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  • Blank installNotifyURI in OMA Download Descriptors

    - by joynes
    People can download content (music, images) for their mobile from my server. Im trying to use the installNotifyURI-tag of the download descriptors specified by OMA, to be able to find out if the download has been successful. When the user has downloaded the item I do get a POST to the url I specified in the installNotifyURI-tag. <installNotifyURIhttp://joynes.se/mytest.php</installNotifyURI Although I never get any status code. The POST is just blank. Anyone who knows about this problem? /Br Johannes

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  • Apache rewrite to add a directory to REQUEST_URI not working on localhost running wamp.

    - by Brett Pontarelli
    I'm running wamp on Vista (Apache v2.2.11) and have projects setup such that http://localhost/projectx is the base directory for projectx. Now, I want that requests for http://localhost/projectx/somepage/extra will rewrite to http://localhost/projectx/PUBLIC/somepage/extra To that end I have a file in C:\wamp\www\projectx\.htacces that is this simple: RewriteEngine On RewriteBase /projectx RewriteCond %{REQUEST_URI} !^/PUBLIC RewriteRule ^(.*)$ /PUBLIC$1 [L] I can't for the life of me figure out why this doesn't work. The error I'm getting is "The requested URL /PUBLIC was not found on this server". Thanks.

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  • Loading Files in AppEngine

    - by Chris M
    I've got a tiny bit of code to display a file in app.yaml - url: /(.*\.(gif|png|jpg)) static_files: static/\1 upload: static/(.*\.(gif|png|jpg)) in main.py ... class ShowImage(webapp.RequestHandler): def get(self): rootpath = os.path.dirname(__file__) file = rootpath + "/static/tracker.gif"; fh=open(file, 'r') self.response.out.write(fh.read()) fh.close ... I can see the files gone up by going to my *.appspot.com/tracker.gif (as per the app.yaml) But using *.appspot.com/showimage returns Traceback (most recent call last): File "/base/python_lib/versions/1/google/appengine/ext/webapp/__init__.py", line 510, in __call__ handler.get(*groups) File "/base/data/home/apps/APPNAME/2.341131266814384624/main.py", line 170, in get fh=open(file, 'r') IOError: [Errno 2] No such file or directory: '/base/data/home/apps/APPNAME/2.341131266814384624/static/tracker.gif'

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  • How do i redirect to a GET request from a POST request on GAE

    - by user259349
    Hello everyone, i am writing an FBML app on facebook hosted in GAE. Facebook will talk to your hosted app only vai POST (im sure this is the cause, but please do correct me if i'm wrong). So im faced with the issue that inside of my POST method, i need to redirect to facebook OAuth authroize URL. But i can only send a GET request. How can i do that? At the moment i'm doing class OauthHandler(webapp.RequestHandler): def post(self): # blablablab request.redirect(oauth_uri) Which is wrong since the oauth_uri is only responding to GET. Further more, OAuth will redirect back to my redirect handler through GET, but i cant! i can only do post. So i'm confused. ideas? Thanks in advance

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  • how to execute javascript in delphi?

    - by radick
    hi all i am coding a small app ,in middle i struck at some point where i have to execute javascript to get my data ? in my process ,i have to login to some url and then go to some page and have to get data from that . i done all this with indy idhttp ,i got all info except one column which needs javascript to get value ,then i itried to using twebbowser to make it work for me ,but how can i use cookies to enabled to webbrowser ? i navigated browserto('http://mysite.com/login.php user and pass ') ,well its loged in and then i tried to access next link like ('http://mysite.com/link1/example.php')but it directing to login page :( any help appreciated :)

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  • Illustration for code presentation

    - by Lasse V. Karlsen
    I got an odd request, and I fear it will be closed as off-topic. So be it, but it's worth a shot. I'm creating a presentation about dependency injection and inversion of control, and I thought I'd make the point of interchangeable parts that serve a common purpose, but has different implementations, by showing an image I've seen before. Basically the image is of a man or a woman, but the image is split up into four parts: Head Torso uhm... not sure the name of this part, stomach, etc. Legs Possibly a fifth with feet and for each part you can choose among a few variants, creating odd people in the process. ie. a man torso with a woman head. But, I can't find such an image now of course. Does anyone know of such an image and can provide me with an url?

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  • Downloading Eclipse's Source Code

    - by digiarnie
    I'm doing a study on large Java projects and would like to view the source code for Eclipse. I have gone to this url (http://wiki.eclipse.org/index.php/CVS_Howto) and figured that the most useful cvs repository for me to look at would be this one: :pserver:[email protected]:/cvsroot/eclipse (The Eclipse platform project) However, when looking at this repository, it has so many modules! Which modules should I be trying to check out? I don't necessarily want to build the IDE from source, however, I just want to get the core Eclipse code base to perform some analysis. Would I just check out any modules starting with "org.eclipse..."? Should I be checking out any of the others? Or is there an easier way to get the source? I read somewhere that you can get the source from the binary version of Eclipse but I am unsure where to find the source.

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  • Connecting SceneBuilder edited FXML to Java code

    - by daniel
    Recently I had to answer several questions regarding how to connect an UI built with the JavaFX SceneBuilder 1.0 Developer Preview to Java Code. So I figured out that a short overview might be helpful. But first, let me state the obvious. What is FXML? To make it short, FXML is an XML based declaration format for JavaFX. JavaFX provides an FXML loader which will parse FXML files and from that construct a graph of Java object. It may sound complex when stated like that but it is actually quite simple. Here is an example of FXML file, which instantiate a StackPane and puts a Button inside it: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml"> <children> <Button mnemonicParsing="false" text="Button" /> </children> </StackPane> ... and here is the code I would have had to write if I had chosen to do the same thing programatically: import javafx.scene.control.*; import javafx.scene.layout.*; ... final Button button = new Button("Button"); button.setMnemonicParsing(false); final StackPane stackPane = new StackPane(); stackPane.setPrefWidth(200.0); stackPane.setPrefHeight(150.0); stacPane.getChildren().add(button); As you can see - FXML is rather simple to understand - as it is quite close to the JavaFX API. So OK FXML is simple, but why would I use it?Well, there are several answers to that - but my own favorite is: because you can make it with SceneBuilder. What is SceneBuilder? In short SceneBuilder is a layout tool that will let you graphically build JavaFX user interfaces by dragging and dropping JavaFX components from a library, and save it as an FXML file. SceneBuilder can also be used to load and modify JavaFX scenegraphs declared in FXML. Here is how I made the small FXML file above: Start the JavaFX SceneBuilder 1.0 Developer Preview In the Library on the left hand side, click on 'StackPane' and drag it on the content view (the white rectangle) In the Library, select a Button and drag it onto the StackPane on the content view. In the Hierarchy Panel on the left hand side - select the StackPane component, then invoke 'Edit > Trim To Selected' from the menubar That's it - you can now save, and you will obtain the small FXML file shown above. Of course this is only a trivial sample, made for the sake of the example - and SceneBuilder will let you create much more complex UIs. So, I have now an FXML file. But what do I do with it? How do I include it in my program? How do I write my main class? Loading an FXML file with JavaFX Well, that's the easy part - because the piece of code you need to write never changes. You can download and look at the SceneBuilder samples if you need to get convinced, but here is the short version: Create a Java class (let's call it 'Main.java') which extends javafx.application.Application In the same directory copy/save the FXML file you just created using SceneBuilder. Let's name it "simple.fxml" Now here is the Java code for the Main class, which simply loads the FXML file and puts it as root in a stage's scene. /* * Copyright (c) 2012, Oracle and/or its affiliates. All rights reserved. */ package simple; import java.util.logging.Level; import java.util.logging.Logger; import javafx.application.Application; import javafx.fxml.FXMLLoader; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; public class Main extends Application { /** * @param args the command line arguments */ public static void main(String[] args) { Application.launch(Main.class, (java.lang.String[])null); } @Override public void start(Stage primaryStage) { try { StackPane page = (StackPane) FXMLLoader.load(Main.class.getResource("simple.fxml")); Scene scene = new Scene(page); primaryStage.setScene(scene); primaryStage.setTitle("FXML is Simple"); primaryStage.show(); } catch (Exception ex) { Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); } } } Great! Now I only have to use my favorite IDE to compile the class and run it. But... wait... what does it do? Well nothing. It just displays a button in the middle of a window. There's no logic attached to it. So how do we do that? How can I connect this button to my application logic? Here is how: Connection to code First let's define our application logic. Since this post is only intended to give a very brief overview - let's keep things simple. Let's say that the only thing I want to do is print a message on System.out when the user clicks on my button. To do that, I'll need to register an action handler with my button. And to do that, I'll need to somehow get a handle on my button. I'll need some kind of controller logic that will get my button and add my action handler to it. So how do I get a handle to my button and pass it to my controller? Once again - this is easy: I just need to write a controller class for my FXML. With each FXML file, it is possible to associate a controller class defined for that FXML. That controller class will make the link between the UI (the objects defined in the FXML) and the application logic. To each object defined in FXML we can associate an fx:id. The value of the id must be unique within the scope of the FXML, and is the name of an instance variable inside the controller class, in which the object will be injected. Since I want to have access to my button, I will need to add an fx:id to my button in FXML, and declare an @FXML variable in my controller class with the same name. In other words - I will need to add fx:id="myButton" to my button in FXML: -- <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> and declare @FXML private Button myButton in my controller class @FXML private Button myButton; // value will be injected by the FXMLLoader Let's see how to do this. Add an fx:id to the Button object Load "simple.fxml" in SceneBuilder - if not already done In the hierarchy panel (bottom left), or directly on the content view, select the Button object. Open the Properties sections of the inspector (right panel) for the button object At the top of the section, you will see a text field labelled fx:id. Enter myButton in that field and validate. Associate a controller class with the FXML file Still in SceneBuilder, select the top root object (in our case, that's the StackPane), and open the Code section of the inspector (right hand side) At the top of the section you should see a text field labelled Controller Class. In the field, type simple.SimpleController. This is the name of the class we're going to create manually. If you save at this point, the FXML will look like this: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml" fx:controller="simple.SimpleController"> <children> <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> </children> </StackPane> As you can see, the name of the controller class has been added to the root object: fx:controller="simple.SimpleController" Coding the controller class In your favorite IDE, create an empty SimpleController.java class. Now what does a controller class looks like? What should we put inside? Well - SceneBuilder will help you there: it will show you an example of controller skeleton tailored for your FXML. In the menu bar, invoke View > Show Sample Controller Skeleton. A popup appears, displaying a suggestion for the controller skeleton: copy the code displayed there, and paste it into your SimpleController.java: /** * Sample Skeleton for "simple.fxml" Controller Class * Use copy/paste to copy paste this code into your favorite IDE **/ package simple; import java.net.URL; import java.util.ResourceBundle; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; public class SimpleController implements Initializable { @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'simple.fxml'."; // initialize your logic here: all @FXML variables will have been injected } } Note that the code displayed by SceneBuilder is there only for educational purpose: SceneBuilder does not create and does not modify Java files. This is simply a hint of what you can use, given the fx:id present in your FXML file. You are free to copy all or part of the displayed code and paste it into your own Java class. Now at this point, there only remains to add our logic to the controller class. Quite easy: in the initialize method, I will register an action handler with my button: () { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... -- ... // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... That's it - if you now compile everything in your IDE, and run your application, clicking on the button should print a message on the console! Summary What happens is that in Main.java, the FXMLLoader will load simple.fxml from the jar/classpath, as specified by 'FXMLLoader.load(Main.class.getResource("simple.fxml"))'. When loading simple.fxml, the loader will find the name of the controller class, as specified by 'fx:controller="simple.SimpleController"' in the FXML. Upon finding the name of the controller class, the loader will create an instance of that class, in which it will try to inject all the objects that have an fx:id in the FXML. Thus, after having created '<Button fx:id="myButton" ... />', the FXMLLoader will inject the button instance into the '@FXML private Button myButton;' instance variable found on the controller instance. This is because The instance variable has an @FXML annotation, The name of the variable exactly matches the value of the fx:id Finally, when the whole FXML has been loaded, the FXMLLoader will call the controller's initialize method, and our code that registers an action handler with the button will be executed. For a complete example, take a look at the HelloWorld SceneBuilder sample. Also make sure to follow the SceneBuilder Get Started guide, which will guide you through a much more complete example. Of course, there are more elegant ways to set up an Event Handler using FXML and SceneBuilder. There are also many different ways to work with the FXMLLoader. But since it's starting to be very late here, I think it will have to wait for another post. I hope you have enjoyed the tour! --daniel

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  • Can't access dojo object property using string variable

    - by Kareem
    I am retrieving a json associative array using a dojo xhrGet request. The data comes back just fine, however I need the app to be able to display the keys and their properties (or values) without knowing the keys beforehand. So, I do the following: function getData() { dojo.xhrGet( { url: "ytd_process.php", handleAs: "json", load: function(response) { for (var key in response) { dojo.byId("boxes").innerHTML+="<div id=\"box\">"+key+":"+response.key+"</div>"; } console.dir(response); // Dump it to the console } }); }; The keys are retrieved and displayed on the page, but the response.key returns undefined. I know the syntax is correct because if I replace .key with an actual key value it will display correctly. It appears it doesn't like a string as the key. Any help or advice would be greatly appreciated. Thank you.

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  • Issue with JSON and jQuery

    - by Jason N. Gaylord
    I'm calling a web service and returning the following data in JSON format: ["OrderNumber":"12345","CustomerId":"555"] In my web service success method, I'm trying to parse both: $.ajax({ type: "POST", url: "MyService.asmx/ServiceName", data: "{}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(msg) { var data = msg.d; var rtn = ""; $.each(data, function(list) { rtn = rtn + this.OrderNumber + ", " + this.CustomerId + "<br/>"; } rtn = rtn + "<br/>" + data; $("#test").html(rtn); } }); but I'm getting a bunch of "undefined, undefined" rows followed by the correct JSON string. Any idea why? I've tried using the eval() method but that didn't help as I got some error message talking about ']' being expected.

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  • How to call iframe's function from this iframe

    - by Adrian
    Hi, I have an iframe created in Javascript with some function f(): var iframe = document.createElement("iframe"); $(iframe).attr({ width: 0, height: 0, frameborder: 0, src: this.options.url, name: id, id: id }); document.body.appendChild(iframe); iframe.contentWindow.f = function(data) { alert("test"); }; Document loaded in this iframe should call function f(): <script ...>f();</script> And this works perfectly in Firefox but Opera tells, f() is undefined. Is there any solution? Adrian.

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  • Some special characters defined in "ISO-8859-1" can't be shown when encoding with "UTF-8"

    - by Mike.Huang
    I need to get a string from URL request of brower, and then create a text image by requested text. I know the default encoding of the Java net transmission is "ISO-8859-1", it can works normally with all characters what defined in "ISO-8859-1". But when I request a multi-byte Unicode character (e.g. chinese or something like ¤?), then I need to decode it by "UTF-8" from "ISO-8859-1". My codes like: String reslut = new String(requestString.getBytes("ISO-8859-1"), "UTF-8"); Everything is fine, but I found some characters in ISO-8859-1 are not been shown now, which characters are 0x80 - 0xFF(defined in" ISO-8859-1"), i.e. the characters after 0x80 (in "ISO-8859-1") not been shown when converted to "UTF-8" from "ISO-8859-1". Any other method can solve this query?

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  • How to monitor HTTP(S) traffic / URLs in Android?

    - by Pawel Krakowiak
    I'm interested in whether there is a way to monitor HTTP(S) traffic on an Android phone? What I would like to do is to be able to retrieve all URLs that have been accessed on the phone's browser. I thought that there would be a browser intent for that, but have not seen anything - given I'm green, maybe I just did not know where to look? I followed the question and answer here, but it works only for hyperlinks which were clicked by the user, however I need to catch all URLs - including the ones typed in by the user. Basically I need to know about every single URL that was opened in the web browser. Can I register some kind of a handler with the browser? Is something like that feasible at all?

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  • Making GWT application crawlable by a search engine.

    - by Philippe Beaudoin
    I want to use the #! token to make my GWT application crawlable, as described here: http://code.google.com/web/ajaxcrawling/ There is a GWT sample app available online that uses this, for example: http://gwt.google.com/samples/Showcase/Showcase.html#!CwRadioButton Will serve the following static webpage to the googlebot: http://gwt.google.com/samples/Showcase/Showcase.html?_escaped_fragment_=CwRadioButton I want my GWT app to do something similar. In short, I'd like to serve a different flavor of the page whenever the _escaped_fragment_ parameter is found in the URL. What should I modify in order for the server to serve something else (a static page, or a page dynamically generated through a headless browser like HTML Unit)? I'm guessing it could be the web.xml file, but I'm not sure. (Note: I thought of checking the Showcase app provided with the GWT SDK, but unfortunately it doesn't seem to support serving static files on _escaped_fragment_ and it doesn't use the #! token..)

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  • Return Count from Netflix oData Service When the LINQ Count() Method Doesn't Work

    - by Craig Shoemaker
    Is there a way to use a LINQ expression to request a Count query from the Netflix oData service? The Netflix documentation shows that you can return counts by appending $count to a request for a collection, but a URL like this: http://netflix.cloudapp.net/Catalog/Genres/$count Is not generated from an expression like this: var count = (from g in catalog.Genres select g).Count(); The above code returns an error saying that the Count method is not supported. Is there a way to do this in LINQ, or do I just need to make WebClient request to get the value?

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  • Mod rewrite with 3 parameters ?

    - by Axel
    Hello, I did tons of methods to figure out how to make this mod rewrite but i was completly unsuccessful. I want a .htaccess code that rewrite in the following method: http://www.mydomain.com/apple/upcoming/2 --- http://www.mydomain.com/handler.php?topic=apple&orderby=upcoming&page=2 This is easy to do, but the problem is that all parameters are not required so the link has different levels of parameters each time like this: http://www.mydomain.com/apple/popular/2 -- topic=apple&orderby=popular&page=2 http://www.mydomain.com/apple/2 -- topic=apple&orderby=&page=2 http://www.mydomain.com/all/popular/2 -- topic=all&orderby=popular&page=2 http://www.mydomain.com/apple/upcoming/ -- topic=apple&orderby=upcoming&page= So briefly, the url has 3 optional parameters in one static order: (topic) (orderby) (page) Note: the ORDERBY parameter can be "popular" or "upcoming" or nothing. Thanks

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  • The underlying connection was closed: An unexpected error occurred on a receive

    - by Dave
    Using a console app which runs as a scheduled task on Azure, to all a long(ish) running webpage on Azure. Problem after a few minutes: The underlying connection was closed: An unexpected error occurred on a receive //// used as WebClient doesn't support timeout public class ExtendedWebClient : WebClient { public int Timeout { get; set; } protected override WebRequest GetWebRequest(Uri address) { HttpWebRequest request = (HttpWebRequest)base.GetWebRequest(address); if (request != null) request.Timeout = Timeout; request.KeepAlive = false; request.ProtocolVersion = HttpVersion.Version10; return request; } public ExtendedWebClient() { Timeout = 1000000; // in ms.. the standard is 100,000 } } class Program { static void Main(string[] args) { var taskUrl = "http://www.secret.com/secret.aspx"; // create a webclient and issue an HTTP get to our url using (ExtendedWebClient httpRequest = new ExtendedWebClient()) { var output = httpRequest.DownloadString(taskUrl); } } }

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  • StackExchange API key

    - by user21289
    I am working on a project with the StackExchange API, the problem is at a moment I have this Exception on eclipse console: java.io.IOException: Server returned HTTP response code: 400 for URL: https://api.stackexchange.com/2.1/questions?order=desc&sort=votes&tagged=OSM&site=stackoverflow at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source) atbr.inf.pucrio.sog.StackOverflowAcessor.getQuestionsIds(StackOverflowAcessor.java:41) After verifying on the browser with the same link, I have this error message: {"error_id":502,"error_name":"throttle_violation","error_message":"too many requests from this IP, more requests available in 74089 seconds"} I am wondering if this is dur to the limited numbers of the queries per day, if it is the case, how can I do to have the key? if it is not, how can I do to resolve the problem?

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  • appcfg.py upload_data entity kind problem

    - by Dingo
    Hi, I am developing application on app-engine-path and I would like to upload some data to datastore. For example I have a model models/places.py: class Place(db.Model): name = db.StringProperty() longitude = db.FloatProperty() latitude = db.FloatProperty() If I save this in view, kind() of this entity is "models_place". All is ok, Place.all() in view work fine. But: If I upload some next row using appcfg.py upload_data, the kind() of this entities is Place. loader.py look like this: import datetime, os, sys from google.appengine.ext import db from google.appengine.tools import bulkloader libs_path = os.path.join("/home/martin/myproject/src/") if libs_path not in sys.path: sys.path.insert(0, libs_path) from models import places class AlbumLoader(bulkloader.Loader): def __init__(self): bulkloader.Loader.__init__(self, 'Place', [('name', lambda x: x.decode('utf-8')), ('longitude', float), ('latitude', float), ]) loaders = [AlbumLoader] and command for uploading: python /usr/local/google_appengine/appcfg.py upload_data --config_file=places_loader.py --kind=models_place --filename=data/places.csv --url=http://localhost:8000/remote_api /home/martin/myproject/src/

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  • problem in return value from server to client in ajax

    - by user1400
    hello i try to use ajax and zend framework in my application , i could pass variable to server but i can not get data from server , it does not return values, it return all html code page, where is my mistake? $('#myForm').submit(function($e){ $e.preventDefault(); var $paramToServer=$("#myForm").serialize(); $.ajax({ type:'POST', url:'test', data:$paramToServer , success:function(re){ var res = $.evalJSON(re); console.log(res.id); // to see in firebog }, dataType:'json' }); }); public function testAction() { $this->_helper->getHelper('viewRenderer')->setNoRender(); //disable layout Zend_Layout::getMvcInstance()->disableLayout(); $name=$this->getRequest()->getParam ( 'name' ); //pass $name to server $return = array( 'id' => '5', 'family' => 'hello ', ); $return = Zend_Json::encode( $return); // Response $this->getResponse()->setBody($return); }

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  • Getting info from NSData object

    - by Moshe
    How would I get returningResponse (into say, a NSString) from the following code: NSURLResponse* response; NSError* error; NSData* result = [NSURLConnection sendSynchronousRequest:theRequest returningResponse:&response error:&error]; I think I can get the info that I need into a string but I can't call anything on response because it's null. Therefore, I assume that I need to call something on result. The problem is, I don't know what to call. (The URL request has been coded prior to the code sample. I know that that works.) I want to be able to detect if the request as successful.

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  • javascript ajax variable question..

    - by Kelso
    Hey there, new to AJAX, JS.. Im trying to add to a Javascript/Ajax search script that I've put together. Previously, it had a single search field, called search_word, I added one called search_date. $(".search_button").click(function() { var search_word = $("#search_box").val(); var search_date = $("#datepicker").val(); var dataString = 'search_word='+ search_word; if(search_word=='') { } else { $.ajax({ type: "GET", url: "searchdata.php", data: dataString, In the Ajax, it appears to pass data of dataString, to my processing script. How do I add search date to the dataString so that I can use that var in my searchdata.php? In searchdata, I can do this $search_word=$_GET['search_word']; and use that var, but so far every time i attempt to alter the dataString, it breaks all the other functionality. Thanks!

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  • firefox window.onerror event problem - alerts "Script error!" only

    - by powerboy
    I use the window.onerror to alert javascript errors for debugging. window.onerror = function(msg, url, line) { alert(msg + '\nLine: ' + line); }; When an error is fired, it can alert this actual error message in IE. But in firefox, it just alerts "Script error!", but I can still see the actual error message in firefox's error console. I remembered several months ago when I worked on another project, firefox did not work like this. But I cannot get the code of that project currently. So I wonder what are the possible problems with this?

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  • remove multiple training slashes mod_rewrite

    - by Boyan
    I know this question was asked a number of times on this site alone, but browsing through the relevant posts I couldn't find a solution. Trying to remove multiple trailing slashes after domain. The following mod_rewrite expressions seem to work for URLs such as http://www.domain.com//path1///path2////, but do not work for domain// DirectorySlash Off RewriteEngine on # Canonical fix RewriteCond %{HTTP_HOST} !^www.domain.com$ [NC] RewriteRule ^(.*)$ http://www.domain.com/$1 [R=301] RewriteRule ^/main.do http://www.domain.com/ [R=301,L] RewriteRule ^/index.jsp http://www.domain.com/ [R=301,L] # Remove bogus query strings RewriteCond %{query_string} q= [NC] RewriteRule (.*) http://www.domain.com/$1? [R=301,L] # Remove multiple slashes after domain - DOESN'T WORK!!! #RewriteCond %{REQUEST_URI} ^//+(.*)$ [OR] #RewriteCond %{REQUEST_URI} ^(.*/)/+$ #RewriteRule / http://www.domain.com/%1 [R=301,L] # Remove multiple slashes anywhere in URL RewriteCond %{REQUEST_URI} ^(.*)//(.*)$ RewriteRule . %1/%2 [R=301,L] # Externally redirect to get rid of trailing slash except for home page, ads RewriteCond %{REQUEST_URI} !^/ads/ RewriteRule ^(.+)/$ $1 [R=301,L] Your help is appreciated.

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  • jquery.ajax multiple data problem

    - by Guillaume P
    Hi, I've been trying to make this code work for the last 3 hours. I've tried about everytinh, but I'm still unable to get it to work. I only managed to send 1 data. When I use this code, I only manage to retrieve recaptcha_challenge_field. If I remove recaptcha_challenge_field, I retrieve recaptcha_response_field. However, I am unable to retrieve the two at the same time. challengeField = $("#recaptcha_challenge_field").val(); responseField = $("#recaptcha_response_field").val(); var html = $.ajax( { global: false, type: "POST", async: false, dataType: "html", data: "recaptcha_response_field=" + responseField + "&recaptcha_challenge_field=" + challengeField, url: "../ajax.recaptcha.php" }).responseText; if(html == "success") { $("#captchaStatus").html("Success. Submitting form."); return true; } else { $("#captchaStatus").html("Your captcha is incorrect. Please try again"); Recaptcha.reload(); return false; }

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