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• After C++ - Python or Java?

  - by carleeto

  I'm fast approaching the point in my coding where I would like to quickly write object oriented code in languages other than C++ for a variety of reasons. After a lot of research, my choices have pretty much narrowed down to Python and Java. I'm leaning towards Python because of its relationship to C, but with Java, from what I can see, I get a good introduction to using and creating test suites with Eclipse - there is also Processing which is pulling me towards Java. I'm not the kind of guy to tackle two languages at once, so which one would you recommend and why? What I want at the end is to have an additional language I can use for rapid development. Ease of learning isn't important to me as I'm willing to put in the time regardless. Ability to use the new language widely is.

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• Check boxes for a has_many and belongs_to association.

  - by Thomas

  I have a has_many and belongs_to association. class Link < ActiveRecord::Base has_and_belongs_to_many :categories belongs_to :property end class Property < ActiveRecord::Base has_many :links end In the index and show I have <%= link.property.name %> and it will show the Property that I assigned to the link with the console just fine. I have a problem with figuring out how to show check boxes in the _form that assign a property to the link (a drop down would work as well). It seems everyone who has had this question before has ether a has_many :through or a HABTM relationship and I can't seem to adapt their answers.

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• Want to save data field from form into two columns of two models.

  - by vette982

  I have a Profile model with a hasOne relationship to a Detail model. I have a registration form that saves data into both model's tables, but I want the username field from the profile model to be copied over to the usernamefield in the details model so that each has the same username. function new_account() { if(!empty($this->data)) { $this->Profile->modified = date("Y-m-d H:i:s"); if($this->Profile->save($this->data)) { $this->data['Detail']['profile_id'] = $this->Profile->id; $this->data['Detail']['username'] = $this->Profile->username; $this->Profile->Detail->save($this->data); $this->Session->setFlash('Your registration was successful.'); $this->redirect(array('action'=>'index')); } } } This code in my Profile controller gives me the error: Undefined property: Profile::$username Any ideas?

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• Rails: Best practice to store user settings?

  - by ole_berlin

  Hi, I'm wondering what the best way is to store user settings? For a web 2.0 app I want users to be able to select certain settings. At the moment is it only when to receive email notifications. The easiest way would be to just create a Model "Settings" and have a column for every setting and then have a 1-1 relationship with users. But is there a pattern to solve this better? Is it maybe better to store the info in the user table itself? Or should I use a table with "settings_name" and "settings_value" to be completely open about the type of settings stored there (without having to run any migrations when adding options)? What is your opinion? Thanks

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• Storing Data as XML BLOB

  - by NBrowne

  Hi, At the moment the team i am working with is looking into the possibility of storing data which is entered by users from a series of input wizard screens as an XML blob in the database. the main reason for this being that i would like to write the input wizard as a component which can be brought into a number of systems without having to bring with it a large table structure. To try to clarify if the wizard has 100 input fields (for example) then if i go with the normal relational db structure then their will be a 1 to 1 relationship so will have 100 columns in database. So to get this working in another system will have to bring the tables,strore procedures etc into the new system. I have a number of reservations about this but i would like peoples opinions?? thanks

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• user_objects oracle

  - by mysticfalls

  I would just like to ask what is the difference between user_constraints and user_objects. I have this two database. I run a script on both DB that resulted a unique constraint error. To solve the problem I delete the constraint on user_constraint table for both DB. After that DB1 run without error.. DB2 however failed, I checked the user_constraint for both db and the constraints was deleted. I was asked to check the user_objects.. and found that DB2 has that same constraint_name as the object_name in user_objects table.. Any info regarding their relationship, use, similarites, etc will be appreciated ... Thanks..

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• SQL SELECT using in() but excluding others.

  - by Pickledegg

  I have a table called 'countries' linked to another table 'networks' with a many to many relationship: countries countries_networks networks +-------------+----------+ +-------------+----------+ +-------------+---------------+ | Field | Type | | Field | Type | | Field | Type | +-------------+----------+ +-------------+----------+ +-------------+---------------+ | id | int(11) | | id | int(11) | | id | int(11) | | countryName | char(35) | | country_id | int(11) | | name | varchar(100) | +-------------+----------+ | network_id | int(11) | | description | varchar(255) | To retrieve all countries that have a network_id of 6 & 7, I just do the following: ( I could go further to use the networks.name but I know the countries_networks.network_id so i just use those to reduce SQL.) SELECT DISTINCT countryName FROM countries AS Country INNER JOIN countries_networks AS n ON Country.id = n.country_id WHERE n.network_id IN (6,7) This is fine, but I then want to retrieve the countries with a network_id of JUST 8, and no others. I'ver tried the following but its still returning networks with 6 & 7 in. Is it something to do with my JOIN? SELECT DISTINCT countryName FROM countries AS Country INNER JOIN countries_networks AS n ON Country.id = n.country_id WHERE n.network_id IN (8) AND n.network_id not IN(6,7) Thanks.

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• has_many conditions

  - by user305270

  c = "(f.profile_id = #{self.id} OR f.friend_id = #{self.id})" c += AND + "(CASE WHEN f.profile_id=#{self.id} THEN f.friend_id ELSE f.profile_id END = p.id)" c += AND + "(CASE WHEN f.profile_id=#{self.id} THEN f.profile_rejected ELSE f.friend_rejected END = 1)" c += AND + "(p.banned = 0)" I need this to be used in a has_many relationship like this: has_many :removed_friends, :conditions => ??? how do i set there the self.id?, or how do i pass there the id? Then i want to use the will_paginate plugin: @profile.removed_friends.paginate(:page => 1, :per_page => 20) Thanks for your help

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• Very basic database theory.

  - by John R

  I have a set of tables to show the relationship between organziations and supporters below. Although I have done some basic mySQL querries, I know very little about database 'design'. I plan to querry the database for: -a list of contributors to a specific organization... or, -a list of organizations that a specific suporter supports. The database tables for organiations and contributors may have other columns in the future and recieve a lesser amount of querries based on that information. A | X A | Y A | Z B | X B | Y C | X C | Z How should the tables be set up? I assume that there should be a third table, but there is still redundent information in the third table. Is there a better way of setting up the tables? +----+-------+ +-------------+----------+ +----+-------+ | id | org | | org | contr | | id | contr.| +----+-------+ +-------------+----------+ +----+-------+ | 1 | A | | 1 | 1 | | 1 | X | | 2 | B | | 1 | 2 | | 2 | Y | | 3 | C | | 1 | 3 | | 3 | Z | +----+-------+ | 2 | 1 | +----+-------+ | 2 | 2 | | 3 | 1 | | 3 | 3 | +-------------+----------+

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• Generate a valid array key from an URL string in PHP

  - by John Riche

  I have a PHP array with some predefined values: $aArray = array( 0 => 'value0', 1 => 'value1' ); I need to create a function where the string input will always return the same, valid, array key so that when I call: GiveMeAKey('http://www.google.com'); // May return 0 or 1 I receive always the same key (I don't care which one) from the array. Obvisously I can't store the relationship in a database and the string passed to the GiveMeAKey method can be any URL. I wonder if there is a way of doing that ?

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• Rails - How to secure foreign keys and still allow association selection

  - by Bryce

  For simplicity, assume that I have a simple has-many-through relationship class User < ActiveRecord::Base has_many :courses, :through => :registrations end class Registration < ActiveRecord::Base belongs_to :user belongs_to :course end class Course < ActiveRecord::Base has_many :users, :through => :registrations end I want to keep my app secure, so I use attr_accessible to whitelist my attributes. My question is twofold: How would I set up my whitelist attributes such that I could create a new Registration object through a form (passing in :user and :course, but not risk allowing those foreign keys to be maliciously updated later? How would I set up my validations such that both belongs_to associations are required BUT also allow for Registration objects to be created in nested forms?

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• Is there an ORM that allows a "plugin" to extend the database?

  - by IP

  So, I've been searching for the answer to this, but I can't find anything I have an Entity Framework Model (MyModel1) - for now, we'll say this contains a "Users" table It's part of a big app, that has a references to an "Addresses" project The addresses project contains an Entity Framework Model (MyModel2), this contains a Users table, and an Addresses table (pointing to the same database. The main app has a control that edits the user, and in that control it has an "addresses" control which actually exists in the "Addresses" project. To make this work, the User control passes the User object down to the addresses control, however, as the User that's been passed belongs to MyModel1 and not MyModel2, another User object has to be loaded up, then it can be used. This isn't ideal as I've had to load up the User twice. Is there a way of say, MyModel2 extending MyModel1, which effectively just adds a relationship to "User". Or is there an ORM that would handle this better? Or even a design pattern that would handle this better?

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• Is JPA + EJB to much slow (or heavy) for over Internet transactions?

  - by Xavier Callejas

  Hi, I am developing a stand-alone java client application that connects to a Glassfish v3 application for JPA/EJB facade style transactions. In other words, my client application do not connect directly to the database to CRUD, but it transfers JPA objets using EJB stateless sessions. I have scenarios where this client application will be used in an external network connected with a VPN over Internet with a client connection of 512kbp/DSL, and a simple query takes so much time, I'm seeing the traffic graph and when I merge a entity in the client application I see megabytes of traffic (I couldn't believe how a purchase order entity could weight more than 1 mb). I have LAZY fetch in almost every many-to-many relationship, but I have a lot of many-to-one relationships between entities (but this is the great advantage of JPA!). Could I do something to accelerate the the speed of transactions between JPA/EJB server and the remote java client? Thank you in advance.

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• save object associate to another object automatically

  - by Luca Romagnoli

  Hi i have these classes: class Core < ActiveRecord::Base belongs_to :resource, :polymorphic => true belongs_to :image, :class_name => 'Multimedia', :foreign_key => 'image_id' end class Place < ActiveRecord::Base has_one :core, :as => :resource end If i try do launch this: a = Place.find(5) a.name ="a" a.core.image_id = 24 a.save name is saved. image_id no i want save automatically all changes in records in relationship with place class at a.save command. is possible? thanks

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• Symfony use NativeSQL to JOIN unrelated tables

  - by keybored

  I'd like to run a query like this: $rsm = new ResultSetMappingBuilder($this->em); $rsm->addRootEntityFromClassMetadata('myBundle:Foo', 'f'); $rsm->addRootEntityFromClassMetadata('myBundle:Bar', 'b'); $sql = 'SELECT l.*, b.* FROM foos f INNER JOIN FROM bars b ON b.baz_id = f.baz_id WHERE l.bam = 1'; $query = $this->em->createNativeQuery($sql, $rsm); $fooBarQuery= $query->getResult(); Unfortunately this is not a situation where I can set up a proper relationship in the entity. Is not going to be possible for me to do this? Thanks.

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• Need help with Excel 2007 Formula - Many to many update

  - by Monica

  I'm experienced with database development, but not so much with Excel. I'm looking for help writing an Excel formula that would help my client's spreadsheet behave like a database. This is what I'm looking to do, but I can't figure out how to write it in Excel 2007: "If Q4 (on sheet 2) contains A2 (on sheet 1), append A1 (on sheet 1) with Q5 (on sheet 2)" Some factors: 1) This formula may find multiple instances of A2, so it should not stop after finding the first match 2) The values, as they are created in A1, should be separated with comma and space 3) This is a many to many relationship between Q4 and A2 Thanks for any help with this. I've tried vlookups, match, if statements, but they all fall short in one way or another.

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• AS or not to AS, queries

  - by zeMinimalist

  I'm fairly new to PHP/MySql and using queries in general. I was just wondering if there's any benefit to using "AS" in a query other than trying to make it look cleaner? Does it speed up the query at all? I probably could have figured this out by a google search but I wanted to ask my first question and see how this works. I WILL select an answer (unlike some people...) with: SELECT news.id as id news.name as name FROM news without: SELECT news.id news.name FROM news A more complex example from a many-to-many relationship tutorial I found: SELECT c.name, cf.title FROM celebrities AS c JOIN ( SELECT icf.c_id, icf.f_id, f.title FROM int_cf AS icf JOIN films AS f ON icf.f_id = f.f_id ) AS cf ON c.c_id = cf.c_id ORDER BY c.c_id ASC

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• Rails 3 Order By Count on has_many :through

  - by goo

  I have an application where I can list Items and add tags to each Item. The models Items and Tags are associated like this: class Item < ActiveRecord::Base has_many :taggings has_many :tags, :through => :taggings end class Tagging < ActiveRecord::Base belongs_to :item belongs_to :tag end class Tag < ActiveRecord::Base has_many :taggings has_many :items, :through => :taggings end So, this many-to-many relationship allows me to set n tags for each Item, and the same tag can be used several times. I'd like to list all tags ordered by the number of items associated with this tag. More used tags, shows first. Less used, last. How can I do that? Regards.

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• Designing Relational Survey Questionnaires Database

  - by user1213055

  I'm trying to build a simple sql database for following access database. Currently there is no relationship and I just have two tables male and female with 6 sections in each form. How can I design it a better way so end user can connect to the database and analyze using STATA or SPSS ? I'm really confused whether I should create one table with all fields or break down into different tables. The database is specific to this study only so I'm not looking for a generic survey database where user can create surveys and capture them. Any feedback or suggestion is much appreciated.

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• Hibernate Save Parent Only

  - by user239905

  Hi, I'm having an issue with Hibernate 3.2.5, where I have to save only the parent object in a one-to-many relationship. For example, I have a flower A, that can have many details. Firstly I want to save only the flower, and the details will be added later. This process throws an exception: not-null property references a null or transient value: com.juflora.bean.JFlora._floraSetBackref This is my code: JFlora flora = new JFlora(); flora.setTypeId(Integer.parseInt(type)); flora.setDescription(description); flora.setName(name); flora.setImage(image); flora.setFloraDetails(new HashSet()); session.save(flora); session.getTransaction().commit();

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• iOS Development: Can I store an array of integers in a Core Data object without creating a new table to represent the array?

  - by BeachRunnerJoe

  Hello. I'm using Core Data and I'm trying to figure out the simplest way to store an array of integers in one of my Core Data entities. Currently, my entities contain various arrays of objects that are more complex than a single number, so it makes sense to represent those arrays as tables in my DB and attach them using relationships. If I want to store a simple array of integers, do I need to create a new table with a single column and attach it using a one-to-many relationship? Or is there a more simple way? Thanks in advance for your wisdom!

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• How do I customize the format of git rebase --interactive commit messages?

  - by adamjford

  Hi everyone, I use git for my local work (and love it ever so much), and I follow a workflow similar to the one described in this article. So basically, when starting on a new feature, I create a branch for it, go through the usual hack then commit cycle, and when I think I'm done with it, I squash it into a single commit using git rebase --interactive master, and these squashed commit messages always end up looking like the example in the article, reproduced here: [#3275] User Can Add A Comment To a Post * Adding Comment model, migrations, spec * Adding Comment controller, helper, spec * Adding Comment relationship with Post * Comment belongs to a User * Comment form on Post show page Of course, that's after a bunch of removing # This is the xth commit message lines and copy/pasting * in front of each commit message. Now, what I was wondering, is there any way to customize how git rebase -i outputs the merged commit messages so I don't have to do all that hacking? (I use msysgit, if that matters.) Thanks!

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• Problem with nhibernate join

  - by MexicanHacker

  I'm trying to do a join like this using fluent nhibernate: Id(x => x.Id); Map(x => x.SourceSystemRecordId,"sourceSystemRecord_id"); Then Join("cat.tbl_SourceSystemRecords", SourceSystemRecords); But, it seems I don't have a way to specify the column I want to join with from the first table, in this case I need to join on SourceSystemRecordId and not on Id Is there any way I can specify this? I tried References() but that requires me to create an object for this relationship, what I need is to aggregate the columns in sourcesystem records to the ones in the main table.

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• Join data from two Lists into one object

  - by Petr Mensik

  I ran into following situation and I am wondering about best solution. Let's say I have List<Object1> and List<Object2>, these lists are result of two separated queries. Both of them have the same size and there is relationship 1:1 between elements in the lists based on ID. I know that best solution would be fetching data in one DB query but that's possible right now. So my question is, what is the best way to join these lists into let's say List<Object3>?

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• IndexedDB and Relationships

  - by Josh Johnson

  Can I create relationships between my object stores in IndexedDB? For example, I have two object stores: artist and album. An artist has a one-to-many relationship with an album. album.artistId relates the album to artist.id. I'm thinking along the lines of Hibernate here. I would like to do a query for artists and have the albums belonging to that artist returned as an array called artists on the album object. artist.albums = [];

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