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  • Round bottom corners on Android Bitmap?

    - by alex
    Hey all, what would be best practice for clipping the bottom borders of a Bitmap? Just manipulate the Bitmap itself or overlay an alpha mask drawable or ...? The whole story: I've a Listview which looks like the iPhone's grouped UITableView style. I would like to display a Bitmap in the last row, but for now the Bitmap overlaps my custom background drawable of the Listview cell. Thx in advance!

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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  • Not able to play videos (from youtube) in WebView

    - by user1205193
    I am using a webview to display a video (could be from youtube or vimeo) in my app. In order to not load the video webpages in the default Android Browser, I am also extending the WebViewClient so I can override the shouldOverrideUrlLoading method. This way the video webpage loads successfully in the WebView. However, when I click on the embedded video on the WebView, it does not play. If I do not override the shouldOverrideUrlLoading method, and let the video webpages load in the default Android browser, the videos work just fine. Any ideas why the videos are not working in the WebView? Also, the main reason why I overrode the shouldOverrideUrlLoading method is because if I do not do that, then when I exit the Android browser to come back to my activity (by hitting the back button on the phone), I see a white screen. Upon hitting the back button twice, I am able to get back to my Activity. I am using the emulator to do this test. Here is my code: public class YoutubeLink extends Activity { WebView myWebView; String video_url; private class HelloWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } } @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.youtubelink); //Retrieving data from ListSample.java Bundle extras = getIntent().getExtras(); if(extras !=null) { video_url = extras.getString("video_url"); Log.d("inside YoutubeLink.java", video_url); } myWebView = (WebView) findViewById(R.id.web); myWebView.getSettings().setJavaScriptEnabled(true); myWebView.setWebViewClient(new HelloWebViewClient()); myWebView.loadUrl(video_url); } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if ((keyCode == KeyEvent.KEYCODE_BACK) && myWebView.canGoBack()) { myWebView.goBack(); return true; } return super.onKeyDown(keyCode, event); }}

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  • Overriding iPhone shutter sound through SDK

    - by Suresh
    In my iPhone app, I am using the UIImagePickerController with source type UIImagePickerControllerSourceTypeCamera. When the user takes a picture, the phone plays the familiar camera shutter sound. How can I replace this with my own custom sound? I know it's possible because I've seen other apps from the App Store do it (e.g. Red Laser). Thanks in advance!

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  • How do I specify a project dependency with Hudson?

    - by Brett Ryan
    We have common library projects shared amongst many projects that are required to be checked out into a "Libraries" folder which a developer needs to checkout prior to opening the main project in visual studio. How I tell hudson that there is this dependency? I figured one thing I could do is setup a custom workspace and specify the location for all projects, but how do I wire up the dependency between them all? Is simply specifying "Build after other projects are built" enough?

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  • php request variables assigning $_GEt

    - by chris
    if you take a look at a previous question http://stackoverflow.com/questions/2690742/mod-rewrite-title-slugs-and-htaccess I am using the solution that Col. Shrapnel proposed- but when i assign values to $_GET in the actual file and not from a request the code doesnt work. It defaults away from the file as if the $_GET variables are not set The code I have come up with is- if(!empty($_GET['cat'])){ $_GET['target'] = "category"; if(isset($_GET['page'])){ $_GET['pageID'] = $_GET['page']; } $URL_query = "SELECT category_id FROM cats WHERE slug = '".$_GET['cat']."';"; $URL_result = mysql_query($URL_query); $URL_array = mysql_fetch_array($URL_result); $_GET['category_id'] = $URL_array['category_id']; }elseif($_GET['product']){ $_GET['target'] = "product"; $URL_query = "SELECT product_id FROM products WHERE slug = '".$_GET['product']."';"; $URL_result = mysql_query($URL_query); $URL_array = mysql_fetch_array($URL_result); print_r($URL_array); $_GET['product_id'] = $URL_array['product_id']; The original variable string that im trying to represent is /cart.php?Target=product&product_id=16142&category_id=249 And i'm trying to build the query string variables with code and including cart.php so i can use cleaner URL's So I have product/product-title-with-clean-url/ going to slug.php?product=slug Then the slug searches the db for a record with the matching slug and returns the product_id as in the code above.Then built the query string and include cart.php

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  • How to organize Drupal templates?

    - by picardo
    I created a few custom templates while modifying a theme (Acquia Prosper), and my usual practice is to put all my templates in this fashion: theme-name/templates/page/page-front.tpl.php But it didn't quite work this time. So I'm wondering why. I looked through the templates.php for a clue, but there is nothing there. My base theme where I used this organization was genesis, and in that theme it seems to work, but not in Acquia Prosper. Can anyone shed some light on this?

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  • Why do browsers encode special characters differently with ajax requests?

    - by Andrei Oniga
    I have a web application that reads the values of a few input fields (alphanumeric) and constructs a very simple xml that is passes to the server, using jQuery's $.ajax() method. The template for that xml is: <request> <session>[some-string]</session> <space>[some-string]</space> <plot>[some-string]</plot> ... </request> Sending such requests to the server when the inputs contain Finnish diacritical characters (such as ä or ö) raises a problem in terms of character encoding with different browsers. For instance, if I add the word Käyttötarkoitus" in one of the inputs, here's how Chrome and Firefox send EXACTLY the same request to the server: Chrome: <request> <session>{string-hidden}</session> <space>2080874</space> <plot>Käyttötarkoitus</plot> ... </request> FF 12.0: <request> <session>{string-hidden}</session> <space>2080874</space> <plot>Käyttötarkoitus</plot> ... </request> And here is the code fragment that I use to send the requests: $.ajax({ type: "POST", url: url, dataType: 'xml;charset=UTF-8', data: xml, success: function(xml) { // }, error: function(jqXHR, textStatus, errorThrown) { // } }); Why do I get different encodings and how do I get rid of this difference? I need to fix this problem because it's causing other on the server-side.

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  • DateTime.AddMonths question

    - by grady
    Hello, lets say, I have 28th of February 2010 and add one months to this date using AddMonths(1)...the resulting date is 28th of March, but not 31st of March, which I want. Is there a way to tweak that a bit so this works without adding custom code? Thanks!

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  • Tomcat does not pick up the class file - the JSP file is not displayed

    - by blueSky
    I have a Java code which is a controller for a jsp page, called: HomeController.java. Code is as follows: @Controller public class HomeController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/mypage") public String home() { System.out.println("HomeController: Passing through..."); return "home"; } } There is nothing especial in the jsp page: home.jsp. If I go to this url: http://localhost:8080/adcopyqueue/mypage I can view mypage and everything works fine. Also in the tomcat Dos page I can see the comment: HomeController: Passing through... As expected. Now under the same directory that I have HomeController.java, I've created another file called: LoginController.java. Following is the code: @Controller public class LoginController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/loginpage") public String login() { System.out.println("LoginController: Passing through..."); return "login"; } } And under the same place which I have home.jsp, I've created login.jsp. Also under tomcat folders, LoginController.class exists under the same folder that HomeController.class exists and login.jsp exists under the same folder which home.jsp exists. But when I go to this url: http://localhost:8080/adcopyqueue/loginpage Nothing is displayed! I think tomcat does not pick up LoginController.class b/c on the tomcat Dos window, I do NOT see this comment: LoginController: Passing through... Instead I see following which I do not know what do they mean? [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:34) got manifest [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:36) manifest entrie s 8 The structure and the code for HomeController.java and LoginController.java plus the jsp files match. I have no idea why tomcat sees one of the files and not the other? Clean build did not help. Does anybody have any idea? Any help is greatly appraciated.

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  • rails javascript_include_tag

    - by ash34
    Hi, I have a few custom .js files in my public/javascripts folder. The 'javascript_include_tag' adds script tags to the head element. Are these executed in the order in which they appear. If yes, how do I control the order in which these script tags are added to my html. thanks, ash

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  • Freelance Apple Mac Development

    - by morgs
    I'm looking to contract with a freelance Apple Mac developer to write a custom application for me. Can anyone point me in the direction of any good Apple Mac developers in the UK or Internationally or websites where I can upload my project requirements and obtain quotes? Thanks in advance!

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  • The youtube API sometimes throws error: Call to a member function children() on a non-object

    - by Anna Lica
    When i launch the php script, sometime works fine, but many other times it retrieve me this errror Fatal error: Call to a member function children() on a non-object in /membri/americanhorizon/ytvideo/rilevametadatadaurlyoutube.php on line 21 This is the first part of the code // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/dZec2Lbr_r8'; // read feed into SimpleXML object $entry = simplexml_load_file($feedURL); $video = parseVideoEntry($entry); function parseVideoEntry($entry) { $obj= new stdClass; // get nodes in media: namespace for media information $media = $entry->children('http://search.yahoo.com/mrss/'); //<----this is the doomed line 21 UPDATE: solution adopted for ($i=0 ; $i< count($fileArray); $i++) { // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/'.$fileArray[$i]; // read feed into SimpleXML object $entry = simplexml_load_file($feedURL); if ( is_object($entry)) { $video = parseVideoEntry($entry); echo ($video->description."|".$video->length); echo "<br>"; } else { $i--; } } In this mode i force the script to re-check the file that caused the error

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  • Using JQuery in an AJAX control and avoiding conflicts

    - by Rich Andrews
    Hi, I am using JQuery within a custom AJAX user control (part of a home grown toolkit) and I need to ensure that JQuery is present on the hosting page. There can be multiple instances of the control on a page and some controls may need to use different versions of JQuery. At the moment I am using the following code to load in JQuery when the control initializes... Page.ClientScript.RegisterClientScriptInclude(Page.GetType(), "jquery-1.4.4.min.js", this.ResolveUrl("TextControlPlugin/lib/jquery-1.4.4.min.js")); This works because the scriptmanager handles not putting multiple copies of the same script into he page. Problems... I cannot use JQuery statically in the calling page (I may not have a control on the page but need to use JQuery) The scriptmanager appears to handle only duplicate URL's and I will need to deploy it from potentially 2 different URL's (the calling page's copy and the controls copy) So, is there a way to isolate a version of JQuery to the context of my control that doesnt interfear with any use of JQuery from the calling page? The developer writing the page may not have access to the internals of the control. I have looked at JQuery.noConflict() but cannot seem to get it to work correctly - I believe I'm having problems with the order in which the scripts are injected into the page - I keep getting JQuery is undefined errors. Any help would be much appreciated

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  • CakePHP Observe field for validation check(already exists)

    - by deck john
    i have already user observe field in cakephp 1.3 Now i want to do the same thing in cakephp 2.0 I have one form.there is a one field named email. When user insert email. onblur there is a popup one message that displays "email already exists" or "right" for that i have write below code in my projects. the below code is my add file code <?php $options = array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exist'); echo $this->ajax->observeField('UserEmailId',array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exists')); ?> In my controller i have created one function like public function is_exist($id = null) { $result = "yes"; $this->set('existdata',$result); } i have also created is_exists.ctp fiel in view/uers. i dont know why its not working. i did the same thing in Cakephp 1.3 and its working file but not in cakephp 2.0 can anyone tell me how i implement this ? thanks in advance

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  • Jquery Sorting by Letter

    - by Batfan
    I am using jquery to sort through a group of paragraph tags (kudos to Aaron Harun). It pulls the value "letter" (a letter) from the url string and displays only paragraphs that start with that letter. It hides all others and also consolidates the list so that there are no duplicates showing. See the code: var letter = '<?php echo(strlen($_GET['letter']) == 1) ? $_GET['letter'] : ''; ?>' function finish(){ var found_first = []; jQuery('p').each(function(){ if(jQuery(this).text().substr(0,1).toUpperCase() == letter){ if(found_first[jQuery(this).text()] != true){ jQuery(this).addClass('current-series'); found_first[jQuery(this).text()] = true; }else{ jQuery(this).hide(); } } else{ jQuery(this).hide();} }) } Been working with this all day and I have 2 Questions on this: Is there a way to get it to ignore the word 'The', if it's first? For example, if a paragraph starts with 'The Amazing', I would like it to show up on the 'A' page, not the 'T' page, like it currently is. Is there a way to have a single page for (all) numbers? For example, the url to the page would be something similar to domain.com/index.php?letter=0 and this would show only the paragraph tags that start with a number, any number. I can currently do this with single numbers but, I would like 1 page for all numbers.

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