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  • Stored Procedure Does Not Fire Last Command

    - by jp2code
    On our SQL Server (Version 10.0.1600), I have a stored procedure that I wrote. It is not throwing any errors, and it is returning the correct values after making the insert in the database. However, the last command spSendEventNotificationEmail (which sends out email notifications) is not being run. I can run the spSendEventNotificationEmail script manually using the same data, and the notifications show up, so I know it works. Is there something wrong with how I call it in my stored procedure? [dbo].[spUpdateRequest](@packetID int, @statusID int output, @empID int, @mtf nVarChar(50)) AS BEGIN -- SET NOCOUNT ON added to prevent extra result sets from -- interfering with SELECT statements. SET NOCOUNT ON; DECLARE @id int SET @id=-1 -- Insert statements for procedure here SELECT A.ID, PacketID, StatusID INTO #act FROM Action A JOIN Request R ON (R.ID=A.RequestID) WHERE (PacketID=@packetID) AND (StatusID=@statusID) IF ((SELECT COUNT(ID) FROM #act)=0) BEGIN -- this statusID has not been entered. Continue SELECT ID, MTF INTO #req FROM Request WHERE PacketID=@packetID WHILE (0 < (SELECT COUNT(ID) FROM #req)) BEGIN SELECT TOP 1 @id=ID FROM #req INSERT INTO Action (RequestID, StatusID, EmpID, DateStamp) VALUES (@id, @statusID, @empID, GETDATE()) IF ((@mtf IS NOT NULL) AND (0 < LEN(RTRIM(@mtf)))) BEGIN UPDATE Request SET MTF=@mtf WHERE ID=@id END DELETE #req WHERE ID=@id END DROP TABLE #req SELECT @id=@@IDENTITY, @statusID=StatusID FROM Action SELECT TOP 1 @statusID=ID FROM Status WHERE (@statusID<ID) AND (-1 < Sequence) EXEC spSendEventNotificationEmail @packetID, @statusID, 'http:\\cpweb:8100\NextStep.aspx' END ELSE BEGIN SET @statusID = -1 END DROP TABLE #act END Idea of how the data tables are connected:

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  • Reading text files line by line, with exact offset/position reporting

    - by Benjamin Podszun
    Hi. My simple requirement: Reading a huge ( a million) line test file (For this example assume it's a CSV of some sorts) and keeping a reference to the beginning of that line for faster lookup in the future (read a line, starting at X). I tried the naive and easy way first, using a StreamWriter and accessing the underlying BaseStream.Position. Unfortunately that doesn't work as I intended: Given a file containing the following Foo Bar Baz Bla Fasel and this very simple code using (var sr = new StreamReader(@"C:\Temp\LineTest.txt")) { string line; long pos = sr.BaseStream.Position; while ((line = sr.ReadLine()) != null) { Console.Write("{0:d3} ", pos); Console.WriteLine(line); pos = sr.BaseStream.Position; } } the output is: 000 Foo 025 Bar 025 Baz 025 Bla 025 Fasel I can imagine that the stream is trying to be helpful/efficient and probably reads in (big) chunks whenever new data is necessary. For me this is bad.. The question, finally: Any way to get the (byte, char) offset while reading a file line by line without using a basic Stream and messing with \r \n \r\n and string encoding etc. manually? Not a big deal, really, I just don't like to build things that might exist already..

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  • php (rar) i want to rar a folder using rar on Ubuntu (linux) by php (on dedi server) noob

    - by Steve
    hey guyz i want rar (not tar) my folder on my server by using php RAR RAR 3.93 Copyright (c) 1993-2010 Alexander Roshal 15 Mar 2010 Registered to my real name OS Ubuntu Release (Karmic) kernel linux 2.6.32.2-xxxx-grs-ipv4-32 Gnome 2.28.1 latest php an lighthttpd i have tried these things http://php.net/manual/en/function.escapeshellarg.php // may be wrong code http://php.net/manual/en/function.exec.php http://php.net/manual/en/function.shell-exec.php my command (working in ssh and nautilus script) rar a -m0 /where/file/will/saved/file_name.rar /location/ti/data/dir/datafolder php code $log=Shell_exec("rar a -m0 /where/file/will/saved/file_name.rar /location/ti/data/dir/datafolder"); echo $log; one method is left which i don't know how to use and its working on server that is by somefile_to_execute_command.sh i have to execute .sh file from php need to send some variables (command) and i tried this method can rar file with a script named RapidLeech but its rar from only its own files dir only :( but i want to do in different directories. Rapid Leech rar class http://paste2.org/p/791668 i m able run shell command with php (cp(copy),mv(move),ls(directory list),rm(remove aka delete)) but got failed to run rar i gives no output i also tried to given path rar and i used alot commands with php Shell_exec function and working like they work with ssh and i have tried almost 80 % method given on net and failed from last 3days i m over now plz help me i need php script file working plz reply if u have any info n code and experience about rar and this kinda :( problem i m 99% noob just used code mean search Google collect script make my own working thing (for personal use only) n now i m failed to rar folder and file :(( now plz provide me code plz don't talk in technical language because i m just reading my first php book (for dummies :D) mean noob and 0.1 plz help me as much u can thankx

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  • Get the key and value of Map that is used Inside another Map (JAVA)

    - by Umair Iqbal
    I am using a map inside another map, The key of the outer map is Integer and the value is another Map. I get the values as expected but I don't know how to get the key and value of teh inner map. Here is the code Map<Integer, Map<Integer, Integer>> cellsMap = new HashMap<Integer, Map<Integer, Integer>>(); Map<Integer , Integer> bandForCell = cellsMap.get(band_number); if (bandForCell == null) bandForCell = new HashMap<Integer, Integer>(); bandForCell.put(erfcn, cell_found); cellsMap.put(band_number, bandForCell); csv.writeCells((Map<Integer, Map<Integer, Integer>>) cellsMap); public void writeCells (Map<Integer, Map<Integer, Integer>> cellsMap ) throws IOException { for (Map.Entry<Integer, Map<Integer, Integer>> entry : cellsMap.entrySet()) { System.out.println("Key: " + entry.getKey() + ". Value: " + entry.getValue() + "\n"); } } Out put of my Map Key: 20 Value: {6331=0, 6330=1, 6329=1, 6328=0, 6335=1, 6437=0, 6436=1} The value in the above output is another map. How can I get the key and value of the inner map from the value of the outer map? Like Keys of inner map = 6331, 6330, 6329 .... and values of inner map = 0 , 1 , 1 , 0 ... Thanks

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  • Implementing a normal website inside ASP.NET MVC 2

    - by cc0
    I have a website consisting of an index.html, a number of style sheet files as well as some javascript files. Then I needed a way for this site to communicate efficiently with a Microsoft SQL Server, so I was recommended to use the MVC framework to facilitate that kind of communication. I created the C#.net controller code needed to output the necessary information from the database using URL parameters, so now I am trying to put the whole web-site together inside the MVC framework. I started an empty project-template in MVC 2 framework. I'm sure there must be a good way to implement the current code into this framework, but I am very uncertain as to what the best approach to this would be. Could anyone point me in the right direction here? I'm not sure whether I need to change any of the current HTML, or exactly what to add to it. I'd love to see some kind of guide or tutorial, or just any advice I can get as I try to learn this. Any help is very much appreciated!

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  • activemerchant PayPalExpress transaction is invalid

    - by Ameya Savale
    I am trying to integrate activemerchant into my ruby on rails application. This is my controller where I get the purchase attirbutes and create a PaypalExpressResponse object def checkout total_as_cents, purchase_params = get_setup_params(Schedule.find(params[:schedule]), request) setup_response = @gateway.setup_purchase(total_as_cents, purchase_params) redirect_to @gateway.redirect_url_for(setup_response.token) end @gateway is my PaypalExpressGateway object which I create using this method in my controller def assign_gateway @gateway = PaypalExpressGateway.new( :login => api_user, :password => api_pass, :signature => api_signature ) end I got the api_user, api_pass, and api_signature values from my developer.paypal.com account, when I logged in for the first time there was already a sandbox user created as a merchant which is where I got the api credentials from. And finally here is my get_setup_params method: def get_setup_params(schedule, request) purchase_params = { :ip => request.remote_ip, :return_url => url_for(:action => 'review', :only_path => false, :sched => schedule.id), :cancel_return_url => register_path, :allow_note => true, :item => schedule.id } return to_cents(schedule.fee), purchase_params end How ever when I click on the checkout button, I get redirected to a sandbox paypal page saying "This transaction is invalid. Please return to the recipient's website to complete your transaction using their regular checkout flow." I'm not sure exactly what's wrong, I think the problem lies in the credentials but don't know why. Any help will be appreciated. One other point, I'm running this in my development environment so I have put this in my config file config.after_initialize do ActiveMerchant::Billing::Base.mode = :test end UPDATE Found out what the problem was, my return cancel url was invalid instead of using register_path, I used url_for(action: "action-name", :only_path => false) this answer helped me Rails ActiveMerchant - Paypal Express Checkout Error even though I wasn't able to see the output of the response like the person has managed to do

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  • Minimal assembler program for CP/M 3.1 (z80)

    - by Andrew J. Brehm
    I seem to be losing the battle against my stupidity. This site explains the system calls under various versions of CP/M. However, when I try to use call 2 (C_WRITE, console output), nothing much happens. I have the following code. ORG 100h LD E,'a' LD C,2 CALL 5 CALL 0 I recite this here from memory. If there are typos, rest assured they were not in the original since the file did compile and I had a COM file to start. I am thinking the lines mean the following: Make sure this gets loaded at address 100h (0h to FFh being the zero page). Load ASCII 'a' into E register for system call 2. Load integer 2 into C register for system call 2. Make system call (JMP to system call is at address 5 in zero page). End program (Exit command is at address 0 in zero page). The program starts and exits with no problems. If I remove the last command, it hangs the computer (which I guess is also expected and shows that CALL 0 works). However, it does not print the ASCII character. (But it does print an extra new line, but the system might have done that.) How can I get my CP/M program to do what the system call is supposed to do? What am I doing wrong?

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  • Error when loading YAML config files in Rails

    - by ZelluX
    I am configuring Rails with MongoDB, and find a strange problem when paring config/mongo.yml file. config/mongo.yml is generated by executing script/rails generate mongo_mapper:config, and it looks like following: defaults: &defaults host: 127.0.0.1 port: 27017 development: <<: *defaults database: tc_web_development test: <<: *defaults database: tc_web_test From the config file we can see the objects development and test should both have a database field. But when it is parsed and loaded in config/initializers/mongo.db, config = YAML::load(File.read(Rails.root.join('config/mongo.yml'))) puts config.inspect MongoMapper.setup(config, Rails.env) the strange thing comes: the output of puts config.inspect is {"defaults"=>{"host"=>"127.0.0.1", "port"=>27017}, "development"=>{"host"=>"127.0.0.1", "port"=>27017}, "test"=>{"host"=>"127.0.0.1", "port"=>27017}} which does not contain database attribute. But when I execute the same statements in a plain ruby console, instead of using rails console, mongo.yml is parsed in a right way. {"defaults"=>{"host"=>"127.0.0.1", "port"=>27017}, "development"=>{"host"=>"127.0.0.1", "port"=>27017, "database"=>"tc_web_development"}, "test"=>{"host"=>"127.0.0.1", "port"=>27017, "database"=>"tc_web_test"}} I am wondering what may be the cause of this problem. Any ideas? Thanks.

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  • Problems compiling libjingle/gtk+-2.0 for Mac OS X

    - by mindthief
    Hi All, I'm trying to compile libjingle on Mac OSX Snow Leopard. The INSTALL file said to './configure', 'make' and 'make install', as usual. But make fails for me. Initially it gave some messages indicating that I didn't have pkg-config installed (I guess OSX doesn't come with it installed?), so I downloaded pkg-config from http://pkgconfig.freedesktop.org/releases/ Now I get this message: Package gtk+-2.0 was not found in the pkg-config search path. Perhaps you should add the directory containing `gtk+-2.0.pc' to the PKG_CONFIG_PATH environment variable No package 'gtk+-2.0' found I tried to install gtk by using the script at SourceForge: http://sourceforge.net/projects/gtk-osx/ (this is the website pointed to by the gtk website) Running the script didn't really seem to do anything, here is the output: $./gtk-osx-build-setup.sh Checking out jhbuild (2.27.3) from git... From git://git.gnome.org/jhbuild * tag 2.27.3 -> FETCH_HEAD Installing jhbuild... Installing jhbuild configuration... Installing gtk-osx moduleset files... Done. $ And I still get that error message about "Package gtk+-2.0 not found" while make-ing libjingle. Help will be appreciated, thanks!

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  • ByteFlow installation Error on Windows

    - by Patrick
    Hi Folks, When I try to install ByteFlow on my Windows development machine, I got the following MySQL error, and I don't know what to do, please give me some suggestion. Thank you so much!!! E:\byteflow-5b6d964917b5>manage.py syncdb !!! Read about DEBUG in settings_local.py and then remove me !!! !!! Read about DEBUG in settings_local.py and then remove me !!! J:\Program Files\Python26\lib\site-packages\MySQLdb\converters.py:37: DeprecationWarning: the sets module is deprecated from sets import BaseSet, Set Creating table auth_permission Creating table auth_group Creating table auth_user Creating table auth_message Creating table django_content_type Creating table django_session Creating table django_site Creating table django_admin_log Creating table django_flatpage Creating table actionrecord Creating table blog_post Traceback (most recent call last): File "E:\byteflow-5b6d964917b5\manage.py", line 11, in <module> execute_manager(settings) File "J:\Program Files\Python26\lib\site-packages\django\core\management\__init__.py", line 362, in execute_manager utility.execute() File "J:\Program Files\Python26\lib\site-packages\django\core\management\__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "J:\Program Files\Python26\lib\site-packages\django\core\management\base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "J:\Program Files\Python26\lib\site-packages\django\core\management\base.py", line 222, in execute output = self.handle(*args, **options) File "J:\Program Files\Python26\lib\site-packages\django\core\management\base.py", line 351, in handle return self.handle_noargs(**options) File "J:\Program Files\Python26\lib\site-packages\django\core\management\commands\syncdb.py", line 78, in handle_noargs cursor.execute(statement) File "J:\Program Files\Python26\lib\site-packages\django\db\backends\util.py", line 19, in execute return self.cursor.execute(sql, params) File "J:\Program Files\Python26\lib\site-packages\django\db\backends\mysql\base.py", line 84, in execute return self.cursor.execute(query, args) File "J:\Program Files\Python26\lib\site-packages\MySQLdb\cursors.py", line 166, in execute self.errorhandler(self, exc, value) File "J:\Program Files\Python26\lib\site-packages\MySQLdb\connections.py", line 35, in defaulterrorhandler raise errorclass, errorvalue _mysql_exceptions.OperationalError: (1071, 'Specified key was too long; max key length is 767 bytes')

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  • "You have already activated" message even when using bundle exec

    - by juanpastas
    I am installing gems in my Gemfile in shared path as Capistrano does by default, and when I run: bundle exec rake assets:precompile RAILS_ENV=production I get: You have already activated rake 0.9.2.2, but your Gemfile requires rake 10.0.4. Using bundle exec may solve this. See that: cat Gemfile.lock | grep rake returns: rake (>= 0.8.7) rake (10.0.4) This is my gem environment output: - RUBYGEMS VERSION: 1.8.24 - RUBY VERSION: 1.9.3 (2013-06-27 patchlevel 448) [x86_64-linux] - INSTALLATION DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - RUBY EXECUTABLE: /opt/bitnami/ruby/bin/ruby - EXECUTABLE DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/bin - RUBYGEMS PLATFORMS: - ruby - x86_64-linux - GEM PATHS: - /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - "gemhome" => "/home/bitnami/my_app/shared/bundle/ruby/1.9.1/" - "gempath" => ["/home/bitnami/my_app/shared/bundle/ruby/1.9.1/"] - REMOTE SOURCES: - http://rubygems.org/ Update which -a rake /opt/bitnami/rvm/bin/rake /opt/bitnami/ruby/bin/rake Update 2 I tried giving full path to rake, but same problem

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  • How do I install websocket module for Node.js on Debian VPS?

    - by Ollie Shaw
    I currently am renting a VPS from Dreamhost which runs Debian. I am still learning command line on this OS, but fast! I have successfully installed Node.js, now I want to install the websocket module found here: https://github.com/Worlize/WebSocket-Node From the root user, I have run the following command: npm install websocket The error thrown is: [websocket v1.0.7] Native code compile failed!! On Windows, native extensions require Visual Studio and Python. On Unix, native extensions require Python, make and a C++ compiler. Start npm with --websocket:verbose to show compilation output (if any). What commands should I issue to install this websocket module and its requirements? Thanks very much! Edit: When I run sudo apt-get install gcc make I get this message: Reading package lists... Done Building dependency tree Reading state information... Done gcc is already the newest version. gcc set to manually installed. make is already the newest version. 0 upgraded, 0 newly installed, 0 to remove and 44 not upgraded. And the same error when trying to install WebSocket.

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  • ActiveRecord/sqlite3 column type lost in table view?

    - by duncan
    I have the following ActiveRecord testcase that mimics my problem. I have a People table with one attribute being a date. I create a view over that table adding one column which is just that date plus 20 minutes: #!/usr/bin/env ruby %w|pp rubygems active_record irb active_support date|.each {|lib| require lib} ActiveRecord::Base.establish_connection( :adapter => "sqlite3", :database => "test.db" ) ActiveRecord::Schema.define do create_table :people, :force => true do |t| t.column :name, :string t.column :born_at, :datetime end execute "create view clowns as select p.name, p.born_at, datetime(p.born_at, '+' || '20' || ' minutes') as twenty_after_born_at from people p;" end class Person < ActiveRecord::Base validates_presence_of :name end class Clown < ActiveRecord::Base end Person.create(:name => "John", :born_at => DateTime.now) pp Person.all.first.born_at.class pp Clown.all.first.born_at.class pp Clown.all.first.twenty_after_born_at.class The problem is, the output is Time Time String When I expect the new datetime attribute of the view to be also a Time or DateTime in the ruby world. Any ideas? I also tried: create view clowns as select p.name, p.born_at, CAST(datetime(p.born_at, '+' || '20' || ' minutes') as datetime) as twenty_after_born_at from people p; With the same result.

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  • Switching languages on a website with PHP

    - by jnkrois
    Hello everybody, I'm just looking for some advice. I'm creating a website that offers (at least) 2 languages. The way I'm setting it up is by using XML files for the language, PHP to retrieve the values in the XML nodes. Say you have any XML file, being loaded as follows: <?php $lang = "en"; $xmlFile = simplexml_load_file("$lang/main.xml"); ?> Once the file contents are available, I just output each node into an HTML tag like so: <li><?php echo $xmlFile->navigation->home; ?></li> which in turn is equal to : <li><a href="#">Home</a></li> as a nav bar link. Now, the way in which I'm switching languages is by changing the value of the "$lang" variable, through a "$_POST", like so: if(isset($_POST['es'])){ $lang = "es"; }elseif(isset($_POST['en'])){ $lang = "en"; } The value of the "$lang" variable is reset and the new file is loaded, loading as well all the new nodes from the new XML file, hence changing the language. I'm just wondering if there is another way to reset the "$lang" variable using something else, other than "$_POST" or "$_GET". I don't want to use query string either. I know I could use JavaScript or jQuery to achieve this, but I'd like to make the site not too dependable on JavaScript. I'd appreciate any ideas or advice. Thanks

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  • How can I diagnose "Cannot determine peer address" in my Perl TCP script?

    - by MadBoy
    I've this little script which does it's job pretty well but sometimes it tends to fail. It fails in 2 cases: with error send: Cannot determine peer address at ./tcp-new.pl line 52 with no output or anything, it just fails to deliver what it got to connected Tcp Client. Usually it happens after I disconnect from server, go home and connect it again. To fix this restart is required and it starts working. Sometimes this problem is followed by problem mentioned in point 1. Note: it's not problem when I disconnect and reconnect to it again within short amount of time (unless error nr 1 happens). So can anyone help me make this code be a bit more stable so I don't have to restart it every day? #!/usr/bin/perl use strict; use warnings; use IO::Socket; use IO::Select; my $tcp_port = "10008"; my $udp_port = "2099"; my $tcp_socket = IO::Socket::INET->new( Listen => SOMAXCONN, LocalPort => $tcp_port, Proto => 'tcp', ReuseAddr => 1, ); my $udp_socket = IO::Socket::INET->new( LocalPort => $udp_port, Proto => 'udp', ); my $read_select = IO::Select->new(); my $write_select = IO::Select->new(); $read_select->add($tcp_socket); $read_select->add($udp_socket); while (1) { my @read = $read_select->can_read(); foreach my $read (@read) { if ($read == $tcp_socket) { my $new_tcp = $read->accept(); $write_select->add($new_tcp); } elsif ($read == $udp_socket) { my $recv_buffer; $udp_socket->recv($recv_buffer, 1024, undef); my @write = $write_select->can_write(); foreach my $write (@write) { $write->send($recv_buffer); } } } }

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  • Need some help with a MySQL subquery count

    - by Ferdy
    I'm running into my own limits of MySQL query skills, so I hope some SQL guru can help out on this one. The situation is as follow: I have images that can be tagged. As you might expect this is stored in three tables: Image Tag Tag_map (maps images to tags) I have a SQL query that calculates the related tags based on a tag id. The query basically checks what other tags were used for images for images using that tag. Example: Image1 tagged as "Bear" Image2 tagged as "Bear" and "Canada" If I throw "Bear" (or its tag id) at the query, it will return "Canada". This works fine. Here's the query: SELECT tag.name, tag.id, COUNT(tag_map.id) as cnt FROM tag_map,tag WHERE tag_map.tag_id = tag.id AND tag.id != '185' AND tag_map.image_id IN (SELECT tag_map.image_id FROM tag_map INNER JOIN tag ON tag_map.tag_id = tag.id WHERE tag.id = '185') GROUP BY tag_map.id LIMIT 0,100 The part I'm stuck with is the count. For each related tag returned, I want to know how many images are in that tag. Currently it always returns 1, even if there are for example 3. I've tried counting different columns all resulting in the same output, so I guess there is a flaw in my thinking.

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  • Global resources can't be resolved after publishing Website in VS2008

    - by Scoregraphic
    Hi there I have a web-project running in VS 2008. We have some global resource files (*.resx) in the App_GlobalResources folder for internationalisation. All this works like a charm on my local IIS installation out of VS. But when I publish my web-project to the local filesystem and/or another server, all the resources can no longer be found. So I guess the pre-compilation is somehow corrupting stuff. When I call the pre-compiled web, I get an error that the resource object with key xyz cannot be found, although it could be found before. I checked with .NET reflector if the resource stuff made it into the *.dlls. All those identifiers are there (bin/Web.dll, bin/<culture>/Web.resources.dll). The identifiers are loaded like this: <asp:MenuItem NavigateUrl="~/OrderNew.aspx" Text="<%$ Resources:MyProject, MenuNewOrder %>" Value="NewOrder"> The resource files are called MyProject.resx and MyProject.<culture>.resx where <culture> corresponds the the specific culture (i.e. MyProject.de-DE.resx). Any ideas how to solve this? I really appreciate any help. Thanks Edit: If I copy the App_GlobalResources folder manually to the output, the resources may be loaded normally. So I really really wonder what this pre-compilation is all about. I'm still interested in solving the issue "the right way".

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  • How can I diff against a revision of a single file using only the default Git GUI tools?

    - by Rich
    I want to view the history of a single file, and then compare a single revision from that history against the current version. On the command line, this is easy: Run: git log -- <filename> Locate the version you want to compare, Run: git diff <commitid> -- <filename> But how can this be done using only the default Git gui tools, git gui and gitk? I know of two methods using gitk, but they're both horribly clunky: Either: Select the New View option from the View menu, Type in the full path to your file into the box labelled Enter files and directories to include, one per line, Locate the version you want to compare by looking at the highlighted items in the top pane, and click on it to select it, Right-click on the current version and select Diff selected - this, Or: Select Tree in the bottom right-hand pane, Locate the file you want to look at, right-click on it, and select Highlight this only, Locate the version you want to compare by looking at the highlighted items in the top pane, and click on it to select it, Right-click on the current version and select Diff selected - this, Click on the file in the bottom right-hand pane to jump to it in the diff output, or scroll manually. Is a better method than this?

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  • Paramaterising SQL in SSIS

    - by Anonymouslemming
    Hi all, I'm trying to paramaterize some queries in SSIS. After some reading, it sounds like my best option is to create one variable that contains my base sql, another that contains my criteria and a final variable that is evaluated as an expression that includes both of these. I want to end up with an SQL query that is effectively UPDATE mytable set something='bar' where something_else='foo' So my first two variables have the scope of my package and are as follows: Name: BaseSQL Data Type: String Value: UPDATE mytable set something = 'bar' where something_else = Name: MyVariable Data Type: String Value: foo My third variable has a scope of the data flow task where I want to use this SQL and is as follows: Name: SQLQuery Data Type: String Value: @[User::BaseSQL] + "'" + @[User::MyVariable] + "'" EvaluateAsExpression: True In the OLE DB Source, I then choose my connection and 'SQL command from variable' and select User::SQLQuery from the dropdown box. The Variable Value window then displays the following: @[User::BaseSQL] + "'" + @[User::MyVariable] + "'" This is as desired, and would provide the output I want from my DB. The variable name dropdown also contains User::BaseSQL and User::MyVariable so I believe that my namespaces are correct. However, when I then click preview, I get the following error when configuring an OLE DB Source (using SQL command from variable): TITLE: Microsoft Visual Studio Error at Set runtime in DB [Set runtime in myDb DB [1]]: SSIS Error Code DTS_E_OLEDBERROR. An OLE DB error has occurred. Error code: 0x80040E14. An OLE DB record is available. Source: "Microsoft SQL Server Native Client 10.0" Hresult: 0x80040E14 Description: "Statement(s) could not be prepared.". An OLE DB record is available. Source: "Microsoft SQL Server Native Client 10.0" Hresult: 0x80040E14 Description: "Must declare the scalar variable "@".". (Microsoft Visual Studio) Can anyone advise what I'm missing or how I can resolve this please ? Thanks in advance!

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  • asp.net ajax + http module fails

    - by Sri Kumar
    Hi, I am trying my hands on asp.net+ajax+httpmodule. My Form <form id="LoginForm" runat="server"> <asp:ScriptManager ID="LoginScriptMgr" runat="server"></asp:ScriptManager> <asp:UpdatePanel ID="LoginPanel" runat="server"> <ContentTemplate> <asp:Label ID="lblLoginHeader" Text="Login" runat="server"></asp:Label> <asp:TextBox ID="txtUserName" runat="server"></asp:TextBox> <asp:TextBox ID="txtPassword" runat="server" TextMode="Password"></asp:TextBox> <asp:Button ID="btnLogin" Text="Login" runat="server" OnClick="Login" /> <asp:Label ID="lblLoginStatus" runat="server" /> </ContentTemplate> </asp:UpdatePanel> </form> C# Code protected void Login(object sender, EventArgs e) { lblLoginStatus.Text = "Login Successful"; } Web.config <httpModules> <add name="TimeModule" type="MyWebPortal.App_Code.TimeModule,App_Code"/> </httpModules> HTTP Module public class TimeModule : IHttpModule { private HttpApplication oApps = null; public void Dispose() { } public void Init(System.Web.HttpApplication context) { oApps = context; context.PreSendRequestContent += new EventHandler (context_PreSendRequestContent); } void context_PreSendRequestContent(object sender, EventArgs e) { string message = "&lt;!-- This page is being processed at " + System.DateTime.Now.ToString() + " -->"; oApps.Context.Response.Output.Write(message); } } When i remove the TimeModule from Web.config my ajax works. If add the TimeModule then the label doesn't show the message "Login Successful". Removing the ajax panel and with httpmodule available the label shows the message. So, how ajax panel was related to httpmodules?

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  • Problems uploading pictures to Facebook wall.

    - by Miguel Ángel Ortuño
    Hi, i'm trying to upload a JPEG picture to Facebook wall using libcurl. Appareantly the connection is established but cURL hangs when waiting for server response. The libcurl output is the following: About to connect() to api.facebook.com port 80 (#0) Trying 66.220.146.15... * connected Connected to api.facebook.com (66.220.146.15) port 80 (#0) POST /restserver.php?api_key=e57addd5a98ac4445e36359043ded182&call_id=3&caption=ddfg&format=JSON&method=facebook.photos.upload&session_key=a3fc731e4c0329201606daeb-723233322&sig=a3f32226cff3e49ec799cf7dcc17a57e&ss=1&v=1.0?method=photos.upload HTTP/1.1 User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.14) Gecko/20080404 Firefox/2.0.0.14 Host: api.facebook.com Accept: / Content-Type: multipart/form-data; charset=UTF-8; boundary=PPoSt_dElImTTer MIME-version: 1.0 Content-Length: 128033 Expect: 100-continue Done waiting for 100-continue And the C++ code is as follow: String post_header = "Content-Type: multipart/form-data; charset=UTF-8; boundary=PPoSt_dElImTTer\r\nMIME-version: 1.0\r\n"; // POST binary data curl_slist* chunk = NULL; chunk = curl_slist_append(chunk, post_header.c_str()); curl_easy_setopt(m_http, CURLOPT_HTTPHEADER, chunk); curl_easy_setopt(m_http, CURLOPT_POST, true); curl_easy_setopt(m_http, CURLOPT_POSTFIELDS, buf); curl_easy_setopt(m_http, CURLOPT_POSTFIELDSIZE, all_size); curl_easy_setopt(m_http, CURLOPT_URL, m_request.c_str()); curl_easy_setopt(m_http, CURLOPT_WRITEFUNCTION, Facebook::Request::httpCallback); curl_easy_setopt(m_http, CURLOPT_WRITEDATA, this); curl_easy_setopt(m_http, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.14) Gecko/20080404 Firefox/2.0.0.14"); curl_easy_setopt(m_http, CURLOPT_VERBOSE, true);

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  • XSLT-Looping and recursion based on parameter passed

    - by contactkx
    I have an XML organized like below- <section name="Parent 1 Text here" ID="1" > <section name="Child 1 Text here" ID="11"> </section> <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 1 Text here" ID="22"> </section> <section name="Child 2 Text here" ID="23"> <section name="GrandChild Text here" ID="232" > </section> </section> </section> I have to produce the below output XML - <section name="Parent 1 Text here" ID="1" > <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 2 Text here" ID="23"> </section> </section> I have to achive above using XSLT 1.0 transformation. I was planning to pass a comma separated string as a parameter with value= "1,12,121,2,23" My question- How to loop the comma separated parameter in XSLT 1.0 ? Is there a simpler way to achieve the above. Please remember I have to do this in XSLT 1.0 Your help is appreciated.

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  • how avoids deadlock condition

    - by rima
    Hi I try to write a program like a compiler.In this case I must simulate these codes of SQLPL(This one can be just for example).for example in command prompt i wana do these: c:\> sqlplus .... Enter User-Name:(here we must enter username) xxxx Enter password:(same up)yyyyy ... sql>(now i want to send my sql command to shell)prompt "rima"; "rima" [<-output] sql> prompt "xxxx" sql> exit very simple. I try to use this code: ProcessStartInfo psi = new ProcessStartInfo( @"sqlplus"); psi.UseShellExecute = false; psi.CreateNoWindow = true; psi.RedirectStandardInput = true; psi.RedirectStandardOutput = true; //psi.RedirectStandardError = true; Process process = new Process(); process.StartInfo = psi; bool started = process.Start(); if (started) { process.StandardInput.WriteLine("user/password"); process.StandardInput.Flush(); string ret = process.StandardOutput.ReadLine(); // <-- stalls here System.Console.WriteLine("sqlplus says :" + ret + "\"."); } i find out it form here but as if u read this code has problem!DEADLOCK Condition problem! this is my second time i ask my question,every time my knowledge growing,but i cant get how I can solve my problem at last!!! So I kindly kiss your hand,please help me,these process is not clear for me.any one can give me a code that handle my problem?Already i look at all codes,also I try to use ProcessRunner that in my last post some one offer me,but I cant use it also,i receive an error. I hope by first example u find out what i want,and solve the second code problem... thanks I use C# for implemantation

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  • Addresses stored in SQL server have many small variations(errors)

    - by MAW74656
    I have a table in my database which stores packing slips and their information. I'm trying to query that table and get each unique address. I've come close, but I still have many near misses and I'm looking for a way to exclude these near duplicates from my select. Sample Data CompanyCode CompanyName Addr1 City State Zip 10033 UNITED DIE CUTTING & FINISHIN 3610 HAMILTON AVE CLEVELAND Ohio 44114 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVE CLEVELAND Ohio 44114 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVE. CLEVELAND Ohio 44114 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVENUE CLEVELAND Ohio 44114 10033 UNITED DIECUTTING & FINISHING 3610 HAMILTON AVE CLEVELAND Ohio 44144 10033 UNITED FINISHING 3610 HAMILTON AVE CLEVLAND Ohio 44114 10033 UNITED FINISHING & DIE CUTTING 3610 HAMILTON AVE CLEVELAND Ohio 44114 And all I want is 1 record. Is there some way I can get the "Average" record? Meaning, if most of the records say CLEVELAND instead of CLEVLAND, I want my 1 record to say CLEVELAND. Is there any way to par this data down to what I'm looking for? Desired Output CompanyCode CompanyName Addr1 City State Zip 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVE CLEVELAND Ohio 44114

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  • Can't log in with a valid password using Authlogic and Ruby on Rails?

    - by kbighorse
    We support a bit of an unusual scheme. We don't require a password on User creation, and use password_resets to add a password to the user later, on demand. The problem is, once a password is created, the console indicates the password is valid: user.valid_password? 'test' = true but in my UserSessions controller, @user_session.save returns false using the same password. What am I not seeing? Kimball UPDATE: Providing more details, here is the output when saving the new password: Processing PasswordResetsController#update (for 127.0.0.1 at 2011-01-31 14:01:12) [PUT] Parameters: {"commit"="Update password", "action"="update", "_method"="put", "authenticity_token"="PQD4+eIREKBfHR3/fleWuQSEtZd7RIvl7khSYo5eXe0=", "id"="v3iWW5eD9P9frbEQDvxp", "controller"="password_resets", "user"={"password"="johnwayne"}} The applicable SQL is: UPDATE users SET updated_at = '2011-01-31 22:01:12', crypted_password = 'blah', perishable_token = 'blah', password_salt = 'blah', persistence_token = 'blah' WHERE id = 580 I don't see an error per se, @user_session.save just returns false, as if the password didn't match. I skip validating passwords in the User model: class User < ActiveRecord::Base acts_as_authentic do |c| c.validate_password_field = false end Here's the simplified controller code: def create logger.info("SAVED SESSION? #{@user_session.save}") end which outputs: Processing UserSessionsController#create (for 127.0.0.1 at 2011-01-31 14:16:59) [POST] Parameters: {"commit"="Login", "user_session"={"remember_me"="0", "password"="johnwayne", "email"="[email protected]"}, "action"="create", "authenticity_token"="PQD4+eIREKBfHR3/fleWuQSEtZd7RIvl7khSYo5eXe0=", "controller"="user_sessions"} User Columns (2.2ms) SHOW FIELDS FROM users User Load (3.7ms) SELECT * FROM users WHERE (users.email = '[email protected]') ORDER BY email ASC LIMIT 1 SAVED SESSION? false CACHE (0.0ms) SELECT * FROM users WHERE (users.email = '[email protected]') ORDER BY email ASC LIMIT 1 Redirected to http://localhost:3000/login Lastly, the console indicates that the new password is valid: $ u.valid_password? 'johnwayne' = true Would love to do it all in the console, is there a way to load UserSession controller and call methods directly? Kimball

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