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  • Display problem after deletion in linked list in C

    - by LuckySlevin
    Hi, actually this was another problem but it changed so I decided to open a new question. My code is typedef struct inner_list { int count; char word[100]; inner_list*next; } inner_list; typedef struct outer_list { char word [100]; inner_list * head; int count; outer_list * next; } outer_list; void delnode(outer_list **head,char num[100])//thanks to both Nir Levy and Jeremy P. { outer_list *temp, *m; m=temp=*head; /*FIX #1*/ while(temp!=NULL) { if(strcmp(temp->word,num)==0) { if(temp==*head) { delinner(temp->head); /* FIX#2 */ *head=temp->next; free(temp); return; } else { delinner(temp->head); /* FIX#2 */ m->next=temp->next; free(temp); return; } } else { m=temp; temp= temp->next; } } printf(" ELEMENT %s NOT FOUND ", num); } void delinner(inner_list *head) { /* FIX#2 */ inner_list *temp; temp=head; while(temp!=NULL) { head=temp->next; free(temp); temp=head; } } void delnode2(outer_list *up,inner_list **head,char num[100]) { inner_list *temp2,*temp, *m; outer_list *p; p = up; while(p!=NULL){m=temp=temp2=p->head; while(temp!=NULL) { if(strcmp(temp->word,num)==0) { if(temp==(*head)) { *head=temp->next; free(temp); return; } else { m->next=temp->next; free(temp); return; } } else { m=temp; temp= temp->next; } } p=p->next; } printf(" ELEMENT %s NOT FOUND ", num); } void print_node(outer_list *parent_node) { while(parent_node!=NULL){ printf("%s\t%d\t", parent_node->word, parent_node->count); inner_list *child_node = parent_node->head; printf("list: "); if(child_node ==NULL){printf("BUARADA");} while (child_node != NULL) { printf("%s-%d", child_node->word,child_node->count); child_node = child_node->next; if (child_node != NULL) { printf("->"); } } printf("\n"); parent_node = parent_node->next; } } While deleting an element from outer list I am also trying the delete the same element from inner_list too. For example: - Let's say aaa is an element of outer_list linked list and let's point it with outer_list *p - This aaa can also be in an inner_list linked list too. (it can be in p-head or another innerlist.) Now, the tricky part again. I tried to apply the same rules with outer_list deletion but whenever i delete the head element of inner_list it gives an error. Where is the wrong thing in print_node or delnode2?

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  • Best way to display a background with a pattern in an iPhone/iPad app

    - by Dr Dork
    Here's an example of the type of background image I'm talking about... Clearly, there's a pattern in it. My question is, if this were an iPad app and the background image was twice the size, would there be any significant benefits to taking advantage of this pattern by tiling the image? Or would it really make no difference in terms of performance and just be easier to load the entire image into a UIImageView? Thanks in advance for all your wisdom!

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  • I can't display my pages on ASP.NET

    - by iva123
    Hi, I'm developing a web site with asp.net on localhost, I'm beginner. I wrote a login page and it works well. However when I click a link, the server can't load the page and gives this error: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server) Any idea?

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  • Activity monitor doesnt display process name

    - by Mohsin Khawas
    Hi, I have an application, when I see that application in "Activity Monitor" the applications Process Name is displayed nothing. Only the application icon is displayed. I tried debugging this by getting processInfo of the app, I got the application name correct. Even tried with the "top" command, I got the application name correct. The target name and settings also shows the same, only the activity monitor got wrong. Is it something I missed so that activity monitor is displaying nothing. M

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  • PHP, MySQL: Display only required parts of my website in sister website

    - by Devner
    Hi all, Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend. I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time. It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome. Is this really possible? Thank you in advance.

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  • Make python display help screen if no action is given

    - by luckytaxi
    Let's say a user runs the script w/o giving any paramters. How can I make it so that it defaults to ./myscript.py -h so that it shows them the help info? parser = optparse.OptionParser() parser.add_option("-d", "--directory", metavar="DIR", help="Directory to scan for big files") parser.add_option("-e", "--email", metavar='EMAIL', help='email to send the list to') parser.add_option("-l", "--limit", metavar='LIMIT', help='return number of files')

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  • Zend Framework Internet Explorer images won't display

    - by Matt
    I am using Zend Framework and it works fine in Firefox/Safari. In IE I have a problem with images not loading. Say I have an image in my public folder and I have this in my page: <img src="/photos/category/img.jpg" /> Well that works, except when I'm at a URL with a controller like http://www.example.com/controller/action I can see why, but I want a good solution to properly creating these img src links that works across browsers.

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  • Display the same prev/next usercontrol twice on a page

    - by Scott
    I haven't seen a question like this. I have a prev/next paging control on my page, one at the top and one at the bottom like this: top pager product catalog bottom pager Each pager is bound to a PagedDataSource that is exactly the same. I don't want to duplicate effort, so I am trying to figure out a way to do the processing once, but show the control twice.

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  • Display values and how many times they occured using a Dictionary

    - by user1730056
    I've been told to By using a dictionary (or your solution to Part 4), write a method at_least(a, n) that takes a list, a, and an integer, n, as arguments and returns a list containing only the elements of a that occur at least n times. For complete marks, the list should contain the elements in order of their first occurrence in a. I was able to figure this without using a dictionary, with def at_least2(a, n): return [x for x in a if a.count(x) is n] I was wondering how I can write this using a dictionary? The input is: a = [-6, 8, 7, 3, 2, -9, 1, -3, 2, -4, 4, -8, 7, 8, 2, -2, -7, 0, 1, -9, -3, -7, -3, -5, 6, -3, 6, -3, -10, -8] def at_least(a, 2): and the output: [8, 7, 2, -9, 1, -3, 2, -8, 7, 8, 2, -7, 1, -9, -3, -7, -3, 6, -3, 6, -3, -8] Edit: I don't understand how a dictionary is being used, yet the output isn't in dictionary form? My understanding is that dictionaries have values for each object. I'm not sure if I'm using the right terms.

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  • LinkedList Wrong Display(string builder)

    - by Chris
    Hello, The following program is a basic linked list divided in 3 classes. In the tester class (main) i add several numbers to the list (sorted). But insteed of getting the numbers as a result i get the result: LinkedList.LinkedList Is something wrong with the stringbuilder (the program was first in java where a string buffer was used, but that should be the same i think?) LinkedListTester.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace LinkedList { public class LinkedListTester { static void Main(string[] args) { LinkedList ll = new LinkedList(); ll.addDataSorted(5); ll.addDataSorted(7); ll.addDataSorted(13); ll.addDataSorted(1); ll.addDataSorted(17); ll.addDataSorted(8); Console.WriteLine(ll); } } }/LinkedList/ LinkedList.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace LinkedList { public class LinkedList { //toestand private LinkedListNode first; private LinkedListNode last; //gedrag public LinkedList() { first = null; last = null; } public void addDataInFront(int data) { first = new LinkedListNode(data, first); if (last == null){ last = first; } }/*addDataInFront*/ public void addDataToBack(int data) { if (first == null) { addDataInFront(data); } else { last.setNext(new LinkedListNode(data, null)); last = last.getNext(); } }/*addDataToBack*/ public void addDataSorted(int data) { if (first == null || first.getData() > data) { addDataInFront(data); } else { LinkedListNode currentNode = first; while (currentNode.getNext() != null && currentNode.getNext().getData() < data) { currentNode = currentNode.getNext(); } currentNode.setNext(new LinkedListNode(data, currentNode.getNext())); currentNode = currentNode.getNext(); if (currentNode.getNext() == null) { last = currentNode; } } }/*addDataSorted*/ public String toString() { StringBuilder Buf = new StringBuilder(); LinkedListNode currentNode = first; while (currentNode != null) { Buf.Append(currentNode.getData()); Buf.Append(' '); currentNode = currentNode.getNext(); } return Buf.ToString(); }/*toString*/ }/*LinkedList*/ }/LinkedList/ LinkedListNode: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace LinkedList { public class LinkedListNode { //toestand private int data; private LinkedListNode next; private LinkedListNode previous; //gedrag public LinkedListNode(int data, LinkedListNode next) { this.data = data; this.next = next; this.previous = null; } public LinkedListNode(int data, LinkedListNode next, LinkedListNode previous) { this.data = data; this.next = next; this.previous = previous; } public LinkedListNode getNext() { return next; } public LinkedListNode getPrevious() { return previous; } public void setNext(LinkedListNode next) { this.next = next; } public void setPrevious(LinkedListNode previous) { this.previous = previous; } public int getData() { return data; } }/*LinkedListNode*/ }/LinkedList/

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  • Image display permissions in PHP/Apache

    - by Randy
    I have a PHP site with a login system, and am trying to make a feature where only specific usernames can view particular images. I think what I'm trying to do is more involved than merely changing the .htaccess file, because a) this won't help discern between users that are/aren't allowed to view the image, and b) if someone enters the exact URL of the image ("directory/images/photos/230ru0q0238rn230nd_asdi0nqn8.jpg") they can still view the image (since it's a physical file in the directory, and not text in a DB, etc.). Again, restricting via .htaccess would restrict the directory as a whole, or all files in it, so I can't figure out how it would work. Ideally, all images would be blocked by trying to access them directly through their direct URL, and the image would only appear between <img> tags if the user's session/username is valid, else they get an error message. I've heard the term ACL but I'm not sure this is related to what I'm trying to do.

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  • Unable to display google maps in a dojo layout

    - by Jens
    Dear All, I am a real newbie in programming and now I have to combine Google Maps and Dojo. Both alone are fine but when I try to implement a Google Map into a Dojo content pane which is embedded in a border-container it simply does not work. I think there is a problem with the naming of the divs but perhaps there is something else to take care of? Could someone post the simplest possible solution? many thanks

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  • Gridview display multiple tables?

    - by Shawn
    I have a gridview setup that gets its data from a SQL database stored procedure. This procedure will return one of several different tables. The gridview complains if the table is different than the one previously displayed. How do I work around this?

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  • How to automatically display relationships in logical diagram?

    - by Cliff Chaney
    Consider a Logical Model where Entity A and Entity B are connected via Relationship Z. If I create a Logical Diagram (note: not another logical MODEL), I am able to drag Entity A and Entity B onto the diagram. Since the Logical Model already "knows" that Entity A and Entity B have a relationship, I would like to be able to easily add it to my logical diagram. I am already aware of the "Show Symbols" option whereby I can select the specific relationship that I want and have it appear. That is not a solution for me. The problem is that I have a LARGE logical model consisting of HUNDREDS of Entities and their various relationships. I then need to create application-specific diagrams consisting of a subset of those entities. I can easily identify and drag the 50+ entities onto a new diagram. But identifying and selecting all the associations is an exercise in frustration. Is there an option or some sort of feature that I'm missing - or any other trick - that would allow me to add only the relationships between selected entities or all entities on a diagram?

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  • how to display the grid in div tag..

    - by kumar
    <script type="text/javascript"> var showGrid = function() { $("#Grid1").load('/friends/names/fried'); }; </script> <div> <%= Html.Trirand().JQGrid(Model.OrdersGrid, "JqGrid1")%> </div> <div> </div> /////// i need to dispaly the Grid1 here? can anyone tell me? thanks

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  • Load page for validation but do not display it to user in ASP.NET

    - by Kevin
    We have a site requiring users pay $2 to view the details of a record. We occasionally get complaints because we send them to the payment page, and once they pay it turns out the record isn't valid, or it was lost, or the data couldn't be generated. So we want to add in a check to ensure the page constructs properly before the user is required to pay for it. However, we don't want the user to have access to the page until they pay for it. Is there anything in ASP.NET 3.5 or just general web design that would allow something like this? The data on the record is real time and computed on a backend server before sent to the client. Occasionally this computation fails for whatever reason. Our alternative is to call all of the loading methods and validate the data, then redirect them to the payment page. The problem is A) this will be a relatively involved process rewriting all of these methods to return validation information, and B) it still doesn't guarentee us the page will load properly. Any thoughts?

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  • i want to display an item in between a for each loop

    - by atif
    i had this code <ul class="links"<?php if($this->getName()): ?> id="<?php echo $this->getName() ?>"<?php endif;?>> <?php foreach($_links as $_link): ?> <?php if ($_link instanceof Mage_Core_Block_Abstract):?> <?php echo $_link->toHtml() ?> <?php else: ?> <li<?php if($_link->getIsFirst()||$_link->getIsLast()): ?> class="<?php if($_link->getIsFirst()): ?>first<?php endif; ?><?php if($_link->getIsLast()): ?> last<?php endif; ?>"<?php endif; ?> <?php echo $_link->getLiParams() ?>><?php echo $_link->getBeforeText() ?><a href="<?php echo $_link->getUrl() ?>" title="<?php echo $_link->getTitle() ?>" <?php echo $_link->getAParams() ?>><?php echo $_link->getLabel() ?></a><?php echo $_link->getAfterText() ?></li> <?php endif;?> <?php endforeach; ?> </ul> now i know that i had four links but i want to insert "wishlist" after 1st so how could i do that?

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  • How to display CodeRush menu item in VS ?

    - by drasto
    I just installed CodeRush to my VS and when I run VS for the first time after installation it showed me a dialog asking if I'm experienced user. While the dialog was visible I could see that there was new menu item in VS named DevExpress. There was a small check box on that dialog saying something about menu items that I probably should have checked. As I did not the menu items disappeared just after I clicked OK. I cannot make that menu item reappear. Can somebody help me with this ?

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