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  • Which way is preferred when doing asynchronous WCF calls?

    - by Mikael Svenson
    When invoking a WCF service asynchronous there seems to be two ways it can be done. 1. public void One() { WcfClient client = new WcfClient(); client.BegindoSearch("input", ResultOne, null); } private void ResultOne(IAsyncResult ar) { WcfClient client = new WcfClient(); string data = client.EnddoSearch(ar); } 2. public void Two() { WcfClient client = new WcfClient(); client.doSearchCompleted += TwoCompleted; client.doSearchAsync("input"); } void TwoCompleted(object sender, doSearchCompletedEventArgs e) { string data = e.Result; } And with the new Task<T> class we have an easy third way by wrapping the synchronous operation in a task. 3. public void Three() { WcfClient client = new WcfClient(); var task = Task<string>.Factory.StartNew(() => client.doSearch("input")); string data = task.Result; } They all give you the ability to execute other code while you wait for the result, but I think Task<T> gives better control on what you execute before or after the result is retrieved. Are there any advantages or disadvantages to using one over the other? Or scenarios where one way of doing it is more preferable?

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  • undefined offset error in php

    - by user225269
    I don't know why but the code below is working when I have a different query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <?php list($year,$month,$day)=explode("-", $row['BIRTHDAY']); ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mm" type="text" id="mm" onkeypress="return handleEnter(this, event)" value="<?php echo $month;?>"> <td width="30" height="35"><font size="2">Day:</td> <td width="30"><input name="dd" type="text" id="dd" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $day;?>"> <td width="30" height="35"><font size="2">Year:</td> <td width="30"><input name="yyyy" type="text" id="yyyy" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $year;?>"> And it works when this is my query: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); Please help, why do I get the undefined offset error when I use this query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") I assume that the query is the problem because its the only thing that's different between the two.

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  • multiple inheritance

    - by hitech
    when we say "a member declated as protected is accessible to any class imediately derived from it" what does this mean. in the follwing example get_number function can be accessible by the result class , as per the statement it sould only be accessile to test class. class student { protected: int roll_number; public: void get_number(int){ cout<< "hello"; } void put_number(void) {cout<< "hello"; } }; class test : public student { protected : float sub1; float sub2; public: void get_marks(float, float) {cout<< "hello"; roll_number = 10; } void put_marks(void) {cout<< "hello"; cout << "roll_number = " << roll_number ; } }; class result :public test { float total; public: void display(){cout<< "hello"; roll_number = 10; } }; int main() { result student; student.get_marks(2.2, 2.2); student.put_marks(); return 0; } i changed the code as per the first statement the protected variable roll_number not be accessible upto the result class ?

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  • MVC JsonResult with the [Authorize] attribute going to Logon but not displaying the view

    - by likestoski
    I am seeing odd behavior with MVC 3 methods that return a JsonResult when used with the Authorize attribute. What looks like happens is the Authorize is correctly evaluated when I am not logged in but instead of redirecting to the logon form the Json response is the logon form. Is there an addition attribute that directs the response to not return a value but instead redirect the user to the logon form, preferebly with the correct returnUrl value? What I did as a demo was to setup a new MVC3 site and added AspNetMembership to my DB using the aspnet_regsql.exe command. All that is setup and logging me in correctly. The behavior of the JsonResult doesn't seem right and I'm hoping I have just missed an attribute to make it work properly. Any help is greatly appreciated, thanks in advance. Here is the Account Controller (leaving out the Post action which is not part of this question). public class AccountController : Controller { public ActionResult LogOn() { return View(); } [Authorize] public JsonResult AuthorizedAction() { return Json("Only returns if I am authorized"); } } Here is the Html markup: <script src="@Url.Content("~/Scripts/jquery-ui-1.8.11.min.js")" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function () { $("#btnTest").click(function () { $.ajax({ type: "POST", url: "Account/AuthorizedAction", data: {}, success: function (result) { $("#testMe").html(result); }, error: function (result) { $("#testMe").html('Something broke in the ajax request'); } }); }); }); </script> <input type="button" id="btnTest" value="Test me" /> <div id="testMe">I have initial text</div> The Result: 1) When logged in I get 'Only returns if I am authorized' in my test div 2) When not logged and I have a break point in my Logon() method I see this value Request["returnUrl"] "/Account/AuthorizedAction" The test div I have displays the logon form :) this seems like I'm just not handling this properly.

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  • Merging two arrays in PHP

    - by Industrial
    Hi everyone, I am trying to create a new array from two current arrays. Tried array_merge, but it will not give me what I want. $array1 is a list of keys that I pass to a function. $array2 holds the results from that function, but doesn't contain any non-available resuls for keys. So, I want to make sure that all requested keys comes out with 'null':ed values, as according to the shown $result array. It goes a little something like this: $array1 = array('item1', 'item2', 'item3', 'item4'); $array2 = array( 'item1' => 'value1', 'item2' => 'value2', 'item3' => 'value3' ); Here's the result I want: $result = array( 'item1' => 'value1', 'item2' => 'value2', 'item3' => 'value3', 'item4' => '' ); It can be done this way, but I don't think that it's a good solution - I really don't like to take the easy way out and suppress PHP errors by adding @:s in the code. This sample would obviously throw errors since 'item4' is not in $array2, based on the example. foreach ($keys as $k => $v){ @$array[$v] = $items[$v]; } So, what's the fastest (performance-wise) way to accomplish the same result?

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  • android Json show only lasy item

    - by 03uk
    i have one problem, my json parser show only last item! But at Logcat i see all item's! Can you help me? @Override protected void onPostExecute(JSONObject result) { super.onPostExecute(result); Log.d("Log", result.toString()); JSONObject jsn = result; try { JSONArray jarray = jsn.getJSONArray("item"); for (int i = 0; i < jarray.length(); i++){ JSONObject jsno = jarray.getJSONObject(i); title.setText(Html.fromHtml("<a href=\""+jsno.getString("link")+"\">"+jsno.getString("title")+"</a>")); cat.setText(jsno.getString("category")); date.setText(jsno.getString("pubDate")); desc.getSettings().setJavaScriptEnabled(true); desc.getSettings().setDefaultTextEncodingName("charset=UTF-8"); desc.loadData(jsno.getString("description"), "text/html; charset=UTF-8", "utf-8"); } } catch (JSONException e) { e.printStackTrace(); }

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  • What's the best practice for make username check like Twitter ?

    - by Space Cracker
    I develop registration form and it have username field, and it's required to be like twitter username check ( real time check ) .. i already develop as in every textbox key up I use jquery to pass textbox.Text to page that return if is username exist or not as following code : function Check() { var userName = $('#<%= TextBox1.ClientID %>').val(); if (userName.length < 3) { $('#checkUserNameDIV').html("user name must be between 3 and 20"); return; } $('#checkUserNameDIV').html('<img src="loader.gif" />'); //setTimeout("CheckExistance('" + userName + "')", 5000); CheckExistance(userName); } function CheckExistance(userName) { $.get( "JQueryPage.aspx", { name: userName }, function(result) { var msg = ""; if (result == "1") msg = "Not Exist " + '<img src="unOK.gif" />'; else if (result == "0") msg = "Exist" ; else if (result == "error") msg = "Error , try again"; $('#checkUserNameDIV').html(msg); } ); } but i don't know if is it the best way to do that ? specially i do check every keyup .. is there any design pattern for this problem or nay good practice for doing that ?

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  • Best way to do one-to-many "JOIN" in CouchDB

    - by mit
    There are CouchDB documents that are list elements: { "type" : "el", "id" : "1", "content" : "first" } { "type" : "el", "id" : "2", "content" : "second" } { "type" : "el", "id" : "3", "content" : "third" } There is one document that defines the list: { "type" : "list", "elements" : ["2","1"] , "id" : "abc123" } As you can see the third element was deleted, it is no longer part of the list. So it must not be part of the result. Now I want a view that returns the content elements including the right order. The result could be: { "content" : ["second", "first"] } In this case the order of the elements is already as it should be. Another possible result: { "content" : [{"content" : "first", "order" : 2},{"content" : "second", "order" : 1}] } I started writing the map function: map = function (doc) { if (doc.type === 'el') { emit(doc.id, {"content" : doc.content}); //emit the id and the content exit; } if (doc.type === 'list') { for ( var i=0, l=doc.elements.length; i<l; ++i ){ emit(doc.elements[i], { "order" : i }); //emit the id and the order } } } This is as far as I can get. Can you correct my mistakes and write a reduce function? Remember that the third document must not be part of the result. Of course you can write a different map function also. But the structure of the documents (one definig element document and an entry document for each entry) cannot be changed.

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  • Celery Received unregistered task of type (run example)

    - by Echeg
    I'm trying to run example from Celery documentation. I run: celeryd --loglevel=INFO /usr/local/lib/python2.7/dist-packages/celery/loaders/default.py:64: NotConfigured: No 'celeryconfig' module found! Please make sure it exists and is available to Python. "is available to Python." % (configname, ))) [2012-03-19 04:26:34,899: WARNING/MainProcess] -------------- celery@ubuntu v2.5.1 ---- **** ----- --- * *** * -- [Configuration] -- * - **** --- . broker: amqp://guest@localhost:5672// - ** ---------- . loader: celery.loaders.default.Loader - ** ---------- . logfile: [stderr]@INFO - ** ---------- . concurrency: 4 - ** ---------- . events: OFF - *** --- * --- . beat: OFF -- ******* ---- --- ***** ----- [Queues] -------------- . celery: exchange:celery (direct) binding:celery tasks.py: # -*- coding: utf-8 -*- from celery.task import task @task def add(x, y): return x + y run_task.py: # -*- coding: utf-8 -*- from tasks import add result = add.delay(4, 4) print (result) print (result.ready()) print (result.get()) In same folder celeryconfig.py: CELERY_IMPORTS = ("tasks", ) CELERY_RESULT_BACKEND = "amqp" BROKER_URL = "amqp://guest:guest@localhost:5672//" CELERY_TASK_RESULT_EXPIRES = 300 When I run "run_task.py": on python console eb503f77-b5fc-44e2-ac0b-91ce6ddbf153 False errors on celeryd server [2012-03-19 04:34:14,913: ERROR/MainProcess] Received unregistered task of type 'tasks.add'. The message has been ignored and discarded. Did you remember to import the module containing this task? Or maybe you are using relative imports? Please see http://bit.ly/gLye1c for more information. The full contents of the message body was: {'retries': 0, 'task': 'tasks.add', 'utc': False, 'args': (4, 4), 'expires': None, 'eta': None, 'kwargs': {}, 'id': '841bc21f-8124-436b-92f1-e3b62cafdfe7'} Traceback (most recent call last): File "/usr/local/lib/python2.7/dist-packages/celery/worker/consumer.py", line 444, in receive_message self.strategies[name](message, body, message.ack_log_error) KeyError: 'tasks.add' Please explain what's the problem.

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  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

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  • Password protect user image album

    - by Poland Rocks
    Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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  • android: ending activity from tab

    - by Jin
    I have 3 classes, let's call them 1, 2, and 3. Class 1 extends TabActivity and organizes the whole tab thing, Class 2 and 3 are just two separate tabs each with some lines of text. I call Class 1 from another activity using startActivityForResult. I then added an optionsMenu in class 2, and when user clicks the optionMenu, the following code is carried out: @Override public boolean onMenuItemSelected(int featureId, MenuItem item) { Intent i = new Intent(); switch(item.getItemId()) { case Result.NEXT_ID: i.putExtra(Result.PAGE_REQUEST, NEXT); setResult(RESULT_OK, i); finish(); break; case Result.PREV_ID: i.putExtra(Result.PAGE_REQUEST, PREV); setResult(RESULT_OK, i); finish(); } return super.onMenuItemSelected(featureId, item); } In my parent class (the class that called 1 to begin with), in its onActivityResult function, I want to get the data from the extras. However, the intent is always null, and I can't figure out why. When I call finish() on class 2, is it calling some other function in class 1? Do I have to transfer the intent data somehow?

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  • Delphi static method of a class returning property value

    - by mitko.berbatov
    I'm making a Delphi VCL application. There is a class TStudent where I have two static functions: one which returns last name from an array of TStudent and another one which returns the first name of the student. Their code is something like: class function TStudent.FirstNameOf(aLastName: string): string; var i : integer; begin for i := 0 to Length(studentsArray) - 1 do begin if studentsArray[i].LastName = aLastName then begin result := studentsArray[i].FirstName; Exit; end; end; result := 'no match was found'; end; class function TStudent.LastNameOf(aFirstName: string): string; var i : integer; begin for i := 0 to Length(studentsArray) - 1 do begin if studentsArray[i].FirstName = aFirstName then begin result := studentsArray[i].LastName; Exit; end; end; result := 'no match was found'; end; My question is how can I avoid writing almost same code twice. Is there any way to pass the property as parameter of the functions.

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  • How to put data from List<string []> to dataGridView

    - by Kirill
    Try to put some data from List to dataGridView, but have some problem with it. Currently have method, that return me required List - please see picture below code public List<string[]> ReadFromFileBooks() { List<string> myIdCollection = new List<string>(); List<string[]> resultColl = new List<string[]>(); if (chooise == "all") { if (File.Exists(filePath)) { using (FileStream fs = new FileStream(filePath, FileMode.Open, FileAccess.Read)) { StreamReader sr = new StreamReader(fs); string[] line = sr.ReadToEnd().Split(new string[] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries); foreach (string l in line) { string[] result = l.Split(','); foreach (string element in result) { myIdCollection.Add(element); } resultColl.Add(new string[] { myIdCollection[0], myIdCollection[1], myIdCollection[2], myIdCollection[3] }); myIdCollection.Clear(); } sr.Close(); return resultColl; } } .... this return to me required data in requred form (like list from arrays). After this, try to move it to the dataGridView, that already have 4 columns with names (because i'm sure, that no than 4 colums required) - please see pic below Try to put data in to dataGridView using next code private void radioButtonViewAll_CheckedChanged(object sender, EventArgs e) { TxtLibrary myList = new TxtLibrary(filePathBooks); myList.chooise = "all"; //myList.ReadFromFileBooks(); DataTable table = new DataTable(); foreach (var array in myList.ReadFromFileBooks()) { table.Rows.Add(array); } dataGridViewLibrary.DataSource = table; } But as result got error - "required more rows that exist in dataGridVIew", but accordint to what I'm see (pic above) q-ty of rows (4) equal q-ty of arrays element in List (4). Try to check result by putting additional temp variables - but it's ok - please see pic below Where I'm wrong? Maybe i use dataGridView not in correct way?

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  • implementing interface

    - by 1ace1
    hello guys so i have this assignment that i need to implement interface to go over an ArrayList and sort it (ascending or descnding).I dont want "the" answer i just need some suggestions on my approach and why i get this error Exception in thread "main" java.lang.ClassCastException: Week7.Check cannot be cast to java.lang.Comparable at java.util.Arrays.mergeSort(Unknown Source) at java.util.Arrays.sort(Unknown Source) at java.util.Collections.sort(Unknown Source) at Week7.TestCheck.main(TestCheck.java:18) This is how i did it: comparable had one method called public int compairTo(Object o) public class Check implements comparable { private Integer checkNumber; public Check(Integer newCheckNumber) { setCheckNumber(newCheckNumber); } public String toString() { return getCheckNumber().toString(); } public void setCheckNumber(Integer checkNumber) { this.checkNumber = checkNumber; } public Integer getCheckNumber() { return checkNumber; } @Override public int compairTo(Object o) { Check compair = (Check)o; int result = 0; if (this.getCheckNumber() > compair.getCheckNumber()) result = 1; else if(this.getCheckNumber() < compair.getCheckNumber()) result = -1; return result; } } in my main i had this import java.util.ArrayList; import java.util.Collections; public class TestCheck { public static void main(String[] args) { ArrayList checkList = new ArrayList(); checkList.add(new Check(445)); checkList.add(new Check(101)); checkList.add(new Check(110)); checkList.add(new Check(553)); checkList.add(new Check(123)); Collections.sort(checkList); for (int i =0; i < checkList.size(); i++){ System.out.println(checkList.get(i)); } } }

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  • Create a console from within a non-console .NET application.

    - by pauldoo
    How can I open a console window from within a non-console .NET application (so I have a place for System.Console.Out and friends when debugging)? In C++ this can be done using various Win32 APIs: /* EnsureConsoleExists() will create a console window and attach stdout (and friends) to it. Can be useful when debugging. */ FILE* const CreateConsoleStream(const DWORD stdHandle, const char* const mode) { const HANDLE outputHandle = ::GetStdHandle(stdHandle); assert(outputHandle != 0); const int outputFileDescriptor = _open_osfhandle(reinterpret_cast<intptr_t>(outputHandle), _O_TEXT); assert(outputFileDescriptor != -1); FILE* const outputStream = _fdopen(outputFileDescriptor, mode); assert(outputStream != 0); return outputStream; } void EnsureConsoleExists() { const bool haveCreatedConsole = (::AllocConsole() != 0); if (haveCreatedConsole) { /* If we didn't manage to create the console then chances are that stdout is already going to a console window. */ *stderr = *CreateConsoleStream(STD_ERROR_HANDLE, "w"); *stdout = *CreateConsoleStream(STD_OUTPUT_HANDLE, "w"); *stdin = *CreateConsoleStream(STD_INPUT_HANDLE, "r"); std::ios::sync_with_stdio(false); const HANDLE consoleHandle = ::GetStdHandle(STD_OUTPUT_HANDLE); assert(consoleHandle != NULL && consoleHandle != INVALID_HANDLE_VALUE); CONSOLE_SCREEN_BUFFER_INFO info; BOOL result = ::GetConsoleScreenBufferInfo(consoleHandle, &info); assert(result != 0); COORD size; size.X = info.dwSize.X; size.Y = 30000; result = ::SetConsoleScreenBufferSize(consoleHandle, size); assert(result != 0); } }

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  • How to output multiple rows from an SQL query using the mysqli object

    - by Jonathan
    Assuming that the mysqli object is already instantiatied (and connected) with the global variable $mysql, here is the code I am trying to work with. class Listing { private $mysql; function getListingInfo($l_id = "", $category = "", $subcategory = "", $username = "", $status = "active") { $condition = "`status` = '$status'"; if (!empty($l_id)) $condition .= "AND `L_ID` = '$l_id'"; if (!empty($category)) $condition .= "AND `category` = '$category'"; if (!empty($subcategory)) $condition .= "AND `subcategory` = '$subcategory'"; if (!empty($username)) $condition .= "AND `username` = '$username'"; $result = $this->mysql->query("SELECT * FROM listing WHERE $condition") or die('Error fetching values'); $this->listing = $result->fetch_array() or die('could not create object'); foreach ($this->listing as $key => $value) : $info[$key] = stripslashes(html_entity_decode($value)); endforeach; return $info; } } there are several hundred listings in the db and when I call $result-fetch_array() it places in an array the first row in the db. however when I try to call the object, I can't seem to access more than the first row. for instance: $listing_row = new Listing; while ($listing = $listing_row-getListingInfo()) { echo $listing[0]; } this outputs an infinite loop of the same row in the db. Why does it not advance to the next row? if I move the code: $this->listing = $result->fetch_array() or die('could not create object'); foreach ($this->listing as $key => $value) : $info[$key] = stripslashes(html_entity_decode($value)); endforeach; if I move this outside the class, it works exactly as expected outputting a row at a time while looping through the while statement. Is there a way to write this so that I can keep the fetch_array() call in the class and still loop through the records?

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  • How to access parents' members from a inner class in WPF?

    - by black sensei
    Hello Experts! I'm trying to do scheduled operation let's say to check for user's credit left via web service call and update the user interface. i've tried with quartz.net to implement the scheduling bit.i created an inner class in the window class i need to update.That inner class has the method that calls the webservice and the result needs to be displayed back to the UI. here is an example of what i did. public partial class Window2 : Window { private int i; public Window2() { InitializeComponent(); } public class Myclass :IJob { public void Execute(JobExecutionContext context) { string result = doMyOperation(); //i'll like to call parent label member of name lblNotif //is something like parent.lblNotif.Content = result; //possible? } public string doMyOperation() { //calling the wermethod to retreive user's balance return result = service.GetUsersBalace(user); } } } Well the quartz bit is working and this post is not about quartz. here are my questions Question 1 : How is it possible to access Window2 controls, for instace lable lblNotif? Question 2 : If my thinking about this is wrong, what is done as best practice to solve my kind of problem, where an application need to do an operation let's say every 5mn and update the the UI. Question 3 : i at first tried to use the backgroundworker and i felt like i can't do the scheduling bit with it.Is that correct or i'm wrong. thanks for those who commented already and sorry for those who didn't get the meaning of my post.I hope this will be a bit clearer.Thanks for reading

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • singledispatch in class, how to dispatch self type

    - by yanxinyou
    Using python3.4. Here I want use singledispatch to dispatch different type in __mul__ method . The code like this : class Vector(object): ## some code not paste @functools.singledispatch def __mul__(self, other): raise NotImplementedError("can't mul these type") @__mul__.register(int) @__mul__.register(object) # Becasue can't use Vector , I have to use object def _(self, other): result = Vector(len(self)) # start with vector of zeros for j in range(len(self)): result[j] = self[j]*other return result @__mul__.register(Vector) # how can I use the self't type @__mul__.register(object) # def _(self, other): pass # need impl As you can see the code , I want support Vector*Vertor , This has Name error Traceback (most recent call last): File "p_algorithms\vector.py", line 6, in <module> class Vector(object): File "p_algorithms\vector.py", line 84, in Vector @__mul__.register(Vector) # how can I use the self't type NameError: name 'Vector' is not defined The question may be How Can I use class Name a Type in the class's method ? I know c++ have font class statement . How python solve my problem ? And it is strange to see result = Vector(len(self)) where the Vector can be used in method body .

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  • Error while saving csv file generated by PHP

    - by user1667374
    I have created below script which is saving the csv file in the same path of this script but when I am saving it to different directory, it gives me error. Can somebody please help me on this? This is the error: Warning: fopen(/store/secure/mas/) [function.fopen]: failed to open stream: No such file or directory in /getdetails.php on line 15 Warning: fputs(): supplied argument is not a valid stream resource in /getdetails.php on line 36 Warning: fclose(): supplied argument is not a valid stream resource in /getdetails.php on line 39 This is the script: <?php $MYSQL_HOST="localhost"; $MYSQL_USERNAME="***"; $MYSQL_PASSWORD="***"; $MYSQL_DATABASE="shop"; $MYSQL_TABLE="ds_orders"; mysql_connect( "$MYSQL_HOST", "$MYSQL_USERNAME", "$MYSQL_PASSWORD" ) or die( mysql_error( ) ); mysql_select_db( "$MYSQL_DATABASE") or die( mysql_error( $conn ) ); $filename="Order_Details"; $directory = "/store/secure/mas/"; $csv_filename = $filename.".csv"; $fd = fopen ( "$directory" . $cvs_filename, "w"); $today="2009-03-17"; $disp_date="05122008"; $sql = "SELECT * FROM $MYSQL_TABLE where cDate='$today'"; $result=mysql_query($sql); $rows=mysql_num_rows($result); echo $rows; if(mysql_num_rows($result)>0){ $fileContent="Record ID,Discount Percent\n"; while($data=mysql_fetch_array($result)) { $fileContent.= "".$data['oID'].",".$data['discount']."\n"; } $fileContent=str_replace("\n\n","\n",$fileContent); fputs($fd, $fileContent); } fclose($fd); ?>

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  • PHP/MySQL Problem

    - by Scott
    Why does this only print the sites specific content under the first site, and doesn't do it for the other 2? <?php echo 'NPSIN Data will be here soon!'; // connect to DB $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to DB'); $dbname = 'npsin'; mysql_select_db($dbname); // get number of sites $query = 'select count(*) from sites'; $result = mysql_query($query) or die ('Query failed: ' . mysql_error()); $resultArray = mysql_fetch_array($result); $numSites = $resultArray[0]; echo "<br><br>"; // get all sites $query = 'select site_name from sites'; $result = mysql_query($query); // get site content $query2 = 'select content_name, site_id from content'; $result2 = mysql_query($query2); // get site files // print info $count = 1; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "Site $count: "; echo "$row[0]"; echo "<br>"; $contentCount = 1; while ($row2 = mysql_fetch_array($result2, MYSQL_NUM)) { $id = $row2[1]; if ($id == ($count - 1)) { echo "Content $contentCount: "; echo "$row2[0]"; echo "<br>"; } $contentCount++; } $count++; } ?>

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  • why my pagination link doesnt appear ?

    - by udaya
    This is my script which i have used to paginate ,,The datas are restricted to 4 but the pagination link doesn't appear <? require_once ('Pager/Pager.php'); $connection = mysql_connect( "localhost" , "root" , "" ); mysql_select_db( "ssit",$connection); $result=mysql_query("SELECT dFrindName FROM tbl_friendslist", $connection); $row = mysql_fetch_array($result); $totalItems = $row['total']; $pager_options = array( 'mode' => 'Sliding', // Sliding or Jumping mode. See below. 'perPage' => 4, // Total rows to show per page 'delta' => 4, // See below 'totalItems' => $totalItems, ); $pager = Pager::factory($pager_options); echo $pager->links; list($from, $to) = $pager->getOffsetByPageId(); $from = $from - 1; $perPage = $pager_options['perPage']; $result = mysql_query("SELECT * FROM tbl_friendslist LIMIT 5 , $perPage",$connection); while($row = mysql_fetch_array($result)) { echo $row['dFrindName'].'</br>'; } ?>

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  • Sending a file to an API - C#

    - by alex
    I'm trying to use an API which sends a fax. I have a PHP example below: (I will be using C# however) <?php //This is example code to send a FAX from the command line using the Simwood API //It is illustrative only and should not be used without the addition of error checking etc. $ch = curl_init("http://url-to-api-endpoint"); $fax_variables=array( 'user'=> 'test', 'password'=> 'test', 'sendat' => '2050-01-01 01:00', 'priority'=> 10, 'output'=> 'json', 'to[0]' => '44123456789', 'to[1]' => '44123456780', 'file[0]'=>'@/tmp/myfirstfile.pdf', 'file[1]' => '@/tmp/mysecondfile.pdf' ); print_r($fax_variables); curl_setopt ($ch, CURLOPT_POST, 1); curl_setopt ($ch, CURLOPT_POSTFIELDS, $fax_variables); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $result=curl_exec ($ch); $info = curl_getinfo($ch); $result['http_code']; curl_close ($ch); print_r($result); ?> My question is - in the C# world, how would I achieve the same result? Do i need to build a post request? Ideally, i was trying to do this using REST - and constructing a URL, and using HttpWebRequest (GET) to call the API

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  • login script in php using session variables

    - by kracekumar
    ? username: '; } else { $user=$_POST['user']; $query="select name from login where name='$user'"; $result=mysql_query($query) or die(mysql_error()); $rows=mysql_num_rows($result)or die(mysql_error()); session_start(); //echo "results"; $username=mysql_fetch_array($result) or die(mysql_error()); $fields=mysql_num_fields($result) or die(mysql_error()); echo "username:$username[0]"; $_SESSION['username']=$username[0]; $sesion_username=$_SESSION['username']; //echo "rows:$rows"." "."fields:$fields"; echo""."username:$sesion_username"; } ? i wanted to create a site where user can login and upload their details depending on their user name have stored their details in a database,the problem i am facing is two people 'a' and 'b' login one after other session_variable $_SESSION['username'] will have 'b's' username ,so i can't display 'a's' details now. . . . what i want to achieve is when a user logins in i want to store his name and other details in session variable and navigate him according and display his details

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