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  • problem to create session of facebook login

    - by khoyendra
    import com.facebook.api.FacebookRestClient; import org.apache.commons.httpclient.HttpClient; import org.apache.commons.httpclient.HttpState; import org.apache.commons.httpclient.NameValuePair; import org.apache.commons.httpclient.methods.GetMethod; import org.apache.commons.httpclient.methods.PostMethod; import org.apache.commons.httpclient.params.HttpClientParams; public class FaceLogin { public FaceLogin(){ getUserID("xxxxxx", "xxxxxx"); } private static void getUserID(String email, String password){ String session = null; try { HttpClient http = new HttpClient(); http.setParams(new HttpClientParams()); http.setState(new HttpState()); String api_key = "API KEY"; String secret = "SECRETS"; FacebookRestClient client = new FacebookRestClient(api_key, secret); client.setIsDesktop(true); String token = client.auth_createToken(); final String loginId = "http://www.facebook.com/login.php"; GetMethod get = new GetMethod(loginId + "?api_key=" + api_key + "&v=1.0&auth_token=" +token); System.out.println("Get="+get); http.executeMethod(get); PostMethod post = new PostMethod(loginId); post.addParameter(new NameValuePair("api_key", api_key)); post.addParameter(new NameValuePair("v", "1.0")); post.addParameter(new NameValuePair("auth_token", token)); post.addParameter(new NameValuePair("fbconnect","true")); post.addParameter(new NameValuePair("return_session","true")); post.addParameter(new NameValuePair("session_key_only","true")); post.addParameter(new NameValuePair("req_perms","read_stream,publish_stream")); post.addParameter(new NameValuePair("lsd","8HYdi")); post.addParameter(new NameValuePair("locale","en_US")); post.addParameter(new NameValuePair("persistent","1")); post.addParameter(new NameValuePair("email", email)); post.addParameter(new NameValuePair("pass", password)); System.out.println("Token ="+token); int postStatus = http.executeMethod(post); System.out.println("Response : " + postStatus); session = client.auth_getSession(token); // Here I am getting error System.out.println("Session string: " + session); long userid = client.users_getLoggedInUser(); System.out.println("User Id is : " + userid); } catch (Exception e) { e.printStackTrace(); } } public static void main(String k[]) { FacebookLogin facebookLoginObj=new FacebookLogin(); } } here i have to find some error when i create session error is run: Get=org.apache.commons.httpclient.methods.GetMethod@17ec9f7 Token =0c578e0692ae04327cd29a4beede48e3 Jun 8, 2010 7:04:48 PM org.apache.commons.httpclient.HttpMethodBase processResponseHeaders WARNING: Cookie rejected: "$Version=0; $Domain=deleted; $Path=/; $Domain=.facebook.com". Cookie name may not start with $ Response : 200 Jun 8, 2010 7:04:48 PM org.apache.commons.httpclient.HttpMethodBase processResponseHeaders WARNING: Cookie rejected: "$Version=0; $Path=deleted; $Path=/; $Domain=.facebook.com". Cookie name may not start with $ Facebook returns error code 100 - v -> 1.0 - auth_token -> 0c578e0692ae04327cd29a4beede48e3 - method -> facebook.auth.getSession com.facebook.api.FacebookException: Invalid parameter - call_id -> 1276004088734 - api_key -> f7cb1e48c383ef599da9021fc4dec322 - sig -> 8b7f0a5394b25551ab3cf1487ac0da00 at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:828) at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:606) at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:606) at com.facebook.api.FacebookRestClient.auth_getSession(FacebookRestClient.java:1891) at facebookcrawler.FacebookLogin.getUserID(FacebookLogin.java:81) at facebookcrawler.FacebookLogin.<init>(FacebookLogin.java:24) at facebookcrawler.FaceLogin.main(FaceLogin.java:80) BUILD SUCCESSFUL (total time: 7 seconds)

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  • Failure with LogonUser in MC++

    - by Alikar
    After fighting with this for a week I have not really gotten anywhere in why it constantly fails in my code, but not in other examples. My code, which while it compiles, will not log into a user that I know has the correct login information. Where it fails is the following line: wi = gcnew WindowsIdentity(token); It fails here because the token is zero, meaning that it was never set to a user token. Here is my full code: #ifndef UNCAPI_H #define UNCAPI_H #include <windows.h> #pragma once using namespace System; using namespace System::Runtime::InteropServices; using namespace System::Security::Principal; using namespace System::Security::Permissions; namespace UNCAPI { public ref class UNCAccess { public: //bool Logon(String ^_srUsername, String ^_srDomain, String ^_srPassword); [PermissionSetAttribute(SecurityAction::Demand, Name = "FullTrust")] bool Logon(String ^_srUsername, String ^_srDomain, String ^_srPassword) { bool bSuccess = false; token = IntPtr(0); bSuccess = LogonUser(_srUsername, _srDomain, _srPassword, 8, 0, &tokenHandle); if(bSuccess) { wi = gcnew WindowsIdentity(token); wic = wi->Impersonate(); } return bSuccess; } void UNCAccess::Logoff() { if (wic != nullptr ) { wic->Undo(); } CloseHandle((int*)token.ToPointer()); } private: [DllImport("advapi32.dll", SetLastError=true)]//[DllImport("advapi32.DLL", EntryPoint="LogonUserW", SetLastError=true, CharSet=CharSet::Unicode, ExactSpelling=true, CallingConvention=CallingConvention::StdCall)] bool static LogonUser(String ^lpszUsername, String ^lpszDomain, String ^lpszPassword, int dwLogonType, int dwLogonProvider, IntPtr *phToken); [DllImport("KERNEL32.DLL", EntryPoint="CloseHandle", SetLastError=true, CharSet=CharSet::Unicode, ExactSpelling=true, CallingConvention=CallingConvention::StdCall)] bool static CloseHandle(int *handle); IntPtr token; WindowsIdentity ^wi; WindowsImpersonationContext ^wic; };// End of Class UNCAccess }// End of Name Space #endif UNCAPI_H Now using this slightly modified example from Microsoft I was able to get a login and a token: #using <mscorlib.dll> #using <System.dll> using namespace System; using namespace System::Runtime::InteropServices; using namespace System::Security::Principal; using namespace System::Security::Permissions; [assembly:SecurityPermissionAttribute(SecurityAction::RequestMinimum, UnmanagedCode=true)] [assembly:PermissionSetAttribute(SecurityAction::RequestMinimum, Name = "FullTrust")]; [DllImport("advapi32.dll", SetLastError=true)] bool LogonUser(String^ lpszUsername, String^ lpszDomain, String^ lpszPassword, int dwLogonType, int dwLogonProvider, IntPtr* phToken); [DllImport("kernel32.dll", CharSet=System::Runtime::InteropServices::CharSet::Auto)] int FormatMessage(int dwFlags, IntPtr* lpSource, int dwMessageId, int dwLanguageId, String^ lpBuffer, int nSize, IntPtr *Arguments); [DllImport("kernel32.dll", CharSet=CharSet::Auto)] bool CloseHandle(IntPtr handle); [DllImport("advapi32.dll", CharSet=CharSet::Auto, SetLastError=true)] bool DuplicateToken(IntPtr ExistingTokenHandle, int SECURITY_IMPERSONATION_LEVEL, IntPtr* DuplicateTokenHandle); // GetErrorMessage formats and returns an error message // corresponding to the input errorCode. String^ GetErrorMessage(int errorCode) { int FORMAT_MESSAGE_ALLOCATE_BUFFER = 0x00000100; int FORMAT_MESSAGE_IGNORE_INSERTS = 0x00000200; int FORMAT_MESSAGE_FROM_SYSTEM = 0x00001000; //int errorCode = 0x5; //ERROR_ACCESS_DENIED //throw new System.ComponentModel.Win32Exception(errorCode); int messageSize = 255; String^ lpMsgBuf = ""; int dwFlags = FORMAT_MESSAGE_ALLOCATE_BUFFER | FORMAT_MESSAGE_FROM_SYSTEM | FORMAT_MESSAGE_IGNORE_INSERTS; IntPtr ptrlpSource = IntPtr::Zero; IntPtr prtArguments = IntPtr::Zero; int retVal = FormatMessage(dwFlags, &ptrlpSource, errorCode, 0, lpMsgBuf, messageSize, &prtArguments); if (0 == retVal) { throw gcnew Exception(String::Format( "Failed to format message for error code {0}. ", errorCode)); } return lpMsgBuf; } // Test harness. // If you incorporate this code into a DLL, be sure to demand FullTrust. [PermissionSetAttribute(SecurityAction::Demand, Name = "FullTrust")] int main() { IntPtr tokenHandle = IntPtr(0); IntPtr dupeTokenHandle = IntPtr(0); try { String^ userName; String^ domainName; // Get the user token for the specified user, domain, and password using the // unmanaged LogonUser method. // The local machine name can be used for the domain name to impersonate a user on this machine. Console::Write("Enter the name of the domain on which to log on: "); domainName = Console::ReadLine(); Console::Write("Enter the login of a user on {0} that you wish to impersonate: ", domainName); userName = Console::ReadLine(); Console::Write("Enter the password for {0}: ", userName); const int LOGON32_PROVIDER_DEFAULT = 0; //This parameter causes LogonUser to create a primary token. const int LOGON32_LOGON_INTERACTIVE = 2; const int SecurityImpersonation = 2; tokenHandle = IntPtr::Zero; dupeTokenHandle = IntPtr::Zero; // Call LogonUser to obtain a handle to an access token. bool returnValue = LogonUser(userName, domainName, Console::ReadLine(), LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, &tokenHandle); Console::WriteLine("LogonUser called."); if (false == returnValue) { int ret = Marshal::GetLastWin32Error(); Console::WriteLine("LogonUser failed with error code : {0}", ret); Console::WriteLine("\nError: [{0}] {1}\n", ret, GetErrorMessage(ret)); int errorCode = 0x5; //ERROR_ACCESS_DENIED throw gcnew System::ComponentModel::Win32Exception(errorCode); } Console::WriteLine("Did LogonUser Succeed? {0}", (returnValue?"Yes":"No")); Console::WriteLine("Value of Windows NT token: {0}", tokenHandle); // Check the identity. Console::WriteLine("Before impersonation: {0}", WindowsIdentity::GetCurrent()->Name); bool retVal = DuplicateToken(tokenHandle, SecurityImpersonation, &dupeTokenHandle); if (false == retVal) { CloseHandle(tokenHandle); Console::WriteLine("Exception thrown in trying to duplicate token."); return -1; } // The token that is passed to the following constructor must // be a primary token in order to use it for impersonation. WindowsIdentity^ newId = gcnew WindowsIdentity(dupeTokenHandle); WindowsImpersonationContext^ impersonatedUser = newId->Impersonate(); // Check the identity. Console::WriteLine("After impersonation: {0}", WindowsIdentity::GetCurrent()->Name); // Stop impersonating the user. impersonatedUser->Undo(); // Check the identity. Console::WriteLine("After Undo: {0}", WindowsIdentity::GetCurrent()->Name); // Free the tokens. if (tokenHandle != IntPtr::Zero) CloseHandle(tokenHandle); if (dupeTokenHandle != IntPtr::Zero) CloseHandle(dupeTokenHandle); } catch(Exception^ ex) { Console::WriteLine("Exception occurred. {0}", ex->Message); } Console::ReadLine(); }// end of function Why should Microsoft's code succeed, where mine fails?

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  • Does a lazy-programmer "document template" with tags exist for Windows?

    - by Anthony Forloney
    I was wondering (if possible) if there was a program/tool/utility that when I create a new file and provide it with an extension that it creates the tags automatically? For example, a new file I create called index.php would have the appropriate tags auto-generated inside: <?php ?> I hope you get the idea. Does one, or could one, exist, preferably Windows based? Any information regarding this would be helpful.

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  • Auto complete from database using CodeIgniter (Active Record)

    - by Ralph David Abernathy
    I have a form on my website in which one is able to submit a cat. The form contains inputs such as "Name" and "Gender", but I am just trying to get the auto completion to work with the "Name" field. Here is what my jquery looks like : $(document).ready(function() { $( "#tags" ).autocomplete({ source: '/Anish/auto_cat' }); }); Here is what my model looks like: public function auto_cat($search_term) { $this->db->like('name', $search_term); $response = $this->db->get('anish_cats')->result_array(); // var_dump($response);die; return $response; } } Here is my controller: public function auto_cat(){ $search_term = $this->input->get('term'); $cats = $this->Anish_m->auto_cat($search_term); } And here is my view: <head> <link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" /> <script src="http://code.jquery.com/jquery-1.9.1.js"></script> <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script> <link rel="stylesheet" href="/resources/demos/style.css" /> </head> <h1>Anish's Page</h1> <form action="/Anish/create" method="POST"> <div class="ui-widget"> <label for="tags">Name</label><input id="tags" type="text" name="name"> </div> <div> <label>Age</label><input type="text" name="age"> </div> <div> <label>Gender</label><input type="text" name="gender"> </div> <div> <label>Species</label><input type="text" name="species"> </div> <div> <label>Eye Color</label><input type="text" name="eye_color"> </div> <div> <label>Color</label><input type="text" name="color"> </div> <div> <label>Description</label><input type="text" name="description"> </div> <div> <label>marital status</label><input type="text" name="marital_status"> </div> <br> <button type="submit" class="btn btn-block btn-primary span1">Add cat</button> </form> <br/><br/><br/><br/> <table class="table table-striped table-bordered table-hover"> <thead> <tr> <th>Name</th> <th>Gender</th> <th>Age</th> <th>Species</th> <th>Eye Color</th> <th>Color</th> <th>Description</th> <th>Marital Status</th> <th>Edit</th> <th>Delete</th> </tr> </thead> <tbody> <?php foreach ($cats as $cat):?> <tr> <td> <?php echo ($cat['name']);?><br/> </td> <td> <?php echo ($cat['gender']);?><br/> </td> <td> <?php echo ($cat['age']);?><br/> </td> <td> <?php echo ($cat['species']);?><br/> </td> <td> <?php echo ($cat['eye_color']);?><br/> </td> <td> <?php echo ($cat['color']);?><br/> </td> <td> <?php echo ($cat['description']);?><br/> </td> <td> <?php echo ($cat['marital_status']);?><br/> </td> <td> <form action="/Anish/edit" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id_edit"> <button class="btn btn-block btn-info">Edit</button> </form> </td> <td> <form action="/Anish/delete" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id"> <button class="btn btn-block btn-danger">Delete</button> </form> </td> </tr> <?php endforeach;?> </tbody> </table> I am stuck. In my console, I am able to see this output when I type the letter 'a' if I uncomment the var_dump in my model: array(4) { [0]=> array(9) { ["id"]=> string(2) "13" ["name"]=> string(5) "Anish" ["gender"]=> string(4) "Male" ["age"]=> string(2) "20" ["species"]=> string(3) "Cat" ["eye_color"]=> string(5) "Brown" ["color"]=> string(5) "Black" ["description"]=> string(7) "Awesome" ["marital_status"]=> string(1) "0" } [1]=> array(9) { ["id"]=> string(2) "16" ["name"]=> string(5) "Anish" ["gender"]=> string(2) "fe" ["age"]=> string(2) "23" ["species"]=> string(2) "fe" ["eye_color"]=> string(2) "fe" ["color"]=> string(2) "fe" ["description"]=> string(2) "fe" ["marital_status"]=> string(1) "1" } [2]=> array(9) { ["id"]=> string(2) "17" ["name"]=> string(1) "a" ["gender"]=> string(1) "a" ["age"]=> string(1) "4" ["species"]=> string(1) "a" ["eye_color"]=> string(1) "a" ["color"]=> string(1) "a" ["description"]=> string(1) "a" ["marital_status"]=> string(1) "0" } [3]=> array(9) { ["id"]=> string(2) "18" ["name"]=> string(4) "Matt" ["gender"]=> string(6) "Female" ["age"]=> string(2) "80" ["species"]=> string(6) "ferret" ["eye_color"]=> string(4) "blue" ["color"]=> string(4) "pink" ["description"]=> string(5) "Chill" ["marital_status"]=> string(1) "0" } }

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  • IP blocked because: (smtpauth) Failed SMTP AUTH login from - can someone explain?

    - by gdaniel
    Today I had a few users blocked in our server firewall because of: (smtpauth) Failed SMTP AUTH login from Can someone explain the reason? What does it exactly mean? Could someone be using the our website to access SMTP for spamming purpose? UPDATE: Server info: Centos OS with CPanel and WHM. However no one has access to either. Taking a look at the logs it looks like someone repetitively attempted to login with a known existent user/pass.

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  • Login with Kohana auth module - what am I doing wrong?

    - by keithjgrant
    I'm trying to login with the following controller action, but my login attempt keeps failing (I get the 'invalid username and/or password' message). What am I doing wrong? I also tried the other method given in the examples in the auth documentation, Auth::instance()->login($user->username, $form->password);, but I get the same result. Kohana version is 2.3.4. public function login() { $auth = Auth::instance(); if ($auth->logged_in()) { url::redirect('/account/summary'); } $view = new View('login'); $view->username = ''; $view->password = ''; $post = $this->input->post(); $form = new Validation($post); $form->pre_filter('trim', 'username') ->pre_filter('trim', 'password') ->add_rules('username', 'required'); $failed = false; if (!empty($post) && $form->validate()) { $login = array( 'username' => $form->username, 'password' => $form->password, ); if (ORM::factory('user')->login($login)) { url::redirect('/accounts/summary'); } else { $view->username = $form->username; $view->message = in_array('required', $form->errors()) ? 'Username and password are required.' : 'Invalid username and/or password.'; } } $view->render(true); }

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  • How to implement a Client-side Ajax Login on Asp.Net MVC (A link to the solution for Asp.Net Webform

    - by Matt
    Hi, I'm trying to implement a client-side ajax login on Asp.Net MVC. I used to have this set up just fine on WebForms, but now that I've moved to MVC it's giving me some troubles. If you'd like a tutorial on Client-side Ajax Login for Asp.Net Webforms, it can be found here -- Easy, A++ Now... for some reason it's not working for Asp.Net MVC. I used the exact same tutorial as for the Webforms, except when it executes the ssa.login() (equivalently: Sys.Services.AuthenticationService.login()) it's not doing anything. I have alerts in both the onLoginComplete() function and the onError() function. As well I have an alert before the ssa.login gets called and right after... function loginHandler() { var username = $("#login_UserName").val(); var password = $("#login_Password").val(); var isPersistent = $("#login_RememberMe").attr("checked"); var customInfo = null; var redirectUrl = null; // Log them in. alert("try login"); ssa.login(username, password, isPersistent, customInfo, redirectUrl, onLoginComplete, onError); alert("made it here"); } The first alert fires but the second one doesn't which means the function is failing. Here's the function I pulled from Asp.Net Ajax to show you: function(c, b, a, h, f, d, e, g) { this._invoke(this._get_path(), "Login", false, { userName: c, password: b, createPersistentCookie: a }, Function.createDelegate(this, this._onLoginComplete), Function.createDelegate(this, this._onLoginFailed), [c, b, a, h, f, d, e, g]); } Anyone have any idea of why it's failing?

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  • Python - retrieving info from a syslog file

    - by Johnny
    Ive been asked to do a program using python for an assignment. Ive been given a syslog file and I have to find things out about it How do I find out how many attempts were made to login to the root account? Any advice would be highly appreciated as Im very new to python an completely lost!

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  • Adding Facebook Log in button to PHP code

    - by CMaury
    I am trying to add the new Facebook log in button to my registration page on my Drupal site. I know the following code is wrong, but I don't know the right syntax to implement it: function facebook_user($op, &$edit, &$user, $category = NULL) { switch($op) { // User is registering. case 'register': // Add a Facebook login button. echo ' '; } } What should I use instead of echo? Is there another way I should be going about this? Thanks

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  • How do I stop mail.app and its nag screen from opening upon login in OS X if I don't use it

    - by user26453
    Currently whenever I start OS X (10.6.2), mail.app starts up with a "Welcome to Mail" dialog, asking me to create an account by inputting name, email address, and password. If I cancel this dialog, the app just hangs and I have to force quit it. I do not use the mail.app and I do not want it to start up with OS X. I have checked the login items and it is NOT present in the login items list for my account. I have also ctrl+clicked the doc icon that appears and confirmed there is no option enabled for "Run at Login". If I go ahead and just spam continue through the dialogs for a new account, I can get through to actually using Mail and accessing preferences. I cannot find a startup option in Mail preferences. After I have completed this, if I now restart, Mail does NOT open automatically. However as soon as I delete the account that I created, it once again goes back to popping up a "Welcome to Mail" dialog every time I startup and login. As best as I can tell, it seems OS X checks if an account exists in the Mail app, and if it does not, it will always start up a "Welcome to Mail" dialog on login, regardless if the Mail app is set to run via login items, etc. This is incredibly frustrating given I have no intention of using the Mail app. I realize I can easily leave account info in there (perhaps even disable the account via preferences), but this behavior is ridiculous. ajgs

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  • SQL Server 2008: Getting Login failed for user "Domain\User". Failed to open the explicitly specified database [CLIENT: IP.ADD.RR.ESS]

    - by GodEater
    This is a very similar issue to " SQL Server 2008 login problem with ASP.NET application: Failed to open the explicitly specified database " which unfortunately seems to have gone unsolved. My issue here is subtly different. Firstly the account failing login is not 'NT AUTHORITY\NETWORK SERVICE' - it's an actual domain account. Secondly, there are two machines involved - I gathered from the first question it was a single machine running both the IIS and SQL instances. The application which is trying to connect to the database is an ASP.NET one running on another server (if that makes any different, I'm not sure it does.) The ConnectionString being used in the web.config for the application is : data source=MySQLServer;initial catalog=MyDatabase;integrated security=sspi; And the Application Pool is set to NetworkService for Identity. So - in the web app, I get the following error : Cannot open database "MyDatabase" requested by the login. The login failed. Login failed for user 'MyDomain\WebServerMachineName$' In the SQL Server logs I see : Login failed for user 'MyDomain\WebServerMachineName$'. Reason: Failed to open the explicitly specified database. [CLIENT: Web.Server.IP.Address] Running this bit of SQL against the database in question : USE [MyDatabase] GO SELECT SDP.name AS [User Name], SDP.type_desc AS [User Type], UPPER(SDPS.name) AS [Database Role] FROM sys.database_principals SDP INNER JOIN sys.database_role_members SDRM ON SDP.principal_id=SDRM.member_principal_id INNER JOIN sys.database_principals SDPS ON SDRM.role_principal_id = SDPS.principal_id Gets me this result : MyDomain\WebServerMachineName$ WINDOWS_USER DB_DDLADMIN MyDomain\WebServerMachineName$ WINDOWS_USER DB_DATAREADER MyDomain\WebServerMachineName$ WINDOWS_USER DB_DATAWRITER Which appears to me to indicate I've got the permissions right. Anyone have any idea why it's not working, or how I can narrow the issue down some more?

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  • User accounts in Symfony?

    - by gruner
    I'm new to Symfony. Is my understanding correct that the User class is actually for controlling sessions? But is there built-in login and account creation? I'm not finding it. But if there's an admin backend generator, how can it function without user logins?

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  • Maintaining a secure database of user logins and info?

    - by Rafe Kettler
    I want to have a login form on a charity website I am building (it's for a friend, and I'm learning on the go), and I want to know what languages/software should I learn to build databases for user logins and info? Note: it HAS to be secure and relatively simple to learn for someone with moderate programming experience. Update: I understand that CMSs offer good tools for logins etc. but I want to do this all by myself.

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  • Wordpress loginform

    - by Erik Larsson
    Hello, I have created a loginform that is displayed on the front page. Everything works fine except one thing, if you log in with bad information you get redirected to wp-login.php and the error message pans out there. What i want is so the error message displays at the form on my front page. Is there way of doing this?

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  • How do I disable auto- poster image generation on the video tag?

    - by ekallevig
    I'm using the 'poster' attribute on a video tag and the way it seems to work at least in webkit browsers is that it loads the poster image and then once enough of the video has loaded, it replaces that poster with an auto-generated poster from the video file itself. However, my poster images don't match the auto-generated posters which results in a weird experience of one image loading, then being replaced in a few seconds by the auto-generated image. Is there any way to prevent the auto-generated image from being used?

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  • Automatically change resolution when not in dock

    - by jwir3
    I have Ubuntu 11.04 (yep, I know it's old news) on my Lenovo W520. At home, I have a dock with dual monitors. I have a pretty decent setup - things work almost perfectly (hence the reason I'm reluctant to upgrade... that and I'm not 100% sold on Unity). Anyway, the only annoyance I have is that when I'm on travel, I use the laptop screen. When I un-dock the laptop, I need to manually go into nvidia x-server settings and change the resolution from 'Auto' to 1920x1200, or it will think I have two screens, and my mouse pointer will be able to go way off the left side of the screen. This isn't a big deal, but I need to do it every time I restart the x-server (so if I reboot, or have to kill it, etc...) What would be really nice is if there was a way for it to automatically detect whether or not there is external monitors (which it seems to do already), and switch into the mode I select, depending on which monitors are connected. Is there any way to accomplish this? I've posted my xorg.conf file for reference. # nvidia-settings: X configuration file generated by nvidia-settings # nvidia-settings: version 270.29 (buildd@allspice) Fri Feb 25 14:42:07 UTC 2011 # nvidia-xconfig: X configuration file generated by nvidia-xconfig # nvidia-xconfig: version 275.19 ([email protected]) Tue Jul 12 18:35:38 PDT 2011 #Section "Monitor" # Identifier "Monitor1" # VendorName "Lenovo" # ModelName "ThinkpadLCD" # #HorizSync 28.0 - 33.0 # #VertRefresh 43.0 - 72.0 # #Option "DPMS" #EndSection Section "ServerLayout" Identifier "Layout0" Screen 0 "Screen0" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "0" EndSection Section "InputDevice" Identifier "Mouse0" Driver "mouse" Option "Protocol" "auto" Option "Device" "/dev/psaux" Option "Emulate3Buttons" "no" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" # generated from default Identifier "Keyboard0" Driver "kbd" EndSection Section "Monitor" Identifier "Monitor0" VendorName "Unknown" ModelName "DELL U2410" HorizSync 30.0 - 81.0 VertRefresh 56.0 - 76.0 Option "DPMS" EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "Quadro 1000M" Option "RegistryDwords" "EnableBrightnessControl=1" EndSection Section "Screen" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+120, DFP-6: nvidia-auto-select +1920+0" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+120, DFP-5: nvidia-auto-select +1920+0" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +1920+419, DFP-5: nvidia-auto-select +3840+0, DFP-6: nvidia-auto-select +0+0" # Removed Option "metamodes" "DFP-5: nvidia-auto-select +0+0, DFP-6: 1920x1200 +1920+0" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "NoLogo" "True" Option "TwinViewXineramaInfoOrder" "DFP-0" Option "TwinView" "1" Option "metamodes" "DFP-5: nvidia-auto-select +1920+0, DFP-6: 1920x1200 +0+0" SubSection "Display" Depth 24 EndSubSection EndSection

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  • How to find the next generated value for a auto-increment column?

    - by Tim Büthe
    I face some trouble with IBM DB2's auto-increment columns. At first, all my columns were defined as GENERATED ALWAYS, but since I had trouble with this when using the "db2 import ..." command, I changed them to GENERATED BY DEFAULT. This is necessary, sinceI need the IDs to be consistent, because other tables reference them. So using "db2 import ... modified by identityignore ..." isn't an option. When I now import data, the IDs are inserted correctly, but everytime I do this, I have to remember to set a new start for the auto-increment column by getting the highest Id+1 and alter the column like this: SELECT MAX(mycolumn)+ 1 FROM mytable; ALTER TABLE mytable ALTER COLUMN mycolumn RESTART WITH <above_result>; If I forget this, an Insert-Statement will fail with an duplicate PK error, since the auto-increment column is the primary key. So my question is: Is there a way to find the next value for an auto-increment column, so I could write Statements that would check, if this value is less then the SELECT MAX and needs to be set? Or: Isn't this whole thing as complicated as it seems to me? Could I somehow import data, preserving the IDs and have the auto-increment column still working as expected?

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  • Writing a simple incrementing counter in rails

    - by Trip
    For every Card, I would like to attach a special number to them that increments by one. I assume I can do this all in the controller. def create @card = Card.new(params[:card]) @card.SpecNum = @card.SpecNum ++ ... end Or. I can be blatantly retarded. And maybe the best bet is to add an auto-incremement table to mysql. The problem is the number has to start at a specific number, 1020. Any ideas?

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  • Why does MySQL autoincrement increase on failed inserts?

    - by Sorcy
    A co-worker just made me aware of a very strange MySQL behavior. Assuming you have a table with an auto_increment field and another field that is set to unique (e.g. a username-field). When trying to insert a row with a username thats already in the table the insert fails, as expected. Yet the auto_increment value is increased as can be seen when you insert a valid new entry after several failed attempts. For example, when our last entry looks like this... ID: 10 Username: myname ...and we try five new entries with the same username value on our next insert we will have created a new row like so: ID: 16 Username: mynewname While this is not a big problem in itself it seems like a very silly attack vector to kill a table by flooding it with failed insert requests, as the MySQL Reference Manual states: "The behavior of the auto-increment mechanism is not defined if [...] the value becomes bigger than the maximum integer that can be stored in the specified integer type." Is this expected behavior?

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