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  • Using Google's Contacts API's, how can I get the user's name and gmail address?

    - by chris
    I know how to get the entire contacts list using Google Contacts API (I get a session token and use Google's Zend package for PHP). But how can I get the person's name and email address? Currently, the Contacts API just seems to give all of the contacts. I'm not sure how to distinguish which email and name out of that list corresponds to the user's account. Is there an easy way to get the user's full name and email address? Any help would be useful. Thanks!

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  • OrderBy on children in a LINQ Query

    - by eka808
    Hello everybody I have a user entity who contains a one to many relationship with a role entity So with this linq expression : from user in USER_TABLE.Include("USERROLE_TABLE") order by user.Name select user I can get users with related roles as a child. My problem is that i want to get roles of each user ordered alphabetically. How can i do that ? I googled a lot and don't find anything Thank's by advance !

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  • zend one controller many views

    - by Sherif
    hi there when i build my web site it was handling only one interface but now i need to handle many interface i can detect which site to communicate and isolate it from other sites but i stuck with this : all the sites have the same views ... is there are a way so i can rander from the same controller different views .. something like application application controller model site_1_view site_2_view is this possible ??!!

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  • Entityframework duplicate record on second insert

    - by Delysid
    I am building an application for recipe/meal planning, and i have come across a problem i cant seem to figure out. i have a table for units of measure, where i keep the used units in, i only want unique units in here (for grocery list calculation and so forth) but if i use a unit from the table on a recipe, the first time it is okay, nothing is inserted in units of measure, but the second time i get a "duplicate". i suspect it has something to do with entitykey, because the primary key is identity column on the sql server (2008 r2) for some reason it works to change the objectstate on some objects (courses, see code) and that does not generate a duplicate, but that does not work on the unit of measure my insert methods looks like this : public recipe Create(recipe recipe) { using (RecipeDataContext ctx = new RecipeDataContext()) { foreach (recipe_ingredient rec_ing in recipe.recipe_ingredient) { if (rec_ing.ingredient.ingredient_id == 0) { ingredient ing = (from _ing in ctx.ingredients where _ing.name == rec_ing.ingredient.name select _ing).FirstOrDefault(); if (ing != null) { rec_ing.ingredient_id = ing.ingredient_id; rec_ing.ingredient = null; } } if (rec_ing.unit_of_measure.unit_of_measure_id == 0) { unit_of_measure _uom = (from dbUom in ctx.unit_of_measure where dbUom.unit == rec_ing.unit_of_measure.unit select dbUom).FirstOrDefault(); if (_uom != null) { rec_ing.unit_of_measure_id = _uom.unit_of_measure_id; rec_ing.unit_of_measure = null; } } ctx.Recipes.AddObject(recipe); //for some reason it works to change object state of this, and not generate a duplicate ctx.ObjectStateManager.ChangeObjectState(recipe.courses[0], EntityState.Unchanged); } ctx.SaveChanges(); } return recipe; } My datamodel looks like this : http://i.imgur.com/NMwZv.png

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  • symfony 2.0 stable enough to use?

    - by fayer
    i wonder if symfony 2.0 is stable enough to use? cause i never used symfony before. it seems that symfony 2 is much more better than the previous version and i dont want to relearn/recode everything some months from now. when do you think symfony 2.0 will be released? will it be a wise choice to use 2.0 now?

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  • ZendFramework Zend_Form_Element_File setDestination vs rename filter

    - by bibstha
    The code says Zend_Form_element_File::setDestination() is depricated and to use the rename filter. However the rename filter is currently codes such that when path is set, only temporary name is given. Original filename is lost. <?php $file = new Zend_Form_Element_File(); $file->setDestination('/var/www/project/public'); ?> vs <?php $file = new Zend_Form_Element_File(); $file->addFilter('Rename', array('target' => '/var/www/project/public')); ?> Any solution to upload files so that it preserves original filename structure but checks for existing file and appends _1.ext or _2.ext?

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  • How can I use Tier Pricing with Configurable Products? (Magento 1.4+)

    - by Rad The Mad
    How can I use/setup Tier Pricing with Configurable Products? (Magento 1.4+) There was an extension to do this but I think it is only for Magento 1.3. Tried to setup tiers in my Simple Products, but those do not show up, or do not activate when I add to cart from my Config Product page. Any help is appreciated! Thanks. Edit: In my case, I would like to use the Tier Pricing FROM the Simple Product. and not use the Tier Pricing from the Config. Product

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  • Linq Having Sum(Quantity) = x?

    - by molgan
    Hello I have a function that returns IQueryable, and I would like to add "HAVING SUM(Quantity) = X" to it, but I get error if I try like this: _rep.GetBookings().ByBookingObjectID(bookingObjectID).Sum(x => x.Quantity == somevariablehere); I cant seem to find functions for it to find by sum /M

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  • Defining a function to a Row

    - by Siedrix
    Hi, im making an application and i need to implement diferent level of user permits. I coul have the function $this->view->users->hasPermits($this->view->user); By declaring a function on the model, an things could be easy to implement. But i would like to be able to have the next function doing the same: $this->view->user->hasPermits(); Is there a way to do this? do i need to extend the Zend_Db_Table_Row class? any ideas?

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  • EF code first error "The specified index already exists. [ IX_Id ]" for object tree

    - by PascalN
    Using EF code first 4.3 I'm trying to model an object tree with a required-required relationships and a required-optional relationships. Here is a simple representation of those classes public class Top { public int Id { get; set; } public virtual Middle Middle { get; set; } } public class Middle { public int Id { get; set; } public virtual Child Child { get; set; } } public class Child { public int Id { get; set; } } Here is the OnModelCreating code modelBuilder.Entity<Top>().HasRequired(t => t.Middle).WithRequiredPrincipal().WillCascadeOnDelete(); modelBuilder.Entity<Middle>().HasRequired(t => t.Child).WithOptional().WillCascadeOnDelete(); This produces the error "The specified index already exists. [ IX_Id ]" on SQLCE After checking the db schema, both model binder fluent API configuration lines create an index IX_Id on the table Middles. Does anyone know how to work around that problem? Is there a way to set the index name? Thank you! Pascal

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  • ETA on Smart Device Projects for Visual Studio 2010

    - by Vaccano
    I really want to upgrade to Visual Studio 2010. But since I do a lot of development for the Pocket PC version of Windows Mobile I cannot. (I develop for a Symbol device that does not support Windows Phone 7, so that is not a option.) Does any one know any kind of time frame of when Microsoft plans to add support for Smart Device Projects into Visual Studio 2010

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  • how to add multiple modules to a single page in digitalus

    - by jspeshu
    when i do some thing like this i can see the module <div id='search' class="module"> <digitalusControl type='moduleSelector' id='module' label="searchM" group='mods' /> </div> but i want to have two modules so i make something like this <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulesearch' label="searchM" group='mods' /> </div> <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulenews' label="newsM" group='mods' /> </div> plz help how can i create multiple modules since i can't create another element "digitalusControl" with id "module" i really need this plz help EDIT: even worse a template with only one module, this single line is not working for me

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  • trying to show a variable in my layout

    - by user1400
    hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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  • Using Zend_Db and multiple tables

    - by Yacoby
    I have a normalized database that stores locations of files on the internet. A file may have multiple locations spread across different sites. I am storing the urls in two parts (Site.UrlStart, FileLocation.UrlEnd). The UrlEnd is the part unique to that file (for the site). Simplified Db structure: I am using Zend_Db as my ORM (If it is that), with classes for the tables inheriting from Zend_Db_Table_Abstract. The issue is that retrieving the location data (e.g. the url) requires the use of multiple tables and as far as I can make out and I would either have to use both table classes (thereby exposing my table structure) or scatter sql all over my application, neither of which sound appealing. The only solution I can see is to create a façade that acts like Zend_Db_Table_Abstract (Maybe inherits from it?) and hides the fact that the data is actually on two tables. My questions are as follows: Am I going in the right direction in creating a façade class (Are there other alternatives)? Should the facade class inherit from Zend_Db_Table_Abstract?

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  • Zend_Controller_Router_Route_Chain more routes - more problems

    - by epmspec
    When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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  • insert with many to many relationship

    - by Luca Romagnoli
    hi, i have 2 object: user, group that have a relationship many to many i want create a user and associate some groups to it. How can i do it? thanks I've tried with this. but it's wrong: user = new User(); List<int> gruppi = new List<int>() {1,2}; utente.Group =db.Group.Where(p => gruppi.Contains(p.GruppoID)

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • EF4 querying through the generations

    - by Hans Kesting
    I have a model withs Parents, Children and Grandchildren, in a many-to-many relationship. Using this article I created POCO classes that work fine, except for one thing I can't yet figure out. When I query the Parents or Children directly using LINQ, the SQL reflects the LINQ query (a .Count() executes a COUNT in the database and so on) - fine. The Parent class has a Children property, to access it's children. But (and now for the problem) this doesn't expose an IQueryable interface but an ICollection. So when I access the Children property on a particular parent all the Parent's Children are read. Even worse, when I access the Grandchildren (theParent.Children.SelectMany(child => child.GrandChildren).Count()) then for each and every child a separate request is issued to select it's grandchildren. Changing the type of the Children property from ICollection to IQueryable doesn't solve this. Apart from missing needed methods like Add() and Remove(), EF just doesn't recognize the property then. Are there correct ways (as in: low database interaction) of querying through children (and what are they)? Or is this just not possible?

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  • Trying to understand the Zend_Auth OpenId

    - by Will Olbrys
    I'm using a slightly modified version of the Zend_Auth_OpenId classes to get openid logins from google apps. The results are very positive, as I seem to be getting successful results from Google. I cannot get successful results passed to Zend_Auth, though. For example, Zend_Auth_Adapter_OpenId on line 241: if (!$consumer->login($id, $this->_returnTo, $this->_root, $this->_extensions, $this->_response)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $consumer->getError())); } The consumer calls login() which in turn calls the private method _checkId() in Zend_OpenId_Consumer. _checkId() always ends in redirecting to the openid server. How is this ever supposed to return a valid Zend_Auth_Result object? I'm pretty close to giving up and trying to implement another OpenId library, but I'm so close to just making this work. I must be missing something so obvious! Maybe I don't understand how openid works exactly, but if someone could help me understand I would really appreciate it.

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  • Why newly created entity object with navigation property is automaticly added to ObjectContext?

    - by Levelbit
    I have to entities: Company and Location (one to many). When I create new Location entity object and assign navigation property(Company) with the navigation property of already existing Location object (Location _new = new Location(); _new.Company = _old.Company). It seems that at that point newly created object is added to Object Context automatically, because when I call SaveChanges method that object is insert to database although I didn't call ObjectContext.AddObject(_new). I'm new in EF so there is probably reason why I have result like this? Is there need to assign also CompanyReference filed too and how to do it? IDaoFactory daoFactory = new DaoFactory(); ILocationDao locaitonDao = daoFactory.GetLocationDao(); IEnumerable<Location> locations = locaitonDao.GetLocations(); Location _old = locations.First(); Location _new = new Location(); _new.LocationName = _old.LocationName; _new.Company = _old.Company;// 1 _new.Address = _old.Address; //... ContactEntities.SaveChanges();//2 If I execute line (1) instantly _new object is added to object context and I can see additional datarow in my datagrid after line (2) is executed.

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  • EF4 (CPT5) ForeignKeyAttribute in base class - Assert Failure entityType != null

    - by Anthony Johnston
    Getting an error when trying to set a ForeignKeyAttribute in a base class class User{} abstract class FruitBase{ [ForeignKey("CreateById")] public User CreateBy{ get; set; } public int CreateById{ get; set; } } class Banana{} class DataContext : DbContext{ DbSet<Banana> Bananas{ get; set; } } If I move the FruitBase code into the banana, all is well, but I don't want to, as there will be many many fruit and I want to remain relatively DRY if I can Is this a know issue that will be fixed by March? Does anyone know a work around?

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  • What to set the scalar type to contain a byte []. Entity in MVC2

    - by Brad8118
    I'm trying out the EF 4.0 and using the Model first approach. I'd like to store images into the database and I'm not sure of the best type for the scalar in the entity. I currently have it(the image scalar type) setup as a binary. From what I have been reading the best way to store the image in the db is a byte[]. So I'm assuming that binary is the way to go. If there is a better way I'd switch. In my controller I have: //file from client to store in the db HttpPostedFileBase file = Request.Files[inputTagName]; if (file.ContentLength > 0) { keyToAdd.Image = new byte[file.ContentLength]; file.InputStream.Write(keyToAdd.Image, 0, file.ContentLength); } This builds fine but when I run it I get an exception writing the stream to keyToAdd.Image. The exception is something like: Method does not exist. Any ideas? Note that when using a EF 4.0 model first approach I only have int16, int32, double, string, decimal, binary, byte, DateTime, Double, Single, and SByte as available types. Thanks

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