Search Results

Search found 50990 results on 2040 pages for 'system center'.

Page 635/2040 | < Previous Page | 631 632 633 634 635 636 637 638 639 640 641 642  | Next Page >

  • WinForms Dynamic Label

    - by tolga
    I am creating dynamic labels and letting users change attributes of the labes like backcolor and so by sending unicode. However I don't know how to check if the label exists therefore I can't manipulate the dynamicly created label. below is my code: if ((InputBox.Text.StartsWith("p")) && (InputBox.Text.EndsWith("}")))// only process if the message starts with p and ends with } { string Message = InputBox.Text; InputBox.Text = "";// Clear the box when done. // Butt1 message line if (Message.StartsWith("plabelt1")) { if (Message.StartsWith("plabelt1_BackColor")) { Message = Message.Substring(19); //labelt1.BackColor = System.Drawing.Color.FromName(Message.Replace("}", "")); } } private void ImageBox_DragDrop(object sender, DragEventArgs e) { //Graphics g = ImageBox.CreateGraphics(); //g.DrawImage((Image)e.Data.GetData(DataFormats.Bitmap), //new Point(e.X - this.Left, e.Y - this.Top - 150)); Point p2 = PointToClient(Cursor.Position); Label buttlbl_ = new Label(); labelCount++; buttlbl_.Name = "labelt" + labelCount.ToString(); buttlbl_.Location = new Point(p2.X, p2.Y); buttlbl_.Size = new System.Drawing.Size(37, 37); buttlbl_.BackColor = System.Drawing.Color.DarkGray; this.Controls.Add(buttlbl_); buttlbl_.BringToFront(); ImageBox.Invalidate(); } } Any suggestions?

    Read the article

  • Iterating over a String to check for a number and printing out the String value if it doesn't have a number

    - by wheelerlc64
    I have set up my function for checking for a number in a String, and printing out that String if it has no numbers, and putting up an error message if it does. Here is my code: public class NumberFunction { public boolean containsNbr(String str) { boolean containsNbr = false; if(str != null && !str.isEmpty()) { for(char c : str.toCharArray()) { if(containsNbr = Character.isDigit(c)) { System.out.println("Can't contain numbers in the word."); break; } else { System.out.println(str); } } } return containsNbr; } } import com.imports.validationexample.function.NumberFunction; public class Main { public static void main(String[] args) { NumberFunction nf = new NumberFunction(); System.out.println(nf.containsNbr("bill4")); } } I am trying to get it to print out the result to the console, but the result keeps printing multiple times and prints the boolean value, which I do not want, something like this: bill4 bill4 bill4 bill4 Can't contain numbers in the word. true Why is this happening? I've tried casting but that hasn't worked out either. Any help would be much appreciated.

    Read the article

  • Handling primary key duplicates in a data warehouse load

    - by Meff
    I'm currently building an ETL system to load a data warehouse from a transactional system. The grain of my fact table is the transaction level. In order to ensure I don't load duplicate rows I've put a primary key on the fact table, which is the transaction ID. I've encountered a problem with transactions being reversed - In the transactional database this is done via a status, which I pick up and I can work out if the transaction is being done, or rolled back so I can load a reversal row in the warehouse. However, the reversal row will have the same transaction ID and so I get a primary key violation. I've solved this for now by negating the primary key, so transaction ID 1 would be a payment, and transaction ID -1 (In the warehouse only) would be the reversal. I have considered an alternative of generating a BIT column, where 0 is normal and 1 is reversal, then making the PK the transaction ID and the BIT column. My question is, is this a good practice, and has anyone else encountered anything like this? For reference, this is a payment processing system, so values will not be modified, so there will only ever be transactions and reversals.

    Read the article

  • How to get two TD cells side by side WITHOUT using css

    - by Joe
    Hi, in the following HTML snippet, I would like the two cells be placed side by side with NO spaces between them; without using css if possible. If the leftmost position of the 2nd one is the rightmost position of the 1st, why WOULD they have any space between? thx. <TR> <TD style="position:absolute; top:98px; left:0px; right:56px; bottom:126px; font-size: 7pt; background-color:Lime; text-align: center; font-family: Arial;" cellpadding="0" cellspacing="0">ABC</TD> <TD style="position:absolute; top:98px; left:56px; right:112px; bottom:126px; font-size: 7pt; background-color:Lime; text-align: center; font-family: Arial;" cellpadding="0" cellspacing="0">123</TD>

    Read the article

  • selected area to cut an image

    - by Oskar Marciniak
    Hi I would do the selected area to cut an image on picturebox control. I have the following code: using System; using System.Drawing; using System.Windows.Forms; namespace WindowsFormsApplication1 { public partial class Form1 : Form { private Rectangle rect; private Pen p; public Form1() { InitializeComponent(); } private void pictureBox1_Paint(object sender, PaintEventArgs e) { if (this.p == null) this.p = new Pen(Color.FromArgb(100, 200, 200, 200), 5); if (this.rect.Width > 0) e.Graphics.DrawRectangle(this.p, this.rect); } private void pictureBox1_MouseUp(object sender, MouseEventArgs e) { if (e.X < this.rect.X) { this.rect.Width = this.rect.X - e.X; this.rect.X = e.X; } else { this.rect.Width = e.X - this.rect.X; } if (e.Y < this.rect.Y) { this.rect.Height = this.rect.Y - e.Y; this.rect.Y = e.Y; } else { this.rect.Height = e.Y - this.rect.Y; } this.Invalidate(this.rect); } private void pictureBox1_MouseDown(object sender, MouseEventArgs e) { this.rect.X = e.X; this.rect.Y = e.Y; } } } It returns an error here: Application.Run(new Form1()); Why? thanks for all replies ;p

    Read the article

  • Can I make a derived class inherit a derived member from its base class in Java?

    - by Eric
    I have code that looks like this: public class A { public void doStuff() { System.out.print("Stuff successfully done"); } } public class B extends A { public void doStuff() { System.out.print("Stuff successfully done, but in a different way"); } public void doMoreStuff() { System.out.print("More advanced stuff successully done"); } } public class AWrapper { public A member; public AWrapper(A member) { this.member = member; } public void doStuffWithMember() { a.doStuff(); } } public class BWrapper extends AWrapper { public B member; public BWrapper(B member) { super(member); //Pointer to member stored in two places: this.member = member; //Not great if one changes, but the other does not } public void doStuffWithMember() { member.doMoreStuff(); } } However, there is a problem with this code. I'm storing a reference to the member in two places, but if one changes and the other does not, there could be trouble. I know that in Java, an inherited method can narrow down its return type (and perhaps arguments, but I'm not certain) to a derived class. Is the same true of fields?

    Read the article

  • Problem monitoring directory for file activity in VB.net 2010...

    - by Mike Cialowicz
    I'm trying to write a simple program to monitor a folder for new files in VB.NET 2010, and am having some trouble. Here's a simplified version of what my program looks like: Imports System.IO Public Class Main Public fileWatcher As FileSystemWatcher Sub btnGo_Click(sender As System.Object, e As System.EventArgs) Handles btnGo.Click '//# initialize my FileSystemWatcher to monitor a particular directory for new files fileWatcher = New FileSystemWatcher() fileWatcher.Path = thisIsAValidPath.ToString() fileWatcher.NotifyFilter = NotifyFilters.FileName AddHandler fileWatcher.Created, AddressOf fileCreated fileWatcher.EnableRaisingEvents = True End Sub Private Sub fileCreated(sender As Object, e As FileSystemEventArgs) '//# program does not exit when I comment the line below out txtLatestAddedFilePath.Text = e.FullPath '//# e.FullPath is valid when I set a breakpoint here, but when I step into the next line, the program abruptly halts with no error code that I can see End Sub End Class As you can see, I have a button which will initialize a FileSystemWatcher when clicked. The initialization works, and when I place a new file in the monitored directory, the program reaches the fileCreated sub. I can even see that e.FullPath is set correctly. However, it exits abruptly right after that with no error code (none that I can see, anyways). If I comment everything in the fileCreated sub out, the program continues running as expected. Any ideas as to why it's dying on me? Any help would be greatly appreciated. I'm fairly new to VS/VB.NET, so maybe I'm just making a silly mistake. Thanks!

    Read the article

  • Dojo's nested BorderContainer disappear in IE

    - by h4b0
    I have this terrible problem with IE 7/8/9. I wrote an app using Dojo toolkit 1.8.0 and Play! framework. It works fine in all browser except for IE. Its 'developers tools' show no error, so does firebug. The problematic code section is here: <div data-dojo-type="dijit.layout.BorderContainer" data-dojo-props="design: 'headline'"> <div data-dojo-type="dijit.layout.ContentPane" id="head" region="top"> </div> <div data-dojo-type="dijit.layout.BorderContainer" data-dojo-props="region: 'center'"> <div data-dojo-type="dijit.layout.ContentPane" id="menu" region="left"> </div> <div data-dojo-type="dijit.layout.BorderContainer" data-dojo-props="region: 'center'"> <div data-dojo-type="dijit.layout.ContentPane" id="content_1" region="top"> </div> <div data-dojo-type="dijit.layout.ContentPane" id="content_2" region="bottom"> </div> </div> </div> <div data-dojo-type="dijit.layout.ContentPane" id="foot" region="bottom"> </div> </div> The result, in all browsers except for IE is like that: But in IE it is shown like that: Can anyone explain why there are such differences? At first I thought that in IE content is hidden, so I set overflow: auto, but no scrollbar appeared after page load.

    Read the article

  • Background loading javascript into iframe with using jQuery/Ajax?

    - by user210099
    I'm working on an offline only help system which requires loading a large amount of search-related data into an iframe before the search functionality can be used. Due to the folder structure of the project, I am unable to use Ajax-related background load methods, since the files I need are loaded a few directories "up and over." I have written some code which delays the loading of the help data until the rest of the webpage is loaded. The help data consists of a bunch of javascript files which have information about the terms, ect that exist in the help books which are installed on the system. The webpage works fine, until I start to load this help data into a hidden iframe. While the javascript files are loading, I can not use any of the webpage. Links that require a small files be downloaded for hover over effects don't show up, javascript (switching tabs on the page) has no effect. I'm wondering if this is just a limitation of the way javascript works, or if there's something else going on here. Once all the files are loaded for the help system, the webpage works as expected. function test(){ var MGCFrame = eval("parent.parent"); if((ALLFRAMESLOADED == true)){ t2 = MGCFrame.setTimeout("this.IHHeader.frames[0].loadData()",1); } else{ t1 = MGCFrame.setTimeout("this.IHHeader.frames[0].test()",1000); } } Load data simply starts the data loading process. Thanks for any help you can provide.

    Read the article

  • list all files from directories and subdirectories in Java

    - by Adnan
    What would be the fastest way to list the names of files from 1000+ directories and sub-directories? EDIT; The current code I use is: import java.io.File; public class DirectoryReader { static int spc_count=-1; static void Process(File aFile) { spc_count++; String spcs = ""; for (int i = 0; i < spc_count; i++) spcs += " "; if(aFile.isFile()) System.out.println(spcs + "[FILE] " + aFile.getName()); else if (aFile.isDirectory()) { System.out.println(spcs + "[DIR] " + aFile.getName()); File[] listOfFiles = aFile.listFiles(); if(listOfFiles!=null) { for (int i = 0; i < listOfFiles.length; i++) Process(listOfFiles[i]); } else { System.out.println(spcs + " [ACCESS DENIED]"); } } spc_count--; } public static void main(String[] args) { String nam = "D:/"; File aFile = new File(nam); Process(aFile); } }

    Read the article

  • For each loop not reading in the last item

    - by Gandalf StormCrow
    I'm trying to read in a multi line string then split it then print it .. here is the string : 1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T 11X21b1X 4X1b1X When I split the string with ! I get this without the last line string : 1T1b5T 1T1b5T1T2b1T1b2T 1T2b1T1b2T1T1b1T2b2T 1T1b1T2b2T1T3b1T1b1T 1T3b1T1b1T3T3b1T 3T3b1T1T3b1T1b1T 1T3b1T1b1T5T1*1T 5T1*1T11X21b1X 11X21b1X Here is my code : import java.io.BufferedInputStream; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner stdin = new Scanner(new BufferedInputStream(System.in)); while (stdin.hasNext()) { for (String line : stdin.next().split("!")) { System.out.println(line); for (int i = 0; i < line.length(); i++) { System.out.print(line.charAt(i)); } } } } } Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you

    Read the article

  • Making A Dynaically Created Excel Report Downloadable

    - by Nick LaMarca
    I have 2 blocks of code, if someone could help me put them together I would get the functionality I am looking for. The first block of code downloads a gridview to excel using the download dialog I am looking for: Public Overloads Overrides Sub VerifyRenderingInServerForm(ByVal control As Control) ' Verifies that the control is rendered End Sub Private Sub ExportToExcel(ByVal filename As String, ByVal gv As GridView, ByVal numOfCol As Integer) Response.Clear() Response.Buffer = True Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", filename)) Response.Charset = "" Response.ContentType = "application/vnd.ms-excel" Dim sw As New StringWriter() Dim hw As New HtmlTextWriter(sw) gv.AllowPaging = False gv.DataBind() 'Change the Header Row back to white color gv.HeaderRow.Style.Add("background-color", "#FFFFFF") For i As Integer = 0 To numOfCol - 1 gv.HeaderRow.Cells(i).Style.Add("background-color", "blue") gv.HeaderRow.Cells(i).Style.Add("color", "#FFFFFF") Next For i As Integer = 0 To gv.Rows.Count - 1 Dim row As GridViewRow = gv.Rows(i) 'Change Color back to white row.BackColor = System.Drawing.Color.White For j As Integer = 0 To numOfCol - 1 row.Cells(j).Style.Add("text-align", "center") Next 'Apply text style to each Row row.Attributes.Add("class", "textmode") 'Apply style to Individual Cells of Alternating Row If i Mod 2 <> 0 Then For j As Integer = 0 To numOfCol - 1 row.Cells(j).Style.Add("background-color", "#CCFFFF") row.Cells(j).Style.Add("text-align", "center") '#C2D69B 'row.Cells(j).Style.Add("font-size", "12pt") Next End If Next gv.RenderControl(hw) 'style to format numbers to string Dim style As String = "<style> .textmode { mso-number-format:\@; } </style>" Response.Write(style) Response.Output.Write(sw.ToString()) Response.Flush() Response.End() End Sub The second block of code is a sample report I am wish to be downloaded. So instead of downloading a gridview I want this function to accept a worksheet object.

    Read the article

  • Extend footer wrap to width of page.

    - by hawkeye126
    I've made a footer wrap outside the content wrap (which everything else is in). I would like to make the footer wrap extend to fill the width of the page and I would like it to be fixed on the bottom. Here's the code: footerWrap { background-color:#000; width: auto; } footer { margin: auto; text-align:center; width:965px; height:150px; background-color:#000; border:#000 inset medium; } The website is item9andthemadhatters.com please let me know if you need any other code or info. Thanks!! update: html { padding:0; height:100%; width: 100%; } body{ margin: -1px 0 0 0; background-color:#FFF; font-family: calibri; background-image:url(images/item9HeaderSideFiller.gif); background-repeat: repeat-x; padding:0; height:100%; width: 100%; } wrap { width: 965px; margin:auto auto; min-height:462px; max-height:4000 px; footerWrap { background-color:#000; position:absolute; bottom:0; width:100% } footer { margin: auto; text-align:center; width:965px; height:150px; background-color:#000; } }

    Read the article

  • How best to present a security vulnerability to a web development team in your own company?

    - by BigCoEmployee
    Imagine the following scenario: You work at Big Co. and your coworkers down the hall are on the web development team for Big Co's public blog system, which a lot of Big Co employees and some public people use. The blog system allows any HTML and JavaScript, and you've been told that it was a choice (not by accident) but you aren't sure if they realize the implications of this. So you want to convince them that this is a bad idea. You write some demonstration code and plant a XSS script in your own blog, and then write some blog posts. Soon after, the head blog admin (down the hall) visits your blog post and the XSS sends his cookies to you. You copy them into your browser and you are now logged in as him. Okay, now you're logged in as him... And you start realizing that it maybe wasn't such a good idea to go ahead and 'hack' the blog system. But you are a good guy! You don't touch his account after logging into it, and you definitely don't plan on publicizing this weakness; you just maybe want to show them that the public is able to do this, so that they can fix it before someone malicious realizes the same thing! What is the best course of action from here?

    Read the article

  • Creation of AsyncTask taking too much time Android

    - by user2842342
    I am making a network call in an AsyncTask, but the problem i am facing is the amount of time it is taking to start the doInBackground method. Here is a part of my code: button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.d("Temp:",System.currentTimeMillis()+""); new Move().execute(); /*some other logic } } And my AsyncTask is: private class Move extends AsyncTask<Void, Void, Void> { @Override protected Void doInBackground(Void... temp) { Log.d("start:",System.currentTimeMillis()+""); gson.fromJson(Web.Request.get(some_URL),Void.class); Log.d("end:",System.currentTimeMillis()+""); return null; } } These are the logs i got: 32658-998/com.example.game D/temp:? 1408923006159 32658-998/com.example.game D/start:? 1408923035163 32658-998/com.example.game D/end:? 1408923035199 So actually it took almost 29 secs to reach the first line in doInBackground method, where as it took just 36 ms to finish the network call. I tried it many times, the time taken is almost in the same order. Is it possible to start the AsyncTask immediately? Or is there any other way to solve this problem.(other than a running a simple thread?) Thank you :)

    Read the article

  • Java socket bug on linux (0xFF sent, -3 received)

    - by Marius
    While working on a WebSocket server in Java I came across this strange bug. I've reduced it down to two small java files, one is the server, the other is the client. The client simply sends 0x00, the string Hello and then 0xFF (per the WebSocket specification). On my windows machine, the server prints the following: Listening byte: 0 72 101 108 108 111 recieved: 'Hello' While on my unix box the same code prints the following: Listening byte: 0 72 101 108 108 111 -3 Instead of receiving 0xFF it gets -3, never breaks out of the loop and never prints what it has received. The important part of the code looks like this: byte b = (byte)in.read(); System.out.println("byte: "+b); StringBuilder input = new StringBuilder(); b = (byte)in.read(); while((b & 0xFF) != 0xFF){ input.append((char)b); System.out.print(b+" "); b = (byte)in.read(); } inputLine = input.toString(); System.out.println("recieved: '" + inputLine+"'"); if(inputLine.equals("bye")){ break; } I've also uploaded the two files to my server: Server.java Client.java My Windows machine is running windows 7 and my Linux machine is running Debian

    Read the article

  • Background loading javascript into iframe without using jQuery/Ajax?

    - by user210099
    I'm working on an offline only help system which requires loading a large amount of search-related data into an iframe before the search functionality can be used. Due to the folder structure of the project, I am unable to use Ajax-related background load methods, since the files I need are loaded a few directories "up and over." I have written some code which delays the loading of the help data until the rest of the webpage is loaded. The help data consists of a bunch of javascript files which have information about the terms, ect that exist in the help books which are installed on the system. The webpage works fine, until I start to load this help data into a hidden iframe. While the javascript files are loading, I can not use any of the webpage. Links that require a small files be downloaded for hover over effects don't show up, javascript (switching tabs on the page) has no effect. I'm wondering if this is just a limitation of the way javascript works, or if there's something else going on here. Once all the files are loaded for the help system, the webpage works as expected. function test(){ var MGCFrame = eval("parent.parent"); if((ALLFRAMESLOADED == true)){ t2 = MGCFrame.setTimeout("this.IHHeader.frames[0].loadData()",1); } else{ t1 = MGCFrame.setTimeout("this.IHHeader.frames[0].test()",1000); } } Load data simply starts the data loading process. Thanks for any help you can provide.

    Read the article

  • How is machine code understood by the machine

    - by Kraken
    I have a very naive question here, and I would like you to correct me on whatever wrong concepts I put out here. The question is as follows: I have ubuntu installed on my machine, now I write a helloWorld.c program in C language. Now, on the operating system I have a compiler installed, when I execute my helloWorld.c program, the OS schedules the compiler and that basically compiles my code into machine code, which eventually, I execute. Now my kernel code is written in C, then how does my machine interprets that code? Say my kernel code is helloWorld.c, now would not I require any compiler, to compile this code. Also, if I hardcode a compiler in maybe ROM or something, then what language is it written in? Assembly language? Let me know if I have made myself clear with the problem. Thanks. EDIT: By kernel code I mean, the code for operating system. Operating System code. I guess it is written in C right?

    Read the article

  • Do running times match with O(nlogn)?

    - by user472221
    Hi I have written a class(greedy strategy) that at first i used sort method which has O(nlogn) Collections.sort(array, new SortingObjectsWithProbabilityField()); and then i used the insert method of binary search tree which takes O(h) and h here is the tree height. for different n ,the running time will be : n,running time 17,515428 33,783340 65,540572 129,1285080 257,2052216 513,4299709 which I think is not correct because for increasing n , the running time should almost increase. This method will take the running time: Exponent = -1; for(int n = 2;n<1000;n+=Math.pow(2,exponent){ for (int j = 1; j <= 3; j++) { Random rand = new Random(); for (int i = 0; i < n; i++) { Element e = new Element(rand.nextInt(100) + 1, rand.nextInt(100) + 1, 0); for (int k = 0; k < i; k++) { if (e.getDigit() == randList.get(k).getDigit()) { e.setDigit(e.getDigit() + 1); } } randList.add(e); } double sum = 0.0; for (int i = 0; i < randList.size(); i++) { sum += randList.get(i).getProbability(); } for (Element i : randList) { i.setProbability(i.getProbability() / sum); } //Get time. long t2 = System.nanoTime(); GreedyVersion greedy = new GreedyVersion((ArrayList<Element>) randList); long t3 = System.nanoTime(); timeForGreedy = timeForGreedy + t3 - t2; } System.out.println(n + "," + "," + timeForGreedy/3 ); exponent++; } thanks

    Read the article

  • Java: "cannot find symbol" error of a String[] defined within a while-loop

    - by David
    Here's the relevant code: public static String[] runTeams (String CPUcolor) { boolean z = false ; //String[] a = new String[6] ; boolean CPU = false ; while (z == false) { while (CPU==false) { String[] a = assignTeams () ; printOrder (a) ; for (int i = 1; i<a.length; i++) { if (a[i].equals(CPUcolor)) CPU = true ; } if (CPU==false) { System.out.println ("ERROR YOU NEED TO INCLUDE THE COLOR OF THE CPU IN THE TURN ORDER") ; } } System.out.println ("is this turn order correct? (Y/N)") ; String s = getIns () ; while (!((s.equals ("y")) || (s.equals ("Y")) || (s.equals ("n")) || (s.equals ("N")))) { System.out.println ("try again") ; s = getIns () ; } if (s.equals ("y") || s.equals ("Y") ) z = true ; } return a ; } the error i get is: Risk.java:416: cannot find symbol symbol : variable a location: class Risk return a ; ^ Why did i get this error? It seems that a is clearly defined in the line String[] a = assignTeams () ; and if anything is used by the lineprintOrder (a) ;` it seems to me that if the symbol a really couldn't be found then the compiler should blow up there and not at the return statment. (also the method assignTeams returns an array of Strings.)

    Read the article

  • Qt - 2 QMainWindow glued - Size of Layout

    - by user1773603
    I have a main window that I center this way in main.cpp : int main(int argc, char *argv[]) { QApplication app(argc, argv); QMainWindow *qmain = new QMainWindow; Ui_MainWindow ui; ui.setupUi(qmain); QRect r = qmain->geometry(); r.moveCenter(QApplication::desktop()->availableGeometry().center()); qmain->setGeometry(r); qmain->show(); return app.exec(); } In this "qmain" main window, I can create another QMainWindow and I try to make stick (or glue I don't know how to say) the two windows. Actually, I would like the right-top corner of the first one to be located at the left-top of the second one. For this, I use the following Ui_MainWindow's member function : void Ui_MainWindow::generate_IC() { qmenu = new QMainWindow; DiskMenu = new Ui_DiskGalMenu; DiskMenu->setupUi(qmenu); setInitialDiskMenuPosition(qmenu, this); qmenu->show(); } and the setInitialDiskMenuPosition : void Ui_MainWindow::setInitialDiskMenuPosition(QMainWindow *MainWindow, Ui_MainWindow *parent) { QSize size = parent->widget->size(); QDesktopWidget* desktop = QApplication::desktop(); int width = desktop->width(); int height = desktop->height(); int mw = size.width(); int mh = size.height(); int right = (width/2) + (mw/2); int top = (height/2) - (mh/2); MainWindow->move(right, top); } But the problem is that I don't get exactly what I want since the centralwidget size "parent- widget-size()" only returns the size of the widget and not the whole "qmain" parent window. So I have a light shift because the borders of the "qmain" window are not taken in account like it is shown below : If I could have access to the size of the whole parent window... If anyone could help me

    Read the article

  • Reverse wildcard search in codeigniter

    - by Andy Platt
    I am implementing a snippet-based content management system into my current project. Snippets can be associated with a page either by exact match of the full url falling back to a wildcard match on a partial url or finally a default snippet. To implement this I have a created table of page associations with a wildcard flag, the system first checks the current url against the non-wildcard associations and if it doesn't find a match it checks against the partial url's where the wildcard flag is set. In order to achieve this I am getting all the partial url's from the database and putting them into an array then walking the array to check for a match against the current url: protected function _check_wildcard($url = NULL) { if($url) { $q = $this->db->where('wildcard' ,'Y') ->from('content') ->get(); $wildcards = $q->result_array(); foreach($wildcards AS $wildcard) { if(strpos($url,$wildcard['url']) > 0) { return $wildcard['snipppet_id']; } } } else { return NULL; } } Can anyone suggest a better way to do this - preferably one that doesn't involve having to constantly download the full list of all the wildcards each time I load a page as I am afraid that this will have a negative effect on the scalability of the system down the line?

    Read the article

  • C# Custom user settings class not saving

    - by Zenox
    I have the following class: [Serializable] [XmlRoot ( ElementName = "TextData", IsNullable = false)] public class TextData { private System.Drawing.Font fontColor; [XmlAttribute ( AttributeName = "Font" )] public System.Drawing.Font Font { get; set; } [XmlAttribute ( AttributeName = "FontColor" )] public System.Drawing.Color FontColor { get; set; } [XmlAttribute ( AttributeName = "Text" )] public string Text { get; set; } public TextData ( ) { } // End of TextData } // End of TextData And Im attempting to save it with the following code: // Create our font dialog FontDialog fontDialog = new FontDialog ( ); fontDialog.ShowColor = true; // Display the dialog and check for an ok if ( DialogResult.OK == fontDialog.ShowDialog ( ) ) { // Save our changes for the font settings if ( null == Properties.Settings.Default.MainHeadlineTextData ) { Properties.Settings.Default.MainHeadlineTextData = new TextData ( ); } Properties.Settings.Default.MainHeadlineTextData.Font = fontDialog.Font; Properties.Settings.Default.MainHeadlineTextData.FontColor = fontDialog.Color; Properties.Settings.Default.Save ( ); } Everytime I load the the application, the Properties.Settings.Default.MainHeadlineTextData is still null. Saving does not seem to take effect. I read on another post that the class must be public and it is. Any ideas why this would not be working properly?

    Read the article

  • Use a table as container or not?

    - by Camran
    I have created my entire website by using a main table, and having the content inside the table. Some ppl suggest this is wrong, and I would like to know what to do specifically in my situation. On my index.html I have a <table align="center"> and then all content in it. Now the content is in form of DIVS and they all have relative positioning, so they are relative to the table. For example: <table align="center"> <tr> <td> <div style="position:relative; left:14px; top:50px;"> CONTENT HERE... (Form, divs, images) </div> </td> </tr> </table> I have just gotten to the stage of browser compatibility. Without making any changes whatsoever, my website works perfect in FF, SAFARI, Chrome and Opera. Only trouble with IE. So for my Q, if you where me, would you change my layout and remove the tables, and instead use alot more css and alot more DIVS, or would you go with what I have? And please if you answer me, don't just provide me with the answer, but also a "why" that is... in other words, give me arguments and facts... Thanks

    Read the article

  • Dynamically changing layout

    - by LTMOD
    I have a 2 x 2 grid of buttons. Each row of 2 is wrapped in a horizontal linear layout. <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="100dip"> <Button android:layout_weight=".5" android:id="@+id/btn1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_gravity="center_vertical|center_horizontal" android:padding="5dip" android:layout_margin="2dip"> </Button> <Button android:layout_weight=".5" android:id="@+id/btn2" android:layout_width="fill_parent" android:layout_height="fill_parent" android:padding="5dip" android:layout_margin="2dip"> </Button> At times I want to show all 4 buttons, and other times, I show the top 2 only, and sometimes, I need to show 2 on top, and one on the bottom. I would like to center the bottom one, but can't seem to accomplish this. In my code, I call btn4.setVisibility(8); //8 = GONE, which makes my 4th button disappear, but then btn3 ends up filling the entire layout. What I would like it to do instead is center itself within the layout at its correct width / height. I'm a bit new to this, so any help is greatly appreciated. Thanks in advance!

    Read the article

< Previous Page | 631 632 633 634 635 636 637 638 639 640 641 642  | Next Page >