Right, I think I really am living a dream. I have the following piece of code which I compile and run on an AIX machine:
AIX 3 5
PowerPC_POWER5 processor type
IBM XL C/C++ for AIX, V10.1
Version: 10.01.0000.0003
#include <stdio.h>
#include <math.h>
#define RADIAN(x) ((x) * acos(0.0) / 90.0)
double nearest_distance(double radius,double lon1, double lat1, double lon2, double lat2){
double rlat1=RADIAN(lat1);
double rlat2=RADIAN(lat2);
double rlon1=lon1;
double rlon2=lon2;
double a=0,b=0,c=0;
a = sin(rlat1)*sin(rlat2)+ cos(rlat1)*cos(rlat2)*cos(rlon2-rlon1);
printf("%lf\n",a);
if (a > 1) {
printf("aaaaaaaaaaaaaaaa\n");
}
b = acos(a);
c = radius * b;
return radius*(acos(sin(rlat1)*sin(rlat2)+
cos(rlat1)*cos(rlat2)*cos(rlon2-rlon1)));
}
int main(int argc, char** argv) {
nearest_distance(6367.47,10,64,10,64);
return 0;
}
Now, the value of 'a' after the calculation is reported as being '1'. And, on this AIX machine, it looks like 1 1 is true as my 'if' is entered !!! And my acos of what I think is '1' returns NanQ since 1 is bigger than 1. May I ask how that is even possible ? I do not know what to think anymore !
The code works just fine on other architectures where 'a' really takes the value of what I think is 1 and acos(a) is 0.
