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  • How to turn off Eclipse console on Windows

    - by engfer
    So I change the -vm argument for eclipse.exe using the eclipse.ini settings file, and now there's an command prompt console (even if I remove the -vm value). Does anyone know how to turn off the console so I only have the eclipse GUI and not the console window? I'm running MS Windows 7.

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  • delete hibernate entity question?

    - by ylazez
    i want to delete a row and cascade all foreign keys in hibernate i am new to hibernate and i want to know if there's a method to delete an entity session.delete(); like the session.save and session.update methods in hibernate?

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  • Creating Linear Layout with TextViews using a for loop

    - by cad8
    Hi all, I was wondering if there is a way to dynamically create an additional linear layout with a textview within a predefined liner layout. THis is my code so you get the gist of what I am asking: LinearLayout MainLL= (LinearLayout) findViewById(R.id.myLayoutId); for(int i=0; i<5; i++) { LinearLayout childLL= new LinearLayout(this); childLL.setOrientation(LinearLayout.VERTICAL); childLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); childLL.setGravity(Gravity.LEFT); TextView text = new TextView(this); text.setText("The Value of i is :"i); text.setTextSize(12); text.setGravity(Gravity.LEFT); text.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT)); childLL.addView(text); MainLL.addView(childLL); } My problem is that I am only getting "The Value of i is :0" as the output, i.e. the first instance. Any help would be much appreciated

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  • Return the difference between the lowest and highest key

    - by stan
    This is a past exam paper i am attempting and have no way to check if the out put is correct as i am not capable of building one of these things the question is in the title class Tree{ Tree left; Tree right; int key; public static int span(Tree tree) { if ( tree == null ){ return null; } if( tree.left != null) int min = span(tree.left); } if( tree.right != null){ int max = span(tree.right); } return max - min; } } Could anyone suggest what i need to change to get 5/5 marks :D - the only thing we have to do is write the span method, the header was given for us Thanks

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  • Is this the right way to have "global" parameters for my servlets?

    - by Geo
    If I have: <context-param> <param-name>SomeParam</param-name> <param-value>SomeValue</param-value> </context-param> in my web.xml, is this the servlet way of specifying options ( like in the way a config file is used ) , or am I doing something wrong? I know about init-param that can be specified for a servlet, but I'd like o make sure some values are the same for all the servlets.

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  • How to update JLabel in Swing?

    - by Roman
    I am trying to use Swing Timer and I wanted to start from a very simple program. I have a window with text: "You have n seconds", where n changes from 10 to 0 every second. I know how to generate a window with text. And I understand how Timer works (it starts an action periodically). But I cannot figure out how to combing this two things. Should I use that: JLabel label = new JLabel(myMessage); and then with timer I need to update the "myMessage" variable? But I think I need to "force" my window to "update" itself (to display a new value stored in "myMessage").

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  • Null Pointer Exception with an array of bitsets

    - by p0ny
    could someone explain to me why the following results in a Null pointer Exception? And how to set a value for bitarray[0]? BitSet[] bitarray; bitarray= new BitSet[10]; bitarray[0].set(1); Also, why something like this work and not result in a pointer exception? BitSet[] bitarray = new BitSet[10]; BitSet bits = new BitSet(32); bits.set(1); bitarray[0] = bits; Thanks

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  • How can we compute the LAST page with JPA?

    - by Kevin
    I would like to implement pagination in my Servlet/EJB/JPA-Hibernate project, but I can't figure out how only one page from the query and know the number of pages I must display I use setFirstResult(int first) ; setMaxResults(int max) ; and that's working alright, but how can I know how many pages I will have in total? (Hibernate is my JPA provider, but I would prefer using only JPA if possible) UPDATE: COUNT() seems to be the better/easiest solution; but what can be the cost of SELECT COUNT(*) FROM ... in comparison with executeQuery("SELECT * FROM ...).getListResult().size() ?

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  • Is it more secure to run a desktop app in a applet?

    - by Tom Brito
    Fist of all, when I say "run a desktop app in a applet" I mean do a Applet application that runs off-line, instead of a Desktop application that runs inside a JFrame. The little I know about applets (and maybe something I say is wrong, please correct me) is that applets have all permitions not granted by default. Also, the applets run inside a Sandbox, that does not allow information in or out without explicity permition. So, if I am focused on security in my application, its best to run it inside an applet (off-line, for a desktop application) then inside a JFrame. Is it right?

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  • Array returning Null values

    - by Nick Gibson
    Dunno why it is...heres the coding for it. http://pastebin.org/301343 I know theres a lot of repetitiveness in the coding...but its because the arrays were retuning null so I got tired of messing with them. Everything works until it reaches line 224, which returns null values.

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  • How can I implement log4j logging to an existing J2EE Struts web application?

    - by Ruepen
    I have recently inherited a J2EE Struts web app that was written back in 2002. There is no logging in the application other than the odd System.out.println(). I have added log4j logging so that I can write out some info to the console, but I'm concerned on how best to approach this. Any suggestions, tips, best practices would be welcome as I don't want to spend too much time adding logging to every method or class (or trying to find what places where logging would be best - ie. bad code blocks/defects). My current approach is to just add some logging to the few classes that I have been looking at to understand the code, but are there a few key places where I can add logging to maximize my use of adding log4j?

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  • Do running times match with O(nlogn)?

    - by user472221
    Hi I have written a class(greedy strategy) that at first i used sort method which has O(nlogn) Collections.sort(array, new SortingObjectsWithProbabilityField()); and then i used the insert method of binary search tree which takes O(h) and h here is the tree height. for different n ,the running time will be : n,running time 17,515428 33,783340 65,540572 129,1285080 257,2052216 513,4299709 which I think is not correct because for increasing n , the running time should almost increase. This method will take the running time: Exponent = -1; for(int n = 2;n<1000;n+=Math.pow(2,exponent){ for (int j = 1; j <= 3; j++) { Random rand = new Random(); for (int i = 0; i < n; i++) { Element e = new Element(rand.nextInt(100) + 1, rand.nextInt(100) + 1, 0); for (int k = 0; k < i; k++) { if (e.getDigit() == randList.get(k).getDigit()) { e.setDigit(e.getDigit() + 1); } } randList.add(e); } double sum = 0.0; for (int i = 0; i < randList.size(); i++) { sum += randList.get(i).getProbability(); } for (Element i : randList) { i.setProbability(i.getProbability() / sum); } //Get time. long t2 = System.nanoTime(); GreedyVersion greedy = new GreedyVersion((ArrayList<Element>) randList); long t3 = System.nanoTime(); timeForGreedy = timeForGreedy + t3 - t2; } System.out.println(n + "," + "," + timeForGreedy/3 ); exponent++; } thanks

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  • Hot to set class variable to be visible to its public static methods?

    - by RCola
    Why I can noy access my variable p in mull form iterate method? How to resolve a problem? Hot to set class variable to be visible to its public static methods? public class mull { public static void main(String[] args) throws InterruptedException { final JPanel p = createAndShowGUI(); Timer timer = new Timer(1000, new MyTimerActionListener()); timer.start(); try { Thread.sleep(10000); } catch (InterruptedException e) { } timer.stop(); public static void iterate(){ for (int i = 0; i < 55; i++){ // "p cannot be resolved" p.moveSquare(i*10, i*10); p.setParamsRing(i*5, i*7, 200, 200); // p.repaint(); } } } class MyPanel extends JPanel { .... } How to access variable set in another method (in this example main())? Why Eclipse forces me to use this ((MyPanel) p).setParamsRing(i*5, i*7, 200, 200); instead of this p.setParamsRing(i*5, i*7, 200, 200);?

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  • How is it possible my array is broken?

    - by user1812765
    I have this piece of code: public lot merge (lot otherlot){ wafer[] mWaferarray = new wafer[16]; byte[] bytearray = new byte[16]; wafer resultwafer = new wafer(bytearray); wafer w1; wafer w2; int i; int[][] assignmentmatrix = HungarianAlgorithm.computeAssignments(convertinttofloat (solutionmatrix(otherlot))); for (i=0; i != assignmentmatrix.length ;i++){ w1 = otherlot.getWaferarray()[assignmentmatrix[i][0]]; w2 = getWaferarray()[assignmentmatrix[i][1]]; resultwafer.setWafer(w1.wafercompare(w2)); mWaferarray[i] = resultwafer; mWaferarray[i].print(); } System.out.println("HERE\n"); mWaferarray[5].toString(); resultlot = new lot(mWaferarray); resultlot.print();// Problem occurs here. return resultlot; } As you can see I create an array of wafers (selfdefined class). Then I fill this up with new wafers. When I print this array (mWaferarray[i].print()) it gives me the wanted results. But when I go out of the "for"-loop the array is broken and it is as if the last item I add to mWaferarray fills it up (the entire array, 16 long, is filled with this wafer). So if run this program this is what I get: 1011110010111100 0011011111111110 0111110111101101 1010111001101111 0110110111101111 1010110101111010 1010110111011110 1011111010111100 1111110011101110 0111111111011011 1111111111011010 1101111011111010 1010110101011110 0101111011011010 1011111011011000 0101111011011010 HERE 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 As you can see it is as if the array is filled with the last wafer. I have been looking at this for some time now, I hope you guy can help me out. Thx in advance PS: my print functions are written like this: void print(){ int j; for (j=0; j != waferarray.length ;j++){ waferarray[j].print(); } } EDIT: added code for lot this is the beginning of the lot class public class lot { wafer[] waferarray = new wafer[16]; lot resultlot; public lot (wafer wafer1,wafer wafer2,wafer wafer3,wafer wafer4, wafer wafer5,wafer wafer6,wafer wafer7,wafer wafer8, wafer wafer9,wafer wafer10,wafer wafer11,wafer wafer12, wafer wafer13,wafer wafer14,wafer wafer15,wafer wafer16){ waferarray[0] = wafer1; waferarray[1] = wafer2; waferarray[2] = wafer3; waferarray[3] = wafer4; waferarray[4] = wafer5; waferarray[5] = wafer6; waferarray[6] = wafer7; waferarray[7] = wafer8; waferarray[8] = wafer9; waferarray[9] = wafer10; waferarray[10] = wafer11; waferarray[11] = wafer12; waferarray[12] = wafer13; waferarray[13] = wafer14; waferarray[14] = wafer15; waferarray[15] = wafer16; } public lot (wafer[] thiswaferarray){ waferarray = thiswaferarray; }

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  • Associate activity with database ID

    - by Mohit Deshpande
    I have a main ListView that is based on an adapter from my database. Each database id is "assigned" to an Activity via the ListView. And in my AndroidManifest, each activity has an intent filter with a custom action. Now with this, I have had to create this class: public final class ActivityLauncher { private ActivityLauncher() { } public static void launch(Context c, int id) { switch(id) { case 1: Intent intent = new Intent(); intent.setAction(SomeActivity.ACTION_SOMEACTIVITY); c.startActivity(intent); break; case 2: ... break; ... } } private static void st(Context context, String action) { Intent intent = new Intent(); intent.setAction(action); context.startActivity(intent); } } So I have to manually create a new case for the switch statement. This would get troublesome if I have to rearrange or delete an id. Is there any way to get around this?

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  • Check and avoid if a char is being entered in a int

    - by John
    Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

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  • Testing what a String token holds

    - by Yiwei Gao
    I am making a calculator and part of this program takes in user String input and tokenizes it (using my own implementation of a Tokenizer class). So now I have a bunch of Token objects and I would like to test each one of them to see if they hold numbers or operators. Is there a way to test to see if they hold operators (ie. +, -, *, /, =, (, ), etc.) without using if (token.equals("+") || token.equals("-") || ... and so on, for each operator? These Token objects are all of type String.

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  • Two forms but only 1 jsp file

    - by joshft91
    Here's what I've got going on. I have one .jsp file. However, I have two forms with multiple inputs inside those forms. What is the best way to detect that one form was submitted but not the other? Here's an example: I have this form: <form name = "login" action="index.jsp" method="get"> Username: <input id="username" name="username" type="text"/><br/> Password: <input id="password" name="password" type="password"/> <input type="submit" Value="Login" ></input> </form> If that button is clicked, I'd like to run this code: String username = request.getParameter("username"); String password = request.getParameter("password"); if((username!= null && !username.trim().equals("")) && (password != null && !username.trim().equals(""))) { DBentry DBentry=new DBentry(); boolean flag = DBentry.isTaken(username); if(flag) {%><script type="text/javascript">alert("Login Successful!");</script><% } else { %><script type="text/javascript">alert("Unrecognized username. Please register!");</script><% } } else { %><script type="text/javascript">alert("Please enter both a username and password!");</script><% } Further down I would have something exactly like it but submitting a different form. Thanks!

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  • How to avoid Foreign Keys constraints for all tables in DB truncate ?

    - by eugeneK
    Hi, for designing purposes i need to truncate all DB which has lots of FK's. I cannot use DELETE command simply because some tables set with Identity of TinyInts and contain about 150 items. this is a query ( truncate all tables in selected DB ) i'm trying to run Declare @t varchar (1024) Declare tbl_cur cursor for select TABLE_NAME from INFORMATION_SCHEMA.TABLES WHERE TABLE_TYPE = 'BASE TABLE' OPEN tbl_cur FETCH NEXT from tbl_cur INTO @t WHILE @@FETCH_STATUS = 0 BEGIN EXEC ('TRUNCATE TABLE '+ @t) FETCH NEXT from tbl_cur INTO @t END CLOSE tbl_cur DEALLOCATE tbl_Cur What the best and easiest way to achieve truncate on DB with many FK's ?

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