Explicit constructor still has default values even though a default constructor is not invoked.
- by Phoenix
According to my understanding a default constructor initializes the state of the object to default values, so if i provide an explicit no-arg public constructor like this then how are the values of d and e still getting initialized to zero because in this case the default constructor is not invoked.
public class B extends A{
private int d;
private int e;
public B() {
System.out.println(d);
System.out.println(e);
}
}
EDIT:: The only thing default constructor does is call to super() then how come if i have a explicitly mentioned a constructor here and A has a protected variable say c which is initialized to 17 in its constructor. Should I not be explicitly calling super() to be able to see that change since I'm using my own constructor ? Why is B still getting the value of 17 through inheritance ?
