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  • Mod Rewriting Image Location Not Working Very Well

    - by Belgin Fish
    Hey, I'm trying to mod rewrite the image locations on my site, I'm just using this : rewriteRule ^thumbs/(.*)$ http://site2.com/images/$1 [L] so that I can redirect all image requests going from http://site1.com/thumbs/something to http://site2.com/thumbs/something But only some of the images are loading, and not all of them. Thanks!

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  • storing crontab php outputs in a log file

    - by vick
    * * * * * php /home/admin/public_html/domain.com/public/cron/route.php &>> /home/admin/public_html/domain.com/log/cron.log I have that cron running every minute. I want to store the errors that occur in route.php in cron.log This works wonderfully when I run : php /home/admin/public_html/domain.com/public/cron/route.php &>> /home/admin/public_html/domain.com/log/cron.log through the command line manually. But when crontab runs it no errors gets stored in cron.log the cron.log is owned by admin:admin and the permissions are set to 777 just to be sure. anyone?

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  • ListView is Widget(View) or Layout(Viewgroup)?

    - by Manoj Maurya
    Hi All, I need your help to explore few topics in Android. My understanding is Widget is View and Layout is ViewGroups in Android. I described the problems as below- Please go through the below links- developer.android.com/guide/topics/ui/custom-components.html- (add http:// in the beginning) developer.android.com/resources/tutorials/views/index.html - (add http:// in the beginning) In the first link ListView is included as Widget and in the Second link ListView has been shown as Layout. So, is ListView is Widget(View) or Layout(Viewgroup)? Same is the case for Spinner in Andriod developer.android.com/resources/tutorials/views/hello-spinner.html- (add http:// in the beginning) (Link- says Spinner is Widget(View)) developer.android.com/guide/topics/ui/layout-objects.html- (add http:// in the beginning) says Spinner is Layout(ViewGroup) So, Spinner is View or ViewGroup? Please update me with your views?

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  • Why does JPA require a no-arg constructor for domain objects ?

    - by Jacques René Mesrine
    Why does JPA require a no-arg constructor for domain objects ? I am using eclipselink and just got this exception during deployment. Exception [EclipseLink-63] (Eclipse Persistence Services-1.1.0.r3639-SNAPSHOT): org.eclipse.persistence.exceptions.DescriptorException Exception Description: The instance creation method [com.me.model.UserVO.<Default Constructor>], with no parameters, does not exist, or is not accessible. Internal Exception: java.lang.NoSuchMethodException: com.me.model.UserVO.<init>() Descriptor: RelationalDescriptor(com.me.model.UserVO --> [DatabaseTable(user)])

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  • Best way to send mass email to my subscribers ( BCC or PEAR mail queue ? )

    - by xRobot
    I need to send email to my 5000 subscribers. What is the best way to do this ? 1) By using BCC ?: $from_addr = 'myemail@example.com'; $mailing_list = 'sub1@example.com', 'sub2@example.com', '[email protected]; $message_subject = 'this is a test'; `$headers = array ("From" => $from_addr, "Bcc" => $mailing_list, "Subject" => $message_subject); $smtp = Mail::factory("smtp", array ('host' => "smtp.example.com", 'auth' => true, 'username' => "xxx", 'password' => "xxx")); $mail = $smtp->send($email, $headers, $message_body);` . 2) by using PEAR mail queue ?

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  • Can I test for the end of the content of a text/plain file with Selenium or javascript?

    - by fool4jesus
    I have a page that results in a text/plain file being displayed in the browser that looks like this: ... Admin Site Administration 2010-04-21 22:26:34 admin_user@abcdef.com Test Site Bob Smith 2010-04-21 22:27:09 bsmith@yahoo.com Admin Site Administration 2010-04-21 22:29:26 admin_user@abcdef.com I am trying to write a Selenium test against this that verifies the last line of the file has "admin_user@abcdef.com" at the end. How would you do this? I can't depend on the date/time as this is a login report that is constantly getting updated - all I want is to ensure that the last line ends with that email address. And I can't figure out how to do it using Selenium expressions, DOM, or XPath.

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  • showing content from subdomain

    - by coure06
    I have a root site in httpdocs folder. There is another website (for subdomain) at httpdocs/demo1 Mapping is like www.abc.com to httpdocs demo1.abco.com to httpdocs/demo1 How can I show image from demo1 folder? I want to access it like www.abc.com/demo1/images/some.png Error: Parser Error Message: It is an error to use a section registered as allowDefinition='MachineToApplication' beyond application level. This error can be caused by a virtual directory not being configured as an application in IIS.

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  • Can I create an xml that specifies element from 2 nested xsd's without using a prefixes?

    - by TweeZz
    I have 2 xsd's which are nested: DefaultSchema.xsd: <?xml version="1.0" encoding="utf-8"?> <xs:schema id="DefaultSchema" targetNamespace="http://myNamespace.com/DefaultSchema.xsd" elementFormDefault="qualified" xmlns="http://myNamespace.com/DefaultSchema.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" > <xs:complexType name="ZForm"> <xs:sequence minOccurs="0" maxOccurs="unbounded"> <xs:element name="Part" minOccurs="0" maxOccurs="unbounded" type="Part"/> </xs:sequence> <xs:attribute name="Title" use="required" type="xs:string"/> <xs:attribute name="Version" type="xs:int"/> </xs:complexType> <xs:complexType name="Part"> <xs:sequence minOccurs="0" maxOccurs="unbounded"> <xs:element name="Label" type="Label" minOccurs="0"></xs:element> </xs:sequence> <xs:attribute name="Title" use="required" type="xs:string"/> </xs:complexType> <xs:complexType name="Label"> <xs:simpleContent> <xs:extension base="xs:string"> <xs:attribute name="Title" type="xs:string"/> </xs:extension> </xs:simpleContent> </xs:complexType> </xs:schema> ExportSchema.xsd: (this one kinda wraps 1 more element (ZForms) around the main element (ZForm) of the DefaultSchema) <?xml version="1.0" encoding="utf-8"?> <xs:schema id="ExportSchema" targetNamespace="http://myNamespace.com/ExportSchema.xsd" elementFormDefault="qualified" xmlns="http://myNamespace.com/DefaultSchema.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:es="http://myNamespace.com/ExportSchema.xsd" > <xs:import namespace="http://myNamespace.com/DefaultSchema.xsd" schemaLocation="DefaultSchema.xsd"/> <xs:element name="ZForms" type="es:ZFormType"></xs:element> <xs:complexType name="ZFormType"> <xs:sequence> <xs:element name="ZForm" type="ZForm" maxOccurs="unbounded" /> </xs:sequence> </xs:complexType> </xs:schema> And then finally I have a generated xml: <?xml version="1.0" encoding="utf-8"?> <ZForms xmlns="http://myNamespace.com/ExportSchema.xsd"> <ZForm Version="1" Title="FormTitle"> <Part Title="PartTitle" > <Label Title="LabelTitle" /> </Part> </ZForm> </ZForms> Visual studio complains it doesn't know what 'Part' is. I was hoping I do not need to use xml namespace prefixes (..) to make this xml validate, since ExportSchema.xsd has a reference to the DefaultSChema.xsd. Is there any way to make that xml structure valid without explicitly specifying the DefaultSchema.xsd? Or is this a no go?

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  • display image in image control

    - by KareemSaad
    I had Image control and I added code to display images But there is not any image displayed ASPX: <body> <form id="form1" runat="server"> <div dir='<%= sDirection %>'> <div id="ContentImage" runat="server"> <asp:Image ID="Image2" runat="server" /> </div> </div> </form> </body> C#: using (System.Data.SqlClient.SqlConnection con = Connection.GetConnection()) { string Sql = "Select Image From AboutUsData Where Id=@Id"; System.Data.SqlClient.SqlCommand com = new System.Data.SqlClient.SqlCommand(Sql, con); com.CommandType = System.Data.CommandType.Text; com.Parameters.Add(Parameter.NewInt("@Id", Request.QueryString["Id"].ToString())); System.Data.SqlClient.SqlDataReader dr = com.ExecuteReader(); if (dr.Read() && dr != null) { Image1.ImageUrl = dr["Image"].ToString(); } }

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  • <jaxrs:client> not getting autowired

    - by himangshu
    I am trying to build a restful client using jaxrs:client as defined in http://svn.apache.org/repos/asf/cxf/trunk/systests/jaxrs/src/test/resources/jaxrs_soap_rest/WEB-INF/beans.xml In my test class I am getting org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'com.abc.service.ExportServiceTest': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private com.bankbazaar.service.ExportService com.abc.service.ExportServiceTest.exportClient; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean of type [com.abc.service.ExportService] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {@org.springframework.beans.factory.annotation.Autowired(required=true), @org.springframework.beans.factory.annotation.Qualifier(value=exportClient)} this is my spring config However exportClient=(ExportService)applicationContext.getBean("exportClient"); this works. Thanks Himangshu

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  • problem with twitter api friends_timeline

    - by siznax
    i can get my user_timeline fine: curl -u user:pwd http://www.twitter.com/statuses/user_timeline/user.json {blob of tweets} but when i try to get the friends_timeline, i get an auth error: curl -u user:pwd http://www.twitter.com/statuses/friends_timeline.json {"request":"\/statuses\/friends_timeline.json", "error":"Could not authenticate you."} do i just not understand the documentation? http://apiwiki.twitter.com/REST+API+Documentation#friendstimeline

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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • How to filter current url using php

    - by bob
    Example current URL http://www.domain.com/subdomain/install/finish.php I use this code to get the current URL. $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; Now I want to get the URL looks like http://www.domain.com/subdomain if there don't have sub-folder it will read like http://www.domain.com Let me know.

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  • protect (encrypt) password in the web.config file (asp.net)

    - by Hazro City
    <system.net> <mailSettings> <smtp from="email@domain.com" deliveryMethod="Network"> <network clientDomain="www.domain.com" host="smtp.live.com" defaultCredentials="false" port="25" userName=" email@domain.com " password="password" enableSsl="true" /> </smtp> </mailSettings> </system.net> This is the case where I need encryption for my password. I searched and googled much on the web but I can’t be able to encrypt anymore. Can anyone help me do this in a simple but secure way.

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  • Why can't I put a jquery-ui progressbar inside a div with fixed position?

    - by Matthew
    I started the source from this progressbar example, and it works fine. My only change was to set the width of the progressbar to "20%". <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> $(document).ready(function() { $("#progressbar").progressbar({ value: 37 }).css({ width : "20%"}); }); </script> </head> <body style="font-size:62.5%;"> <div id="progressbar"></div> </body> </html> I then put the progressbar inside another div, and used css to fix that div in the upper-right-hand corner. <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <style type="text/css"> #testContainer { position : fixed; top : 6; right : 6; } </style> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> $(document).ready(function() { $("#progressbar").progressbar({ value: 37 }).css({ width : "20%"}); }); </script> </head> <body style="font-size:62.5%;"> <div id="testContainer"> <div id="progressbar"></div> </div> </body> </html> The progressbar becomes a slim vertical line on the left side of the screen. What am I doing wrong? I'm new to web development in general, and jquery in particular, so please forgive me if this is a stupid question.

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  • Using javascript to check which CDN jQuery is cached from on the client

    - by Hazro City
    Can I use JavaScript to check whether JQuery is (already) downloaded (cached) on the target web browser (user) or not? For Example: If (JQuery-from-Microsoft-CDN-downloaded) Then use http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.4.4.js Else if (JQuery-from-Google-APIs- downloaded) Then use http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js Else if (JQuery-from-code.jquery.com- downloaded) Then use http://code.jquery.com/jquery-1.4.4.min.js Else use jQuery from my own website. Means that using the ability of javascript to check whether one of them is downloaded on the target User (Web Browser), if not then use jQuery from my own website otherwise if true then use that version of JQuery that is downloaded on the target User.

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  • setup apache virtualhost (windows)

    - by nightingale2k1
    Hi, How to setup virtualhost for multiple domain name on windows ? I will use it for my own test projects. I have 3 projects that I need to setup and at the moment I'm using xampplite for the portable apache. www.foo-bar.com -- direct to c:\xampplite\htdocs\foo-bar\ www.abcdef.com -- directo to c:\xampplite\htdocs\abcdef\ www.qwerty.com -- direct to c:\xampplite\htdocs\qwerty\web\ I also need to access on another project but it just like typing http://localhost/my-project/ how to write the vhost configuration for that ?

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  • Why does VerticalScrollBarVisibility not work in a style in Silverlight?

    - by Edward Tanguay
    VerticalScrollBarVisibility works when I define it inline like this: <UserControl x:Class="TestScrollBar.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <UserControl.Resources> <Style TargetType="TextBox" x:Key="EditListContainerContentMultiLineTwoColumn"> <Setter Property="AcceptsReturn" Value="True"/> <Setter Property="Width" Value="400"/> <Setter Property="Height" Value="300"/> <Setter Property="IsReadOnly" Value="False"/> <Setter Property="Margin" Value="0 0 0 20"/> <Setter Property="HorizontalAlignment" Value="Left"/> <Setter Property="TextWrapping" Value="Wrap" /> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White" Margin="10"> <StackPanel HorizontalAlignment="Left"> <TextBox Text="this is a test" Style="{StaticResource EditListContainerContentMultiLineTwoColumn}" VerticalScrollBarVisibility="Auto" /> </StackPanel> </Grid> </UserControl> But when I put VerticalScrollBarVisibility in a style, it shows me a blank screen: <UserControl x:Class="TestScrollBar.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <UserControl.Resources> <Style TargetType="TextBox" x:Key="EditListContainerContentMultiLineTwoColumn"> <Setter Property="VerticalScrollBarVisibility" Value="Auto"/> <Setter Property="AcceptsReturn" Value="True"/> <Setter Property="Width" Value="400"/> <Setter Property="Height" Value="300"/> <Setter Property="IsReadOnly" Value="False"/> <Setter Property="Margin" Value="0 0 0 20"/> <Setter Property="HorizontalAlignment" Value="Left"/> <Setter Property="TextWrapping" Value="Wrap" /> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White" Margin="10"> <StackPanel HorizontalAlignment="Left"> <TextBox Text="this is a test" Style="{StaticResource EditListContainerContentMultiLineTwoColumn}" /> </StackPanel> </Grid> </UserControl> In WPF it works works fine. How can I get VerticalScrollBarVisibility to work in a style?

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  • RewriteRule help

    - by Camran
    I have successfully setup htaccess to do this: domain.com/ad.php?ad_id=bmw_m3_2498224 INTO: domain.com/ads/bmw_m3_2498224 However, I have a link on the page which makes the page submit to itself... The link saves the ad inside a cookie: domain.com/ad.php?ad_id=bmw_m3_2498224&save=1 // Note the 'save' variable I need to make this work on the rewritten rule also, so this link: domain.com/ads/bmw_m3_2498224/save will save the cookie... I have this so far which DOES NOT work for the save part: RewriteRule ^annons/([a-zA-Z0-9_]+)$ ad.php?ad_id=$1 [NC,L] How can I include another rule to accomplish what I want? Thanks

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  • Sql Select Query Question. Merge Rows

    - by Jono
    I have a single MYSQL Question and need help ASAP. Database: Email | Name | Tag test@test.com |Test Person | TagOne test@test.com |Test Person | Tag Two Need an SQL query that will return Email | Name | Tag test@test.com |Test Person | TagOne, Tag Two Any help?

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  • Old query String hard coded 301 url redirection using htaccess

    - by Nilesh Toshniwal
    I have recently changed CMS of my website and now looking to redirect old urls like: oldpage.php?key=7cdb93c26 to some new urls but I want all of them in hard coded way and it should be a 301 redirect I tried the following rules but none of them work for me redirect 301 /oldpage.php?key=7cdb93c26 http://www.mynewsite.com/my-new-page.html redirect 301 "/oldpage.php?key=7cdb93c26" http://www.mynewsite.com/my-new-page.html RewriteRule ^oldpage.php?key=7cdb93c26$ http://www.mynewsite.com/my-new-page.html [L,R=301] RewriteRule ^oldpage.php?key=7cdb93c26$ /my-new-page.html [L,R=301]

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  • free RSS feed caching

    - by cherouvim
    Hello I've got an application which serves an rss feed of headlines and I need to provide this rss feed to other consumers. I don't want to provide the rss directly from my server though, due to limited server resources, so I need to proxy (cache) it through some service which will handle the load. Assuming the rss feed URL of my application is http://example.com/rss I initially provided my consumers with the url http://ajax.googleapis.com/ajax/services/feed/load?v=1.0&q=http%3A%2F%2Fexample.com%2Frss which solved my server load problem but introduced a liveness problem. The headlines are minutes to hours late from the actual feed (haven't exactly measured how much late). I've also tried distributing through feedburner so the url became something like http://feeds.feedburner.com/example123?format=xml but the liveness problem still exists. Is there a public and free solution for this problem? Anything below 5 minutes of liveness delay would be totally acceptable. thanks

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