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  • How to find full module path of a class to import in other file

    - by Pooya
    I have method that returns module path of given class name def findModulePath(path, className): attributes = [] for root, dirs, files in os.walk(path): for source in (s for s in files if s.endswith(".py")): name = os.path.splitext(os.path.basename(source))[0] full_name = os.path.splitext(source)[0].replace(os.path.sep, '.') m = imp.load_module(full_name, *imp.find_module(name, [root])) try: attr = getattr(m, className) attributes.append(attr) except: pass if len(attributes) <= 0: raise Exception, "Class %s not found" % className for element in attributes: print "%s.%s" % (element.__module__, className) but it does not return the full path of the module, For example I have a python file named "objectmodel" in objects package,and it contains a Model class, So I call findModulePath(MyProjectPath,"Model"). it prints objectmodel.Model but I need objects.objectmodel.Model

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  • Error with swig: undefined symbol: _ZN7hosters11hostersLink7getLinkEi

    - by Eduardo
    I'm trying to make a python binding for the this library: http://code.google.com/p/hosterslib/. I'm using swig, heres is the code: %module pyhosters %{ include "hosters/hosters.hpp" %} %include "hosters/hosters.hpp" I run "swig -c++ -python -o swig_wrap.cxx swig.i" and I compile with "g++ -O2 -fPIC -shared -o _pyhosters.so swig_wrap.cxx python-config --libs --cflags -lhosters -lcln -lhtmlcxx pkg-config libglog --libs --cflags -I/usr/include/python2.6 -Wall -Wextra" But when I run python and I import it, I get: import pyhosters Traceback (most recent call last): File "", line 1, in File "./pyhosters.py", line 7, in import _pyhosters ImportError: ./_pyhosters.so: undefined symbol: _ZN7hosters11hostersLink7getLinkEi How can I solve that? Thanks.

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  • Why is django.test.client.Client not keeping me logged in.

    - by Mystic
    I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

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  • changing the saved contents of the model , edit model fileds once saved

    - by imran-glt
    hi I have extended the user model and added extra fields to it i.e "latitude" "longitude" and status and than save it. up to here it works fine. but i want to allow the user to change his/her "latitude" "longitude" whenever he/she needs like the hotmail and yahoo allows change account feature. in my case the user only wants to chage the latitude and longitude i tried it in this way but it didnt work. is this the right way to do it ...... or is there any other way to change the saved contents view.py def status_change(request): print "status_change function called" if request.method == "POST": rform = registerForm(data = request.POST) uform = UserForm(data = request.POST) if rform.is_valid(): user = uform.save() register = rform.save() register.user = user register.save() return render_to_response('home.html') else: rform = registerForm() return render_to_response('status_change.html',{'rform':rform})

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  • Launching browser within CherryPy

    - by Alan Harris-Reid
    I have a html page displayed using... cherrypy.quickstart(ShowHTML(htmlfile), config=configfile) Once the page is loaded (eg. initiated via. the command 'python mypage.py'), I would like to automatically launch the browser to display the page (eg. via. http://localhost/8000). Is there any way I can achieve this (eg. via. a hook within CherryPy), or do I have to call-up the browser manually (eg. by double-clicking an icon)? TIA Alan

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  • Can you change/redirect a django form's function by passing in your own function?

    - by Derek
    I'm dealing with django-paypal and want to change the button src images. So I went the the conf.py file in the source and edited the src destination. However, I really want to leave the source alone, and I noticed that the class PayPalPaymentsForm(forms.Form): has def get_image(self): return { (True, self.SUBSCRIBE): SUBSCRIPTION_SANDBOX_IMAGE, (True, self.BUY): SANDBOX_IMAGE, (True, self.DONATE): DONATION_SANDBOX_IMAGE, (False, self.SUBSCRIBE): SUBSCRIPTION_IMAGE, (False, self.BUY): IMAGE, (False, self.DONATE): DONATION_IMAGE, }[TEST, self.button_type] which handles all the image src destinations. Since changing this def in the source is worse than changing conf, I was wondering if there was a way to pass in customized defs you make like passing in initial arguments in forms? This way no source code is changed, and I can customize the get_image def as much as I need. passing in def something like this? def get_image(self): .... .... paypal = { 'amount': 10, 'item_name': 'test1', 'item_number': 'test1_slug', # PayPal wants a unique invoice ID 'invoice': str(uuid.uuid4()), } form = PayPalPaymentsForm(initial=paypal, get_image) Thanks!

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  • How do I modify gitstats to only utilize a specified file extension for it's statistics?

    - by Fake Code Monkey Rashid
    Hello good people! The website of the statistics generator in question is: http://gitstats.sourceforge.net/ It's git repo can be cloned from: git clone git://repo.or.cz/gitstats.git What I want to do is something like: ./gitstatus --ext=".py" /input/foo /output/bar Failing being able to easily pass the above option without heavy modification, I'd just hardcore the file extentsion I want to be included. However, I'm unsure of the relevant section of code to modify and even if I did no, I'm unsure of how to start such modifications. It's seems like it'd be rather simple but alas...

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  • Problem with sys.argv[1] when unittest module is in a script

    - by chrissygormley
    Hello, I have a script that does various things and access paramenters using sys.argv but when the script gets to the unittest part of the code it says there is no module for this. The script that I have is: class MyScript(): def __init__(self): self.value = sys.argv[1] def hello(self): print self.value def suite(self): modules_to_test = ('external_sanity_onvif', 'starttest') alltests = unittest.TestSuite() for module in map(__import__, modules_to_test): alltests.addTest(unittest.findTestCases(module)) return alltests if __name__ == '__main__': Run = MyScript() Run.hello() log_file = 'log_file.txt' test_file = open(log_file, "w") runner = unittest.TextTestRunner(test_file) unittest.main(defaultTest='Run.suite', testRunner=runner) Say I enter ./script.py Hello in the command line. The error I get is: AttributeError: 'module' object has no attribute 'Hello' If I remove the unittest module it works. Also if I remove the testrunner log and leave it at: unittest.main(defaultTest='Run.suite') This still doesn't work. Can anyone help. Thanks

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  • Django 404 pages not appearing?

    - by AP257
    I want to add a 404 page on my Django site. I've created a template, 404.html, and saved it in the root of my /templates directory. I've also made sure that the from django.conf.urls.defaults import * line is included at the top of urls.py. I've set DEBUG to False. (I've been following these instructions.) However, if I try to go to a page that I know doesn't exist - whether a made-up URL or a view specifically designed to do get_object_or_404 - the 404 page doesn't appear: I just get Chrome's standard 'Oops! This link appears to be broken' page. Oddly, I also have a 500.html template in the same place and that is appearing just fine if I generate a 500 error. What might the problem be?

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  • zeromq installtion on mac os snow leopard

    - by Ashish
    I have installed zeromq 2.1.11 on mac os x using the steps given on http://www.zeromq.org/area:download Then i installed pyzmq (python bindings ) But i get the following error : import zmq Traceback (most recent call last): File "<pyshell#1>", line 1, in <module> import zmq File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/zmq/__init__.py", line 35, in <module> from zmq.utils import initthreads # initialize threads ImportError: dlopen(/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/zmq/utils/initthreads.so, 2): no suitable image found. Did find: /Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/zmq/utils/initthreads.so: no matching architecture in universal wrapper

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  • Passing session data to ModelForm inside of ModelAdmin

    - by theactiveactor
    I'm trying to initialize the form attribute for MyModelAdmin class inside an instance method, as follows: class MyModelAdmin(admin.ModelAdmin): def queryset(self, request): MyModelAdmin.form = MyModelForm(request.user) My goal is to customize the editing form of MyModelForm based on the current session. When I try this however, I keep getting an error (shown below). Is this the proper place to pass session data to ModelForm? If so, then what may be causing this error? TypeError at ... Exception Type: TypeError Exception Value: issubclass() arg 1 must be a class Exception Location: /usr/lib/pymodules/python2.6/django/forms/models.py in new, line 185

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  • libxml2 install error: command 'gcc' failed with exit status 1? What are the dependencies of libxml2

    - by SIA
    Hi everybody!! I am trying to install libxml2 on unbuntu 9.10 and getting errors: $ sudo python setup.py develop Its a very lengthy error message but the last error is Setup script exited with error: Command 'gcc' failed with exit status 1. Can anybody tell me why i am getting this error? What are the dependencies or libraries required to install this? scenario: I am trying to setup the reddit.com clone, and when i run develop command, its generating a huge error as stated above. Please help!! Thanks in advance And my many thanks to Stackoverflow team for having such a life saving site.

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  • Windows equivalent to this Makefile

    - by Sridhar Ratnakumar
    The advantage of writing a Makefile is that "make" is generally assumed to be present on the various Unices (Linux and Mac primarily). Now I have the following Makefile: PYTHON := python all: e installdeps e: virtualenv --distribute --python=${PYTHON} e installdeps: e/bin/python setup.py develop clean: rm -rf e As you can see this Makefile uses simple targets and variable substitution. Can this be achieved on Windows? By that mean - without having to install external tools (like cygwin make); perhaps make.cmd? Typing "make installdeps" for instance, should work both on Unix and Windows.

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  • How to use traceit to report function input variables in stack trace

    - by reckoner
    Hi, I've been using the following code to trace the execution of my programs: import sys import linecache import random def traceit(frame, event, arg): if event == "line": lineno = frame.f_lineno filename = frame.f_globals["__file__"] if filename == "<stdin>": filename = "traceit.py" if (filename.endswith(".pyc") or filename.endswith(".pyo")): filename = filename[:-1] name = frame.f_globals["__name__"] line = linecache.getline(filename, lineno) print "%s:%s:%s: %s" % (name, lineno,frame.f_code.co_name , line.rstrip()) return traceit def main(): print "In main" for i in range(5): print i, random.randrange(0, 10) print "Done." sys.settrace(traceit) main() Using this code, or something like it, is it possible to report the values of certain function arguments? In other words, the above code tells me "which" functions were called and I would like to know "what" the corresponding values of the input variables for those function calls. Thanks in advance.

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  • Django nose to run only project tests

    - by patroqueeet
    I added nose, django-nose, nose-exclude, coverage to my buildout.cfg and ran buildout. Furthermore I added the TEST_RUNNER and the NOSE_ARGS to my settings.py. In the last step I created a exclude_dirs.txt and included it into the NOSE_ARGS. That worked so far. Finally I ran bin/django testto run the tests of my project. I found out that every app inside INSTALLED_APP is run and that even parts of the django core models are run. How can I limit this to my project only without exernal packages?

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  • Can I turn off implicit Python unicode conversions to find my mixed-strings bugs?

    - by Tal Weiss
    When profiling our code I was surprised to find millions of calls to C:\Python26\lib\encodings\utf_8.py:15(decode) I started debugging and found that across our code base there are many small bugs, usually comparing a string to a unicode or adding a sting and a unicode. Python graciously decodes the strings and performs the following operations in unicode. How kind. But expensive! I am fluent in unicode, having read Joel Spolsky and Dive Into Python... I try to keep our code internals in unicode only. My question - can I turn off this pythonic nice-guy behavior? At least until I find all these bugs and fix them (usually by adding a u'u')? Some of them are extremely hard to find (a variable that is sometimes a string...). Python 2.6.5 (and I can't switch to 3.x).

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  • Having my Python package install shortcuts in Start menu

    - by cool-RR
    I'm making a Python package that gets installed with a setup.py file using setuptools. The package includes a GUI, and when it's installed on a Windows machine, I want the installation to make a folder in "Programs" in the start menu, and make a shortcut there to a pyw script that will start the GUI. (The pyw think works on all platforms, right?) On Mac and Linux, I would like it to put this shortcut in whatever Mac and Linux have that is parallel to the start menu. How do I do this?

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  • Django equivalent to paster for backend processes

    - by intractelicious
    I use pylons in my job, but I'm new to django. I'm making an rss filtering application, and so I'd like to have two backend processes that run on a schedule: one to crawl rss feeds for each user, and another to determine relevance of individual posts relative to users' past preferences. In pylons, I'd just write paster commands to update the db with that data. Is there an equivalent in django? EG is there a way to run the equivalent of python manage.py shell in a non-interactive mode?

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  • Symbol not found: _curl_easy_cleanup

    - by Bharadwaj
    I am working on porting a python application to Mac OS X. The application makes use of pycurl and PyCDF. When I run my code, I get this error : > File > "/Library/Python/2.5/site-packages/pycdf/pycdfext.py", > line 5, in <module> > import _pycdfext ImportError: dlopen(/Library/Python/2.5/site-packages/pycdf/_pycdfext.so, > 2): Symbol not found: > _curl_easy_cleanup Referenced from: /Library/Python/2.5/site-packages/pycdf/_pycdfext.so > Expected in: dynamic lookup I tried installing different versions of curl, pycurl with different configs of libcurl. Still stuck Platform : 10.5.8 Curl : 7.19.4 [also tried 7.20.1] Pycurl : 7.19.0 How do I fix this error?

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  • How do I get the path of the current executed file in python?

    - by Sorin Sbarnea
    This may seam a newbie question but it is not. It looks that common approaches are not always working: Currently I know only two options but none of them looks to work an all cases. sys.argv[0] This means using path = os.path.abspath(os.path.dirname(sys.argv[0])) but this does not work if you are running from another python script from another directory, and this can really happen in real life. __file__ this means that path = os.path.abspath(os.path.dirname(__file__)) but I found that this doesn't work: py2exe that doesn't have a __file__ attribute but there is an workaround. when you run from IDLE with execute() there is no __file__ attribute OS X 10.6 where I get NameError: global name '__file__' is not defined Related questions with incomplete answers: http://stackoverflow.com/questions/1296501/python-find-path-to-file-being-run http://stackoverflow.com/questions/1483827/python-path-to-current-file-depends-on-how-i-execute-the-program http://stackoverflow.com/questions/2259503/how-to-know-the-path-of-the-running-script-in-python http://stackoverflow.com/questions/509742/python-chdir-to-dir-the-py-script-is-in

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  • Django colon syntax in template tags: only in newer versions?

    - by Alan
    I just deployed an application to a new server, and although I'm using virtualenv, I had to install a new environment on the production server, which has a different architecture. Anyway, I received no TemplateSytaxErrors in development, but on the production server, I get: Exception Type: TemplateSyntaxError Exception Value: Caught SyntaxError while rendering: invalid syntax (views.py, line 25) The offending line is: {% url admin:password_change as password_change_url %} Upon removing that line, the TemplateSyntaxError hops to the next line that has a colon in it (and lets other template tags work fine). So my question is this: is there some discrepancy in versions of Python/Django that would allow or disallow the namespacing syntax? The template tags are in django-grappelli (http://code.google.com/p/django-grappelli/), so I'd rather not go through their code and rewrite all the template tags. Development server: 32-bit Debian Python 2.5.5 Django 1.2.1 Production server: 64-bit CentOS Python 2.4.3 Django 1.2.1 Any ideas?

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  • urlopen error [errno 111] connection refused

    - by Ui-Gyun Jeong
    I am doing python exercise with a book 'headfirst python' and making android app by using python and sl4a my code is import android import json import time from urllib import urlencode from urllib2 import urlopen hello_msg = "Welcome to Coach Kelly's Timing App" list_title = 'Here is your list of athletes:' quit_msg = "Quitting Coach Kelly's App." web_server = 'http://127.0.0.1:8080' get_names_cgi = '/cgi-bin/generate_name.py' def send_to_server(url, post_data=None): if post_data: page = urlopen(url, urlencode(post_data)) else: page = urlopen(url) return(page.read().decode("utf8")) app = android.Android() def status_update(msg, how_long=2): app.makeToast(msg) time.sleep(how_long) status_update(hello_msg) athlete_names = sorted(json.loads(send_to_server(web_server + get_names_cgi))) app.dialogCreateAlert(list_title) app.dialogSetSingleChoiceItems(athlete_names) app.dialogSetPositiveButtonText('Select') app.dialogSetNegativeButtonText('Quit') app.dialogShow() resp = app.dialogGetResponse().result status_update(quit_msg) this is my code and the result is what is the problem??? I can not figure out what the problem is...

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  • Running "source" from python

    - by R S
    Hello, I have a file a.txt with lines of commands I want to run, say: echo 1 echo 2 echo 3 If I was on csh (unix), I would have done source a.txt and it would run. From python I want to run os.execl with it, however I get: >>> os.execl("source", "a.txt") Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.5/os.py", line 322, in execl execv(file, args) OSError: [Errno 2] No such file or directory How to do it?

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  • Python interpreter invocation with "-c" and indentation issues

    - by alexander
    I'm trying to invoke Python using the "-c" argument to allow me to run some arbitrary python code easily, like this: python.exe -c "for idx in range(10): print idx" Now this code works fine, from within my batch file, however, I'm running into problems when I want to do anything more than this. Consider the following Python code: foo = 'bar' for idx in range(10): print idx this would then give you 0-9 on the stdout. However, if I collapse this into a single line, using semicolons as delimiters, to get the following: foo = 'bar';for idx in range(10): print idx and try to run it using python.exe -c it get a SyntaxError raised: C:\Python>python.exe -c "foo = 'bar';for idx in range(10): print idx" File "<string>", line 1 foo = 'bar';for idx in range(10): print idx ^ SyntaxError: invalid syntax Anyone know how I can actually use this without switching to a separate .py file?

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  • django access to parent

    - by SledgehammerPL
    model: class Product(models.Model): name = models.CharField(max_length = 128) (...) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive And now I'd like to get list of the most often useable products: ReceiptComponent.objects.values('product').annotate(Count('product')).order_by('-product__count' the example result: [{'product': 3, 'product__count': 5}, {'product': 6, 'product__count': 4}, {'product': 5, 'product__count': 3}, {'product': 7, 'product__count': 2}, {'product': 1, 'product__count': 2}, {'product': 11, 'product__count': 1}, {'product': 8, 'product__count': 1}, {'product': 4, 'product__count': 1}, {'product': 9, 'product__count': 1}] It's almost what I need. But I'd prefer having Product object not product value, because I'd like to use this in views.py for generating list.

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