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  • groovy regexpression

    - by srinath
    Hi, How to get file name from these lines using groovy . File file = new File(SOURCE_FILE_NAME).eachLine{line- println line } getting line like this : /usr/local/testing.groovy /usr/local/picture.jpg expecting output: testing.groovy picture.jpg Can any one help me using any if regex needed . thanks

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  • Mouse left button up event and openfiledialog

    - by phm
    I have few images in a grid, then when i click a button, a "open file dialog" comes up.(of course, over the images) Microsoft.Win32.OpenFileDialog dlgOpenFiles = new Microsoft.Win32.OpenFileDialog(); dlgOpenFile.DoModal(); The images have a LeftButtonUp event attached. The problem is that if i select a file by double clicking it, the open file dialog closes(which is good), but besides that, the image behind the clicked file is receiving a LeftButtonUp message which is not good at all. I am using wpf/c#/vs2010

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  • ssh client problem: Connection reset by peer

    - by yonix
    I'm having a really annoying problem on my Ubuntu laptop. I noticed it today, after upgrading to Ubuntu 11.04, although I'm not entirely sure this is the cause as I played with my ssh keys a few days ago. The problem is, whenever I try to ssh to ANY host I get the following error: Read from socket failed: Connection reset by peer running with -vvv gives the following output: OpenSSH_5.8p1 Debian-1ubuntu3, OpenSSL 0.9.8o 01 Jun 2010 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug2: ssh_connect: needpriv 0 debug1: Connecting to hostname [10.0.0.2] port 22. debug1: Connection established. debug1: permanently_set_uid: 0/0 debug1: identity file /root/.ssh/id_rsa type -1 debug1: identity file /root/.ssh/id_rsa-cert type -1 debug1: identity file /root/.ssh/id_dsa type -1 debug1: identity file /root/.ssh/id_dsa-cert type -1 debug1: identity file /root/.ssh/id_ecdsa type -1 debug1: identity file /root/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 1.99, remote software version OpenSSH_4.2 debug1: match: OpenSSH_4.2 pat OpenSSH_4* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.8p1 Debian-1ubuntu3 debug2: fd 3 setting O_NONBLOCK debug3: load_hostkeys: loading entries for host "hostname" from file "/root/.ssh/known_hosts" debug3: load_hostkeys: loaded 0 keys debug1: SSH2_MSG_KEXINIT sent Read from socket failed: Connection reset by peer My /etc/ssh/ssh_config: Host * SendEnv LANG LC_* HashKnownHosts yes GSSAPIAuthentication no GSSAPIDelegateCredentials no I can connect to my laptop from any other server via ssh, and I can also ssh localhost from my laptop successfully. I can connect to all these other server from other laptops, and I don't see anything in the logs of the other servers regarding my failed attempt. I tried to stop iptables, didn't help. I tried several tricks I could find online with my /etc/ssh/ssh_config, but I was unsuccessful in solving the problem... Any ideas? Edit: This is the log from one of the hosts I try to connect to: May 1 19:15:23 localhost sshd[2845]: debug1: Forked child 2847. May 1 19:15:23 localhost sshd[2845]: debug3: send_rexec_state: entering fd = 8 config len 577 May 1 19:15:23 localhost sshd[2845]: debug3: ssh_msg_send: type 0 May 1 19:15:23 localhost sshd[2845]: debug3: send_rexec_state: done May 1 19:15:23 localhost sshd[2847]: debug1: rexec start in 5 out 5 newsock 5 pipe 7 sock 8 May 1 19:15:23 localhost sshd[2847]: debug1: inetd sockets after dupping: 3, 3 May 1 19:15:23 localhost sshd[2847]: Connection from 10.0.0.7 port 55747 May 1 19:15:23 localhost sshd[2847]: debug1: Client protocol version 2.0; client software version OpenSSH_5.8p1 Debian-1ubuntu3 May 1 19:15:23 localhost sshd[2847]: debug1: match: OpenSSH_5.8p1 Debian-1ubuntu3 pat OpenSSH* May 1 19:15:23 localhost sshd[2847]: debug1: Enabling compatibility mode for protocol 2.0 May 1 19:15:23 localhost sshd[2847]: debug1: Local version string SSH-2.0-OpenSSH_5.3 May 1 19:15:23 localhost sshd[2847]: debug2: fd 3 setting O_NONBLOCK May 1 19:15:23 localhost sshd[2847]: debug2: Network child is on pid 2848 May 1 19:15:23 localhost sshd[2847]: debug3: preauth child monitor started May 1 19:15:23 localhost sshd[2847]: debug3: mm_request_receive entering May 1 19:15:23 localhost sshd[2848]: debug3: privsep user:group 74:74 May 1 19:15:23 localhost sshd[2848]: debug1: permanently_set_uid: 74/74 May 1 19:15:23 localhost sshd[2848]: debug1: list_hostkey_types: ssh-rsa,ssh-dss May 1 19:15:23 localhost sshd[2848]: debug1: SSH2_MSG_KEXINIT sent May 1 19:15:23 localhost sshd[2848]: debug3: Wrote 784 bytes for a total of 805 May 1 19:15:23 localhost sshd[2848]: fatal: Read from socket failed: Connection reset by peer

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  • How to get ROI of an image in Android

    - by uday
    Hi All, I have an image file (.jpg) which contains image like Face. From my application i want to capture that particular Face part and copy that part into a new bitmap file. I have a rectangular co-ordinates of that Face part, so how do i capture only Face part from the image file and copy that into a bitmap file?? Could any body help me to get rid of this problem.... Thanks & Regards Uday Kiran

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  • IE6 turns jar into zip

    - by Sean Martin
    Using windows server, I have a path to a file that, when you click the button, executes the jar file and runs the program. At least in firefox. The problem occurs with IE6. It takes my file.jar and turns it into file.zip. Any suggestions here?

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  • NFS4 / ZFS: revert ACL to clean/inherited state

    - by Keiichi
    My problem is identical to this Windows question, but pertains NFS4 (Linux) and the underlying ZFS (OpenIndiana) we are using. We have this ZFS shared via NFS4 and CIFS for Linux and Windows users respectively. It would be nice for both user groups to benefit from ACLs, but the one missing puzzle piece goes thusly: Each user has a home, where he sets a top-level, inherited ACL. He can later on refine permissions for the contained files/folders iteratively. Over time, sometimes permissions need to be generalized again to avoid increasing pollution of ACL entries. You can tweak the ACL of every single file if need be to obtain the wanted permissions, but that defeats the purpose of inherited ACLs. So, how can an ACL be completely cleared like in the question linked above? I have found nothing about what a blank, inherited ACL should look like. This usecase simply does not seem to exist. In fact, the solaris chmod manpage clearly states A- Removes all ACEs for current ACL on file and replaces current ACL with new ACL that represents only the current mode of the file. I.e. we get three new ACL entries filled with stuff representing the permission bits, which is rather useless for cleaning up. If I try to manually remove every ACE, on the last one I get chmod A0- <file> chmod: ERROR: Can't remove all ACL entries from a file Which by the way makes me think: and why not? In fact, I really want the whole file-specific ACL gone. The same holds for linux, which enumerates ACEs starting with 1(!), and verbalizes its woes less diligently nfs4_setacl -x 1 <file> Failed setxattr operation: Unknown error 524 So, what is the idea behind ACLs under Solaris/NFS? Can they never be cleaned up? Why does the recursion option for the ACL setting commands pollute all children instead of setting a single ACL and making the children inherit? Is this really the intention of the designers? I can clean up the ACLs using a windows client perfectly well, but am I supposed to tell the linux users they have to switch OS just to consolidate permissions?

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  • Sort directory listing using RecursiveDirectoryIterator

    - by Scott Saunders
    I'm using RecursiveDirectoryIterator and RecursiveIteratorIterator to build a file listing tree using code like below. I need to the list to be sorted - either directories then files alphabetically, or just alphabetically. Can anyone tell me how to sort the file list? $dir_iterator = new RecursiveDirectoryIterator($groupDirectory); $iterator = new RecursiveIteratorIterator($dir_iterator, RecursiveIteratorIterator::SELF_FIRST); foreach ($iterator as $file) { // do stuff with $file }

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  • GitLab on a fresh Ubuntu 13 EC2 instance

    - by Polly
    I've spun up a fresh Amazon EC2 instance for a micro Ubuntu 13 server to be used as a GitLab server. I know the specs are a little low, but it should serve well for my purposes. It has an elastic (static) IP address that I have created an A record for git.mydomain.com. The first thing I did to the instance was add 1GB of swap to keep it happy from a memory perspective. I then set the hostname of the box to be git.mydomain.com and followed https://github.com/gitlabhq/gitlabhq/blob/6-2-stable/doc/install/installation.md to the letter. Everything seems to have worked, except for the web server side of things. Doing a gitlab:check shows the following: Checking Environment ... Git configured for git user? ... yes Has python2? ... yes python2 is supported version? ... yes Checking Environment ... Finished Checking GitLab Shell ... GitLab Shell version >= 1.7.4 ? ... OK (1.7.4) Repo base directory exists? ... yes Repo base directory is a symlink? ... no Repo base owned by git:git? ... yes Repo base access is drwxrws---? ... yes update hook up-to-date? ... yes update hooks in repos are links: ... can't check, you have no projects Running /home/git/gitlab-shell/bin/check Check GitLab API access: /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `initialize': Connection refused - connect(2) (Errno::ECONNREFUSED) from /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `open' from /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `block in connect' from /usr/local/lib/ruby/2.0.0/timeout.rb:52:in `timeout' from /usr/local/lib/ruby/2.0.0/net/http.rb:877:in `connect' from /usr/local/lib/ruby/2.0.0/net/http.rb:862:in `do_start' from /usr/local/lib/ruby/2.0.0/net/http.rb:851:in `start' from /home/git/gitlab-shell/lib/gitlab_net.rb:62:in `get' from /home/git/gitlab-shell/lib/gitlab_net.rb:29:in `check' from /home/git/gitlab-shell/bin/check:11:in `<main>' gitlab-shell self-check failed Try fixing it: Make sure GitLab is running; Check the gitlab-shell configuration file: sudo -u git -H editor /home/git/gitlab-shell/config.yml Please fix the error above and rerun the checks. Checking GitLab Shell ... Finished Checking Sidekiq ... Running? ... yes Number of Sidekiq processes ... 1 Checking Sidekiq ... Finished Checking GitLab ... Database config exists? ... yes Database is SQLite ... no All migrations up? ... yes GitLab config exists? ... yes GitLab config outdated? ... no Log directory writable? ... yes Tmp directory writable? ... yes Init script exists? ... yes Init script up-to-date? ... yes projects have namespace: ... can't check, you have no projects Projects have satellites? ... can't check, you have no projects Redis version >= 2.0.0? ... yes Your git bin path is "/usr/bin/git" Git version >= 1.7.10 ? ... yes (1.8.3) Checking GitLab ... Finished It seems like I'm very nearly there. Searching on this error I have only found advice that unfortunately hasn't helped. I'm not using any kind of SSL setup, which a lot of the posts I found were about. I have tried appending 127.0.0.1 git.mydomain.com to /etc/hosts and giving the instance a reboot but there was no change. My config/gitlab.yml file has host: git.mydomain.com in it, and my gitlab-shell/config.yml has gitlab_url: "http://git.mydomain.com/" in it. I'm sure I'm missing something simple, but I've been through every relevant link I can find and have had no positive results; thank you in advance for any help!

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  • problem with python script

    - by hidayat
    I want to run a csh file from a python scrip, example, #!/usr/bin/python import os os.system("source path/to/file.csh") and I want this file to run in the same shell as I am running the python script, because the file.csh script is settings some environment variables that I need. Does anyone know how to do this in Python?

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  • Import Excel to sqlserver 2005 using Sqlbulkupload

    - by Jayesh
    Hi all, I want to upload excel file using SqlBulkCopy into sql server 2005 table. My excel file size is 43MB. When i am uploading this file it will display error message that "The request filtering module is configured to deny a request that exceeds the request content length.". My web.config file setting is <httpRuntime executionTimeout="12000" maxRequestLength="2097151" useFullyQualifiedRedirectUrl="false" minFreeThreads="8" minLocalRequestFreeThreads="4" appRequestQueueLimit="100"/> Thanks in advance.

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  • Java FilePath Android

    - by user654460
    I have an android app that I am trying to get a file path for a SAX parser. I have the following structure: assets:(Where my xml file is) src(same level as assets) com msi androidrss(The calling java file is in here) I tried several variations of this: InputSource is = new InputSource("file://../../../../assets/Rss.xml"); But I always get a FNF Exception Any suggestions? Thanks

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  • Paperclip renaming files after they're saved

    - by fivetwentysix
    How do I rename a file after is has been uploaded and saved? My problem is that I need to parse information about the files automatically in order to come up with the file name the file should be saved as with my application, but I can't access the information required to generate the file name till the record for the model has been saved.

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  • Partial view postback from a standard Html form with MVC

    - by fearofawhackplanet
    I have a file upload button on my MVC view. After the file is uploaded, my FileList partial view on the page should refresh. I tried to upload with Ajax.BeginForm(), but have discovered that Ajax will not submit file data. I've got the file upload working now by using the jQuery Form plugin, which lets you ajaxify the normal Html.BeginForm() submit method. Is is still possible to trigger the partial page update using this method?

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  • Two-Hop SSH connection with two separate public keys

    - by yigit
    We have the following ssh hop setup: localhost -> hub -> server hubuser@hub accepts the public key for localuser@localhost. serveruser@server accepts the public key for hubuser@hub. So we are issuing ssh -t hubuser@hub ssh serveruser@server for connecting to server. The problem with this setup is we can not scp directly to the server. I tried creating .ssh/config file like this: Host server user serveruser port 22 hostname server ProxyCommand ssh -q hubuser@hub 'nc %h %p' But I am not able to connect (yigit is localuser): $ ssh serveruser@server -v OpenSSH_6.1p1, OpenSSL 1.0.1c 10 May 2012 debug1: Reading configuration data /home/yigit/.ssh/config debug1: /home/yigit/.ssh/config line 19: Applying options for server debug1: Reading configuration data /etc/ssh/ssh_config debug1: Executing proxy command: exec ssh -q hubuser@hub 'nc server 22' debug1: permanently_drop_suid: 1000 debug1: identity file /home/yigit/.ssh/id_rsa type 1000 debug1: identity file /home/yigit/.ssh/id_rsa-cert type -1 debug1: identity file /home/yigit/.ssh/id_dsa type -1 debug1: identity file /home/yigit/.ssh/id_dsa-cert type -1 debug1: identity file /home/yigit/.ssh/id_ecdsa type -1 debug1: identity file /home/yigit/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9p1 Debian-5ubuntu1 debug1: match: OpenSSH_5.9p1 Debian-5ubuntu1 pat OpenSSH_5* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_6.1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA cb:ee:1f:78:82:1e:b4:39:c6:67:6f:4d:b4:01:f2:9f debug1: Host 'server' is known and matches the ECDSA host key. debug1: Found key in /home/yigit/.ssh/known_hosts:33 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: /home/yigit/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /home/yigit/.ssh/id_dsa debug1: Trying private key: /home/yigit/.ssh/id_ecdsa debug1: No more authentication methods to try. Permission denied (publickey). Notice that it is trying to use the public key localuser@localhost for authenticating on server and fails since it is not the right one. Is it possible to modify the ProxyCommand so that the key for hubuser@hub is used for authenticating on server?

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  • How to generalize a method call in Java (to avoid code duplication)

    - by dln385
    I have a process that needs to call a method and return its value. However, there are several different methods that this process may need to call, depending on the situation. If I could pass the method and its arguments to the process (like in Python), then this would be no problem. However, I don't know of any way to do this in Java. Here's a concrete example. (This example uses Apache ZooKeeper, but you don't need to know anything about ZooKeeper to understand the example.) The ZooKeeper object has several methods that will fail if the network goes down. In this case, I always want to retry the method. To make this easy, I made a "BetterZooKeeper" class that inherits the ZooKeeper class, and all of its methods automatically retry on failure. This is what the code looked like: public class BetterZooKeeper extends ZooKeeper { private void waitForReconnect() { // logic } @Override public Stat exists(String path, Watcher watcher) { while (true) { try { return super.exists(path, watcher); } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } @Override public byte[] getData(String path, boolean watch, Stat stat) { while (true) { try { return super.getData(path, watch, stat); } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } @Override public void delete(String path, int version) { while (true) { try { super.delete(path, version); return; } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } } (In the actual program there is much more logic and many more methods that I took out of the example for simplicity.) We can see that I'm using the same retry logic, but the arguments, method call, and return type are all different for each of the methods. Here's what I did to eliminate the duplication of code: public class BetterZooKeeper extends ZooKeeper { private void waitForReconnect() { // logic } @Override public Stat exists(final String path, final Watcher watcher) { return new RetryableZooKeeperAction<Stat>() { @Override public Stat action() { return BetterZooKeeper.super.exists(path, watcher); } }.run(); } @Override public byte[] getData(final String path, final boolean watch, final Stat stat) { return new RetryableZooKeeperAction<byte[]>() { @Override public byte[] action() { return BetterZooKeeper.super.getData(path, watch, stat); } }.run(); } @Override public void delete(final String path, final int version) { new RetryableZooKeeperAction<Object>() { @Override public Object action() { BetterZooKeeper.super.delete(path, version); return null; } }.run(); return; } private abstract class RetryableZooKeeperAction<T> { public abstract T action(); public final T run() { while (true) { try { return action(); } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } } } The RetryableZooKeeperAction is parameterized with the return type of the function. The run() method holds the retry logic, and the action() method is a placeholder for whichever ZooKeeper method needs to be run. Each of the public methods of BetterZooKeeper instantiates an anonymous inner class that is a subclass of the RetryableZooKeeperAction inner class, and it overrides the action() method. The local variables are (strangely enough) implicitly passed to the action() method, which is possible because they are final. In the end, this approach does work and it does eliminate the duplication of the retry logic. However, it has two major drawbacks: (1) it creates a new object every time a method is called, and (2) it's ugly and hardly readable. Also I had to workaround the 'delete' method which has a void return value. So, here is my question: is there a better way to do this in Java? This can't be a totally uncommon task, and other languages (like Python) make it easier by allowing methods to be passed. I suspect there might be a way to do this through reflection, but I haven't been able to wrap my head around it.

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  • passing nsdata in stringwithformat

    - by milanjansari
    hello, How to pass nsdata in below of the string NSData *myData = [NSData dataWithContentsOfFile:pathDoc]; pathDoc = [NSString stringWithFormat:@"<size>%d</size><type>%d</type><cdate>%@</cdate><file>%c</file><fname>File</fname>",fileSizeVal,filetype,creationDate,file]; Any idea about this? Thanks you, Milan

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  • While try to open the project - getting error.

    - by Gopal
    Using Visual Studio 2008 I have .net file name like UPS.Tek, version - Visual Studio 2005 C# files are UPSReport.cs (Visual C# Source File) UPSConn.Cs (Visual C# Source File) UPSBase.cs (Visual C# Source File) ...., When i try to open the C# files individually in VS 2008, the C# files are opening But When I try to open this UPS.Tek in Visual Studio 2008, It showing error as "make sure the application for the project type .csproj is installed" How to solve this error.

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  • XCode CoreData files not found/opening

    - by jAmi
    Hello, I am using the Xcode 3.1.4 that means SDK 3.1.2 The problem is that I cannot open .xcdatamodel (Core Data) file and I don't even get the Data Model option in Design Menu bar. When ever I double click and try to open the file, XCode gives me an error saying that it cannot find the file at (my project's path).Perhaps it was moved or deleted? , but the file exists at the same path. Please help me out as I haven't upgraded my system to Snow Leopard so cant use SDK 3.2 Regards jAmi

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  • Can anyone tell me why these lines are not working?

    - by user343934
    I am trying to generate tree with fasta file input and Alignment with MuscleCommandline import sys,os, subprocess from Bio import AlignIO from Bio.Align.Applications import MuscleCommandline cline = MuscleCommandline(input="c:\Python26\opuntia.fasta") child= subprocess.Popen(str(cline), stdout = subprocess.PIPE, stderr=subprocess.PIPE, shell=(sys.platform!="win32")) align=AlignIO.read(child.stdout,"fasta") outfile=open('c:\Python26\opuntia.phy','w') AlignIO.write([align],outfile,'phylip') outfile.close() I always encounter with these problems Traceback (most recent call last): File "", line 244, in run_nodebug File "C:\Python26\muscleIO.py", line 11, in align=AlignIO.read(child.stdout,"fasta") File "C:\Python26\Lib\site-packages\Bio\AlignIO_init_.py", line 423, in read raise ValueError("No records found in handle") ValueError: No records found in handle

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  • how to increase the limit of exceptions in oracle

    - by Arunachalam
    how to increase the limit of exceptions in oracle ? i have a excel sheet in which their are about 900 records to be appended .so i converted the excel to dat file and wrote a batch file that read from the dat file and appends it to the concern table but the batch file stop execution once the exceptions reach 51(all integrity constrain parent key not found) so the remaining valid files are not updated .its very difficult to find which record has integrity constrain is there a way to increase this exception limit ?

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  • Re-generate Code Gen Files in Visual Studio

    - by dev.e.loper
    I'm using Visual Studio 2008. I've added a control on a page but can't reference it in code-behind file. When I looked at the Code-Gen file, I didn't find my new control. It looks like Visual Studio didn't update Code Gen file to include my control. Is there a way to manually re-generate that Code Gen file?

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  • Autoconf -- building with static library (newbie)

    - by EB
    I am trying to migrate my application from manual build to autoconf, which is working very nicely so far. But I have one static library that I can't figure out how to integrate. That library will NOT be located in the usual library locations - the location of the binary (.a file) and header (.h file) will be given as a configure argument. (Notably, even if I move the .a file to /usr/lib or anywhere else I can think of, it still won't work.) It is also not named traditionally (it does not start with "lib" or "l"). Manual compilation is working with these (directory is not predictable - this is just an example): gcc ... -I/home/john/mystuff /home/john/mystuff/helper.a (Uh, I actually don't understand why the .a file is referenced directly, not with -L or anything. Yes, I have a half-baked understanding of building C programs.) So, in my configure.ac, I can use the relevant configure argument to successfully find the header (.h file) using AC_CHECK_HEADER. Inside the AC_CHECK_HEADER I then add the location to CPFLAGS and the #include of the header file in the actual C code picks it up nicely. Given a configure argument that has been put into $location and the name of the needed files are helper.h and helper.a (which are both in the same directory), here is what works so far: AC_CHECK_HEADER([$location/helper.h], [AC_DEFINE([HAVE_HELPER_H], [1], [found helper.h]) CFLAGS="$CFLAGS -I$location"]) Where I run into difficulties is getting the binary (.a file) linked in. No matter what I try, I always get an error about undefined references to the function calls for that library. I'm pretty sure it's a linkage issue, because I can fuss with the C code and make an intentional error in the function calls to that library which produces earlier errors that indicate that the function prototypes have been loaded and used to compile. I tried adding the location that contains the .a file to LDFLAGS and then doing a AC_CHECK_LIB but it is not found. Maybe my syntax is wrong, or maybe I'm missing something more fundamental, which would not be surprising since I'm a newbie and don't really know what I'm doing. Here is what I have tried: AC_CHECK_HEADER([$location/helper.h], [AC_DEFINE([HAVE_HELPER_H], [1], [found helper.h]) CFLAGS="$CFLAGS -I$location"; LDFLAGS="$LDFLAGS -L$location"; AC_CHECK_LIB(helper)]) No dice. AC_CHECK_LIB is looking for -lhelper I guess (or libhelper?) so I'm not sure if that's a problem, so I tried this, too (omit AC_CHECK_LIB and include the .a directly in LDFLAGS), without luck: AC_CHECK_HEADER([$location/helper.h], [AC_DEFINE([HAVE_HELPER_H], [1], [found helper.h]) CFLAGS="$CFLAGS -I$location"; LDFLAGS="$LDFLAGS -L$location/helper.a"]) To emulate the manual compilation, I tried removing the -L but that doesn't help: AC_CHECK_HEADER([$location/helper.h], [AC_DEFINE([HAVE_HELPER_H], [1], [found helper.h]) CFLAGS="$CFLAGS -I$location"; LDFLAGS="$LDFLAGS $location/helper.a"]) I tried other combinations and permutations, but I think I might be missing something more fundamental....

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  • Permits in iPhone apps

    - by zp26
    HI, I want to create i file in the iPhone application. I try it but i have a anomaly. In my pc the file is correctly written. In other pc with the same program the file wasn't exist. In the iPhone device the file not exist. But the strange think thing is that i haven't any error for the app in the all case. Do you have a idea? Thanks so much

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  • Combining echo and cat on Unix

    - by Dan
    Really simple question, how do I combine echo and cat in the shell, I'm trying to write the contents of a file into another file with a prepended string? If /tmp/file looks like this: this is a test I want to run this: echo "PREPENDED STRING" cat /tmp/file | sed 's/test/test2/g' > /tmp/result so that /tmp/result looks like this: PREPENDED STRINGthis is a test2 Thanks.

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