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  • Sample twitter application

    - by Jack
    I have installed WAMP and running PHP scripts on localhost. I have enabled cURL. Here is my code. <?php function updateTwitter($status) { // Twitter login information $username = 'xxxxx'; $password = 'xxxxx'; // The url of the update function $url = 'http://twitter.com/statuses/update.xml'; // Arguments we are posting to Twitter $postargs = 'status='.urlencode($status); // Will store the response we get from Twitter $responseInfo=array(); // Initialize CURL $ch = curl_init($url); // Tell CURL we are doing a POST curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_NOBODY, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // execute the CURL call $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> Here's my output Operation completed without any errors Error: 404 Here's what error 404 means 404 Not Found: The URI requested is invalid or the resource requested, such as a user, does not exists. Please help.

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  • Can't use my form

    - by Alexandr
    I have class with my form in folder /application/forms/Auth.php it looks like class Form_Auth extends Zend_Form { public function __construct() { $this->setName(); parent::__construct(); $username = new Zend_Form_Element_Text('username'); $password = new Zend_Form_Element_Password('password'); $mail = new Zend_Form_Element_Text('mail'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username,$password,$mail,$submit)); } } When i try create object $this->view->form = new Form_Auth(); is see exeption Application error Exception information: Message: Invalid name provided; must contain only valid variable characters and be non-empty Stack trace: D:\WWW\zends\application\Forms\Auth.php(8): Zend_Form-setName() d:\WWW\zends\application\controllers\RegistrationController.php(49): Form_Auth-__construct() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Action.php(513): RegistrationController-indexAction() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action-dispatch('indexAction') D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard-dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front-dispatch() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap-run() D:\WWW\zends\public\index.php(26): Zend_Application-run() {main} Request Parameters: array ( 'controller' = 'registration', 'action' = 'index', 'module' = 'default', ) the version zf is 1.10.3 what i do wrong ?

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  • How can I determine PerlLogHandler performance impact?

    - by Timmy
    I want to create a custom Apache2 log handler, and the template that is found on the apache site is: #file:MyApache2/LogPerUser.pm #--------------------------- package MyApache2::LogPerUser; use strict; use warnings; use Apache2::RequestRec (); use Apache2::Connection (); use Fcntl qw(:flock); use File::Spec::Functions qw(catfile); use Apache2::Const -compile => qw(OK DECLINED); sub handler { my $r = shift; my ($username) = $r->uri =~ m|^/~([^/]+)|; return Apache2::Const::DECLINED unless defined $username; my $entry = sprintf qq(%s [%s] "%s" %d %d\n), $r->connection->remote_ip, scalar(localtime), $r->uri, $r->status, $r->bytes_sent; my $log_path = catfile Apache2::ServerUtil::server_root, "logs", "$username.log"; open my $fh, ">>$log_path" or die "can't open $log_path: $!"; flock $fh, LOCK_EX; print $fh $entry; close $fh; return Apache2::Const::OK; } 1; What is the performance cost of the flocks? Is this logging process done in parallel, or in serial with the HTTP request? In parallel the performance would not matter as much, but I wouldn't want the user to wait another split second to add something like this.

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  • Transaction to find an entity - locks all entities of that type?

    - by user246114
    Hi, Reading the docs for transactions: http://code.google.com/appengine/docs/java/datastore/transactions.html An example provided shows one way to make an instance of an object: try { tx.begin(); Key k = KeyFactory.createKey("SalesAccount", id); try { account = pm.getObjectById(Employee.class, k); } catch (JDOObjectNotFoundException e) { account = new SalesAccount(); account.setId(id); } ... When the above transaction gets executed, it will probably block all other write attempts on Account objects? I'm wondering because I'd like to have a user signup which checks for a username or email already in use: tx.begin(); "select from User where mUsername == str1 LIMIT 1"; if (count > 0) { throw new Exception("username already in use!"); } "select from User where mEmail == str1 LIMIT 1"; if (count > 0) { throw new Exception("email already in use!"); } pm.makePersistent(user(username, email)); // ok. tx.commit(); but the above would be even more time consuming I think, making an even worse bottleneck? Am I understanding what will happen correctly? Thanks

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  • Integrate OpenId into an existing site

    - by Andrea
    I have a working web application which already has a login and registration system. I'm looking for some advice on how to do it. Until now, users have a username, an email, a password and some optional fields. The registrartion is the usual process with email confirmation. Now I'd like to allow users to use OpenId. So I have added an openid field to the table. There are two different login forms, and users which are already registered can add their openid info and use either login form. The problem is with new users who come on the site for the first time and try to login with OpenId. I create a new user for them, and I don't need a password, but still I need at least a username, which is used on the site (I'm not sure if the email is needed). So my problems are: 1) How do I manage validation? Some fields are required for some users, (e.g. a password) but not for some others. I mean, I can do this, but it immediately gets messy. 2) Should I ask for a username and email on the first OpenId login? On the one hand I'd say yes, but I fear this vanishes the advantages of using OpenId, that is, not having to provide details. 3) I could get the details via SReg or AttributeExchange, but most providers have a bad support for those. For instance my Gmail OpenId account does not tell the email (!). Is there some place to learn more about the current support for these extensions?

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  • PDO using singleton stored as class properity

    - by Misiur
    Hi again. OOP drives me crazy. I can't move PDO to work. Here's my DB class: class DB extends PDO { public function &instance($dsn, $username = null, $password = null, $driver_options = array()) { static $instance = null; if($instance === null) { try { $instance = new self($dsn, $username, $password, $driver_options); } catch(PDOException $e) { throw new DBException($e->getMessage()); } } return $instance; } } It's okay when i do something like this: try { $db = new DB(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } But this: try { $db = DB::instance(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } Does nothing. I mean, even when I use wrong password/username, I don't get any exception. Second thing - I have class which is "heart" of my site: class Core { static private $instance; public $db; public function __construct() { if(!self::$instance) { $this->db = DB::instance(DB_TYPE.':hpost='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } return self::$instance; } private function __clone() { } } I've tried to use "new DB" inside class, but this: $r = $core->db->query("SELECT * FROM me_config"); print_r($r->fetch()); Return nothing. $sql = "SELECT * FROM me_config"; print_r($core->db->query($sql)); I get: PDOStatement Object ( [queryString] => SELECT * FROM me_config ) I'm really confused, what am I doing wrong?

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  • Sorcery/Capybara: Cannon log in with :js => true

    - by PlankTon
    I've been using capybara for a while, but I'm new to sorcery. I have a very odd problem whereby if I run the specs without Capybara's :js = true functionality I can log in fine, but if I try to specify :js = true on a spec, username/password cannot be found. Here's the authentication macro: module AuthenticationMacros def sign_in user = FactoryGirl.create(:user) user.activate! visit new_sessions_path fill_in 'Email Address', :with => user.email fill_in 'Password', :with => 'foobar' click_button 'Sign In' user end end Which is called in specs like this: feature "project setup" do include AuthenticationMacros background do sign_in end scenario "creating a project" do "my spec here" end The above code works fine. However, IF I change the scenario spec from (in this case) scenario "adding questions to a project" do to scenario "adding questions to a project", :js => true do login fails with an 'incorrect username/password' combination. Literally the only change is that :js = true. I'm using the default capybara javascript driver. (Loads up Firefox) Any ideas what could be going on here? I'm completely stumped. I'm using Capybara 2.0.1, Sorcery 0.7.13. There is no javascript on the sign in page and save_and_open_page before clicking 'sign in' confirms that the correct details are entered into the username/password fields. Any suggestions really appreciated - I'm at a loss.

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  • Resolving the WMI DNS Host Name

    - by Stephen Murby
    I am trying to make a comparison between a machine name i have retrieved from AD, and the DNS Host Name i want to get using WMI from the machine. I currently have: foreach (SearchResult oneMachine in allMachinesCollected) { pcName = oneMachine.Properties["name"][0].ToString(); ConnectionOptions setupConnection = new ConnectionOptions(); setupConnection.Username = USERNAME; setupConnection.Password = PASSWORD; setupConnection.Authority = "ntlmdomain:DOMAIN"; ManagementScope setupScope = new ManagementScope("\\\\" + pcName + "\\root\\cimv2", setupConnection); setupScope.Connect(); ObjectQuery dnsNameQuery = new ObjectQuery("SELECT * FROM Win32_ComputerSystem"); ManagementObjectSearcher dnsNameSearch = new ManagementObjectSearcher(setupScope, dnsNameQuery); ManagementObjectCollection allDNSNames = dnsNameSearch.Get(); string dnsHostName; foreach (ManagementObject oneName in allDNSNames) { dnsHostName = oneName.Properties["DNSHostName"].ToString(); if (dnsHostName == pcName) { shutdownMethods.ShutdownMachine(pcName, USERNAME, PASSWORD); MessageBox.Show(pcName + " has been sent the reboot command"); } } } } But i get a ManagementException dnsHostName = oneName.Properties["DNSHostName"].ToString(); << here saying not found. Any ideas?

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  • How to check for a null object reference when validating forms in MVC

    - by quakkels
    Hello SO, I'm experimenting with validating forms in the asp.net MVC framework. I'm focusing on server side validation for the time being. I've come across an error that I'm not sure how to rectify. System.NullReferenceException: Object reference not set to an instance of an object. The code that throws the error is: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create([Bind(Exclude="ID")] MembersCreate mc ) { mc.Modules = ModuleListDataContext.GetModuleList(); ViewData.Model = mc; //Validation using ModelState // // //line below errors when form field is empty // if ((string)mc.Member.Username.Trim() == "") ModelState.AddModelError("Member.Username", "Username is required."); if (!ModelState.IsValid) return View(); try { // TODO: Add insert logic here return RedirectToAction("Index","Home"); } catch { return View(); } } When I put spaces in the field it performs exactly as i want, but if I leave the field blank and press submit I get the error. What's the best way to avoid this error and still validate blank form fields? Thanks all -

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  • Inserting variables into a query string - it won't work!

    - by Jonesy
    Basically i have a query string that when i hardcode in the catalogue value its fine. when I try adding it via a variable it just doesn't pick it up. This works: Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=WaspTrackAsset_NROI;User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") This doesn't: Public Sub GetWASPAcr() connection.Open() Dim dt As New DataTable() Dim username As String = HttpContext.Current.User.Identity.Name Dim sqlCmd As New SqlCommand("SELECT WASPDatabase FROM dbo.aspnet_Users WHERE UserName = '" & username & "'", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) If dt.Rows.Count > 0 Then For i As Integer = 0 To dt.Rows.Count - 1 If dt.Rows(i)("WASPDatabase") Is DBNull.Value Then WASP = "" Else WASP = "WaspTrackAsset_" + dt.Rows(i)("WASPDatabase") End If Next End If connection.Close() End Sub Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=" & WASP & ";User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") When I debug the catalog is empty in the query string but the WASP variable holds the value "WaspTrackAsset_NROI" Any idea's why? Cheers, jonesy

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  • mongoose updating a field in a MongoDB not working

    - by Masiar
    I have this code var UserSchema = new Schema({ Username: {type: String, index: true}, Password: String, Email: String, Points: {type: Number, default: 0} }); [...] var User = db.model('User'); /* * Function to save the points in the user's account */ function savePoints(name, points){ if(name != "unregistered user"){ User.find({Username: name}, function(err, users){ var oldPoints = users[0].Points; var newPoints = oldPoints + points; User.update({name: name}, { $inc: {Points: newPoints}}, function(err){ if(err){ console.log("some error happened when update"); } else{ console.log("update successfull! with name = " + name); User.find({Username: name}, function(err, users) { console.log("updated : " + users[0].Points); }); } }); }); } } savePoints("Masiar", 666); I would like to update my user (by finding it with its name) by updating his/her points. I'm sure oldPoints and points contain a value, but still my user keep being at zero points. The console prints "update successful". What am I doing wrong? Sorry for the stupid / noob question. Masiar

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  • Make Trac use a Drupal user database for authentication

    - by denisw
    I am trying to set up a Trac instance as a complement to a Drupal site and would like to give users the possibility to use their Drupal account in Trac, too, ideally in a single sign-on fashion (if the user is already logged into Drupal, he is automatically logged into Trac). The question now is how to accomplish this. I have found a plugin named DrupalIntegration which seems to implement that functionality; however, it is poorly documented - in fact, not documented at all. I managed to install it, but don't know how to configure it. Here is what I came up with from looking at the source code and the documentation of the AccountManager plugin (on which DrupalIntegration depends): [components] trac.web.auth.loginmodule = disabled acct_mgr.api = enabled acct_mgr.web_ui.LoginModule = enabled acct_mgr.web_ui.RegistrationModule = disabled TracDrupalIntegration.DrupalIntegration = enabled [account-manager] drupal_database = mysql://<usernam>:<password>@localhost/<db> password_store = DrupalIntegration (<username>, <password> and <db> are naturally substituted with the correct data). While the Trac log says: 2010-12-18 10:54:09,570 Trac[loader] DEBUG: Loading TracDrupalIntegration from /usr/lib/python2.5/site-packages/TracDrupalIntegration-0.1-py2.5.egg this doesn't seem to work: trying to log in with a Drupal username / password results in an "Invalid username or password" error. Has someone used the DrupalIntegration and can point out to me what I did wrong? Or is there any other approach you know (or even have used in the past) to integrate Drupal and Trac that way?

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  • Javascript XMLHttpRequest Post method

    - by user535617
    Hey So I have a question about posting using an XMLHttpRequest. In theory, if I am to post a username and password to an https domain (which I have yet to get working, unfortunately) would the responseText then change to the next website, or should the text fields become filled in? What normally happens is you navigate to this page via browser, enter a username and password, and it uses a POST method when the submit button is clicked, doing some authentication under the hood and returning a different page. I feel like maybe the responseText should even stay exactly the same (which is what happens now), but I don't know as I have no experience with this kind of thing. this.requests[1].open("POST", "https://" + this.address, true); var query = "target=%2Fcgi-bin%2FStatusConfig.cgi%3FPage%3Dindex&userfile=&username=user&password=pass&log+in=Log+in"; this.requests[1].setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); this.requests[1].setRequestHeader("Content-length", query.length); this.requests[1].setRequestHeader("Keep-Alive", 115); this.requests[1].setRequestHeader("Connection", "keep-alive"); this.requests[1].setRequestHeader("Host", this.address); this.requests[1].send(query); this.requests[1].onreadystatechange = onReadyStateChange1; Then basically onReadyStateChange1 displays the responseText when ready. Any light that could be shed on what SHOULD be happening with the post and responseText would be very appreciated. As would any advice in getting the new, logged into page. For further clarification, what I'm trying to do is log in and then return the new page, because the login page displays only log in information/functionality and the page after logging in has a lot of relevant information. I'm not trying to check the credentials as much as I'm trying to get it (the script) to log in so it can access the next page. Granted, the credentials will have to be valid for that. Thanks all.

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  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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  • Paramiko ssh output stops at --more--

    - by Anesh
    The output stops printing at --more-- any idea how to get the end of the output >>> import paramiko >>> ssh = paramiko.SSHClient() >>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) >>> conn=ssh.connect("ipaddress",username="user", password="pass") >>> channel = ssh.invoke_shell() >>> channel.send("en\n") 3 >>> channel.send("password\n") 9 >>> channel.send("show security local-user-list\n") 30 >>> results = '' >>> channel.send("\n") 1 >>> results += channel.recv(5000) >>> print results bluecoat>en Password: bluecoat#show security local-user-list Default List: local_user_database Append users loaded from file to default list: false local_user_database Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: Groups: admin_local Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: <username> Hashed Password: Enabled: true Groups: <username> Hashed Password: Enabled: true **--More--** As you can see above the output stops printing at --more-- any idea how to get the output to print till the end.

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  • Providing custom database functionality to custom asp.net membership provider

    - by IrfanRaza
    Hello friends, I am creating custom membership provider for my asp.net application. I have also created a separate class "DBConnect" that provides database functionality such as Executing SQL statement, Executing SPs, Executing SPs or Query and returning SqlDataReader and so on... I have created instance of DBConnect class within Session_Start of Global.asax and stored to a session. Later using a static class I am providing the database functionality throughout the application using the same single session. In short I am providing a single point for all database operations from any asp.net page. I know that i can write my own code to connect/disconnect database and execute SPs within from the methods i need to override. Please look at the code below - public class SGI_MembershipProvider : MembershipProvider { ...... public override bool ChangePassword(string username, string oldPassword, string newPassword) { if (!ValidateUser(username, oldPassword)) return false; ValidatePasswordEventArgs args = new ValidatePasswordEventArgs(username, newPassword, true); OnValidatingPassword(args); if (args.Cancel) { if (args.FailureInformation != null) { throw args.FailureInformation; } else { throw new Exception("Change password canceled due to new password validation failure."); } } ..... //Database connectivity and code execution to change password. } .... } MY PROBLEM - Now what i need is to execute the database part within all these overriden methods from the same database point as described on the top. That is i have to pass the instance of DBConnect existing in the session to this class, so that i can access the methods. Could anyone provide solution on this. There might be some better techniques i am not aware of that. The approach i am using might be wrong. Your suggessions are always welcome. Thanks for sharing your valuable time.

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  • Why is my element variable always null in this foreach loop?

    - by ZeroDivide
    Here is the code: public IEnumerable<UserSummary> getUserSummaryList() { var db = new entityContext(); List<UserSummary> model = new List<UserSummary>(); List<aspnet_Users> users = (from user in db.aspnet_Users select user).ToList<aspnet_Users>(); foreach (aspnet_Users u in users) //u is always null while users is a list that contains 4 objects { model.Add(new UserSummary() { UserName = u.UserName, Email = u.aspnet_Membership.Email, Role = Roles.GetRolesForUser(u.UserName).First(), AdCompany = u.AD_COMPANIES.ad_company_name != null ? u.AD_COMPANIES.ad_company_name : "Not an Advertiser", EmployeeName = u.EMPLOYEE.emp_name != null ? u.EMPLOYEE.emp_name : "Not an Employee" }); } return model; } For some reason the u variable in the foreach loop is always null. I've stepped through the code and the users collection is always populated. The table entity for db.aspnet_Users is the users table that comes with asp.net membership services. I've only added a couple associations to it. edit : image of debugger

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  • Is is possible to determine a password input string as plaintext or hashed?

    - by Godders
    I have a RESTful API containing a URI of /UserService/Register. /UserService/Register takes an XML request such as: <UserRegistrationRequest> <Password>password</Password> <Profile> <User> <UserName>username</UserName> </User> </Profile> </UserRegistrationRequest> I have the following questions given the above scenario: Is there a way (using C# and .Net 3.5+) of enforcing/validating that clients calling Register are passing a hashed password rather than plaintext? Is leaving the choice of hashing algorithm to be used to the client a good idea? We could provide a second URI of /UserService/ComputePasswordHash which the client would call before calling /UserService/Register. This has the benefit of ensuring that each password is hashed using the same algorithm. Is there a mechanism within REST to ensure that a client has called one URI before calling another? Hope I've explained myself ok. Many thanks in advance for any help.

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • Create Session Variable from different datasources?

    - by Szafranamn
    Currently I am developing a dynamic website using Dreamweaver cs5 with ColdFusion 9 and using Access to create my databases along with QuickBooks and QODBC to create database. I have established a login session variable stemming from the login page. This session variable is being drawn from one Datasource "Access" Table "Logininfo" Field "FullName" but I wanted to create another session variable either at this point or further into the member's page to use in a query sequence. This session variable would stem from another Datasoucre "QBs" Table "Invoice" Field "CustomerRefFullName" which is generated through Quickbooks and QODBC. I am not sure if this is possible but if it is how do I do it. I want to do this so I can query the Invoice database to upload the customer's Invoices unique to them onto their page. So it would have to be related to their login credentials. If there is another better route to take I would greatly appreciate the advice. Below is the login code if there is additional information needed let me know. This is my current thinking/plan to do what I wish to intend hence the need to create the session variable: I have another Datasource "QBs" with a Table "Invoice" when I create another webpage for the customer to see their invoice I need to create a recordset that accesses that Table. In order to do so I think the best way would some home convert the session.FullName (which came from Access Datasource, Logininfor Table) into a session.CustomerRefFullName (which would have to come from (Datasource: QBs Table: Invoice Field: CustomerRefFullName) that way I could set the query WHERE CustomerRefFullName and have each logged in user see their specific Invoices. So is there a way to turn the session variable off one datasource/table into a different sessionvariable off a new datasource/table even if it is unique just to that page??? <cfif IsDefined("FORM.username")> SELECT FullName, Username,Password,AccessLevels FROM Logininfo WHERE Username= AND Password=

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • Using a join with three tables when a field might be null

    - by John
    Hello, The code below works great. It combines data from two MySQL tables. I would like to modify it by pulling in some data from a third MySQL table called "comment." In the HTML table below, "title" is a field in the MySQL table "submission." Every "title" has a corresponding "submissionid" field. The field "submissionid" is also found in the "comment" MySQL table. In the HTML table below, I would like "countComments" to equal the number of times a field called "commentid" appears in the MySQL table "comment" for any given "submissionid," where the "submissionid" is the same in both the "submission" and "comment" tables, and where the "submissionid" corresponds to the "title" being used. Here's the catch: if there is no row in the MySQL table "comment" that corresponds with the "submissionid" being used for "table", I would like "countComments" to equal to zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • can I add properties to a typo3 extbase domain model object?

    - by The Newbie Qs
    I want to store a username in a coupon object, each coupon object already has the uid of the user who created it. I can loop over the coupon objects and read the associated usernames from fe_users but how then will I save those usernames into the coupons so when they are passed to the template the usernames can be read like so coupon.username, or in some other easy way so each username will appear on the page with the right coupon as they are all printed out in a table? If I was doing basic php instead of typo3 i would just define a query but what is the typo3 v4.5 way? My code so far - which dies on the line where I try to assign the new property --creatorname -- to the $coup object. public function listAction() { $coupons = $this->couponRepository->findAll(); // @var Tx_Extbase_Domain_Repository_FrontendUserRepository $userRepository */ $userRepository = $this->objectManager->get("Tx_Extbase_Domain_Repository_FrontendUserRepository"); foreach ($coupons as $coup) { echo '<br />test '.$coup->getCreator(); echo '<br />count = '.$userRepository->countAll().'<br />'; $newObject = $userRepository->findByUid( intval($coup->getCreator())); //var_dump($newObject); var_dump($coup); echo '<br />getUsername '.$newObject->getUsername() ; $coup['creatorname'] = $newObject->getUsername(); echo '<br />creatorname '.$coup['creatorname'] ; } $this->view->assign('coupons', $coupons); }

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  • How to add a new entry to a multiple has_many association?

    - by siulamvictor
    I am not sure am I doing these correct. I have 3 models, Account, User, and Event. Account contains a group of Users. Each User have its own username and password for login, but they can access the same Account data under the same Account. Events is create by a User, which other Users in the same Account can also read or edit it. I created the following migrations and models. User migration class CreateUsers < ActiveRecord::Migration def self.up create_table :users do |t| t.integer :account_id t.string :username t.string :password t.timestamps end end def self.down drop_table :users end end Account migration class CreateAccounts < ActiveRecord::Migration def self.up create_table :accounts do |t| t.string :name t.timestamps end end def self.down drop_table :accounts end end Event migration class CreateEvents < ActiveRecord::Migration def self.up create_table :events do |t| t.integer :account_id t.integer :user_id t.string :name t.string :location t.timestamps end end def self.down drop_table :events end end Account model class Account < ActiveRecord::Base has_many :users has_many :events end User model class User < ActiveRecord::Base belongs_to :account end Event model class Event < ActiveRecord::Base belongs_to :account belongs_to :user end so.... Is this setting correct? Every time when a user create a new account, the system will ask for the user information, e.g. username and password. How can I add them into correct tables? How can I add a new event? I am sorry for such a long question. I am not very understand the rails way in handling such data structure. Thank you guys for answering me. :)

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  • starting rails in test environment

    - by Brian D.
    I'm trying to load up rails in the test environment using a ruby script. I've tried googling a bit and found this recommendation: require "../../config/environment" ENV['RAILS_ENV'] = ARGV.first || ENV['RAILS_ENV'] || 'test' This seems to load up my environment alright, but my development database is still being used. Am I doing something wrong? Here is my database.yml file... however I don't think it is the issue development: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_development pool: 5 username: root password: dev host: localhost # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_test pool: 5 username: root password: dev host: localhost production: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_production pool: 5 username: root password: dev host: localhost I can't use ruby script/server -e test because I'm trying to run ruby code after I load rails. More specifically what I'm trying to do is: run a .sql database script, load up rails and then run automated tests. Everything seems to be working fine, but for whatever reason rails seems to be loading in the development environment instead of the test environment. Here is a shortened version of the code I am trying to run: system "execute mysql script here" require "../../config/environment" ENV['RAILS_ENV'] = ARGV.first || ENV['RAILS_ENV'] || 'test' describe Blog do it "should be initialized successfully" do blog = Blog.new end end I don't need to start a server, I just need to load my rails code base (models, controllers, etc..) so I can run tests against my code. Thanks for any help.

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