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  • How do I change the JAVA_HOME for ant?

    - by Eugene M
    I'm doing java work on a class server where I don't have root. Whenever I try to compile using ant, it points to the wrong directory (/usr/tomcat instead of /usr/tomcat/jre ). One of the things we were told to do when setting up our user accounts was to add export JAVA_HOME=/usr/tomcat/jre to the .bashrc file. I don't know if that was supposed to take care of the problem but it doesn't seem to. So, how can I change the JAVA_HOME property for ant but only for when I run ant? EDIT: echo $JAVA_HOME points to /usr/tomcat/jre echo $JAVA_HOME\bin points to /usr/tomcat/jrebin The problem is when I normally run ant I get this error: Unable to locate tools.jar. Expected to find it in /usr/tomcat/lib/tools.jar Buildfile: build.xml compile: [javac] Compiling 1 source file to /home/ejm244/build/classes BUILD FAILED /home/ejm244/build.xml:9: Unable to find a javac compiler; com.sun.tools.javac.Main is not on the classpath. Perhaps JAVA_HOME does not point to the JDK Total time: 0 seconds

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  • Why does get_posts() return only 5 matching posts, when it should return 9?

    - by Scott B
    global $post; $cat1=get_cat_ID('test1'); $cat2=get_cat_ID('test2'); $myrecentposts = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2",'showposts' => 5)); $myrecentposts2 = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2")); $myrecentpostscount = count($myrecentposts2); echo $myrecentpostscount; The value of the echo is 5 (the correct value should be 9). The only way I can get it to return the correct value for the post count is to change the $myrecentposts2 calculation as follows... $myrecentposts2 = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2",'showposts' => 999));

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  • IE problem with javascript

    - by Syom
    i have the following simple script <input class="input" type="text" name="password" style="color: #797272;" value= "<?php if ($_POST[password] != '') {echo '';} else {echo '????????';}?>" onclick="if (this.value === this.defaultValue) { this.value=''; this.style.color='black'; this.type='password'; }" /> it works fine, but in IE7 it doesn't change the input type. this.type='password'; doesn't work could you help me? thanks

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  • Use text input as php variable

    - by Thomas Lai
    <input type="text" onkeydown="domaincheck()" /> <?php function domaincheck() { $recordexists = checkdnsrr("", "ANY"); if ($recordexists) echo "The domain name has been taken. Sorry!"; else echo "The domain name is available!"; } ?> I want my php code to process the text input and say if it's a valid domain or not. The only thing that doesn't work is linking the input to the php.

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  • Jquery Serialize data

    - by Richard
    So I have several text boxes, drop down menus, and radio options on this form. When the user clicks submit i want to save ALL that information so I can put it into a database. So this is all the form's inputs <div id="reg2a"> First Name: <br/><input type="text" name="fname" /> <br/> Last Name: <br/><input type="text" name="lname" /> <br/> Address: <br/><input type="text" name="address" /> <br/> City: <br/><input type="text" name="city" /> <br/> State: <br/><input type="text" name="state" /> <br/> Zip Code: <br/><input type="text" name="zip" /> <br/> Phone Number: <br/><input type="text" name="phone" /> <br/> Fax: <br/><input type="text" name="fax" /> <br/> Email: <br/><input type="text" name="email" /> <br/> Ethnicity: <i>Used only for grant reporting purposes</i> <br/><input type="text" name="ethnicity" /> <br/><br/> Instutional Information Type (select the best option) <br/> <select name="iitype"> <option value="none">None</option> <option value="uni">University</option> <option value="commorg">Community Organization</option> </select> <br/><br/> Number of sessions willing to present: <select id="vennum_select" name="vnum"> <?php for($i=0;$i<=3;$i++) { ?> <option value="<?php echo $i ?>"><?php echo $i ?></option> <?php } ?><br/> </select><br/> Number of tables requested: <select id="tabnum_select" name="tnum"> <?php for($i=1;$i<=3;$i++) { ?> <option value="<?php echo $i ?>"><?php echo $i ?></option> <?php } ?> </select><br/><br/> Awarding of a door prize during the conference will result in a reduction in the cost of your first table. <br/><br/> I am providing a door prize for delivery during the conference of $75 or more <select id="prize_select" name="pnum"> <option value="0">No</option> <option value="1">Yes</option> </select><br/> Prize name: <input type="text" name="prize_name" /><br/> Description: <input type="text" name="descr" /><br/> Value: <input type="text" name="retail" /><br/><br/> Name of Institution: <br/><input type="text" name="institution" /> <br/><br/> Type (select the best option) <br/> <select name="type"> <option value="none">None</option> <option value="k5">K-5</option> <option value="k8">K-8</option> <option value="68">6-8</option> <option value="912">9-12</option> </select> <br/><br/> Address: <br/><input type="text" name="address_sch" /> <br/> City: <br/><input type="text" name="city_sch" /> <br/> State: <br/><input type="text" name="state_sch" /> <br/> Zip Code: <br/><input type="text" name="zip_sch" /> <br/> <form name="frm2sub" id="frm2sub" action="page3.php" method="post"> <input type="submit" name="submit" value="Submit" id="submit" /> </form> </div> This is my jquery function: $("#frm2sub").submit( function() { var values = {}; values["fname"] = $("#fname").val(); }); I can do this for each one of the input boxes but I want to give all this data to the next page. So how do I put this array into $_POST? Btw, I've tried doing var data = $("#reg2a").serialize(); and var data = $(document).serialize(); Data ended up being empty. Any ideas? Thanks

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  • click multiple times a submit button

    - by Olga Anastasiadou
    Hi all, I encountered a problem that I can't solve. My point is to "click" my sybmit button and every time increase a counter, while this counter reach 10. For the first time it works, but this is it! My test code is below : <form name="testForm" method="post"> <?php $cnt=0; ?> <input type="submit" name="next" id="next" value="NEXT"/> <?php if(isset($_POST['next'])){ if($cnt< 10){ echo $cnt.' --> '; $cnt++; echo $cnt; } } ?> </form> Only 0 -- 1 is printed, every time... please help!! Thanks

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  • VBScript: how to set values from recordset to string

    - by phill
    This is probably a beginner question, but how do you set a recordset to a string variable? Here is my code: Function getOffice (strname, uname) strEmail = uname WScript.Echo "email: " & strEmail Dim objRoot : Set objRoot = GetObject("LDAP://RootDSE") Dim objDomain : Set objDomain = GetObject("LDAP://" & objRoot.Get("defaultNamingContext")) Dim cn : Set cn = CreateObject("ADODB.Connection") Dim cmd : Set cmd = CreateObject("ADODB.Command") cn.Provider = "ADsDSOObject" cn.Open "Active Directory Provider" Set cmd.ActiveConnection = cn cmd.CommandText = "SELECT physicalDeliveryOfficeName FROM '" & objDomain.ADsPath & "' WHERE mail='" & strEmail & "'" cmd.Properties("Page Size") = 1 cmd.Properties("Timeout") = 300 cmd.Properties("Searchscope") = ADS_SCOPE_SUBTREE Dim objRS : Set objRS = cmd.Execute WScript.Echo objRS.Fields(0) Set cmd = Nothing Set cn = Nothing Set objDomain = Nothing Set objRoot = Nothing Dim arStore Set getOffice = objRS.Fields(0) Set objRS = Nothing End function When I try to run the function, it throws an error "vbscript runtime error: Type mismatch" I presume this means it can't set the string variable with a recordset value. How do I fix this problem?

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  • How to Execute an Oracle SQL Statements with VBScript

    - by Arno Conradie
    I am trying to execute an Oracle SQL statement or Oracle Functions through Microsoft VBScript and the loop throught the result set or display the value returned by the function So far I have managed to connect to Oracle via SQLPlus*, but now I am stuck. Can anybody help? Dim output Dim WshShell, oExec, input set WshShell = CreateObject("WScript.Shell") set oEnv=WshShell.Environment("Process") cmdString = "C:\Oracle\11g\product\11.1.0\ruby\BIN\sqlplus.exe -S stradmin/stradmin@ruby select * from dual" Set oExec = WshShell.Exec(cmdString) WScript.Echo "Status" & oExec.Status Do While oExec.Status = 0 WScript.Sleep 2 Loop input = "" Do While Not oExec.StdOut.AtEndOfStream input = input & oExec.StdOut.Read(1) Loop wscript.echo input

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  • jQuery - Show field based on value of a type-hidden on refresh.

    - by Sebhael
    Hello, I'm trying to create something in jQuery and having a bit of problems with it. I'm not too adept on the framework, so I'm sure this is all wrong. Anyways, the ultimate goal is a full form that contains 3 radio buttons - depending on the value of the button, a LI is shown. I have all of that done, but my problem is coming with validation. If something fails then the page is reloaded and the div that was selected doesn't show without clicking another radio first, then back to the original. This process is basically the same as someone came up with here. Here's what I got so far. HTML <li> <label> License (radio) </label> <label for="commercial" class="checkBox"> Commercial </label> <input type="radio" name="license" value="commercial" id="commercial" class="checkBox" <?php echo set_radio('license', 'commercial'); ?> /> <label for="abandonware" class="checkBox"> Abandonware </label> <input type="radio" name="license" value="abandonware" id="abandonware" class="checkBox" <?php echo set_radio('license', 'abandonware'); ?> /> <label for="freeware" class="checkBox"> Freeware </label> <input type="radio" name="license" value="freeware" id="freeware" class="checkBox" <?php echo set_radio('license', 'freeware'); ?> /> </li> This is followed by three LI's that contain id="commercial, abandonware, and freeware" and class="licenseli" My jQuery is, as said, something from here. $('li.licenseli').hide(); $('input[name=license]:radio').change(function(){ var Type = $(this).val(); // Get value of radio $('li.licenseli').slideUp(); // Hide non-selected $('li#'+Type).slideDown(); // Show Selected }); So what I need help with is I have a hidden input that retrieves the value of the radio box from validation - I want to take this value (or the radio's if possible?) and have the original selected option's LI already visible.

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  • jquery load a specific #Div content from multiple html files

    - by Vikram
    Hello friends I am trying to make a Content Slider for my site. I have multiple HTML files and the structure of these files is like this: <div id="title"><h2>Title of the Slide</h2></div> <div id="image"><a href="http://mylink.com"><img src="image.jpg" width="600" height="300" alt="image"</a></div> <div id="content">Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s.</div> I have been trying to use the following script get content (but no success): <?php function render($position="") { ob_start(); foreach(glob("/slides/*.html") as $fileName) { $fname = basename( $fileName ); $curArr = file($fname); $slides[$fname ]['title'] = $curArr[0]; $slides[$fname ]['image'] = $curArr[1]; $slides[$fname ]['content'] = $curArr[2]; foreach($slides as $key => $value){ ?> <div id="slide-title"> <?php echo $value['title'] ?> </div> <div id="slide-content"> <?php echo $value['image'] ?> </div> <div id="slide-image"> <?php echo $value['content'] ?> </div> <?php }} ?> <?php return ob_get_clean(); } But then I came to know about a jQuery function.... (again no success) jQuery.noConflict(); (function($){ $(document).ready(function () { $('#slide-title').load('slides/slide1.html #title'); $('#slide-content').load('slides/slide1.html #content'); $('#slide-image').load('slides/slide1.html #image'); }); })(jQuery); Now My questions are..... Am I using the right syntax. How do I get the content from multiple files using jQuery. Please Note : My knowledge on Programming is almost '0'. I have just started learning it.

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  • MySQL - Selecting the top occurring entries

    - by RC
    Hi, Should be a simple one. Database is mydb. One of the columns is mydata. What SELECT query do I need in order to select the top 3 occurring results from mydata, but sorted alphabetically? For example, if my data is this: mydata ====== kilo (x 1 occurrence) lima (x 9 occurrences) golf (x 5 occurrences) echo (x 9 occurrences) zulu (x 8 occurrences) How do I get it to return "echo, lima, zulu", which are the top three frequently occurring entries sorted alphabetically? Thanks! EDIT: Just to add, they need to be distinct entries. Thanks!

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  • php session variable

    - by Idealflip
    Hi Everyone, my session variable seems to keep dropping its array values. What could I be doing wrong? Is it my object? if(isset($_SESSION['locations'])){ $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session exists"; }else{ $_SESSION['locations'] = new Location(); $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session does not exist"; } class Location { function listItems($location){ $array; $array[] = $location; print_r($array); }

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  • codeIgniter: pass parameter to a select query from previous query

    - by krike
    I'm creating a little management tool for the browser game travian. So I select all the villages from the database and I want to display some content that's unique to each of the villages. But in order to query for those unique details I need to pass the id of the village. How should I do this? this is my code (controller): function members_area() { global $site_title; $this->load->model('membership_model'); if($this->membership_model->get_villages()) { $data['rows'] = $this->membership_model->get_villages(); $id = 1;//this should be dynamic, but how? if($this->membership_model->get_tasks($id)): $data['tasks'] = $this->membership_model->get_tasks($id); endif; } $data['title'] = $site_title." | Your account"; $data['main_content'] = 'account'; $this->load->view('template', $data); } and this is the 2 functions I'm using in the model: function get_villages() { $q = $this->db->get('villages'); if($q->num_rows() > 0) { foreach ($q->result() as $row) { $data[] = $row; } return $data; } } function get_tasks($id) { $this->db->select('name'); $this->db->from('tasks'); $this->db->where('villageid', $id); $q = $this->db->get(); if($q->num_rows() > 0) { foreach ($q->result() as $task) { $data[] = $task; } return $data; } } and of course the view: <?php foreach($rows as $r) : ?> <div class="village"> <h3><?php echo $r->name; ?></h3> <ul> <?php foreach($tasks as $task): ?> <li><?php echo $task->name; ?></li> <?php endforeach; ?> </ul> <?php echo anchor('site/add_village/'.$r->id.'', '+ add new task'); ?> </div> <?php endforeach; ?> ps: please do not remove the comment in the first block of code!

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  • Move/copy files/folder in linux/solaris using only bash built-ins

    - by KullDox
    There was a situation when somebody moved the whole rootdir into a subdir on a remote system, thus all the system tools like cp, mv, etc didn't work anymore. We had an active session though but couldn't find a way to copy/move the files back using only bash built-ins. Do somebody know of a way to achieve this? I even thought about copy the cp or mv binary in the currentdir with while read -r; do echo $LINE; done and then redirect this to a file, but it didn't work. Guess because of all the special non printable chars in a binary file that can't be copied/displayed using echo. thanks.

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  • query excuting problem

    - by srini-r85
    hi, i tried to execute following query in php script. $db_selected = mysql_select_db("lumiinc1_sndemo1", $con); if ($db_selected) { echo "database connected"; } else { die ("Can\'t use db : " . mysql_error()); } $sql = "INSERT INTO `markers` ( `name`, `address`, `lat`, `lng`, `id` ) SELECT `name`, `street`, `latitude`, `longitude`, `lid` FROM `location` WHERE NOT EXISTS ( SELECT * FROM `markers` WHERE `location`.`lid` = `markers`.`id` )"; $result = mysql_query($sql); if ($result) { echo "Query executed OK"; } else { die("Invalid query: " . mysql_error()); } script does not show any error.also query executed.but i didn't get my expected result.at the same i try this query in phpmyAdmin i got my expected result. i dont know the cause of this problem. plz any one find the problem . thanks

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  • dynamic access magic constants in php

    - by Radu
    Hello, Is there a way to shortcut this: function a($where){ echo $where; } function b(){ a(basename(__FILE__).'::'.__FUNCTION__.'()::'.__LINE__); } to something like this: define("__myLocation__", ''.basename(__FILE__).'::'.__FUNCTION__.'()::'.__LINE__.''); function a($where){ echo $where; } function b(){ a(__mYLocation_); } I know that this cannot be done with constants (is just an theoretical example), but I can't find a way to shorthen my code. If a use a function to get my line it will get the line where that function is not the line from where the function was called. I usualy call a function that prints directly to the log file, but in my log I need to know from where the function was called, so i use basename(__FILE__).'::'.__FUNCTION__.'()::'.__LINE__ this will print something like: index.php::b()::6 It is a lot of code when you have over 500 functions in different files. Is there a shorten or better way to do this? Thank you.

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  • Pagination links do not work after first page

    - by TheStack
    Hello, I am trying to fix this pagination script. It seems when I click on the pagination links [1][2][3][4]or[5] , it doesn't work. It just shows the first page and when clicking on the next numbers nothing happens. I hoping someone can see something in the script that I can not see. The main page looks like this (pagination.php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php generate_pagination() ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Then, generate_pagination.php: <?php function generate_pagination($sql) { include_once('config.php'); $per_page = 3; //Calculating no of pages $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="'.$i.'">'.$i.'</li>'; } } $ids=$_GET['ids']; generate_pagination("SELECT COUNT(*) FROM explore WHERE category='$ids'"); ?> Here is the jquery file (jquery_pagination.js): $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = this.id; $("#content").load("pagination_data.php?page=" + pageNum, function(){ Hide_Load(); $(this).attr('data-page', pageNum); }); }); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); }); Lastly, filter_marketing.php (when a user clicks the filter link buttons): <?php include('config.php'); $per_page = 3; if(count($_GET)>0) { if($_GET['page']!=''){ $page=$_GET['page']; } if($_GET['id']!=''){ $id=$_GET['id']; } } $page= ($_GET['page']!='') ? $_GET['page']: false; $id= ($_GET['id']!='') ? $_GET['id']: false; $start = ($page-1)*$per_page; if($page && $id){ $sql = "SELECT * FROM explore WHERE category='$id' ORDER BY category LIMIT $start,$per_page"; } else { die('Error: missing parameters. Id= '.$id.' and page= '.$page); } $result = mysql_query($sql); ?> <table width="800px"> <?php while($row = mysql_fetch_array($result)) { $msg_id=$row['id']; $message=$row['site_description']; $site_price=$row['site_price']; ?> <tr> <td><?php echo $msg_id; ?></td> <td><?php echo $message; ?></td> <td><?php echo $site_price; ?></td> </tr> <?php } ?> </table> So, if anyone sees where the problem is occurring and can help rid of the problem, that would be great, Thank you.

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  • foreach with an array of stdclass objects

    - by Jared Steffen
    So, what I want to do is quite simple in my mind. I have an array that consists solely of four objects. I want to create a loop that will echo an attribute of each object in the array. The only success I've had, however, is echoing every object and every property of the objects. I've never dealt with objects so this is probably the TRUE root of the problem. There's been a few revisions but the only thing I've really excelled at is creating error codes. Here is what I have: $categories = get_categories(array('child_of' => '8')); foreach ($categories as $cat) { echo $cat->name; };

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  • mysql_fetch_array() not displaying all results

    - by user1666995
    I have a database with a calendar table (each row represents one day) with 4 years of rows (2012, 2013, 2014, 2015). I use the column name calyear for the year. I use the following code to find values for distinct years then display it: $year = mysql_query("SELECT DISTINCT calyear FROM calendar"); while($yeararray = mysql_fetch_array($year)) { echo($yeararray['calyear']."<br />"); } The problem is it only displays the years 2013, 2014, 2015 even though when I use echo(mysql_num_rows($year); it displays the value 4 which I take to mean all 4 years are there. I'm not quite sure where I'm going wrong with this.

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  • php zencart mod - having problems with attributes array

    - by user80151
    I inherited a zencart mod and can't figure out what's wrong. The customer selects a product and an attribute (model#). This is then sent to another form that they complete. When they submit the form, the product and the attribute should be included in the email sent. At this time, only the product is coming through. The attribute just says "array." The interesting part is, when I delete the line that prints the attribute, the products_options_names will print out. So I know that both the product and the products_options_names are working. The attribute is the only thing that is not working right. Here's what I believe to be the significant code. This is the page that has the form, so the attribute should already be passed to the form. //Begin Adding of New features //$productsimage = $product['productsImage']; $productsname = $product['productsName']; $attributes = $product['attributes']; $products_options_name = $value['products_options_name']; $arr_product_list[] = "<strong>Product Name:</strong> $productsname <br />"; $arr_product_list[] .= "<strong>Attributes:</strong> $attributes <br />"; $arr_product_list[] .= "<strong>Products Options Name:</strong> $products_options_name <br />"; $arr_product_list[] .= "---------------------------------------------------------------"; //End Adding of New features } // end foreach ($productArray as $product) ?> Above this, there is another section that has attributes: <?php echo $product['attributeHiddenField']; if (isset($product['attributes']) && is_array($product['attributes'])) { echo '<div class="cartAttribsList">'; echo '<ul>'; reset($product['attributes']); foreach ($product['attributes'] as $option => $value) { ?> Can anyone help me figure out what is wrong? I'm not sure if the problem is on this page or if the attribute isn't being passed to this page. TIA

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  • Handling errors on php contact form

    - by topSearchDesign
    The below code is working great for handling errors for text fields in my contact form, but how do I get this same method to work for dropdown select option boxes and textareas? <input type="text" name="name" value="<?php if($errors){echo $name;} ?>" id="name" size="30" /> For example: <textarea name="message" value="<?php if($errors){echo $message;} ?>" id="message" rows="10" cols="40"></textarea> does not work.

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  • json null error help in php

    - by bobby
    I get 'json is null' as error My php file: <?php if (isset($_REQUEST['query'])) { $query = $_REQUEST['query']; $url='https://www.googleapis.com/urlshortener/v1/'; $key='ApiKey'; $result= $url.($query).$key; $ch = curl_init($result); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,1); $resp = curl_exec($ch); curl_close($ch); echo $resp; } ?> My html: <html> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ // when the user clicks the button $("button").click(function(){ $.getJSON("shortner.php?query="+$('#query').attr("value"),function(json){ $('#results').append('<p>Id : ' + json.id+ '</p>'); $('#results').append('<p>Longurl: ' + json.longurl+ '</p>'); }); }); }); </script> </head> <body> <input type="text" value="Enter a place" id="query" /><button>Get Coordinates</button> <div id="results"></div> Edited : <?php if (isset($_REQUEST['query'])) { $query = $_REQUEST['query']; $url='https://www.googleapis.com/urlshortener/v1/'; $key='Api'; $key2='?key='; $result= $url.$query.$key2.$key; $requestData= json_encode($result); echo var_dump($query); $ch = curl_init($requestData); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,1); $resp = curl_exec($ch); curl_close($ch); echo $resp; } ?>

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  • json jquery post request

    - by John
    <script type="text/javascript"> $(document).ready(function() { $("a").click(function() { var content = $('#content').html(); var data = {"content":content}; $.ajax({ type: "POST", dataType: "json", url: "ajax.php", data: {content:content}, success function (data) { alert('Hello!'); } }); }); }); </script> <div id="content"><?php echo $content; ?></div> ajax.php echo json_encode($_POST['content']); ?> Nothing happens... WhatI really want to achieve is to get that alert box and get the return data, but I am lost since I don't get any errors or nothing.

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  • problems, custum wrap (class) around PDO, doesn't work

    - by Knarf
    DB::construct(); $STH = DB::prepare('INSERT INTO users (username, password, email, activationkey) VALUES (?, UNHEX(?), ?, ?)'); var_dump($STH); $result = $STH->execute(array('test', 'nils', '[email protected]', '227a038fe9c81515b514cb152188e95c')); echo "working? <br />"; if($result == false) echo 'noooo...'; It outputs and doesn't put anything in the database. Works with a similare code with DPO just without my DB class. But I doesn't get any errors. Anyone have an idea what the problem could be? object(PDOStatement)#2 (1) { ["queryString"]=> string(87) "INSERT INTO users (username, password, email, activationkey) VALUES (?, UNHEX(?), ?, ?)" } working? <br /> noooo...

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  • How can I execute a PHP function in a form action?

    - by stocksy101
    I am trying to run a function from a PHP script in the form action. My code: <?php require_once ( 'username.php' ); echo ' <form name="form1" method="post" action="username()"> <p> <label> <input type="text" name="textfield" id="textfield"> </label> </p> <p> <label> <input type="submit" name="button" id="button" value="Submit"> </label> </p> </form>'; ?> I echo the form but I want the function "username" which is called from username.php to be executed. how can I do this in a simliar way to the above?

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