clipped by the browser window. I sense this can all be done nicely in CSS, I just can't quite figure out how. I'm not averse to adding another container if necessary... Since the only desired layout changes are event-based, I am also willing to use a bit of JS. But is this necessary? (And I'm still not sure I know what to modify: container dimensions? inner floatiness? other?) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <style type="text/css"> #canvas { overflow:auto; /* for clearing floats */ } #container { float:left; /* so container shrinks around contained divs */ border:thin solid blue; } .inner { float:left; /* so inner elems line up nicely w/o saying fixed coords */ padding-top:8px; padding-bottom:4px; padding-left:80px; padding-right:80px; } #inner1 { background-color:#ffdddd; } #inner2 { background-color:#ddffdd; } #inner3 { background-color:#ddddff; } </style> </head> <body> <div id="canvas"> <div id="container"> <div id="inner1" class="inner"> inner 1 </div> <div id="inner2" class="inner"> inner 2 </div> <div id="inner3" class="inner"> inner 3 </div> </div> </div> cleared element </body> </html>

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  • GridBagConstraints problem-moved to left and size isn't the same

    - by Damir
    I have in Java two panels which need to have same layout, there is my functions for initializations panels. private void InitializePanelCom(){ pnlCom=new JPanel(); pnlCom.setSize(300,160); pnlCom.setLocation(10, 60); add(pnlCom); GridBagLayout gb=new GridBagLayout(); GridBagConstraints gc=new GridBagConstraints(); pnlCom.setLayout(gb); jLabelcommPort = setJLabel("Com Port : "); jLabelbaudRate = setJLabel("Baud Rate : "); jLabelplcAddress = setJLabel("Plc Address : "); jLabelsendTime = setJLabel("Send Time : "); jLabelx50 = setJLabel(" x 50 ms (2 - 99)"); jComboBoxcommPort = setJComboBox(commPortList); jComboBoxbaudRate = setJComboBox(bitRateList); jTextAreaPlcAddress = setJTextField(""); jTextAreaSendTime = setJTextField(""); gc.insets = new Insets(10,0,0,0); gc.ipadx = 120; gc.weightx = 1; gc.gridx = 0; gc.gridy = 0; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jLabelcommPort,gc); gc.insets = new Insets(10,0,0,0); gc.ipadx = 120; gc.weightx = 1; gc.gridx = 1; gc.gridy = 0; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jComboBoxcommPort,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=0; gc.gridy=1; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jLabelbaudRate,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=1; gc.gridy=1; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jComboBoxbaudRate,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=0; gc.gridy=2; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jLabelplcAddress,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=1; gc.gridy=2; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jTextAreaPlcAddress,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=0; gc.gridy=3; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jLabelsendTime,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=1; gc.gridy=3; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jTextAreaSendTime,gc); gc.insets=new Insets(10,0,0,0); gc.ipadx=120; gc.weightx=1; gc.gridx=2; gc.gridy=3; gc.anchor=GridBagConstraints.EAST; pnlCom.add(jLabelx50,gc); } ![alt text][1] private void InitializePanelTcp(){ pnlTcp=new JPanel(); pnlTcp.setSize(300,160); pnlTcp.setLocation(10, 60); add(pnlTcp); GridBagLayout gb=new GridBagLayout(); GridBagConstraints gc=new GridBagConstraints(); pnlTcp.setLayout(gb); lblIPAddress=setJLabel("IP Address : "); txtIPAddress=setJTextField(""); lblPort=setJLabel("Port : "); txtPort=setJTextField(""); cmbBaudRateTCP = setJComboBox(bitRateList); lblBaudRateTCP = setJLabel("Baud Rate : "); lblParityCheck=setJLabel("Parity check : "); txtParityCheck=setJTextField(""); gc.insets = new Insets(10,0,0,0); //gc.ipadx = 20; gc.weightx = 0.3; gc.gridx = 0; gc.gridy = 0; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(lblIPAddress,gc); gc.insets = new Insets(10,0,0,0); //gc.ipadx = 80; gc.weightx = 0.7; gc.gridx = 1; gc.gridy = 0; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(txtIPAddress,gc); gc.insets=new Insets(10,0,0,0); //gc.ipadx=120; gc.weightx=0.3; gc.gridx=0; gc.gridy=1; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(lblPort,gc); gc.insets=new Insets(10,0,0,0); //gc.ipadx=80; gc.weightx=0.7; gc.gridx=1; gc.gridy=1; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(txtPort,gc); gc.insets=new Insets(10,0,0,0); //gc.ipadx=120; gc.weightx=0.3; gc.gridx=0; gc.gridy=2; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(lblBaudRateTCP,gc); gc.insets=new Insets(10,0,0,0); //gc.ipadx=0; gc.weightx=0.7; gc.gridx=1; gc.gridy=2; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(cmbBaudRateTCP,gc); gc.insets=new Insets(10,0,0,0); //gc.ipadx=120; gc.weightx=0.3; gc.gridx=0; gc.gridy=3; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(lblParityCheck,gc); gc.insets=new Insets(10,0,0,0); //gc.ipadx=0; gc.weightx=1.7; gc.gridx=1; gc.gridy=3; gc.anchor=GridBagConstraints.WEST; pnlTcp.add(txtParityCheck,gc); } Problem is that second panel (initializetcp, second picture doesn't look the same, labels are moved at left , it is different ). Can anybody help, I am new with GridBagContsraints at all ?

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  • Html layout with <DIV> work on html editor but not on brownser

    - by DomingoSL
    Hello, i made this layout: <div id="todo" align="center" > <form method="post"> <div id="cabeza" style="width:850px;height:100px"> </div> <div id="contenido" style="width:420px;height:220px;background-image: url(IMG/cuadrologin.png); margin-top: 1px" > <div id="usuario" style="width:348px; height:35px; margin-top: 58px"> <input name="username" type="text" style="width: 250px; height: 30px;background-color: transparent;border: 0px solid #000000;font-size:x-large;color: #222; font-family: 'Trebuchet MS', 'Lucida Sans Unicode', 'Lucida Grande', 'Lucida Sans', Arial, sans-serif; font-weight: bold;" size="299" /> </div> <div id="clave" style="width:348px; height:35px; margin-top: 22px"> <input name="clave" type="text" style="width: 250px; height: 30px;background-color: transparent;border: 0px solid #000000;font-size:x-large;color: #222; font-family: 'Trebuchet MS', 'Lucida Sans Unicode', 'Lucida Grande', 'Lucida Sans', Arial, sans-serif; font-weight: bold;" size="299" /> </div> </div> </form> </div> And in my html editor looks just fine: But when i see it on the browser (Chrome & Firefox) looks like this: Im very new to layout with tag, any idea of what im making worng?

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  • d3.js force layout increase linkDistance

    - by user1159833
    How to increase linkDistance without affecting the node alignment, example: http://mbostock.github.com/d3/talk/20110921/force.html when I try to increase the circle radius and linkDistance the it collapse <script type="text/javascript"> var w = 1280, h = 800, z = d3.scale.category20c(); var force = d3.layout.force() .size([w, h]); var svg = d3.select("#chart").append("svg:svg") .attr("width", w) .attr("height", h); svg.append("svg:rect") .attr("width", w) .attr("height", h); d3.json("flare.json", function(root) { var nodes = flatten(root), links = d3.layout.tree().links(nodes); force .nodes(nodes) .links(links) .start(); var link = svg.selectAll("line") .data(links) .enter().insert("svg:line") .style("stroke", "#999") .style("stroke-width", "1px"); var node = svg.selectAll("circle.node") .data(nodes) .enter().append("svg:circle") .attr("r", 4.5) .style("fill", function(d) { return z(d.parent && d.parent.name); }) .style("stroke", "#000") .call(force.drag); force.on("tick", function(e) { link.attr("x1", function(d) { return d.source.x; }) .attr("y1", function(d) { return d.source.y; }) .attr("x2", function(d) { return d.target.x; }) .attr("y2", function(d) { return d.target.y; }); node.attr("cx", function(d) { return d.x; }) .attr("cy", function(d) { return d.y; }); }); }); function flatten(root) { var nodes = []; function recurse(node, depth) { if (node.children) { node.children.forEach(function(child) { child.parent = node; recurse(child, depth + 1); }); } node.depth = depth; nodes.push(node); } recurse(root, 1); return nodes; } </script>

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  • jQuery and XHTML layout problems in ie7

    - by abysslogic
    Hi there, I am back again with more layout problems on my up and coming website. I am able to achieve the proper animation, positioning and results with my layout / splash on every modern browser (excluding ie7 or older). I have an image in the center of the page, that is text-align: center'd, and pushed to a vertical center by having a div (#SPLASH_HEAD) set to 50% on the top half of the page. The loading animation changes the height of #SPLASH_HEAD to 0px, to drag the image to the top (and then do other things). In ie7 (or compatability mode), it appears that there is an error in jquery-1.4.2.min.js, line 116 char 165 (which I dont think has anything to do with the actual jQuery file itself). The splash is not centered either vertically (#SPLASH_HEAD does not register at 50% of window height) and is not centered properly with margin-left. Also, none of the other elements are hidden properly (with .hide()) as ie7 does not appear to be loading all of my jQuery / javascript. heres a link: www.voidsync.com/test (it would be easier to view the source on there) thanks!

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  • form layout in drupal from a module

    - by EricP
    I created my own module called "cssswitch". I'm trying to create my own html layout to display the admin form portion of the module. I understand how to use the hook_form_alter() to modify form elements, but I need to create the entire form layout to make some fields appear next to each other. It seems I need something like the way I have the frontend view of the node displayed with theme_cssswitch_display(), but for the admin part of the node. function cssswitch_form_alter(&$form, $form_state, $form_id) { switch($form_id) { case 'cssswitch_node_form': $form['hour_start']['#prefix'] = '<div class="start-box">'; $form['ampm_start']['#suffix'] = '</div>'; $form['ampm_start']['#attributes'] = array("style" => "border-width:2px;"); break; } } function cssswitch_theme() { return array( 'cssswitch_display' => array( 'arguments' => array('node'), ), ); } // to display the view of the node function theme_cssswitch_display($node) { $output = '<div class="cssswitch-cssfilename">Filename: '. check_plain($node->cssfilename). '</div>'; $output .= '<div class="cssswitch-time_start">Start: '. check_plain($node->hour_start). ':'.check_plain($node->minute_start).' '.check_plain($node->ampm_start).'</div>'; $output .= '<div class="cssswitch-time_end">End: '. check_plain($node->hour_end). ':'.check_plain($node->minute_end).' '.check_plain($node->ampm_end).'</div>'; return $output; } thanks for any help

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  • Boost link error when using "--layout=system" on VS2005

    - by Kevin
    I'm new to boost, and thought I'd try it out with some realistic deployment scenarios for the .dlls, so I used the following command to compile/install the libraries: .\bjam install --layout=system variant=debug runtime-link=shared link=shared --with-date_time --with-thread --with-regex --with-filesystem --includedir=<my include directory> --libdir=<my bin directory> > installlog.txt That seemed to work, but my simple program (taken right from the "Getting Started" page) fails: #include <boost/regex.hpp> #include <iostream> #include <string> // Place your functions after this line int main() { std::string line; boost::regex pat( "^Subject: (Re: |Aw: )*(.*)" ); while (std::cin) { std::getline(std::cin, line); boost::smatch matches; if (boost::regex_match(line, matches, pat)) std::cout << matches[2] << std::endl; } } This fails with the following linker error: fatal error LNK1104: cannot open file 'libboost_regex-vc80-mt-1_42.lib' I'm sure that both the .lib and the .dlls are in that directory, and named how I want them to be (ie: boost_regex.lib, etc, all unversioned, as the --layout=system says). So why is it looking for the versioned type of it? And how do I get it to look for the unversioned type of the library? I've tried this with more "normal" options, such as below: .\bjam stage --build-type=complete --with-date_time --with-thread --with-filesystem --with-regex > mybuildlog.txt And that works fine. I made sure my compiler saw the "stage\lib" directory, and it compiled and ran fine with nothing beyond having the environment looking into the right lib directory. But when I took those "testing" directories away, and wanted to use these others (unversioned), then it failed. I'm under VS2005 here on XP. Any ideas?

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