Search Results

Search found 6714 results on 269 pages for 'secondary views'.

Page 81/269 | < Previous Page | 77 78 79 80 81 82 83 84 85 86 87 88  | Next Page >

• ACL suggestions needed for a small light framework developed

  - by Sai

  Hello all, I've developed a small framework that was needed for the firm that I work. The problem is I've not made a full level framework, as developers are finding tough time to understand what is what, So I made a simple structure with app/controllers, app/models, app/views so that they can clearly separate the code and can get used to higher frameworks later. All other things like components/modules/helpers are just coded for now in a file called app_functions.php. The above framework is derived from cakePHP, not all, but just the framework uses a modified code of dispatcher of cake. The models all work with normal sqls, and views with pure html using a template engine. Now I'm trying to develop a small application over it, it cameout well, but ACL is something which many versions of it have not proved that satisfactory. Can anybody suggest a good ACL. I've checked phpGACL(too heavy), Zend_ACL likely won't be compatible, Cakephp's ACL which wont fit in the structure,as we are not using cake's SQLs, as there too many queries hitting the database for one page display.

  Read the article

• Seam page navigation with includes

  - by Marc

  Hello, I'm using seam page navigation rules. and did not experience any problem with adding rules which redirect from one page to another. But since I designed my page views using those redirection simply don't happen anymore for those pages. Tried to define the rule to the view that gets included, then to the view that includes the others (which to me was making more sense) but none work. Is there anything special about page navigation in seam using included view-id ? I'm using jsf, xhtml as my page views. Thanks

  Read the article

• In Prism (CAL), how can I RegisterPresenterWithRegion instead of RegisterViewWithRegion

  - by Edward Tanguay

  I have a module in a Prism application and in its initialize method I want to register a presenter instead of a view with a region, i.e. I want to do this: PSEUDO-CODE: regionManager.RegisterPresenterWithRegion( "MainRegion", typeof(Presenters.EditCustomerPresenter)); instead of loading a view like this: regionManager.RegisterViewWithRegion( "MainRegion", typeof(Views.EditCustomerView)); The presenter would of course bring along its own view and ultimately register this view in the region, but it would allow me to bind the presenter to the view in the presenter's constructor instead of binding the two together in XAML (which is more of a decoupled MVVM pattern which I want to avoid here). How can I add a Presenter to a Region instead of a view? namespace Client.Modules.CustomerModule { [Module(ModuleName = "CustomerModule")] public class CustomerModule : IModule { private readonly IRegionManager regionManager; public CustomerModule(IRegionManager regionManager) { this.regionManager = regionManager; } public void Initialize() { regionManager.RegisterViewWithRegion("MainRegion", typeof(Views.EditCustomerView)); } } }

  Read the article

• A little bit more complicated multiview App for Iphone

  - by Thomas Losert

  Hi, i'm new to iphone development. I spend several days by looking for how write muliview app for an Iphone OS. I found how to switch the diferent views without navigation hierarchy (in this article). It's great, but i want more complicated function. For example, i have three diferent views (view 1 - 3) and i can switch between them with technique from link 1. It works fine. My question is: How can i put UITabBarController on view 2, that shows own subviews (tabView 1 - 3) and how put UINavigationController on view 3, that shows own subviews (navView 1 - 2)? The reslut should look like that, one main view (view 1) with two buttons (for example), which switch me to "window" with UiTabBarController or UINavigationController. I found only tutorials, where UITabBarController was a first controller class, that shows directly from AppDelegate (something like default Xcode predefined scenarios). Thanks for your helpfull answer, or i will be crazy soon:).

  Read the article

• How to allow for modular development while still running in same JVM?

  - by Marcus

  Our current app runs in a single JVM. We are now splitting up the app into separate logical services where each service runs in its own JVM. The split is being done to allow a single service to be modified and deployed without impacting the entire system. This reduces the need to QA the entire system - just need to QA the interaction with the service being changed. For interservice communication we use a combination of REST, an MQ system bus, and database views. What I don't like about this: REST means we have to marshal data to/from XML DB views couple the systems together which defeats the whole concept of separate services MQ / system bus is added complexity There is inevitably some code duplication between services You have set up n JBoss server configurations, we have to do n number of deployments, n number of set up scripts, etc, etc. Is there a better way to structure an internal application to allow modular development and deployment while allowing the app to run in a single JVM (and achieving the associated benefits)?

  Read the article

• Rails - Format number as currency format in the Getter

  - by daemonsy

  I am making a simple retail commerce solution, where there are prices in a few different models. These prices contribute to a total price. Imagine paying $0.30 more for selecting a topping for your yogurt. When I set the price field to t.decimal :price, precision:8, scale:2 The database stores 6.50 as 6.5. I know in the standard rails way, you call number_to_currency(price) to get the formatted value in the Views. I need to programmatically call the price field as well formatted string, i.e. $6.50 a few places that are not directly part of the View. Also, my needs are simple (no currency conversion etc), I prefer to have the price formatted universally in the model without repeated calling number_to_currency in views. Is there a good way I can modify my getter for price such that it always returns two decimal place with a dollar sign, i.e. $6.50 when it's called? Thanks in advance.

  Read the article

• Load a UIView from a NIB

  - by Winder

  I have been using UIViewControllers and initWithNibName with much success, basically using them as a convenient way to design the view with Interface Builder. Unfortunately I have built a hierarchy of views before noticing this line in the UIViewController documentation: Note: You should not use view controllers to manage views that fill only a part of their window My question is this: Having a very simple NIB that only has a UIView in addition to the default First Responder and Owning Object, what is the simplest way to load the UIView into my code? I have not been able to get loadNibNamed:owner:options: to work at this point, but suspect the answer will involve it somehow.

  Read the article

• Visual Studio: How to override the default "Build Action" for certain extension types per project or solution?

  - by Lukasz Podolak

  I'm serving my asp.net mvc views from many assemblies and copying views to the main application on post-build event. This works, however, I realized, that when I change something in view and just hit F5, changes are not included. What I have to do to see changes is to: save, build<- explicitly clicking, and then hit F5. However, it's pretty annoying solution. I discovered that setting Build action to "Embedded Resource" on view solves the problem as well, however other devs may not remember that they have to do this after adding every view to the solution. Is there a way to override the default build action for certain file extensions, such as: *.aspx, *.ascx in project or (better) in solution ? What I've found is an ability to add this setting globally, per machine, but I do not want to do that (link: http://blog.andreloker.de/post/2010/07/02/Visual-Studio-default-build-action-for-non-default-file-types.aspx) Any ideas ?

  Read the article

• UITabBarController "More" tab issues

  - by codemonkey

  I've got a UITabBarController with 7 tabs. Each of the 7 tabs has its own UINavigationController and customizes its toolbar. When a view is loaded via the UITabBarController's "More" menu its custom toolbar isn't appearing. If i switch the order of the views around so that the same view is now accessible from the UITabBar without going through the "More" menu then the custom toolbar shows up like it's supposed to. Is there a way to customize a NavigationController's toolbar when that NavigationController is loaded via the "More" menu of a TabBarController? I'm actually also interested in replacing the "More" menu navigation controller with my own custom one on views loaded via the "More" menu... not sure whether that's even possible. Any feedback will be appreciated.

  Read the article

• django: ajax view structure

  - by zack

  I want to know the correct way to structure ajax views in django. say i do something like : def foo_json(request): if is.ajax(): # return JSON here and make it available as a resource at something like '/foo/data/'.. all is fine.. but if I point the browser at '/foo/data/' .. obviously I get an error (debug) like: app.views.foo_json didn't return an HttpResponse object. so... my question is: Whats the best way structure this kind of view? ..should I return an HTTP response code ..maybe 404 / 405 ... or something else? - not sure of the best way to handle this, any advice appreciated :)

  Read the article

• How to set the content of the $script_for_layout in cakephp?

  - by sipiatti

  Hi, I am learning cakephp in an autodidact manner and I am a complete newbie :) I am creating a simple application. Some logic work so now I going to dive into designing views and layouts. I read the docs and the tutorial but I could not find where to set the content of $script_for_layout. Especially I want to set a $html-css to create link in pages to the stylesheet. I found out that I could do it in directly in the layout template but I would like to create the same link in all pages/views/layouts to the stylesheet so I hope there is a simple way, and avoid to do this in all layouts and/or controllers

  Read the article

• Add version control to existing SQL Server database

  - by ederbf

  I am part of a development team currently working with a database that does not have any kind of source control. We work with SQL Server 2008 R2 and have always managed the DB directly with SSMS. It now has ~340 tables and ~1600 stored procedures, plus a few triggers and views, so it is not a small DB. My goal is to have the DB under version control, so I have been reading articles, like Scott Allen's series (http://bitly.com/9cJmGR) and many old SO related questions. But I am still unable to decide on how to proceed. What I'm thinking of is to script the database schema in one file, then procedures, triggers and views in one file each. Then keep everything versioned under Mercurial. But of course, every member of the team can access SSMS and directly change the schema and procedures, with the possibility that any of us can forget to replicate those changes in the versioned files. What better options are there? And, did I forget any element worth having source control of?

  Read the article

• UISegmentedControl is hidden under the titleBar

  - by shay te

  i guess i am missing something with the UISegmentedControl and auto layout. i have a TabbedApplication (UITabBarController), and i created a new UIViewController to act as tab. to the new view i added UISegmentedControl, and place it to top using auto layout. i guess i don't understand completely something , cause the UISegmentedControl is hiding under the titleBar . can u help me understand what i am missing ? thank you . import Foundation import UIKit; class ViewLikes:UIViewController { override func viewDidLoad() { super.viewDidLoad() title = "some title"; var segmentControl:UISegmentedControl = UISegmentedControl(items:["blash", "blah blah"]); segmentControl.selectedSegmentIndex = 1; segmentControl.setTranslatesAutoresizingMaskIntoConstraints(false) self.view.addSubview(segmentControl) //Set layout var viewsDict = Dictionary <String, UIView>() viewsDict["segment"] = segmentControl; //controls self.view.addConstraints(NSLayoutConstraint.constraintsWithVisualFormat("H:|-[segment]-|", options: NSLayoutFormatOptions.AlignAllCenterX, metrics: nil, views: viewsDict)) self.view.addConstraints(NSLayoutConstraint.constraintsWithVisualFormat("V:|-[segment]", options: NSLayoutFormatOptions(0), metrics: nil, views: viewsDict)) } override func didReceiveMemoryWarning() { super.didReceiveMemoryWarning() // Dispose of any resources that can be recreated. } }

  Read the article

• memory issue iPad 4.2 crashes

  - by Manoj Kumar

  I am developing a application which receives 600-700 KB of XML data from the server. I have to do some manipulations in that data so once received the data the memory increases to 600 KB to 2 M.B. Already view occupied 4 M.B of memory in the application. So while processing the XML data i m doing some manipulation(pre-parsing) and the memory increases to 600 K.B to 2 M.B and finally decreases to 600 K.B. due to increase in memory, application gives the memory warning. While getting memory warning i m releasing all the views in the navigation controller but it releases only 1 M.B of memory. Even though I release all the views the application is crashing. Please help me out in this issue. It happens in iPad 4.2. Thanks in advance

  Read the article

• Why does my Spring Controller direct me to the wrong page?

  - by kc2001

  I am writing my first Spring 3.0.5 MVC app and am confused about why my controller mappings aren't doing what I expect. I have a VerifyPasswordController that is called after a user tries to log in by entering his name and password. // Called upon clicking "submit" from /login @RequestMapping(value = "/verifyPassword", method = RequestMethod.POST) @ModelAttribute("user") public String verifyPassword(User user, BindingResult result) { String email = user.getEmail(); String nextPage = CHOOSE_OPERATION_PAGE; // success case if (result.hasErrors()) { nextPage = LOGIN_PAGE; } else if (!passwordMatches(email, user.getPassword())) { nextPage = LOGIN_FAILURE_PAGE; } else { // success } return nextPage; } I can verify in the debugger that this method is being called, but afterwards, the verifyPassword page is displayed rather than the chooseOperation page. The console output of WebLogic seems to show that my mapping are correct: INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation] onto handler 'chooseOperationController' INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation.*] onto handler 'chooseOperationController' INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation/] onto handler 'chooseOperationController' Here is the ChooseOperationController: @Controller @SessionAttributes("leaveRequestForm") public class ChooseOperationController implements PageIfc, AttributeIfc { @RequestMapping(value = "/chooseOperation") @ModelAttribute("leaveRequestForm") public LeaveRequest setUpLeaveRequestForm( @RequestParam(NAME_ATTRIBUTE) String name) { LeaveRequest form = populateFormFromDatabase(name); return form; } // helper methods omited } I welcome any advice, particularly "generic" techniques for debugging such mapping problems. BTW, I've also tried to "redirect" to the desired page, but got the same result. servlet-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure --> <!-- Enables the Spring MVC @Controller programming model --> <annotation-driven /> <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory --> <resources mapping="/resources/**" location="/resources/" /> <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory --> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> <context:component-scan base-package="com.engilitycorp.leavetracker" /> <beans:bean id="leaveRequestForm" class="com.engilitycorp.leavetracker.model.LeaveRequest" /> </beans:beans> The constants: String LOGIN_FAILURE_PAGE = "loginFailure"; String LOGIN_PAGE = "login"; String CHOOSE_OPERATION_PAGE = "chooseOperation";

  Read the article

• Make a view to be the primary one in navigation controller?

  - by Earl Grey

  I am using a tabbar, each tab having a navigation controller, and this in turn having a stack of views. Each view is having its own view controller but this is not important now. Lets have a tab 1 with a navigation controller 1 with views A, B, C. The nature of the application dictates however that the view B is the primary one. So what I want is that by default (after first or after relaunch of the app), when I tap the tab 1, I will see the B view together with the back button to A view. How can I achieve this?

  Read the article

• Return only the new database items since last check in Rails

  - by Smith

  I'm fairly new to Ruby, and currently trying to implement an AJAX style commenting system. When the user views a topic, all the current comments on that topic will be displayed. The user can post a comment on the page of a topic and it should automatically display without having to refresh the page, along with any new comments that have been posted since the last comment currently displayed to the user. The comments should also automatically refresh at a specified frequency. I currently have the following code: views/idea/view.html.erb <%= periodically_call_remote(:update => "div_chat", :frequency => 1, :position => "top", :url => {:controller => "comment", :action => :test_view, :idea_id => @idea.id } ) %> <div id="div_chat"> </div> views/comment/test_view.html.erb <% @comments.each do |c| %><div id="comment"> <%= c.comment %> </div> <% end %> controllers/comment_controller.rb class CommentController < ApplicationController before_filter :start_defs def add_comment @comment = Comment.new params[:comment] if @comment.save flash[:notice] = "Successfully commented." else flash[:notice] = "UnSuccessfully commented." end end def test_render @comments = Comment.find_all_by_idea_id(params[:idea_id], :order => "created_at DESC", :conditions => ["created_at > ?", @latest_time] ) @latest = Comment.find(:first, :order => "created_at DESC") @latest_time = @latest.created_at end def start_defs @latest = Comment.find(:first, :order => "created_at ASC") @latest_time = @latest.created_at end end The problem is that every time periodically_call_remote makes a call, it returns the entire list of comments for that topic. From what I can tell, the @latest_time gets constantly reset to the earliest created_at, rather than staying updated to the latest created_at after the comments have been retrieved. I'm also not sure how I should directly refresh the comments when a comment is posted. Is it possible to force a call to periodically_call_remote on a successful save?

  Read the article

• The best way to display data in a table view?

  - by LawVS

  Hey guys, I'm trying to display nutritional information in a table view but am struggling about the best way to show the info. I don't want to create unique views for each page as that would take up a lot of space. My ideal avenue would be like a website having links to data pages instead of individual views for each page. How would I best implement that? For example, I would want the first page to be a list of restaurants, then as you press the restaurant it would list the different types of food...the next page would be a list of those foods and then the final page would be the nutrition info itself. Thanks

  Read the article

• Allow for modular development while still running in same JVM?

  - by Marcus

  Our current app runs in a single JVM. We are now splitting up the app into separate logical services where each service runs in its own JVM. The split is being done to allow a single service to be modified and deployed without impacting the entire system. This reduces the need to QA the entire system - just need to QA the interaction with the service being changed. For inter service communication we use a combination of REST, an MQ system bus, and database views. What I don't like about this: REST means we have to marshal data to/from XML DB views couple the systems together which defeats the whole concept of separate services MQ / system bus is added complexity There is inevitably some code duplication between services You have set up n JBoss server configurations, we have to do n number of deployments, n number of set up scripts, etc, etc. Is there a better way to structure an internal application to allow modular development and deployment while allowing the app to run in a single JVM (and achieving the associated benefits)?

  Read the article

• Returning user data for forms that have errors in when using ModelForms

  - by Sevenearths

  forms.py from django.forms import ModelForm from client.models import ClientDetails, ClientAddress, ClientPhone from snippets.UKPhoneNumberForm import UKPhoneNumberField class ClientDetailsForm(ModelForm): class Meta: model = ClientDetails class ClientAddressForm(ModelForm): class Meta: model = ClientAddress class ClientPhoneForm(ModelForm): number = UKPhoneNumberField() class Meta: model = ClientPhone views.py from django.shortcuts import render_to_response, redirect from django.template import RequestContext from client.forms import ClientDetailsForm, ClientAddressForm, ClientPhoneForm def new_client_view(request): formDetails = ClientDetailsForm(initial={'marital_status':'u'}) formAddress = ClientAddressForm() formHomePhone = ClientPhoneForm(initial={'phone_type':'home'}) formWorkPhone = ClientPhoneForm(initial={'phone_type':'work'}) formMobilePhone = ClientPhoneForm(initial={'phone_type':'mobi'}) return render_to_response('client/new_client.html', {'formDetails': formDetails, 'formAddress': formAddress, 'formHomePhone': formHomePhone, 'formWorkPhone': formWorkPhone, 'formMobilePhone': formMobilePhone}, context_instance=RequestContext(request)) (the new_client.html is nothing special) How should I write views.py so that if the user's data raises an error, instead of showing them the form again with the errors in but none of their original data, it shows them the form again with the errors AND their original data?

  Read the article

• ActionBarSherlock + ViewPager caching more then just prev/next view

  - by miroslavign

  on the page: onCreate called for two tabs each time one tab is selected there is explained how the ABS(actually ViewPager) is working in order for ViewPager to be able to do a scrolling. It is clear that at least a prev/next page need all to be created at the same time. Would it be possible to "cache" more than just prev/next Views(Fragments), in a way: I am on Page 1 and there I have a network call to fetch some data(doing this in Activity, not in Fragment - btw. is this OK?) switch to Page 2, and then switch to Page 3, and then switch to Page 1 = Here my page is recreated (using some caching though, BUT, I do not need any recreation if possible) So, it would be nice to cache all the pages. How to accomplish this If possible in current version (4), or this would be some new feature? Or even better question, how to postpond/disable destroying of views?

  Read the article

• Referencing View directory in asp.net mvc

  - by ooo

  i have some html files as part of a regular website that has been ported over to asp.net mvc. In my code i need to read and write these html files and stick them in a tinymce editor To be able to read and write this file from disk in the past i had a hard coded path but this doesn't seem to work in asp.net mvc unless i do something like this: Writing: string _urlDirectory = @"c:\hosting\MySite\Views\Members\newsletters\test.html"; System.IO.File.WriteAllText(_urlDirectory, htmlData_); Reading: string url = @"c:\hosting\MySite\Views\Members\newsletters\test.html"; var req = WebRequest.Create(url); var response = req.GetResponse(); StreamReader sr = new StreamReader(response.GetResponseStream()); string htmlData_ = sr.ReadToEnd(); i am moving my site from one data center to another and the directory structure is changing. instead of just changing the hard coded path to another hard coded path i wanted to see if there was a more relative way to reference these files.

  Read the article

• Rails: render a partial from a plugin

  - by Sam

  I'm getting a missing template error after I try rendering a partial from a plugin. I have included the files with the following: %w{ models controllers helpers views }.each do |dir| path = File.join(File.dirname(__FILE__), 'app', dir) $LOAD_PATH << path ActiveSupport::Dependencies.load_paths << path ActiveSupport::Dependencies.load_once_paths.delete(path) end The Models are getting loaded, but as for other things I'm not sure what's going on. The helpers are not getting loaded too because I just copied the contents of the partial from the plugin instead of the render :partial = and then it came up with a helper error. Question is how to be able to :render :partial = from the views folder in my plugin

  Read the article

• iphone: Accessing Code for Elements Created in Interface Builder

  - by user362685

  I am attempting to create a basic tab-bar application using interface builder. I create a new project in Xcode selecting tab bar application. My question is how can I access the code that instantiates and pushes each of the views when the tab bar buttons are pressed? I would imagine that would be done by the tab bar controller, however when I write the class file from interface builder (filewrite class files), it just creates a blank generic TabBarController.h/TabBarController.m without the methods for pushing each of the views associated with the tab bar elements. I ask this because I would like to pass each view controller a reference to the data model when they are instantiated. Any help would be greatly appreciated, thanks.

  Read the article

• How to import data from a Lotus private view into Access?

  - by PowerUser

  I'm experimenting with Lotus private views for the first time and I finally made a private view that (more or less) has the data I want. I just need to get it into MS Access. If this was a standard shared view, I'd just fire up the ODBC administrator, and make a DSN to the database using the NotesSQL driver. Been there, done that. But you can't get to private views that way. So, how do I import the data from my private view into Access? (Also, I'm not one of the IT gurus in our company, so I can't just make a view and share it, even if it's hidden)

  Read the article

< Previous Page | 77 78 79 80 81 82 83 84 85 86 87 88  | Next Page >