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  • Drag Drop copy file

    - by Graham Warrender
    I've perhaps done something marginally stupid, but can't see what it is!! string pegasusKey = @"HKEY_LOCAL_MACHINE\SOFTWARE\Pegasus\"; string opera2ServerPath = @"Server VFP\"; string opera3ServerPath = @"O3 Client VFP\"; string opera2InstallationPath = null; string opera3InstallationPath = null; //Gets the opera Installtion paths and reads to the string opera*InstallationPath opera2InstallationPath = (string)Registry.GetValue(pegasusKey + opera2ServerPath + "System", "PathToServerDynamic", null); opera3InstallationPath = (string)Registry.GetValue(pegasusKey + opera3ServerPath + "System", "PathToServerDynamic", null); string Filesource = null; string[] FileList = (string[])e.Data.GetData(DataFormats.FileDrop, false); foreach (string File in FileList) Filesource = File; label.Text = Filesource; if (System.IO.Directory.Exists(opera3InstallationPath)) { System.IO.File.Copy(Filesource, opera3InstallationPath); MessageBox.Show("File Copied from" + Filesource + "\n to" + opera3InstallationPath); } else { MessageBox.Show("Directory Doesn't Exist"); } The user drags the file onto the window, I then get the installation path of an application which is then used as the destination for the source file.. When the application is runs, it throws the error directory not found. But surely if the directory doesn't exists is should step into the else statement? a simple application that is becoming a headache!!

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  • Livevalidation: only validate when default value is changed

    - by usr122212
    Hello there! I am validating my html form with livevalidation and everything works great except for one feature. I have a input field with a default value age, I only want the livevalidation to validate when it says something other than "age". so maybe the user will type in 20 then the validation will fire checking its things but if left as "age" it won't check it all. But as of now, it just checks everything with a validation script and this is a problem for me as I have lots of fields in my form and some of them are optional so when I hit submit, the livevalidation checks the age field as well even if the user didnt touch it to begin with. Would this be possible with livevalidation ? Thanks for the help.

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  • How to open links in new window ONLY IF the check box is checked

    - by Travis
    Here is what i have so far. I have it so they open in new windows, but i want it only if the check box is checked... <!DOCTYPE html> <html> <head> <script> function new() { if ( document.getElementById('checkbox').checked ) window.open( 'y', 'n', 't', 'New Window' ); } else { break; } var OpenNew = document.getElementById('opennew'); OpenNew.addEventListener('click', OpenWin, false ); </script> </head> <body> <p> <form name="test"> <p>Open link in a new window &nbsp; <input type="checkbox" id="checkbox" name="check" /></p> </form> </p> <p> <h2>My favorite Websites to visit</h2> <a href="http://www.youtube.com" target="new" id="y">Youtube</a><br /> <a href="http://www.newegg.com" target="new" id="n">Newegg</a><br /> <a href="http://www.twitch.tv" target="new" id="t">Twitch.tv</a><br /> </p> </body> </html> I am unsure how to actually do the if statement if it is checked then open. It does currently open in a new tab.. i just need it to be only when its checked. Any help with this will be greatly appreciated! Thanks!

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  • Creating two Windows by running one as a process from another - C

    - by Jamie Keeling
    Hello, I have a windows form that has a simple menu and performs a simple operation, I want to be able to create another windows form with all the functionality of a menu bar, message pump etc.. as a seperate process so I can then share the results of the operation to the second window. I.E. 1) Form A opens Form B opens as a separate process 2)Form A performs operation 3)Form A passes results via memory to Form B 4)Form B display results I'm confused as to how to go about it, the main app runs fine but i'm not sure how to add a second window if the first one already exists. I hope it makes sense. Thanks!

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  • Rails: Different prices for different branches, association depending on two other models combined

    - by Greg Lemond
    I have three models: Service has_many :prices has_many :groups, through: prices Price belongs_to :service belongs_to :group Group has_many :prices I want to have an input field (Simple_Form) for every price. In views/services/_form.html.haml I do: simple_form_for @service do |f| simple_fields_for :groups do |g| simple_fields_for :prices do |p| p.input :price With this setup I only get input fields for already saved prices. How I can get a price field for every group? I tried to do it manually, but it got really nasty and didn't work either. Thanks for any ideas!

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  • How to get a single widget to set 2 fields in Django?

    - by kender
    Hi, I got a model with 2 fields: latitude and longitude. Right now they're 2 CharFields, but I want to make a custom widget to set it in admin - was thinking about displaying Google Maps, then getting the coordinates of the marker. But can I have 1 widget (a single map) to set 2 different fields?

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  • Why does setting a form's enabled property crash the application?

    - by Ruirize
    private void launchbutton_Click(object sender, EventArgs e) { launchbutton.Enabled = false; Process proc = new Process(); proc.EnableRaisingEvents = true; proc.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden; //The arguments/filename is set here, just removed for privacy. proc.Exited += new EventHandler(procExit); proc.Start(); } private void procExit(object sender, EventArgs e) { MessageBox.Show("YAY","WOOT"); Thread.Sleep(2000); launchbutton.Enabled = true; } 2 Seconds after I quit the created process, my program crashes. Why?

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  • PHP: $_POST array to XML file and display results.

    - by user633264
    I'm creating a "Madlibs" page where visitors can create funny story things online. The original files are in XML format with the blanks enclosed in XML tags (Such as blablabla <PluralNoun></PluralNoun> blablabla <Verb></Verb> ). The form data is created using XSL and the results are saved using a $_POST array. How do I post the $_POST array between the matching XML tags and then display the result to the page? I'm sure it uses a "foreach" statement, but I'm just not familiar enough with PHP to figure out what functions to use. Any help would be great. Thanks, E

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  • Javascript "inlet" or "offset" function for drop-list options

    - by Camran
    I have seen on several sites that drop list values can have offsets... For example this drop-list: Fruits Apple Banana Orange Colors Red White Black The above are all options, but some have "inlets" or "offsets" or whatever you want to call it. How is this done with js? (regular js, not jquery at the moment) Thanks If you need more input let me know.

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  • Uploading an xml direct to ftp

    - by Joshua Maerten
    i put this direct below a button: XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("Login"); XmlElement id = doc.CreateElement("id"); id.SetAttribute("userName", usernameTxb.Text); id.SetAttribute("passWord", passwordTxb.Text); XmlElement name = doc.CreateElement("Name"); name.InnerText = nameTxb.Text; XmlElement age = doc.CreateElement("Age"); age.InnerText = ageTxb.Text; XmlElement Country = doc.CreateElement("Country"); Country.InnerText = countryTxb.Text; id.AppendChild(name); id.AppendChild(age); id.AppendChild(Country); root.AppendChild(id); doc.AppendChild(root); // Get the object used to communicate with the server. FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://users.skynet.be"); request.Method = WebRequestMethods.Ftp.UploadFile; request.UsePassive = false; // This example assumes the FTP site uses anonymous logon. request.Credentials = new NetworkCredential("fa490002", "password"); // Copy the contents of the file to the request stream. StreamReader sourceStream = new StreamReader(); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); request.ContentLength = fileContents.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close(); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); response.Close(); MessageBox.Show("Created SuccesFully!"); this.Close(); but i always get an error of the streamreader path, what do i need to place there ? the meening is, creating an account and when i press the button, an xml file is saved to, ftp://users.skynet.be/testxml/ the filename is from usernameTxb.Text + ".xml".

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  • Why does the following Javascript/form not work?

    - by joshim5
    <form> <input type="text" id="inputbox" value="hello"/> <input type="submit" value="Convert" onClick="convert(document.getElementById("inputbox"))"/> </form> <script type="text/javascript"> function convert (text) { alert(text); return text; </script> This also does not work when I change alert to document.write. I obviously have more HTML to go along with this. Thanks!

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  • How can ishow Form in process1 from Form in process2 ?

    - by Al0NE
    Hi I'm trying to show hidden form in process1 from another one was called by : Process.Start(@"F:\MyOtherFormPath\MyOtherForm.exe",this.Handle.ToInt32()); As you can see i passed the handle number of the hidden form ,which i'm calling the "MyOtherForm" from, and i used this number to get a handle and show the hidden form from my "MyOtherForm" like this : Form newFrm = Form.FromHandle(new IntPtr(long.Parse(handleNumberOfMyHiddenForm))); newFrm.show(); But it didn't work, any way to do this . P.S: it didn't throw any exception . thanx in advanced ..

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  • jQuery append breaks my HTML form (with submit button)

    - by JimFing
    I'm trying to create a form with a submit button via jQuery using append(). So the following: out.append('<form name="input" action="/createuser" method="get">'); out.append('Username: <input type="text" name="user" />'); out.append('<input type="submit" value="Submit" />'); out.append('</form>'); However, clicking on submit, nothing happens! However if I do the following: var s = '<form name="input" action="/createuser" method="get">' + 'Username: <input type="text" name="user" />' + '<input type="submit" value="Submit" />' + '</form>'; out.html(s); Then the submit button works fine! I'm happy to use the 2nd method, but would rather know what the problem is here. Thanks

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  • Sending Javascript variables.

    - by shinjuo
    I have a page that allows a user to choose some things in a form and it will calculate the weight using javascript. It breaks it up into 5 variables that I need to send to another page. Originally I was just having it put the variable into a text box and then I was posting that text box. However I dont want to have 5 text boxes. So now I need to somehow send or post the five variables to another page. Here is my javascript function. I need to post weightBoxOne - weightBoxFive js function function getWeight(){ var weightBoxOne; var weightBoxTwo; var totalWeight; var box = .5; var quantity = document.dhform.quantity.value; var cardSize = document.dhform.cardSize.value; if(cardSize == 0.0141){ if(quantity <= 1000){ weightBoxOne = (quantity * cardSize) + box; totalWeight = weightBoxOne; }else if(quantity > 1000 && quantity <= 2000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = ((quantity - 1000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo; }else if(quantity > 2000 && quantity <= 3000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = ((quantity - 2000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree; }else if(quantity > 3000 && quantity <= 4000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = (1000 * cardSize) + box; weightBoxFour = ((quantity - 3000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree + weightBoxFour; }else{ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = (1000 * cardSize) + box; weightBoxFour = (1000 * cardSize) + box; weightBoxFive = ((quantity - 4000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree + weightBoxFour + weightBoxFive; } }else if(cardSize == 0.00949){ if(quantity <= 4000){ weightBoxOne = (quantity * cardSize) + box; totalWeight = weightBoxOne; }else{ weightBoxOne = (4000 * cardSize) + box; weightBoxTwo = ((quantity - 4000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo; } } document.rates.weight.value = totalWeight; } //--> this is the form that was originally posting <form action="getRates.php" name="rates" method="post" onSubmit="popupform(this, 'join')"> <table style="width: 216px"> <tr> <td style="width: 115px; height: 49px;"><span class="style16">Weight</span><br/> <input type="text" id="weight" name="weight" size="10" maxlength="4"/> </td> <td align="right" style="width: 68px; height: 49px;" valign="top"><span class="style16">Zip Code</span><br/> <input type="text" id="zip" name="zip" size="10" maxlength="5"/> </td> </tr> <tr> <td style="width: 115px"> <input name="submit" type="submit" value="Get Rate Costs" style="width: 138px" />

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  • change the return of to_param by action? or, terribly broken edit action if perma-url is returned in

    - by Stacia
    I did some stuff to have to_param return a perma-url so I'd have seo friendly links. Upon creation and update it will generate and return the perma-url in a to_param method that I put in the model. However this causing me some grief in other areas. I have a form that looks like this: <% @apps.each do |app| %> <% fields_for "[id][]", app do |fields| %> .... this fails terribly since it tries to insert the perma-url in place of the id. If I could just restrict to_param by action, that could solve things. If I change app to app.id, that fails since I have stuff like this: fields.check_box :is_featured . I suppose I could get the app instance, but that feels hacky. Again please excuse my lack of rails-foo ;)

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  • JSP JPA Form: how to insert value in a path variable

    - by kajarigd
    I have the following code snippet in a jsp file: <hr> <form:form commandName="newTicketSale" id="reg" action="transactionResult.htm"> <h3>Buy Movie Tickets:</h3> <form:label path="movieName">Movie Name:</form:label> <form:input path="movieName" /> <form:errors class="invalid" path="movieName" /> <form:label path="ticketPrice">Ticket Price:</form:label> <form:input path="ticketPrice" /> <form:errors class="invalid" path="ticketPrice" /> <input type="submit"> <br><br> </form:form> I am using JPA tags in this jsp. Now, in the commandName "newTicketSale" there is another parameter called userId. In the jsp file itself I need to insert value ${name} in userId, so that in the Controller file when I am doing @Valid @ModelAttribute("newTicketSale") MovieTicket newTicket I can retrieve the value ${name} when I am doing newTicket.getUserId(). I don't know how to do this. Please help! Thanks in advance!

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  • InfoPath browser form submitting dirty fields changed through javascript

    - by Xavier
    I'm trying to submit an InfoPath browser form with fields that have been modified through the Spell Checker included in Sharepoint server. The spell checker checks all the fields in the page and once the user closes the SpellChecker dialog, it changes the textboxes with the new values through javascript. When I click Submit, debug the FormEvents_Submit in the form code behind and try to do a GetNodeValue("XPath to changed field"), it still shows the old values. I realize that this may be a problem of doing postbacks and I'd like to do a full page postback once the SpellChecker is done changing all the textboxes. Any suggestions would be appreciated. Thanks.

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • How to convert submitted form array to this array on php?

    - by drfanai
    Lets suppose i have the following array submitted by a html form: array( 'firstname' => array('Sara','Jim'), 'lastname' => array('Gibson','Jobs') ); What i wanna achieve is the following array: array( array( 'firstname' => 'sara', 'lastname' => 'Gibson' ), array( 'firstname' => 'Jim', 'lastname' => 'Jim' ) ); I need a function to automatically sort the array not manually by entering data but automatically processing array data.

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  • This code is not submitting to a form? Why

    - by Ankur
    Since I am using get I expect to see the submitted values appended to the queryString but instead all I see is the URL of the servlet being called with nothing added at the end. <form id="editClassList" name="editClassList" method="get" action="EditClassList"> <% HashMap<Integer,String> classes = new HashMap<Integer,String>(); classes = (HashMap<Integer,String>) request.getAttribute("classes"); %> <% if(classes.size()==0){ %> <label><input class="small-link" type="text" id="add-this-class" size="42" value="" /></label> <% } %> <% Set<Integer> classIds = new HashSet<Integer>(); classIds = classes.keySet(); Iterator<Integer> itr = classIds.iterator(); while(itr.hasNext()){ int nextId = (Integer)itr.next(); %> <label><input class="small-link" type="text" id="<% out.print(nextId); %>" size="42" value="<% out.print(classes.get(nextId)); %>" /> </label> <img id="add-class" src="images/add.png" width="16" height="16" /><br /> <label><input class="small-link" type="text" id="class-to-add" size="42" value="" /></label> <% } %> <label><input type="submit" id="save-class-btn" value="Save Class(es)" /></label> </form>

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  • How to protect a form HTML/PHP with JS callback to AS3

    - by Jk_
    Hi guys, I'm developing a Flash website (as3) where I need to be able to upload directly to YouTube by using the DATA API. However in order to do so, I had to use a proper HTML form on top of my flash object. Why? Because of the Browser Based Upload restictions. I first hide the form using JQuery and with a little CSS the form is display just where I want it. Within flash I use ExternalInterface.call() to show/hide the form when I need it! ExternalInterface.call("YTUploader.showIt"); The upload process is working great my only problem is that the form can be displayed easily... You just need a tool like firebug and you can use the form wherever you want on my flash app. So I was wandering which will be the best way to 'protect' this form or the best way to limit its access. Any advices will be appreciated. Thanks for your time. Jk.

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