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  • iphone download several files

    - by Floo
    hi all !  In my app i need to download several plist.  to download a plist i use the NSURLconnection  in my code i use an UIAlertView with a UIActivityIndicator then when the download is finished i add a button to the alert to dismiss it.  To download the plist i use somewhere in my code an NSURL set to the adresse where the plist is, next i set a NSURLRequest with the url cache policy and a timeout interval.  Then i set my NSMutableData to the NSURL connection with a NSURLRequest.  In the delegate didReceiveData: i append data to my mutable data object, in the didFailWithError: i handle error. And finaly in the connectionDidFinishLoading  i serialize my data to a plist so i can write to file my plist, and release my alertview.  My problem is : how can i do if i have sevetal file to download because the connectionDidFinishLoading is called each time my NSURLConnection is finished but i want to release my UiAlert when everything is finished. But when the first plist is downloaded my code in the connectionDidFinishLoading will fire.  here is my code :  in the view did load :  // set the UiAlert in the view did load  NSURL *theUrl = [NSURL URLWithString:@"http://adress.com/plist/myPlist.plist"]; NSURLRequest *theRequest = [NSURLRequest requestWithURL:theUrl cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; self.plistConnection = [[ NSURLConnection alloc] initwithRequest:theRequest delegate:self startImmediatly:YES]; //plistConnection is a NSURLConnection - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {  [incomingPListData appendData:data]; } -(void)connection:(NSURLConnection *)connectionDidFailWithError:(NSError *)error { // handle error here  } -(void)connectionDidFinisloading:(NSURLConnection *) connection {  NSPropertyListFormat format; NSString *serialErrorString;  NSData *plist = [NSPropertyListSerialisation propertyListFromData:incomingPlistData mutabilityOption:NSPropertyListImmutable format:&format errorDescription:&serialErrorString]; if (serialErrorString) {//error} else { // create path and write plist to path} // change message and title of the alert so if i want todownload an another file  where do i put the request the connection and how can i tell the didFinishLoading to fire code when all my file are downloaded.  thanks to all

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  • Reuse Client java Socket in a Java Server

    - by user1394983
    I'm devoloping an Java server two control an android online game. It's possible save the client socket of myserversocket.accept() in a variable in Client class? This are very util because this way, server can communicate with client when server wants and no when client contact server. My actual code are: import java.io.IOException; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; import java.net.ServerSocket; import java.net.Socket; import java.util.ArrayList; import java.util.UUID; import sal.app.shared.Packet; public class Server { private ArrayList<GameSession> games = new ArrayList<GameSession>(); private ArrayList<Client> pendent_clients = new ArrayList<Client>(); private Packet read_packet= new Packet(); private Packet sent_packet = new Packet(); private Socket clientSocket = null; public static void main(String[] args) throws ClassNotFoundException{ ServerSocket serverSocket = null; //DataInputStream dataInputStream = null; //DataOutputStream dataOutputStream = null; ObjectOutputStream oos=null; ObjectInputStream ois=null; Server myServer = new Server(); try { serverSocket = new ServerSocket(7777); System.out.println("Listening :7777"); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } while(true){ try { myServer.clientSocket = new Socket(); myServer.clientSocket = serverSocket.accept(); myServer.read_packet = new Packet(); myServer.sent_packet = new Packet(); oos = new ObjectOutputStream(myServer.clientSocket.getOutputStream()); ois = new ObjectInputStream(myServer.clientSocket.getInputStream()); //dataInputStream = new DataInputStream(clientSocket.getInputStream()); //dataOutputStream = new DataOutputStream(clientSocket.getOutputStream()); //System.out.println("ip: " + clientSocket.getInetAddress()); //System.out.println("message: " + ois.read()); //dataOutputStream.writeUTF("Hello!"); /*while ((myServer.read_packet = (Packet) ois.readObject()) != null) { myServer.handlePacket(myServer.read_packet); break; }*/ myServer.read_packet=(Packet) ois.readObject(); myServer.handlePacket(myServer.read_packet); //oos.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } finally{ if( myServer.clientSocket!= null){ /*try { //myServer.clientSocket.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ } /*if( ois!= null){ try { ois.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } if( oos!= null){ try { oos.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } }*/ } } } public void handlePacket(Packet hp) throws IOException { if(hp.getOpCode() == 1) { registPlayer(hp); } } public void registPlayer(Packet p) throws IOException { Client registClient = new Client(this.clientSocket); this.pendent_clients.add(registClient); if(pendent_clients.size() == 2) { initAGame(); } else { ObjectOutputStream out=null; Packet to_send = new Packet(); to_send.setOpCode(4); out = new ObjectOutputStream(registClient.getClientSocket().getOutputStream()); out.writeObject(to_send); } } public void initAGame() throws IOException { Client c1 = pendent_clients.get(0); Client c2 = pendent_clients.get(1); Packet to_send = new Packet(); ObjectOutputStream out=null; GameSession incomingGame = new GameSession(c1,c2); games.add(incomingGame); to_send.setGameId(incomingGame.getGameId()); to_send.setOpCode(5); out = new ObjectOutputStream(c1.getClientSocket().getOutputStream()); out.writeObject(to_send); out = new ObjectOutputStream(c2.getClientSocket().getOutputStream()); out.writeObject(to_send); pendent_clients.clear(); } public Client getClientById(UUID given_id) { for(GameSession gs: games) { if(gs.getClient1().getClientId().equals(given_id)) { return gs.getClient1(); } else if(gs.getClient2().getClientId().equals(given_id)) { return gs.getClient2(); } } return null; } } With this code i got this erros: java.net.SocketException: Broken pipe at java.net.SocketOutputStream.socketWrite0(Native Method) at java.net.SocketOutputStream.socketWrite(SocketOutputStream.java:92) at java.net.SocketOutputStream.write(SocketOutputStream.java:136) at java.io.ObjectOutputStream$BlockDataOutputStream.drain(ObjectOutputStream.java:1847) at java.io.ObjectOutputStream$BlockDataOutputStream.setBlockDataMode(ObjectOutputStream.java:1756) at java.io.ObjectOutputStream.writeNonProxyDesc(ObjectOutputStream.java:1257) at java.io.ObjectOutputStream.writeClassDesc(ObjectOutputStream.java:1211) at java.io.ObjectOutputStream.writeOrdinaryObject(ObjectOutputStream.java:1395) at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1158) at java.io.ObjectOutputStream.writeFatalException(ObjectOutputStream.java:1547) at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:333) at Server.initAGame(Server.java:146) at Server.registPlayer(Server.java:120) at Server.handlePacket(Server.java:106) at Server.main(Server.java:63) This error ocurre when second client connect and server try to send an Packet to previous client 1 in function initGame() in this code: out = new ObjectOutputStream(c1.getClientSocket().getOutputStream()); out.writeObject(to_send); my android code is this: package sal.app; import java.io.DataInputStream; import java.io.DataOutputStream; import java.io.IOException; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; import java.net.Socket; import java.net.UnknownHostException; import sal.app.logic.DataBaseManager; import sal.app.shared.Packet; import android.app.Activity; import android.os.Bundle; import android.view.Window; import android.view.WindowManager; public class MultiPlayerWaitActivity extends Activity{ private DataBaseManager db; public void onCreate(Bundle savedInstanceState) { super.requestWindowFeature(Window.FEATURE_NO_TITLE); super.getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,WindowManager.LayoutParams.FLAG_FULLSCREEN); super.onCreate(savedInstanceState); setContentView(R.layout.multiwaitlayout); db=DataBaseManager.getSalDatabase(this); db.teste(); try { db.createDataBase(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } Socket socket = null; ObjectOutputStream outputStream = null; ObjectInputStream inputStream = null; //System.out.println("dadadad"); try { socket = new Socket("192.168.1.4", 7777); //Game = new MultiPlayerGame(new ServerManager("192.168.1.66"),new Session(), new Player("")); outputStream = new ObjectOutputStream(socket.getOutputStream()); inputStream = new ObjectInputStream(socket.getInputStream()); //dataOutputStream.writeUTF(textOut.getText().toString()); //textIn.setText(dataInputStream.readUTF()); Packet p = new Packet(); Packet r = new Packet(); p.setOpCode(1); outputStream.writeObject(p); /*try { r=(Packet)inputStream.readObject(); } catch (ClassNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ //while(true){ //dataInputStream = new DataInputStream(clientSocket.getInputStream()); //dataOutputStream = new DataOutputStream(clientSocket.getOutputStream()); //System.out.println("ip: " + clientSocket.getInetAddress()); //System.out.println("message: " + ois.read()); //dataOutputStream.writeUTF("Hello!"); /*while ((r= (Packet) inputStream.readObject()) != null) { handPacket(r); break; }*/ r=(Packet) inputStream.readObject(); handPacket(r); //oos.close(); //} /*System.out.println(r.getOpCode()); if(r.getOpCode() == 5) { this.finish(); }*/ } catch (UnknownHostException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /*finally{ if (socket != null){ try { socket.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } if (outputStream != null){ try { outputStream.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } if (inputStream != null){ try { inputStream.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }*/ //catch (ClassNotFoundException e) { // TODO Auto-generated catch block //e.printStackTrace(); //} catch (ClassNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } } public void handPacket(Packet hp) { if(hp.getOpCode() == 5) { this.finish(); } this.finish(); } } Regards

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  • Azure SDK causes Node.js service bus call to run slow

    - by PazoozaTest Pazman
    I am using this piece of code to call the service bus queue from my node.js server running locally using web matrix, I have also upload to windows azure "web sites" and it still performs slowly. var sb1 = azure.createServiceBusService(config.serviceBusNamespace, config.serviceBusAccessKey); sbMessage = { "Entity": { "SerialNumbersToCreate": '0', "SerialNumberSize": config.usageRates[3], "BlobName": 'snvideos' + channel.ChannelTableName, "TableName": 'snvideos' + channel.ChannelTableName } }; sb1.getQueue('serialnumbers', function(error, queue){ if (error === null){ sb1.sendQueueMessage('serialnumbers', JSON.stringify(sbMessage), function(error) { if (!error) res.send(req.query.callback + '({data: ' + JSON.stringify({ success: true, video: newVideo }) + '});'); else res.send(req.query.callback + '({data: ' + JSON.stringify({ success: false }) + '});'); }); } else res.send(req.query.callback + '({data: ' + JSON.stringify({ success: false }) + '});'); }); It can be up to 5 seconds before the server responds back to the client with the return result. When I comment out the sb1.getQueue('serialnumbers', function(error, queue){ and just have it return without sending a queue message it performs in less than 1 second. Why is that? Is my approach to using the azure sdk service bus correct? Any help would be appreciated.

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  • Producer/consumer system using database (MySql), is this feasible?

    - by johnrl
    Hi all. I need to use something to coordinate my system with several consumers/producers each running on different machines with different operating systems. I have been researching on using MySql to do this, but it seems ridiculously difficult. My requirements are simple: I want to be able to add or remove consumers/producers at any time and thus they should not depend on each other at all. Naturally a database would separate the two nicely. I have been looking at Q4M message queuing plugin for MySql but it seems complicated to use: I have to recompile it every time I upgrade MySql (can this really be true?) because when I try to install it on Ubuntu 9.10 with MySql 5.1.37 it says "Can't open shared library 'libqueue_engine.so' (errno: 0 API version for STORAGE ENGINE plugin is too different)". There is no precompiled version for MySql 5.1.37 apparently. Also what if I want to run MySql on my windows machine, then I can't rely on this plugin as it only seems to run on Linux and OSX?? I really need some input on how to construct my system best possible.

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  • What is default javac source mode (assert as identifier compilation)?

    - by waste
    According to Orcale's Java7 assert guide: source mode 1.3 (default) — the compiler accepts programs that use assert as an identifier, but issues warnings. In this mode, programs are not permitted to use the assert statement. source mode 1.4 — the compiler generates an error message if the program uses assert as an identifier. In this mode, programs are permitted to use the assert statement. I wrote such class: package mm; public class ClassTest { public static void main(String[] arg) { int assert = 1; System.out.println(assert); } } It should compile fine if Oracle's info right (1.3 is default source mode). But I got errors like this: $ javac -version javac 1.7.0_04 $ javac -d bin src/mm/* src\mm\ClassTest.java:5: error: as of release 1.4, 'assert' is a keyword, and may not be used as an identifier int assert = 1; ^ (use -source 1.3 or lower to use 'assert' as an identifier) src\mm\ClassTest.java:6: error: as of release 1.4, 'assert' is a keyword, and may not be used as an identifier System.out.println(assert); ^ (use -source 1.3 or lower to use 'assert' as an identifier) 2 errors I added manually -source 1.3 and it issued warnings but compiled fine. It seems that Oracle's information is wrong and 1.3 is not default source mode. Which one is it then?

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  • Rails 2.3.2 trying to render ERB instead of HAML

    - by c00lryguy
    Rails is suddenly trying to render ERB instead of Haml and I can't figure out why. I've created new rails projects, reinstalled Haml, and reinstalled Rails. Here's exactly the steps I take when making my application (Rails 2.3.2): rails> rails test rails> cd test rails\test> haml --rails . rails\test> ruby script\generate model user email:string password:string rails\test> ruby script\generate controller users index rails\test> rake db:migrate Here's what the UsersController looks like: class UsersController < ApplicationController def index @users = User.all end end My routes: ActionController::Routing::Routes.draw do |map| map.resources :users end I now create views\users\index.html.haml: %table %th(style="text-align: left;") %h1 Users - for user in @users %tr %td= user.email %td= user.password Annnd run the server... I navigate to localhost:3000\users and I get this error message: Template is missing Missing template users/index.erb in view path app/views For some reason Rails is trying to find and render .erb files instead of .haml files. vendor\plugins\haml\init.rb exists, untouched. I've reinstalled Haml (Pretty Penny) multiple times and still get the same results. I've also tried adding config.gem 'haml' to my environment.rb but this also doesn't work. I can't figure out why suddenly rails will not render haml for me.

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  • Bind Command to MenuItem

    - by Neir0
    Hi I have ListView and i am trying to bind command to ContextMenu of ListView. <ListView x:Name="listView1" ItemsSource="{Binding Path=Persons}"> <ListView.Resources> <ContextMenu x:Key="ItemContextMenu"> <MenuItem Header="Add" /> <MenuItem Header="Edit"/> <Separator/> <MenuItem Header="Delete" Command="{Binding Msg}" /> </ContextMenu> </ListView.Resources> <ListView.ItemContainerStyle> <Style TargetType="ListViewItem"> <!--<EventSetter Event="PreviewMouseLeftButtonDown" />--><!--Handler="OnListViewItem_PreviewMouseLeftButtonDown" />--> <Setter Property="ContextMenu" Value="{StaticResource ItemContextMenu}"/> <Setter Property="HorizontalContentAlignment" Value="Stretch" /> </Style> </ListView.ItemContainerStyle> <ListView.View> <GridView> <GridViewColumn Header="Name" DisplayMemberBinding="{Binding Path=Name}" /> <GridViewColumn Header="Sur Name" DisplayMemberBinding="{Binding Path=SurName}" /> <GridViewColumn Header="Age" DisplayMemberBinding="{Binding Path=Age}" /> </GridView> </ListView.View> </ListView> <Button Content="Message" Command="{Binding Msg}" /> Binding to Button works well but when i click to delete item in ContextMenu, command is not working! Why?

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  • Problem calling web service from within JBOSS EJB Service

    - by Rob Goodwin
    I have a simple web service sitting on our internal network. I used SOAPUI to do a bit of testing, generated the service classes from the WSDL , and wrote some java code to access the service. All went as expected as I was able to create the service proxy classes and make calls. Pretty simple stuff. The only speed bump was getting java to trust the certificate from the machine providing the web service. That was not a technical problem, but rather my lack of experience with SSL based web services. Now onto my problem. I coded up a simple EJB service and deployed it into JBoss Application Server 4.3 and now get the following error in the code that previously worked. 12:21:50,235 WARN [ServiceDelegateImpl] Cannot access wsdlURL: https://WS-Test/TestService/v2/TestService?wsdl I can access the wsdl file from a web browser running on the same machine as the application server using the URL in the error message. I am at a loss as to where to go from here. I turned on the debug logs in JBOSS and got nothing more than what I showed above. I have done some searching on the net and found the same error in some questions, but those questions had no answers. The web services classes where generated with JAX-WS 2.2 using the wsimport ant task and placed in a jar that is included in the ejb package. JBoss is deployed in RHEL 5.4, where the standalone testing was done on Windows XP.

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  • Use of unassigned local variable 'dictionary'

    - by codemonkie
    I got the error Use of unassigned local variable 'dictionary' despite I assigned the value in the following code: private static void UpdateJadProperties(Uri jadUri, Uri jarUri, Uri notifierUri) { Dictionary<String, String> dictionary; try { String[] jadFileContent; // Create an instance of StreamReader to read from a file. // The using statement also closes the StreamReader. using (StreamReader sr = new StreamReader(jadUri.AbsolutePath.ToString())) { Char[] delimiters = { '\r', '\n' }; jadFileContent = sr.ReadToEnd().Split(delimiters, System.StringSplitOptions.RemoveEmptyEntries); } // @@NOTE: Keys contain ": " suffix, values don't! dictionary = jadFileContent.ToDictionary(x => x.Substring(0, x.IndexOf(':') + 2), x => x.Substring(x.IndexOf(':') + 2)); } catch (Exception e) { // Let the user know what went wrong. Console.WriteLine("The file could not be read:"); Console.WriteLine(e.Message); } try { if (dictionary.ContainsKey("MIDlet-Jar-URL: ")) { // Change the value by Remove follow by Add } } catch (ArgumentNullException ane) { throw; } } The error is from the line: if (dictionary.ContainsKey("MIDlet-Jar-URL: ")) Can any one help me out here, pls? TIA

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  • Encrypt a hex string in java.

    - by twintwins
    I would like to ask for any suggestions about my problem. I need to encrypt a hexadecimal string. I must not to use the built-in functions of java because it doesn't work in my server. In short, I have to hard code an algorithm or any means of encrypting the message. Anyone who could help me with this? thanks a lot! here is the code. public Encrypt(SecretKey key, String algorithm) { try { ecipher = Cipher.getInstance(algorithm); dcipher = Cipher.getInstance(algorithm); ecipher.init(Cipher.ENCRYPT_MODE, key); dcipher.init(Cipher.DECRYPT_MODE, key); } catch (NoSuchPaddingException e) { System.out.println("EXCEPTION: NoSuchPaddingException"); } catch (NoSuchAlgorithmException e) { System.out.println("EXCEPTION: NoSuchAlgorithmException"); } catch (InvalidKeyException e) { System.out.println("EXCEPTION: InvalidKeyException"); } } public void useSecretKey(String secretString) { try { SecretKey desKey = KeyGenerator.getInstance("DES").generateKey(); SecretKey blowfishKey = KeyGenerator.getInstance("Blowfish").generateKey(); SecretKey desedeKey = KeyGenerator.getInstance("DESede").generateKey(); Encrypt desEncrypter = new Encrypt(desKey, desKey.getAlgorithm()); Encrypt blowfishEncrypter = new Encrypt(blowfishKey, blowfishKey.getAlgorithm()); Encrypt desedeEncrypter = new Encrypt(desedeKey, desedeKey.getAlgorithm()); desEncrypted = desEncrypter.encrypt(secretString); blowfishEncrypted = blowfishEncrypter.encrypt(secretString); desedeEncrypted = desedeEncrypter.encrypt(secretString); } catch (NoSuchAlgorithmException e) {} } those are the methods i used. no problem if it is run as an application but then when i put it to my server which is the glassfish server an exception occured and it says no such algorithm.

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  • Social Network News Feed Database & Design

    - by pws5068
    I'm designing a News Feed system using PHP/MySQL similar to facebook's. I have asked a similar question before but now I've changed the design and I'm looking for feedback. Example Notifications: User_A commented on User_B's new album. "Hey man nice picture!" User_B added a new Photo to [his/her] profile. [show photo thumbnail] Initially, I implemented this using excessive columns for Obj1:Type1 | Obj2:Type2 | etc.. Now the design is set up using a couple special keywords, and actor/receiver relationships. My database is designed for efficiency - using a table of messages joined on a table containing userid,actionid,receiverid,receiverObjectTypeID, Here's a condensed version of what it will look like once joined: News_ID | User_ID | Message | Timestamp 2643 A %a commented on %o's new %r. SomeTimestamp 2644 B %a added a new %r to [his/her] profile. SomeTimestamp %a = the User_ID of the person doing the action %r = the receiving object %o = the owner of the receiving object (for example the owner of the album) (NULL if %r is a user) Questions: Is this a smart (efficient/scalable) way to move forward? How can I show messages like: "User_B added 4 new photos to his profile."?

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  • JQuery Post-Request question - FF doesn't get the result of the referenced php page

    - by OlliD
    Dear community, I just want to have my question posted here but just from the beginning: For a personal web project I use PHP + JQuery. Now I got stuck when I try to use the ajax posting method to send data to another php-page. I planned to have some navigational elements like next + previous on the bottom of the page by saving the user input / user given data. The code looks as follows: <div id="bottom_nav"> <div id="prev" class="flt_l"><a href="?&step=<?= $pages[$step-1] ?>">next</a></div> <div id="next" class="flt_r"><a href="?&step=<?= $pages[$step+1] ?>">previous</a></div> </div> The functionality of the page works fine. Lateron, I use the following code to sent data over via POST: $("#bottom_nav a").click( function() { alert("POST-Link: Parameter=" + $("#Parameter").val()); $.ajax( { type:"post", url:"saveParameter.php", data:"Parameter=" + $("#Parameter").val(), success: function(result) { alert(result); //$("#test").text(result); } }); }); The request itself work perfectly on IE, but on FF I'm not able to get back any result. within the PHP page, there just written: <? echo $_POST['Parameter']; ?> As IE returns the correct value, FF just provide an empty message box. I assumed that the behaviour on the -Link is different. While IE seems to handle the click event after the JS-Code execution, FF will interpret it before. My question was whether you has a solution on this regarding restructuring the code itself or using another method to reach the intened behaviour. Thanks for your assistance and recommendations, Olli

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  • Jquery ajaxStart doesnt get triggered

    - by gnomixa
    This code $("#loading").ajaxStart(function() { alert("start"); $(this).show(); }); in my mark-up <div style="text-align:center;"><img id="loading" src="../images/common/loading.gif" alt="" /></div> Here is the full ajax request: $.ajax({ type: "POST", url: "http://localhost/WebServices/Service.asmx/GetResults", data: jsonText, contentType: "application/json; charset=utf-8", dataType: "json", success: function(response) { var results = (typeof response.d) == 'string' ? eval('(' + response.d + ')') : response.d; PopulateTree(results); }, error: function(xhr, status, error) { var msg = JSON.parse(xhr.responseText); alert(msg.Message); } }); $("#loading").ajaxStart(function() { alert("start"); $(this).show(); }); $("#loading").ajaxStop(function() { alert("stop"); $(this).hide(); $("#st-tree-container").show(); }); never fires alert "start" even though the gif is shown to rotate. AjaxStop gets triggered as expected. Any ideas why?

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  • Ordered delivery with NetNamedPipeBinding using oneWay calls

    - by Aseem Bansal
    Is it possible to guarantee ordered delivery with oneWay calls using namedPipe binding? I have a WCF service/client communicating using namedPipe binding. The client is exposing a callback contract in which all the methods in the callback are marked as OneWay. Something like this [ServiceContract(CallbackContract = typeof(IMyServiceCallback))] public interface IMyService { [OperationContract] void MyOperation(); } public interface IMyServiceCallback { [OperationContract(IsOneWay=true)] void MyCallback1(); [OperationContract(IsOneWay=true)] void MyCallback2(); } At the server side, the implementation of MyOperation method always calls MyCallback1 first and then MyCallback2 but I am observing that sometimes the client receives the calls in the incorrect order (MyCallback2 first and then MyCallback1). On searching the internet I found that the order is not guaranteed with oneway operation as mentioned here and also there is something called reliableSession which ensure message ordering. All the examples on the internet for reliable session are with TCP binding (and not a single one with NamedPipeBinding) and the tcpBinding also has a property called ReliableSession which is not present on the NetNamedPipeBinding. So I am not sure whether reliable session is expected to work with NetNamedPipeBinding or not. Question: Does reliable session work with namedPipeBinding? If yes, how? If no, Is there any other approach with which I can guarantee ordered delivery?

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  • SQL Server Blocking Issue

    - by Robin Weston
    We currently have an issue that occurs roughly once a day on SQL 2005 database server, although the time it happens is not consistent. Basically, the database grinds to a halt, and starts refusing connections with the following error message. This includes logging into SSMS: A connection was successfully established with the server, but then an error occurred during the login process. (provider: TCP Provider, error: 0 - The specified network name is no longer available.) Our CPU usage for SQL is usually around 15%, but when the DB is in it's broken state it's around 70%, so it's clearly doing something, even if no-one can connect. Even if I disable the web app that uses the database the CPU still doesn't go down. I am unable to restart the SQLSERVER process as it is unresponsive, so I have to end up killing the process manually, which then puts the DB into Suspect/Recovery mode (which I can fix but it's a pain). Below are some PerfMon stats I gathered when the DB was in it's broken state which might help. I have a bunch more if people want to request them: Active Transactions: 2 (Never Changes) Logical Connections: 34 (NC) Process Blocked: 16 (NC) User Connections: 30 (NC) Batch Request: 0 (NC) Active Jobs: 2 (NC) Log Truncations: 596 (NC) Log Shrinks: 24 (NC) Longest Running Transaction Time: 99 (NC) I guess they key is finding out what the DB is using it's CPU on, but as I can't even log into SSMS this isn't possible with the standard methods. Disturbingly, I can't even use the dedicated admin connection to get into SSMS. I get the same timout as with all other requests. Any advice, reccomendations, or even sympathy, is much appreciated!

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  • Using multiple named outlets and a wrapper view with no content in Emberjs

    - by user1889776
    I'm trying to use multiple named outlets with Ember.js. Is my approach below correct? Markup: <script type="text/x-handlebars" data-template-name="application"> <div id="mainArea"> {{outlet main_area}} </div> </script> <script type="text/x-handlebars" data-template-name="home"> <ul id="sections"> {{outlet sections}} </ul> <ul id="categories"> {{outlet categories}} </ul> </script> <script type="text/x-handlebars" data-template-name="sections"> {{#each section in controller}} <li><img {{bindAttr src="section.image"}}></li> {{/each}} </script> <script type="text/x-handlebars" data-template-name="categories"> {{#each category in controller}} <img {{bindAttr src="category.image"}}> {{/each}} </script>? JS Code: Here I set the content of the various controllers to data grabbed from a server and connect outlets with their corresponding views. Since the HomeController has no content, set its content to an empty object - a hack to get the rid of this error message: Uncaught Error: assertion failed: Cannot delegate set('categories' ) to the 'content' property of object proxy : its 'content' is undefined. App.Router = Ember.Router.extend({ enableLogging: false, root: Ember.Route.extend({ index: Ember.Route.extend({ route: '/', connectOutlets: function(router){ router.get('sectionsController').set('content',App.Section.find()); router.get('categoriesController').set('content', App.Category.find()); router.get('applicationController').connectOutlet('main_area', 'home'); router.get('homeController').connectOutlet('home', {}); router.get('homeController').connectOutlet('categories', 'categories'); router.get('homeController').connectOutlet('sections', 'sections'); } }) }) });

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  • Authentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "123456" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • FaceBook UIAlertView problem

    - by william-hu
    My iPhone application connects to facebook . After i log in ,then appear one button named "Add feed to your wall". If i click it , pop a UIAlertView which ask "Yes" or "no". If "Yes", show the FBStreamDialog. But the BFStreamDialog just flash, then disappear. I don't know why. this is my code. First , click the button " Add feed to your wall". call changeFeed: function. -(IBAction) changeFeed { UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Sporting Summer Festival Monte-Carlo" message:@"Are you attending this concert?" delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes",nil]; [alert show]; alert.tag = 1; self.alertView =alert; [alert release]; } Then, if you choose "YES" button. Call this function: - (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex { if (buttonIndex == 0) { NSLog(@"NO"); } else { NSLog(@"YES"); [self showAddFeed]; } } And this is the showAddFeed function , which is defined in front of "clickButtonAtIndex". -(void)showAddFeed { FBStreamDialog dialog = [[[FBStreamDialog alloc] init] autorelease]; dialog.delegate= self; dialog.userMessagePrompt = @""; [dialog show]; } Just cant work well. I don't know why? Thank you for your help.

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  • InvalidArgument=Value of '3' is not valid for 'rowIndex'

    - by Devendra Dwivedi
    Hi all This is my code It is working for if 1 terminal that is having 3 services but it is not working for more than 3 services when I do then I have got following error message: InvalidArgument=Value of '3' is not valid for 'rowIndex' I have so tired to find this problem but couldn't get any solutions. Anybody please help me. MySqlCommand command = new MySqlCommand("VTerminalsLoad");//Procedure MySqlDataAdapter terminalAdapter = this.Database.ExecuteCommand(command); terminalAdapter.Fill(dataSet, "Terminals"); command = new MySqlCommand("VTServicesLoad");//Procedure command.Parameters.Add(new MySqlParameter("pVesselID", 1)); MySqlDataAdapter serviceAdapter = this.Database.ExecuteCommand(command);//Return Adaptor serviceAdapter.Fill(dataSet, "Services"); DataColumn[] parentColumns = { dataSet.Tables[0].Columns["SerialNo"], dataSet.Tables[0].Columns["VesselID"], dataSet.Tables[0].Columns["TerminalID"] }; DataColumn[] childColumns = { dataSet.Tables[1].Columns["SerialNo"], dataSet.Tables[1].Columns["VesselID"], dataSet.Tables[1].Columns["TerminalID"] }; DataRelation relationTS = new DataRelation("TerminalsServices", parentColumns, childColumns); dataSet.Relations.Add(relationTS); //Parent Table ListTerminal.DataSource = dataSet; //ListTerminal Parent datagridview ListTerminal.DataMember = "Terminals"; //Child Table ListServices.DataSource = dataSet;// ListServices Child datagridview ListServices.DataMember = "Terminals.TerminalsServices";

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  • Ideas for a rudimentary software licensing implementation

    - by Ross
    I'm trying to decide how to implement a very basic licensing solution for some software I wrote. The software will run on my (hypothetical) clients' machines, with the idea being that the software will immediately quit (with a friendly message) if the client is running it on greater-than-n machines (n being the number of licenses they have purchased). Additionally, the clients are non-tech-savvy to the point where "basic" is good enough. Here is my current design, but given that I have little to no experience in the topic, I wanted to ask SO before I started any development on it: A remote server hosts a MySQL database with a table containing two columns: client-key and license quantity The client-side application connects to the MySQL database on startup, offering it's client-key that I've put into a properties file packaged into the distribution (I would create a new distribution for each new client) Chances are, I'll need a second table to store validation history, so that with some short logic, the software can decide if it can be run on a given machine (maybe a sliding window of n machines using the software per 24 hours) If the software cannot establish a connection to the MySQL database, or decides that it's over the n allowed machines per day, it closes The connection info for the remote server hosting the MySQL database should be hard-coded into the app? (That sounds like a bad idea, but otherwise they could point it to some other always-validates-to-success server) I think that about covers my initial design. The intent being that while it certainly isn't full-proof, I think I've made it at least somewhat difficult to create an easily-sharable cracking solution. Also, I can easily adjust the license amount for a given client/key pair. I gotta figure this has been done a million times before, so tell me about a better solution that's just as simple to implement and provides the same (low) amount of security. In the event that external libraries are used, I prefer Java, as that's what the software has been written in.

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  • Requested Service not found - .NET Remoting

    - by bharat
    I am Getting this exception System.Runtime.Remoting.RemotingException occurred Message="Object '/55337266_9751_4f58_8446_c54ff254222e/rkutlpt5hvsxipmzhb+jkqyl_98.rem' has been disconnected or does not exist at the server." Source="mscorlib" StackTrace: Server stack trace: at System.Runtime.Remoting.Channels.ChannelServices.CheckDisconnectedOrCreateWellKnownObject(IMessage msg) at System.Runtime.Remoting.Channels.ChannelServices.DispatchMessage(IServerChannelSinkStack sinkStack, IMessage msg, IMessage& replyMsg) Exception rethrown at [0]: at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg) at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type) at Common.Interface.Repository.NA.INRR.GetNRun(Int32 NetworkRunId) at Module.NA.ViewModel.NRDViewModel.get_AS() InnerException: Most of the times i am getting this exception this is my remotingDomain method string tcpURL; TcpChannel channel; channel = new TcpChannel(); ChannelServices.RegisterChannel(channel, false); //-- // Remote domain objects //-- tcpURL = string.Format("tcp://{0}:{1}/DomainComposition", ServerName, TcpPort); RemotingConfiguration.RegisterWellKnownClientType(typeof(DomainComposition), tcpURL); //-- // Remote repository objects //-- tcpURL = string.Format("tcp://{0}:{1}/RepositoryComposition", ServerName, TcpPort); RemotingConfiguration.RegisterWellKnownClientType(typeof(RepositoryComposition), tcpURL); //-- // Remote utility objects //-- tcpURL = string.Format("tcp://{0}:{1}/UtilityComposition", ServerName, TcpPort); RemotingConfiguration.RegisterWellKnownClientType(typeof(UtilityComposition), tcpURL); this.Domain = new DomainComposition(); this.Repository = new RepositoryComposition(); this.Utility = new UtilityComposition(); How to Check if the object is disconnect then re initiate the service

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  • Disable Painting of the VScrollbar in a System.Windows.Forms.RichTextBox

    - by SchlaWiener
    I have a custom control inherited from RichTextBox. This control has the ability to "disable" rich text editing. I achive this by just setting the Rtf property to the text property during the TextChanged event. this is how my code looks like: private bool lockTextChanged; void RichTextBox_TextChanged(object sender, EventArgs e) { // prevent StackOverflowException if (lockTextChanged) return; // remember current position int rtbstart = rtb.SelectionStart; int len = rtb.SelectionLength; // prevent painting rtb.SuspendLayout(); // set the text property to remove the entire formatting. lockTextChanged = true; rtb.Text = rtb.Text; rtb.Select(rtbstart, len); lockTextChanged = false; rtb.ResumeLayout(true); } That worked well. However in a large text with like 200 lines the controls jitters (you see the first lines of text for the wink). To prevent that from happening I filter the WM_PAINT between SuspendLayout() and ResumeLayout() private bool layoutSuspended; public new void SuspendLayout() { layoutSuspended = true; base.SuspendLayout(); } public new void ResumeLayout() { layoutSuspended = false; base.ResumeLayout(); } public new void ResumeLayout(bool performLayout) { layoutSuspended = false; base.ResumeLayout(performLayout); } private const int WM_PAINT = 0x000F; protected override void WndProc(ref System.Windows.Forms.Message m) { if (!(m.Msg == WM_PAINT && layoutSuspended)) base.WndProc(ref m); } that did the trick, the RichTextBox isn't jittering anymoe. That's what I wanted to achive, except one thing: The scrollbar is still jittering everytime I type text to my control. Now my question: Does anyone have a clue for me how to prevent the scrollbar from redrawing during Suspend/Resume Layout?

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  • Supressing GUI?

    - by Legend
    I am trying to run a plugin designed for Vuze using Java. For this I am using a command like this: /home/x/jre1.6.0_14/bin/java -Dazureus.config.path=/home/x/plugin_directory -Dfile.encoding=ANSI_X3.4-1968 -classpath /home/x/P/lib/swtgraphics2d.jar:/home/x/P/lib/Azureus2.jar:/home/x/P/lib/swt.jar org.gudy.azureus2.ui.swt.Main The problem with this is that the launch is failing with an error: changeLocale: *Default Language* != English (United States). Searching without country.. changeLocale: Searching for language English in *any* country.. changeLocale: no message properties for Locale 'English (United States)' (en_US), using 'English (default)' Invoking main failed java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at com.aelitis.azureus.launcher.MainExecutor$1.run(MainExecutor.java:37) at java.lang.Thread.run(Unknown Source) Caused by: org.eclipse.swt.SWTError: No more handles [gtk_init_check() failed] at org.eclipse.swt.SWT.error(SWT.java:3910) at org.eclipse.swt.widgets.Display.createDisplay(Display.java:863) at org.eclipse.swt.widgets.Display.create(Display.java:851) at org.eclipse.swt.graphics.Device.<init>(Device.java:152) at org.eclipse.swt.widgets.Display.<init>(Display.java:479) at org.eclipse.swt.widgets.Display.<init>(Display.java:470) at org.gudy.azureus2.ui.swt.mainwindow.SWTThread.<init>(SWTThread.java:84) at org.gudy.azureus2.ui.swt.mainwindow.SWTThread.createInstance(SWTThread.java:59) at org.gudy.azureus2.ui.swt.mainwindow.Initializer.<init>(Initializer.java:110) at org.gudy.azureus2.ui.swt.Main.<init>(Main.java:88) at org.gudy.azureus2.ui.swt.Main.main(Main.java:255) ... 6 more Exception in thread "MainRunner" java.lang.SecurityException: VM exit operation prohibited at org.gudy.azureus2.core3.security.impl.SESecurityManagerImpl$2.checkExit(SESecurityManagerImpl.java:274) at java.lang.Runtime.exit(Unknown Source) at java.lang.System.exit(Unknown Source) at com.aelitis.azureus.launcher.MainExecutor$1.run(MainExecutor.java:42) at java.lang.Thread.run(Unknown Source) I am sure that this is happening because I am running the program on a terminal. Is there a way to supress the GUI or let the program think that the GUI was spawned successfully? Any suggestions?

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  • Connecting to SFTP service via Java Runtime process

    - by ohseekay
    Under my project, I have a Java class file, inside of which I have a routine which executes the following external SFTP script file: #!/bin/sh echo "cd AV/OASIS" >> sftp echo "put $1 $2" >> sftp echo "get AV/OASIS/$2 $3$2" >> sftp echo "bye" >> sftp /usr/local/bin/sftp -b sftp id@domain cat /dev/null > sftp exit 0 The Java code which executes the script file is as below: String script = "full path of script"; Process p = Runtime.getRuntime().exec(script + " " + param1 + " " + param2 + " " + param3); However, I'm not sure why, but the log generated by the class file always shows the error "Host key verification failed. Connection closed." I'd isolated that line in the script which connected to the remote machine, and ran it on the local machine (where this class file and script file are stored), and the command executed successfully I'd manually run the command which the Java class file will execute and it also tested okay: $ script.sh param1 param2 param3 I'd tried to look up the error message on the Internet, and apparently it seems to have something to do with known_hosts. Could this be the reason, or is there something else I'm missing? Thanks so much!

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  • Web-based game in Python + Django and client browser polling

    - by ty
    I am creating a text-based game that implements a basic model in which multiple (10+) players interact with data and one moderator watches them and sets certain environmental statistics that affect gameplay. Recently I have begun to familiarize myself with Django. It seems to me that it would be an excellent tool for creating a game quickly, particularly because the nature of my game depends largely on sets of data (which lends itself quite well to a database). I am wondering how to "push" changes made by the game moderator to the players (for example, the moderator can decide to display an image to all players). The game is turn-based, not real-time, but certain messages need to be pushed out in roughly real-time. My thoughts: I could have each player's browser poll a status periodically (say, every 30 seconds) to see if there is a message from a moderator. But this forces a lag and means different players might receive it at different times. And reducing this interval to <10 seems like a bad idea for the server. Is there a better way to inform clients of changes? Would you suggest something other than using a web framework like Django? Thanks!

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