c++ Mixing printf with wprintf (or cout with wcout)
- by Bo Jensen
I know you should not mix printing with printf,cout and wprintf,wcout, but have a hard time finding a good answer why and if it is possible to get round it. The problem is I use a external library that prints with printf and my own uses wcout. If I do a simple example it works fine, but from my full application it simply does not print the printf statements. If this is really a limitation, then there would be many libraries out there which can not work together with wide printing applications. Any insight on this is more than welcome.
Update :
I boiled it down to :
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <readline/readline.h>
#include <readline/history.h>
int main()
{
char *buf;
std::wcout << std::endl; /* ADDING THIS LINE MAKES PRINTF VANISH!!! */
rl_bind_key('\t',rl_abort);//disable auto-complete
while((buf = readline("my-command : "))!=NULL)
{
if (strcmp(buf,"quit")==0)
break;
std::wcout<<buf<< std::endl;
if (buf[0]!=0)
add_history(buf);
}
free(buf);
return 0;
}
So I guess it might be a flushing problem, but it still looks strange to me, I have to check up on it.
