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• More efficient R / Sweave / TeXShop work-flow?

  - by user594795

  I've now got everything to work properly on my Mac OS X 10.6 machine so that I can create decent looking LaTeX documents with Sweave that include snippets of R code, output, and LaTeX formatting together. Unfortunately, I feel like my work-flow is a bit clunky and inefficient: Using TextWrangler, I write LaTeX code and R code (surrounded by <<= above and @ below R code chunk) together in one .Rnw file. After saving changes, I call the .Rnw file from R using the Sweave command Sweave(file="/Users/mymachine/Documents/Assign4.Rnw", syntax="SweaveSyntaxNoweb") In response, R outputs the following message: You can now run LaTeX on 'Assign4.tex' So then I find the .tex file (Assign4.tex) in the R directory and copy it over to the folder in my documents ~/Documents/ where the .Rnw file is sitting (to keep everything in one place). Then I open the .tex file (e.g. Assign4.tex) in TeXShop and compile it there into pdf format. It is only at this point that I get to see any changes I have made to the document and see if it 'looks nice'. Is there a way that I can compile everything with one button click? Specifically it would be nice to either call Sweave / R directly from TextWrangler or TeXShop. I suspect it might be possible to code a script in Terminal to do it, but I have no experience with Terminal. Please let me know if there's any other things I can do to streamline or improve my work flow.

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• What could cause xmlrpclib.ResponseError: ResponseError() ?

  - by Tom

  Hi, I am experimenting with XML-RPC. I have the following server script (python): from SimpleXMLRPCServer import SimpleXMLRPCServer server = SimpleXMLRPCServer(('localhost', 9000)) def return_input(someinput): return someinput server.register_function(return_input) try: print 'ctrl-c to stop server' server.serve_forever() except KeyboardInterrupt: print 'stopping' and the following client script: import xmlrpclib server = xmlrpclib.ServerProxy('http://www.example.com/pathto/xmlrpcTester2.py') print server.return_input('some input') I have tested this locally and it works fine. All it does it spit out the input fron the client script, which is right. However, when I try to do it on a remote server I get the following error: Traceback (most recent call last): File "client.py", line 4, in <module> print server.return_input('some input') File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1199, in __call__ return self.__send(self.__name, args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1489, in __request verbose=self.__verbose File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1253, in request return self._parse_response(h.getfile(), sock) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1392, in _parse_response return u.close() File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 836, in close raise ResponseError() xmlrpclib.ResponseError: ResponseError() Any ideas what could cause this? Thanks in advance for your help.

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• KO3: How to deal with stylesheets and scriptfiles

  - by Svish

  I'm using Kohana 3 and it's template controller. My main site template controller currently looks something like this: <?php defined('SYSPATH') or die('No direct script access.'); abstract class Controller_SiteTemplate extends Controller_Template { public function before() { parent::before(); // Initialize default template variables $this->template->styles = Kohana::config('site.styles'); $this->template->scripts = Kohana::config('site.scripts'); $this->template->title = ''; $this->template->content = ''; } } And then in my template view I do: <?php # Styles foreach($styles as $file => $media) echo HTML::style($file, array('media' => $media)).PHP_EOL ?> <?php # Scripts foreach($scripts as $file) echo HTML::script($file).PHP_EOL ?> This works alright. The problem is that it requires the style- and script files to be added in the controller, which shouldn't really have to care about those. It also makes it a hassle if the views are done by someone else than me since they would have to fool around with the controller just to add a new stylesheet or a new script file. How can this be done in a better way? Just to clearify, what I am wondering is how to deal with page specific stylesheets and scripts. The default and site-wide ones I have no problem with fetching from a config file or just put directly in the template view. My issue is how to add custom ones for specific pages in a good way.

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• #include - brackets vs quotes in XCode?

  - by Chris Becke

  In MSVC++ #include files are searched for differently depending on whether the file is enclosed in "" or <. The quoted form searches first in the local folder, then in /I specified locations, The angle bracket form avoids the local folder. This means, in MSVC++, its possible to have header files with the same name as runtime and SDK headers. So, for example, I need to wrap up the windows sdk windows.h file to undefine some macro's that cause trouble. With MSVS I can just add a (optional) windows.h file to my project as long as I include it using the quoted form :- // some .cpp file #include "windows.h" // will include my local windows.h file And in my windows.h, I can pull in the real one using the angle bracket form: // my windows.h #include <windows.h> // will load the real one #undef ConflictingSymbol Trying this trick with GCC in XCode didn't work. angle bracket #includes in system header files in fact are finding my header files with similar names in my local folder structure. The MSVC system means its quite safe to have a "String.h" header file in my own folder structre. On XCode this seems to be a major no no. Is there some way to control this search path behaviour in XCode to be more like MSVC's? Or do I just have to avoid naming any of my headers anything that might possibly conflict with a system header. Writing cross platform code and using lots of frameworks means the possibility of incidental conflicts seems large.

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• Parsing large txt files in ruby taking a lot of time?

  - by hershey92

  below is the code to download a txt file from internet approx 9000 lines and populate the database, I have tried a lot but it takes a lot of time more than 7 minutes. I am using win 7 64 bit and ruby 1.9.3. Is there a way to do it faster ?? require 'open-uri' require 'dbi' dbh = DBI.connect("DBI:Mysql:mfmodel:localhost","root","") #file = open('http://www.amfiindia.com/spages/NAV0.txt') file = File.open('test.txt','r') lines = file.lines 2.times { lines.next } curSubType = '' curType = '' curCompName = '' lines.each do |line| line.strip! if line[-1] == ')' curType,curSubType = line.split('(') curSubType.chop! elsif line[-4..-1] == 'Fund' curCompName = line.split(" Mutual Fund")[0] elsif line == '' next else sCode,isin_div,isin_re,sName,nav,rePrice,salePrice,date = line.split(';') sCode = Integer(sCode) sth = dbh.prepare "call mfmodel.populate(?,?,?,?,?,?,?)" sth.execute curCompName,curSubType,curType,sCode,isin_div,isin_re,sName end end dbh.do "commit" dbh.disconnect file.close 106799;-;-;HDFC ARBITRAGE FUND RETAIL PLAN DIVIDEND OPTION;10.352;10.3;10.352;29-Jun-2012 This is the format of data to be inserted in the table. Now there are 8000 such lines and how can I do an insert by combining all that and call the procedure just once. Also, does mysql support arrays and iteration to do such a thing inside the routine. Please give your suggestions.Thanks.

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• Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

  - by ipalaus

  I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code: <!-- First I add the XML file --> <xsl:param name="menu" select="document('menu.xml')" /> <!-- Next I add the transformations for menu.xml file --> <xsl:include href="menu.xsl" /> <!-- Finally, I process it on the actual ("parent") XML --> <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

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• Trying to grab several random videos from database, but it just shows the same one all the time.

  - by Birk

  Hi guys, I'm trying to grab several random videos from my database, and have them show on a page. However, it just keeps on grabbing the same video rather than several different ones. So I end up with 5 of the same video rather than 5 different ones. Here's the grab random PHP code file... and after it is the template output file. //===================================================== // Random | Previous | Next //===================================================== $show['random'] = $db->quick_fetch( "SELECT file_id, title, title_seo, category_id, thumb FROM files WHERE files.category_id = '".$show['main']['category_id']."' AND files.verified=1 ORDER BY RAND() LIMIT 0,1; "); Here's the template CSS html thingy code I have this pasted 5 times to show 5 random videos <td valign="top" width="53%"><? $sql="select * from files ORDER BY rand() limit 0,5"; $res=@mysql_query($sql); $data=@mysql_result($res,0,'filename'); $id=@mysql_result($res,0,'file_id'); $title=@mysql_result($res,0,'title'); $title2=str_replace(" ", "-",$title); $path="{$siteurl}/media/{$file.random.file_id}/{$file.random.title_seo}/"; $img="{$siteurl}/thumbs/{$file.random.thumb}"; echo " {$file.random.title}"

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• read files from directory and filter files from Java

  - by Adnan

  The following codes goes through all directories and sub-directories and outputs just .java files; import java.io.File; public class DirectoryReader { private static String extension = "none"; private static String fileName; public static void main(String[] args ){ String dir = "C:/tmp"; File aFile = new File(dir); ReadDirectory(aFile); } private static void ReadDirectory(File aFile) { File[] listOfFiles = aFile.listFiles(); if (aFile.isDirectory()) { listOfFiles = aFile.listFiles(); if(listOfFiles!=null) { for(int i=0; i < listOfFiles.length; i++ ) { if (listOfFiles[i].isFile()) { fileName = listOfFiles[i].toString(); int dotPos = fileName.lastIndexOf("."); if (dotPos > 0) { extension = fileName.substring(dotPos); } if (extension.equals(".java")) { System.out.println("FILE:" + listOfFiles[i] ); } } if(listOfFiles[i].isDirectory()) { ReadDirectory(listOfFiles[i]); } } } } } } Is this efficient? What could be done to increase the speed? All ideas are welcome.

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• How to wrap Ruby strings in HTML tags

  - by Jason H.

  Hi all: I'm looking for help on two things. 1) I'm looking for a way for Ruby to wrap strings in HTML. I have a program I'm writing that generates a Hash of word frequencies for a text file and I want to take the results and place it into an HTML file rather than print to STDOUT. I'm thinking each string needs to be wrapped in an HTML paragraph tag using readlines() or something, but I can't quite figure it out. Then, once I've wrapped the strings in HTML 2) I want to write to an empty HTML file. Right now my program looks like: filename = File.new(ARGV[0]).read().downcase().scan(/[\w']+/) frequency = Hash.new(0) words.each { |word| frequency[word] +=1 } frequency.sort_by { |x,y| y }.reverse().each{ |w,f| puts "#{f}, #{w}" } So if we ran a text file through this and received: 35, the 27, of 20, to 16, in # . . . I'd want to export to an HTML file that wraps the lines like: <p>35, the</p> <p>27, of</p> <p>20, to</p> <p>16, in</p> # . . . Thanks for any tips in advance!

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• CSS class not working as expected [closed]

  - by user1050619

  My HTML codes not implement the CSS styling..The border in the CSS file is not being implemented. I tried both in Firefox & IE. Please provide your inputs. Please find the code below: HTML <html> <head> <link href="file://c:/jquery/chapter-1/begin/styles/my_style.css" rel="stylesheet"> </head> <body> <div id="header" class="no_hover"><h1>Header</h1></div> <button type="button" id="btn1">Click to Add</button> <button type="button" id="btn2">Click to Remove</button> <script src="file://c:/jquery/chapter-1/begin/scripts/jquery.js" type="text/javascript"></script> <script src="file://c:/jquery/chapter-1/begin/scripts/test4.js" type="text/javascript"></script> </body> </html> jS FILE $(document).ready(function() { $("#btn1").click( function(){ $("#header").addClass("hover"); $("#header").removeClass("no_hover"); }); $("#btn2").click( function(){ $("#header").removeClass("hover"); $("#header").addClass("no_hover"); }); }); CSS FILE .hover{ border: solid #f00 3px; } .no_hover{ border: solid #000 3px; }

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• SQLite DB open time really long Problem

  - by sxingfeng

  I am using sqlite in c++ windows, And I have a db size about 60M, When I open the sqlite db, It takes about 13 second. sqlite3* mpDB; nRet = sqlite3_open16(szFile, &mpDB); And if I closed my application and reopen it again. It takse only less then 1 second. First, I thought It is because of disk cache. So I preload the 60M db file before sqlite open, and read the file using CFile, However, after preloading, the first time is still very slow. BOOL CQFilePro::PreLoad(const CString& strPath) { boost::shared_array<BYTE> temp = boost::shared_array<BYTE>(new BYTE[PRE_LOAD_BUFFER_LENGTH]); int nReadLength; try { CFile file; if (file.Open(strPath, CFile::modeRead) == FALSE) { return FALSE; } do { nReadLength = file.Read(temp.get(), PRE_LOAD_BUFFER_LENGTH); } while (nReadLength == PRE_LOAD_BUFFER_LENGTH); file.Close(); } catch(...) { } return TRUE; } My question is what is the difference between first open and second open. How can I accelerate the sqlite open-process.

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• In .NET, how do you send multiple arguments into a DOS command prompt?

  - by donde

  I am trying to execute DOS commands in ASP.NET 2.0. What I have now calls a BAT file which, in turn, calls a CMD file. It works (with the end result being a file gets ftp'ed). However, I'd like to dump the BAT and CMD files and run everything in .NET. What is the format of sending multiple arguments into the command window? Here is what I have now. The .NET Code: System.Diagnostics.Process proc = new System.Diagnostics.Process(); proc.EnableRaisingEvents = false; proc.StartInfo.FileName = "C:\\MyBat.BAT"; proc.Start(); proc.WaitForExit(); The Bat File looks like this (all it does is run the cmd file): ftp.exe -s:C:\MyCMD.cmd And here is the content of the Cmd file: open <my host> <my user name> <my pw> quote site cyl pri=1 sec=1 lrecl=1786 blksize=0 recfm=fb retpd=30 put C:\MyDTLFile.dtl 'MyDTLFile.dtl' quit

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• Trouble deciding how to add popup menu to eclipse plugin using either action ObjectContributions or command handlers

  - by user1808408

  The issue is this: Most things I read on the web says that we should avoid actions when creating popup menus because the command framework allows for more decoupling. Example: http://wiki.eclipse.org/FAQ_What_is_the_difference_between_a_command_and_an_action%3F Fair enough. But I am having a heck of a time getting the command framework to add my menu when I right click on a .java file inside the editor, and only when I click inside the editor. I can get the menu to show (using 'with' and the activeEditor variable), but it also shows when I right click on the java file inside the package explorer, which I don't want. I suspect it's because the file is already open inside the editor. I also have a menu that gets added when I right click on the java file inside the package explorer, using IComplilationUnit. That works fine. So my problem is solved using a popup menu action for when I click inside the file. I also get access to to all the ISelection stuff there. But the coupling is to high and I lose the flexability of using handlers. I'm looking for either: Tell me I'm doing it the only way possible; or Tell me how to have my popup appear only when I right click on the java file editor. Regards

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• Run FFmpeg from Shell Script

  - by Abs

  Hello all, I have found a useful shell script that shows all files in a directory recursively. Where it prints the file name echo "$i"; #Display File name. I would instead like to run an ffmpeg command on non MP3 files, how can I do this? I have very limited knowledge of shell scripts so I appreciate if I was spoon fed! :) //if file is NOT MP3 ffmpeg -i [the_file] -sameq [same_file_name_with_mp3_extension] //delete old file Here is the shell script for reference. DIR="." function list_files() { if !(test -d "$1") then echo $1; return; fi cd "$1" echo; echo `pwd`:; #Display Directory name for i in * do if test -d "$i" #if dictionary then list_files "$i" #recursively list files cd .. else echo "$i"; #Display File name fi done } if [ $# -eq 0 ] then list_files . exit 0 fi for i in $* do DIR="$1" list_files "$DIR" shift 1 #To read next directory/file name done

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• programs hangs during socket interaction

  - by herrturtur

  I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

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• Minimizing server load in case of many XMLHttpRequest calls

  - by user1888975

  I am making a website where users are to like some articles. Whenever the like button is clicked I am sending a XMLHttpRequest to the server to run a file called like_clicked.php along with the get data of article id and user id. This file takes article id and user id and updates the sql database and also adds a node in an xml file related to the user. This is the first time I am doing something for mass usage. I am worried about the server load when too many users call the like_clicked.php file. Please help me, if this method is ok. I am also thinking of an alternative in case the above method fails. I am thinking of making many like_clicked files (namely like_clicked1.php, like_clicked2.php ... ) to minimize load on a single i-node. Is there a method to detect that it is better to call the next like_clicked file. Here we would need to detect how many calls per unit time are coming for the particular file. How do we handle this? Thanks in advance.

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• C# call a C++ dll get EntryPointNotFoundException

  - by 5YrsLaterDBA

  I was gaven a C++ dll file, a lib file and a header file. I need to call them from my C# application. header file looks like this: class Clog ; class EXPORT_MACRO NB_DPSM { private: string sFileNameToAnalyze ; Clog *pLog ; void write2log(string text) ; public: NB_DPSM(void); ~NB_DPSM(void); void setFileNameToAnalyze(string FileNameToAnalyze) ; int WriteGenbenchData(string& message) ; }; In my C# code, I have those code: internal ReturnStatus correctDataDLL(string rawDataFileName) { if (rawDataFileName == null || rawDataFileName.Length <= 0) { return ReturnStatus.Return_CannotFindFile; } else { setFileNameToAnalyze(rawDataFileName); } string msg = ""; int returnVal = WriteGenbenchData(ref msg); return ReturnStatus.Return_Success; } [DllImport("..\\..\\thirdParty\\cogs\\NB_DPSM.dll")] public static extern void setFileNameToAnalyze(string fileName); [DllImport("..\\..\\thirdParty\\cogs\\NB_DPSM.dll")] public static extern int WriteGenbenchData(ref string message); I got EntryPointNotFoundException at the setFileNameToAnalyze(rawDataFileName); statement. Few questions: do I need to add that lib file into somewhere of my C# project? how? do I need to add the header file into my C# project? how? (no compile error for now) I would like to remove those "..\\..\\thirdParty\\cogs\\" hardcode path. how to this? how to get ride of that EntryPointNotFoundException? thanks,

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• Java: over-typed structures?

  - by HH

  Term over-type structure = a data structure that accepts different types, can be primitive or user-defined. I think ruby supports many types in structures such as tables. I tried a table with types 'String', 'char' and 'File' in Java but errs. How can I have over-typed structure in Java? How to show types in declaration? What about in initilization? Suppose a structure: INDEX VAR FILETYPE //0 -> file FILE //1 -> lineMap SizeSequence //2 -> type char //3 -> binary boolean //4 -> name String //5 -> path String Code import java.io.*; import java.util.*; public class Object { public static void print(char a) { System.out.println(a); } public static void print(String s) { System.out.println(s); } public static void main(String[] args) { Object[] d = new Object[6]; d[0] = new File("."); d[2] = 'T'; d[4] = "."; print(d[2]); print(d[4]); } } Errors Object.java:18: incompatible types found : java.io.File required: Object d[0] = new File("."); ^ Object.java:19: incompatible types found : char required: Object d[2] = 'T'; ^

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• Another boost error

  - by user1676605

  On this code I get the enourmous error static void ParseTheCommandLine(int argc, char *argv[]) { int count; int seqNumber; namespace po = boost::program_options; std::string appName = boost::filesystem::basename(argv[0]); po::options_description desc("Generic options"); desc.add_options() ("version,v", "print version string") ("help", "produce help message") ("sequence-number", po::value<int>(&seqNumber)->default_value(0), "sequence number") ("pem-file", po::value< vector<string> >(), "pem file") ; po::positional_options_description p; p.add("pem-file", -1); po::variables_map vm; po::store(po::command_line_parser(argc, argv). options(desc).positional(p).run(), vm); po::notify(vm); if (vm.count("pem file")) { cout << "Pem files are: " << vm["pem-file"].as< vector<string> >() << "\n"; } cout << "Sequence number is " << seqNumber << "\n"; exit(1); ../../../FIXMarketDataCommandLineParameters/FIXMarketDataCommandLineParameters.hpp|98|error: no match for ‘operator<<’ in ‘std::operator<< [with _Traits = std::char_traits](((std::basic_ostream &)(& std::cout)), ((const char*)"Pem files are: ")) << ((const boost::program_options::variable_value*)vm.boost::program_options::variables_map::operator[](((const std::string&)(& std::basic_string, std::allocator (((const char*)"pem-file"), ((const std::allocator&)((const std::allocator*)(& std::allocator()))))))))-boost::program_options::variable_value::as with T = std::vector, std::allocator , std::allocator, std::allocator ’|

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• an algorhithm for filtering out raw txt files

  - by Roman Luštrik

  Imagine you have a .txt file of the following structure: >>> header >>> header >>> header K L M 200 0.1 1 201 0.8 1 202 0.01 3 ... 800 0.4 2 >>> end of file 50 0.1 1 75 0.78 5 ... I would like to read all the data except lines denoted by >>> and lines below the >>> end of file line. So far I've solved this using read.table(comment.char = ">", skip = x, nrow = y) (x and y are currently fixed). This reads the data between the header and >>> end of file. However, I would like to make my function a bit more plastic regarding the number of rows. Data may have values larger than 800, and consequently more rows. I could scan or readLines the file and see which row corresponds to the >>> end of file and calculate the number of lines to be read. What approach would you use?

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• PHP generating csv not sending correct new line feeds

  - by sjw

  I have a script that generates a csv file using the following code: header('Content-type: text/csv'); header('Content-Disposition: attachment; filename="'.date("Ymdhis").'.csv"'); print $content; The $content variable simply contains lines with fields separated by commas and then finalised with ."\n"; to generate a new line. When I open the file in csv it looks fine however, when I try to use the file to import into an external program (MYOB) it does not recognise the End Of Line (\n) character and assumes one long line of text. When I view the contents of the file in notepad, the end of line character (\n) is a small rectangle box which looks like the character code 0x7F. If I open the file and re-save it in excel, it removes this character and replaces it with a proper end of line character and I can import the file. What character do I need to be generating in PHP so that notepad recognises it as a valid End Of Line character? (\n) obviously doesn't do the job.

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• FTP exception 501 "pathname" more than 8 characters

  - by BigMac66

  I am trying to access a file via a URI using the FTP protocol. For obvious security reasons I had to make some changes but this is where the problems seem to be coming from. My URI is as follows: ftp://user:[email protected]/u/Bigpathname/XYZ/ABC/BigPathname/bigpathname/xyz/abc/MY_LOG.LOG And I see this exception: sun.net.ftp.FtpProtocolException: CWD Bigpathname:501 A qualifier in "Bigpathname" is more than 8 characters This is really confusing as I can access the file from a Windows 7 command line with the CD command just fine. Both one directory at a time and as a full path. I found one article mentioning that MVS file names must be 8 or fewer characters but this does not explain how I can get to these same files from my command line! They do exist there is data there that I can download manual but I can not get there via a URI in Java. PS I use .toURL().openStream() to get files on my local machine just fine, it only fails when I try to get them from my server. EDIT October 1st I am able to access files on the MVS host using FileZilla and the basic FTP client from the Windows 7 command line - but I still cannot get them from a URI/URL. I downloaded a very basic Java built FTP client and tried accessing the same file in my program from there and the path works but because my file name has a dot in it "MY_LOG.LOG" I am getting File does not exist 501 Invalid data set name "MY_LOG.LOG". Use MVS Dsname conventions. I am utterly perplexed by this...

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• When Creating a Reference for an Object Where from where that class is Loaded?

  - by asela38

  When doing some sample codings with Java I came crosss ClassCast Exception, from where I cast the object to StaticClass. Can any explaing the what has happened here. public void test5() throws Exception { System.out.println(StaticClass.obj); Object newInstance = ClassLoader.getSystemClassLoader().loadClass("com.StaticClass").newInstance(); System.out.println(newInstance.getClass().getDeclaredField("obj").get(newInstance)); Object newInstance2 = new ILoader().loadClass("com//StaticClass.class").newInstance(); System.out.println(newInstance2.getClass().getDeclaredField("obj").get(newInstance2)); StaticClass s = (StaticClass)newInstance2; System.out.println(s.obj); System.out.println(newInstance.getClass().getClassLoader()); System.out.println(newInstance2.getClass().getClassLoader()); } package com; public class StaticClass { public static final Object obj = new Object(); } package com; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; public class ILoader extends ClassLoader { public ILoader() { super(null); } @Override protected Class<?> findClass(String name) throws ClassNotFoundException { File file = new File(name); byte[] bytes = new byte[(int)file.length()]; try { new FileInputStream(file).read(bytes); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return super.defineClass("com.StaticClass",bytes, 0, bytes.length); } } output which was given by last sysout's when the casting part of the code not existed is as belows. sun.misc.Launcher$AppClassLoader@133056f com.ILoader@1ac3c08

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• how to download data which upload to gae ,

  - by zjm1126

  this is my code : import os from google.appengine.ext import webapp from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app from google.appengine.ext import db #from login import htmlPrefix,get_current_user class MyModel(db.Model): blob = db.BlobProperty() class BaseRequestHandler(webapp.RequestHandler): def render_template(self, filename, template_args=None): if not template_args: template_args = {} path = os.path.join(os.path.dirname(__file__), 'templates', filename) self.response.out.write(template.render(path, template_args)) class upload(BaseRequestHandler): def get(self): self.render_template('index.html',) def post(self): file=self.request.get('file') obj = MyModel() obj.blob = db.Blob(file.encode('utf8')) obj.put() self.response.out.write('upload ok') class download(BaseRequestHandler): def get(self): #id=self.request.get('id') o = MyModel.all().get() #self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o))) self.response.out.write(o) application = webapp.WSGIApplication( [ ('/?', upload), ('/download',download), ], debug=True ) def main(): run_wsgi_app(application) if __name__ == "__main__": main() my index.html is : <form action="/" method="post"> <input type="file" name="file" /> <input type="submit" /> </form> and it show : <__main__.MyModel object at 0x02506830> but ,i don't want to see this , i want to download it , how to change my code to run, thanks

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• Converting to MVC3 - some views still want 'System.Web.Mvc, Version=1.0.0.0,

  - by justSteve

  I've used the directions from the release notes and have been able to navigate most pages - my unit tests are not comprehensive but most all pass. However...when I attempt to edit an existing or create a new user I'm getting the error pasted below - notice that it's references version=1... - this project started life as a v1 and was converted to mvc2 at the RTM. I'm still working with V2 projects but no longer any v1. Am i due for a GAC cleansing? Server Error in '/' Application. Could not load file or assembly 'System.Web.Mvc, Version=1.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35' or one of its dependencies. The system cannot find the file specified. === Pre-bind state information === LOG: User = STUDIO11\mUser LOG: DisplayName = System.Web.Mvc, Version=1.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 (Fully-specified) LOG: Appbase = file:///C:/Users/C:\Users\[path to project]/ LOG: Initial PrivatePath = C:\Users\[path to project]\bin Calling assembly : App_Web_qcjylaoc, Version=0.0.0.0, Culture=neutral, PublicKeyToken=null. === LOG: This bind starts in default load context. LOG: Using application configuration file: C:\Users\[path to project]\web.config LOG: Using host configuration file: LOG: Using machine configuration file from C:\Windows\Microsoft.NET\Framework\v4.0.30319\config\machine.config. LOG: Post-policy reference: System.Web.Mvc, Version=1.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 LOG: The same bind was seen before, and was failed with hr = 0x80070002.

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