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  • Saving a Join Model

    - by Thorpe Obazee
    I've been reading the cookbook for a while now and still don't get how I'm supposed to do this: My original problem was this: A related Model isn't being validated From RabidFire's commment: If you want to count the number of Category models that a new Post is associated with (on save), then you need to do this in the beforeSave function as I've mentioned. As you've currently set up your models, you don't need to use the multiple rule anywhere. If you really, really want to validate against a list of Category IDs for some reason, then create a join model, and validate category_id with the multiple rule there. Now, I have these models and are now validating. The problem now is that data isn't being saved in the Join Table: class Post extends AppModel { var $name = 'Post'; var $hasMany = array( 'CategoryPost' => array( 'className' => 'CategoryPost' ) ); var $belongsTo = array( 'Page' => array( 'className' => 'Page' ) ); class Category extends AppModel { var $name = 'Category'; var $hasMany = array( 'CategoryPost' => array( 'className' => 'CategoryPost' ) ); class CategoryPost extends AppModel { var $name = 'CategoryPost'; var $validate = array( 'category_id' => array( 'rule' => array('multiple', array('in' => array(1, 2, 3, 4))), 'required' => FALSE, 'message' => 'Please select one, two or three options' ) ); var $belongsTo = array( 'Post' => array( 'className' => 'Post' ), 'Category' => array( 'className' => 'Category' ) ); This is the new Form: <div id="content-wrap"> <div id="main"> <h2>Add Post</h2> <?php echo $this->Session->flash();?> <div> <?php echo $this->Form->create('Post'); echo $this->Form->input('Post.title'); echo $this->Form->input('CategoryPost.category_id', array('multiple' => 'checkbox')); echo $this->Form->input('Post.body', array('rows' => '3')); echo $this->Form->input('Page.meta_keywords'); echo $this->Form->input('Page.meta_description'); echo $this->Form->end('Save Post'); ?> </div> <!-- main ends --> </div> The data I am producing from the form is as follows: Array ( [Post] => Array ( [title] => 1234 [body] => 1234 ) [CategoryPost] => Array ( [category_id] => Array ( [0] => 1 [1] => 2 ) ) [Page] => Array ( [meta_keywords] => 1234 [meta_description] => 1234 [title] => 1234 [layout] => index ) ) UPDATE: controller action //Controller action function admin_add() { // pr(Debugger::trace()); $this->set('categories', $this->Post->CategoryPost->Category->find('list')); if ( ! empty($this->data)) { $this->data['Page']['title'] = $this->data['Post']['title']; $this->data['Page']['layout'] = 'index'; debug($this->data); if ($this->Post->saveAll($this->data)) { $this->Session->setFlash('Your post has been saved', 'flash_good'); $this->redirect($this->here); } } } UPDATE #2: Should I just do this manually? The problem is that the join tables doesn't have things saved in it. Is there something I'm missing? UPDATE #3 RabidFire gave me a solution. I already did this before and am quite surprised as so why it didn't work. Thus, me asking here. The reason I think there is something wrong. I don't know where: Post beforeSave: function beforeSave() { if (empty($this->id)) { $this->data[$this->name]['uri'] = $this->getUniqueUrl($this->data[$this->name]['title']); } if (isset($this->data['CategoryPost']['category_id']) && is_array($this->data['CategoryPost']['category_id'])) { echo 'test'; $categoryPosts = array(); foreach ($this->data['CategoryPost']['category_id'] as $categoryId) { $categoryPost = array( 'category_id' => $categoryId ); array_push($categoryPosts, $categoryPost); } $this->data['CategoryPost'] = $categoryPosts; } debug($this->data); // Gives RabidFire's correct array for saving. return true; } My Post action: function admin_add() { // pr(Debugger::trace()); $this->set('categories', $this->Post->CategoryPost->Category->find('list')); if ( ! empty($this->data)) { $this->data['Page']['title'] = $this->data['Post']['title']; $this->data['Page']['layout'] = 'index'; debug($this->data); // First debug is giving the correct array as above. if ($this->Post->saveAll($this->data)) { debug($this->data); // STILL gives the above array. which shouldn't be because of the beforeSave in the Post Model // $this->Session->setFlash('Your post has been saved', 'flash_good'); // $this->redirect($this->here); } } }

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  • How to parse the second child node from xml page in iphone

    - by Warrior
    I am new to iphone development.I want parse an you-tube XML page and retrieve its contents and display in a RSS feed. my xml page is <entry> <id>xxxxx</id> <title>xxx xxxx xxxx</title> <content>xxxxxxxxxxx</content> <media:group> <media:thumbnail url="http://tiger.jpg"/> </media:group> </entry> To retrieve the content i am using xml parsing. - (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict{ currentElement = [elementName copy]; if ([elementName isEqualToString:@"entry"]) { entry = [[NSMutableDictionary alloc] init]; currentTitle = [[NSMutableString alloc] init]; currentcontent = [[NSMutableString alloc] init]; } } - (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName{ if ([elementName isEqualToString:@"entry"]) { [entry setObject:currentTitle forKey:@"title"]; [entry setObject:currentDate forKey:@"content"]; [stories addObject:[entry copy]]; }} - (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string{ if ([currentElement isEqualToString:@"title"]) { [currentTitle appendString:string]; } else if ([currentElement isEqualToString:@"content"]) { [currentLink appendString:string]; } } I am able to retrieve id , title and content value and display it in a table-view.How can i retrieve tiger image URL and display it in table-view.Please help me out.Thanks.

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  • open flash chart help needed

    - by Carlos Barbosa
    def reparto_de_ventas_por_marca #obtener los montos de las ventas en el periodo comprendido y sumarlas @ventas = Venta.find(:all) @marcas = Marca.find(:all) title = Title.new("Ingresos de este mes: #{@total}") pie = Pie.new pie.start_angle = 35 pie.animate = true pie.tooltip = '#val# de #total#<br>#percent# de 100%' pie.colours = ["#245a9c", "#fff"] pie.values = [ @marcas.each do |result| PieValue.new(result.ventas.count, result.name) end ] chart = OpenFlashChart.new chart.title = title chart.add_element(pie) chart.x_axis = nil render :text => chart.to_s end It just doesn't works i need to get the values to create a graph with flash chart. any help will be appreciated.

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  • Errors checking and opening a URL using PHP

    - by Jean
    Hello Here is one script with out any errors $url="http://yahoo.com"; $file1 = fopen($url, "r"); $content = file_get_contents($url); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; And here is the same script using a look to check multiple urls and getting errors for ($j=1;$j<=$i;$j++) { if ($x[$j]!=''){ $t_u = "http:".$x[$j]; $file2 = fopen($t_u, "r"); $content2 = file_get_contents($t_u); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; } } The error is Warning: fopen() [function.fopen]: php_network_getaddresses: getaddrinfo failed: No such host is known. in g:/ What exactly is wrong here?

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  • How to turn dynamic URL into static URL

    - by Rafael Carvalho
    I am developing a website using PHP and Apache. I wanna turn my URLs from www.example.com/book.php?book=title into something like this, if it is possible of course: www.example.com/book/title Notice that the title of the books are unique and cannot be repeated. I`ve read about this, but none of the posts were clear enough for a beginner like me. Do you guys know any tutorial that explains that? Thanks.

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  • How do you move an admin menu item in Magento

    - by Josh Pennington
    I currently have an extension that I created and it currently sits inside of its own top level menu. I would like to move it so that the item would appear inside of the Customers menu. Does anyone know how to do this? It looks like this is handled inside the extensions config.xml file. The code that I have for it right now is as follows: <menu> <testimonials module="testimonials"> <title>Testimonials</title> <sort_order>71</sort_order> <children> <items module="testimonials"> <title>Manage Items</title> <sort_order>0</sort_order> <action>testimonials/adminhtml_testimonials</action> </items> </children> </testimonials> </menu> I tried changing the title element to Customers and it just created a duplicate Customers menu. Does anyone have any ideas? Thanks Josh Pennington

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  • xml schema putting both sequence and all under one complexType node

    - by exiang
    Here is the xml file: <section> <number>1</number> <title>A Title goes here...</title> <code>TheCode</code> <element></element> <element></element> </section> In section node, there are number, title and code node. Their sequence must not be fixed. Then, there are multiple element under section node as well. The idea is to use the following schema: <xs:complexType name="Type-section"> <xs:all> <xs:element name="number" minOccurs="0"></xs:element> <xs:element name="code" minOccurs="1"></xs:element> <xs:element name="title" minOccurs="1"></xs:element> </xs:all> <xs:sequence> <xs:element maxOccurs="unbounded" name="element"></xs:element> </xs:sequence> </xs:complexType> But it is invalid. I just cant put "sequence" and "all" together in the same level. How can i fix it?

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  • Only show non blank attributes for a model in views in Rails

    - by Senthil
    Say I've a user model and there are bunch of user info, like email, birthdate, location, telephone number etc. What's the simplest way of hiding the attributes that are blank? I've doing something like <% if blog.title.empty? -%> <p>Body: <%=h blog.body %></p> <p>Comments: <%=h blog.comments %></p> <% elsif blog.body.empty? %> <p>Title: <%=h blog.title %></p> <p>Comments: <%=h blog.comments %></p> <% else -%> <p>Title: <%=h blog.title %></p> <p>Body: <%=h blog.body %></p> <% end -%> Clearly that is one ugly child. Other than using partials to render, is there a trick to only show non blank fields? I've been trying to write a helpher method to make the view cleaner, but that's even more ugly. Any help is appreciated.

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  • Parsing XML wont display all items.

    - by Nauman A
    I have this code but the toast wont display any message what is wrong with my code.. I can get the value from link, linknext but title wont bring out any value. ( I am not very bright with writing code so please suggest anything you may feel like. final Button button = (Button) findViewById(R.id.Button01); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click try { URL url = new URL( "http://somelink.com=" + Link.setFirst_link); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(url.openStream())); doc.getDocumentElement().normalize(); NodeList nodeList = doc.getElementsByTagName("item"); /** Assign textview array lenght by arraylist size */ for (int i = 0; i < nodeList.getLength(); i++) { Node node = nodeList.item(i); Element fstElmnt = (Element) node; NodeList nameList = fstElmnt.getElementsByTagName("link"); Element nameElement = (Element) nameList.item(0); nameList = nameElement.getChildNodes(); String img = (((Node) nameList.item(0)).getNodeValue()); NodeList websiteList = fstElmnt.getElementsByTagName("linknext"); Element websiteElement = (Element) websiteList.item(0); websiteList = websiteElement.getChildNodes(); String nextlink = (((Node) websiteList.item(0)).getNodeValue()); Link.setFirst_link = nextlink; Drawable drawable = LoadImageFromWebOperations(img); imgView.setImageDrawable(drawable); NodeList titleList = fstElmnt.getElementsByTagName("title"); Element titleElement = (Element) titleList.item(0); websiteList = titleElement.getChildNodes(); String title = (((Node) titleList.item(0)).getNodeValue()); Context context = getApplicationContext(); CharSequence text = title; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }); /** Set the layout view to display */ } Here is the xml file <?xml version="1.0"?> <maintag> <item> <link>http://image.com/357769.jpg?40</link> <linknext>http://www.image.com</linknext> <title>imagename</title> </item> </maintag>

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  • Regarding some Update Stored procedure

    - by Serenity
    I have two Tables as follows:- Table1:- ------------------------------------- PageID|Content|TitleID(FK)|LanguageID ------------------------------------- 1 |abc |101 |1 2 |xyz |102 |1 -------------------------------------- Table2:- ------------------------- TitleID|Title |LanguageID ------------------------- 101 |Title1|1 102 |Title2|1 ------------------------ I don't want to add duplicates in my Table1(Content Table). Like..there can be no two Pages with the same Title. What check do I need to add in my Insert/Update Stored Procedure ? How do I make sure duplicates are never added. I have tried as follows:- CREATE PROC InsertUpdatePageContent ( @PageID int, @Content nvarchar(2000), @TitleID int ) AS BEGIN IF(@PageID=-1) BEGIN IF(NOT EXISTS(SELECT TitleID FROM Table1 WHERE LANGUAGEID=@LANGUAGEID)) BEGIN INSERT INTO Table1(Content,TitleID) VALUES(@Content,@TitleID) END END ELSE BEGIN IF(NOT EXISTS(SELECT TitleID FROM Table1 WHERE LANGUAGEID=@LANGUAGEID)) BEGIN UPDATE Table1 SET Content=@Content,TitleID=@TitleID WHERE PAGEID=@PAGEID END END END Now what is happening is that it is inserting new records alright and won't allow duplicates to be added but when I update its giving me problem. On my aspx Page I have a drop down list control that is bound to DataSource that returns Table 2(Title Table) and I have a text box in which user types Page's content to be stored. When I update, like lets say I have a row in my Table 1 as shown above with PageID=1. Now when I am updating this row, like I didn't change the Title from the drop down and only changed Content in the text box, its not updating the record ..and when Stored procedure's Update Query does not execute it displays a Label that says "Page with this title exists already." So whenever I am updating an existing record that label is displayed on screen.How do I change that IF condition in my Update Stored procedure?? EDIT:- @gbn :: Will that IF condition work in case of update? I mean lets say I am updating the Page with TitleID=1, I changed its content, then when I update, it's gonna execute that IF condition and it still won't update coz TitleID=1 already exits!It will only update if TitleID=1 is not there in Table1. Isn't it? Guess I am getting confused. Please answer.Thanks.

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  • Export data to word from php with the headers on all the pages

    - by udaya
    Hi I am exporting data from php page to word document I received the result in word format but when the data's are in excess number then the header are not available for the consecutive page ex my first page has title Country Name Country uday India akila India my second page has no title such as name and title kiran pakisthan vikie america how to get the titles on the consecutive pagess

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  • iphone how to customize UITableViewCell cell.textlabel and cell.detailtextlabel programmatically

    - by Prerak
    Hi! In my iPhone App In table view cell I want to dispaly one main title and 5 subtitlessubtitles suppose item1 as main title and item2 , item3 , item4 , item5 and item6 as subtitles, for that i have saperate two arrays for passing the values in table view cell one for cell.textLabel.text= second for cell.detailTextLabel.text now I want the flexibility to make item2 as maintitle and want to add item1 to subtitle How can I set title and subtitle programmatically from single array? and any of them as Please Help and Suggest, Thank You.

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  • JSP template inheritance

    - by Ryan
    Coming from a background in Django, I often use "template inheritance", where multiple templates inherit from a common base. Is there an easy way to do this in JSP? If not, is there an alternative to JSP that does this (besides Django on Jython that is :) base template <html> <body> {% block content %} {% endblock %} </body> <html> basic content {% extends "base template" %} {% block content %} <h1>{{ content.title }} <-- Fills in a variable</h1> {{ content.body }} <-- Fills in another variable {% endblock %} Will render as follows (assuming that conten.title is "Insert Title Here", and content.body is "Insert Body Here") <html> <body> <h1>Insert title Here <-- Fills in a variable</h1> Insert Body Here <-- Fills in another variable </body> <html>

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  • jQuery toggle caching / cookies

    - by user1706680
    I’m using the jQuery toggle function for my navigation. By default the Authors toggle is visible, the Archives toggle is closed. http://jsfiddle.net/TeDFs/4/ My problem is that when the users switches to another page the toggles reset themselves. For example, when the user closes the Authors toggle and opens the Archive toggle and then navigates to another page the default settings are loaded. I read that it’s possible to store the settings via cookies but I’m absolutely new to jQuery and it would be great if somebody could help me out! HTML <div id="authors" class="widget"> <h2 class="widget-title-visible">Authors</h2> <div class="toggle"> <div class="submenu"> <ul> <li>Name 1</li> <li>Name 2</li> <li>Name 3</li> <li>Name 3</li> </ul> </div> </div> <div id="archives" class="widget"> <h2 class="widget-title">Archiv</h2> <div class="toggle hidden"> <div class="submenu"> <ul> <li>November 2012</li> <li>Oktober 2012</li> </ul> </div> </div> </div>? jQuery function toggleWidgets() { jQuery('.widget-title').addClass('plus'); jQuery('.widget-title-visible').addClass('minus'); jQuery('.widget-title').click(function() { $(this).toggleClass('plus').toggleClass('minus').next().toggle(180); }); jQuery('.widget-title-visible').click(function() { $(this).toggleClass('minus').toggleClass('plus').next().toggle(180); }); } jQuery(document).ready(function() { toggleWidgets(); } )? CSS .hidden{ display:none; } .plus { background: url(http://moargh.de/daten/sidebar_arrows.png) 0 5px no-repeat; padding: 0 0 0 12px; } .minus { background: url(http://moargh.de/daten/sidebar_arrows.png) 0 -10px no-repeat; padding: 0 0 0 12px; }

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  • How can one close html tags in vim quickly

    - by wds
    It's been a while since I've had to do any html-like code in vim, but recently I came across this again. Say I'm doing a simple bit of a html page: <html><head><title>This is a title</title></head></html> How do I write those closing tags for title, head and html down quickly? I feel like I'm missing some really simple way here that does not involve me going through writing them all down one by one. Of course I can use ^P to autocomplete the individual tag names but what gets me on my laptop keyboard is actually getting the brackets and slash right.

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  • Need some suggestions on my softwares architecture. [Code review]

    - by Sergio Tapia
    I'm making an open source C# library for other developers to use. My key concern is ease of use. This means using intuitive names, intuitive method usage and such. This is the first time I've done something with other people in mind, so I'm really concerned about the quality of the architecture. Plus, I wouldn't mind learning a thing or two. :) I have three classes: Downloader, Parser and Movie I was thinking that it would be best to only expose the Movie class of my library and have Downloader and Parser remain hidden from invocation. Ultimately, I see my library being used like this. using FreeIMDB; public void Test() { var MyMovie = Movie.FindMovie("The Matrix"); //Now MyMovie would have all it's fields set and ready for the big show. } Can you review how I'm planning this, and point out any wrong judgement calls I've made and where I could improve. Remember, my main concern is ease of use. Movie.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Drawing; namespace FreeIMDB { public class Movie { public Image Poster { get; set; } public string Title { get; set; } public DateTime ReleaseDate { get; set; } public string Rating { get; set; } public string Director { get; set; } public List<string> Writers { get; set; } public List<string> Genres { get; set; } public string Tagline { get; set; } public string Plot { get; set; } public List<string> Cast { get; set; } public string Runtime { get; set; } public string Country { get; set; } public string Language { get; set; } public Movie FindMovie(string Title) { Movie film = new Movie(); Parser parser = Parser.FromMovieTitle(Title); film.Poster = parser.Poster(); film.Title = parser.Title(); film.ReleaseDate = parser.ReleaseDate(); //And so an so forth. } public Movie FindKnownMovie(string ID) { Movie film = new Movie(); Parser parser = Parser.FromMovieID(ID); film.Poster = parser.Poster(); film.Title = parser.Title(); film.ReleaseDate = parser.ReleaseDate(); //And so an so forth. } } } Parser.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; using HtmlAgilityPack; namespace FreeIMDB { /// <summary> /// Provides a simple, and intuitive way for searching for movies and actors on IMDB. /// </summary> class Parser { private Downloader downloader = new Downloader(); private HtmlDocument Page; #region "Page Loader Events" private Parser() { } public static Parser FromMovieTitle(string MovieTitle) { var newParser = new Parser(); newParser.Page = newParser.downloader.FindMovie(MovieTitle); return newParser; } public static Parser FromActorName(string ActorName) { var newParser = new Parser(); newParser.Page = newParser.downloader.FindActor(ActorName); return newParser; } public static Parser FromMovieID(string MovieID) { var newParser = new Parser(); newParser.Page = newParser.downloader.FindKnownMovie(MovieID); return newParser; } public static Parser FromActorID(string ActorID) { var newParser = new Parser(); newParser.Page = newParser.downloader.FindKnownActor(ActorID); return newParser; } #endregion #region "Page Parsing Methods" public string Poster() { //Logic to scrape the Poster URL from the Page element of this. return null; } public string Title() { return null; } public DateTime ReleaseDate() { return null; } #endregion } } ----------------------------------------------- Do you guys think I'm heading towards a good path, or am I setting myself up for a world of hurt later on? My original thought was to separate the downloading, the parsing and the actual populating to easily have an extensible library. Imagine if one day the website changed its HTML, I would then only have to modifiy the parsing class without touching the Downloader.cs or Movie.cs class. Thanks for reading and for helping!

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  • how to remove repeated record's from results linq to sql

    - by Sadegh
    hi, i want to remove repeated record's from results but distinct don't do this for me! why??? var results = (from words in _Xplorium.Words join wordFiles in _Xplorium.WordFiles on words.WordId equals wordFiles.WordId join files in _Xplorium.Files on wordFiles.FileId equals files.FileId join urls in _Xplorium.Urls on files.UrlId equals urls.UrlId where files.Title.Contains(query) || files.Description.Contains(query) orderby wordFiles.Count descending select new SearchResultItem() { Title = files.Title, Url = urls.Address, Count = wordFiles.Count, CrawledOn = files.CrawledOn, Description = files.Description, Lenght = files.Lenght, UniqueKey = words.WordId + "-" + files.FileId + "-" + urls.UrlId }).Distinct();

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  • Json to treeview (<ul>)

    - by Pieter
    Hi I get the following data back from my WCF Data Service (I cut out the metadata) { "d" : [ {"CodeId": 6, "Title": "A Child Sub Item", "Parent":}, {"CodeId": 5, "Title": "Another Root Item", "Parent": -1}, {"CodeId": 4, "Title": "Child Item", "Parent": 2}, {"CodeId": 2, "Title": "Root Item", "Parent": -1} ] } I am trying to get this into a <ul> style tree with Parent = -1 as root and then the rest as sub items of their parent id's. Can anyone help me please, preferably in jQuery? I will use this in jstree if someone knows of a better way to do this. Thanks

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  • How to add a WHERE clause on the second table of a 1-to-1 join in Fluent NHibernate?

    - by daddywoodland
    I'm using a legacy database that was 'future proofed' to keep track of historical changes. It turns out this feature is never used so I want to map the tables into a single entity. My tables are: CodesHistory (CodesHistoryID (pk), CodeID (fk), Text) Codes (CodeID (pk), CodeName) To add an additional level of complexity, these tables hold the content for the drop down lists throughout the application. So, I'm trying to map a Title entity (Mr, Mrs etc.) as follows: Title ClassMap - Public Sub New() Table("CodesHistory") Id(Function(x) x.TitleID, "CodesHistoryID") Map(Function(x) x.Text) 'Call into the other half of the 1-2-1 join in order to merge them in 'this single domain object Join("Codes", AddressOf AddTitleDetailData) Where("CodeName like 'C.Title.%'") End Sub ' Method to merge two tables with a 1-2-1 join into a single entity in VB.Net Public Sub AddTitleDetailData(ByVal m As JoinPart(Of Title)) m.KeyColumn("CodeID") m.Map(Function(x) x.CodeName) End Sub From the above, you can see that my 'CodeName' field represents the select list in question (C.Title, C.Age etc). The problem is that the WHERE clause only applies to the 'CodesHistory' table but the 'CodeName' field is in the 'Codes' table. As I'm sure you can guess there's no scope to change the database. Is it possible to apply the WHERE clause to the Codes table?

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  • Getting started with workflows in sharepoint 2010

    - by Thomas Stock
    Hi, I'm a beginning sharepoint developer asked to implement the following scenario in sharepoint 2010. We're a bit lost on the best approach to get started.. I'm really struggling to find the best practise solution. This is the flow: A user can make a request with a title and a description. A mail gets sent to the representative with a link to a form. A representative can approve or reject the request. If approved: A mail gets sent to Board with a link to form If rejected: A mail gets sent to the user with the message that it has been rejected. when the request was approved by the representative, the board can approve or reject the request. A mail gets sent to the user and the representative with the descision of the board. So the list has the following fields: Request title Request description Representative approval Representative description Board approval Board description The user should see the following form: Request title (editable) Request description (editable) The representative should see the following form: Request title (read-only) Request description (read-only) Representative approval (editable) Representative description (editable) The Board should see the following form: Request title (read-only) Request description (read-only) Representative approval (read-only) Representative description (read-only) Board approval (editable) Board description (editable) My questions: What tool is most appropriate for making the forms? Infopath? SPD? VS2010? How do I handle rights to make sure only the board can access the board edit form? What kind of workflow do I use? When do I start the workflow(s)? What do I use to develop the workflow(s)? How do I handle rights when showing the listview with all requests? How can I build the links in the mails sent to the different groups. Thanks in advance for any advice.

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  • Breadcrumbs in Fusebox 4/5

    - by Jordan Reiter
    I'm wondering if anyone has come up with a clean way to generate a breadcrumbs trail in Fusebox. Specifically, is there a way of keeping track of "where you are" and having that somehow generate the breadcrumbs for you? So, for example, if you're executing /index.cfm?fuseaction=Widgets.ViewWidget&widget=1 and the circuit structure is something like /foo/bar/widgets/ then somehow the system automatically creates an array like: [ { title: 'Foo', url: '#self#?fuseaction=Foo.Main' }, { title: 'Bar', url: '#self#?fuseaction=Bar.Main' }, { title: 'Widgets', url: '#self#?fuseaction=Widgets.Main' }, { title: 'Awesome Widget', url: '' } ] Which can then be rendered as Foo Bar Widgets Awesome Widget Right now it seems the only way to really do this is to create the structure for each fuseaction in a fuse of some kind (either the display fuse or a fuse dedicated to creating the crumbtrail).

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  • pywinauto: taking more than one app windows

    - by Denis Barmenkov
    I have a GUI application which can create many similar windows on desktop. All windows have same title. I have to enumerate all dialogs with same title and make some tests against each of such dialogs. If I call: dialog = app['Window Name'] pywinauto returns a WindowSpecification object which is useful along with accessing controls by name. When I call: dialogs = app.windows_(title='Window Name') pywinauto returns me a list of HwndWrapper instances which are not so useful. How to obtain a list of windows with specified title but as WindowSpecification objects?

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  • Stepping thru a plist to get at info

    - by cannyboy
    If I've got a plist set up like this Key Type Value Root Array Item 0 Dictionary -Title String Part One -Description String Welcome to part one. Have fun Item 1 Dictionary -Title String Part Two -Description String Welcome to part two. Fun too. Item 2 Dictionary -Title String Part Three -Description String Welcome to part three. It's free Item 3 Dictionary -Title String Part Four -Description String It's part four. No more How would I step thru to put all the titles in one array, and all the descriptions into another?

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  • custom rss feed suddenly does not work anymore

    - by krike
    I just don't understand what's happening, I haven't change anything to the site for a few months but now suddenly the rss feed doesn't work anymore. I create a php file with the following code: header('Content-type: text/xml'); include("config/config.inc.php"); $result = mysqli_query($link, "SELECT * FROM tutorials ORDER BY tutorial_id DESC LIMIT 50"); ?> <rss version="2.0"> <channel> <title>CMS tutorial site</title> <description>Bringing you the best CMS tutorials from the web</description> <link>http://cmstutorials.org</link> <?php while($row = mysqli_fetch_object($result)) { $user = mysqli_fetch_object(mysqli_query($link, "SELECT * FROM user_extra WHERE userid=".$row->user_id."")); ?> <item> <title><?php echo $row->title; ?></title> <author><?php echo $user->username; ?></author> <description><?php echo $row->description; ?></description> <pubDate><?php echo $row->date; ?></pubDate> <link>http://cmstutorials.org/view_tutorial.php?tutorial_id=<?php echo $row->tutorial_id; ?></link> </item> <?php } ?> </channel> </rss> I checked the query by executing it in phpmyadmin and it works, doesn't give any error. When I delete the header content type and the rss tag it will print out each line from the query but the feed won't display anything this is the link of the feed http://cmstutorials.org/rss (or http://cmstutorials.org/rss.php)

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  • Generating 8000 text files from xml files

    - by Ray
    Hi all, i need to generate the same number of text files as the xml files i have. Within the text files, i need the title and maybe some other tags of it. I can generate text files with the elements i wanted but not all xml files can be generated. Only some of them are generated. Something might be wrong with my parser so help out please thanks. This is my code. Please have a look and give me suggestions. Thanks in advance. import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import org.w3c.dom.*; import java.io.*; public class AccessingXmlFile1 { public static void main(String argv[]) { try { //File file = new File("C:\\MyFile.xml"); // create a file that is really a directory File aDirectory = new File("C:/Documents and Settings/I2R/Desktop/test"); // get a listing of all files in the directory String[] filesInDir = aDirectory.list(); System.out.println(""+filesInDir.length); // sort the list of files (optional) // Arrays.sort(filesInDir); //////////////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////////////// // have everything i need, just print it now for ( int a=0; a<filesInDir.length; a++ ) { String xmlFile = filesInDir[a]; String newLine = System.getProperty("line.separator"); File file = new File(xmlFile); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document document = db.parse(file); document.getDocumentElement().normalize(); //System.out.println("Root element " + document.getDocumentElement().getNodeName()); NodeList node = document.getElementsByTagName("metadata"); System.out.println("Information of Xml File"); System.out.println(xmlFile.substring(0, xmlFile.length() - 4)); //////////////////////////////////////////////////////////////////////////////////// String titleStoreText = ""; String descriptionStoreText = ""; String collectionStoreText = ""; String textToWrite = ""; //////////////////////////////////////////////////////////////////////////////////// for (int i = 0; i < node.getLength(); i++) { Node firstNode = node.item(i); if (firstNode.getNodeType() == Node.ELEMENT_NODE) { Element element = (Element) firstNode; NodeList titleElementList = element.getElementsByTagName("title"); Element titleElement = (Element) titleElementList.item(0); NodeList title = titleElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(titleElement == null) titleStoreText = " There is no title for this file."+ newLine; else titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue() + newLine; //titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Title : " + titleStoreText); NodeList collectionElementList = element.getElementsByTagName("collection"); Element collectionElement = (Element) collectionElementList.item(0); NodeList collection = collectionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(collectionElement == null) collectionStoreText = " There is no collection for this file."+ newLine; else collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue() + newLine; //collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Collection : " + collectionStoreText); NodeList descriptionElementList = element.getElementsByTagName("description"); Element descriptionElement = (Element) descriptionElementList.item(0); NodeList description = descriptionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(descriptionElement == null) descriptionStoreText = " There is no description for this file."+ newLine; else descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Description : " + descriptionStoreText); //////////////////////////////////////////////////////////////////////////////////// textToWrite = "=====Title=====" + newLine + titleStoreText + newLine + "=====Collection=====" + newLine + collectionStoreText + newLine + "=====Description=====" + newLine + descriptionStoreText;// + newLine + "=====Subject=====" + newLine + subjectStoreText; //////////////////////////////////////////////////////////////////////////////////// } } ///////////////////////////////////////////write to file part is here///////////////////////////////////////// Writer output = null; File file2 = new File(xmlFile.substring(0, xmlFile.length() - 4)+".txt"); output = new BufferedWriter(new FileWriter(file2)); output.write(textToWrite); output.close(); System.out.println("Your file has been written"); //////////////////////////////////////////////////////////////////////////////////// } } catch (Exception e) { e.printStackTrace(); } } }

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