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  • how to fix my error saying expected expression before 'else'

    - by user292489
    this program intended to read a .txt, a set of numbers, file and wwrite to another two .txt files called even amd odd as follows: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i=0,even,odd; int number[i]; // check to make sure that all the file names are entered if (argc != 3) { printf("Usage: executable in_file output_file\n"); exit(0); } FILE *dog = fopen(argv[1], "r"); FILE *feven= fopen(argv[2], "w"); FILE *fodd= fopen (argv[3], "w"); // check whether the file has been opened successfully if (dog == NULL) { printf("File %s cannot open!\n", argv[1]); exit(0); } //odd = fopen(argv[2], "w"); { if (i%2!=1) i++;} fprintf(feven, "%d", even); fscanf(dog, "%d", &number[i]); else { i%2==1; i++;} fprintf(fodd, "%d", odd); fscanf(dog, "%d", &number[i]); fclose(feven); fclose(fodd);

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  • C system calls open / read / write / close problem.

    - by Andrei Ciobanu
    Hello, given the following code (it's supposed to write "hellowolrd" in a "helloworld" file, and then read the text): #include <fcntl.h> #include <sys/types.h> #include <sys/stat.h> #define FNAME "helloworld" int main(){ int filedes, nbytes; char buf[128]; /* Creates a file */ if((filedes=open(FNAME, O_CREAT | O_EXCL | O_WRONLY | O_APPEND, S_IRUSR | S_IWUSR)) == -1){ write(2, "Error1\n", 7); } /* Writes hellow world to file */ if(write(filedes, FNAME, 10) != 10) write(2, "Error2\n", 7); /* Close file */ close(filedes); if((filedes = open(FNAME, O_RDONLY))==-1) write(2, "Error3\n", 7); /* Prints file contents on screen */ if((nbytes=read(filedes, buf, 128)) == -1) write(2, "Error4\n", 7); if(write(1, buf, nbytes) != nbytes) write(2, "Error5\n", 7); /* Close rile afte read */ close(filedes); return (0); } The first time i run the program, the output is: helloworld After that every time I to run the program, the output is: Error1 Error2 helloworld I don't understand why the text isn't appended, as I've specified the O_APPEND file. Is it because I've included O_CREAT ? It the file is already created, shouldn't O_CREAT be ignored ?

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  • Creating a cocoa Application without nib files/fully pragmatic

    - by Moddy
    Yes, I know this goes against the whole MVC principle! However, I'm just trying to whip up a pretty trivial application - and I've pretty much implemented it pragmatically. However, I have a problem... I create an Empty Project, copy all the frameworks over and set the build settings - and I get errors about the executable.. or lack of executable. The build settings all appear fine, but it tells me there is no executable - it will build + run fine.. however it doesn't run. There is no error either - it just appears to run very fast and cleanly! Unless I try and run gdb which politely tells me I need to give it a file first.. Running… No executable file specified. Use the "file" or "exec-file" command. So I created a Cocoa Application, removed all the stuff I didn't need (i.e the MainMenu.xib file..) and now I can compile my code perfectly.. however it dies with complaining that its "Unable to load nib file: MainMenu, exiting" I have gone through the Project Symbols and see that the code actually relies upon the nib file heavily, even if you don't touch it code-wise. (MVC again I guess..) So my question is - is there a simple way to compile just what you code, no added nib files, just the code you write and the frameworks you add? I assume it would be a blank project but my experience tells me otherwise?!

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  • SVN 409 conflict on commits and updates

    - by bhefny
    We have been using SVN for the past year now and when we migrated to an online server we started getting this error: Commit: Commit failed (details follow): File or directory 'x.php' is out of date; try updating resource out of date; try updating CHECKOUT of '/!svn/ver/491/x.php': 409 Conflict (http://svn.example.com) We are currently using SmartSVN 6.5 and we have also tested with RapidSVN & Syncro (but we can't use tortoise as we have a lot of Ubunutu users) at the begining I though this How do you fix an SVN 409 Conflict Error would help, but it didn't we are still facing the same error and it's even more absurd now. the main problem is that after you get the error, you can't shake it of. Updating doesn't solve, reverting doesn't solve. You are just stuck with the error. The only thing that could work is removing the file from SVN and adding your version but that would be against why we are using SVN in the first place This is our apache config (and yes autoversioning is ON) <Location /> DAV svn SVNPath /home/example/svn SVNAutoversioning on AuthType Basic AuthName "Access Restricted" AuthUserFile /home/example/svn-auth-file Require valid-user </Location> <Directory /> <Files ~ "^\.ht"> Order allow,deny Allow from all Satisfy All </Files> <Files ~ "^error_log"> Order allow,deny Allow from all Satisfy All </Files> </Directory> And here are some observation: We don't receive conflicts anymore, we just get this 409 conflict you can somehow avoid the error if you always update before committing When committing a modified file + a newly added file, you get the error. As if the added file incremented the version by one and then you are committing another file with a older version. Please advise, we are about to go insane

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  • Python CGI Premature end of script error depending on script parameters.

    - by nickengland
    I have a python script which should parse a file and produce some output to disk, as well as returning a webpage linking to the outputted files. When run with a file posted from the HTML form I get no HTML output back, just a 500 error page and the error_log contains the line: [Mon Apr 19 15:03:23 2010] [error] [client xxx.xxx.121.79] Premature end of script headers: uploadcml.py, referer: http://xxx.ch.cam.ac.uk:9000/ However, the files which the script should be saving are indeed saved to disk. If I run it without any arguments, the script returns the correct HTML indicating no file was parsed. All the information I have found on the web about Premature end of script headers implies it is due to either a missing header, or lack of permissions on the python script but neither can apply to me. The first lines of the script are: #!/home/nwe23/bin/bin/python import cgitb; cgitb.enable() import cgi import pybel,openbabel import random print "Content-Type: text/html" print so when run, I can see no way for it to fail to output the header, and it DOES output the header when run without a file to parse, but when given a file produces the error(but still parsed the file and saves the output to disk!). Does anyone know how this is happening and what can be done to fix it? I have tried adding wrongly-indented gibberish (such as foobar) at various points in the file, and this results in adding an indent error to the error_log wherever it is, even if its the very last line in the script. The Premature script headers error remains though. Does this mean the script is executing all the way through?

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  • how to read xml properties value?

    - by bala
    I have xml file in sdcard(xxx.file) how to read all the xml tag properties values starting point to end point and prints that value please help me I am not familiar in xml pullparser please help me... This is my xml file code: <?xml version="1.0"?> <layout schemaVersion="1" width="800" height="450" bgcolor="#000000"> <region id="47ff29524ce1b" width="800" height="450" top="0" left="0" userId="1"> <media id="9" type="image" duration="30" lkid="4" userId="1" schemaVersion="1"> <options><uri>9.png</uri></options> <raw/> </media></region></layout> java code: public class MainActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); try{ XmlPullParserFactory factory = XmlPullParserFactory.newInstance(); factory.setNamespaceAware(true); XmlPullParser parser = factory.newPullParser(); File file = new File(Environment.getExternalStorageDirectory()+ "/xxx.xml"); FileInputStream fis = new FileInputStream(file); parser.setInput(new InputStreamReader(fis)); }catch(XmlPullParserException e){ e.printStackTrace(); }catch(FileNotFoundException e){ e.printStackTrace(); } } }

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  • How can I redirect directory using htaccess including files with spaces in the names

    - by James
    Hi, I am dealing with a situation where someone has handed me a bunch of old files on the server which already have a lot of incoming links directly to them (mostly pdf files). I now have the files organized but in a different directory. Before it was 'domain/manuals/file' now it is 'domain/media/manual/file'. I am trying to resolve this issue using an htaccess file. Many of the files have spaces in the names (not something I can control) and because they already have links to them I can't just go through renaming them. I have found that I can redirect files individually when they have spaces in the names by using quotes such as: redirect 301 "/manuals/file 123.pdf" "http://www.domain.com/manuals/file 123.pdf" However, there are loads of these files and I wondered if there is a way to create a regular expression that will handle spaces in file names that I could use to redirect the entire directory. I should add that some files contain decent file names with no spaces in, some have one space and others more than one space. It's not pretty. If you've encountered this problem before I would really appreciate hearing your advice, I'm running out of ideas. Thanks.

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  • Nose2 multiprocess error on Windows7

    - by tt293
    I was looking into nose2 as a way to get around the restrictions of having both xunit output and multiprocessing in nose1.3. However, when always-on is set to False in the [multiprocess] section, I can only get a single process running, while when running with always-on set to True, I get the following error: ---------------------------------------------------------------------- Ran 0 tests in 0.043s OK Traceback (most recent call last): File "C:\dev\testing\Tests\PythonTests\venv\Scripts\nose2-script.py", line 8, in <module> load_entry_point('nose2==0.4.7', 'console_scripts', 'nose2')() File "C:\dev\testing\Tests\PythonTests\venv\lib\site-packages\nose2-0.4.7-py2. 7.egg\nose2\main.py", line 284, in discover return main(*args, **kwargs) File "C:\dev\testing\Tests\PythonTests\venv\lib\site-packages\nose2-0.4.7-py2. 7.egg\nose2\main.py", line 98, in __init__ super(PluggableTestProgram, self).__init__(**kw) File "C:\dev\testing\Tests\PythonTests\venv\lib\site-packages\unittest2-0.5.1- py2.7.egg\unittest2\main.py", line 98, in __init__ self.runTests() File "C:\dev\testing\Tests\PythonTests\venv\lib\site-packages\nose2-0.4.7-py2. 7.egg\nose2\main.py", line 260, in runTests self.result = runner.run(self.test) File "C:\dev\testing\Tests\PythonTests\venv\lib\site-packages\nose2-0.4.7-py2. 7.egg\nose2\runner.py", line 53, in run executor(test, result) File "C:\dev\testing\Tests\PythonTests\venv\lib\site-packages\nose2-0.4.7-py2. 7.egg\nose2\plugins\mp.py", line 60, in _runmp ready, _, _ = select.select(rdrs, [], [], self.testRunTimeout) select.error: (10038, 'An operation was attempted on something that is not a soc ket') This is running python 2.7.5 (32bit) on Windows 7 in a virtualenv with six-1.1.0, unittest2-0.5.1 and nose2-0.4.7 (I get the same behavior outside of the venv, so I don't think that is the issue here).

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  • CONSOLE appender was turned off. But JBoss still writes some traces to STDOUT

    - by Vladimir Bezugliy
    CONSOLE appender was turned off. But JBoss still writes some traces to STDOUT during startup. Why? C:\as\jboss-5.1.0.GA\bin>start.cmd Calling C:\as\jboss-5.1.0.GA\bin\run.conf.bat =============================================================================== JBoss Bootstrap Environment JBOSS_HOME: C:\as\jboss-5.1.0.GA JAVA: C:\as\jdk1.6.0_07\bin\java JAVA_OPTS: -Dprogram.name=run.bat -Xms512M -Xmx758M -XX:MaxPermSize=256M -server CLASSPATH: C:\as\jboss-5.1.0.GA\bin\run.jar =============================================================================== 13:11:25,080 INFO [ServerImpl] Starting JBoss (Microcontainer)... 13:11:25,080 INFO [ServerImpl] Release ID: JBoss [The Oracle] 5.1.0.GA (build: SVNTag=JBoss_5_1_0_GA date=200905221053) 13:11:25,080 INFO [ServerImpl] Bootstrap URL: null 13:11:25,080 INFO [ServerImpl] Home Dir: C:\as\jboss-5.1.0.GA 13:11:25,080 INFO [ServerImpl] Home URL: file:/C:/as/jboss-5.1.0.GA/ 13:11:25,080 INFO [ServerImpl] Library URL: file:/C:/as/jboss-5.1.0.GA/lib/ 13:11:25,080 INFO [ServerImpl] Patch URL: null 13:11:25,080 INFO [ServerImpl] Common Base URL: file:/C:/as/jboss-5.1.0.GA/common/ 13:11:25,080 INFO [ServerImpl] Common Library URL: file:/C:/as/jboss-5.1.0.GA/common/lib/ 13:11:25,080 INFO [ServerImpl] Server Name: web 13:11:25,080 INFO [ServerImpl] Server Base Dir: C:\as\jboss-5.1.0.GA\server 13:11:25,080 INFO [ServerImpl] Server Base URL: file:/C:/as/jboss-5.1.0.GA/server/ 13:11:25,080 INFO [ServerImpl] Server Config URL: file:/C:/as/jboss-5.1.0.GA/server/web/conf/ 13:11:25,080 INFO [ServerImpl] Server Home Dir: C:\as\jboss-5.1.0.GA\server\web 13:11:25,080 INFO [ServerImpl] Server Home URL: file:/C:/as/jboss-5.1.0.GA/server/web/ 13:11:25,080 INFO [ServerImpl] Server Data Dir: C:\as\jboss-5.1.0.GA\server\web\data ...

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  • Getting unhandled error and connection get lost when a client tries to communicate with chat server in twisted

    - by user2433888
    from twisted.internet.protocol import Protocol,Factory from twisted.internet import reactor class ChatServer(Protocol): def connectionMade(self): print "A Client Has Connected" self.factory.clients.append(self) print"clients are ",self.factory.clients self.transport.write('Hello,Welcome to the telnet chat to sign in type aim:YOUR NAME HERE to send a messsage type msg:YOURMESSAGE '+'\n') def connectionLost(self,reason): self.factory.clients.remove(self) self.transport.write('Somebody was disconnected from the server') def dataReceived(self,data): #print "data is",data a = data.split(':') if len(a) > 1: command = a[0] content = a[1] msg="" if command =="iam": self.name + "has joined" elif command == "msg": ma=sg = self.name + ":" +content print msg for c in self.factory.clients: c.message(msg) def message(self,message): self.transport.write(message + '\n') factory = Factory() factory.protocol = ChatServer factory.clients = [] reactor.listenTCP(80,factory) print "Iphone Chat server started" reactor.run() The above code is running succesfully...but when i connect the client (by typing telnet localhost 80) to this chatserver and try to write message ,connection gets lost and following errors occurs : Iphone Chat server started A Client Has Connected clients are [<__main__.ChatServer instance at 0x024AC0A8>] Unhandled Error Traceback (most recent call last): File "C:\Python27\lib\site-packages\twisted\python\log.py", line 84, in callWithLogger return callWithContext({"system": lp}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\log.py", line 69, in callWithContext return context.call({ILogContext: newCtx}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 118, in callWithContext return self.currentContext().callWithContext(ctx, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 81, in callWithContext return func(*args,**kw) --- --- File "C:\Python27\lib\site-packages\twisted\internet\selectreactor.py", line 150, in _doReadOrWrite why = getattr(selectable, method)() File "C:\Python27\lib\site-packages\twisted\internet\tcp.py", line 199, in doRead rval = self.protocol.dataReceived(data) File "D:\chatserverultimate.py", line 21, in dataReceived content = a[1] exceptions.IndexError: list index out of range Where am I going wrong?

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  • Using an embedded Word document to create a new instance of that document.

    - by jim
    For a variety of reasons that are immutable ... I have a Word document which contains a VBA application (the 'app document') which creates a new document based on another document (the 'template') which contains the framework for the new document. I want to embed the 'template' into the 'app document' so that I deliver one file and I know I am using the correct version of the 'template'. I have, so far, embedded the 'template' file into the 'app document' and can find it by looping through "ThisDocument.InlineShapes", looking at .Field.OleFormat.IconLabel to find the 'template' by its name. The inlineShape.Field.OleFormat.Object is the 'template' document itself, and I can .Activate it, which causes it to appear as a regular document. I try to do SaveAs, and it does in fact save the file as the name I give it, however, that saved-as file is not left open, just the embedded file. I can not .Activate the file and just save it, then open the saved file, but that seems more work than necessary. So ... is the way I am doing this "the way", or I have missed some obvious practice? TIA

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  • Python: Errors saving and loading objects with pickle module

    - by Peterstone
    Hi, I am trying to load and save objects with this piece of code I get it from a question I asked a week ago: Python: saving and loading objects and using pickle. The piece of code is this: class Fruits: pass banana = Fruits() banana.color = 'yellow' banana.value = 30 import pickle filehandler = open("Fruits.obj","wb") pickle.dump(banana,filehandler) filehandler.close() file = open("Fruits.obj",'rb') object_file = pickle.load(file) file.close() print(object_file.color, object_file.value, sep=', ') At a first glance the piece of code works well, getting load and see the 'color' and 'value' of the saved object. But, what I pursuit is to close a session, open a new one and load what I save in a past session. I close the session after putting the line filehandler.close() and I open a new one and I put the rest of your code, then after putting object_file = pickle.load(file) I get this error: Traceback (most recent call last): File "<pyshell#5>", line 1, in <module> object_file = pickle.load(file) File "C:\Python31\lib\pickle.py", line 1365, in load encoding=encoding, errors=errors).load() AttributeError: 'module' object has no attribute 'Fruits' Can anyone explain me what this error message means and telling me how to solve this problem? Thank so much and happy new year!!

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  • How to reference an embedded JCA resource adapater

    - by cg
    For our current J2EE project based on JBoss, we need to interface with a remote system using message driven beans and a JCA resource adapter provided as a RAR file by a third party. I would like to package and deploy the entire project as an EAR file to our JBoss server. Most notably, the RAR file should be embedded within the EAR file and not be deployed globally. All of this is working fine so far, but I'm not particularly happy with the way the RAR file is referenced. The jboss.xml packaged with the MDB for example, currently looks like this: <jboss> <enterprise-beans> <message-driven> <ejb-name>testBean1</ejb-name> <resource-adapter-name>test1.ear#thirdparty-1.0.rar</resource-adapter-name> </message-driven> </enterprise-beans> </jboss> While this is generally working fine, it will break when the EAR file is renamed to "test2.ear". Is there a way to reference the embedded RAR file without hard-coding the containing archive's name?

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  • CVS update doesn't fetch most recent commit

    - by mizipzor
    I just commited changes to a file (bringing it to revision 1.3). I then updated the file and to my surprise I got back revision 1.2 (how the file looked before my commit). Checking the history if the file shows that there is a revision 1.3 (most recent) and a 1.2 before that (which is identical to my local copy). Ive tried removing the file and updating the folder, causing the file to be downloaded again. Ive also tried fetching a clean copy of the file of HEAD. Clearing cache and fetching HEAD doesnt work. But forcing an update to revision 1.3 explicitly does. But doing a normal update after that causes it to go back to revision 1.2. This is on a Windows XP machine, server is also a Windows box. Im using TortoiseCVS. Does anyone know what could be causing this? (If you dont know how to fix it, I will award bonus points to anyone that can tell me why CVS broke and, hopefully, how horrible it will be to fix it. I want to add it to my list so that maybe some day I can convince my colleagues to finally give it up in favor of a more modern VCS.)

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  • Using the Queue class in Python 2.6

    - by voipme
    Let's assume I'm stuck using Python 2.6, and can't upgrade (even if that would help). I've written a program that uses the Queue class. My producer is a simple directory listing. My consumer threads pull a file from the queue, and do stuff with it. If the file has already been processed, I skip it. The processed list is generated before all of the threads are started, so it isn't empty. Here's some pseudo-code. import Queue, sys, threading processed = [] def consumer(): while True: file = dirlist.get(block=True) if file in processed: print "Ignoring %s" % file else: # do stuff here dirlist.task_done() dirlist = Queue.Queue() for f in os.listdir("/some/dir"): dirlist.put(f) max_threads = 8 for i in range(max_threads): thr = Thread(target=consumer) thr.start() dirlist.join() The strange behavior I'm getting is that if a thread encounters a file that's already been processed, the thread stalls out and waits until the entire program ends. I've done a little bit of testing, and the first 7 threads (assuming 8 is the max) stop, while the 8th thread keeps processing, one file at a time. But, by doing that, I'm losing the entire reason for threading the application. Am I doing something wrong, or is this the expected behavior of the Queue/threading classes in Python 2.6?

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • Pass a model object while using a upload

    - by Dejan.S
    I'm trying to pass my model object along with the file I'm uploading but I'm stuck on how I should that should be done. This is the code I use now [AcceptVerbs(HttpVerbs.Post)] public ActionResult Upload(PageBody pageBody) { foreach (string file in Request.Files) { var hpf = Request.Files[file] as HttpPostedFileBase; if (hpf.ContentLength == 0) continue; string savedFileName = Path.Combine(AppDomain.CurrentDomain.BaseDirectory + "Content/Uploads/", Path.GetFileName(hpf.FileName)); hpf.SaveAs(savedFileName); _pageBody.Pictures.Add(new PageBodyPicture() { Picture = file }); } return View(pageBody); } here is my view code, I got the model.Id but there but it wont pass even if I put just Id to the Upload method. <form action="/Admin/Upload" enctype="multipart/form-data" method="post"> <%= Html.HiddenFor(model => model.Id)%> <input type="file" name="file" id="file" /><br /> <input type="submit" name="submit" value="Upload" /> </form>

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  • Ruby core documentation quality

    - by karatedog
    I'm relatively new to Ruby and have limited time therefore I try out simple things. Recently I needed to create a file and because I'm lazy as hell, I run to Google. The result: File.open(local_filename, 'w') {|f| f.write(doc) } Shame on me, it is very straightforward, should have done it myself. Then I wanted to check what ruby magic the File class' methods offer or if there's any 'simplification' when invoking those methods, so I headed for the documentation here, and checked for the File class. 1.8.6 documentation presents me with "ftools.rb: Extra tools for the File class" under 'File' class, which is not what I'm looking for. 1.8.7 documentation seems OK for 'File' class, there are a plethora of methods. Except 'open'. 1.9 documentation finally shows me the 'open' method. And I had an almost same tour with Net::HTTP. Do I exaggerate when I think good old Turbo Pascal's 7.0 documentation was better organized than Ruby documentation is right now? Is there any other source for the uninitiated to collect knowledge? Or is it possible that I just tumbled into a documentation hole and the rest are super-brilliant-five-star organized? Thanks

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  • Is it possible in Perl to require a subroutine call is made?

    - by MitchelWB
    I don't know enough about Perl to even know what I'm asking for exactly, but I'm writing a series of subroutines to be available for many individual scripts that all process different incoming flat files. The process is far from perfect, but it's what I've got to deal with and I'm trying to build myself a small library of subs that make it easier for me to manage it all. Each script handles a different incoming flat file with it's own formatting, sorting, grouping and outputting requirements. One common aspect is that we have small text files that house counters that are used to name the output files so that we have no duplicate file names. Because the processing of the data is different for each file, I need to open the file to get my counter value, because this is a common operation, I'd like to put it in a sub to retrieve the counter. But then need to write specific code to process the data. And would like a second sub that allows me to update the counter with the counter once I've processed the data. Is there a way to make the second sub call a requirement if the first one is called? Ideally if it could even be an error that would prevent the script from running at all much like a syntax error. EDIT: Here is a little [ugly and simplified] psuedo-code to give a better feel for what the current process is: require "importLibrary.plx"; #open data source file open DataIn, $filename; #call getCounterInfo from importLibrary.plx to get the counter value from counter file $counter = &getCounterInfo($counterFileName); while (<DataIn>) { #Process data based on unique formatting and requirements #output to task files based on requirements and name files using the $counter #increment $counter } #update counter file with new value of $counter &updateCounterInfo($counter);

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  • Recursion through a directory tree in PHP

    - by phphelpplz
    I have a set of folders that has a depth of at least 4 or 5 levels. I'm looking to recurse through the directory tree as deep as it goes, and iterate over every file. I've gotten the code to go down into the first sets of subdirectories, but no deeper, and I'm not sure why. Any ideas? $count = 0; $dir = "/Applications/MAMP/htdocs/idahohotsprings.com"; function recurseDirs($main, $count){ $dir = "/Applications/MAMP/htdocs/idahohotsprings.com"; $dirHandle = opendir($main); echo "here"; while($file = readdir($dirHandle)){ if(is_dir($file) && $file != '.' && $file != '..'){ echo "isdir"; recurseDirs($file); } else{ $count++; echo "$count: filename: $file in $dir/$main \n<br />"; } } } recurseDirs($dir, $count); ?

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  • inserting unique date into txt document

    - by durian
    I'm trying this script to insert only a unique date into a text file, but it isn't working properly: $log_file_name = "logfile.txt"; $log_file_path = "log_files/$id/$log_file_name"; if(file_exists($log_file_path)){ $not = "not"; $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $file_contents = file_get_contents($log_file_path); $file_contents_arry = explode(";",$file_contents); if(!in_array($todaytodaydate,$file_contents_arry)){ $append = fopen($log_file_path, 'a'); $write = fwrite($append,$today); //writes our string to our file. $close = fclose($append); //closes our file } else { $append = fopen($log_file_path, 'a'); $write = fwrite($append,$not); //writes our string to our file. $close = fclose($append); //closes our file } } else{ mkdir("log_files/$id", 0700); $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $create = fopen($log_file_path, "w"); $write = fwrite($create, $today, $strlength); //writes our string to our file. $close = fclose($create); //closes our file } The problem is with the if else statement where it should be written if it's already in the array.

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  • A beginner question on passthru() function in PHP

    - by Robert
    Hi all, I've used the following code to do an XSLT translation in PHP and save the result SVG file into a sub folder: $command = $java . $saxon . $target2 . ' ' . $xsl2.' '.$param; ob_start(); passthru($command, $result); $content_grabbed=ob_get_contents(); ob_end_clean(); $info = pathinfo($_FILES['file']['name']); $file_name= basename($_FILES['file']['name'],'.'.$info['extension']); $myFile = "images/convert/".$file_name."_".$_POST["mydropdown"].".svg"; $fh = fopen($myFile, 'w') or die("can't open file"); fwrite($fh, $content_grabbed); fclose($fh); It does a very simple SVG to SVG transformation, and created the resulting SVG file. the $command is just a simple java -jar saxon.jar input.xml stylesheet java command. The current situation is ,the file gets created perfectly, however, the error gets shown in browser, probably because I inserted the "ob_start" before passthru() command. I am thinking of making use of an argument that comes with the saxon.jar, that is "-o output_file_name". Because the final purpose is not to display the resulting SVG to the browser, but instead creating an SVG file ,and provide the link to the user for downloading. Are there any better ways to handle this problem, I am still thinking about how to get rid of the result that gets shown in the browser that is sent by the "passthru()". Thanks in advance for suggestions!

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  • How to handle too many files in Qt

    - by mree
    I'm not sure how to ask this, but here goes the question: I'm migrating from J2SE to Qt. After creating some small applications in Qt, I noticed that I've created way too many files compared to what I would've create if I was developing in Java (I use Netbeans). For an example, for a GUI to Orders, I'd have to create Main Order Search Window Edit Order Dialog Manage Order Dialog Maybe some other dialogs... For Java, I don't have to create a new file for every new Dialog, the Dialog will be created in the JFrame class itself. So, I will only be seeing 1 file for Orders which has other Dialogs in it. However, in Qt, I'd have to create 1 ui file, 1 header file, 1 cpp file for each of the Dialog (I know I can just put the cpp in the header, but it's easier to view codes in seperate files). So, in the end, I might end up with 3 (if there are 3 dialogs) x3 files = 9 files for the GUI in Qt, compared to Java which is only 1 file. I do know that I can create a GUI by coding it manually. But it seems easy on small GUIs but not some on complicated GUIs with lots of inputs, tabs and etc. So, is there any suggestion on how to minimize the file created in Qt?

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  • reporting tool/viewer for large datasets

    - by FrustratedWithFormsDesigner
    I have a data processing system that generates very large reports on the data it processes. By "large" I mean that a "small" execution of this system produces about 30 MB of reporting data when dumped into a CSV file and a large dataset is about 130-150 MB (I'm sure someone out there has a bigger idea of "large" but that's not the point... ;) Excel has the ideal interface for the report consumers in the form of its Data Lists: users can filter and segment the data on-the-fly to see the specific details that they are interested in - they can also add notes and markup to the reports, create charts, graphs, etc... They know how to do all this and it's much easier to let them do it if we just give them the data. Excel was great for the small test datasets, but it cannot handle these large ones. Does anyone know of a tool that can provide a similar interface as Excel data lists, but that can handle much larger files? The next tool I tried was MS Access, and found that the Access file bloats hugely (30 MB input file leads to about 70 MB Access file, and when I open the file, run a report and close it the file's at 120-150 MB!), the import process is slow and very manual (currently, the CSV files are created by the same plsql script that runs the main process so there's next to no intervention on my part). I also tried an Access database with linked tables to the database tables that store the report data and that was many times slower (for some reason, sqlplus could query and generate the report file in a minute or soe while Access would take anywhere from 2-5 minutes for the same data) (If it helps, the data processing system is written in PL/SQL and runs on Oracle 10g.)

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  • BufferedWriter overwriting itself

    - by Danson
    I want to read in a file and create a duplicate of the file but my code only write the last line in the file. How do I make so that whenever I call write(), it writes to a new line. I want to create a new file for the duplicate so I can't add true to FileWriter constructor. This is my code: //Create file reader BufferedReader iReader = new BufferedReader(new FileReader(args[1])); //Create file writer BufferedWriter oWriter = new BufferedWriter(new FileWriter(args[2], true)); String strLine; //reading file int iterate = 0; while((strLine = iReader.readLine()) != null) { instructions[iterate] = strLine; } //creating duplicate for(int i = 0; i < instructions.length; i++) { if(instructions[i] != null) { oWriter.write(instructions[i]); oWriter.newLine(); } else { break; } } try { iReader.close(); oWriter.close(); } catch (IOException e) { e.printStackTrace(); }

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