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  • Sunrise / set calculations

    - by dassouki
    I'm trying to calculate the sunset / rise times using python based on the link provided below. My results done through excel and python do not match the real values. Any ideas on what I could be doing wrong? My Excel sheet can be found under .. http://transpotools.com/sun_time.xls # Created on 2010-03-28 # @author: dassouki # @source: [http://williams.best.vwh.net/sunrise_sunset_algorithm.htm][2] # @summary: this is based on the Nautical Almanac Office, United States Naval # Observatory. import math, sys class TimeOfDay(object): def calculate_time(self, in_day, in_month, in_year, lat, long, is_rise, utc_time_zone): # is_rise is a bool when it's true it indicates rise, # and if it's false it indicates setting time #set Zenith zenith = 96 # offical = 90 degrees 50' # civil = 96 degrees # nautical = 102 degrees # astronomical = 108 degrees #1- calculate the day of year n1 = math.floor( 275 * in_month / 9 ) n2 = math.floor( ( in_month + 9 ) / 12 ) n3 = ( 1 + math.floor( in_year - 4 * math.floor( in_year / 4 ) + 2 ) / 3 ) new_day = n1 - ( n2 * n3 ) + in_day - 30 print "new_day ", new_day #2- calculate rising / setting time if is_rise: rise_or_set_time = new_day + ( ( 6 - ( long / 15 ) ) / 24 ) else: rise_or_set_time = new_day + ( ( 18 - ( long/ 15 ) ) / 24 ) print "rise / set", rise_or_set_time #3- calculate sun mean anamoly sun_mean_anomaly = ( 0.9856 * rise_or_set_time ) - 3.289 print "sun mean anomaly", sun_mean_anomaly #4 calculate true longitude true_long = ( sun_mean_anomaly + ( 1.916 * math.sin( math.radians( sun_mean_anomaly ) ) ) + ( 0.020 * math.sin( 2 * math.radians( sun_mean_anomaly ) ) ) + 282.634 ) print "true long ", true_long # make sure true_long is within 0, 360 if true_long < 0: true_long = true_long + 360 elif true_long > 360: true_long = true_long - 360 else: true_long print "true long (360 if) ", true_long #5 calculate s_r_a (sun_right_ascenstion) s_r_a = math.degrees( math.atan( 0.91764 * math.tan( math.radians( true_long ) ) ) ) print "s_r_a is ", s_r_a #make sure it's between 0 and 360 if s_r_a < 0: s_r_a = s_r_a + 360 elif true_long > 360: s_r_a = s_r_a - 360 else: s_r_a print "s_r_a (modified) is ", s_r_a # s_r_a has to be in the same Quadrant as true_long true_long_quad = ( math.floor( true_long / 90 ) ) * 90 s_r_a_quad = ( math.floor( s_r_a / 90 ) ) * 90 s_r_a = s_r_a + ( true_long_quad - s_r_a_quad ) print "s_r_a (quadrant) is ", s_r_a # convert s_r_a to hours s_r_a = s_r_a / 15 print "s_r_a (to hours) is ", s_r_a #6- calculate sun diclanation in terms of cos and sin sin_declanation = 0.39782 * math.sin( math.radians ( true_long ) ) cos_declanation = math.cos( math.asin( sin_declanation ) ) print " sin/cos declanations ", sin_declanation, ", ", cos_declanation # sun local hour cos_hour = ( math.cos( math.radians( zenith ) ) - ( sin_declanation * math.sin( math.radians ( lat ) ) ) / ( cos_declanation * math.cos( math.radians ( lat ) ) ) ) print "cos_hour ", cos_hour # extreme north / south if cos_hour > 1: print "Sun Never Rises at this location on this date, exiting" # sys.exit() elif cos_hour < -1: print "Sun Never Sets at this location on this date, exiting" # sys.exit() print "cos_hour (2)", cos_hour #7- sun/set local time calculations if is_rise: sun_local_hour = ( 360 - math.degrees(math.acos( cos_hour ) ) ) / 15 else: sun_local_hour = math.degrees( math.acos( cos_hour ) ) / 15 print "sun local hour ", sun_local_hour sun_event_time = sun_local_hour + s_r_a - ( 0.06571 * rise_or_set_time ) - 6.622 print "sun event time ", sun_event_time #final result time_in_utc = sun_event_time - ( long / 15 ) + utc_time_zone return time_in_utc #test through main def main(): print "Time of day App " # test: fredericton, NB # answer: 7:34 am long = 66.6 lat = -45.9 utc_time = -4 d = 3 m = 3 y = 2010 is_rise = True tod = TimeOfDay() print "TOD is ", tod.calculate_time(d, m, y, lat, long, is_rise, utc_time) if __name__ == "__main__": main()

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  • How to transport an XML fragment in an XML Document

    - by mrwayne
    Hi, I'm using an AJAX system on a web application, and for one of the objects i return, it needs to contain an xml fragment. Unfortunately, being AJAX, i'm sending the values back via XML already. So, at the moment, i have something that looks like this (ignoring the fact the tags arent perfect. <Transport> <Message> <Content><[CDATA...] XML Content in here </Cdata></Content> </Message> </Transport> This has worked pretty well for the last few years, however, now the XML content itself needs to contain its own CDATA tags and its causing me grief because you cannot nest CDATA sections. Is there another way to encode the 'XML Content' internally?

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  • extract a specific part from a html document , php cURL , php, preg_match

    - by user331071
    Hello ! I'm trying to extract some information from a webpage using php cURL+preg_match or any other function but for some reasons it doesn't work at all . For example from this page http://www.foxtons.co.uk/search?location_ids=1001-29&property_id=712128&search_form=map&search_type=LL&submit_type=search I want to extract the title which is "4 bed house to rent, Caroline Place, Bayswater, W2", the price which is "2,300" and the description which starts at "This fantastic..." and ends at "(Circle and District Lines). " I tried to use php cURL + dom but I'm getting a lot of errors like this "htmlParseEntityRef: expecting ';' in Entity, line: 243" and no result displayed Also I tried to use preg_match or preg_match_all but doesn't work either . A very basic example would be highly appreciated ! thank you !

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  • RDLC: How to print multiple tables in one report

    - by Eduardo Molteni
    I'm generating the RDLC XML schema and showing the report in the ReportViewer control. No problems there. Now, I want a report with 2 tables, with 2 differents dataset. Something like this gets generated: <Body> <ReportItems> <Table Name="Table1"> .... </Table> <Table Name="Table2"> .... </Table> </ReportItems> </Body> But, when printed, both tables start from the top, printing one table over the other (not nice) Is there a way to tell that Table2 should start after Table1? Update: I've tried with List with a fake DataSource, but it does not work.

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  • iTextSharp: Writing RTF in a PDF document

    - by gllort
    Hello, I'm using iTextSharp (with C# and VS2008) to generate a report from a database table row. Generate PDF is not a problem... but when I try to add RTF text into the PDF I cant't find a way into iTextSharp object structure. How can I do it? Thanks a lot!

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  • Why doesn't this method print its text? (java)

    - by David
    here's the method: public static int chooseStrat () { String[] strats = new String[1] ; strats[0] = "0 - Blob" ; int n ; boolean a = false ; while (a == false) ; { System.out.println ("Which strategy should the AI use?(#)") ; printArrayS (strats) ; n = getInt () ; System.out.println ("you selected "+n+"."+" are you sure you want the computer to use the "+ strats[n]+ " ?(Y/N)") ; String c = getIns () ; while ((((!( (c.equals ("y")) || (c.equals ("Y")) )) && (!( (c.equals ("n")) || (c.equals ("N")) ) ) ))) ; { System.out.println ("try again") ; c = getIns () ; } if ( (c.equals ("Y")) || (c.equals ("y")) ) a = true ; } return n ; } When i run this it never prints "Which strategy should the AI use?(#)" it just tries to get an entry from the keyboard. why does it do this?

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  • XML transform element appearing in wrong place in document

    - by Mike
    I am having some problems with an XML transform and need some help. The stylesheet should iterate through all suffix elements and place the contents without the suffix tag next to the last text node within its first ancestor quote-block element (see desired ouput). It works when only a single suffix is present, but not when 2 are present, when 2 are present it places both suffixes next to each other in the last text node of the first quote-block. Any ideas? I have tried limiting the selections to ancestor::quote-block[1] in various places but that doesn't have the desired effect. Source XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> <suffix>(Emphasis added.)</suffix> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”</para> </item> </list> <suffix>(emphasis in original)</suffix> </quote-block> </para> </paragraph> Stylesheet <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://xml.sm.com/schema/cases/report" xmlns:sm="http://xml.sm.com/functions" xmlns:saxon="http://saxon.sf.net/" xpath-default-namespace="http://sm.com/schema/cases/report" exclude-result-prefixes="xs sm" version="2.0"> <xsl:output method="xml" indent="no"/> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Process the quote block --> <xsl:template name="process-quote-block"> <xsl:variable name="quoteBlockCopy"> <xsl:copy-of select="."/> </xsl:variable> <xsl:apply-templates select="$quoteBlockCopy" mode="append-suffix"> <xsl:with-param name="suffix" select="sm:get-suffix-note(.)"/> <xsl:with-param name="end-node" select="sm:get-last-text-node($quoteBlockCopy)"/> </xsl:apply-templates> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix][ancestor::*:quote-block[1]]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- This will match all elements. Just copy and pass through the parameters. --> <xsl:template match="*" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates mode="append-suffix"> <xsl:with-param name="suffix" select="$suffix"/> <xsl:with-param name="end-node" select="$end-node"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <!-- Apply the text node to the content. If the node is equal to the last node then append the descendants of suffix --> <xsl:template match="text()[normalize-space() != '']" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:choose> <xsl:when test="count(. | $end-node) = 1"> <xsl:value-of select="."/> <xsl:apply-templates select="$suffix"/> </xsl:when> <xsl:otherwise> <!-- Or maybe neither. --> <xsl:value-of select="."/> </xsl:otherwise> </xsl:choose> </xsl:template> <!-- Dont copy suffix as --> <xsl:template match="*:suffix" mode="append-suffix"/> <xsl:function name="sm:get-suffix-note"> <xsl:param name="node"/> <xsl:sequence select="$node/descendant::*:suffix/node()"/> </xsl:function> <xsl:function name="sm:get-last-text-node"> <!-- Finds last non-empty text() node, ignoring <suffix> elements that are a child of this specific quote-block. --> <xsl:param name="node"/> <xsl:sequence select="reverse($node//text()[not(ancestor::*:suffix) and normalize-space() != ''])[1]"/> </xsl:function> </xsl:stylesheet> Current Output XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(Emphasis added.)(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph> Desired Ouput <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’(Emphasis added.)</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph>

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  • Close PrintPreviewDialog when ESC is pressed

    - by Emerick Rogul
    I'm working on a WinForms application that uses System.Windows.Forms.PrintPreviewDialog to display a Print Preview dialog. When the user presses ESC in that dialog, I'd like to close the dialog. Unfortunately, I can't figure out how to do this. I've tried to install a KeyDown/PreviewKeyDown event handler, but it never gets called. I also tried setting focus to the dialog (and to its PrintPreviewControl), thinking that was the issue, but that didn't help either. Does anyone have any idea how to make this work?

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  • Send ESC commands to a printer in C#

    - by Ewerton
    My application needs to print invoices, then a get the invoice from database, insert informations os the invoice in a big string (tellling the line, column, etc). after this a have the string ready to be sent to a printer. My problem is: I need to put some ESC/P commands/characters in my big string i try to do something like this: char formFeed = (char)12; Convert.ToChar(12); MyBigString.Insert(10, formFeed); whit this, the line 10 will do a FormFeed, but this not work NOTE: i send the MybigString all at once to printer. to make my code works i need to send the data line by line to a printer ? Thanks for the helps. PS: Sorry my English, i'am a Brazilian developer which dont speak English (yet).

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  • how to print map value in gdb

    - by Davit Siradeghyan
    Hi all I have a std::map< std::string, std::string cont; I want to see cont[ "some_key" ] in gdb. When I'm trying p cont[ "some_ket" ] I'm getting this message: One of the arguments you tried to pass to operator[] could not be converted to what the function wants. I'm using GNU gdb Red Hat Linux (6.3.0.0-1.162.el4rh). Thanks

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  • PHP Object as XML Document

    - by Sam McAfee
    What is the best way to take a given PHP object and serialize it as XML? I am looking at simple_xml and I have used it to parse XML into objects, but it isn't clear to me how it works the other way around.

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  • How to print labels on both sides of a rangebar in WinForms MS Chart using C#

    - by Meera
    How can i add labels for each and every yvalue in series of a rangebarchart ? You all know that for plotting rangebartype series ,we need two yvalues as yvalue[0] and yvalue[1] .Here I need to add data labels to each of those yvalues( which means both at yvalue[0] and yvalue[1]).how can i implement that?can anybody suggest me?please!! The label should look like as below for a rangebar(to be displayed on both sides of a rangebar). Label1 ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦ Label2 Label¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦ Label

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  • VB.NET add an element to the XML document with LINQ to XML

    - by Bayonian
    Hi, I'm adding an element to existing XML doc with the following code: Dim theXMLSource As String = Server.MapPath("~/Demo/") & "LabDemo.xml" Dim nodeElement As XElement Dim attrAndValue As XElement = _ <LabService> <ServiceType> <%= txtServiceType.Text.Trim %> </ServiceType> <Level> <%= txtLevel.Text.Trim %> </Level> </LabService> nodeElement.Add(New XElement(attrAndValue)) nodeElement.Save(theXMLSource) It makes error like this: System.NullReferenceException: Object reference not set to an instance of an object. Object reference not set to an instance of an object. Error line: nodeElement.Add(New XElement(attrAndValue)) I debugged it but I couldn't get the error yet. Can you show what the problem is? Thank you

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  • Replace Placeholders in word document with c#

    - by Xelluloid
    Hi there, I have a template in word (.docx) format and want to replace some placeholders in this template with my own data, do you know where I can find the right classes for this project? It would be nice for me to know the namespace. Are there any newer classes for handling word documents in the docx format (xml) than the com classes? Thank you for all your answers, I hope someone can help me with my problem. greets Sebastian

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  • SQL Function that calculates Shift from StartTime and EndTime

    - by Gentis
    Hello Folks I have been trying to get a function going that calculates what Shift the Employees worked from their StartTime and EndTime. Here is the code i have so far, there seems to be calculating the shift wrong. Shift 1 from 08:00:00 - 16:30:00 Shift 2 from 16:00:00 - 00:30:00 Shift 3 from 00:00:00 - 08:30:00 Also the shift with most hours wins for times between shifts. Thanks, G `FUNCTION [dbo].[ShiftDifferential] ( @StartTime time(0), @EndTime time(0) ) RETURNS int AS BEGIN --DECLARE @StartTime time(0) --DECLARE @EndTime time(0) -- Declare the return variable here DECLARE @Shift1StartTime time(0) DECLARE @Shift2StartTime time(0) DECLARE @Shift3StartTime time(0) DECLARE @Shift1EndTime time(0) DECLARE @Shift2EndTime time(0) DECLARE @Shift3EndTime time(0) DECLARE @HrsShift1 decimal(18,2) DECLARE @HrsShift2 decimal(18,2) DECLARE @HrsShift3 decimal(18,2) DECLARE @ShiftDiff int --SET @StartTime = '09:00:00' --SET @EndTime = '13:00:00' SET @Shift1StartTime = '08:00:00' SET @Shift2StartTime = '16:00:00' SET @Shift3StartTime = '00:00:00' SET @Shift1EndTime = '16:30:00' SET @Shift2EndTime = '00:30:00' SET @Shift3EndTime = '08:30:00' --SELECT DATEDIFF(HH, @Shift1StartTime, @EndTime) -- hours are between shift 3 and shift 1 if DATEDIFF(HH, @Shift1StartTime, @StartTime) < 0 AND (DATEDIFF(hh, @Shift1StartTime, @EndTime) < 8.0 AND DATEDIFF(hh, @Shift1StartTime, @EndTime) 0) begin --PRINT 'Shift 3-1 step1' SET @HrsShift3 = DATEDIFF(HH, @StartTime, @Shift1StartTime) SET @HrsShift1 = DATEDIFF(HH, @Shift1StartTime, @Endtime) --PRINT @HrsShift3 --PRINT @HrsShift1 -- get shift with most hours if @HrsShift3 @HrsShift1 begin SET @ShiftDiff = 3 end else begin SET @ShiftDiff = 1 end end -- hours are in shift 1 if (DATEDIFF(HH, @Shift1StartTime, @StartTime) = 0 AND DATEDIFF(HH, @Shift1StartTime, @EndTime) <= 8) OR (DATEDIFF(HH, @Shift1StartTime, @StartTime) 0 AND DATEDIFF(HH, @Shift1StartTime, @EndTime) <= 8) begin --PRINT 'Shift 1 step2' SET @HrsShift3 = 0 SET @HrsShift1 = DATEDIFF(HH, @StartTime, @EndTime) --PRINT @HrsShift3 --PRINT @HrsShift1 -- only one shift with hours SET @ShiftDiff = 1 end -- hours are between shift 1 and shift 2 if DATEDIFF(HH, @Shift2StartTime, @StartTime) < 0 and (DATEDIFF(HH, @Shift2StartTime, @EndTime) < 8.0 AND DATEDIFF(HH, @Shift2StartTime, @EndTime) 0) begin --PRINT 'Shift 1-2 step1' SET @HrsShift1 = DATEDIFF(HH, @StartTime, @Shift2StartTime) SET @HrsShift2 = DATEDIFF(HH, @Shift2StartTime, @Endtime) --PRINT @HrsShift1 --PRINT @HrsShift2 -- get the shift with most hours if @HrsShift1 @HrsShift2 begin SET @ShiftDiff = 1 end else begin SET @ShiftDiff = 2 end end -- hours are in shift 2 if (DATEDIFF(HH, @Shift2StartTime, @StartTime) = 0 AND DATEDIFF(HH, @Shift2StartTime, @EndTime) <= 8) OR (DATEDIFF(HH, @Shift2StartTime, @StartTime) 0 AND DATEDIFF(HH, @Shift2StartTime, @EndTime) <= 8) begin --PRINT 'Shift 2 step2' SET @HrsShift3 = 0 SET @HrsShift1 = DATEDIFF(HH, @StartTime, @EndTime) --PRINT @HrsShift3 --PRINT @HrsShift1 -- only one shift with hours SET @ShiftDiff = 2 end -- hours are between shift 2 and shift 3 - overnight shift if DATEDIFF(HH, @StartTime, @EndTime) < 0 begin --PRINT 'Shift 2-3 step1' SET @HrsShift2 = DATEDIFF(HH, @StartTime, '23:59:59') + DATEDIFF(HH, '00:00:00', '00:30:00') SET @HrsShift3 = DATEDIFF(HH, '00:30:00', @EndTime) --PRINT @HrsShift2 --PRINT @HrsShift3 -- get the shift with most hours if @HrsShift2 @HrsShift3 begin SET @ShiftDiff = 2 end else begin SET @ShiftDiff = 3 end end -- hours are in shift 3 if (DATEDIFF(HH, @Shift3StartTime, @StartTime) = 0 AND DATEDIFF(HH, @Shift3StartTime, @EndTime) <= 8) OR (DATEDIFF(HH, @Shift3StartTime, @StartTime) 0 AND DATEDIFF(HH, @Shift3StartTime, @EndTime) <= 8) begin --PRINT 'Shift 3 step2' SET @HrsShift2 = 0 SET @HrsShift3 = DATEDIFF(HH, @StartTime, @EndTime) --PRINT @HrsShift2 --PRINT @HrsShift3 -- only one shift with hours SET @ShiftDiff = 3 end RETURN @ShiftDiff; END`

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  • select & print multiple value from dropdown list

    - by sandy
    hi , in this code how can selected multiple value from dropdown list <?php include ("connect.php"); $member_id = intval($_POST['sector_list']); if($member_id == 0) { // Default choice was selected } else { $res = mysql_query("SELECT * FROM members WHERE MemberID = $member_id LIMIT 1"); if(mysql_num_rows($res) == 0) { // Not a valid member } else { // The member is in the database } } ?> <form method="post" action=""> <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard" multiple="multiple"> <option value="0">send to</option> <?php $result = mysql_query('SELECT * from members') or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['MemberID'] . '">' . $row['MemberName']. '</option>'; } ?> </select> </form> assume the drop down list contain on (a,s,d,f,g,h,j,) users selects multiple value ( a,s,j) output = a,s,j not only j ???

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  • how to print std::map value in gdb

    - by Davit Siradeghyan
    Hi all I have a std::map< std::string, std::string cont; I want to see cont[ "some_key" ] in gdb. When I'm trying p cont[ "some_ket" ] I'm getting this message: One of the arguments you tried to pass to operator[] could not be converted to what the function wants. I'm using GNU gdb Red Hat Linux (6.3.0.0-1.162.el4rh). Thanks

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  • Format XML with JAXB during unmarshal

    - by Tobiask
    Hi there, I want to format a XML document during unmarshal with JAXB. Unmarshal looks like: Unmarshaller u = createAndsetUpUnmarshaller(enableValidation, evtHandler, clazz); return u.unmarshal(new ByteArrayInputStream(stringSource.getBytes())); While marshaling one can format the code via: marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); But this isn´t possible for the unmarchal process... Any idea how I can format the XML string with JAXB during (or after) unmarshal process? BTW: I read some posts here about pretty print, but I want to do it with JAXB!

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  • How to implement RSA-CBC?(I have uploaded the request document)

    - by tq0fqeu
    I don't konw more about cipher, I just want to implement RSA-CBC which maybe mean that the result of RSA encrypt in CBC mode, and I have implemented RSA. any code languages will be ok, java will be appreciated thx I copy the request as follow(maybe has spelling wrong), but that's French I don't konw that: Pr´esentation du mini-projet Le but du mini-projet est d’impl´ementer une version ´el´ementaire du chi?rement d’un bloc par RSA et d’inclure cette primitive dans un systeme de chi?rement par bloc avec chaˆinage de blocs et IV (Initial Vector ) al´eatoire. Dans ce systeme, un texte clair (`a chi?rer) est d´ecompos´e en blocs de taille t (?x´ee par l’utilisa- teur), chaque bloc (clair) est chi?r´e par RSA en un bloc crypt´e de mˆeme taille, puis le cryptogramme associ´e au texte clair initial est obtenu en chaˆinant les blocs crypt´es par la m´ethode CBC (cipher- block chaining) d´ecrite dans le cours (voir poly “Block Ciphers”) Votre programme devra demander a l’utilisateur la taille t, puis, apres g´en´eration des cl´es publique et priv´ee, lui proposer de chi?rer ou d´echi?rer un (court) ?chier ASCII. Il est indispensable que votre programme soit au moins capable de traiter le cas (tres peu r´ealiste du point de vue de la s´ecurit´e) t = 32. Pour les traiter des blocs plus grands, il vous faudra impl´ementer des routines d’arithm´etique multi-pr´ecision ; pour cela, je vous conseille de faire appela des bibliotheques libres comme GMP (GNU Multiprecision Library). Pour la g´en´eration al´eatoire des nombres premiers p et q, vous pouvez ´egalement faire appela des bibliotheques sp´ecialis´ees,a condition de me donner toutes les pr´ecisions n´ecessaires. Vous devez m’envoyer (avant une date qui reste a ?xer)a mon adresse ´electronique ([email protected]) un courriel (sujet : [MI1-crypto] : devoir, corps du message : les noms des ´etudiants ayant travaill´e sur le mini-projet) auquel sera attach´e un dossier compress´e regroupant vos sources C ou Java comment´ees, votre programme ex´ecutable, et un ?chier texte ou PDF donnant toutes les pr´ecisions sur les biblioth`eques utilis´ees, vos choix algorithmiques et d’impl´ementation, et les raisons de ces choix (complexit´e algorithmique, robus- tesse, facilit´e d’impl´ementation, etc.). Vous pouvez travailler en binˆome ou en trinˆome, mais je serai nettement plus exigeant avec les trinˆomes I have uploaded the request at http://uploading.com/files/22emmm6b/enonce_projet.pdf/ thx

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