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  • Generation of abstract class with JCodeModel

    - by SadJokerBY
    I'm trying to generate top-level abstract class with JCodeModel library, but I can't find any way to change class modifiers. It's possible for nested classes (JDefinedClass API provides methods that get modifiers as parameters). But for creation of top level classes I found only JCodeModel API methods that get fully qualified name with or without ClassType (class/interface/annotation/enum) as parameters. Does anybody can suggest me how to change modifiers of JDefinedClass to make it abstract?

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  • How to deploy to Tomcat from NetBeans?

    - by deamon
    I've added Tomcat in the "Tools Servers" menu and as you can see it appears in the list of servers: But when I try to run my project, I cannot select Tomcat! The drop-down with servers is empty. I tried it with NetBeans 6.8 and 6.9 Beta. Any idea?

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  • isAlive problem..Help to understand how it works

    - by max
    I get this error: "non-static method isAlive() cannot be referenced from a static context" what's wrong with this code..please. I'd like to detect if the thread is alive... Any help in terms of code will be highly appreciated..thanks max class RecThread extends Thread { public void run() { recFile = new File("recorded_track.wav"); // Output file type AudioFileFormat.Type fileType = null; fileType = AudioFileFormat.Type.WAVE; // if rcOn =1 thread is alive int rcOn; try { // starts recording targetDataLine.open(audioFormat); targetDataLine.start(); AudioSystem.write(new AudioInputStream(targetDataLine), fileType, recFile); if (RecThread.isAlive() == true) { rcOn =1; } else { rcOn =0; } } catch (Exception e) { showException(e); } // update actions recAction.setEnabled(true); stopRecAction.setEnabled(false); } }

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  • Why is the output like this?

    - by javatechi
    class another { public void method(Object o) { System.out.println("This is in method which takes object"); } public void method(String s) { System.out.println("This is method which takes string"); } } public class NewClass { public static void main(String args[]) { another an = new another(); an.method(null); } } When I try to execute this, I get This is method which takes string as the output. Why not "This is in method which takes object"? Object can also be null and string can also be null, why doesn't it invoke first method?

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  • How to move positions within an array?

    - by Jade Mulholland
    A program that simply moves array elements. Two variables: userInputVariable and blankSpaceVariable. I have a 2D array named table. Defined as table[userInputVariable + 1][6] I am printing out this array in a table format, and the far left column is numbered by whatever number the user entered at the beginning of the program. I then ask the user where they would like to enter a blank space within the array. This blank space acts like a divider for all the other information in the array. For example, if the user enters 10 at the start for the userInputVariable, and then enters 5 for the blank space. Once printed, the numbers should go like this: 1, 2, 3, 4, --, 5, 6, 7, 8, 9, 10. My plan has been to create a for loop and try to move all the numbers in the array back a position starting from the blank space variable. What I currently have, but does not work: for (int i = blankSpaceVariable; i < table.length - 1; i++) { table[i] = table[i + 1]; } table[blankSpaceVariable] = "--"; With my current code, the numbers go like this: 1, 2, 3, 4, 6, 7, 8, 9, 10 Tried completing this a few different ways also, but the other info within my 2D array didn't move with the numbers. So I thought that this approach can hopefully move all the info within my 2D array down, and make way for a blank section. All help is greatly appreciated!

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  • Building a custom iterator.

    - by Isai
    I am making this class which is a custom Map based off a hash map. I have an add method where if you add an object the object will be the key, and its value will be 1 if the object is not currently in the list. However if you add object that is currently in the list its value will be bumped up by 1. So if I added 10 strings which were all the same, the key would be that string and the value will be 10. I understand in practice when I iterate through the map, there is actually only one object to iterate, however, I am trying to create a inner class that will define an iterator that will iterate the same object however many times its value is. I can do this by simply using for loops to construct an appropriate ArrayList and just create an iterator for that, but that is too inefficient. Is there an easy or more efficient way of doing this?

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  • DocumentBuilder.parse() / Parsing Entities

    - by stormin986
    I'm new to parsing XML and am having an issue with entities. (Am doing this on Android, if it makes a difference). Is there a way to have it turn an entity into the character it represents? I have this in the child of an element: "isn&#39;t" (minus quotes). I would prefer it parse it and the end result be a single text node. However, right now this is turned in to TEXT, ENTITY, TEXT. Is there a way to automatically have it parse the entity into text, or a manual way to do it?

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  • How do I change the number of thumbnails seen in the Android sample Home application?

    - by Todd
    I am working with the sample Home application project on http://developer.android.com/resources/samples/Home/index.html I've added another value to the THUMBS_IDS and IMAGE_IDS Integer arrays in the Wallpaper class for a total of four wallpaper options. When I run the application with Device API version 7, Skin: HVGA, hw.lcd.density: 160, in portrait layout, the fourth wallpaper option is not shown. I need to use the directional keys in the emulator to see the 4th wallpaper option, because the first option is centered. I have modified only the wallpaper.xml file with a variety of android:layout_* options with no success at this point. How do I show all four of my wallpaper options?

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  • recursion resulting in extra unwanted data

    - by spacerace
    I'm writing a module to handle dice rolling. Given x die of y sides, I'm trying to come up with a list of all potential roll combinations. This code assumes 3 die, each with 3 sides labeled 1, 2, and 3. (I realize I'm using "magic numbers" but this is just an attempt to simplify and get the base code working.) int[] set = { 1, 1, 1 }; list = diceroll.recurse(0,0, list, set); ... public ArrayList<Integer> recurse(int index, int i, ArrayList<Integer> list, int[] set){ if(index < 3){ // System.out.print("\n(looping on "+index+")\n"); for(int k=1;k<=3;k++){ // System.out.print("setting i"+index+" to "+k+" "); set[index] = k; dump(set); recurse(index+1, i, list, set); } } return list; } (dump() is a simple method to just display the contents of list[]. The variable i is not used at the moment.) What I'm attempting to do is increment a list[index] by one, stepping through the entire length of the list and incrementing as I go. This is my "best attempt" code. Here is the output: Bold output is what I'm looking for. I can't figure out how to get rid of the rest. (This is assuming three dice, each with 3 sides. Using recursion so I can scale it up to any x dice with y sides.) [1][1][1] [1][1][1] [1][1][1] [1][1][2] [1][1][3] [1][2][3] [1][2][1] [1][2][2] [1][2][3] [1][3][3] [1][3][1] [1][3][2] [1][3][3] [2][3][3] [2][1][3] [2][1][1] [2][1][2] [2][1][3] [2][2][3] [2][2][1] [2][2][2] [2][2][3] [2][3][3] [2][3][1] [2][3][2] [2][3][3] [3][3][3] [3][1][3] [3][1][1] [3][1][2] [3][1][3] [3][2][3] [3][2][1] [3][2][2] [3][2][3] [3][3][3] [3][3][1] [3][3][2] [3][3][3] I apologize for the formatting, best I could come up with. Any help would be greatly appreciated. (This method was actually stemmed to use the data for something quite trivial, but has turned into a personal challenge. :) edit: If there is another approach to solving this problem I'd be all ears, but I'd also like to solve my current problem and successfully use recursion for something useful.

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  • Replace carriage returns and line feeds in out.println?

    - by Mike
    I am a novice coder and I am using the following code to outprint a set of Image keywords and input a "|" between them. <% Set allKeywords = new HashSet(); for (AlbumObject ao : currentObjects) { XmpManager mgr = ao.getXmpManager(); if (mgr != null) { allKeywords.addAll(mgr.getKeywordSet()); } } //get the Iterator Iterator itr = allKeywords.iterator(); while(itr.hasNext()){ String str = itr.next(); out.println(str +"|"); } %> I want the output to be like this: red|blue|green|yellow but it prints out: red| blue| green| yellow which breaks my code. I've tried this: str.replaceAll("\n", ""); str.replaceAll("\r", ""); and str.replaceAll("(?:\\n|\\r)", ""); No luck. I'd really appreciate some help!

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  • AJAX Problem - No response text in FireFox, but ok in IE

    - by Taiba
    Hi, I am making a simple AJAX call to an external site. It works ok in IE, but in Firefox, not response text is returned. I think it might have something to do with the response being "chunked", but I'm not sure. Any ideas? Thanks. function loadXMLDoc() { var xmlhttp; var urlString = "http://drc.edeliver.com.au/ratecalc.asp?Pickup_Postcode=6025&Destination_Postcode=6055&Country=AU&Weight=100&Service_Type=STANDARD&Length=100&Width=100&Height=100&Quantity=2"; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { window.alert(xmlhttp.responseText); } } xmlhttp.open("GET", urlString, true); xmlhttp.send(); }

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  • How to debug ConcurrentModificationException?

    - by Dani
    I encountered ConcurrentModificationException and by looking at it I can't see the reason why it's happening; the area throwing the exception and all the places modifying the collection are surrounded by synchronized (this.locks.get(id)) { ... } // locks is a HashMap<String, Object>; I tried to catch the the pesky thread but all I could nail (by setting a breakpoint in the exception) is that the throwing thread owns the monitor while the other thread (there are two threads in the program) sleeps. How should I proceed? What do you usually do when you encounter similar threading issues?

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  • After a few same hql query the application freezes

    - by Oktay
    I am calling below function with the same batchNumber and it is working without problem 15 times and takes the records fromm database without problem but at 16. time the application freezes when the query.list() row is called. It just loses debug focus and not give any exception. This problem probably is not about the hql because I've seen this problem before and I used criteria instead of hql and I got pass this problem. But for this when I use "group by" in criteria(setrojection....) it doesn't return the result as hibernate model(object) just returns a list. But I need the results as model. Note: about 15 times it is just for test. This is a web aplication and user may click the button many times that calls this funtion to see the taken records from database. public List<SiteAddressModel> getSitesByBatch(String batchNumber) { try{ List<SiteAddressModel> siteList; MigrationPlanDao migrationPlanDao = ServiceFactory.getO2SiteService().getMigrationPlanDao(); Query query = this.getSession().createQuery("from " + persistentClass.getName() + " where " + "siteType =:" + "type and siteName in " + "(select distinct exchange from " + migrationPlanDao.getPersistentClass().getName() + " where migrationBatchNumber =:" + "batchNumber" + ")" ); query.setString("batchNumber", batchNumber); query.setString("type", "LLU/ASN"); System.out.println("before query"); siteList = query.list(); System.out.println("after query"); return siteList; }catch (Exception e) { e.printStackTrace(); } Hibernate version 3.2.0.ga

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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  • Which is the 'correct' way to do this (if statement)

    - by frinkz
    I've got plenty of these lying around, and I'm wondering if I'm going to face any trouble - or performance problems. I have method A: MyClass monkey; ... if(monkey != null) { ... } Or method B: boolean hasMonkey; //This is set to TRUE when monkey is not null MyClass monkey; ... if(hasMonkey) { ... } On a functional level, they both do the same thing. Right now, I'm using method A. Is that a bad way of doing things? Which is going to perform better?

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  • Android - Help needed with designing a screen with either table layout or list views

    - by A. Cusano
    I am currently developing an android app that is to be a counterpart to its sister iphone prototype. My task is to recreate the screen from a design mockup from the iphone app in android, as shown here (can't display an image as a new user - sorry!): http://img.photobucket.com/albums/v439/thrawn891/iphone.jpg What would be the best layouts / views to use for replicating this screen in an activity? Thanks.

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  • Adding a MouseOverHandler to an Element?

    - by JP
    I would like to listen for the mouse over event in GWT 1.6. Since GWT 1.6 has introduced handlers and deprecated listeners I'm unsure as to how I can accomplish this with what little information exists. Note: I have an Element object. That's what I need to add the mouse handler to. I apologize for my lack of clarity. Thanks!

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  • comma in regex in String.replaceAll() method?

    - by kknight
    My code tries to replace "," with "/" in a string. Should I escape "," in the regex string? Both of the two code snippets generated the same results, so I am confused. Code snippet 1: String test = "a,bc,def"; System.out.println(test.replaceAll("\\,", "/")); Code snippet 2: String test = "a,bc,def"; System.out.println(test.replaceAll(",", "/")); Should I use "," or "\,"? Which is safer? Thanks.

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