Search Results

Search found 3286 results on 132 pages for 'arthur br'.

Page 94/132 | < Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101 | Next Page >

Drop down of Superfish Menu appear under Smart Slide Show in wordpress

- by oscar

Hi, I spent almost my entire Saturday trying to solve this problem and have not had success. Firefox works well, but in IE8 and Chrome, the dropdown menu appears below the Smart Slide Show (Flash). Please could someone help me? the link to the page: http://www.institutoforlanini.com.br/novosite This is the code of the index: <?php get_header (); ?> <div id=conteiner> <div id=content> <div id="slider"> php echo do_shortcode ('[smart_slide_show ]');?> </ div> </div> </div> <! - End of content div -> <?php get_sidebar ();?> <?php get_footer ();?>

Read the article
Array of an array (Database)

- by Anne Mah Li'en

I am trying to print out an array of an array from database Below are my codes. I am able to retrieve all the values from the first array. But error occurs when I am trying to retrieve the 2nd array from database. <% ArrayList<Questionnaire> allCategories =QuestionnaireController.getQuestionnaireByCategoryAll(); for(int i=0;i<allCategories.size();i++){ Questionnaire allCategoriesQuestionnaire=allCategories.get(i); out.println("<div class=\"silverheader\">" + "<a href= \"\">" + allCategoriesQuestionnaire.getCategory() + "</a>" + "</div>" + "<div class=\"submenu\">" + "ArrayList<Questionnaire> CategoriesSustainability =QuestionnaireController.getQuestionnaireByCategorySustainability();" + out.println(CategoriesSustainability.get(0).getCategory()); + "<br />" + "</div>"); } %>

Read the article
Wordpress parses wp_posts.post_content before rendering?

- by John

I noticed that when I call the the_post() or the_content() function from my wordpress template, it automatically parses the database data to replace new lines with <br/>, wraps the text with <p> tags etc...There's probably some kind of "format" function within the_post() or the_content(). I wrote a query to directly get posts from the wp_posts. I then print it out like <?php $results = $wp->get_results($sql) foreach($results as $row) echo $row->post_content; ?> Clearly, this data is not parsed by wordpress' "format" function. What is the proper way to output this content such that it undergoes the same "formatting" functions as the_post() or the_content()?

Read the article
Creating a custom categories widget

- by Scott B

The code below is an attempt to take the WP_Widget_Categories class and use it as the basis for a custom categories widget based on the default categories widget. I'm getting no output however and the widget is not showing up in the "Available Widgets" listing. What am I doing wrong? <?php /* Plugin Name: My Categories Widget Version: 1.0 */ class MY_Widget_Categories extends WP_Widget { function MY_Widget_Categories() { $widget_ops = array( 'classname' => 'widget_categories', 'description' => __( "A list or dropdown of categories" ) ); $this->WP_Widget('categories', __('Categories'), $widget_ops); } function widget( $args, $instance ) { extract( $args ); $title = apply_filters('widget_title', empty( $instance['title'] ) ? __( 'Categories' ) : $instance['title']); $c = $instance['count'] ? '1' : '0'; $h = $instance['hierarchical'] ? '1' : '0'; $d = $instance['dropdown'] ? '1' : '0'; echo $before_widget; if ( $title ) echo $before_title . $title . $after_title; $cat_args = array('orderby' => 'name', 'show_count' => $c, 'hierarchical' => $h); if ( $d ) { $cat_args['show_option_none'] = __('Select Category'); wp_dropdown_categories(apply_filters('widget_categories_dropdown_args', $cat_args)); ?> <script type='text/javascript'> /* <![CDATA[ */ var dropdown = document.getElementById("cat"); function onCatChange() { if ( dropdown.options[dropdown.selectedIndex].value > 0 ) { location.href = "<?php echo get_option('home'); ?>/?cat="+dropdown.options[dropdown.selectedIndex].value; } } dropdown.onchange = onCatChange; /* ]]> */ </script> <?php } else { ?> <ul> <?php $cat_args['title_li'] = ''; wp_list_categories(apply_filters('widget_categories_args', $cat_args)); ?> </ul> <?php } echo $after_widget; } function update( $new_instance, $old_instance ) { $instance = $old_instance; $instance['title'] = strip_tags($new_instance['title']); $instance['count'] = $new_instance['count'] ? 1 : 0; $instance['hierarchical'] = $new_instance['hierarchical'] ? 1 : 0; $instance['dropdown'] = $new_instance['dropdown'] ? 1 : 0; return $instance; } function form( $instance ) { //Defaults $instance = wp_parse_args( (array) $instance, array( 'title' => '') ); $title = esc_attr( $instance['title'] ); $count = isset($instance['count']) ? (bool) $instance['count'] :false; $hierarchical = isset( $instance['hierarchical'] ) ? (bool) $instance['hierarchical'] : false; $dropdown = isset( $instance['dropdown'] ) ? (bool) $instance['dropdown'] : false; ?> <p><label for="<?php echo $this->get_field_id('title'); ?>"><?php _e( 'Title:' ); ?></label> <input class="widefat" id="<?php echo $this->get_field_id('title'); ?>" name="<?php echo $this->get_field_name('title'); ?>" type="text" value="<?php echo $title; ?>" /></p> <p><input type="checkbox" class="checkbox" id="<?php echo $this->get_field_id('dropdown'); ?>" name="<?php echo $this->get_field_name('dropdown'); ?>"<?php checked( $dropdown ); ?> /> <label for="<?php echo $this->get_field_id('dropdown'); ?>"><?php _e( 'Show as dropdown' ); ?></label><br /> <input type="checkbox" class="checkbox" id="<?php echo $this->get_field_id('count'); ?>" name="<?php echo $this->get_field_name('count'); ?>"<?php checked( $count ); ?> /> <label for="<?php echo $this->get_field_id('count'); ?>"><?php _e( 'Show post counts' ); ?></label><br /> <input type="checkbox" class="checkbox" id="<?php echo $this->get_field_id('hierarchical'); ?>" name="<?php echo $this->get_field_name('hierarchical'); ?>"<?php checked( $hierarchical ); ?> /> <label for="<?php echo $this->get_field_id('hierarchical'); ?>"><?php _e( 'Show hierarchy' ); ?></label></p> <?php } } function my_categories_init() { register_sidebar_widget(__('My Categories Widget'), 'MY_Widget_Categories'); } add_action("plugins_loaded", "my_categories_init"); ?>

Read the article
PHP: documentElement->childNodes warning

- by jun

$xml = file_get_contents(example.com); $dom = new DomDocument(); $dom->loadXML($xml); $items = $dom->documentElement; foreach($items->childNodes as $item) { $childs = $item->childNodes; foreach($childs as $i) { echo $i->nodeValue . "<br />"; } } Now I get this warning in every 2nd foreach: Warning: Invalid argument supplied for foreach() in file_example.php on line 14 Please help guys. Thanks!

Read the article
php: two objects from the same class work independent of each other

- by user317563

Good morning, I would like the code in my controller to look something like this: <?php $class = new sanitizeInput() $string1 = $class -> input($_POST[name]) -> mysql_escape(); $string2 = $class -> input($_POST[age]) -> mysql_escape(); print " String1: $string1 <br /> String2: $string2" ?> It seems with my sanitizeInput class, any change to $string2 is applied to $string1. What ways can I change this? I would preferably like to make the changes within the class to make my controller as easily read as possible. Thank you for your time. Kind regards, Marius

Read the article
PHP - Why does my computation produce a different result when I assign it to a variable?

- by David

I want to round a number to a specific number of significant digits - basically I want the following function: round(12345.67, 2) -> 12000 round(8888, 3) -> 8890 I have the following, but there's a strange problem. function round_to_sf($number, $sf) { $mostsigplace = floor(log10(abs($number)))+1; $num = $number / pow(10, ($mostsigplace-$sf)); echo ($number / pow(10, ($mostsigplace-$sf))).' '.$num.'<BR>'; } round_to_sf(41918.522, 1); Produces the following output: 4.1918522 -0 How can the result of a computation be different when it's assigned to a variable?

Read the article
Problem with PHP array index.

- by user632027

Following code: <?php $test_array = array(); $test_array['string_index'] = "data in string index"; $test_array[] = "data in index 0"; $test_array[] = "data in index 1"; $test_array[] = "data in index 2"; foreach($test_array as $key => $val) { if($key != 'string_index') { echo $val."<br>"; } } ?> gives result: data in index 1 data in index 2 Question is - where is "data in index 0"??? How to get elements from numeric indices 0-n? Also if I change 'string_index' to something else which doesn't exist, it echoes everything except [0]. Plz, explain me this. Thnx in advance

Read the article
Customizing Django Form: Required and InputId?

- by Mark

I'm trying to customize how my form is displayed by using a form_snippet as suggested in the docs. Here's what I've come up with so far: {% for field in form %} <tr> <th><label for="{{ field.html_name }}">{{ field.label }}:</label></th> <td> {{ field }} {% if field.help_text %}<br/><small class="help_text">{{ field.help_text }}</small>{% endif %} {{ field.errors }} </td> </tr> {% endfor %} Of course, field.html_name is not what I'm looking for. I need the id of the input field. How can I get that? Also, is there a way I can determine if the field is required, so that I can display an asterisk beside the label?

Read the article
Radio button how to?

- by Azzyh

what i want to do is that when you vote Y or N (two different radio buttons) and then it inserts into the "vote" column(in database) = Y or N(what you pickd), if nothing then echo error. I know how to do this like halfway, i never worked with radiobuttons before so i need you guys. Here's a two radio button right: Yes: <input type="radio" value="Y" id="voteYes" name="vote"></input> <br> No: <input type="radio" value="N" id="voteNo" name="vote"> </input> I gave the value N and Y, not the same ID, but the same name. I think its right, but how should i do with the PHP part of what i want to do? I mean shall i call for "vote"? ($_GET["vote"]) i dont think so.. here's where im stuck

Read the article
date() returning wrong day although the timestamp is correct!

- by Spiros

I have a bizzare problem with php date function. code: $numDays = 8; $date = strtotime('2010-11-06'); for ($i=1; $i<=$numDays; $i++) { $thisDay = date("D, d M Y", $date); print ($thisDay.'<br>'); $date+=86400; // add one day to timestamp } result on my server (local host, windows): Sat, 06 Nov 2010 Sun, 07 Nov 2010 Mon, 08 Nov 2010 Tue, 09 Nov 2010 Wed, 10 Nov 2010 Thu, 11 Nov 2010 Fri, 12 Nov 2010 Sat, 13 Nov 2010 Result on my web server (linux) Sat, 06 Nov 2010 *Sun, 07 Nov 2010 Sun, 07 Nov 2010* Mon, 08 Nov 2010 Tue, 09 Nov 2010 Wed, 10 Nov 2010 Thu, 11 Nov 2010 Fri, 12 Nov 2010 Notice how Sun, 07 Nov 2010 appears twice on the remote server?? Why is this happening? can anyone explain this Behavior?

Read the article
Creating a PHP web page that enables you to reboot the server in Linux?

- by Stuart

I want to create a web page that allows the user to initiate a reboot on the linux server. Obviously this would only be avaliable for system admins and would also be controlled by using iptables. Below is a sample of code that I was thinking of using but I wanted to know if there is another way to do this and how also to use this in a web page? Also is there any thing else that I should consider? $command = "cat $pass | su -c 'shutdown -r now'"; $output = array(); try{ echo shell_exec($command); exec($command, $output); system($command, $output); } catch(Exception $e) { print "Unable to shutdown system...\n"; } foreach ($output as $line) { print "$line<br>"; } Thanks in advance.

Read the article
Add method to Array in Javascript

- by user1167650

Is it possible to add a method to an array() in javascript? (I know about prototypes, but I don't want to add a method to every array, just one in particular). The reason I want to do this is because I have the following code function drawChart() { //... return [list of important vars] } function updateChart(importantVars) { //... } var importantVars = drawChart(); updateChart(importantVars); And I want to be able to do something like this instead: var chart = drawChart();<br> chart.redraw(); I was hoping there was a way I could just attach a method to what i'm returning in drawChart(). Any way to do that?

Read the article
php random image file name

- by bush man

Okay im using a snippet I found on google to take a users uploaded image and put it in my directory under Content But Im worried about duplicates so I was going have it upload the image as a Random number well here is my code you can probably understand what im going for through it anyways <label for="file">Profile Pic:</label> <input type="file" name="ProfilePic" id="ProfilePic" /><br /> <input type="submit" name="submit" value="Submit" /> $ProfilePicName = $_FILES["ProfilePic"]["name"]; $ProfilePicType = $_FILES["ProfilePic"]["type"]; $ProfilePicSize = $_FILES["ProfilePic"]["size"]; $ProfilePicTemp = $_FILES["ProfilePic"]["tmp_name"]; $ProfilePicError = $_FILES["ProfilePic"]["error"]; $RandomAccountNumber = mt_rand(1, 99999); echo $RandomAccountNumber; move_uploaded_file($ProfilePicTemp, "Content/".$RandomAccountNumber.$ProfilePicType); And then basicly after all this Im going try to get it to put that random number in my database

Read the article
select similar value from MySQL and order the result

- by mathew

how do I order this result?? $range = 5; // you'll be selecting around this range. $min = $rank - $range; $max = $rank + $range; $limit = 10; // max number of results you want. $result = mysql_query("select * from table where rank between $min and $max limit $limit"); while($row = mysql_fetch_array($result)) { echo $row['name']." - ".$row['rank']."<br>"; }

Read the article
Nested <a> and <span> challenge

- by PaddyO

Hi all, Trying in vain to get a nested link working within a nested span. This is a working test page for the code below to explain what I'm trying to do. Any ideas on how to get this working in valid html? I guess it's either a nesting order or style syntax thing but I am at a loss. Any thoughts much appreciated. <div id="greyback"> <ul id="scrollbox"> <li class="listcat">List header</li> <li><a class="menu" href="#freeze">List item 1<span><b>This text has popped up because you have clicked the list item, which has an "a" tag and now has :focus. That "a" tag is the first of two.</b><br><br>What I am trying to do is to set the second "a" tag as a DIFFERENT "embedded" link in this box<span style="color: blue; background-color: yellow;">eg, here<a href="http://www.conservationenterprises.com" target="blank">This is the second (nested) "a" tag in this html nest. It is a link to an external site. Instead of this being an always-visible link, I want it to sit within the yellow box in the first span (click the List item 1 to display).</a></span> </a></span> </li> </a></span> </li> </ul> </div> and the CSS: #scrollbox {margin: 0 auto; margin-top: 1em; margin-bottom: 1em; width:19em; height:auto; max-height: 21em; overflow:auto; border-bottom: 0.1em solid #FFA500; border-top: 0.1em solid #FFA500;} #scrollbox a {float: left; color:#000000; text-decoration:none; width:18em; height: auto; margin-bottom: 0.5em; font-family: Arial, sans-serif; font-size: 0.9em; text-align:left;} #scrollbox a.menu {} #scrollbox a span {display:none; position:absolute; left:0em; top:0;} #scrollbox a span img {float: right; border:0; max-width:7.5em;} #scrollbox a:hover {border: 0; color: #7ebb11; font-size:0.9em;} #scrollbox a:hover span {border: 0; color: #535353;} #scrollbox a span:focus {color: blue;} #scrollbox a:active {border:none; color: #535353; text-decoration: none;} #scrollbox a:focus {border:0em solid #000; outline:0;} #scrollbox a:active span, #scrollbox li a:active span, #scrollbox a:focus span, #scrollbox li a:focus span {display: block; width: 52.5em; min-height: 20em; height: auto; left: 1.5em; top:18em; z-index:10; font-size:0.9em; text-align: left; padding: 1em; padding-bottom: 0em; background-color: #c3FFe3; color: #535353; border: solid #FFA500 0.25em;} #scrollbox li a:active span span, #scrollbox li a:focus span span{display: block; width: auto; height: auto; min-height: 2em; left: 25em; top:10em; z-index:10; font-size:0.9em; text-align: left; padding: 1em; padding-bottom: 0em; background-color: transparent; color: #535353; border: dashed red 1px;} .ul#scrollbox {padding-left: 0.1em;} #scrollbox li {float:left; list-style: none; background: url(blank.png) no-repeat left center; margin-left: 0em; font-family:Arial, sans-serif; font-size: 0.9em;} #scrollbox li.listcat {float: left; text-align:left; width: 18em; margin-left: 0em; margin-top: 0.1em; margin-bottom: 0.3em; padding-top:0.5em; color: green; font-size: 0.9em; font-weight:bold;} Cheers Patrick.

Read the article
display result in status after it post

- by nisardotnet

my question is continuation of what i have posted here i want to know how to display a result status based on my return result from Web Method here is my post code: beforeSubmit: function(data) { var myData = { "firstName": escape($('#txtFirstName').val()), "lastName": escape($('#txtLastName').val()) }; $.ajax(<br> { type: "POST", url: "VisitorWS.asmx/AddVisitors", data: JSON.stringify(myData), contentType: "application/json; charset=utf-8", dataType: "json", success: function(data) { $("#status").fadeTo(500, 1, function() { $(this).html("You are now registered!").fadeTo(5000, 0); }) }, error: function(data) { $("#status").fadeTo(5000, 1, function() { $(this).html("Failed!").fadeTo(5000, 0); }) } }); WebMethod [WebMethod] public bool AddVisitors(string firstName, string lastName) { if (firstName == "test") { return true; } return false; } so based on true or false i want to display a message on the client side.

Read the article
How can i check if user entering correct form of email

- by deerox

Well i am not using email verification so i am facing problem in checking correct form of email address suppose if user enter support or support@ it accept it as well. So i atleast want them to enter there email or at least they enter email form correctly Here is my code: <?php require_once 'global.php'; if (!isset($_SESSION['logged_in'])) { header("Location: login.php"); } $user = unserialize($_SESSION['user']); $email = $user->email; $message = ""; if (isset($_POST['submit-settings'])) { $email = $_POST['email']; $user->email = $email; $user->save(); $msg = "Done!<br/>"; } ?>

Read the article
submit button on html to output result on same page

- by amateur

Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

Read the article
php - How do I get rid of this strange "empty delimiter" message

- by Steven

I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

Read the article
PHP IF statement not taking variable into account!

- by Jess

I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

Read the article
How do I update mysql database when posting form without using hidden inputs?

- by user1322707

I have a "members" table in mysql which has approximately 200 field names. Each user is given up to 7 website templates with 26 different values they can insert unique data into for each template. Each time they create a template, they post the form with the 26 associated values. These 26 field names are the same for each template, but are differentiated by an integer at the end, ie _1, _2, ... _7. In the form submitting the template, I have a variable called $pid_sum which is inserted at the end of each field name to identify which template they are creating. For instance: <form method='post' action='create.template.php'> <input type='hidden' name='address_1' value='address_1'> <input type='hidden' name='city_1' value='city_1'> <input type='hidden' name='state_1' value='state_1'> etc... <input type='hidden' name='address_1' value='address_2'> <input type='hidden' name='city_1' value='city_2'> <input type='hidden' name='state_1' value='state_2'> etc... <input type='hidden' name='address_2' value='address_3'> <input type='hidden' name='city_2' value='city_3'> <input type='hidden' name='state_2' value='state_3'> etc... <input type='hidden' name='address_2' value='address_4'> <input type='hidden' name='city_2' value='city_4'> <input type='hidden' name='state_2' value='state_4'> etc... <input type='hidden' name='address_2' value='address_5'> <input type='hidden' name='city_2' value='city_5'> <input type='hidden' name='state_2' value='state_5'> etc... <input type='hidden' name='address_2' value='address_6'> <input type='hidden' name='city_2' value='city_6'> <input type='hidden' name='state_2' value='state_6'> etc... <input type='hidden' name='address_2' value='address_7'> <input type='hidden' name='city_2' value='city_7'> <input type='hidden' name='state_2' value='state_7'> etc... // Visible form user fills out in creating their template ($pid_sum converts // into an integer 1-7, depending on what template they are filling out) <input type='' name='address_$pid_sum'> <input type='' name='city_$pid_sum'> <input type='' name='state_$pid_sum'> etc... <input type='submit' name='save_button' id='save_button' value='Save Settings'> <form> Each of these need updated in a hidden input tag with each form post, or the values in the database table (which aren't submitted with the form) get deleted. So I am forced to insert approximately 175 hidden input tags with every creation of 26 new values for one of the 7 templates. Is there a PHP function or command that would enable me to update all these values without inserting 175 hidden input tags within each form post? Here is the create.template.php file which the form action calls: <?php $q=new Cdb; $t->set_file("content", "create_template.html"); $q2=new CDB; $query="SELECT menu_category FROM menus WHERE link='create.template.ag.php'"; $q2->query($query); $toall=0; if ($q2->nf()<1) { $toall=1; } while ($q2->next_record()) { if ($q2->f('menu_category')=="main") { $toall=1; } } if ($toall==0) { get_logged_info(); $q2=new CDB; $query="SELECT id FROM menus WHERE link='create_template.php'"; $q2->query($query); $q2->next_record(); $query="SELECT membership_id FROM menu_permissions WHERE menu_item='".$q2->f("id")."'"; $q2->query($query); while ($q2->next_record()) { $permissions[]=$q2->f("membership_id"); } if (count($permissions)>0) { $error='<center><font color="red"><b>You do not have access to this area!<br><br>Upgrade your membership level!</b></font></center>'; foreach ($permissions as $value) { if ($value==$q->f("membership_id")) { $error=''; break; } } if ($error!="") { die("$error"); } } } $member_id=$q->f("id"); $pid=$q->f("pid"); $pid_sum = $pid +1; $first_name=$q->f("first_name"); $last_name=$q->f("last_name"); $email=$q->f("email"); echo " // THIS IS WHERE THE HTML FORM GOES "; replace_tags_t($q->f("id"), $t); ?>

Read the article
What is wrong with selecting with my drop down element.

- by Babiker

<html> <head> <script type='text/javascript' language='javascript' src="http://localhost/javascript/jquery-1.4.2.js"> </script> <script type='text/javascript' language='javascript'> $(document).ready(function(){ $("#button").mousedown(function(){ dropDownMenu = $("#dropDownMenu"); alert(dropDownMenu.options[0].text); }); }); </script> </head> <body> <select id="dropDownMenu"><option>Test</option></select><br> <input id="button" type="button"> </body> </html>

Read the article
Array to string conversion in (cant get it to work)

- by user2966551

ok I am trying to pull a a specific row of data that corresponds to the username logged in. on my page I have started my session but for some reason I cant get the code to work.i keep getting a "Array to string conversion in " on the line " WHERE username = '$_SESSION[user]'");" what am I doing wrong? if I set username = a set username it works but I need it to draw from the session id so it will display different values based on whos logged in. <?php $con=mysqli_connect("localhost","root","xxx","xxxx"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $result = mysqli_query($con,"SELECT * FROM users WHERE username = '$_SESSION[user]'"); while($row = mysqli_fetch_array($result)) { echo $row['username'] . " " . $row['att']; echo "<br>"; } ?>

Read the article
open window with dynamic content

- by julio

Is it possible to open a window from PHP that has predefined content? It's obvious how you can open a window from a javascript link that frames an existing page, or just do a target=_blank from a regular a tag that references an existing page. But I am generating a bit of content, and want that content to be opened in a new link (or streamed to the viewer)-- something like (clearly psuedo code!): $content = "Hello World. <br />Nice to meet you!"; <a href="#" target="_blank" content=$content>Open up!</a> Is this possible? Thanks!

Read the article

< Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101 | Next Page >