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  • @WebServices as @Stateless session bean in ejb jar

    - by kislo_metal
    Hi! Scenario: Creating some web service as @Stateless bean, package it as ejb jar. Result - can`t access to wsdl file. Goal: I want to use @WebServices as @Stateless session using ejb jar packaging with accessible wsdl file form web. Web service: @Stateless @WebService(serviceName = "ws.isp.SecurityService", wsdlLocation = "META-INF/wsdl/SecurityService.wsdl") public class SecurityService{ @EJB private Kerberos factory; @EJB private UsersServiceBean uService; public SecurityService() { } @WebMethod @WebResult(name = "SimpleResponse") public SimpleResponse LogOut( @WebParam(name = "sessionUUID", targetNamespace = "https://secure.co.ua/ws/") String sessionUUID ) { SimpleResponse resp = new SimpleResponse(); try{ factory.removeSession(sessionUUID); resp.setError(WSErrorCodes.SUCCESS); }catch (Exception e){ e.printStackTrace(); resp.setError(WSErrorCodes.UNRELOSVED_ERROR); } return resp; } @WebMethod public MySession logIn( @WebParam(name = "username", targetNamespace = "https://secure.co.ua/ws/") String username, @WebParam(name = "password", targetNamespace = "https://secure.co.ua/ws/") String password){ MySession result = new MySession(); try { UserSession us = factory.creatSession(uService.getUser(username, password).getId()); result.setSessionID(us.getSessionUUID().toString()); result.setError(WSErrorCodes.SUCCESS); } catch (NullPointerException e){ e.printStackTrace(); result.setError(WSErrorCodes.UNRELOSVED_USER); } catch (Exception e){ e.printStackTrace(); result.setError(WSErrorCodes.UNRELOSVED_ERROR); } return result; } } In this case I getting Invalid wsdl request http://192.168.44.48:8181/ws.isp.SecurityService/SecurityService when I try to access to wsdl and if do not use description of wsdlLocation I getting blank page. Web service as it self working good. Q1: what is the rule of describing wsdl file location for web services as stateless in ejb jar. Q2: is it possible to generate wsdl file during maven packaging ? Q3: how to generate wsdl file for web service where we have such annotation as @Stateless and @EJB (currently I can generate it only by commenting those annotations) environment: mave 2, ejb 3.1, glassfish v3, jax-ws 2.x Thank you!

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  • Class 'org.springframework.http.converter.ResourceHttpMessageConverter' not found - how to correct?

    - by Ash Kim
    Eclipse STS is reporting I have problem with my spring project. It's a fresh project generated from the Spring Web MVC Project Template (File-New-Spring Template Project-Spring Web MVC ). When I create the project it has no problems - it's only once I modify the pom (by adding the hibernate dependencies) that STS then picks up the spring problem. Strangely if I revert the pom the problem remains. Also I can run the project on a spring tc server and all works correctly. Any ideas how I can satisfy this problem report? "Class 'org.springframework.http.converter.ResourceHttpMessageConverter' not found" mvc-config.xml /src/main/webapp/WEB-INF/spring line 9 Spring Beans Problem mvc-config.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <mvc:annotation-driven /> <!-- <= PROBLEMATIC LINE REPORTED BY STS --> <!-- Resolves view names to protected .jsp resources within the /WEB-INF/views directory --> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/views/"/> <property name="suffix" value=".jsp"/> </bean> </beans>

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  • Using themed css files requires a header control on the page. (e.g. <head runat="server" />).

    - by wide
    in local it works. when i load server, i got this error. Using themed css files requires a header control on the page. (e.g. <head runat="server" />). Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.InvalidOperationException: Using themed css files requires a header control on the page. (e.g. <head runat="server" />). Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [InvalidOperationException: Using themed css files requires a header control on the page. (e.g. <head runat="server" />).] System.Web.UI.PageTheme.SetStyleSheet() +2458406 System.Web.UI.Page.OnInit(EventArgs e) +8699420 System.Web.UI.Control.InitRecursive(Control namingContainer) +333 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +378 -------------------------------------album1.aspx------------------ <%@ Page Language="C#" MasterPageFile="~/MasterPage.master" AutoEventWireup="true" CodeFile="album1.aspx.cs" Inherits="album1" Title="Özkan Köylü | Albüm" %> <asp:Content ID="Content1" ContentPlaceHolderID="ContentPlaceHolder1" Runat="Server"> <script src="scripts/Silverlight.js" type="text/javascript"></script> <script src="scripts/Default_html.js" type="text/javascript"></script> <script src="scripts/Page.xaml.js" type="text/javascript"></script> <script src="scripts/gallery.js" type="text/javascript"></script> <div align="center" id="SilverlightControlHost"> <script type="text/javascript"> createSilverlight(); </script> </div> </asp:Content>

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  • java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

    - by aelshereay
    I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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  • Create a strongly typed view which inherites a class which is concrete

    - by Ashwani K
    Hello All: I am having one class called BaseClass which contains some logic applicable to whole web site. In order to create a strongly typed view we need to inherit the page from System.Web.Mvc.ViewPage generic class. But In our case I have to Inherit the BaseClass from System.Web.Mvc.ViewPage to apply some common settings, but the BaseClass should be inherited from System.Web.Mvc.ViewPage< generic version. But I cannot inherit the BaseClass from System.Web.Mvc.ViewPage< as it will change other class also. So I created one more class of type BaseClass< inheriting it from System.Web.Mvc.ViewPage< and copied the whole code of BaseClass in BaseClass<. But the code in BaseClass is controlled by other team so it will be changed frequently so my BaseClass< should be in sync with BaseClass. Please help me in eliminating the code duplication or any other approach to make strongly typed View. Thanks Ashwani

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  • How do I use IIS6 style metabase paths in IIS7 AppCmd tool?

    - by Mike Atlas
    I'm currently in the process of upgrading old II6 automation scripts that use the IISVdir tool to create/modify/update apps and virtual directories, and replacing them with AppCmd for IIS7. The IIS6, "IISVDir" commands reference paths in that are from the metabase, eg, "/W3SVC/1/ROOT/MyApp" - where 1 is ID of the "Default Web Site" site. The command doesn't actually require the display name of the site to make changes to it. This works well, since on a different language OS, the "Default Web Site" site name could be named, for example, "??? Web ???" or anything else for that matter. But this flexibility is lost if AppCmd can only reference "Default Web Site" via its name, and not a language-neutral identifier. So, how can I script AppCmd to refer to sites, vdirs and apps using language neutral identifiers to reference the "Default App Site"? Perhaps I need to start creating my own site instead, from the start, and name it something else specific, and stop using "Default Web Site" as the root? (Disclosure: I only have a IIS7-English machine that I am working on currently, but I have both IIS6-English and IIS6-Japanese machines for testing my old scripts - so perhaps it really is just "Default Web Site" still on Win2k8-Japanese?)

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  • Why would the value of the Session object go away?

    - by Michael
    In ASP.NET/VB.NET 2005 I've created a small web app with two forms. In Default there is a button and a text box and a link. When you press the button whatever is in the text box is put into the Session. Protected Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click System.Web.HttpContext.Current.Session("mykey") = Me.TextBox1.Text End Sub When you press the link it's NavigateURL property is "~/Retrieve.aspx" On the Retrieve page it pulls the information out of the Session (that is, whatever you typed in the text box). Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Dim myValue As String = CType(System.Web.HttpContext.Current.Session("mykey"), String) Response.Write(myValue) End Sub Now it works on my machine and when deployed to the production web-site server if I run the browser remotely there it works fine - What you type on the first page appears on the second page. But when I run it from my machine to the production web server the second page is always blank. Why? It doesnt seem like a timeout issue - brand new web.config taking the defaults. Any pointers would be greatly appreciated! Thanks!

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  • Testing ASP.NET webservice using NUnit and transferring session state

    - by herbertyeung
    I have a NUnit test class that starts an ASP.NET web service (using Microsoft.VisualStudio.WebHost.Server) which runs on http://localhost:1070 The problem I am having is that I want to create a session state within the NUnit test that is accessible by the ASP.NET web service on localhost:1070. I have done the following, and the session state can be created successfully inside the NUnit Test, but is lost when the web service is invoked: //Create a new HttpContext for NUnit Testing based on: //http://blogs.imeta.co.uk/jallderidge/archive/2008/10/19/456.aspx HttpContext.Current = new HttpContext( new HttpRequest("", "http://localhost:1070/", ""), new HttpResponse( new System.IO.StringWriter())); //Create a new HttpContext.Current for NUnit Testing System.Web.SessionState.SessionStateUtility.AddHttpSessionStateToContext( HttpContext.Current, new HttpSessionStateContainer("", new SessionStateItemCollection(), new HttpStaticObjectsCollection(), 20000, true, HttpCookieMode.UseCookies, SessionStateMode.Off, false)); HttpContext.Current.Session["UserName"] = "testUserName"; testwebService.testMethod(); I want to be able to get the session state created in the NUnit test for Session["UserName"] in the ASP.NET web service: [WebMethod(EnableSession=true)] public int testMethod() { string user; if(Session["UserName"] != null) { user = (string)Session["UserName"]; //Do some processing of the user return 1; } else return 0; } The web.config file has the following configuration for the session state configuration and would like to remain using InProc than rather StateServer Or SQLServer: <sessionState mode="InProc" stateConnectionString="tcpip=127.0.0.1:42424" cookieless="false" timeout="20"/>

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  • Spring can't find a lib and webapp doesn't start up in tomcat 6

    - by gotch4
    I've this problem using STS: I'm building a simple Spring app, just to try out features like MVC and persistence. Now I've created something very simple, out of a bunch of tutorials for Spring 3, that I'm using. The application fails with this, during server startup: Code: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping#0': Initialization of bean failed; nested exception is org.springframework.beans.factory.CannotLoadBeanClassException: Cannot find class [org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean] for bean with name 'mySessionFactory' defined in ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml]; nested exception is java.lang.ClassNotFoundException: org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean but I've org.springframework.orm in web-inf/classes folder (I even tried putting it in web-inf/lib). As I copied these libs there, the came out in Web App Libraries folder. Building this project in STS works fine as this dependency is set up in build path throught project properties, but how do I transfer the libs to the web app? (I'm using Tomcat 6 as it is the server I'm going to use sometime in the future for production). Is this a config problem of my XML? Or am I just missing the right way to put this lib? (I encountered the same problem before, but adding the needed lib in classes worked it out). More than this I that if I browse inside my workspace to the folder where the working folder of tomcat should be, I can't find any work directory and any commo

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  • Django website on Apache with wsgi failing

    - by notagain
    I have a website I've built in django that I'm trying to get working on our corporate Apache server (on debian) for our intranet at my workplace. Unfortunately, Apache keeps returning server errors whenever I try to navigate to my site. Although I can navigate to the statics folder. My Apache config and wsgi script look like the following... lbirdf.wsgi import os import sys sys.path.append('/home/lbi/rdfweb/web') sys.path.append('/home/lbi/rdfweb/lbirdf') os.environ['DJANGO_SETTINGS_MODULE'] = 'lbirdf.settings_production' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Apache config Listen 8080 <VirtualHost *:8080> ServerName server1 WSGIScriptAlias /rdfweb /home/lbi/rdfweb/web/lbirdf/apache/lbirdf.wsgi Alias /statics /home/lbi/rdfweb/web/lbirdf/statics Alias /admin_media /home/lbi/rdfweb/web/lbirdf/admin_media <Directory /home/lbi/rdfweb/web/lbirdf/apache> Order allow,deny Allow from all </Directory> <Directory /home/lbi/rdfweb/web/lbirdf/admin_media> Order allow,deny Allow from all </Directory> </VirtualHost> Any ideas on where I might be going wrong?

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  • Am I making the right choice in choosing Yii as my PHP Framework?

    - by Bara
    I am about to begin development of a new website and have been doing research on PHP Frameworks. I'm not an advanced PHP developer, but I have been developing web sites and apps (in asp.net) for a few years now. My website will primarily be AJAX-based (using jQuery) and making lots of calls to web services. After some research, here's what I came up with: CakePHP: Originally started developing in this, but found it too complex. The fact that it forces you to use and learn all this new stuff just to use it was a bit daunting, so I put it aside for the time being. Zend: The performance of the framework leaves me a bit skeptical, but I heard it has great support for creating web services. I also heard it was a bit complex. CodeIgniter: No real reason for not using this one. Based on what I've read CodeIgniter and Yii are very similar, but Yii is a bit faster and doesn't have un-needed code for PHP4 (since I plan on developing exclusively in PHP5). As far as Yii, the only things that scare me about it are that it is newer than the other frameworks so it has a smaller community. It also doesn't seem to have a ton of web service support (only SOAP, from my understanding) as opposed to Zend. So my questions come down to: Should these things worry me? (not as big of a community, poor web service support) Is there anything else I should look into? Is my choice of Yii over the other frameworks ok for a primarily AJAX-based web app? Bara

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  • Cache data in SQL CE database

    - by user93422
    Background I have an SQL CE database, that is constantly updated (every second). I have a (web) application that allows a user to look at the data in real-time. At some point a user can click "take a snapshot" button, and it will open the snapshot in a different window. And then on that form, there is "print" and "download" buttons that will either generate a page for printing, or will stream the data as CSV file - but same data snapshot has to be used, i.e. I can't go to the DB to get latest data for that. Details SQL CE dabatase is exposed through WCF web service. Snapshot consists of up to 500 records, 10 columns each. Expiration time on the snapshot of 2 hours is sufficient. It is a low-traffic application, so I don't expect more than few (5) connections at the same time. Loosing snapshot is not a big deal, user can simply generate new one. database is accessed by self-hosted WCF web service using Linq-to-SQL. Web site is ASP.NET MVC hosted on UltiDev Cassini. database, and web site are most likely be on the same box, when deployed. The entire app is intranet bound. Problem I need to cache the snapshot of the data at the moment user pressed "take a snapshot" button, so that I can use same data to generate print page, or generate a file for download. Solution 1: Each time there is a need to generate a snapshot, I will create a table in the database. Since there are no temp tables in SQL CE, I will need to clean it up myself. Solution 2: Cache the snapshot in-memory on either DB server, or web server. Question: Is there anything wrong with proposed solutions? Any different solution suggestions?

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  • php - arrange array to display in score order

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

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  • How to sort multiple arrays in PHP

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

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  • Java Servlet: getInitParameter not work in Service()

    - by Gabriele
    I've added some parameters in my web.xml config file, as follow: <context-param> <param-name>service1</param-name> <param-value>http://www.example.com/example2.html</param-value> </context-param> <context-param> <param-name>service2</param-name> <param-value>http://www.example.com/example2.html</param-value> </context-param> ... I try to get the parameter in my servlet, in particular in my service method: protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println(this.getServletContext().getInitParameter("service1")); ... but at runtime I have a NullPointerException... How can I get the parameter value included in web.xml? This is the stacktrace: GRAVE: Servlet.service() for servlet DispatcherServlet threw exception java.lang.NullPointerException at javax.servlet.GenericServlet.getServletContext(GenericServlet.java:160) at it.servlethope.DispatcherServlet.service(DispatcherServlet.java:66) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.tuckey.web.filters.urlrewrite.RuleChain.handleRewrite(RuleChain.java:176) at org.tuckey.web.filters.urlrewrite.RuleChain.doRules(RuleChain.java:145) at org.tuckey.web.filters.urlrewrite.UrlRewriter.processRequest(UrlRewriter.java:92) at org.tuckey.web.filters.urlrewrite.UrlRewriteFilter.doFilter(UrlRewriteFilter.java:381) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Unknown Source) DispatcherServlet.java:66 is the line where I try the getInitParameter()

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  • Will this class cause memory leaks, and does it need a dispose method? (asp.net vb)

    - by Phil
    Here is the class to export a gridview to an excel sheet: Imports System Imports System.Data Imports System.Configuration Imports System.IO Imports System.Web Imports System.Web.Security Imports System.Web.UI Imports System.Web.UI.WebControls Imports System.Web.UI.WebControls.WebParts Imports System.Web.UI.HtmlControls Namespace ExcelExport Public NotInheritable Class GVExportUtil Private Sub New() End Sub Public Shared Sub Export(ByVal fileName As String, ByVal gv As GridView) HttpContext.Current.Response.Clear() HttpContext.Current.Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", fileName)) HttpContext.Current.Response.ContentType = "application/ms-excel" Dim sw As StringWriter = New StringWriter Dim htw As HtmlTextWriter = New HtmlTextWriter(sw) Dim table As Table = New Table table.GridLines = GridLines.Vertical If (Not (gv.HeaderRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.HeaderRow) table.Rows.Add(gv.HeaderRow) End If For Each row As GridViewRow In gv.Rows GVExportUtil.PrepareControlForExport(row) table.Rows.Add(row) Next If (Not (gv.FooterRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.FooterRow) table.Rows.Add(gv.FooterRow) End If table.RenderControl(htw) HttpContext.Current.Response.Write(sw.ToString) HttpContext.Current.Response.End() End Sub Private Shared Sub PrepareControlForExport(ByVal control As Control) Dim i As Integer = 0 Do While (i < control.Controls.Count) Dim current As Control = control.Controls(i) If (TypeOf current Is LinkButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, LinkButton).Text)) ElseIf (TypeOf current Is ImageButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, ImageButton).AlternateText)) ElseIf (TypeOf current Is HyperLink) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, HyperLink).Text)) ElseIf (TypeOf current Is DropDownList) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, DropDownList).SelectedItem.Text)) ElseIf (TypeOf current Is CheckBox) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, CheckBox).Checked)) End If If current.HasControls Then GVExportUtil.PrepareControlForExport(current) End If i = (i + 1) Loop End Sub End Class End Namespace Will this class cause memory leaks? And does anything here need to be disposed of? The code is working but I am getting frequent crashes of the app pool when it is in use. Thanks.

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  • ASP.NET - Webservice not being called from javascript

    - by Robert
    Ok I'm stumped on this one. I've got a ASMX web service up and running. I can browse to it (~/Webservice.asmx) and see the .NET generated page and test it out.. and it works fine. I've got a page with a Script Manager with the webservice registered... and i can call it in javascript (Webservice.Method(...)) just fine. However, I want to use this Webservice as part of a jQuery Autocomplete box. So I have use the url...? and the Webservice is never being called. Here's the code. [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. [System.Web.Script.Services.ScriptService] public class User : System.Web.Services.WebService { public User () { //Uncomment the following line if using designed components //InitializeComponent(); } [WebMethod] public string Autocomplete(string q) { StringBuilder sb = new StringBuilder(); //doStuff return sb.ToString(); } web.config <system.web> <webServices> <protocols> <add name="HttpGet"/> <add name="HttpPost"/> </protocols> </webServices> And the HTML $(document).ready(function() { User.Autocomplete("rr", function(data) { alert(data); });//this works ("#<%=txtUserNbr.ClientID %>").autocomplete("/User.asmx/Autocomplete"); //doesn't work $.ajax({ url: "/User.asmx/Autocomplete", success: function() { alert(data); }, error: function(e) { alert(e); } }); //just to test... calls "error" function });

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  • Chrome targeted CSS

    - by Chris
    I have some CSS code that hides the cursor on a web page (it is a client facing static screen with no interaction). The code I use to do this is below: *, html { cursor: url('/web/resources/graphics/blank.cur'), pointer; } Blank.cur is a totally blank cursor file. This code works perfectly well in all browsers when I host the web files on my local server but when I upload to a Windows CE webserver (our production unit) the cursor represents itself as a black box. Odd. After some testing it seems that chrome only has a problem with totally blank cursor files when served from WinCE web server, so I created a blank cursor with one pixel as white, specifically for chrome. How do I then target this CSS rule to chrome specifically? i.e. *, html { cursor: url('/web/resources/graphics/blank.cur'), pointer; } <!--[if CHROME]> *, html { cursor: url('/web/resources/graphics/blankChrome.cur'), pointer; } <![endif]-->

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  • Will this class cause memory leaks, and does anything need disposing of? (asp.net vb)

    - by Phil
    Here is the class to export a gridview to an excel sheet: Imports System Imports System.Data Imports System.Configuration Imports System.IO Imports System.Web Imports System.Web.Security Imports System.Web.UI Imports System.Web.UI.WebControls Imports System.Web.UI.WebControls.WebParts Imports System.Web.UI.HtmlControls Namespace ExcelExport Public NotInheritable Class GVExportUtil Private Sub New() End Sub Public Shared Sub Export(ByVal fileName As String, ByVal gv As GridView) HttpContext.Current.Response.Clear() HttpContext.Current.Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", fileName)) HttpContext.Current.Response.ContentType = "application/ms-excel" Dim sw As StringWriter = New StringWriter Dim htw As HtmlTextWriter = New HtmlTextWriter(sw) Dim table As Table = New Table table.GridLines = GridLines.Vertical If (Not (gv.HeaderRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.HeaderRow) table.Rows.Add(gv.HeaderRow) End If For Each row As GridViewRow In gv.Rows GVExportUtil.PrepareControlForExport(row) table.Rows.Add(row) Next If (Not (gv.FooterRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.FooterRow) table.Rows.Add(gv.FooterRow) End If table.RenderControl(htw) HttpContext.Current.Response.Write(sw.ToString) HttpContext.Current.Response.End() End Sub Private Shared Sub PrepareControlForExport(ByVal control As Control) Dim i As Integer = 0 Do While (i < control.Controls.Count) Dim current As Control = control.Controls(i) If (TypeOf current Is LinkButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, LinkButton).Text)) ElseIf (TypeOf current Is ImageButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, ImageButton).AlternateText)) ElseIf (TypeOf current Is HyperLink) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, HyperLink).Text)) ElseIf (TypeOf current Is DropDownList) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, DropDownList).SelectedItem.Text)) ElseIf (TypeOf current Is CheckBox) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, CheckBox).Checked)) End If If current.HasControls Then GVExportUtil.PrepareControlForExport(current) End If i = (i + 1) Loop End Sub End Class End Namespace Will this class cause memory leaks? And does anything here need to be disposed of? The code is working but I am getting the app pool falling over frequently when it is in use. Thanks.

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  • JRuby app throws exception in Spring

    - by mat3001
    I am trying to run a JRuby app in Spring. I use Eclipse to run it. But it doesn't compile. Does anybody know what's going on here? Exception in thread "Launcher:/oflaDemo" [INFO] [Launcher:/oflaDemo] org.springframework.beans.factory.support.DefaultListableBeanFactory - Destroying singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory@4a009ab0: defining beans [placeholderConfig,web.context,web.scope,web.handler,demoService.service]; parent: org.springframework.beans.factory.support.DefaultListableBeanFactory@f5d8d75 [INFO] [Launcher:/installer] org.red5.server.service.Installer - Installer service created org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'web.scope' defined in ServletContext resource [/WEB-INF/red5-web.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type [org.springframework.scripting.jruby.JRubyScriptFactory] to required type [org.red5.server.api.IScopeHandler] for property 'handler'; nested exception is java.lang.IllegalArgumentException: Cannot convert value of type [org.springframework.scripting.jruby.JRubyScriptFactory] to required type [org.red5.server.api.IScopeHandler] for property 'handler': no matching editors or conversion strategy found at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:480) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) I don't have a lot of experience with Spring, so I would really appreciate hits. If you're familiar with red5 - yes it's the oflademo app supplied by red5.

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  • Multiple webroot folders with Jetty

    - by Lóránt Pintér
    I'm using Jetty (version 6.1.22) to service a Java web application. I would like to make Jetty look in two different folders for web resources. Take this layout: +- project1 | +- src | +- main | +- webapp | +- first.jsp | +- project2 +- src +- main +- webapp +- second.jsp I would like to make Jetty serve both URLs: http://localhost/web/first.jsp http://localhost/web/second.jsp I tried starting Jetty like this: Server server = new Server(); SocketConnector connector = new SocketConnector(); connector.setPort(80); server.setConnectors(new Connector[] { connector }); WebAppContext contextWeb1 = new WebAppContext(); contextWeb1.setContextPath("/web"); contextWeb1.setWar("project1/src/main/webapp"); server.addHandler(contextWeb1); WebAppContext contextWeb2 = new WebAppContext(); contextWeb2.setContextPath("/web"); contextWeb2.setWar("project2/src/main/webapp"); server.addHandler(contextWeb2); server.start(); But it only serves first.jsp, and it returns 404 for second.jsp. How can I get this to work?

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  • Please Help to locate the error

    - by jagdeep
    using System; using System.Collections; using System.Configuration; using System.Data; using System.Linq; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Xml.Linq; public partial class expt2 : System.Web.UI.Page { double result ; protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) result = 0.0; protected void Chkbxbd_CheckedChanged(object sender, EventArgs e) { if (Chkbxbd.Checked) { txtbxttl.Text = "" + 10000; result += double.Parse(txtbxttl.Text); } else result = result - 10000; } protected void Chkbxsfa_CheckedChanged(object sender, EventArgs e) { if (Chkbxsfa.Checked) { txtbxttl.Text = "" + 15000; result += double.Parse(txtbxttl.Text); } else result = result - 15000; } protected void btnttl_Click(object sender, EventArgs e) { txtbxttl.Text = "" + result; } } In this code the individual value for checkbox is ok but when the total is made it becomes 0. Please help me to fix it.

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  • What job title should be most suitable for my object in resume and what salary range should I expect

    - by user354177
    I was a classic asp developer in 2000. After a year of full-time employment, I left the field. I found a part-time position as an asp developer again in 2005 and taught myself vb.net. In 2007, I got the current full-time job as an Asp.net web developer. I taught myself C#, LING t0 SQL, Web Services, AJAX, and creating all kinds of reports with reporting services. One and half years ago, I sent myself to part-time graduate program in Database and Web Systems. I'll have two semesters to go and so far my GPA is 4.0/4.0. My job responsibility is to collect business requirements from other departments, design the database, write stored procedures, create aspx pages, and create reports. I love what I do and want to advance my career to the next level. What I enjoy most is to design the relational database. I would want to become an .Net Architect eventually. I got an interview. They were looking for asp.net web developer. But I was surprised and disappointed that position would only create aspx pages. I would not even have opportunity to write stored procedures, let alone design the database (those would be provided by another group). Furthermore, they asked me some detailed questions about web forms, some of which I did not know the answers. they might be disappointed as well. I am eager to learn and can apply what I learn to real projects right away. I believe no matter what specific skills I am lacking for a new position, I can catch up quickly. I am looking for $70k range job. The object in my resume is Experience C# Web Application Developer. Due to the experience from last interview, I wonder if the object is really what I want. Could somebody answer my questions? Thank you.

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  • i don't know how to solve this error

    - by wide
    in local it works. when i load server, i got this error. Using themed css files requires a header control on the page. (e.g. <head runat="server" />). Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.InvalidOperationException: Using themed css files requires a header control on the page. (e.g. <head runat="server" />). Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [InvalidOperationException: Using themed css files requires a header control on the page. (e.g. <head runat="server" />).] System.Web.UI.PageTheme.SetStyleSheet() +2458406 System.Web.UI.Page.OnInit(EventArgs e) +8699420 System.Web.UI.Control.InitRecursive(Control namingContainer) +333 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +378

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  • Quick guide to Oracle IRM 11g: Creating your first sealed document

    - by Simon Thorpe
    Quick guide to Oracle IRM 11g indexThe previous articles in this guide have detailed how to install, configure and secure your Oracle IRM 11g service. This article walks you through the process of now creating your first context and securing a document against it. I should mention that it would be worth reviewing the following to ensure your installation is ready for that all important first document. Ensure you have correctly configured the keystore for the IRM wrapper keys. If this is not correctly configured, creating the context below will fail. Make sure the IRM server URL correctly resolves and uses the right protocol (HTTP or HTTPS) ContentsCreate the first contextInstall the Oracle IRM Desktop Seal your first document Create the first contextIn Oracle 11g there is a built in classification and rights system called the "standard rights model" which is based on 10 years of customer use cases and innovation. It is a system which enables IRM to scale massively whilst retaining the ability to balance security and usability and also separate duties by allowing contacts in the business to own classifications. The final article in this guide goes into detail on this inbuilt classification model, but for the purposes of this current article all we need to do is create at least one context to test our system out.With a new IRM server there are a set of predefined context templates and roles which again are setup in a way which reflects the most common use we've learned from our customers. We will use these out of the box configurations as they are to create the first context against which we will seal some content.First login to your Oracle IRM Management Website located at https://irm.company.com/irm_rights/. Currently the system is only configured to use the built in LDAP for users, so use the only account we have at the moment, which by default is weblogic. Once logged in switch to the Contexts tab. Click on the New Context icon () in the menu bar on the left. In the resulting dialog select the Standard context template and enter in a name for the context. Then just hit finish, the weblogic account will automatically be made the manager. You'll now see your brand new context ready for users to be assigned. Now click on the Assign Role icon () in the menu bar and in the resulting dialog search for your only user account, weblogic, and add to the list on the right. Now select a role for this user. Because we need to create a document with this user we must select contributor, as this is the only role which allows for the ability to seal. Finally hit next and then finish. We now have a context with a user that has the rights to create a document. The next step is to configure the IRM Desktop to get these rights from the server. Install the Oracle IRM Desktop Before we can seal a document we need the client software installed. Oracle IRM has a very small, lightweight client called the Oracle IRM Desktop which can be freely downloaded in 27 languages from here. Double click on the installer and click on next... Next again... And finally on install... Very easy. You may get a warning about closing Outlook, Word or another application and most of the time no reboots are required. Once it is installed you will see the IRM Desktop icon running in your tool tray, bottom right of the desktop. Seal your first document Finally the prize is within reach, creating your first sealed document. The server is running, we've got a context ready, a user assigned a role in the context but there is the simple and obvious hoop left to jump through. To seal a document we need to have the users rights cached to the local machine. For this to take place, the IRM Desktop needs to know where the Oracle IRM server is on the network so we can synchronize these rights and then be able to seal a document. The usual way for the IRM Desktop to know about the IRM server is it learns automatically when you open an existing piece of content that someone has sent you... ack. Bit of a chicken or the egg dilemma. The solution is to manually tell the IRM Desktop the location of the IRM Server and then force a synchronization of rights. Right click on the Oracle IRM Desktop icon in the system tray and select Options.... Then switch to the Servers tab in the resulting dialog. There are no servers in the list because you've never opened any content. This list is usually populated automatically but we are going to add a server manually, so click on New.... Into the dialog enter in the full URL to the IRM server. Note that this time you use the path /irm_desktop/ and not /irm_rights/. You can see an example from the image below. Click on the validate button and you'll be asked to authenticate. Enter in your weblogic username and password and also check the Remember my password check box. Click OK and the IRM Desktop will confirm a successful connection to the server. OK all the dialogs and we are ready to Synchronize this users rights to the desktop. Right click once more on the Oracle IRM Desktop icon in the system tray. Now the Synchronize menu option is available. Select this and the IRM Desktop will now talk to the IRM server, authenticate using your weblogic account and get your rights to the context we created. Because this is the first time this users has communicated with the IRM server the IRM Desktop presents a privacy policy dialog. This is a chance for the business to ask users to agree to any policy about the use of IRM before opening secured documents. In our guide we've not bothered to setup this URL so just click on the check box and hit Accept. The IRM Desktop will then talk to the server, get your rights and display a success dialog. Lets protect a documentNow we are ready to seal a piece of content. In my guide i'm going to protect a Microsoft Word document. This mean's I have to have copy of Office installed, in this guide i'm using Microsoft Office 2007. You could also seal a PDF document, you'll need to download and install Adobe Acrobat Reader. A very simple test could be to seal a GIF/JPG/PNG or piece of HTML because this is rendered using Internet Explorer. But as I say, i'm going to protect a Word document. The following example demonstrates choosing a file in Windows Explorer, there are many ways to seal a file and you can watch a few in this video.Open a copy of Windows Explorer and locate the file you wish to seal. Right click on the document and select Seal To -> Context You are now presented with the Select Context dialog. You'll now have a sealed copy of the document sat in the same location. Double click on this document and it will open, again using the credentials you've already provided. That is it, now you just need to add more users, more documents, more classifications and start exploring the different roles and experiment with different offline periods etc. You may wish to setup the server against an existing LDAP or Active Directory environment instead of using the built in WebLogic LDAP store. You can read how to use your corporate directory here. But before we finish this guide, there is one more article and arguably the most important article of all. Next I discuss the all important decision making surrounding the actually implementation of Oracle IRM inside your business. Who has rights to what? How do you map contexts to your existing business practices? It is the next article which actually ensures you deploy a successful IRM solution by looking at the business and understanding how they use your sensitive information and then configuring Oracle IRM to reflect their use.

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