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  • My Java regex isn't capturing the group

    - by Geo
    I'm trying to match the username with a regex. Please don't suggest a split. USERNAME=geo Here's my code: String input = "USERNAME=geo"; Pattern pat = Pattern.compile("USERNAME=(\\w+)"); Matcher mat = pat.matcher(input); if(mat.find()) { System.out.println(mat.group()); } why doesn't it find geo in the group? I noticed that if I use the .group(1), it finds the username. However the group method contains USERNAME=geo. Why?

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  • Get company name in android using new API's

    - by HellBoy
    Currently I am getting company name using following code public class ContactsDemo extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Cursor cursor = getContentResolver().query(Contacts.Organizations.CONTENT_URI, null, null, null, null); //ContactsContract.CommonDataKinds. if(cursor!=null){ System.out.println(cursor.getString(cursor.getColumnIndex (Contacts.Organizations.COMPANY))); }}} but I don't want to use deprected API's. & in new API's there is no CONTENT_URI in Organisation class. How to get company name using new API.

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  • Set intersection of two strings

    - by user1785712
    import java.util.*; class set { public static void main(String args[]) { TreeSet<Character> t1 = new TreeSet<Character>(); TreeSet<Character> t2 = new TreeSet<Character>(); String s1 = "Ambitab bachan"; String s2 = "Ranjikanth"; for(char c1:s1.toCharArray()) t1.add(c1); for(char c2:s2.toCharArray()) t2.add(c2); t2.retainAll(t1); System.out.println(t2); } } this program find the common character in two different string. in this program Treeset is used to store the value and retainAll() method is used to find the common characters. can anybody help me reduce the line of coding.thanks in advance

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  • Execute an external application as root - problem

    - by user598011
    Good morning: I'm trying to run an external application that needs to be executed as root. I have to read the lines from exit after the execution of this application but it says "permission denied", as if the its not been done correctly. I've been thinking over a time and I can not move forward. The code is as follows: process = Runtime.getRuntime().exec("su"); String[] command = {external application command}; process = Runtime.getRuntime().exec(comando); InputStream inputStream = process.getInputStream(); BufferedReader bufferedReader = null; try { bufferedReader = new BufferedReader(new InputStreamReader(inputStream),8192); String line = null; while ((line = bufferedReader.readLine()) != null) { System.out.println("read line:"+line ); } } catch (IOException ioe) { ioe.printStackTrace(); } process.waitFor(); Does anyone know why not let me run the command? Thanks.

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  • retrieving 'nulls' from website using Java URL input stream

    - by Roio
    hi all, i'm trying to read the text from a website using the Java URL input stream as follows - URL u = new URL(str); br3 = new BufferedReader(new InputStreamReader(u.openStream())); while(true) System.out.println(br3.readLine()); this seems to work fine for most websites, but for some url shortening services like linkbee, the object draws a blank. e.g. http://linkbee.com/FUAKF, i can view the source code using an explorer, however i repeatedly get nulls when i use the above code.

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  • jEdit+JythonInterpreter: how to import java class?

    - by JChao
    Hi, I'm running jEdit with the JythonInterprete and I have a .jar file called JavaTest.jar. JavaTest has a class called SampleJavaClass which has a method printerCount. From my .py file, I want to do: from javatest import SampleJavaClass class SampleClass(SampleJavaClass): def pymain(self): SampleJavaClass.printerCount(4) Java code: package javatest; public class SampleJavaClass { public static void printerCount(int i){ for(int j=0; j< i; j++){ System.out.println("hello world"); } } (etc...) In the JythonInterpreter, I have already tried clicking "Edit Jython Path" and adding the .jar file then running the interpreter again, but it still gives me ImportError: cannot import name SampleJavaClass

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  • what (clip) and DataLine.Info represents...?

    - by user528050
    I got this code from one of my friend. import java.io.*; import javax.sound.sampled.*; public class xx { public static void main(String args[]) { try { File f=new File("mm.wav"); AudioInputStream a=AudioSystem.getAudioInputStream(f); AudioFormat au=a.getFormat(); DataLine.Info di=new DataLine.Info(Clip.class,au); Clip c=(Clip)AudioSystem.getLine(di); c.open(a); c.start(); } catch(Exception e) { System.out.println("Exception caught "); } } } But i didn't understand what this line means Cilp c=(Clip)AudioSystem.getLine(di); what (clip) represents....? And my 2nd problem is what is the DataLine is it an interface and what is the meaning of this statement DataLine.Info....?

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  • Image not getting displayed on a JPanel.

    - by Myth17
    class Deal implements ActionListener { public void actionPerformed(ActionEvent e) { dl.setDeck(); dl.shuffle(); dl.firstDraw(pl); for(Card c:pl.showHand()) panelplay.add(new JLabel(c.getImageIcon())); panelplay.validate(); } } This is an event handler for a Jbutton. The method pl.showHand() returns a ArrayList of a user defined class 'Card'. Inserting a println() inside the loop shows the print, so the code is being executed but the Panel panelplay isnt showing card Images.

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  • multitreading scheduling related java

    - by vichi
    class A implements Runnable{ B b=new B(); public void run(){ while(true){ System.out.println("H1"+Thread.currentThread().getName()); } } } public class Test { public static void main(String[] str){ A a1 =new A(); // A a2 =new A(); // Thread t1 =new Thread(a1, "Vichi"); Thread t2 =new Thread(a1,"Vishu"); t1.start(); t2.start(); } } what will be the ans: 1) only one of them will get the chance to execute 2) both will get chance in arbitrary manner please suggest possible ans with explations

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  • how to get values sent by location.replace(URL)

    - by kawtousse
    hi everyone, In my javascript function I do livke this in order to redirect parameters to servlet: var ids1=document.getElementById("projet").value; document.location.href("http://localhost:8080/Opc_Web_App/ServletAffectation?ids1="+ids1); and in the servlet I do the following to get Value: String idprojet= request.getParameter("projet"); System.out.println("le projet selectionné est :" +idprojet); the problem that i didnt have the result of System.out.print in my screen; so in other terms the servlet didn't get the parameter. I can not see the problemn untill now. Please help. Thank you.

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  • why selenium.isConfirmationPresent() returns true after using chooseCancelOnNextConfirmation

    - by padmakumar
    I am having a code like the following selenium.chooseCancelOnNextConfirmation(); selenium.click("deleteRequest");// confirm dialog will be displayed on clicking the button System.out.println("is confirmation present "+selenium.isConfirmationPresent()); Eventhough i am using selenium.chooseCancelOnNextConfirmation(), please let me know why selenium.isConfirmationPresent() returns true. But selenium.isConfirmationPresent() returns false after selenium.getConfirmation(); Is it mandatory to use selenium.getConfirmation(), as i am not able to do further processing. It says com.thoughtworks.selenium.SeleniumException: ERROR: There was an unexpected Confirmation! [Are you sure to delete selected request(s)?] com.thoughtworks.selenium.HttpCommandProcessor.throwAssertionFailureExceptionOrError(HttpCommandProcessor.java:97) at com.thoughtworks.selenium.HttpCommandProcessor.doCommand(HttpCommandProcessor.java:9

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  • How to delete object with a mouse click ?

    - by Meko
    Hi all. I made a simple FlowChat Editor that creates rectangles and triangles and connects them to each other and shows the way from up to down. I can move this elements on screen too. I am now trying to create a button to delete the element which I clicked. There is problem that I can delete MyTriangle objects, but I can't delete MyRectangle objects. It deletes but not object which I clicked. I delete from first object to last. Here is my code: if (deleteObj) { if (rectsList.size() != 0) { for (int i = 0; i < rectsList.size(); i++) { MyRect rect = (MyRect) rectsList.get(i); if (e.getX() <= rect.c.x + 50 && e.getX() >= rect.c.x - 50 && e.getY() <= rect.c.y + 15 && e.getY() >= rect.c.y - 15) { rectsList.remove(rect); System.out.println("This is REctangle DELETED\n"); } } } if (triangleList.size() != 0) { for (int j = 0; j < triangleList.size(); j++) { MyTriangle trian = (MyTriangle) triangleList.get(j); if (e.getX() <= trian.c.x + 20 && e.getX() >= trian.c.x - 20 && e.getY() <= trian.c.y + 20 && e.getY() >= trian.c.y - 20) { triangleList.remove(trian); System.out.println("This is Triangle Deleted\n"); } } } Edit Here MyRectangle and MyTriangle classes public class MyRect extends Ellipse2D.Double { Point c; Point in; Point out; int posX; int posY; int width = 100; int height = 30; int count; public MyRect(Point center, Point input, Point output,int counter) { c = center; in = input; out = output; count=counter; } void drawMe(Graphics g) { // in.x=c.x+20; int posX = c.x; int posY = c.y; int posInX = in.x; int posInY = in.y; int posOutX = out.x; int posOutY = out.y; g.setColor(Color.MAGENTA); g.drawString(" S "+count ,posX-5, posY+5); g.setColor(Color.black); g.drawRect(posX-50, posY-15, width, height); g.setColor(Color.green); g.drawRect(posInX-3, posInY-9, 6, 6); g.setColor(Color.blue); g.drawRect(posOutX-3, posOutY+3, 6, 6); } } public class MyTriangle { Point c; Point in ; Point outYES ; Point outNO ; int posX; int posY; int count; public MyTriangle(Point center,Point input,Point outputYES,Point outputNO,int counter) { c = center; in = input; outYES = outputYES; outNO = outputNO; count=counter; } void drawMe(Graphics g) { int posX = c.x; int posY = c.y; int posInX=in.x; int posInY=in.y; int posOutYESX=outYES.x; int posOutYESY=outYES.y; int posOutNOX=outNO.x; int posOutNOY=outNO.y; int[] xPoints = {posX - 50, posX, posX + 50, posX}; int[] yPoints = {posY, posY - 30, posY, posY + 30}; g.setColor(Color.MAGENTA); g.drawString(" T "+count,posX-5, posY+5); g.setColor(Color.black); g.drawPolygon(xPoints, yPoints, 4); // draw input g.setColor(Color.green); g.drawRect(posInX-3,posInY-9, 6, 6); g.setColor(Color.blue); g.drawRect(posOutYESX-9,posOutYESY-3 , 6, 6); g.setColor(Color.red); g.drawRect(posOutNOX-3,posOutNOY+3 , 6, 6); } }

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  • Send a String[] ArrayList over Socket connection

    - by Duncan Palmer
    So i'm trying to send a String[] Array/List over an open socket connection. I currently have this code: Sending: public void sendData() { try { OutputStream socketStream = socket.getOutputStream(); ObjectOutputStream objectOutput = new ObjectOutputStream(socketStream); objectOutput.writeObject(new String[] {"Test", "Test2", "Test3"}); objectOutput.close(); socketStream.close(); } catch (Exception e) { System.out.println(e.toString()); } } Recieving: public Object readData() { try { InputStream socketStream = socket.getInputStream(); ObjectInputStream objectInput = new ObjectInputStream(new GZIPInputStream(socketStream)); Object a = objectInput.readObject(); return a; } catch(Exception e) { return null; } } After I have recieved the String array/list on the other end I want to be able to iterate through it like I would do normally so I can get the values. My current code doesn't seem to works as it returns null as the value. is this possible?

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  • How to read output of android process command

    - by kevdliu
    I am trying to get the output of android shell command 'getprop' with java since getprop() always returns null no matter what. I tried this from developer.android.com: Process process = null; try { process = new ProcessBuilder() .command("/system/bin/getprop", "build.version") .redirectErrorStream(true) .start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } InputStream in = process.getInputStream(); //String prop = in.toString(); System.out.println(in); process.destroy(); However what is printed is not the output but a bunch of characters and numbers (dont have the exact output right now). How can i get the output of the process? Thanks!

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  • Eclipse bug? Switching on a null with only default case

    - by polygenelubricants
    I was experimenting with enum, and I found that the following compiles and runs fine on Eclipse (Build id: 20090920-1017, not sure exact compiler version): public class SwitchingOnAnull { enum X { ,; } public static void main(String[] args) { X x = null; switch(x) { default: System.out.println("Hello world!"); } } } When compiled and run with Eclipse, this prints "Hello world!" and exits normally. With the javac compiler, this throws a NullPointerException as expected. So is there a bug in Eclipse Java compiler?

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  • How do I restrict accepting only one type in my generic method?

    - by kunjaan
    I have a generic function foo, which accepts any type and prints them out. public static <T> T foo(T... arg) { List<T> foo = Arrays.asList(arg); for (T t : foo) { System.out.println(t); } return null; } How do I make sure that the arguments received are of only 1 type. For example, {1,'a',3} should be invalid. It should either be all numbers or all characters.

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  • Why Timer does not work if we do not generate a window?

    - by Roman
    Here is the code: import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JFrame; import javax.swing.Timer; public class TimerSample { public static void main(String args[]) { new JFrame().setVisible(true); ActionListener actionListener = new ActionListener() { public void actionPerformed(ActionEvent actionEvent) { System.out.println("Hello World Timer"); } }; Timer timer = new Timer(500, actionListener); timer.start(); } } It generates a window and then periodically prints "Hello World Timer" in the terminal (Command Prompt). If I comment this line new JFrame().setVisible(true); the application do not print anything to the command line. Why?

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  • inputMismatchException Java reading doubles from plain text file

    - by user939287
    Using double variable = inputFile.nextDouble(); Gives the mismatch error and I can't figure out why... Anyone know what's up? The input file is just a bunch of doubles like 5.0... Okay here is the code snippet String fileName; Scanner scanner = new Scanner(System.in); System.out.println("\nEnter file name that contains the matrix and vector: "); fileName = scanner.nextLine(); Scanner inputFile = new Scanner(fileName); double a1 = inputFile.nextDouble(); the input file is a plain text document .txt in this format 5.0 4.0 -3.0 4.0 2.0 5.0 6.0 5.0 -2.0 -13.0 4.0 12.0 I don't understand why it wouldn't take those as doubles... As far as what its expecting the format of the file to be... I suppose binary? isn't that the default? I didn't specify in the code...

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  • List files starting with a specific name using java

    - by user3610075
    i want to list files starting with a name like "Report" from a folder. i found this in google to list all files but i don't how to list file starting with a name. Thank you File directory = new File("C:\\Users\\kiki\\Downloads"); File[] files = directory.listFiles(); for (int index = 0; index < files.length; index++) { //Print out the name of files in the directory System.out.println(files[index].toString()); }

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  • Why do I have to give an identifier?

    - by Knowing me knowing you
    In code: try { System.out.print(fromClient.readLine()); } catch(IOException )//LINE 1 { System.err.println("Error while trying to read from Client"); } In code line marked as LINE 1 compiler forces me to give an identifier even though I'm not using it. Why this unnatural constrain? And then if I type an identifier I'm getting warning that identifier isn't used. It just doesn't make sense to me, forcing a programmer to do something unnecesarry and surplus. And after me someone will revise this code and will be wondering if I didn't use this variable on purpouse or I just forgot. So in order to avoid that I have to write additional comment explaining why I do not use variable which is unnecessary in my code. Thanks

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  • How do you send an array as part of an (jquery) ajax request

    - by Ankur
    I tried to send an array as part of an ajax request like this: var query = []; // in between I add some values to 'query' $.ajax({ url: "MyServlet", data: query, dataType: "json", success: function(noOfResults) { alert(noOfResults); } }); } I wanted to see what I get back in the servlet, so I used this line: System.out.println(request.getParameterMap().toString()); Which returned {} suggesting an empty map. Firebug tells me I am getting a 400 bad request error If I send a queryString like attribute=value as the 'data' then everything works fine, so it has to do with not being able to send an array as is. What do I have to do to get that data into the servlet for further processing. I don't want to pull it out and turn it into a queryString in the JS if I can avoid it. EDIT: I used the .serializeArray() (jQuery) function before sending the data. I don't get the 400 but nothing useful is being sent through.

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  • Java: ListA.addAll(ListB) fires NullPointerException?

    - by HH
    The err part is Capitalized in the code, it also comes in foreaching. Because of the abstract list, it cannot be initialized, declaration is in a static field. The lists have the same type. import java.util.*; public class Test { public static final List<String> highPrio = Arrays.asList("*","/"); public static List<String> ops; public static void main(String[] args) { //ERROR HERE, why do it throw nullPointer? ops.addAll(highPrio); for(String s : ops) { System.out.println(s); } } }

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  • How to sort an array by (smallest, largest, second smallest, second, largest) etc?

    - by Binka
    Any ideas? I can sort an array. But not in this pattern? It needs to sort by the pattern I mentioned above. public void wackySort2(int[] nums) { int sign = 0; int temp = 0; int temp2 = 0; for (int i = 0; i < nums.length; i++) { for (int j = 0; j < nums.length - 1; j++) { if (nums[j] > nums[j + 1]) { temp = nums[j]; nums[j] = nums[j + 1]; nums[j + 1] = temp; //sign = 1; System.out.println("Something has been done"); } } } }

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  • Why javabeans framework create the IndexedPropertyDescriptor for the NON index method

    - by George Macus
    I'm not familiar with java beans framework, in the below scenario, I got the IndexedPropertyDescriptor for the method getFooWithX, could someone explain why? public class IntrospectorTest { public static void main(String[] args) throws IntrospectionException { BeanInfo info = Introspector.getBeanInfo(SubClass.class); PropertyDescriptor[] descriptors = info.getPropertyDescriptors(); for (int i = 0; i < descriptors.length; i++) { System.out.println(descriptors[i].getClass().getName() + ":" + descriptors[i].getName()); } } } abstract class BaseClass { public abstract Object getFoo(); } abstract class SubClass extends BaseClass { public Object getFooWithX(int x) { return null; } } and the result will be: java.beans.PropertyDescriptor:class java.beans.PropertyDescriptor:foo java.beans.IndexedPropertyDescriptor:fooWithX Why?

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  • Why doesn't list.get(0).equals(null) work?

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

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