SQL -- How to combine three SELECT statements with very tricky requirements
- by Frederick
I have a SQL query with three SELECT statements. A picture of the data tables generated by these three select statements is located at www.britestudent.com/pub/1.png. Each of the three data tables have identical columns. I want to combine these three tables into one table such that:
(1) All rows in top table (Table1) are always included.
(2) Rows in the middle table (Table2) are included only when the values in column1 (UserName) and column4 (CourseName) do not match with any row from Table1. Both columns need to match for the row in Table2 to not be included.
(3) Rows in the bottom table (Table3) are included only when the value in column4 (CourseName) is not already in any row of the results from combining Table1 and Table2.
I have had success in implementing (1) and (2) with an SQL query like this:
SELECT DISTINCT UserName AS UserName, MAX(AmountUsed) AS AmountUsed, MAX(AnsweredCorrectly) AS AnsweredCorrectly, CourseName, MAX(course_code) AS course_code, MAX(NoOfQuestionsInCourse) AS NoOfQuestionsInCourse, MAX(NoOfQuestionSetsInCourse) AS NoOfQuestionSetsInCourse
FROM ( "SELECT statement 1" UNION "SELECT statement 2" ) dt_derivedTable_1
GROUP BY CourseName, UserName
Where "SELECT statement 1" is the query that generates Table1 and "SELECT statement 2" is the query that generates Table2. A picture of the data table generated by this query is located at www.britestudent.com/pub/2.png. I can get away with using the MAX() function because values in the AmountUsed and AnsweredCorrectly columns in Table1 will always be larger than those in Table2 (and they are identical in the last three columns of both tables).
What I fail at is implementing (3). Any suggestions on how to do this will be appreciated. It is tricky because the UserName values in Table3 are null, and because the CourseName values in the combined Table1 and Table2 results are not unique (but they are unique in Table3).
After implementing (3), the final table should look like the table in picture 2.png with the addition of the last row from Table3 (the row with the CourseName value starting with "4. Klasse..."
I have tried to implement (3) using another derived table using SELECT, MAX() and UNION, but I could not get it to work. Below is my full SQL query with the lines from this failed attempt to implement (3) commented out.
Cheers,
Frederick
PS--I am new to this forum (and new to SQL as well), but I have had more of my previous problems answered by reading other people's posts on this forum than from reading any other forum or Web site. This forum is a great resources.
-- SELECT DISTINCT MAX(UserName), MAX(AmountUsed) AS AmountUsed, MAX(AnsweredCorrectly) AS AnsweredCorrectly, CourseName, MAX(course_code) AS course_code, MAX(NoOfQuestionsInCourse) AS NoOfQuestionsInCourse, MAX(NoOfQuestionSetsInCourse) AS NoOfQuestionSetsInCourse
-- FROM (
SELECT DISTINCT UserName AS UserName, MAX(AmountUsed) AS AmountUsed, MAX(AnsweredCorrectly) AS AnsweredCorrectly, CourseName, MAX(course_code) AS course_code, MAX(NoOfQuestionsInCourse) AS NoOfQuestionsInCourse, MAX(NoOfQuestionSetsInCourse) AS NoOfQuestionSetsInCourse
FROM (
-- Table 1 - All UserAccount/Course combinations that have had quizzez.
SELECT DISTINCT dbo.win_user.user_name AS UserName,
cast(dbo.GetAmountUsed(dbo.session_header.win_user_id, dbo.course.course_id, dbo.course.no_of_questionsets_in_course) as nvarchar(10)) AS AmountUsed,
Isnull(cast(dbo.GetAnswerCorrectly(dbo.session_header.win_user_id, dbo.course.course_id, dbo.question_set.no_of_questions) as nvarchar(10)),0) AS AnsweredCorrectly,
dbo.course.course_name AS CourseName,
dbo.course.course_code,
dbo.course.no_of_questions_in_course AS NoOfQuestionsInCourse,
dbo.course.no_of_questionsets_in_course AS NoOfQuestionSetsInCourse
FROM dbo.session_detail
INNER JOIN dbo.session_header ON dbo.session_detail.session_header_id = dbo.session_header.session_header_id
INNER JOIN dbo.win_user ON dbo.session_header.win_user_id = dbo.win_user.win_user_id
INNER JOIN dbo.win_user_course ON dbo.win_user_course.win_user_id = dbo.win_user.win_user_id
INNER JOIN dbo.question_set ON dbo.session_header.question_set_id = dbo.question_set.question_set_id
RIGHT OUTER JOIN dbo.course ON dbo.win_user_course.course_id = dbo.course.course_id
WHERE (dbo.session_detail.no_of_attempts = 1 OR dbo.session_detail.no_of_attempts IS NULL)
AND (dbo.session_detail.is_correct = 1 OR dbo.session_detail.is_correct IS NULL)
AND (dbo.win_user_course.is_active = 'True')
GROUP BY dbo.win_user.user_name, dbo.course.course_name, dbo.question_set.no_of_questions, dbo.course.no_of_questions_in_course,
dbo.course.no_of_questionsets_in_course, dbo.session_header.win_user_id, dbo.course.course_id, dbo.course.course_code
UNION ALL
-- Table 2 - All UserAccount/Course combinations that do or do not have quizzes but where the Course is selected for quizzes for that User Account.
SELECT dbo.win_user.user_name AS UserName,
-1 AS AmountUsed,
-1 AS AnsweredCorrectly,
dbo.course.course_name AS CourseName,
dbo.course.course_code,
dbo.course.no_of_questions_in_course AS NoOfQuestionsInCourse,
dbo.course.no_of_questionsets_in_course AS NoOfQuestionSetsInCourse
FROM dbo.win_user_course
INNER JOIN dbo.win_user ON dbo.win_user_course.win_user_id = dbo.win_user.win_user_id
RIGHT OUTER JOIN dbo.course ON dbo.win_user_course.course_id = dbo.course.course_id
WHERE (dbo.win_user_course.is_active = 'True')
GROUP BY dbo.win_user.user_name, dbo.course.course_name, dbo.course.no_of_questions_in_course,
dbo.course.no_of_questionsets_in_course, dbo.course.course_id, dbo.course.course_code
) dt_derivedTable_1
GROUP BY CourseName, UserName
-- UNION ALL
-- Table 3 - All Courses.
-- SELECT DISTINCT null AS UserName,
-- -2 AS AmountUsed,
-- -2 AS AnsweredCorrectly,
-- dbo.course.course_name AS CourseName,
-- dbo.course.course_code,
-- dbo.course.no_of_questions_in_course AS NoOfQuestionsInCourse,
-- dbo.course.no_of_questionsets_in_course AS NoOfQuestionSetsInCourse
-- FROM dbo.course
-- WHERE is_active = 'True'
-- ) dt_derivedTable_2
-- GROUP BY CourseName
-- ORDER BY CourseName
