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  • How can I handle validation of non-latin script input in PHP?

    - by Matt
    I am trying to adapt a php application to handle non-latin scripts (specifically: Japanese, simplified Chinese and Arabic). The app's data validation routines make frequent use of regular expressions to check input, but I am not sure how to adapt the \w character type to other languages without installing additional locales on the system (which I cannot rely on). Previous developers to have worked on the app have simply added needed characters to the regexes as the number of languages we supported grew (you frequently see "[\wÀÁÂÃÄÅÆÇÈÉ... etc" in the code), but I can't really do this for all the alphabets I need to support now. Does anybody out there have some advice on how to tackle this?

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  • Pulling international street addresses / phone numbers from free-form text

    - by spitzanator
    Hey, folks. I'm looking for some regular expressions to help grab street addresses and phone numbers from free-form text (a la Gmail). Given some text: "John, I went to the store today, and it was awesome! Did you hear that they moved to 500 Green St.? ... Give me a call at +14252425424 when you get a chance." I'd like to be able to pull out: 500 Green St. (recognized as a street address) +14252425424 (recognized as a phone number) What makes this problem easier is that I don't care about parsing text that gets pulled out. That is, I don't care that Green is the name of the road or that 425 is the area code. I just want to grab strings that "look like" addresses or telephone numbers. Unfortunately, this needs to work internationally, as best as possible. Anyone have any leads? Thanks!

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  • How to match a variable list of items separated by commas

    - by user261915
    I want to turn something like this CS 240, CS 246, ECE 222, ... (more or less); Software Engineering students only into ('CS 240', 'CS 246', 'ECE 222', 'ECE 220') in Python, code that matches a single course looks like >>> re.search('([A-Z]{2,5} \d{3})', 'SE 112').groups() ('SE 112',) I prefer a regular expression only method because I have a bunch of other alternate reg exps using '|' to combine them. However, a method with split is acceptable.

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  • Need to add specific characters to regular expression

    - by lordryan
    i'm using the following regular expression to form a basic email validation. var emailRegEx = /^([a-zA-Z0-9])(([a-zA-Z0-9])*([\._\+-])*([a-zA-Z0-9]))*@(([a-zA-Z0-9\-])+(\.))+([a-zA-Z]{2,4})+$/; this works pretty well for what i need but i also need to exclude these specific characters for reasons i won't go into. !,#,$,%,^,&,*,(,),-,+,|,{,},[,],:,>,<,?,/,\,= - (the characters between the "," if that isn't clear) could someone help me with adding the second group to the first? I know the pro's and cons of using javascript to validate email addresses - i have to do it this way. thanks.

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  • Elegant way to distinct Path or Entry key

    - by sum1stolemyname
    I have an application loading CAD data (Custom format), either from the local filesystem specifing an absolute path to a drawing or from a database. Database access is realized through a library function taking the drawings identifier as a parameter. the identifiers have a format like ABC 01234T56-T, while my paths a typical windows Paths (eg x:\Data\cadfiles\cadfile001.bin). I would like to write a wrapper function Taking a String as an argument which can be either a path or an identifier which calls the appropriate functions to load my data. Like this: Function CadLoader(nameOrPath : String):TCadData; My Question: How can I elegantly decide wether my string is an idnetifier or a Path to a file? Use A regexp? Or just search for '\' and ':', which are not appearing in the Identifiers?

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  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

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  • How do I .MatchCase and .WholeWord?

    - by Tanner
    Hello, Ive been making a find, find next function for my richtextbox, so I have these check boxes to let the user search by whole word or case sensitive or both, and I got the first two, to work but I can't get it to work with both case a whole word checked, here's my code: if (isWhole == true && isCase == true) { string searchText = Form2.text; this.Focus(); richTextBox1.Focus(); findPos = richTextBox1.Find(searchText,findPos,richTextBox1.Text.Length, RichTextBoxFinds.WhatGoesHere?); richTextBox1.Select(findPos, searchText.Length); findPos += searchText.Length; } But there's no option for wholeword and matchcase so is there any way to do this with .Find()?

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  • java - check if string ends with certain pattern

    - by The Learner
    I have string like: This.is.a.great.place.too.work. (or) This/is/a/great/place/too/work/ than my java program should give me that the sentence is valid and it has "work". if i Have : This.is.a.great.place.too.work.hahahha (or) This/is/a/great/place/too/work/hahahah Should not give me that there is a work in the sentance. so I am looking at java strings to find a word at the end of the sentance having . (or),(or)/ before it. How can I achieve that

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  • PHP: Return string between two characters

    - by Nic Hubbard
    I am wanting to use "keywords" within a large string. These keywords start and end using *my_keyword* and are user defined. How, within a large string, can I search and find what is between the two * characters and return each instance? The reason it might change it, that parts of the keywords can be user defined, such as *page_date_Y* which might show the year in which the page was created. So, again, I just need to do a search and return what is between those * characters. Is this possible, or is there a better way of doing this if I don't know the "keyword" length or what i might be?

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  • JavaScript: add or subtract from number in string

    - by yoavf
    I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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  • Regular expression to match text that doesn't start with substring?

    - by Steven
    I have text with file names scattered throughout. The filenames appear in the text like this: |test.txt| |usr01.txt| |usr02.txt| |foo.txt| I want to match the filenames that don't start with usr. I came up with (?<=\|).*\.txt(?=\|) to match the filenames, but it doesn't exclude the ones starting with usr. Is this possible with regular expressions?

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  • How can I test if an input field contains foreign characters?

    - by zeckdude
    I have an input field in a form. Upon pushing submit, I want to validate to make sure the user entered non-latin characters only, so any foreign language characters, like Chinese among many others. Or at the very least test to make sure it does not contain any latin characters. Could I use a regular expression for this? What would be the best approach for this? I am validating in both javaScript and in PHP. What solutions can I use to check for foreign characters in the input field in both programming languages?

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  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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  • Censoring selected words (replacing them with ****) using a single replaceAll?

    - by aioobe
    I'd like to censor some words in a string by replacing each character in the word with a "*". Basically I would want to do String s = "lorem ipsum dolor sit"; s = s.replaceAll("ipsum|sit", $0.length() number of *)); so that the resulting s equals "lorem ***** dolor ***". I know how to do this with repeated replaceAll invokations, but I'm wondering, is this possible to do with a single replaceAll?

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  • Regular Expression to capture the first <p> of HTML

    - by Program.X
    I have the following regular expression: (?:<(?<tag>\w*)>(?<text>.*)</\k<tag>>) I want it t grab the text within the first HTML element. eg. <p>This should capture</p>This shouldn't Works, but ... <p>This should capture</p><p>This shouldn't</p> Doesn't work. As you'd expect, it returns: This should capture</p><p>This shouldn't I'm racking my brains here. How can I just have it select the FIRST inner text? (I'm trying to be tag-agnostic, so <strong>This should match</strong> is equally appropriate, etc.)

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  • Notepad++ regular expression find and replace $_REQUEST with $_GET but a more secure

    - by David
    What I am doing is replacing, in a large program, all $_REQUEST['var'] and mysql_escape_string($_REQUEST['var']) with either the 1st or 2nd line below the dotted line. Now, I have figured out this much of the regular expression but I would like to make it simpler. Instead of having to run the top one first then the 2nd one I would like to just run one all together. I tried this but it did not work. (mysql_escape_string\()*$_REQUEST\[\'([^']*)\'\]\)(\)*) So below is what works but again have to do it twice. $_REQUEST\[\'([^']*)\'\] mysql_escape_string\($_REQUEST\[\'([^']*)\'\]\) (isset($_GET['\1'])?mysql_real_escape_string($_GET['\1']):false) (isset($_POST['\1'])?mysql_real_escape_string($_POST['\1']):false) ============================ Update: Yeah, after some research I figured out that Notepad++ does not support most regular expressions. I guess one additional step can not hurt a person. It's just laziness. *NOTE: BUT if anyone wants to try feel free to comment. At least it is just 2 steps and not 20.

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  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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  • preg_replace replacing with array

    - by Scott
    What I want to do is replace the "[replace]" in input string with the corresponding vaule in the replace array. The total number of values will change but there will always be the same number in the replace array as in input string. I have tried doing this with preg_replace and preg_replace_callback but I can't get the pattern right for [replace], I also tried using vsprintf but the % in <table width="100%"> was messing it up. All help is greatly appreciated! Replace Array: $array = array('value 1','value 2','value 3'); Input String $string = ' <table width="100%"> <tr> <td>Name:</td> <td>[replace]</td> </tr> <tr> <td>Date:</td> <td>[replace]</td> </tr> <tr> <td>Info:</td> <td>[replace]</td> </tr> </table> '; Desired Result <table width="100%"> <tr> <td>Name:</td> <td>value 1</td> </tr> <tr> <td>Date:</td> <td>value 2</td> </tr> <tr> <td>Info:</td> <td>value 3</td> </tr> </table>

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  • extract word with regular expression

    - by farka
    I have a string 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and I would like to extract the words temperatoA and CelcieusB. I have this regular expression (\d+/(\w+),?)*! but I only get the match 1/temperatoA,2/CelcieusB! Why?

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