How to get top and left style property values in Javascript
- by Dude-Dastic
Hi all,
I have a little bit of Javascript that almost works correctly. Here's the code:
function toggle(curlink) {
curlink.style.backgroundColor = curlink.style.backgroundColor == "yellow" ? "transparent" : "yellow";
var maindiv = document.getElementById("grid");
var links = maindiv.getElementsByTagName("a");
var list = "";
for (var i = 0; i < links.length; ++i) {
var link = links[i];
if (link.style.backgroundColor == "yellow") {
list += ("," + parseInt(link.style.left, 10) + "-" + parseInt(link.style.top, 10));
}
}
document.theForm.theList.value = list.substring(1);
return false;
};
window.onload = function() {
var links = document.getElementById("grid").getElementsByTagName("a");
for (var i = 0; i < links.length; ++i) {
links[i].onclick = function() { return toggle(this); }
}
};
The issue is with line #9; it only works when I specify values for the top and left style property of every link in the array. How do I get the top and left style property values (or X and Y coordinates) of each link in the array with Javascript when those values aren't given?
Also, what would the code above look like in jquery? Not that it's needed - I just want to reduce the code a little and dabble in the jquery framework (I'm a Javascript newbie).
Thanks in advance,
Dude-Dastic
