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  • how to call array values based on the main id they linked to?

    - by veronica george
    In page one, $add_id2=implode(',',$add_id); //result is 1,4 $item_type2=implode(',',$item_type_2); //result is 8,16 $final_total2=implode(',',$final); //result is 150,430 I pass these values via URL to the page two and store them in session. $_SESSION['cart'][$car]= array ('car'=>$car, 'loc_1'=>$location, array ( 'addon_id'=>$a_id, 'item_type'=>$item_type2, 'final_total'=>$final_t ) ); I call them like this, foreach($_SESSION['cart'] as $cart=>$things) { //display main array value like car id and location id echo $cart; foreach($things as $thing_1=>$thing_2) { foreach($thing_2['addon_id'] as $thi_2=>$thi_4) { //to display addons item for the car id //this is the id for each addon under the above car //echo $thi_2; //this is to echo addon id $thi_4; } } } The above loop works . the addon items array loops through inside main array which is car. If there were two addon items chosen then the addon array will loop twice. Now al I need to do is, How to make $item_type2 and $final_total2 display the value according to the addon id? PS: Same addon items can be chosen multiple times. They are identified uniquely by id(//echo $thi_2;). Thanks.

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  • php explode() delimiter issue

    - by mumis2012
    I am new to php so this may be a simple fix. I have a text file named 'textt.txt' that looks like this: South East asia,2222,code1 winter break,3333,code2 my php code looks like this: <?php $x = file_get_contents('textt.txt'); $y = explode("\r\n", $x); $z = $y[0]; echo $z; ?> the outcome of this is: South East asia,2222,code1 I would like it to return only: South East Asia. How can I make this happen? Thanks!

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  • C# assign values of array to separate variables in one line

    - by Sarah Vessels
    Can I assign each value in an array to separate variables in one line in C#? Here's an example in Ruby code of what I want: irb(main):001:0> str1, str2 = ["hey", "now"] => ["hey", "now"] irb(main):002:0> str1 => "hey" irb(main):003:0> str2 => "now" I'm not sure if what I'm wanting is possible in C#. Edit: for those suggesting I just assign the strings "hey" and "now" to variables, that's not what I want. Imagine the following: irb(main):004:0> val1, val2 = get_two_values() => ["hey", "now"] irb(main):005:0> val1 => "hey" irb(main):006:0> val2 => "now" Now the fact that the method get_two_values returned strings "hey" and "now" is arbitrary. In fact it could return any two values, they don't even have to be strings.

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  • Simple Array in java

    - by user1311590
    I need to create the following in my main method. Create an array of size 100 doubles. write a loop to sotr the number 150.0 - 249.0 in the 100 location. public class Lab6_2 { public static void main(String[] args) { double[] values; values = new double [100]; double i = 0; for(double i = 150.0; i<249.0;i++){ System.out.println(values[99]); } } }

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  • How can I initialize a 2d array in Perl?

    - by Mark
    How do I initialize a 2d array in perl? I am trying the following code: 0 use strict; 10 my @frame_events = (((1) x 10), ((1) x 10)); 20 print "$frame_events[1][1]\n"; but it gives the following error: Can't use string ("1") as an ARRAY ref while "strict refs" in use at ./dyn_pf.pl line 20. This syntax only seems to initialize a 1d array as print "$frame_events[1]\n" works. Though perl doesn't give any error during the assignment.

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  • Array Related Doubt.......

    - by AGeek
    I have the following program........... int insert(int *array, int arraySize, int newElement) { array[arraySize + 1] = newElement; return (arraySize+1); // Return new Array size...... } int main() { int array[] = {1,2,3,4,5}; int arraySize = sizeof(array) / sizeof(int); insertInArray(array, arraySize,6); print(array); } I am trying to work out this program in C programming language... But when i print the array after insertion,,, it doesn't prints the desired output which is needed.. Please correct me if i am doing something wrong..... Thanks..

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  • Dynamic Array of Objects Sans Vector Class

    - by Connor Black
    I am doing a homework assignment for my summer OO class and we need to write two classes. One is called Sale and the other is called Register. I've written my Sale class; here's the .h file: enum ItemType {BOOK, DVD, SOFTWARE, CREDIT}; class Sale { public: Sale(); // default constructor, // sets numerical member data to 0 void MakeSale(ItemType x, double amt); ItemType Item(); // Returns the type of item in the sale double Price(); // Returns the price of the sale double Tax(); // Returns the amount of tax on the sale double Total(); // Returns the total price of the sale void Display(); // outputs sale info private: double price; // price of item or amount of credit double tax; // amount of sales tax double total; // final price once tax is added in. ItemType item; // transaction type }; For the Register class we need to include a dynamic array of Sale objects in our member data. We cannot use the vector class. How is this done? Here's my 'Register' '.h' class Register{ public: Register(int ident, int amount); ~Register(); int GetID(){return identification;} int GetAmount(){return amountMoney;} void RingUpSale(ItemType item, int basePrice); void ShowLast(); void ShowAll(); void Cancel(); int SalesTax(int n); private: int identification; int amountMoney; };

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  • How to move positions within an array?

    - by Jade Mulholland
    A program that simply moves array elements. Two variables: userInputVariable and blankSpaceVariable. I have a 2D array named table. Defined as table[userInputVariable + 1][6] I am printing out this array in a table format, and the far left column is numbered by whatever number the user entered at the beginning of the program. I then ask the user where they would like to enter a blank space within the array. This blank space acts like a divider for all the other information in the array. For example, if the user enters 10 at the start for the userInputVariable, and then enters 5 for the blank space. Once printed, the numbers should go like this: 1, 2, 3, 4, --, 5, 6, 7, 8, 9, 10. My plan has been to create a for loop and try to move all the numbers in the array back a position starting from the blank space variable. What I currently have, but does not work: for (int i = blankSpaceVariable; i < table.length - 1; i++) { table[i] = table[i + 1]; } table[blankSpaceVariable] = "--"; With my current code, the numbers go like this: 1, 2, 3, 4, 6, 7, 8, 9, 10 Tried completing this a few different ways also, but the other info within my 2D array didn't move with the numbers. So I thought that this approach can hopefully move all the info within my 2D array down, and make way for a blank section. All help is greatly appreciated!

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  • Sorting an array based on its value

    - by MaxerDude
    I have an Array, Sample: $array { [0] { [something]=1; [something2]=2; } [1] { [something]=2; [something2]=4; } [2] { [something]=5; [something2]=2; } } I want to order the array based on the key something; So it will look like: $array { [0] { [something]=5; [something2]=2; } [1] { [something]=2; [something2]=4; } [2] { [something]=1; [something2]=2; } }

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  • Extreamely fast way to clone the values of an array into a second array?

    - by George
    I am currently working on an application that is responsible for calculating random permutations of a multidemensional array. Currently the bulk of the time in the application is spent copying the array in each iteration (1 million iterations total). On my current system, the entire process takes 50 seconds to complete, 39 of those seconds spent cloning the array. My array cloning routine is the following: public static int[][] CopyArray(this int[][] source) { int[][] destination = new int[source.Length][]; // For each Row for (int y = 0; y < source.Length; y++) { // Initialize Array destination[y] = new int[source[y].Length]; // For each Column for (int x = 0; x < destination[y].Length; x++) { destination[y][x] = source[y][x]; } } return destination; } Is there any way, safe or unsafe, to achieve the same effect as above, much faster?

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  • function.array-diff problems!

    - by SKY
    Hi, im currently getting these error on my site: Warning: array_keys() [function.array-keys]: The first argument should be an array on line 43 Warning: Invalid argument supplied for foreach() on line 44 Warning: array_diff() [function.array-diff]: Argument #1 is not an array on line 47 Warning: array_diff() [function.array-diff]: Argument #1 is not an array on line 48 And the source are: 42. $tmp = $this->network->get_user_follows($this->user->id); 43. $tmp = array_keys($tmp->followers); 44. foreach($tmp as &$v) { $v = intval($v); } 45. $tmp2 = array_keys($this->network->get_group_members($g->id)); 46. foreach($tmp2 as &$v) { $v = intval($v); } 47. $tmp = array_diff($tmp, $tmp2); 48. $tmp = array_diff($tmp, array(intval($this->user->id))); I want to know what is the problem and how i fix it. Thanks!

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  • : for displaying all elements in a multidimensional array in python 3.1.

    - by Leif Andersen
    I have a multidimensional array in python like: arr = [['foo', 1], ['bar',2]] Now, if I want to print out everything in the array, I could do: print(arr[:][:]) Or I could also just do print(arr). However, If I only wanted to print out the first element of each box (for arr, that would be 'foo', 'bar'), I would imagine I would do something like: print(arr[:][0]) however, that just prints out the first data blog (['foo', 1]), also, I tried reversing it (just in case): print(arr[0][:]) and I got the same thing. So, is there anyway that I can get it to print the first element in each tuple (other than: for tuple in arr: print(tuple[0]) )? Thanks.

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  • Perl array and hash manipulation using map

    - by somebody
    I have the following test code use Data::Dumper; my $hash = { foo => 'bar', os => 'linux' }; my @keys = qw (foo os); my $extra = 'test'; my @final_array = (map {$hash->{$_}} @keys,$extra); print Dumper \@final_array; The output is $VAR1 = [ 'bar', 'linux', undef ]; Shouldn't the elements be "bar, linux, test"? Why is the last element undefined and how do I insert an element into @final_array? I know I can use the push function but is there a way to insert it on the same line as using the map command? Basically the manipulated array is meant to be used in an SQL command in the actual script and I want to avoid using extra variables before that and instead do something like: $sql->execute(map {$hash->{$_}} @keys,$extra);

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  • php transform array into multidim array

    - by fverswijver
    So I'm working on a website with Doctrine as ORM and I get the following array back as a result: Array ( [0] => Array ( [c_cat_id] => 1 [c_title] => Programas e projetos [p_menu] => PBA BR 163 [p_page_id] => 1 ) [1] => Array ( [c_cat_id] => 1 [c_title] => Programas e projetos [p_menu] => Outros projetos [p_page_id] => 3 ) ) Is it possible to transform this array (in PHP) to something like this: Array ( [0] => Array ( [c_cat_id] => 1 [c_title] => Programas e projetos [pages] => Array ([p_page_id] => 1 [p_menu] => PBA BR 163, [p_page_id] => 3 [p_menu] => Outros projetos)) Thanks for your help, always eager to learn new ways of doing things and that's why I love StackOverflow ;)

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  • why doesnt this program print?

    - by Alex
    What I'm trying to do is to print my two-dimensional array but i'm lost. The first function is running perfect, the problem is the second or maybe the way I'm passing it to the "Print" function. #include <stdio.h> #include <stdlib.h> #define ROW 2 #define COL 2 //Memory allocation and values input void func(int **arr) { int i, j; arr = (int**)calloc(ROW,sizeof(int*)); for(i=0; i < ROW; i++) arr[i] = (int*)calloc(COL,sizeof(int)); printf("Input: \n"); for(i=0; i<ROW; i++) for(j=0; j<COL; j++) scanf_s("%d", &arr[i][j]); } //This is where the problem begins or maybe it's in the main void print(int **arr) { int i, j; for(i=0; i<ROW; i++) { for(j=0; j<COL; j++) printf("%5d", arr[i][j]); printf("\n"); } } void main() { int *arr; func(&arr); print(&arr); //maybe I'm not passing the arr right ? }

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  • php weird bug where an array is not an array !

    - by iko
    I've been going mad trying to figure out why an array would not be an array in php. For a reason I can't understand I have a bug in a smarty class. The code is this : $compiled_tags = array(); for ($i = 0, $for_max = count($template_tags); $i < $for_max; $i++) { $this->_current_line_no += substr_count($text_blocks[$i], "\n"); // I tried array push instead to see // bug is here array_push($compiled_tags,$this->_compile_tag($template_tags[$i])); //$compiled_tags[] = $this->_compile_tag($template_tags[$i]); $this->_current_line_no += substr_count($template_tags[$i], "\n"); } the error message is Warning: array_push() expects parameter 1 to be array, integer given in .... OR before with [] Warning: Cannot use a scalar value as an array in .... I trying a var_debug on $compiled_tags and as soon I enter the for loop is not an array anymore but an integer. I tried renaming the variable, but same problem. I'm sure is something simple that I missed but I can't figure it out. Any help is (as always) welcomed !

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  • dreferencing 2 d array

    - by ashish-sangwan
    Please look at this peice of code :- #include<stdio.h> int main() { int arr[2][2]={1,2,3,4}; printf("%d %u %u",**arr,*arr,arr); return 0; } When i compiled and executed this program i got same value for arr and *arr which is the starting address of the 2 d array. For example:- 1 3214506 3214506 My question is why does dereferencing arr ( *arr ) does not print the value stored at the address contained in arr ?

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  • Can I assign array size using NSMutableArray?

    - by Tattat
    I used to be a Java Programmer, which the array need to declare the very first time, like this: int[] anArray; // declares an array of integers anArray = new int[10]; // allocates memory for 10 integers I don't know whether the Objective C , NSMutableArray also give me this ability or not. Actually, I want to make a 10*10 array. thz in advance.

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  • Storing database records into array

    - by zerey
    I would want to create an array that will hold records retrieved from a database using a query of SELECT statement. The records to be retrieved have multiple fields such as lastname, firstname, mi and 20 more fields. What would be the best approach on coding this function? alright i have followed what prisoner have given below.. the next question is how do i search through this kind of array using queries? for example i want to search for a username..

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  • how to make this piece of code work in C++?

    - by cambr
    #include<stdio.h> void print(int *arr[], int s1, int s2) { int i, j; printf("\n"); for(i = 0; i<s1; i++) { for(j = 0; j<s2; j++) { printf("%d, ", *((arr+i)+j)); } } printf("\n"); } int main() { int a[4][4] = {{0}}; print(a,4,4); } This works in C, but not in C++. error: cannot convert `int (*)[4]' to `int**' for argument `1' to `void print(int**, int, int)' Why does it not work in C++? What change is needed to be made?

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  • Extracting the most duplicate value from an array in JavaScript (with jQuery)

    - by TK
    I have several array to deal with. I need to extract the most duplicate value from each array. From [3, 7, 7, 7], I need to find the value 7. Each array size is 4. For now, I don't have to think about when the most duplicate values are more than one such as [3, 7, 7, 7]. All the values are a number. I looked around the web. I found several ways to make an array to become uniq(). But I haven't found a way to get the duplicate value. I am using jQuery, but raw JavaScript is fine for this task.

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  • C Program not running as intended, hangs after input

    - by user41419
    The program I am writing to take a number and display that number as a calculator would display it (shown below) is compiling with no issues, but when I try to run it, I am able to input my number, but nothing happens. It seems like it is "hanging", since no further output is shown as I would have expected. Might anyone know what the problem is? #include <stdio.h> #define MAX_DIGITS 20 char segments[10][7] = /* seven segment array */ {{'1','1','1','1','1','1','0'}, /* zero */ {'0','1','1','0','0','0','0'}, /* one */ {'1','1','0','1','1','0','1'}, /* two */ {'1','1','1','1','0','0','1'}, /* three */ {'0','1','1','0','0','1','1'}, /* four */ {'1','0','1','1','0','1','1'}, /* five */ {'1','0','1','1','1','1','1'}, /* six */ {'1','1','1','0','0','0','0'}, /* seven */ {'1','1','1','1','1','1','1'}, /* eight */ {'1','1','1','0','0','1','1'}};/* nine */ char digits[3][MAX_DIGITS * 4]; /* digits array */ int i, j; /* count variables */ int adjust; /* output formatting */ int main(void) { clear_digits_array(); int digit[20]; for (i = 0; i < 20; i++) { digit[i] = 0; } int count = 20; int position = 0; printf("Enter a number: "); int number = scanf("%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d", &digit[0], &digit[1], &digit[2], &digit[3], &digit[4], &digit[5], &digit[6], &digit[7], &digit[8], &digit[9], &digit[10], &digit[11], &digit[12], &digit[13], &digit[14], &digit[15], &digit[16], &digit[17], &digit[18], &digit[19]); //NOTHING HAPPENS AFTER HERE printf("Got input, number is %d", number); while (count > 0) { printf("Reading digits, count is %d", count); process_digit(digit[20 - count], position); position++; count--; } print_digits_array(); printf("\n"); return 0; } void clear_digits_array(void) { /* fill all positions in digits array with blank spaces */ for (i = 0; i < 3; i++) { for (j = 0; j < (MAX_DIGITS * 4); j++) { digits[i][j] = ' '; } } } void process_digit(int digit, int position) { /* check each segment to see if segment should be filled in for given digit */ for (i = 0; i < 7; i++) { printf("Processing digit %d at position %d, i is %d", digit, position, i); if (segments[digit][i] == 1) { switch (i) { case 0: digits[0][(position * 4) + 1] = '_'; break; case 1: digits[1][(position * 4) + 2] = '|'; break; case 2: digits[2][(position * 4) + 2] = '|'; break; case 3: digits[2][(position * 4) + 1] = '_'; break; case 4: digits[2][(position * 4) + 0] = '|'; break; case 5: digits[1][(position * 4) + 0] = '|'; break; case 6: digits[1][(position * 4) + 1] = '_'; break; } } } } void print_digits_array(void) { /* print each character in digits array */ for (i = 0; i < 3; i++) { for (j = 0; j < (MAX_DIGITS * 4); j++) { printf("%c", digits[i][j]); } printf("/n"); } }

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  • VB 2008 - Index was outside the bounds of the array

    - by Jan
    Hey guys I'm having a problem while reading a config.cfg file of my program. I can read the 23. char of the file but I can't read the 24. char (last char in file). This is the code: Dim CFGReader2 As System.IO.StreamReader CFGReader2 = _ My.Computer.FileSystem.OpenTextFileReader(CurDir() & "\Config.cfg") Dim Server(2) As String Server(0) = CFGReader2.ReadToEnd.Chars(23)//This part works If Server(0) = 0 Then Server(1) = CFGReader2.ReadToEnd.Chars(24)//This part results in "Index was outside the bounds of the array". ElseIf Server(0) = 1 Then Server(2) = CFGReader2.ReadToEnd.Chars(24)//This part results in "Index was outside the bounds of the array". Server(1) = 10 + Server(2) ElseIf Server(0) = 2 Then Server(2) = CFGReader2.ReadToEnd.Chars(24)//This part results in "Index was outside the bounds of the array". Server(1) = 20 + Server(2) ElseIf Server(0) = 3 Then Server(2) = CFGReader2.ReadToEnd.Chars(24)//This part results in "Index was outside the bounds of the array". Server(1) = 30 + Server(2) End If And this is the file: Language = 2 Server = 11 Thanks for the answer! Frosty

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