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  • jquery find() function not working on ie. (ie 8) not tested on others

    - by Val
    I have a tiny problem: I am trying to use the find function to get data from an external page. here is the code can some one please help me why doesnt it work on ie? index.php <div id="testing">Hello Worlds</div> jquery var txt=$('<div id="Temp"></div>').hide().appendTo('body'); var t; $('#Temp').load('index.php',null,function (t){ t = $('#Temp').find('#testing').text(); alert(t); }) Please help me... it works well on fireworks and chrome result should be to alert "Hello Worlds" instead its blank.

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  • What is the advantage of creating an enumerable object using to_enum in Ruby?

    - by Jason
    Hi, Why would you create a proxy reference to an object in Ruby, by using the to_enum method rather than just using the object directly? I cannot think of any practical use for this, trying to understand this concept & where someone might use it, but all the examples I have seen seem very trivial. For example, why use: "hello".enum_for(:each_char).map {|c| c.succ } instead of "hello".each_char.map {|c| c.succ } I know this is a very simple example, does anyone have any real-world examples? Thanks!

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  • No response in Eclipse: File ->Import->Existing Projects into Workspace

    - by Hula
    I'm trying to import one of the GWT samples into Eclipse by following the instructions below. But when I browse to the directory containing the "Hello" sample and uncheck "Copy projects into workspace", the Finish button is grayed out, preventing me from completing the import. Any ideas why? -- Option A: Import your project into Eclipse (recommended) -- If you use Eclipse, you can simply import the generated project into Eclipse. We've tested against Eclipse 3.3 and 3.4. Later versions will likely also work, earlier versions may not. In Eclipse, go to the File menu and choose: File - Import... - Existing Projects into Workspace Browse to the directory containing this file, select "Hello". Be sure to uncheck "Copy projects into workspace" if it is checked. Click Finish.

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  • Why Timer does not work if we do not generate a window?

    - by Roman
    Here is the code: import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JFrame; import javax.swing.Timer; public class TimerSample { public static void main(String args[]) { new JFrame().setVisible(true); ActionListener actionListener = new ActionListener() { public void actionPerformed(ActionEvent actionEvent) { System.out.println("Hello World Timer"); } }; Timer timer = new Timer(500, actionListener); timer.start(); } } It generates a window and then periodically prints "Hello World Timer" in the terminal (Command Prompt). If I comment this line new JFrame().setVisible(true); the application do not print anything to the command line. Why?

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  • PHP: Remove blank line before text

    - by Bailey
    Occasionally, my email-to-support-ticket system catches an extra line break before the message itself, thus my messages look like this: " Hello. I have been wondering if y..." What can I use to get rid of that line before the text? It is on random occasion due to email providers and the way they format their emails using mime. I have already tried the trim functions but no luck. (Yes, I also tried ltrim) Once processed it should look like: "Hello. I have been wondering if y..."

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  • Eclipse bug? Switching on a null with only default case

    - by polygenelubricants
    I was experimenting with enum, and I found that the following compiles and runs fine on Eclipse (Build id: 20090920-1017, not sure exact compiler version): public class SwitchingOnAnull { enum X { ,; } public static void main(String[] args) { X x = null; switch(x) { default: System.out.println("Hello world!"); } } } When compiled and run with Eclipse, this prints "Hello world!" and exits normally. With the javac compiler, this throws a NullPointerException as expected. So is there a bug in Eclipse Java compiler?

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  • Bash redirection: save stderr/stdout to different files and still print them out on a console

    - by Alby
    Here is a simple program. class Redirection { public static void main (String args[]){ System.out.println("Hello World_Stdout"); System.err.println("Hello World_Stderr"); } } I want to see the all the outputs on a console, but at the same time I want to store stdout and stderr in different files. I tried the following command, to no avail. $java Redirection 3>&1 2>stderr 1>stdout 1>&3 2>&3 stderr& stdout files have the file size of 0. So basically I want to do what "tee" command does but I also want to capture stderr as well.

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  • Java generic Interface performance

    - by halfwarp
    Simple question, but tricky answer I guess. Does using Generic Interfaces hurts performance? Example: public interface Stuff<T> { void hello(T var); } vs public interface Stuff { void hello(Integer var); <---- Integer used just as an example } My first thought is that it doesn't. Generics are just part of the language and the compiler will optimize it as though there were no generics (at least in this particular case of generic interfaces). Is this correct?

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  • Why is Python 3.1 throwing a SyntaxError when printing after loop?

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

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  • can I put the break on the same line

    - by brett
    I have a switch statement that has over 300 case statements. case 'hello': { $say = 'some text'; } break; case 'hi': { $say = 'some text'; } break; Why is it that the break is always on a separate line? Is this required? Is there anything syntactically incorrect about me doing this: case 'hello': { $say = 'some text'; } break; case 'hi': { $say = 'some text'; } break;

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  • What is the difference between these two ways of creating NSStrings?

    - by adame
    NSString *myString = @"Hello"; NSString *myString = [NSString stringWithString:@"Hello"]; I understand that using method (1) creates a pointer to a string literal that is defined as static memory (and cannot be deallocated) and that using (2) creates an NSString object that will be autoreleased. Is using method (1) bad? What are the major differences? Is there any instances where you would want to use (1)? Is there a performance difference? P.S. I have searched extensively on Stack Overflow and while there are questions on the same topic, none of them have answers to the questions I have posted above.

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  • JavaScript prototype(ing) question

    - by OneNerd
    Trying to grasp Prototyping in Javascript. Trying to create my own namespace to extend the String object in JavaScript. Here is what I have so far (a snippet): var ns { alert: function() { alert (this); } } String.prototype.$ns = ns; As you can see, I am trying to place what will be a series of functions into the ns namespace. So I can execute a command like this: "hello world".$ns.alert(); But the problem is, the this doesn't seem to reference the text being sent (in this case, "hello world"). What I get is an alert box with the following: [object Object] Not having a full grasp of the object-oriented nature of JavaScript, I am at a loss, but I am guessing I am missing something simple. Does anyone know how to achieve this? Thanks -

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  • Easy way to cast an object array into another type in C#

    - by Na7coldwater
    I want to be able to be able to quickly cast an array of objects to a different type, such as String, but the following code doesn't work: String[] a = new String[2]; a[0] = "Hello"; a[1] = "World"; ArrayList b = new ArrayList(a); String[] c = (String[]) b.ToArray(); And I don't want to have to do this: String[] a = new String[2]; a[0] = "Hello"; a[1] = "World"; ArrayList b = new ArrayList(a); Object[] temp = b.ToArray(); Object[] temp = b.ToArray(); String[] c = new String[temp.Length]; for(int i=0;i<temp.Length;i++) { c[i] = (String) temp[i]; } Is there an easy way to do this without using a temporary variable?

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  • Google app engine-php: script handler

    - by Eve
    I try to create php web app using GAE. In the GAE tutorial, "A script handler executes a PHP script to handle the request that matches the URL pattern. The mapping defines a URL pattern to match, and the script to be executed" Now I want to map the url with the file having same name in the folder, e.g. if the url is /hello.* , it will map the file name hello.php in the folder. And if it is /hello1.*, hello1.php in the folder will be responded to the server. I thought this should be done directly by mapping the name of the url with the name in the folder. But if I left empty for the handler in the app.yaml, I got an error. So I want to know how to set up the handler in app.yaml?

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