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  • MySQL Query order by numer of rows?

    - by Clemens
    hi, i have a mysql table for votes. there's am id, a project_id and a vote field (which is 1 if a specific project is voted). now i want to generate a ranking from those entries. is there a way to get the number of votes for each project_id and automatically sort the entries by the number of TRUE votes of a project with a single mysql query? Or do you know a php way? e.g. ID - Project ID - Vote 1 - 2 - 1 2 - 2 - 1 3 - 1 - 1 == Project Nr. 2 has 2 Votes Project Nr. 1 has 1 Vote Thanks in advance!

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  • Windows desktop virutalization instead of replacing work stations

    - by Chris Marisic
    I'm head of the IT department at the small business I work for, however I am primarily a software architect and all of my system administration experience and knowledge is ancillary to software development. At some point this year or next we will be looking at upgrading our workstation environment to a uniform Windows 7 / Office 2010 environment as opposed to the hodge podge collection of various OEM licensed editions of software that are on each different machine. It occurred to me that it is probably possible to forgo upgrading each workstation and instead have it be a dumb terminal to access a virutalization server and have their entire virtual workstation hosted on the server. Now I know basically anything is possible but is this a feasible solution for a small business (25-50 work stations)? Assuming that this is feasible, what type of rough guidelines exist for calculating the required server resources needed for this. How exactly do solutions handle a user accessing their VM, do they log on normally to their physical workstation and then use remote desktop to access their VM, or is it usually done with a client piece of software to negotiate this? What types of software available for administering and monitoring these VM's, can this functionality be achieved out of box with Microsoft Server 2008? I'm mostly interested in these questions relating to Server 2008 with Hyper-V but fell free to offer insight with VMware's product line up, especially if there's any compelling reasons to choose them over Hyper-V in a Microsoft shop. Edit: Just to add some more information on implementation goals would be to upgrade our platform from a Win2k3 / XP environment to a full Windows 2008 / Win7 platform without having to perform any of that associated work with our each differently configured workstation. Also could anyone offer any realistic guidelines for how big of hardware is needed to support 25-50 workstations virtually? The majority the workstations do nothing except Office, Outlook and web. The only high demand workstations are the development workstations which would keep everything local.

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  • symfony 1.4 sformextra autocomplete sort order

    - by jdog
    I'm using the jquery autocomplete plugin that comes with the symfony sfFormExtra plugin. /* * jQuery Autocomplete plugin 1.1 * * Copyright (c) 2009 Jörn Zaefferer * * Dual licensed under the MIT and GPL licenses: * http://www.opensource.org/licenses/mit-license.php * http://www.gnu.org/licenses/gpl.html * * Revision: $Id: jquery.autocomplete.js 15 2009-08-22 10:30:27Z joern.zaefferer $ */ It does seem to sort json results according to the key, but I can't find any mention of sort options in the code. I would like the results sorted like returned from the server. How can I achieve this?

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  • How to order actions in menus in Eclipse RCP

    - by Marcos Scriven
    If I add action within an extension point thus: <action class="com.mycompany.MyAction" id="mycompany.myaction.MyAction" menubarPath="actions" /> How can I control its ordering programatically? It looks like they are simply ordered alphabetically according to their ID. I don't want to have to give them names such as '001-z', '002-a', just to get 'z' to appear before 'a'. It would also be a nightmare re-ordering them later.

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  • Fetch a specific tag from Rally in order to compute a value in another field

    - by 4jas
    I'm extremely new to Rally development so my question may sound dumb (but couldn't find how to do it from rally's help or from previous posts here) :) I've started from the rally freeform grid example - my purpose is to implement a Business Value calculator: I fill the score field with a 5-digit figure where each number is a score in the 1-5 range. Then I compute a business value as the result of a calculation, where each number is weighted by a preset weight. I can sort my stories by Business Value to help me prioritize my backlog: that's the first step, and it works. Now what I want to do is to make my freeform grid editable: I am extracting each of my digits as a separate column, but those columns are display-only. How can I turn them into something editable? What I want to do of course is update back the score field based on the values input in each custom column. Here's an example: I have a record with score "15254", which means Business Value criteria 1 scores 1 out of 5, Business Value criteria 2 scores 5 out of 5, and so on... In the end my Business Value is computed as "1*1 + 5*2 + 2*3 + 5*4 + 4*5 = 57". So far this is the part that works. Now let's say I found that the third criteria should not score 2 but 3, I want to be able to edit the value in the corresponding column and have my score field updated to "15354", and my Business Value to display 60 instead of 57. Here is my current code, I'll be really grateful if you can help me with turning that grid into something editable :) <!--Include SDK--> <script type="text/javascript" src="https://rally1.rallydev.com/apps/2.0p2/sdk-debug.js"></script> <!--App code--> <script type="text/javascript"> Rally.onReady(function() { Ext.define('BVApp', { extend: 'Rally.app.App', componentCls: 'app', launch: function() { Ext.create('Rally.data.WsapiDataStore', { model: 'UserStory', autoLoad: true, listeners: { load: this._onDataLoaded, scope: this } }); }, _onDataLoaded: function(store, data) { var records = []; var li_score; var li_bv1, li_bv2, li_bv3, li_bv4, li_bv5, li_bvtotal; var weights = new Array(1, 2, 3, 4, 5); Ext.Array.each(data, function(record) { //Let's fetch score and compute the business values... li_score = record.get('Score'); if (li_score) { li_bv1 = li_score.toString().substring(0,1); li_bv2 = li_score.toString().substring(1,2); li_bv3 = li_score.toString().substring(2,3); li_bv4 = li_score.toString().substring(3,4); li_bv5 = li_score.toString().substring(4,5); li_bvtotal = li_bv1*weights[0] + li_bv2*weights[1] + li_bv3*weights[2] + li_bv4*weights[3] + li_bv5*weights[4]; } records.push({ FormattedID: record.get('FormattedID'), ref: record.get('_ref'), Name: record.get('Name'), Score: record.get('Score'), Bv1: li_bv1, Bv2: li_bv2, Bv3: li_bv3, Bv4: li_bv4, Bv5: li_bv5, BvTotal: li_bvtotal }); }); this.add({ xtype: 'rallygrid', store: Ext.create('Rally.data.custom.Store', { data: records, pageSize: 5 }), columnCfgs: [ { text: 'FormattedID', dataIndex: 'FormattedID' }, { text: 'ref', dataIndex: 'ref' }, { text: 'Name', dataIndex: 'Name', flex: 1 }, { text: 'Score', dataIndex: 'Score' }, { text: 'BusVal 1', dataIndex: 'Bv1' }, { text: 'BusVal 2', dataIndex: 'Bv2' }, { text: 'BusVal 3', dataIndex: 'Bv3' }, { text: 'BusVal 4', dataIndex: 'Bv4' }, { text: 'BusVal 5', dataIndex: 'Bv5' }, { text: 'BusVal Total', dataIndex: 'BvTotal' } ] }); } }); Rally.launchApp('BVApp', { name: 'Business Values App' }); var exampleHtml = '<div id="example-intro"><h1>Business Values App</h1>' + '<div>Own sample app for Business Values</div>' + '</div>'; // Default app viewport uses layout: 'fit', // so we need to insert a container into the viewport var viewport = Ext.ComponentQuery.query('viewport')[0]; var appComponent = viewport.items.getAt(0); var viewportContainerItems = [{ html: exampleHtml, border: 0 }]; //hide advanced cardboard live previews in examples for now viewportContainerItems.push({ xtype: 'container', items: [appComponent] }); viewport.remove(appComponent, false); viewport.add({ xtype: 'container', layout: 'vbox', items: viewportContainerItems }); }); </script> <!--App styles--> <style type="text/css"> .app { /* Add app styles here */ } </style>

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  • Bash and sort files in order

    - by Werner
    Hi, with a previous bash script I created a list of files: data_1_box data_2_box ... data_10_box ... data_99_box the thing is that now I need to concatenate them, so I tried ls -l data_* but I get ..... data_89_box data_8_box data_90_box ... data_99_box data_9_box but I need to get in the sucession 1, 2, 3, 4, .. 9, ..., 89, 90, 91, ..., 99 Can it be done in bash?

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  • Webpage layout order for my webapp - does it matter if the Sidebar is programmatically displayed bef

    - by Jack W-H
    OK that's the worst title I could ever possibly think up. But I'm not too sure how to phrase it! What I mean is, is it inefficient for the browser, search engine optimisation, or any other important factors, if programmatically my float:righted sidebar appears in the markup before the main content div, which is set to float:left? To the user, the main content appears on the left, and the sidebar on the right. In the source code it appears like so: <div id="sidebar">This is where my sidebar goes </div> <div id="content">This is where my content goes </div> Will this affect SEO or other factors in my page?

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  • ORACLE SQL ROWNUM execution order

    - by iwan
    Dear expert, in Oracle SQL, there is a possible criteria called rownum. Can i confirm that rownum will be executed at last as just a limit for number of records return? or could it be executed first, before other WHERE SQL criteria (let's if we put rownum prior to the others)?

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  • MySQL limit from descending order

    - by faya
    Hello, Is it available to write a query to use same "LIMIT (from), (count)", but get result in backwards? In example if I have 8 rows in the table and I want to get 5 rows in two steps I would: first step query: select * from table limit 0, 5 first step result: first 5 rows; second step query: select * from table limit 5, 5 second step result: last 3 rows; But I want to get it vice versa. I mean from the first step I want last 3 rows and from the second I want 5 first rows. Thank you for your answer

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  • How to re-order a List<String>

    - by tarka
    I have created the following method: public List<String> listAll() { List worldCountriesByLocal = new ArrayList(); for (Locale locale : Locale.getAvailableLocales()) { final String isoCountry = locale.getDisplayCountry(); if (isoCountry.length() > 0) { worldCountriesByLocal.add(isoCountry); Collections.sort(worldCountriesByLocal); } } return worldCountriesByLocal; } Its pretty simple and it returns a list of world countries in the users locale. I then sort it to get it alphabetic. This all works perfectly (except I seem to occasionally get duplicates of countries!). Anyway, what I need is to place the US, and UK at the top of the list regardless. The problem I have is that I can't isolate the index or the string that will be returned for the US and UK because that is specific to the locale! Any ideas would be really appreciated.

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  • Teaching a kid to type in order to start programming

    - by at
    My 5 year old wants to start programming, but he doesn't yet know how to type without looking for each letter 1 at a time. I know it's going to frustrate him to go so slow because of his typing speed. And it's not going to be fun looking for all the letters constantly... So what's the best way to get him to type fast? Clearly he'll need to type a lot of punctuation like semicolons, colons and symbols. So his little hands will have to get used to spreading over the keyboard... I did some google searches and found some very poor looking apps that focused on the letters.

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  • Django: order by count of a ForeignKey field?

    - by AP257
    This is almost certainly a duplicate question, in which case apologies, but I've been searching for around half an hour on SO and can't find the answer here. I'm probably using the wrong search terms, sorry. I have a User model and a Submission model. Each Submission has a ForeignKey field called user_submitted for the User who uploaded it. class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) My question is pretty simple: how can I get a list of the three users with the most Submissions? I trued creating a num_submissions method on the User model: def num_submissions(self): num_submissions = Submission.objects.filter(uploaded_by=self).count() return num_submissions and then doing: top_users = User.objects.filter(problem_user=False).order_by('num_submissions')[:3] but this fails, as do all the other things I've tried. Can I actually do it using a smart database query? Or should I just do something more hacky in the views file?

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  • order of initialization in Java

    - by M.H
    Hi, I want to ask why java initializes the static objects before the non-static objects ? in this example b3 will be initialized after b4 and b5 : class Cupboard { Bowl b3 = new Bowl(3); static Bowl b4 = new Bowl(4); Cupboard() {} static Bowl b5 = new Bowl(5); }

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  • How to order a ls output by suffix?

    - by Luca Borrione
    Having a ls output like GGGG_3.0.3_98/ GGGG_3.0.3_d_100/ GGGG_3.0.3_d_101/ GGGG_3.0.3_d_99/ GGGG_3.0.4_104/ GGGG_3.0.4_105/ GGGG_3.0.4_106/ GGGG_3.0_87/ GGGG_3.0_89/ GGGG_3.0_90/ GGGG_3.0_91/ GGGG_3.0_92/ GGGG_3.0_93/ SSS_2.2.3_01/ SSS_2.2.3_02/ SSS_2.2.3_03/ TTT_2.8.3_29/ how to get the elements ordered by suffix? Also, is there any quick command I can use to know that 106 is the last suffix in this example? Sorry: it wasn't clear that "the suffix" in the given example is everything following the final underscore.

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  • Change library load order at run time (like LD_PRELOAD but during execution)

    - by tylerl
    How do I change the library a function loads from during run time? For example, say I want to replace the standard printf function with something new, I can write my own version and compile it into a shared library, then put "LD_PRELOAD=/my/library.so" in the environment before running my executable. But let's say that instead, I want to change that linkage from within the program itself. Surely that must be possible... right?

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  • Re-order mysql rows using PHP

    - by dave e
    | id | url | title | menu_id | ------+--------+--------+---------- | 1 | http://| link 1 | 1 | | 2 | http://| link 2 | 2 | | 3 | http://| link 3 | 3 | | 4 | http://| link 4 | 4 | Hi, I was wondering if its possible using PHP to reorder the above to something like below. I am trying to generate a menu which can easily be reordered by clicking an up or down arrow. I have no idea where to start. Any help would be much appreciated. | id | url | title | menu_id | ------+--------+--------+---------- | 1 | http://| link 1 | 2 | | 2 | http://| link 2 | 4 | | 3 | http://| link 3 | 3 | | 4 | http://| link 4 | 1 |

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  • Generate combinations by order and fixed length.

    - by roconmachine
    Suppose there is array main[] = [a,b,c,....z]; a[] = [a1,a2,a3,....] , b[] = [b1,b2,b3,....] and so on. So if we generate combination in main.length of ordered then it looks like ..... a1 b1 c1, a1 b1 c2, a1 b1 c3 ...... a1 b2 c1, a1 b3 c1, ..... a2 b1 c1, a3 b1 c1, ..... and total count will be a.length * b.length * c.length ........ = ? So write a code in any language to generate those combination. all the best. alex

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  • Using :limit and :order in the associated model

    - by r2b2
    Hello, Is there any way i can limit the results of an associated model? This what i was trying to do : <ul> <% account.logins.slice(0,5).sort_by(&:login_date).reverse.each do |login| -%> <li><%=h login.login_date.strftime("%d.%m.%Y")%></li> <% end -%> </ul> I'm trying to get the last five logins of the account. I cant seem to do it with account.logins(:limit=5) Thanks !

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  • CRC function without order dependency

    - by Pirks
    I need a CRC mechanism to calculate the CRC of a number of strings, such that, given two strings, A and B, the sum crc(A) + crc(B) == crc(A+B). P.S. XOR is too weak---the algorithm should be not trivial for reverse engineering.

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  • SQL: How to order values inside group by

    - by Denis Yaremov
    Consider the following MS SQL Server table: ID | X | Y ------+-------+------- 1 | 1 | 1 2 | 1 | 2 3 | 1 | 3 4 | 2 | 40 5 | 2 | 500 6 | 3 | 1 7 | 3 | 100 8 | 3 | 10 I need to select the ID of the row that has the maximum value of Y grouped by x, i.e: ID | X | Y ------+-------+------- 3 | 1 | 3 5 | 2 | 500 7 | 3 | 100 The query will be nested several times so an optimal performance solution is required... Thank you!

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