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  • How to send multiple MVP matrices to a vertex shader in OpenGL ES 2.0

    - by Carbon Crystal
    I'm working my way through optimizing the rendering of sprites in a 2D game using OpenGL ES and I've hit the limit of my knowledge when it comes to GLSL and vertex shaders. I have two large float buffers containing my vertex coordinates and texture coordinates (eventually this will be one buffer) for multiple sprites in order to perform a single glDrawArrays call. This works but I've hit a snag when it comes to passing the transformation matrix into the vertex shader. My shader code is: uniform mat4 u_MVPMatrix; attribute vec4 a_Position; attribute vec2 a_TexCoordinate; varying vec2 v_TexCoordinate; void main() { v_TexCoordinate = a_TexCoordinate; gl_Position = u_MVPMatrix * a_Position; } In Java (Android) I am using a FloatBuffer to store the vertex/texture data and this is provided to the shader like so: mGlEs20.glVertexAttribPointer(mVertexHandle, Globals.GL_POSITION_VERTEX_COUNT, GLES20.GL_FLOAT, false, 0, mVertexCoordinates); mGlEs20.glVertexAttribPointer(mTextureCoordinateHandle, Globals.GL_TEXTURE_VERTEX_COUNT, GLES20.GL_FLOAT, false, 0, mTextureCoordinates); (The Globals.GL_POSITION_VERTEX_COUNT etc are just integers with the value of 2 right now) And I'm passing the MVP (Model/View/Projection) matrix buffer like this: GLES20.glUniformMatrix4fv(mMVPMatrixHandle, 1, false, mModelCoordinates); (mModelCoordinates is a FloatBuffer containing 16-float sequences representing the MVP matrix for each sprite) This renders my scene but all the sprites share the same transformation, so it's obviously only picking the first 16 elements from the buffer which makes sense since I am passing in "1" as the second parameter. The documentation for this method says: "This should be 1 if the targeted uniform variable is not an array of matrices, and 1 or more if it is an array of matrices." So I tried modifying the shader with a fixed size array large enough to accomodate most of my scenarios: uniform mat4 u_MVPMatrix[1000]; But this lead to an error in the shader: cannot convert from 'uniform array of 4X4 matrix of float' to 'Position 4-component vector of float' This just seems wrong anyway as it's not clear to me how the shader would know when to transition to the next matrix anyway. Anyone have an idea how I can get my shader to pick up a different MVP matrix (i.e. the NEXT 16 floats) from my MVP buffer for every 4 vertices it encounters? (I am using GL_TRIANGLE_STRIP so each sprite has 4 vertices). Thanks!

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  • Efficient way to find unique elements in a vector compared against multiple vectors

    - by SyncMaster
    I am trying find the number of unique elements in a vector compared against multiple vectors using C++. Suppose I have, v1: 5, 8, 13, 16, 20 v2: 2, 4, 6, 8 v3: 20 v4: 1, 2, 3, 4, 5, 6, 7 v5: 1, 3, 5, 7, 11, 13, 15 The number of unique elements in v1 is 1 (i.e. number 16). I tried two approaches. Added vectors v2,v3,v4 and v5 into a vector of vector. For each element in v1, checked if the element is present in any of the other vectors. Combined all the vectors v2,v3,v4 and v5 using merge sort into a single vector and compared it against v1 to find the unique elements. Note: sample_vector = v1 and all_vectors_merged contains v2,v3,v4,v5 //Method 1 unsigned int compute_unique_elements_1(vector<unsigned int> sample_vector,vector<vector<unsigned int> > all_vectors_merged) { unsigned int duplicate = 0; for (unsigned int i = 0; i < sample_vector.size(); i++) { for (unsigned int j = 0; j < all_vectors_merged.size(); j++) { if (std::find(all_vectors_merged.at(j).begin(), all_vectors_merged.at(j).end(), sample_vector.at(i)) != all_vectors_merged.at(j).end()) { duplicate++; } } } return sample_vector.size()-duplicate; } // Method 2 unsigned int compute_unique_elements_2(vector<unsigned int> sample_vector, vector<unsigned int> all_vectors_merged) { unsigned int unique = 0; unsigned int i = 0, j = 0; while (i < sample_vector.size() && j < all_vectors_merged.size()) { if (sample_vector.at(i) > all_vectors_merged.at(j)) { j++; } else if (sample_vector.at(i) < all_vectors_merged.at(j)) { i++; unique ++; } else { i++; j++; } } if (i < sample_vector.size()) { unique += sample_vector.size() - i; } return unique; } Of these two techniques, I see that Method 2 gives faster results. 1) Method 1: Is there a more efficient way to find the elements than running std::find on all the vectors for all the elements in v1. 2) Method 2: Extra overhead in comparing vectors v2,v3,v4,v5 and sorting them. How can I do this in a better way?

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  • Autologin on Ubuntu Server

    - by hekevintran
    I have a machine running Ubuntu Server. It has only a command-line interface. How can I make the system login with a specific user automatically (I don't want to type the username/password). I know that this is insecure and I don't care.

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  • Tried to join a workgroup but now can't loginto system

    - by Ali
    Help - I tried to join a workgroup but now all of a sudden I can't log into my system. I get an account not found error - also for some reason when I click the options button on the log in screen I can't see the domain option at all.. whats going on! I can't even log in using the adminstrator login or anything!!

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  • SSH closing by itself - root works fine

    - by Antti
    I'm trying to connect to a server but if i use any other user than root the connection closes itself after a successful login: XXXXXXX:~ user$ ssh -v [email protected] OpenSSH_5.2p1, OpenSSL 0.9.8l 5 Nov 2009 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to XXXXXXX.XXXXXX.XXX [xxx.xxx.xxx.xxx] port 22. debug1: Connection established. debug1: identity file /Users/user/.ssh/identity type -1 debug1: identity file /Users/user/.ssh/id_rsa type -1 debug1: identity file /Users/user/.ssh/id_dsa type 2 debug1: Remote protocol version 2.0, remote software version OpenSSH_4.3 debug1: match: OpenSSH_4.3 pat OpenSSH_4* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'XXXXXXX.XXXXXX.XXX' is known and matches the RSA host key. debug1: Found key in /Users/user/.ssh/known_hosts:12 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: publickey debug1: Offering public key: /Users/user/.ssh/woo_openssh debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Offering public key: /Users/user/.ssh/sidlee.dsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Trying private key: /Users/user/.ssh/identity debug1: Trying private key: /Users/user/.ssh/id_rsa debug1: Offering public key: /Users/user/.ssh/id_dsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: password [email protected]'s password: debug1: Authentication succeeded (password). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 29 01:41:51 2010 from 193.67.179.2 debug1: client_input_channel_req: channel 0 rtype exit-status reply 0 debug1: channel 0: free: client-session, nchannels 1 Connection to XXXXXXX.XXXXXX.XXX closed. Transferred: sent 2976, received 2136 bytes, in 0.5 seconds Bytes per second: sent 5892.2, received 4229.1 debug1: Exit status 1 If i log in as root the exact same way it works as expected. I've added the users i want to log in with to a group (sshusers) and added that group to /etc/sshd_config: AllowGroups sshusers I'm not sure what to try next as i don't get a clear error anywhere. I would like to enable specific accounts to log in so that i can disable root. This is a GridServer/Media Temple (CentOS).

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  • Setting Sql server security rights for multiple situations

    - by DanDan
    We have an application which uses an instance of Sql Server locally for its backend storage. The administrator windows login has had its sysadmin right revoked, and instead two sql logins have been created; one for the application with a secret password and one read only login we let users view the raw data with. This was working fine until we moved on FileStreams, which requires intergrated windows authentication. So now the sql server logins must be replaced. As a result, I am now reviewing all of our logins but I am not sure how it is possible. It seems that the application needs full read/write access, yet I still need to lock down writing to the tables so the user cannot login into the database and delete data randomly. Does anyone have any tips for setting multiple levels of security using intergrated windows logins, or can you direct me to any further reading? Thanks.

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  • How can I log in with my Google OpenID

    - by compie
    I'm trying to login to www.refactormycode.com with my Google OpenID. But the site keeps saying: "Sorry, the OpenID server couldn't be found" What am I doing wrong? I have tried https://www.google.com/accounts/o8/id and http://google.com/profiles/me

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  • Override LDAP shell

    - by Incredible
    I have a LDAP server and a predefined shell (bash) set in it. But there are some machine on which I want a different shell to be used whenever user login to that instead of the shell stored in LDAP. How can I do this?? Can someone give me some direction in this? Thank you

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  • Computer keeps locking me out

    - by me32
    When I'm away from my computer (Windows XP) for more than ~30 minutes, I get locked out, and have to press Ctrl+Alt+Delete to login. I've checked the screensaver settings, and it's not set to lock the screen. Does anyone know what else could be causing this? Thanks

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  • Maintain cookie session in Android

    - by datguywhowanders
    Okay, I have an android application that has a form in it, two EditText, a spinner, and a login button. The user selects the service from the spinner, types in their user name and password, and clicks login. The data is sent via POST, a response is returned, it's handled, a new webview is launched, the html string generated form the response is loaded, and I have the home page of whatever service the user selected. That's all well and good. Now, when the user clicks on a link, the login info can't be found, and the page asks the user to login again. My login session is being dropped somewhere, and I'm not certain how to pass the info from the class that controls the main part of my app to the class that just launches the webview activity. The on click handler from the form login button: private class FormOnClickListener implements View.OnClickListener { public void onClick(View v) { String actionURL, user, pwd, user_field, pwd_field; actionURL = "thePageURL"; user_field = "username"; //this changes based on selections in a spinner pwd_field = "password"; //this changes based on selections in a spinner user = "theUserLogin"; pwd = "theUserPassword"; List<NameValuePair> myList = new ArrayList<NameValuePair>(); myList.add(new BasicNameValuePair(user_field, user)); myList.add(new BasicNameValuePair(pwd_field, pwd)); HttpParams params = new BasicHttpParams(); DefaultHttpClient client = new DefaultHttpClient(params); HttpPost post = new HttpPost(actionURL); HttpResponse response = null; BasicResponseHandler myHandler = new BasicResponseHandler(); String endResult = null; try { post.setEntity(new UrlEncodedFormEntity(myList)); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } try { response = client.execute(post); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { endResult = myHandler.handleResponse(response); } catch (HttpResponseException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } List cookies = client.getCookieStore().getCookies(); if (!cookies.isEmpty()) { for (int i = 0; i < cookies.size(); i++) { cookie = cookies.get(i); } } Intent myWebViewIntent = new Intent(MsidePortal.this, MyWebView.class); myWebViewIntent.putExtra("htmlString", endResult); myWebViewIntent.putExtra("actionURL", actionURL); startActivity(myWebViewIntent); } } And here is the webview class that handles the response display: public class MyWebView extends android.app.Activity{ private class MyWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.web); MyWebViewClient myClient = new MyWebViewClient(); WebView webview = (WebView)findViewById(R.id.mainwebview); webview.getSettings().setBuiltInZoomControls(true); webview.getSettings().setJavaScriptEnabled(true); webview.setWebViewClient(myClient); Bundle extras = getIntent().getExtras(); if(extras != null) { // Get endResult String htmlString = extras.getString("htmlString"); String actionURL = extras.getString("actionURL"); Cookie sessionCookie = MsidePortal.cookie; CookieSyncManager.createInstance(this); CookieManager cookieManager = CookieManager.getInstance(); if (sessionCookie != null) { cookieManager.removeSessionCookie(); String cookieString = sessionCookie.getName() + "=" + sessionCookie.getValue() + "; domain=" + sessionCookie.getDomain(); cookieManager.setCookie(actionURL, cookieString); CookieSyncManager.getInstance().sync(); } webview.loadDataWithBaseURL(actionURL, htmlString, "text/html", "utf-8", actionURL); } } } I've had mixed success implementing that cookie solution. It seems to work for one service I log into that I know keeps the cookies on the server (old, archaic, but it works and they don't want to change it.) The service I'm attempting now requires the user to keep cookies on their local machine, and it does not work with this setup. Any suggestions?

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  • Android multiple email attachment using Intent question

    - by yyyy1234
    Hi, I've been working on Android program to send email with attachment (image file , audio file , etc) using Intent with (ACTION_SEND) . THe program is working when email has a single attachment. I used Intent.putExtra( android.content.Intent.EXTRA_STREAM, uri) to attach the designated image file to the mail and it is wokring fine , the mail can be delivered through Gmail . However, when I tried to have multiple images attached to the same mail by calling Intent.putExtra( android.content.Intent.EXTRA_STREAM, uri) multiple times, it failed to work. None of the attachment show up in the email . I searched the SDK documentation and Android programming user group about email attachment but cannot find any related info. However, I've discovered that there's another intent constnat ACTION_SEND_MULTIPLE (available since API level 4 ) which might meet my requirement. Based on SDK documentation, it simply states that it deliver multiple data to someone else , it works like ACTION_SEND , excpet the data is multiple. But I still could not figure out the correct usage for this command. I tried to delcare intent with ACTION_SEND_MULTIPLE , then call putExtra(EXTRA_STREAM, uri) multiple times to attach multiple images , but I got the same errnoenous result just like before, none of the attachment show up in the email. Has anyone tried with ACTION_SEND_MULTIPLE and got it working with multiple email attachment ? Thanks very much for your help. Regards, yyyy1234

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  • Teamviewer: cannot control monitor 1, but can control monitor 2

    - by DaveT
    I'm using the web client of Teamviewer from my work computer trying to control my home computer. I have 2 monitors on the remote desktop, but for some reason only have control on the second monitor. When I switch to the main monitor (monitor 1), I cannot do anything and cannot even move the cursor. But I have no issues when I switch over to the second monitor (monitor 2). I used to have no issues with either, but in the past couple of months this has been causing me issues. Anyone have a suggestion? Thanks!! Also... Here is the log from the Teamviewer session. Showing me switching back and forth between the monitors. (just in case this will help). I had to remove the links in order to post the log since I don't have enough reputation points, but they were just teamviewer login weblinks. =============================================================================== 21.08 16:00:41,176: Version: 9.0.15099 21.08 16:00:41,177: Sandbox: remote 21.08 16:00:41,177: SysLanguage: en 21.08 16:00:41,177: VarLanguage: en 21.08 16:00:41,177: Flash Player: PlugIn (WIN 14,0,0,179) 21.08 16:00:41,178: UseLanguage: en 21.08 16:00:41,178: UseLanguage: en 21.08 16:00:41,182: TeamViewer hasPassword: true 21.08 16:00:41,418: ExternalConnect id=910035824 21.08 16:00:41,419: CT connect 910035824 masterURL: , sandbox = remote 21.08 16:00:41,425: MC.requestRoute(910035824) 21.08 16:00:41,426: MC.sendMasterCommand text=F=RequestRoute2&ID1=777&Client=TV& ID2=910035824&SA_AccountID=26641022&SA_PasswordMD5HashBase64Encoded=& SA_SessionSecret=f7H6Z7SYfX5ahQ7SJq/r/K20PBYg9fOZhp+DKLhf5ts=&SA_SessionID=1558929948& V=9.0.15099&OS=Flash 21.08 16:00:41,426: MC wait for ping completion 21.08 16:00:42,064: PS.socket event: [Event type="connect" bubbles=false cancelable=false eventPhase=2] 21.08 16:00:42,182: PingThread: TCP-Ping ok 21.08 16:00:42,183: MC.socket mode = TCP, MasterURL: 21.08 16:00:42,183: MC.connect: 21.08 16:00:43,058: PS.socket event: [Event type="connect" bubbles=false cancelable=false eventPhase=2] 21.08 16:00:43,058: MC.connectHandler: [Event type="connect" bubbles=false cancelable=false eventPhase=2] 21.08 16:00:43,236: MC.requestRouteResponse: [email protected]_10800_128000_762319420_910035824_10000__1_0_16778176_128000_16778176: 128000;2147483647:1280000;4:640000_786297_786297 21.08 16:00:43,239: CT init socket: TCP 21.08 16:00:43,513: PS.socket event: [Event type="connect" bubbles=false cancelable=false eventPhase=2] 21.08 16:00:43,514: CT.connectHandler: [Event type="connect" bubbles=false cancelable=false eventPhase=2] 21.08 16:00:43,519: Browser name: Netscape 21.08 16:00:43,936: CMD_IDENTIFY id=910035824 ver=2.41 21.08 16:00:44,666: CMD_CONFIRMENCRYPTION: encryption confirmed 21.08 16:00:44,667: Started resendrequest timer 21.08 16:00:45,063: Remote Version: TV 009.000 21.08 16:00:45,501: start classic authentication 21.08 16:00:45,502: Login::SendRequestToConsole(): url= 21.08 16:00:45,828: start srp authentication 21.08 16:00:46,983: checkFirstPacket ok, m_LastReceivedPacketID =4 21.08 16:00:47,148: Login::SendRequestToConsole(): url= 21.08 16:00:47,478: start srp authentication 21.08 16:00:48,210: Login::SendRequestToConsole(): url= 21.08 16:00:48,485: checkFirstPacket ok, m_LastReceivedPacketID =7 21.08 16:00:48,780: TVCmdAuthenticate_Authenticated: 1 21.08 16:00:49,321: Connected to 910035824, name=NEWMAN, os=14, version=9.0.31064 21.08 16:00:49,329: ConnectionAccessSettings: RemoteControl: AllowedFileTransfer: AllowedControlRemoteTV: AllowedSwitchSides: DeniedAllowDisableRemoteInput: AllowedAllowVPN: AllowedAllowPartnerViewDesktop: Allowed 21.08 16:00:52,195: unexpected TVCommand.CommandType == 56 21.08 16:00:52,231: CW received display params: 1680x1050x8 monitors: 2 (active:0) 21.08 16:00:52,301: Caching active, version=2 21.08 16:03:47,158: CW received display params: 1680x1050x8 monitors: 2 (active:1) 21.08 16:04:24,447: CW received display params: 1680x1050x8 monitors: 2 (active:0) 21.08 16:04:40,609: CW received display params: 3360x1050x8 monitors: 2 (active:-1) 21.08 16:04:59,802: CW received display params: 1680x1050x8 monitors: 2 (active:1) 21.08 16:04:59,933: CW received display params: 1680x1050x8 monitors: 2 (active:1) 21.08 16:05:58,419: CW received display params: 1680x1050x8 monitors: 2 (active:0) 21.08 16:06:36,824: CW received display params: 1680x1050x8 monitors: 2 (active:1) 21.08 16:07:07,232: CW received display params: 1680x1050x8 monitors: 2 (active:0)

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  • How to avoid open-redirect vulnerability and safely redirect on successful login (HINT: ASP.NET MVC

    - by Brad B.
    Normally, when a site requires that you are logged in before you can access a certain page, you are taken to the login screen and after successfully authenticating yourself, you are redirected back to the originally requested page. This is great for usability - but without careful scrutiny, this feature can easily become an open redirect vulnerability. Sadly, for an example of this vulnerability, look no further than the default LogOn action provided by ASP.NET MVC 2: [HttpPost] public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (!String.IsNullOrEmpty(returnUrl)) { return Redirect(returnUrl); // open redirect vulnerability HERE } else { return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "User name or password incorrect..."); } } return View(model); } If a user is successfully authenticated, they are redirected to "returnUrl" (if it was provided via the login form submission). Here is a simple example attack (one of many, actually) that exploits this vulnerability: Attacker, pretending to be victim's bank, sends an email to victim containing a link, like this: http://www.mybank.com/logon?returnUrl=http://www.badsite.com Having been taught to verify the ENTIRE domain name (e.g., google.com = GOOD, google.com.as31x.example.com = BAD), the victim knows the link is OK - there isn't any tricky sub-domain phishing going on. The victim clicks the link, sees their actual familiar banking website and is asked to logon Victim logs on and is subsequently redirected to http://www.badsite.com which is made to look exactly like victim's bank's website, so victim doesn't know he is now on a different site. http://www.badsite.com says something like "We need to update our records - please type in some extremely personal information below: [ssn], [address], [phone number], etc." Victim, still thinking he is on his banking website, falls for the ploy and provides attacker with the information Any ideas on how to maintain this redirect-on-successful-login functionality yet avoid the open-redirect vulnerability? I'm leaning toward the option of splitting the "returnUrl" parameter into controller/action parts and use "RedirectToRouteResult" instead of simply "Redirect". Does this approach open any new vulnerabilities? Side note: I know this open-redirect may not seem to be a big deal compared to the likes of XSS and CSRF, but us developers are the only thing protecting our customers from the bad guys - anything we can do to make the bad guys' job harder is a win in my book. Thanks, Brad

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  • SQL 2008 R2 login/network issue

    - by martinjd
    I have a Windows Server 2008 R2 new clean install , not a VM, that I have added to a Windows Server 2003 based domain using my account which has domain admin rights. The domain functional level is 2003. I performed a clean install of SQL Server 2008 R2 using my account which has domain admin rights. The installation completed without any errors. I logged into SSMS locally and attempted to add another domain account by clicking Search, Advanced and finding the user in the domain. When I return to the "Dialog - New" window and click OK I receive the following error: Create failed for Login 'Domain\User'. (Microsoft.SqlServer.Smo) An exception occurred while executing a Transact-SQL statement or batch. (Microsoft.SqlServer.ConnectionInfo) Windows NT user or group 'Domain\User' not found. Check the name again. (Microsoft SQL Server, Error: 15401) I have verified that the firewall is off, tried adding a different domain user, tried using SA to add a user, installed the hotfix for KB 976494 and verified that the Local Security Policy for Domain Member: Digitally encrypt or sign secure channel Domain Member: Digitally encrypt secure channel Domain Member: Digitally sign secure channel are disabled none of which have made a difference. I can RDP to a Server 2003 server running SQL 2008 and add the same domain user without issue. Also if I try to connect with SSMS to the sql server from another system on the domain using my account I get the following error: Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452) and on the database server I see the following in the security event log: An account failed to log on. Subject: Security ID: NULL SID Account Name: - Account Domain: - Logon ID: 0x0 Logon Type: 3 Account For Which Logon Failed: Security ID: NULL SID Account Name: myUserName Account Domain: MYDOMAIN Failure Information: Failure Reason: An Error occured during Logon. Status: 0xc000018d Sub Status: 0x0 Process Information: Caller Process ID: 0x0 Caller Process Name: - Network Information: Workstation Name: MYWKS Source Network Address: - Source Port: - Detailed Authentication Information: Logon Process: NtLmSsp Authentication Package: NTLM Transited Services: - Package Name (NTLM only): - Key Length: 0 I am sure that the "NULL SID" has some significant meaning but have no idea at this point what the issue could be.

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  • IPhone Example : Login Page and then Navigate to another Screen (UI Table View)

    - by Smc
    Hi, I am an .Net Expert but a new to the IPhone App Development. Recently I have started workinf on Objective - c. I need a help I need a example which shows a Login Screen and then Navigates to the another Screen (UITableView) when username and password and found correct. As of now I am assuming that username and passwords are hardcoded in app. I have tried to Design the Screen for Login UI but unable to Load the another ViewController but it wont worked Can some one help me out with examples, Links?

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